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Boundedness of the Twisted
Paraproduct
Vjekoslav Kovaˇc, UCLA
Indiana University, Bloomington
January 13, 2011
Mathematical Institute, University of Bonn
February 3, 2011
Ordinary paraproduct
Dyadic version
Td(f , g) :=
k∈Z
(Ekf )(∆kg)
Ekf := |I|=2−k
1
|I| I f 1I , ∆kg := Ek+1g − Ekg
Continuous version
Tc(f , g) :=
k∈Z
(Pϕk
f )(Pψk
g)
Pϕk
f := f ∗ ϕk, Pψk
g := g ∗ ψk
ϕ, ψ Schwartz, supp( ˆψ) ⊆ {ξ ∈ R : 1
2 ≤|ξ| ≤ 2}
ϕk(x) := 2kϕ(2kx), ψk(x) := 2kψ(2kx)
Twisted paraproduct
Dyadic version
Td(F, G) :=
k∈Z
(E
(1)
k F)(∆
(2)
k G)
E
(1)
k martingale averages in the 1st variable
∆
(2)
k martingale differences in the 2nd variable
Continuous version
Tc(F, G) :=
k∈Z
(P(1)
ϕk
F)(P
(2)
ψk
G)
P
(1)
ϕk , P
(2)
ψk
Littlewood-Paley projections in the 1st and the 2nd
variable respectively
(P
(1)
ϕk F)(x, y) := R F(x−t, y)ϕk(t)dt
(P
(2)
ψk
G)(x, y) := R G(x, y −t)ψk(t)dt
Twisted paraproduct – Estimates
We are interested in
strong-type estimates
T(F, G) Lpq/(p+q)(R2) p,q F Lp(R2) G Lq(R2)
weak-type estimates
α |T(F, G)| > α
(p+q)/pq
p,q F Lp(R2) G Lq(R2)
Theorem (K., 2010)
Operators Td and Tc satisfy the strong bound if
1 < p, q < ∞, 1
p + 1
q > 1
2.
Additionally, operators Td and Tc satisfy the weak bound
when p = 1, 1 ≤ q < ∞ or q = 1, 1 ≤ p < ∞.
The weak estimate fails for p = ∞ or q = ∞.
Range of exponents
B( ), _
2
1 C( )_
2
1 , _
2
1
1
2
_,1
4
_ )(E
D( )_
2
1 ,
0
0,1
2
_ )(A
_
4
1
_1
q
p
1_
1
0
10
the shaded region – the
strong estimate
two solid sides of the square
– the weak estimate
two dashed sides of the
square – no estimates
the white region –
unresolved
Proof outline
B( ), _
2
1 C( )_
2
1 , _
2
1
1
2
_,1
4
_ )(E
D( )_
2
1 ,
0
0,1
2
_ )(A
_
4
1
_1
q
p
1_
1
0
10
Dyadic version Td
ABC – direct proof,
K. (2010)
the rest of the shaded region
– conditional proof,
Bernicot (2010)
dashed segments –
counterexamples,
K. (2010)
points D, E – the direct
proof simplifies
Continuous version Tc
transition using the
Jones-Seeger-Wright square
function
Some motivation
1D bilinear Hilbert transform
Tα,β(f , g)(x) := p.v.
R
f (x − αt) g(x − βt)
dt
t
Bounds proved by Lacey and Thiele (1997–1999).
2D bilinear Hilbert transform
TA,B(F, G)(x, y) :=
p.v.
R2
F (x, y) − A(s, t) G (x, y) − B(s, t) K(s, t) ds dt
|∂α ˆK(ξ, η)| α (ξ2 + η2)−|α|/2
Introduced by Demeter and Thiele (2008). They proved bounds in
the range 2 < p, q < ∞, 1
p + 1
q > 1
2, and for almost all cases
depending on matrices A and B.
Some motivation
Essentially the only unresolved case was (denoted “Case 6”):
T(F, G)(x, y) := p.v.
R2
F(x − s, y) G(x, y − t) K(s, t) ds dt
Using “cone decomposition” it reduces to bilinear multipliers with
symbols
ˆK(ξ, η) =
k∈Z
ˆϕ(2−k
ξ) ˆψ(2−k
η)
which are twisted paraproducts.
Bounding the dyadic version
ϕd
I := |I|−1/21I the Haar scaling function
ψd
I := |I|−1/2(1Ileft
− 1Iright
) the Haar wavelet
C = dyadic squares in R2
Td(F, G)(x, y) =
I×J∈C R2
F(u, y)G(x, v)ϕd
I (u)ϕd
I (x)ψd
J (v)ψd
J (y)dudv
Λd(F, G, H) =
R2
Td(F, G)(x, y)H(x, y) dx dy
=
I×J∈C R4
F(u, y)G(x, v)H(x, y) ϕd
I (u)ϕd
I (x)ψd
J (v)ψd
J (y) du dx dv dy
Introducing trees
A finite convex tree is a collection T of dyadic squares such that
There exists QT ∈ T , called the root of T , satisfying Q ⊆ QT
for every Q ∈ T .
