Celestial Navigation 3.0
2014.04.22 Yen @ NTU-AST
http://www.exploratorium.edu/neverlost
Navigation
is not about you, or your mind, or what you
can do. It's not about the sun and stars.
It's really about Everything.
-- Shorty Bertelmann, Navigator
Navigation
is about…
# 1
Speed
- sandglass
- log, knot
# 2
Direction
-sun stone
-compass
# 3
Position Fix
(before 18 century)
-lead 測深儀
-astrolabe 觀象儀
-cross-staff 橫桿測天儀
-back-staff 背桿測天儀
-quadrant 象限儀
-octans 八分儀
( coastal sailing 海岸線航法 )
( lead )
( parallel sailing 平緯航法 )
(astrolabe)
( back-staff )
(quadrant)
The navigator always knows his Latitude,
but never knows his Longitude…
Until 18 century !
Tech Progress:
New Instruments in 18 century
## Before
Nocturnal – Only useful in the night
## New Instruments :
Chronometer & Sextant
1772, Harrison, H5
## New Instruments :
Chronometer & Sextant
## New Instruments :
Chronometer & Sextant
http://en.wikipedia.org/wiki/File:Using_sextant_swing.gif
Review :
3 Systems of Coordinates
## 1
The
Terrestrial
Coordinate
System
30oN
## 2
The
Celestial
Coordinate
System
North Celestial Pole
( Pn )
天北極
Local Hour Angle
( LHA )
當地時角
Polar Distance
極距
Declination
( Dec )
赤緯
Celestial Meridian
天子午線
## 2 ( test )
The
Celestial
Coordinate
System
Dec=23.5
Q1: where is LHA?
Q2: polar distance = ?
LHA=120
## 2
The
Celestial
Coordinate
System
春分點
North Celestial Pole
( Pn )
天北極
Sidereal Hour Angle
( SHA )
恆星時角
Declination
( Dec )
赤緯
## 2
The
Celestial
Coordinate
System
Greenwich
Celestial
Meridian
格林威治天子午線
Greenwich Hour Angle
( GHA )
格林威治天子午線
Summary for Hour Angle
All West
• LHA –
• SHA –
• GHA - Greenwich
## 2
The
Celestial
Coordinate
System
♈
Relation
between
## 1 & ## 2
## 3
The
Horizon
Coordinate
System
Zenuth
( Z )
天頂
Altitude
( Hc)
高度/仰角
Zenith Distant
( zd )
天頂距
Azimuth Angle
( Az)
方位角
Azimuth
( Zn )
真方位
Celestial Horizon
天水平線
## 3 ( test )
The
Horizon
Coordinate
System
Hc =50
Az=150
Q1: Zenith distance = ?
Q2: Azimuth = ?
## 1+2+ 3
Combine the
3 Systems of
Coordinates
Are you ready ?
Lat of =35oN
Hc=20o
Dec of = 20oS
Q1: zenith distance = ?
Q2: polar distance =?
Theory :
Fix Position
## Position Fix :
in plane geometry (I)
Situation:
1. You do not know where you are.
2. All you know is the positions
of A and D , their altitudes
(60o,45o), and length of AB and
DE
How to solve your position ?
D
A
E
B
1
√3
## Position Fix :
in plane geometry (I)
Solution:
1.
for A, altitude = 60, RA=1
for D, altitude = 45, RD=1
2.
plot the circles with radius = RA
and RD.
3.
C must lie on the intersections.
A
√3
## Position Fix :
in plane geometry (I)
Solution:
1.
for A, altitude = 60, RA=1
for D, altitude = 45, RD=1
2.
plot the circles with radius = RA
and RD.
3.
C must lie on the intersections.
A
B
D
E
45
45
45
60
60
60
C
C
1
√3
## Position Fix :
in spherical geometry (I)
Where H1 > Hc > H2
Geometric Position
天體於地球之投影位置
Circle of equal Altitude
等高度圈
Pn
Assumed Position
假定船位
## Position fix :
in spherical geometry (I)
What is the length between AP and GP?
1) the angle of XZ = zenith dis.
