Grafana in space: Monitoring Japan's SLIM moon lander in real time
Chi square test
1. Devi Aliyah Vishva Vidhyalaya, Indore
Χ 2 (CHI - SQUARE) TEST:
AS A TEST OF INDEPENDECE
Submitted To Submitted By
Mr. Ritesh Tiwari Miss. Nayna Azad
Lecturer M.Phil 1st Sem
2. DEFINITION OF CHI-SQUARE TEST
INTRODUCTION TO CHI-SQUARE TEST
CHI-SQUARE AS A TEST FOR COMPARING VARIANCE
CHI-SQUARE AS A NON-PARAMETRIC TEST
CONDITIONS FOR THE APPLICATION OF χ2 TEST
CHARACTERISTICS OF χ2 TEST
STEPS INVOLVED IN APPLYING CHI-SQUARE TEST AND
A NUEMERICAL TO EXPLAIN
SIGNIFICANCE OF CHI SQUARE TEST
CONCLUSION
CONTENTS:
3. 33
The Chi-Square (χ2) test could be defined as a
Non-parametric test that is used to test
hypotheses about distributions of frequencies
across categories of data. It can be used to test
for comparing variance too.
DEFINATION OF CHI-SQUARE TEST
4. 44
One way to do this is to work out what we
would expect to find if there was no relationship
between them (the usual null hypothesis) and
what we actually observe.
The test we use to measure the differences
between what is observed and what is expected
according to an assumed hypothesis is called
the chi-square test.
We often have occasions to make comparisons
between two characteristics of something to see
if they are linked or related to each other.
INTRODUCTION TO CHI-SQUARE TEST
5. 55
The chi-square test is often used to judge the
significance of population variance.
Formula of Chi-square test of comparing
variance:
χ 2 = σ2
s /σ2
p (n-1)
Where
σ2
s = variance of the sample
σ2
p = variance of the population
(n-1) = degree of freedom, n being the number
of items in the sample.
CHI-SQUARE TEST AS A TEST FOR
COMPARING VARIANCE
7. 77
Chi-square is an important test and as such no
rigid assumptions are necessary in respect of
the type of population. We require only the
degree of freedom (implicitly of course the size
of the sample) for using this test. As a non-
parametric test, chi square can be used
(i) as a test of goodness of fit,
(ii) as a test of homogeneity and
(iii) as a test of independence.
CHI-SQUARE AS A NON-PARAMETRIC TEST
8. 88
As a test of goodness of fit -
It is used to test the single variable i.e., it is
fit to the population or not. It means
Sample is supporting the population or not.
As a test of goodness of fit -
It is used to test a single categorical variable
from two different populations. It is used to
determine whether frequency counts are
distributed identification across different
populations.
As a test of independence –
To explain that variable are how much
attached with each other.
Continued...
9. 99
There must be two observed set of data or one
observed set and one expected set [generally
there are n - rows and c - columns].
The number of observations or items must be
reasonably large [i.e., normally equal or greater
than 50].
Expected frequency should not be very small
should not be less than five.
Observations recorded and used are collected
on random basis.
All the times in the sample must be
independent.
CONDITIONS FOR THE APPLICATIONS OF
χ2 TEST
10. 1010
Chi-square is based on the observed
frequency and not on the parameters mean and
standard deviation.
It is a technique for testing the hypothesis and
not used for the purposes of estimation.
It is useful test for research and is used to
complex contingency table with several Classes.
In contingency table variables are arranged in
different formats in a table; It is a way to
present the different attributes of a population.
The text involves less mathematical details
and there is no need of any parameter values
eg. Mean and standard deviation.
CHARACTERISTICS OF χ2 TEST
11. 1111
Step 1-
First of all expected frequencies are calculated
on the basis of null hypothesis. The expected
frequency of any given cell is calculated on the
basis of following formula:
Expected frequency of any cell = (Row total of
that cell) X (Column Total of the cell) / Grand
Total of the Table.