Whenever Q1 ⊆ Q2 ⊆ Q3 and Q1, Q3 ∈ T , then also Q2 ∈ T .
A leaf of T is a square that is not contained in T , but its parent is.
L(T ) = the family of leaves of T
Squares in L(T ) partition QT .
Local forms
For any finite convex tree T we define:
ΛT (F, G, H) :=
I×J∈T R4
F(u, y)G(x, v)H(x, y)
ϕd
I (u)ϕd
I (x)ψd
J (v)ψd
J (y) du dx dv dy
Θ
(2)
T (F1, F2, F3, F4) :=
I×J∈T R4
F1(u, v)F2(x, v)F3(u, y)F4(x, y)
ϕd
I (u)ϕd
I (x)ψd
J (v)ψd
J (y) du dv dx dy
Θ
(1)
T (F1, F2, F3, F4) :=
I×J∈T R4
F1(u, v)F2(x, v)F3(u, y)F4(x, y)
ψd
I (u)ψd
I (x) ϕd
Jleft
(v)ϕd
Jleft
(y) + ϕd
Jright
(v)ϕd
Jright
(y) du dv dx dy
Observe that ΛT (F, G, H) = Θ
(2)
T (1, G, F, H).
A notion from additive combinatorics
For Q = I × J ∈ C we define:
Gowers box inner-product and norm
[F1, F2, F3, F4] (Q) :=
1
|Q|2
I I J J
F1(u, v)F2(x, v)F3(u, y)F4(x, y) du dx dv dy
F (Q) := [F, F, F, F]
1/4
(Q)
The box Cauchy-Schwarz inequality:
[F1, F2, F3, F4] (Q) ≤ F1 (Q) F2 (Q) F3 (Q) F4 (Q)
A special case of Brascamp-Lieb inequalities:
F (Q) ≤ 1
|Q| Q |F|2 1/2
Local forms
For any finite collection of squares F we define:
ΞF (F1, F2, F3, F4) :=
Q∈F
|Q| F1, F2, F3, F4 (Q)
=
I×J∈F R4
F1(u, v)F2(x, v)F3(u, y)F4(x, y)
ϕd
I (u)ϕd
I (x)ϕd
J (v)ϕd
J (y) du dv dx dy
A single-scale estimate:
ΞL(T )(F1, F2, F3, F4) ≤ |QT |
4
j=1
max
Q∈L(T )
Fj (Q)
Telescoping identity over trees
Lemma (Telescoping identity)
For any finite convex tree T with root QT we have
Θ
(1)
T (F1, F2, F3, F4) + Θ
(2)
T (F1, F2, F3, F4)
= ΞL(T )(F1, F2, F3, F4) − Ξ{QT }(F1, F2, F3, F4)
Telescoping identity over trees
Lemma (Telescoping identity)
For any finite convex tree T with root QT we have
Θ
(1)
T (F1, F2, F3, F4) + Θ
(2)
T (F1, F2, F3, F4)
= ΞL(T )(F1, F2, F3, F4) − Ξ{QT }(F1, F2, F3, F4)
Proof, part 1.
When T consists of only one square, the identity reduces to
j∈{left,right}
ψd
I (u)ψd
I (x)ϕd
Jj
(v)ϕd
Jj
(y) + ϕd
I (u)ϕd
I (x)ψd
J (v)ψd
J (y)
=
i,j∈{left,right}
ϕd
Ii
(u)ϕd
Ii
(x)ϕd
Jj
(v)ϕd
Jj
(y) − ϕd
I (u)ϕd
I (x)ϕd
J (v)ϕd
J (y)
Telescoping identity over trees
Lemma (Telescoping identity)
For any finite convex tree T with root QT we have
Θ
(1)
T (F1, F2, F3, F4) + Θ
(2)
T (F1, F2, F3, F4)
= ΞL(T )(F1, F2, F3, F4) − Ξ{QT }(F1, F2, F3, F4)
Proof, part 2.
For a general finite convex tree T the following sum
Q∈T Q is a child of Q
Ξ{Q}
− Ξ{Q}
telescopes into the right hand side.
Reduction inequalities
Lemma (Reduction inequalities)
Θ
(1)
T (F1, F2, F3, F4) ≤ Θ
(1)
T (F1, F1, F3, F3)
1
2 Θ
(1)
T (F2, F2, F4, F4)
1
2
Θ
(2)
T (F1, F2, F3, F4) ≤ Θ
(2)
T (F1, F2, F1, F2)
1
2 Θ
(2)
T (F3, F4, F3, F4)
1
2
Reduction inequalities
Lemma (Reduction inequalities)
Θ
(1)
T (F1, F2, F3, F4) ≤ Θ
(1)
T (F1, F1, F3, F3)
1
2 Θ
(1)
T (F2, F2, F4, F4)
1
2
Θ
(2)
T (F1, F2, F3, F4) ≤ Θ
(2)
T (F1, F2, F1, F2)
1
2 Θ
(2)
T (F3, F4, F3, F4)
1
2
Proof.