2) 1 nautical mile = 1 海浬
(on earth) =1’arc
= 1/60° arc
≒ 1852 km
Problem of High Altitude Method (高高
度觀測法)
1) radius too large
2) distortion on sea chart
AP
Intercept Method
截距法
## Position fix :
in spherical geometry (II)
sine rule:
sin(a)/sin(A) = sin(b)/sin(B) = sin(c)/sin(C)
cosine rule:
cos(a) = cos(b) cos(c) + sin(b) sin(c) cos(A)
cos(b) = cos(c) cos(a) + sin(c) sin(a) cos(B)
cos(c) = cos(a) cos(b) + sin(a) sin(b) cos(C)
Positional Astronomy: Spherical trigonometry http://star-www.st-and.ac.uk/~fv/webnotes/chapter2.htm
Spherical Triangle
## Position fix :
in spherical geometry (II)
A =當地時角(LHA)
B= 天體角
C =方位角(Az)
Terrestrial Triangle
a = 90 - Hc
b= 90 -L
c =90 -Dec
sin(Hc) =sin(L)sin(Dec)+cos(L)cos(Dec)cos(LHA)
sin(C) =cos (Dec)sin(LHA)/ sin(Hc)
@ Northern Hemisphere
North Pole
GP
AP
## Position fix :
in spherical geometry (II)
Test: 已知兩邊夾一角,求對邊
觀測者所在緯度45度N,天體赤緯5度N,當地時角(LHA)60度,
試求:天體之高度。
Hint: sin(Hc) =sin(L)sin(Dec)+cos(L)cos(Dec)cos(LHA)
Solution:
sin(Hc) =sin(L)sin(Dec)+cos(L)cos(Dec)cos(LHA)
=sin(45)sin(5)+cos(45)cos(5)cos(60)
=0.41384
Hc = 24°26.8’#
周和平<天文航海學> 第七章 217頁 例1
## Position fix :
in spherical geometry (II)
That’s okay ! ( pad )
There are some Tables, e.g. No.229
,that keep you away from mathematics
during Sight Reduction !
We will be soon there !
Hc H0
GP
90-Hc
Altitude
Intercept
Hc > H0 , Away
H0 > Hc , Toward
(Homoto, H0 more Toward)
AP
## Position fix :
in spherical geometry (II)
## Position fix :
in spherical geometry (II)
AP
Intercept
Line of Position 天文位置線
## Position fix :
in spherical geometry (II)
## Position fix :
in spherical geometry (II)
We got the
Position !
Sight Reduction
using
Nautical Almanac and Table No.229
Warm up
1990年6月5日,某船2000 DR L41°34.8’N,
λ17°10.5W,於ZT 20-01-56,以船用六分儀觀
測Pollux ( 北河三 ),得H028°02.1’。試以航海
曆及229表,求AP、a (截距 ) 及Zn。
( key: GP,LHA,AP )
Aztec sailing: http://www.aztecsailing.co.uk/theory/ch6%20sect%202.html
周和平<天文航海學> 第九章 314頁 例2改寫
Nautical Almanac
Parameter:
1.GMT
Download @ http://navsoft.com/downloads.html
Time Zone
Warm up
1990年6月5日,某船2000 DR L41°34.8’N,
λ17°10.5W,於ZT 20-01-56,以船用六分儀觀
測Pollux,得H028°02.1’。試以航海曆及229
表,求AP、a及Zn。
( key: GP,LHA,AP )
Zone time ( ZT ) 20-01-56
Zone difference ( ZD) +1
_________________________________________________
Greenwich mean time (GMT) 21-01-56
Warm up
1990年6月5日,某船2000 DR L41°34.8’N,
λ17°10.5W,於ZT 20-01-56,以船用六分儀觀
測Pollux,得H028°02.1’。試以航海曆及229
表,求AP、a及Zn。
( key: GP,LHA,AP )
Greenwich mean time (GMT) = 21-01-56
GHA ♈ 209°01.5’
SHA ( Pollux ) 243°49.1
____________________________________________________
GHA ( Pollux ) 452°50.6’
=93°19.7’
Warm up
1990年6月5日,某船2000 DR L41°34.8’N,
λ17°10.5W,於ZT 20-01-56,以船用六分儀觀
測Pollux,得H028°02.1’。試以航海曆及229
表,求AP、a及Zn。
( key: GP,LHA,AP )
GHA ( Pollux ) = 93°19.7’
Aλ 17°19.7’W
____________________________________________________
LHA ( Pollux ) 76°
Dec. (Pollux) 28°03.1’N
aL 42°
Warm up
1990年6月5日,某船2000 DR L41°34.8’N,
λ17°10.5W,於ZT 20-01-56,以船用六分儀觀
測Pollux,得H028°02.1’。試以航海曆及229
表,求AP、a及Zn。
( key: GP,LHA,AP )
LHA ( Pollux ) 76°
Dec. (Pollux) 28°03.1’N
aL 42°
____________________________________________________
已知兩邊一夾角,求對邊 ( Hc ) 與方位角 ( Z ) 。
Help me, Table No.229 !!
