convert c code to mipsthese 2 functions are linked with each other.pdf

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convert c code to mips these 2 functions are linked with each other. #define MAX_BOARD_SIZE 12 // Players #define PLAYER_EMPTY 0 #define PLAYER_BLACK 1 #define PLAYER_WHITE 2 int board_size; int current_player = PLAYER_BLACK; char board[MAX_BOARD_SIZE][MAX_BOARD_SIZE]; int main(void); void announce_winner(void); unsigned int count_discs(int player); void announce_winner(void) { int black_count = count_discs(PLAYER_BLACK); int white_count = count_discs(PLAYER_WHITE); if (white_count > black_count) { printf("The game is a win for WHITE!\n"); white_count += count_discs(PLAYER_EMPTY); } else if (black_count > white_count) { printf("The game is a win for BLACK!\n"); black_count += count_discs(PLAYER_EMPTY); } else { printf("The game is a tie! Wow!\n"); } printf("Score for black: %d, for white: %d.\n", black_count, white_count); } unsigned int count_discs(int player) { int count = 0; for (int row = 0; row < board_size; ++row) { for (int col = 0; col < board_size; ++col) { if (board[row][col] == player) { count++; } } } return count; }.

$convert c code to mips these 2 functions are linked with each other. #define MAX_BOARD_SIZE 12 // Players #define PLAYER_EMPTY 0 #define PLAYER_BLACK 1 #define PLAYER_WHITE 2 int board_size; int current_player = PLAYER_BLACK; char board[MAX_BOARD_SIZE][MAX_BOARD_SIZE]; int main(void); void announce_winner(void); unsigned int count_discs(int player); void announce_winner(void) { int black_count = count_discs(PLAYER_BLACK); int white_count = count_discs(PLAYER_WHITE); if (white_count > black_count) { printf("The game is a win for WHITE!n"); white_count += count_discs(PLAYER_EMPTY); } else if (black_count > white_count) { printf("The game is a win for BLACK!n"); black_count += count_discs(PLAYER_EMPTY); } else { printf("The game is a tie! Wow!n"); } printf("Score for black: %d, for white: %d.n", black_count, white_count); } unsigned int count_discs(int player) { int count = 0; for (int row = 0; row < board_size; ++row) { for (int col = 0; col < board_size; ++col) { if (board[row][col] == player) { count++;$

}
}
}
return count;
}

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PLEASE can do this in NETBEAN I need that way thank very much Mancala is a family of board games played around the world, sometimes called \"sowing\" games, or \"count-and-capture\" games, which describes the gameplay. The Kalah variant was imported to the United States in 1940. This game favors the starting player, who will always win the three-seed to six-seed versions with perfect play. As a result, this variant is usually considered a children\'s game. mancalaBoard Rules The game provides a Kalah board and a number of seeds or counters. The board has 12 small pits, called houses, on each side; and a big pit, called an end zone, at each end. The object of the game is to capture more seeds than one\'s opponent. At the beginning of the game, four seeds are placed in each house. This is the traditional method. Each player controls the six houses and their seeds on the player\'s side of the board. The player\'s score is the number of seeds in the store to their right. Players take turns sowing their seeds. On a turn, the player removes all seeds from one of the houses under their control. Moving counter-clockwise, the player drops one seed in each house in turn, including the player\'s own store but not their opponent\'s. If the last sown seed lands in an empty house owned by the player, and the opposite house contains seeds, both the last seed and the opposite seeds are captured and placed into the player\'s store. If the last sown seed lands in the player\'s store, the player gets an additional move. There is no limit on the number of moves a player can make in their turn. When one player no longer has any seeds in any of their houses, the game ends. The other player moves all remaining seeds to their store, and the player with the most seeds in their store wins. It is possible for the game to end in a draw. Requirements The project name shall be _GEM_Mancala Create a JSP-based application using MVC architecture that implements the Mancala game as described above The application must display: The game board current player indicator current number of seeds in each pit current scores (number of seeds in each house) game over indicator winner indicator a quit button The game cannot use old-style scriptlet tags (<% %>), expression tags (<%= %>) or declaration tags (<%! %>) mancalaStamp Solution New File Save file as Gboard.java Inthiswe will build the game board and all ofit\'sproperties It includes: Each player\'s pots, with player ownership (although we can do this in the LinkList/Array classes. We should also have win conditions, pot placement in the window, and pool placement. Possibly we should have the score and what not placed in here too referenced from the LinkList/Array classes. package main; import java.util.Random; public class GBoard { private int STANDARDBEADS = 3; private int m_bowls[]; private int player1Pool; private int player2Pool; private int SelectOn, currentPlayer; private boolean running; Random rand = new Random(); privat.

