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Geometric Mean
Dr. RMKV
Asst. Prof
Geometric Mean
ο‚΄ The geometric mean of a series containing n observations is the nth
root of the product of the values. If x1,x2…, xn are observations
ο‚΄ That is G.M =
𝑛
π‘₯1 βˆ— π‘₯2 βˆ— π‘₯3 … .βˆ— π‘₯𝑛
ο‚΄ Eg. Find GM from the following data 2, 4, 6, 8
ο‚΄ GM =
4
2 βˆ— 4 βˆ— 6 βˆ— 8 =
4
384 = 4.4267=4.43
Geometric Mean
ο‚΄ In many problem, numerous values are given to calculation
ο‚΄ At that time, To simplify the calculation with help of logarithm
ο‚΄ How do simplify..
Arithmetic Calculation Logarithm Calculation
X +
Γ· -
^ X
Γ·
Proof
ο‚΄ X – 3, 4, 5, 6, 7 GM =
5
3π‘₯4π‘₯5π‘₯6π‘₯7
ο‚΄ =
5
2520 = 4.7894
ο‚΄ Logarithm
ο‚΄ GM =AL(
log 3 +log 4+log 5+log 6 + log 7
5
)
ο‚΄ = AL(
3.4014
5
) =AL(0.68028)
ο‚΄ 4.7894
X Log X
3 0.4771
4 0.6021
5 0.6990
6 0.7781
7 0.8451
log π‘₯ = 3.4014
Formula
ο‚΄ Individual observation
ο‚΄ G.M. = Antilog(
βˆ‘ log X
𝑡
)
ο‚΄ Discrete Series
ο‚΄ G.M. = Antilog(
βˆ‘f log X
𝑡
)
ο‚΄ Continuous series
ο‚΄ G.M. = Antilog(
βˆ‘f log π’Ž
𝑡
)
INDIVIDUAL OBSERVATION: Illustration
and Solution
ο‚΄ Daily income of 10 families of a particular place
is given below. Find out Geometric Mean
ο‚΄ X = 85, 70, 15, 75, 500, 8, 45, 250, 40, 36
ο‚΄ Solution
ο‚΄ GM = AL(
βˆ‘ log X
𝑡
)
ο‚΄ = AL(
πŸπŸ•.πŸ”πŸ‘πŸ•πŸ
𝟏𝟎
)
ο‚΄ AL(1.76372) = 58.04
ο‚΄ Geometric Mean of Daily Income Rs. 58.04
X Log x
85 1.9294
70 1.8451
15 1.1761
75 1.8751
500 2.6990
8 0.9031
45 1.6532
250 2.3979
40 1.6020
36 1.5563
log π‘₯ = 17.6372
INDIVIDUAL OBSERVATION: Illustration
and Solution
ο‚΄ Find out Geometric Mean from the following
data
ο‚΄ X = 125, 1462, 38, 7, 0.22, 0.08, 12.75, 0.5
ο‚΄ Solution
ο‚΄ GM = AL(
βˆ‘ log X
𝑡
)
ο‚΄ = AL(
πŸ”.πŸ•πŸ‘πŸ”πŸ•
πŸ–
)
ο‚΄ AL(0.8421) = 6.952
ο‚΄ Geometric Mean = 6.95 or 7
X Log x
125 2.0969
1462 3.1649
38 1.5798
7 0.8451
0.22 -0.6576
0.08 -1.0969
12.75 1.1055
0.5 -0.3010
log π‘₯ = 6.7367
Discrete Series: Illustration and Solution
ο‚΄ Calculate the Geometric Mean Income of families
ο‚΄ Solution
ο‚΄ Let us take monthly incomes as X and No. of families as f
ο‚΄ G.M. = Antilog(
βˆ‘f log X
𝑡
)
Monthly
Income
5000 400 2000 3750 3000 750 600 300
No. of
families
2 100 50 4 6 8 6 10
x f Log x F log x
5000 2 3.6990 7.3980
400 100 2.6021 260.2100
2000 50 3.3010 165.0500
