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Experiment A involved reacting excess zinc granules with 50 cm3 of 0.5 mol/dm3 sulfuric acid, producing 0.6 dm3 of gas. Experiment B involved reacting excess zinc granules with 50 cm3 of 0.5 mol/dm3 hydrochloric acid, producing 0.3 dm3 of gas. Changing the zinc from granules to powder would not change the amount of gas collected. Repeating the experiments with 2g of zinc granules would still produce 0.6 dm3 of gas for Experiment A. Using a higher acid concentration of 1.0 mol/dm3 would produce 0.72 dm3 of gas for Experiment A.
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Calculation
- 1. CALCULATION:<br />Experiment A :<br />Excess zinc granules react with 50 cm3 sulphuric acid 0.5 mol dm-3 at room condition.<br />Experiment B :<br />Excess zinc granules react with 50 cm3 hydrochloric acid 0.5 mol dm-3 at room condition<br />Question:<br />(i)Compare the gas collected between Experiment A and Experiment B.<br />Sample Answer:<br />Experiment A : <br />REACTANTPRODUCTchemical equationZnH2SO4ZnSO4H2Mole ratio1111n,molexcess=50 ×0.51000 =0.025=0.025Volume of gas,dm3---=0.025 ×24=0.6<br />Experiment B: <br />REACTANTPRODUCTchemical equationZn2HClZnCl2H2Mole ratio1211n,molexcess=50 ×0.51000 =0.025=0.0252=0.0125Volume of gas,dm3---=0.0125 ×24=0.3<br />Volume of gas in Experiment A is 0.6 dm3 higher than Experiment B is 0.3 dm3<br />(ii) Calculate the gas collected when the Experiment A repeated and changed the Excess zinc granules to excess zinc powder.<br />Sample Answer:<br />Volume of gas in Experiment A is 0.6 dm3. Volume of gas given off equal because size of reactant , not effect to amount of gas collected.<br />(iii)Calculate the gas collected when Experiment A and Experiment B are repeated and changed excess zinc granules to 2 gram zinc granules.<br />Sample Answer:<br />REACTANTPRODUCTchemical equationZnH2SO4ZnSO4H2Mole ratio1111n,mol=265=0.03≡excess=50 ×0.51000 =0.025=0.025Volume of gas,dm3---=0.025 ×24=0.6<br />Volume of gas in Experiment A is 0.6 dm3 <br />(iv)Calculate the gas collected when experiment (iii) repeated and used the 1.0 mol dm-3 concentration of both acid<br />Sample Answer:<br />REACTANTPRODUCTchemical equationZnH2SO4ZnSO4H2Mole ratio1111n,mol=265=0.03=50 ×1.01000 =0.05≡excess=0.03Volume of gas,dm3---=0.03 ×24=0.72<br />