PLEASE can do this in NETBEAN I need that way thank very muchManca.pdf

PLEASE can do this in NETBEAN I need that way thank very muchManca.pdf

PLEASE can do this in NETBEAN I need that way thank very muchManca.pdf

Please help with this. program must be written in C# .. All of the game logic must be written in a seperate class using using an array that is passed in through a prperty that represents the game board. The class needs to have methods to determine of someone won, or if there was a tie, make sure all business logic is in a seperate class anot behind the UI.. ***** These are the complete in instructions for the game assignment design Create a Tic-Tac-Toe game that can be played by two players. The form will consist of a Tic- Tac-Toe board in which the users’ click on to choose their space. As the game is being played the Game Status section will tell whose turn it is. When someone wins or there is a tie, a message will be displayed in the Game status section telling the users the status. When someone wins the game the winning move needs to be indicated. There also needs to be a section that keeps track of the number of wins for each player, and the number of ties. When the game is finished the user may click the “Start Game” button to start a new game. This program will consist of the main form and at least one class that will define the rules of the game. This class will have an array that is passed in through a property that represents the game board. The class will then have methods within it that determines if someone won, if there is a tie, or if neither has occurred yet. Make sure all business logic is in a separate class and not behind the UI. EXTRA CREDIT (10 Points) Create a computer player that can be played against. The computer player will need to be smart enough to make a winning move or to block a winning move. Solution using System; using System.Collections.Generic; using System.Drawing; using System.Windows.Forms; namespace Tic_Tac_Toe { /// /// Description of MainForm. /// public partial class MainForm : Form { Logic logicObj = new Logic(); public MainForm() { // // The InitializeComponent() call is required for Windows Forms designer support. // InitializeComponent(); // // TODO: Add constructor code after the InitializeComponent() call. // } int turn=1; int click1=0,click2=0,click3=0,click4=0,click5=0,click6=0,click7=0,click8=0,click9=0; int player1=0,player2=0; void Button1Click(object sender, EventArgs e) { if(click1==0) { if(turn%2!=0) { button1.Text=\"X\"; click1++; } else { button1.Text=\"O\"; click1++; } turn++; } else { button1.Text=button1.Text; } display(); int a = logicObj.winLossFunc(button1.Text, button2.Text, button3.Text, button4.Text, button5.Text, button6.Text, button7.Text, button8.Text, button9.Text); if (a==1) { player1++; player1score.Text = player1.ToString(); cleargame(); } else if(a==2) { player2++; player2score.Text = player2.ToString(); cleargame(); } } void Button2Click(object sender, EventArgs e) { if(click2==0) { if(turn%2!=0) { button2.Text=\"X\"; click2++; } else { button2.Text=\"O\"; click2++; } turn++; } else { button2.Text=button2.Text; } display(); int a = logicObj.winLossFunc(button1.Text, b.