3750 4 3.5740 14.2960
3000 6 3.4771 20.8630
750 8 2.8751 23.0008
600 6 2.7782 16.6692
300 10 2.4771 24.7710
N = 186 βˆ‘f log X = 532.2580
ο‚΄ G.M. = Antilog(
βˆ‘f log X
𝑡
)
ο‚΄ = AL(
πŸ“πŸ‘πŸ.πŸπŸ“πŸ–πŸŽ
πŸπŸ–πŸ”
)
ο‚΄ = AL(2.8616)
ο‚΄ = 727.11
ο‚΄ Geometric Mean of family monthly
income Rs. 727.11
Discrete Series: Illustration and Solution
ο‚΄ The following table gives the diameter of screws obtained in a sample inquiry. Calculate the
mean diameter using GM
ο‚΄ Solution
ο‚΄ Let us take Diameter as X and No. of screws as f
ο‚΄ G.M. = Antilog(
βˆ‘f log X
𝑡
)
Diameter(in
mm)
130 135 140 145 150 155 160 165 170
No. of
screws
3 4 6 6 3 5 2 1 1
x f Log x F log x
130 3 2.1139 6.3417
135 4 2.1303 8.5212
140 6 2.1461 12.8766
145 6 2.1614 12.9684
150 3 2.1761 6.5283
155 5 2.1903 10.9515
160 2 2.2041 4.4082
165 1 2.2175 2.2175
170 1 2.2304 2.2304
N = 31 βˆ‘f log X = 67.0438
ο‚΄ G.M. = Antilog(
βˆ‘f log X
𝑡
)
ο‚΄ = AL(
πŸ”πŸ•.πŸŽπŸ’πŸ‘πŸ–
πŸ‘πŸ
)
ο‚΄ = AL(2.1627)
ο‚΄ = 145.446
ο‚΄ Geometric Mean diameter of screws
145.45
Continuous Series: Illustration and Solution
ο‚΄ Calculate Geometric Mean from the following data
ο‚΄ Let us take mark as X and No. of students as f
ο‚΄ G.M. = Antilog(
βˆ‘f log π’Ž
𝑡
)
Marks 4-8 8-12 12-16 16-20 20-24 24-28 28-32 32-36 36-40
No. of
Students
6 10 18 30 15 12 10 6 2
x f m Log m F log m
4-8 6 (4+8)/2
= 6
0.7782 4.6692
8-12 10 (8+12)/
2= 10
1.0000 10.0000
12-16 18 14 1.1461 20.6298
16-20 30 18 1.2553 37.6590
20-24 15 22 1.3424 20.1360
24-28 12 26 1.4150 16.9800
28-32 10 30 1.4771 14.7710
32-36 6 34 1.5315 9.1890
36-40 2 38 1.5798 3.1596
N = 109 βˆ‘f log m =
137.1936
ο‚΄ G.M. = Antilog(
βˆ‘f log m
𝑡
)
ο‚΄ = AL(
πŸπŸ‘πŸ•.πŸπŸ—πŸ‘πŸ”
πŸπŸŽπŸ—
)
ο‚΄ = AL(1.2587)
ο‚΄ = 18.14
ο‚΄ Geometric Mean of Mark = 18.14
Continuous Series: Illustration and Solution
ο‚΄ Find the geometric mean for the data given below
ο‚΄ G.M. = Antilog(
βˆ‘f log π’Ž
𝑡
)
x 0-10 10-20 20-30 30-40 40-50
f 5 15 30 8 2
x f m Log m F log m
0-10 5 5 0.6990 3.4950
10-20 15 15 1.1761 17.6415
20-30 30 25 1.3979 41.9370
30-40 8 35 1.5441 12.3528
40-50 2 45 1.6532 3.3064
N = 60 βˆ‘f logm =78.7327
ο‚΄ G.M. = Antilog(
βˆ‘f log m
𝑡
)
ο‚΄ = AL(
πŸ•πŸ–.πŸ•πŸ‘πŸπŸ•
πŸ”πŸŽ
)
ο‚΄ = AL(1.3122)
ο‚΄ = 20.52
ο‚΄ Geometric Mean = 20.52

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Calculate GM from data using logarithms