Table No.229
Parameter:
1. LHA
2. Dec
3. aL
Download @National Geospatial-Intelligence Agency ( https://www1.nga.mil/‎)
Online sight reduction ( http://www.csgnetwork.com/directnautsrt1.html )
Warm up
1990年6月5日,某船2000 DR L41°34.8’N,
λ17°10.5W,於ZT 20-01-56,以船用六分儀觀測
Pollux,得H028°02.1’。試以航海曆及229表,求
AP、a及Zn。 ( key: GP,LHA,AP )
LHA ( Pollux ) = 76°
Dec. (Pollux) = 28°03.1’N
aL = 42°
____________________________________________________
Z 76 .4°
Rule 360 °
_____________________________________________________
Zn = 283.6 °
Hc = 28 °13.3'
Warm up
Pollux AP
Line of Position
42°N
17°W
AP (aL , aλ ) ( 42°00.0N , 19°19.7W)
A = Hc-Ho 11.2’Away
Zn 283.6°
Practice
2013年5月2日,某船 0200 DR L45°00.0’N,
λ23°23.0’W,於ZT 02-01-59,以船用六分儀
觀測 Deneb( 天津四 ),得H052°18.0’。
試以航海曆及229表,求:LHA、Hc、Z、a以及
天文位置線 ( LOP )。
2013年5月2日,某船 0200 DR L45°00.0’N,
λ23°23.0’W,於ZT 02-01-59,以船用六分儀觀測
Deneb( 天津四 ),得H052°48.0’。試以航海曆及229表,
求:LHA、Hc、Zn、a以及天文位置線。
Solution:
ZT 02-01-59
ZD +2 e
GMT 04-01-59
GHA ♈ 280°14.3’
SHA + 49°31.5’ 45°19.5N
GHA 329°45.8’
aλ - 23°45.8’
LHA 306°
Dec 45°19.5’
aL 45°00.0’
Hc 52°33.0’
Z 70.2°
Hc 52°33.0’
H0 52°48.0’
a 15.0’Toward
Z 70.2°
Rule -) 360.0°
Zn 289.8°
Reference
周和平 <天文航海學>
www.owenpalmiotti.com
Thank you for listening !

Celestial navigation 2014 (pdf)

  • 1.
    Celestial Navigation 3.0 2014.04.22Yen @ NTU-AST http://www.exploratorium.edu/neverlost
  • 2.
    Navigation is not aboutyou, or your mind, or what you can do. It's not about the sun and stars. It's really about Everything. -- Shorty Bertelmann, Navigator
  • 3.
  • 4.
  • 5.
  • 6.
    # 3 Position Fix (before18 century) -lead 測深儀 -astrolabe 觀象儀 -cross-staff 橫桿測天儀 -back-staff 背桿測天儀 -quadrant 象限儀 -octans 八分儀 ( coastal sailing 海岸線航法 ) ( lead )
  • 7.
    ( parallel sailing平緯航法 ) (astrolabe)
  • 9.
  • 10.
  • 12.
    The navigator alwaysknows his Latitude, but never knows his Longitude… Until 18 century !
  • 13.
  • 14.
    ## Before Nocturnal –Only useful in the night
  • 15.
    ## New Instruments: Chronometer & Sextant 1772, Harrison, H5
  • 16.
    ## New Instruments: Chronometer & Sextant
  • 17.
    ## New Instruments: Chronometer & Sextant http://en.wikipedia.org/wiki/File:Using_sextant_swing.gif
  • 18.
    Review : 3 Systemsof Coordinates
  • 19.
  • 20.
    ## 2 The Celestial Coordinate System North CelestialPole ( Pn ) 天北極 Local Hour Angle ( LHA ) 當地時角 Polar Distance 極距 Declination ( Dec ) 赤緯 Celestial Meridian 天子午線
  • 21.
    ## 2 (test ) The Celestial Coordinate System Dec=23.5 Q1: where is LHA? Q2: polar distance = ? LHA=120
  • 22.
    ## 2 The Celestial Coordinate System 春分點 North CelestialPole ( Pn ) 天北極 Sidereal Hour Angle ( SHA ) 恆星時角 Declination ( Dec ) 赤緯
  • 23.
  • 24.
    Summary for HourAngle All West • LHA – • SHA – • GHA - Greenwich ## 2 The Celestial Coordinate System ♈
  • 25.
  • 26.