Please help with this. program must be written in C# .. All of the g.pdf

Please help with this. program must be written in C# .. All of the g.pdf

Please help with this. program must be written in C# .. All of the g.pdf

#include #include #include #include #include \"game.h\" #include \"aaball.h\" #define CHECKERS_CELL_SIZE 40 #define CHECKERS_NUM_PIECES 4 #define CHECKERS_BOARD_WID 8 #define CHECKERS_BOARD_HEIT 8 #define CHECKERS_WK 1 #define CHECKERS_WP 2 #define CHECKERS_BK 3 #define CHECKERS_BP 4 #define CHECKERS_ISKING(x) (x == 1 || x == 3) #define CHECKERS_ISPAWN(x) (x == 2 || x == 4) #define CHECKERS_ISWHITE(x) (x >= 1 && x <= 2) #define CHECKERS_ISBLACK(x) (x >= 3 && x <= 4) char checkers_colors[] = {200, 200, 200, 220,220,255}; int checkers_init_pos[] = { 0 , 4 , 0 , 4 , 0 , 4 , 0 , 4 , 4 , 0 , 4 , 0 , 4 , 0 , 4 , 0 , 0 , 4 , 0 , 4 , 0 , 4 , 0 , 4 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 , 2 , 0 , 2 , 0 , 2 , 0 , 2 , 0 , 0 , 2 , 0 , 2 , 0 , 2 , 0 , 2 , 2 , 0 , 2 , 0 , 2 , 0 , 2 , 0 , }; static int checkers_max_moves = 200; void checkers_init (); int checkers_getmove (Pos *, int, int, GtkboardEventType, Player, byte **, int **); ResultType checkers_who_won (Pos *, Player, char **); byte *checkers_movegen (Pos *); ResultType checkers_eval (Pos *, Player, float *); char ** checkers_get_pixmap (int idx, int color); void checkers_reset_uistate (); Game Checkers = { CHECKERS_CELL_SIZE, CHECKERS_BOARD_WID, CHECKERS_BOARD_HEIT, CHECKERS_NUM_PIECES, checkers_colors, checkers_init_pos, NULL, \"Checkers\", checkers_init}; void checkers_init () { game_getmove = checkers_getmove; game_movegen = checkers_movegen; game_who_won = checkers_who_won; game_eval = checkers_eval; game_get_pixmap = checkers_get_pixmap; game_reset_uistate = checkers_reset_uistate; game_file_label = FILERANK_LABEL_TYPE_ALPHA; game_rank_label = FILERANK_LABEL_TYPE_NUM | FILERANK_LABEL_DESC; game_allow_flip = TRUE; game_doc_about = \"Checkers\ \" \"Two player game\ \" \"Status: Partially implemented (currently unplayable)\ \" \"URL: \"GAME_DEFAULT_URL(\"checkers\"); } ResultType checkers_who_won (Pos *pos, Player player, char **commp) { static char comment[32]; char *who_str [2] = { \"white won\", \"black won\"}; int found_w = 0, found_b = 0; int i; for (i=0; iboard[i])) found_w = 1; else if (CHECKERS_ISBLACK (pos->board[i])) found_b = 1; if (!found_b) { strncpy (comment, who_str[0], 31); *commp = comment; return RESULT_WHITE; } if (!found_w) { strncpy (comment, who_str[1], 31); *commp = comment; return RESULT_BLACK; } return RESULT_NOTYET; } byte * checkers_movegen (Pos *pos) { int i, j, diffx, diffy; byte movbuf [256]; byte *movlist, *mp = movbuf; byte *board = pos->board; Player player = pos->player; for (i=0; iboard [j * board_wid + i]) { case CHECKERS_WK: sum += (5 - fabs ((i-3.5) * (j-3.5)) / 10); break; case CHECKERS_WP: sum += (1 + j / 10.0); break; case CHECKERS_BK: sum -= (5 - fabs ((i-3.5) * (j-3.5)) / 10); break; case CHECKERS_BP: sum -= (1 + (board_heit - 1 - j) / 10.0); break; } } *eval = sum; return RESULT_NOTYET; } static int oldx = -1, oldy = -1; void checkers_reset_uistate () { oldx = -1, oldy = -1; } int checkers_getmove (Pos *pos, int x, int y, Gtkboa.