  • 2. Geometric Mean ο‚΄ The geometric mean of a series containing n observations is the nth root of the product of the values. If x1,x2…, xn are observations ο‚΄ That is G.M = 𝑛 π‘₯1 βˆ— π‘₯2 βˆ— π‘₯3 … .βˆ— π‘₯𝑛 ο‚΄ Eg. Find GM from the following data 2, 4, 6, 8 ο‚΄ GM = 4 2 βˆ— 4 βˆ— 6 βˆ— 8 = 4 384 = 4.4267=4.43
  • 3. Geometric Mean ο‚΄ In many problem, numerous values are given to calculation ο‚΄ At that time, To simplify the calculation with help of logarithm ο‚΄ How do simplify.. Arithmetic Calculation Logarithm Calculation X + Γ· - ^ X Γ·
  • 4. Proof ο‚΄ X – 3, 4, 5, 6, 7 GM = 5 3π‘₯4π‘₯5π‘₯6π‘₯7 ο‚΄ = 5 2520 = 4.7894 ο‚΄ Logarithm ο‚΄ GM =AL( log 3 +log 4+log 5+log 6 + log 7 5 ) ο‚΄ = AL( 3.4014 5 ) =AL(0.68028) ο‚΄ 4.7894 X Log X 3 0.4771 4 0.6021 5 0.6990 6 0.7781 7 0.8451 log π‘₯ = 3.4014
  • 5. Formula ο‚΄ Individual observation ο‚΄ G.M. = Antilog( βˆ‘ log X 𝑡 ) ο‚΄ Discrete Series ο‚΄ G.M. = Antilog( βˆ‘f log X 𝑡 ) ο‚΄ Continuous series ο‚΄ G.M. = Antilog( βˆ‘f log π’Ž 𝑡 )
  • 6. INDIVIDUAL OBSERVATION: Illustration and Solution ο‚΄ Daily income of 10 families of a particular place is given below. Find out Geometric Mean ο‚΄ X = 85, 70, 15, 75, 500, 8, 45, 250, 40, 36 ο‚΄ Solution ο‚΄ GM = AL( βˆ‘ log X 𝑡 ) ο‚΄ = AL( πŸπŸ•.πŸ”πŸ‘πŸ•πŸ 𝟏𝟎 ) ο‚΄ AL(1.76372) = 58.04 ο‚΄ Geometric Mean of Daily Income Rs. 58.04 X Log x 85 1.9294 70 1.8451 15 1.1761 75 1.8751 500 2.6990 8 0.9031 45 1.6532 250 2.3979 40 1.6020 36 1.5563 log π‘₯ = 17.6372
  • 7. INDIVIDUAL OBSERVATION: Illustration and Solution ο‚΄ Find out Geometric Mean from the following data ο‚΄ X = 125, 1462, 38, 7, 0.22, 0.08, 12.75, 0.5 ο‚΄ Solution ο‚΄ GM = AL( βˆ‘ log X 𝑡 ) ο‚΄ = AL( πŸ”.πŸ•πŸ‘πŸ”πŸ• πŸ– ) ο‚΄ AL(0.8421) = 6.952 ο‚΄ Geometric Mean = 6.95 or 7 X Log x 125 2.0969 1462 3.1649 38 1.5798 7 0.8451 0.22 -0.6576 0.08 -1.0969 12.75 1.1055 0.5 -0.3010 log π‘₯ = 6.7367
  • 8. Discrete Series: Illustration and Solution ο‚΄ Calculate the Geometric Mean Income of families ο‚΄ Solution ο‚΄ Let us take monthly incomes as X and No. of families as f ο‚΄ G.M. = Antilog( βˆ‘f log X 𝑡 ) Monthly Income 5000 400 2000 3750 3000 750 600 300 No. of families 2 100 50 4 6 8 6 10