    ## 3 The Horizon Coordinate System Zenuth ( Z) 天頂 Altitude ( Hc) 高度/仰角 Zenith Distant ( zd ) 天頂距 Azimuth Angle ( Az) 方位角 Azimuth ( Zn ) 真方位 Celestial Horizon 天水平線
  • 27.
    ## 3 (test ) The Horizon Coordinate System Hc =50 Az=150 Q1: Zenith distance = ? Q2: Azimuth = ?
  • 29.
    ## 1+2+ 3 Combinethe 3 Systems of Coordinates Are you ready ?
  • 30.
    Lat of =35oN Hc=20o Decof = 20oS Q1: zenith distance = ? Q2: polar distance =?
  • 31.
  • 32.
    ## Position Fix: in plane geometry (I) Situation: 1. You do not know where you are. 2. All you know is the positions of A and D , their altitudes (60o,45o), and length of AB and DE How to solve your position ? D A E B 1 √3
  • 33.
    ## Position Fix: in plane geometry (I) Solution: 1. for A, altitude = 60, RA=1 for D, altitude = 45, RD=1 2. plot the circles with radius = RA and RD. 3. C must lie on the intersections. A √3
  • 34.
    ## Position Fix: in plane geometry (I) Solution: 1. for A, altitude = 60, RA=1 for D, altitude = 45, RD=1 2. plot the circles with radius = RA and RD. 3. C must lie on the intersections. A B D E 45 45 45 60 60 60 C C 1 √3
  • 35.
    ## Position Fix: in spherical geometry (I) Where H1 > Hc > H2 Geometric Position 天體於地球之投影位置 Circle of equal Altitude 等高度圈 Pn Assumed Position 假定船位
  • 36.
    ## Position fix: in spherical geometry (I) What is the length between AP and GP? 1) the angle of XZ = zenith dis. 2) 1 nautical mile = 1 海浬 (on earth) =1’arc = 1/60° arc ≒ 1852 km Problem of High Altitude Method (高高 度觀測法) 1) radius too large 2) distortion on sea chart AP
  • 37.
    Intercept Method 截距法 ## Positionfix : in spherical geometry (II)
  • 38.
    sine rule: sin(a)/sin(A) =sin(b)/sin(B) = sin(c)/sin(C) cosine rule: cos(a) = cos(b) cos(c) + sin(b) sin(c) cos(A) cos(b) = cos(c) cos(a) + sin(c) sin(a) cos(B) cos(c) = cos(a) cos(b) + sin(a) sin(b) cos(C) Positional Astronomy: Spherical trigonometry http://star-www.st-and.ac.uk/~fv/webnotes/chapter2.htm Spherical Triangle ## Position fix : in spherical geometry (II)
  • 39.
    A =當地時角(LHA) B= 天體角 C=方位角(Az) Terrestrial Triangle a = 90 - Hc b= 90 -L c =90 -Dec sin(Hc) =sin(L)sin(Dec)+cos(L)cos(Dec)cos(LHA) sin(C) =cos (Dec)sin(LHA)/ sin(Hc) @ Northern Hemisphere North Pole GP AP ## Position fix : in spherical geometry (II)
  • 40.
    Test: 已知兩邊夾一角,求對邊 觀測者所在緯度45度N,天體赤緯5度N,當地時角(LHA)60度, 試求:天體之高度。 Hint: sin(Hc)=sin(L)sin(Dec)+cos(L)cos(Dec)cos(LHA) Solution: sin(Hc) =sin(L)sin(Dec)+cos(L)cos(Dec)cos(LHA) =sin(45)sin(5)+cos(45)cos(5)cos(60) =0.41384 Hc = 24°26.8’# 周和平<天文航海學> 第七章 217頁 例1 ## Position fix : in spherical geometry (II)
  • 42.
    That’s okay !( pad ) There are some Tables, e.g. No.229 ,that keep you away from mathematics during Sight Reduction ! We will be soon there !
  • 43.
    Hc H0 GP 90-Hc Altitude Intercept Hc >H0 , Away H0 > Hc , Toward (Homoto, H0 more Toward) AP ## Position fix : in spherical geometry (II)
  • 44.
    ## Position fix: in spherical geometry (II)
  • 45.
    AP Intercept Line of Position天文位置線 ## Position fix : in spherical geometry (II)
  • 46.
    ## Position fix: in spherical geometry (II) We got the Position !
  • 47.
  • 48.