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singhanubhav1234

Game programming-help

Game programming-help

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BlackJack/Blackjack.c // Blackjack.c : Defines the entry point for the console application. // #include <Windows.h> #include <stdlib.h> #define CLUBS 0 #define DIAMONDS 1 #define HEARTS 2 #define SPADES 3 enum{ TWO, THREE, FOUR, FIVE, SIX, SEVEN, EIGHT, NINE, TEN, JACK, QUEEN, KING, ACE }; int Deck[52]; int CurrentDealCard; int Dealer[20], Player[20]; int DealerCards, PlayerCards; int DealerScore, PlayerScore; void DoShuffle() { int i, nextcard; int Used[52]; /* Here we clear out Used array to zeros, which indicates no values have been used. */ for (i = 0; i < 52; i++) Used[i] = 0; /* Loop through the deck of cards, there are 52 values */ for (i = 0; i < 52; i++) { /* Here we used a do-while. If the card has already been used, we need to keep generating random numbers until we find a card that has not been used. */ do { nextcard = rand() % 52; /* Value from 0 to 51 */ } while (Used[nextcard] == 1); /* This is our check */ /* Here we set to 1 so that we remember that this card has been used */ Used[nextcard] = 1; /* Finally, put the card in the deck. */ Deck[i] = nextcard; } } void DrawCard(int rank, int suit) { switch (rank) { case TWO: printf("Two "); break; case THREE: printf("Three "); break; case FOUR: printf("Four "); break; case FIVE: printf("Five "); break; case SIX: printf("Six "); break; case SEVEN: printf("Seven "); break; case EIGHT: printf("Eight "); break; case NINE: printf("Nine "); break; case TEN: printf("Ten "); break; case JACK: printf("Jack "); break; case QUEEN: printf("Queen "); break; case KING: printf("King "); break; case ACE: printf("Ace "); break; } switch (suit) { case CLUBS: printf("Clubs"); break; case DIAMONDS: printf("Diamonds"); break; case HEARTS: printf("Hearts"); break; case SPADES: printf("Spades"); break; } } void DisplayShuffledDeck() { int i, suit, rank; for (i = 0; i < 52; i++) { suit = Deck[i] / 13; rank = Deck[i] % 13; DrawCard(rank, suit); printf("\n"); } } void DealCards() { PlayerCards = DealerCards = CurrentDealCard = 0; Player[PlayerCards++] = Deck[CurrentDealCard++]; Dealer[DealerCards++] = Deck[CurrentDealCard++]; Player[PlayerCards++] = Deck[CurrentDealCard++]; Dealer[DealerCards++] = Deck[CurrentDealCard++]; } void DisplayDealtCards() { int i; printf("\n\n\nDealer:\n"); for (i = 0; i < DealerCards; i++) DrawCard(Dealer[i] % 13, Dealer[i] / 13), printf( " " ); printf("Dealer Score is %d\n\n\nPlayer:\n", DealerScore); for (i = 0; i < PlayerCards; i++) DrawCard(Player[i] % 13, Player[i] / 13), printf(" "); printf("Player Score is %d\n\n\n", PlayerScore); } void DisplayChoice() { printf("What would you like to do?\n"); printf("1. Hit\n2. Stand\n"); } int Get ...