  • 9. x f Log x F log x 5000 2 3.6990 7.3980 400 100 2.6021 260.2100 2000 50 3.3010 165.0500 3750 4 3.5740 14.2960 3000 6 3.4771 20.8630 750 8 2.8751 23.0008 600 6 2.7782 16.6692 300 10 2.4771 24.7710 N = 186 βˆ‘f log X = 532.2580 ο‚΄ G.M. = Antilog( βˆ‘f log X 𝑡 ) ο‚΄ = AL( πŸ“πŸ‘πŸ.πŸπŸ“πŸ–πŸŽ πŸπŸ–πŸ” ) ο‚΄ = AL(2.8616) ο‚΄ = 727.11 ο‚΄ Geometric Mean of family monthly income Rs. 727.11
  • 10. Discrete Series: Illustration and Solution ο‚΄ The following table gives the diameter of screws obtained in a sample inquiry. Calculate the mean diameter using GM ο‚΄ Solution ο‚΄ Let us take Diameter as X and No. of screws as f ο‚΄ G.M. = Antilog( βˆ‘f log X 𝑡 ) Diameter(in mm) 130 135 140 145 150 155 160 165 170 No. of screws 3 4 6 6 3 5 2 1 1
  • 11. x f Log x F log x 130 3 2.1139 6.3417 135 4 2.1303 8.5212 140 6 2.1461 12.8766 145 6 2.1614 12.9684 150 3 2.1761 6.5283 155 5 2.1903 10.9515 160 2 2.2041 4.4082 165 1 2.2175 2.2175 170 1 2.2304 2.2304 N = 31 βˆ‘f log X = 67.0438 ο‚΄ G.M. = Antilog( βˆ‘f log X 𝑡 ) ο‚΄ = AL( πŸ”πŸ•.πŸŽπŸ’πŸ‘πŸ– πŸ‘πŸ ) ο‚΄ = AL(2.1627) ο‚΄ = 145.446 ο‚΄ Geometric Mean diameter of screws 145.45
  • 12. Continuous Series: Illustration and Solution ο‚΄ Calculate Geometric Mean from the following data ο‚΄ Let us take mark as X and No. of students as f ο‚΄ G.M. = Antilog( βˆ‘f log π’Ž 𝑡 ) Marks 4-8 8-12 12-16 16-20 20-24 24-28 28-32 32-36 36-40 No. of Students 6 10 18 30 15 12 10 6 2
  • 13. x f m Log m F log m 4-8 6 (4+8)/2 = 6 0.7782 4.6692 8-12 10 (8+12)/ 2= 10 1.0000 10.0000 12-16 18 14 1.1461 20.6298 16-20 30 18 1.2553 37.6590 20-24 15 22 1.3424 20.1360 24-28 12 26 1.4150 16.9800 28-32 10 30 1.4771 14.7710 32-36 6 34 1.5315 9.1890 36-40 2 38 1.5798 3.1596 N = 109 βˆ‘f log m = 137.1936 ο‚΄ G.M. = Antilog( βˆ‘f log m 𝑡 ) ο‚΄ = AL( πŸπŸ‘πŸ•.πŸπŸ—πŸ‘πŸ” πŸπŸŽπŸ— ) ο‚΄ = AL(1.2587) ο‚΄ = 18.14 ο‚΄ Geometric Mean of Mark = 18.14
  • 14. Continuous Series: Illustration and Solution ο‚΄ Find the geometric mean for the data given below ο‚΄ G.M. = Antilog( βˆ‘f log π’Ž 𝑡 ) x 0-10 10-20 20-30 30-40 40-50 f 5 15 30 8 2
  • 15. x f m Log m F log m 0-10 5 5 0.6990 3.4950 10-20 15 15 1.1761 17.6415 20-30 30 25 1.3979 41.9370 30-40 8 35 1.5441 12.3528 40-50 2 45 1.6532 3.3064 N = 60 βˆ‘f logm =78.7327 ο‚΄ G.M. = Antilog( βˆ‘f log m 𝑡 ) ο‚΄ = AL( πŸ•πŸ–.πŸ•πŸ‘πŸπŸ• πŸ”πŸŽ ) ο‚΄ = AL(1.3122) ο‚΄ = 20.52 ο‚΄ Geometric Mean = 20.52