    Warm up 1990年6月5日,某船2000 DRL41°34.8’N, λ17°10.5W,於ZT 20-01-56,以船用六分儀觀 測Pollux ( 北河三 ),得H028°02.1’。試以航海 曆及229表,求AP、a (截距 ) 及Zn。 ( key: GP,LHA,AP ) Aztec sailing: http://www.aztecsailing.co.uk/theory/ch6%20sect%202.html 周和平<天文航海學> 第九章 314頁 例2改寫
  • 49.
    Nautical Almanac Parameter: 1.GMT Download @http://navsoft.com/downloads.html
  • 50.
  • 51.
    Warm up 1990年6月5日,某船2000 DRL41°34.8’N, λ17°10.5W,於ZT 20-01-56,以船用六分儀觀 測Pollux,得H028°02.1’。試以航海曆及229 表,求AP、a及Zn。 ( key: GP,LHA,AP ) Zone time ( ZT ) 20-01-56 Zone difference ( ZD) +1 _________________________________________________ Greenwich mean time (GMT) 21-01-56
  • 52.
    Warm up 1990年6月5日,某船2000 DRL41°34.8’N, λ17°10.5W,於ZT 20-01-56,以船用六分儀觀 測Pollux,得H028°02.1’。試以航海曆及229 表,求AP、a及Zn。 ( key: GP,LHA,AP ) Greenwich mean time (GMT) = 21-01-56 GHA ♈ 209°01.5’ SHA ( Pollux ) 243°49.1 ____________________________________________________ GHA ( Pollux ) 452°50.6’ =93°19.7’
  • 53.
    Warm up 1990年6月5日,某船2000 DRL41°34.8’N, λ17°10.5W,於ZT 20-01-56,以船用六分儀觀 測Pollux,得H028°02.1’。試以航海曆及229 表,求AP、a及Zn。 ( key: GP,LHA,AP ) GHA ( Pollux ) = 93°19.7’ Aλ 17°19.7’W ____________________________________________________ LHA ( Pollux ) 76° Dec. (Pollux) 28°03.1’N aL 42°
  • 54.
    Warm up 1990年6月5日,某船2000 DRL41°34.8’N, λ17°10.5W,於ZT 20-01-56,以船用六分儀觀 測Pollux,得H028°02.1’。試以航海曆及229 表,求AP、a及Zn。 ( key: GP,LHA,AP ) LHA ( Pollux ) 76° Dec. (Pollux) 28°03.1’N aL 42° ____________________________________________________ 已知兩邊一夾角,求對邊 ( Hc ) 與方位角 ( Z ) 。 Help me, Table No.229 !!
  • 55.
    Table No.229 Parameter: 1. LHA 2.Dec 3. aL Download @National Geospatial-Intelligence Agency ( https://www1.nga.mil/‎) Online sight reduction ( http://www.csgnetwork.com/directnautsrt1.html )
  • 56.
    Warm up 1990年6月5日,某船2000 DRL41°34.8’N, λ17°10.5W,於ZT 20-01-56,以船用六分儀觀測 Pollux,得H028°02.1’。試以航海曆及229表,求 AP、a及Zn。 ( key: GP,LHA,AP ) LHA ( Pollux ) = 76° Dec. (Pollux) = 28°03.1’N aL = 42° ____________________________________________________ Z 76 .4° Rule 360 ° _____________________________________________________ Zn = 283.6 ° Hc = 28 °13.3'
  • 57.
    Warm up Pollux AP Lineof Position 42°N 17°W AP (aL , aλ ) ( 42°00.0N , 19°19.7W) A = Hc-Ho 11.2’Away Zn 283.6°
  • 58.
    Practice 2013年5月2日,某船 0200 DRL45°00.0’N, λ23°23.0’W,於ZT 02-01-59,以船用六分儀 觀測 Deneb( 天津四 ),得H052°18.0’。 試以航海曆及229表,求:LHA、Hc、Z、a以及 天文位置線 ( LOP )。
  • 59.
    2013年5月2日,某船 0200 DRL45°00.0’N, λ23°23.0’W,於ZT 02-01-59,以船用六分儀觀測 Deneb( 天津四 ),得H052°48.0’。試以航海曆及229表, 求:LHA、Hc、Zn、a以及天文位置線。 Solution: ZT 02-01-59 ZD +2 e GMT 04-01-59 GHA ♈ 280°14.3’ SHA + 49°31.5’ 45°19.5N GHA 329°45.8’ aλ - 23°45.8’ LHA 306° Dec 45°19.5’ aL 45°00.0’ Hc 52°33.0’ Z 70.2° Hc 52°33.0’ H0 52°48.0’ a 15.0’Toward Z 70.2° Rule -) 360.0° Zn 289.8°
  • 60.
  • 61.
    Thank you forlistening !