BlackJackBlackjack.c Blackjack.c Defines the entry point .docx

BlackJackBlackjack.c Blackjack.c Defines the entry point .docx

BlackJackBlackjack.c Blackjack.c Defines the entry point .docx

C++ You will design a program to play a simplified version of war, using dice instead of cards. There will be only one user, but 2 “players” for the game. The user will indicate the number of rounds to play. The user will also specify for each “player” the number of sides on the dice used and if that player is using regular or loaded dice. For example, one player could have a loaded 10-sided die while the other has a 4-sided die. User should be able to determine how \"loaded\" the die is - 2/3/4 etc times mores likely to return a high number. To play the game, for each round, you roll a die of the appropriate type for each player. The higher result wins. If the results are equal, it is a draw. The winner of the game is the player who won the most rounds. Your program will print out which player won to the user. Die class: requires an input integer N which determines the number of sides on the individual die. It includes a method to return a random integer between 1 and N as the result of rolling the die for once. LoadedDie class: it inherits the behavior and elements of Die, but the number it returns is biased such that the average output of rolling it for several times will be higher than for a Die object. You can determine how you want to realize the biased function. Game class: it will implement the simple dice-rolling game. In the menu function, the user will specify the die sides used by each player (the players can have dice with different number of sides). The user will also indicate if either or both players are using loaded dice, and will enter the number of rounds in the game. The Game class will create the necessary objects, play the game, and display the results to the user. The output results should indicate the side and type (loaded or not) of die used for each player, the number of rounds won by each player (in each round, compare the rolling results, the larger number will win), and the final winner of the game (the player that win more rounds). Solution //main.cpp #include \"Game.hpp\" #include // Note: system(\"CLS\") works with win / visual studio. Use \"clear\" for *nix... // change value in Game.hpp too! #define CLEAR_SCREEN \"clear\" int main(){ int sides, // how many sides the dice should have. rounds, // how many rounds to play in the game. p1isLoaded, // menu choice for if player 1 is using a loaded die. p2isLoaded; // menu choice for if player 2 is using a loaded die. bool p1Loaded, // converted menu choice for if player 1 is using a loaded die. p2Loaded; // converted menu choice for if player 2 is using a loaded die. // main menu system(CLEAR_SCREEN); do { std::cout << std::endl; std::cout << \"Welcome to a dice based game of War.\" << std::endl; std::cout << \"Please choose the number of sides each die should\" << std::endl; std::cout << \"have for this game, or enter \\\"5\\\" to quit.\" << std::endl << std::endl; std::cout << \"1. Both dice will each have 4 sides.\" << std::endl; std::cout << \"2. Both dice will .

C++You will design a program to play a simplified version of war, .pdf

C++You will design a program to play a simplified version of war, .pdf

C++You will design a program to play a simplified version of war, .pdf

//Ifgqueue.h #ifndef LFGQUEUE_H #define LFGQUEUE_H #include \"player.h\" class LFGQueue { public: LFGQueue(int scrimmage_threshold); void add_player(Player* p); bool remove_next_group(Player** players); bool remove_next_scrimmage(Player** players); int player_count(); int position(Player* p); private: class Node { public: Player* p; Node* next; Node* prev; }; void remove_node(Node* n); Node* head; Node* tail; int scrimmage_threshold; int count; }; #endif //************************************************************************** //main.cpp #include #include #include #include #include #include \"lfgqueue.h\" using namespace std; void permute(Player** players, int len) { for (int i = 0; i < len; ++i) swap(players[i], players[i + rand() % (len-i)]); } int main() { // Setup for testing srand(2017); Player* group[3]; Player* scrimmage[6]; Player daria(\"Daria\", Player::Defender); Player daniela(\"Daniela\", Player::Defender); Player diego(\"Diego\", Player::Defender); Player hector(\"Hector\", Player::Hunter); Player hugo(\"Hugo\", Player::Hunter); Player henri(\"Henri\", Player::Hunter); Player berta(\"Berta\", Player::Bard); Player bernardo(\"Bernardo\", Player::Bard); Player brigida(\"Brigida\", Player::Bard); // Test that everything compiles and queues // construct without issue. LFGQueue q1(3); // Test when queue contains a single complete group in // in an undesired order (Bard, Hunter, Defender) q1.add_player(&bernardo); q1.add_player(&hugo); q1.add_player(&daria); assert(q1.player_count() == 3); assert(q1.position(&bernardo) == 1); assert(q1.position(&hugo) == 2); assert(q1.position(&daria) == 3); group[0] = group[1] = group[2] = 0; assert(q1.remove_next_group(group)); assert(group[0] == &daria); assert(group[0]->name == \"Daria\"); assert(group[0]->role == Player::Defender); assert(group[1] == &hugo); assert(group[1]->name == \"Hugo\"); assert(group[1]->role == Player::Hunter); assert(group[2] == &bernardo); assert(group[2]->name == \"Bernardo\"); assert(group[2]->role == Player::Bard); assert(q1.player_count() == 0); cout << \"20\\% earned.\" << endl; // Test what happens when not enough group group[0] = group[1] = group[2] = 0; assert(!q1.remove_next_group(group)); assert(group[0] == 0); assert(group[1] == 0); assert(group[2] == 0); for (int i = 0; i < 6; ++i) scrimmage[i] = 0; assert(!q1.remove_next_scrimmage(scrimmage)); for (int i = 0; i < 6; ++i) assert(scrimmage[i] == 0); cout << \"25\\% earned.\" << endl; // Test what happens when two full groups of players // not in the right order (Def, Hunt, Hunt, Bard, Bard, Def) q1.add_player(&daria); q1.add_player(&hector); q1.add_player(&hugo); q1.add_player(&bernardo); q1.add_player(&berta); q1.add_player(&daniela); assert(q1.player_count() == 6); assert(q1.position(&daria) == 1); assert(q1.position(&hector) == 2); assert(q1.position(&hugo) == 3); assert(q1.position(&bernardo) == 4); assert(q1.position(&berta) == 5); assert(q1.position(&daniela) == 6); group[0] = group[1] = group[2] = 0;.