Step 2-
Obtained difference between observed and
expected frequency and obtained square of such
differences, i.e. (Oi-Ei)2
STEPS INVOLVED IN CHI-SQUARE
12. 1212
Step 3-
Divide the quantity (Oi-Ei) by the
corresponding expected frequencies to get (Oi-
Ei) 2 / Ei
Step 4-
Find the summation (∑) of there value to get ∑
(Oi-Ei) 2 / Ei
This is the required chi-square value or χ2 value
as the formula of χ2 test is as follows:
χ2 =∑ (Oi-Ei) 2 / Ei
Step 5-
Thus the calculated value of chi-square should
be compared with relevant table value of χ2 and
inference can be drawn as stated above.
Continued...
13. 1313
Data obtained during out break of small pox in town.
Test the effectiveness of vaccination in preventing the attack from
smallpox. Test your result with the help of χ2 test at 5 % level of
significance.
Attributes:
Vaccination
Attacked
Null Hypothesis (H0)- Vaccination (A) and Small Pox (B) are
Independent and i.e., vaccination is not effective in small pox
prevention.
Alternative Hypothesis (Ha)- Vaccination (A) is effective in small
pox prevention.
Numerical
Attacked (B) Not Attacked (b) Total
Vaccinated (A) 31 469 500
Not vaccinated (a) 185 1315 1500
Total 216 1784 2000
14. 1414
Solution
Contingency Table:
Calculation of Expected Frequencies for (CT):
AB = 500 X 216 / 2000 = 54
aB = 1500 X 216 / 2000 = 162
Ab = 500 X 1784 / 2000 = 446
Ab = 1500 X 1784 / 2000= 1338
Continued...
Attacked (B) Not Attacked (b) Total
Vaccinated (A) (AB) 54 (Ab) 446 500
Not vaccinated
(a)
(aB) 162 (ab) 1338 1500
Total 216 1784 2000
15. 1515
Putting the value in table:
Continued...
Group Oi Ei Oi - Ei (Oi - Ei)2 (Oi - Ei)2 / Ei
AB 31 54 31-54 = -23 529 9.796
Ab 469 446 469-446 = 23 529 1.186
aB 185 162 185-162 = 23 529 3.265
ab 1315 1338 1315-1338 = -23 529 0.395
∑ (Oi - Ei)2 / Ei
14.642
16. 1616
χ2 = (Oi - Ei)2 / E2
χ2 = 14.642
Degrees of freedom in this case = (r-1) (C-1)
Degrees of freedom in this case = (2-1) (2-1)
Degrees of freedom in this case = (1) (1)
Degrees of freedom in this case = 1
Table value of χ2 for 1 degree of freedom at 5% level of
significance is 3.841. The calculated value of χ2 is much
higher than this table value and hence the result of the
experiment does not support the hypothesis. We can,
thus, conclude that vaccination is effective in preventing
the attack from smallpox.
Continued...
17. 1717
SIGNIFICANCE OF THE CHI-SQUARE TEST IS AS FOLLOW:
It is very useful to check the Interdependence of two variables on
each other.
Chi Square can also be used to test differences between two or
more actual samples.
Being a non-parametric tests chi-square test is much easier to
compute, and also to apply.
The Chi Square (X2) test is undoubtedly the most important and
most used member of the non-parametric family of statistical tests.
Chi Square is employed to test the difference between an actual
sample and another hypothetical or previously established
distribution such as that which may be expected due to chance or
probability.
Chi square test can be used to treat data which have been
measured on nominal (classificatory) scales. Such data cannot, on
any logical basis, be ordered numerically, hence there is no
possibility of using parametric statistical tests which require
numerical data.
SIGNIFICANCE OF CHI-SQUARE TEST
18. 1818
As conclusion we can say that the chi-square
test is an important test amongst the several
tests of significance developed by statisticians.
Being a non-parametric test It’s calculations are
easier than other tests. It tests for effect of one
variable over the other, hence it is very helpful
to understand the effectiveness of products. It is
very useful for all researchers to
Test goodness of fit.
Test the significance of association between
two attributes.
Test the homogeneity or the significance of
population variance.
Conclusion