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Ifgqueue.h#ifndef LFGQUEUE_H #define LFGQUEUE_H#include pl.pdf

Ifgqueue.h#ifndef LFGQUEUE_H #define LFGQUEUE_H#include pl.pdf

Variants have been around in C++ for a long time and C++17 now has std::variant. We will compare inheritance and std::variant for their ability to model sum-types (a fancy name for tagged unions). We will visit std::visit and discuss how it helps us model the pattern matching idiom. Immutability is one of the core pillars of Functional Programming (FP). C++ now allows you to model deep immutability; we'll see a way to do that using the standard library. We'll explore if `return std::move(*this)` makes any sense in C++. Immutability may be a reason for that.

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New Tools for a More Functional C++

New Tools for a More Functional C++

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मलय केशव

In Java using Eclipse, I\'m suppose to write a class that encapsulates a tic tac toe board using two dimensional arrays. It should only involve the human player vs. the computer, and should randomly select who should use \'X\' or \'O\' and whether the human player or the computer should go first. Verify that all moves by the human player are to a valid space on the tic-tac-toe board, and an incorrect choice should not halt or terminate the game. Below is my Java program that is currently a work in progress. Can you help me remodify it? Thanks. import java.util.Scanner; public class LeavinesTicTacToe { public static Scanner sc = new Scanner(System.in); public static void main(String[] args) { final int SIZE = 3; char[][] board = new char[SIZE][SIZE]; // game board resetBoard(board); // initialize the board (with \' \' for all cells) // First, welcome message and display the board. System.out.println(\"===== WELCOME TO THE TIC-TAC-TOE GAME!! =====\ \"); showBoard(board); // Then ask the user which symbol (x or o) he/she wants to play. System.out.print(\" Which symbol do you want to play, \\\"x\\\" or \\\"o\\\"? \"); char userSymbol = sc.next().toLowerCase().charAt(0); char compSymbol = (userSymbol == \'x\') ? \'o\' : \'x\'; // Also ask whether or not the user wants to go first. System.out.println(); System.out.print(\" Do you want to go first (y/n)? \"); char ans = sc.next().toLowerCase().charAt(0); int turn; // 0 -- the user, 1 -- the computer int remainCount = SIZE * SIZE; // empty cell count // THE VERY FIRST MOVE. if (ans == \'y\') { turn = 0; userPlay(board, userSymbol); // user puts his/her first tic } else { turn = 1; compPlay(board, compSymbol); // computer puts its first tic } // Show the board, and decrement the count of remaining cells. showBoard(board); remainCount--; // Play the game until either one wins. boolean done = false; int winner = -1; // 0 -- the user, 1 -- the computer, -1 -- draw while (!done && remainCount > 0) { // If there is a winner at this time, set the winner and the done flag to true. done = isGameWon(board, turn, userSymbol, compSymbol); // Did the turn won? if (done) winner = turn; // the one who made the last move won the game else { // No winner yet. Find the next turn and play. turn = (turn + 1 ) % 2; if (turn == 0) userPlay(board, userSymbol); else compPlay(board, compSymbol); // Show the board after one tic, and decrement the rem count. showBoard(board); remainCount--; } } // Winner is found. Declare the winner. if (winner == 0) System.out.println(\"\ ** YOU WON. CONGRATULATIONS!! **\"); else if (winner == 1) System.out.println(\"\ ** YOU LOST.. Maybe next time :) **\"); else System.out.println(\"\ ** DRAW... **\"); } public static void resetBoard(char[][] brd) { for (int i = 0; i < brd.length; i++) for (int j = 0; j < brd[0].length; j++) brd[i][j] = \' \'; } public static void showBoard(char[][] brd) { int numRow = brd.length; int numCol = brd[0].length; System.out.println(); // First write the column he.

In Java using Eclipse, Im suppose to write a class that encapsulat.pdf

In Java using Eclipse, Im suppose to write a class that encapsulat.pdf

In Java using Eclipse, Im suppose to write a class that encapsulat.pdf

public interface Game // Note *interface* in place of *class* { /// play the game and return the final score /// where a higher score should be better, /// and a negative score is allowed. int play(); // Note semicolon in place of a body // You can have multiple method headings declared } -------------------------------------------------------------------------------------------------------------- import java.util.*; /// Starting point for Interface Lab. public class PlayGames { private static Scanner in; private static Random rand = new Random(); private static int gameCount = 0; public static Game popRandom(Game[] g) { int n = gameCount; int i = rand.nextInt(n); Game ret = g[i]; g[i] = g[n-1]; gameCount--; return ret; } public static void main(String[] args) { Game[] games = new Game[10]; // Note Game as a type games[gameCount] = new AdditionGame(rand, 100); gameCount++; // next index to put a Game at // write at least 2 more different types of Game classes // and add a new one of each type to games // ... in = new Scanner(System.in); int totScore = 0; do { Game g = popRandom(games); totScore += g.play(); // use numerical result from the game } while (gameCount > 0 && agree(\"Want a game? \")); System.out.println(\"Thanks for Playing!\"); System.out.println(\"Your total score is \" + totScore); } public static boolean agree(String prompt) { System.out.print(prompt); String input = in.next(); if (input.equalsIgnoreCase(\"y\")) return true; return false; } -------------------------------------------------------------------------------------------------------------------- -- import java.util.*; public class AdditionGame implements Game // note implements!! { private Random rand; private int n; // Constructor for objects of class AdditionGame public AdditionGame(Random r, int big) { rand = r; n = big; } // play all games and keep score. public int play() // exactly matches heading in Game interface { final int numGames = 3; Scanner in = new Scanner(System.in); int score = 0; System.out.println(\"Welcome to the addition game! We\'ll now play \" + numGames + \" rounds.\"); for (int i = 0; i < numGames; i++) { int x = rand.nextInt(n), y = rand.nextInt(n), ans = x+y; System.out.print(String.format(\"Enter the sum: %d + %d = \", x, y)); int val = in.nextInt(); if (ans == val) { System.out.println(\"Correct!\"); score++; } else System.out.println(\"Wrong! Right answer is \" + ans); } System.out.println(\"Thanks for playing the addition game. Your score is \" + score + \".\"); System.out.println(); return score; } } -------------------------------------------------------------------------------------------------------------------- --- Create two classes that implement a Game interface: ------------------------------------ There is a Game interface defined, and also a PlayGames class that uses objects from classes that implement that interface. The Game interface declares a single abstract method play that returns an int, the score from playing the gam.

public interface Game Note interface in place of class { .pdf

public interface Game Note interface in place of class { .pdf

public interface Game Note interface in place of class { .pdf

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PLEASE can do this in NETBEAN I need that way thank very muchManca.pdf

PLEASE can do this in NETBEAN I need that way thank very muchManca.pdf

PLEASE can do this in NETBEAN I need that way thank very muchManca.pdf

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Please help with this. program must be written in C# .. All of the g.pdf

Please help with this. program must be written in C# .. All of the g.pdf

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#include stdio.h #include string.h #include stdlib.h #in.pdf

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In Java using Eclipse, Im suppose to write a class that encapsulat.pdf

In Java using Eclipse, Im suppose to write a class that encapsulat.pdf

In Java using Eclipse, Im suppose to write a class that encapsulat.pdf

public interface Game Note interface in place of class { .pdf

public interface Game Note interface in place of class { .pdf

public interface Game Note interface in place of class { .pdf

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Consider these vaccinations MMR, DPT and SARS-2 coronavirus (COVID-.pdf

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Consider the following wage regression in which you have data on gen.pdf

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core issue in frank by ocbc singapore case study In 2010, Jin Kang Zwicky, the vice president of Oversea-Chinese Banking Corporation Limited (OCBC Bank)s Experience Design & Group Customer Experience division, and her team conducted ethnographical studies to understand the concerns of millennials students to young working adults. They applied design thinking methodology to the banks processes to uncover the underlying needs of the banks customers. Their aim was to design user-centred services to help millennials become confident and capable of making strong financial decisions (Paperny, 2015). The outcome of the research and prototyping exercise was FRANK by OCBC designed with core values of delivering simple, stylish and meaningful banking experience..

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CONTRATO DE ARRENDAMIENTO COMERCIAL Este Contrato de Arrendamiento C.pdf

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Contesta las preguntas del siguiente prrafo: Debera responsabilizarse a Ford por las enfermedades de los residentes? Por qu o por qu no? Consulte los videos en http://toxiclegacy.northjersey.com (enlaces a un sitio externo). Los videos sugieren que la contaminacin debera preocuparte? Si es as por qu? Qu diran las diversas formas de tica ambiental descritas en este captulo sobre las acciones de Ford? En el borde Residuos txicos de Ford La fabricacin de automviles produce un flujo constante de lquidos y slidos txicos, y desde mediados de la dcada de 1950 hasta alrededor de 1980, Ford Motor Company arroj miles de toneladas de los desechos de su fbrica Mahwah en un rea montaosa boscosa de 500 acres en Ringwood, Nueva Jersey. incluyendo pinturas sin usar, solventes, diluyentes de pintura, cidos de batera y otros productos qumicos. Entonces era legal arrojar desechos en terrenos baldos, y Ford era dueo del rea boscosa. Sin embargo, un memorando escrito en en ese momento por un ejecutivo de Ford dijo: El rea utilizada como vertedero durante muchos aos se est filtrando a un suministro pblico de agua y representa un pasivo contingente.23 El lodo colorido, que contena benceno, plomo, arsnico, antimonio, , y otras sustancias venenosas, algunas cancergenas, como el cromo que causa hemorragias nasales, se arrojaron en lo que los lugareos llaman Sludge Hill. La sustancia resbaladiza atrajo a los nios locales que jugaban con ella y, a menudo, volvan a casa con fuertes hemorragias nasales. Un residente, Wayne Mann, dijo en 2009: Yo era uno de esos nios que sola subir a Sludge Hill. . . [Yo] tomara el cap de un automvil y bajara, manejando la direccin a mano en el lodo hmedo. Te pintas la cara. Lo lames, lo que sea. 24 Muchos residentes, incluido Mann, estn enfermos. Algunos ya han muerto de cncer. Los adultos y los nios sufren erupciones cutneas misteriosas, trastornos sanguneos raros, cnceres, asma y otras enfermedades inusuales. Las 600 personas que viven en el rea creen que los lodos txicos causaron sus enfermedades y que muchos estn enfermos o muriendo como para culpar a la casualidad de las enfermedades. El rea est poblada por Ramapough, un grupo indio empobrecido que dice ser vctima de la injusticia ambiental. Aunque Ford admite que arrojaron los productos qumicos, John Holt, un vocero de la compaa, insiste en que los productos qumicos no estn causando las enfermedades: No han encontrado una mayor incidencia de cncer o cualquier otra cosa aqu adems del cncer de pulmn. informaron que las tasas de cncer de vejiga y linfoma no Hodgkin tambin son elevadas, pero sus nmeros son demasiado pequeos para descartar una coincidencia. Las estadsticas no muestran causa y efecto, por lo que no hay forma de saber con certeza qu caus las enfermedades. Holt seala que Ford pas 10 aos limpiando el sitio y en 1994, la EPA de EE. UU. y el Departamento de Proteccin Ambiental de Nueva Jersey certificaron que Ford hizo un trabajo adecuado. Sin embargo, en 2006, la EPA descubri.

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