Rewrite Θ
(2)
T (F1, F2, F3, F4) as
I×J∈T R2 R
F1(u, v)F2(x, v)ψd
J (v)dv
·
R
F3(u, y)F4(x, y)ψd
J (y)dy ϕd
I (u)ϕd
I (x) du dx
and apply the Cauchy-Schwarz inequality, first over (u, x) ∈ I × I,
and then over I × J ∈ T .
Single tree estimate
For any finite convex tree T we have:
Proposition (Single tree estimate)
Θ
(2)
T (F1, F2, F3, F4) |QT |
4
j=1
max
Q∈L(T )
Fj (Q)
ΛT (F, G, H)
|QT | max
Q∈L(T )
F (Q) max
Q∈L(T )
G (Q) max
Q∈L(T )
H (Q)
Proof of the single tree estimate
Θ
(2)
T (F1, F2, F3, F4)
ww ''
Θ
(2)
T (F1, F2, F1, F2)

Θ
(2)
T (F3, F4, F3, F4)

Θ
(1)
T (F1, F2, F1, F2)
~~
Θ
(1)
T (F3, F4, F3, F4)
~~
Θ
(1)
T (F1, F1, F1, F1) Θ
(1)
T (F2, F2, F2, F2) Θ
(1)
T (F3, F3, F3, F3) Θ
(1)
T (F4, F4, F4, F4)
Proof of the single tree estimate
How do we control Θ
(1)
T (Fj , Fj , Fj , Fj ) ?
Θ
(1)
T (Fj , Fj , Fj , Fj )
≥0
+ Θ
(2)
T (Fj , Fj , Fj , Fj )
≥0
+ Ξ{QT }(Fj , Fj , Fj , Fj )
≥0 if Fj ≥0
= ΞL(T )(Fj , Fj , Fj , Fj )
Estimates in the local L2
range
Proposition
|Λd(F, G, H)| p,q,r F Lp G Lq H Lr
for 1
p + 1
q + 1
r = 1, 2  p, q, r  ∞
Estimates in the local L2
range
Proposition
|Λd(F, G, H)| p,q,r F Lp G Lq H Lr
for 1
p + 1
q + 1
r = 1, 2  p, q, r  ∞
Proof, part 1.
PF
k := Q : 2k ≤ supQ ⊇Q F (Q )  2k+1
MF
k = maximal squares in PF
k
PG
k , MG
k , PH
k , MH
k defined analogously
Pk1,k2,k3 := PF
k1
∩ PG
k2
∩ PH
k3
Mk1,k2,k3 = maximal squares in Pk1,k2,k3
Estimates in the local L2
range
Proposition
|Λd(F, G, H)| p,q,r F Lp G Lq H Lr
for 1
p + 1
q + 1
r = 1, 2  p, q, r  ∞
Proof, part 2.
For each Q ∈ Mk1,k2,k3
TQ := {Q ∈ Pk1,k2,k3 : Q ⊆ Q}
is a convex tree with root Q. We apply the single tree estimate to
each of the trees TQ.
It remains to show
k1,k2,k3∈Z
2k1+k2+k3
Q∈Mk1,k2,k3
|Q| p,q,r F Lp G Lq H Lr
Estimates in the local L2
range
Proposition
|Λd(F, G, H)| p,q,r F Lp G Lq H Lr
for 1
p + 1
q + 1
r = 1, 2  p, q, r  ∞
Proof, part 3.
i.e.
k1,k2,k3∈Z
2k1+k2+k3
min
Q∈MF
k1
|Q|,
Q∈MG
k2
|Q|,
Q∈MH
k3
|Q|
p,q,r F Lp G Lq H Lr
i.e.
k∈Z
2pk
Q∈MF
k
|Q| p F p
Lp ,
k∈Z
2qk
Q∈MG
k
|Q| q G q
Lq ,
k∈Z
2rk
Q∈MH
k
|Q| r H r
Lr
Estimates in the local L2
range
Proposition
|Λd(F, G, H)| p,q,r F Lp G Lq H Lr
for 1
p + 1
q + 1
r = 1, 2  p, q, r  ∞
Proof, part 4.
M2F := sup
Q∈C
1
|Q| Q
|F|2
1/2
1Q
For each Q ∈ MF
k we have 1
|Q| Q |F|2 1/2
≥ F (Q) ≥ 2k and
so by disjointness
Q∈MF
k
|Q| ≤ |{M2F ≥ 2k
}|
k∈Z
2pk
|{M2F ≥ 2k
}| ∼p M2F p
Lp p F p
Lp
Extending the range of exponents
Proposition (Bernicot, 2010)
If for some (p, q), 1  p, q  ∞
Td(F, G) Lpq/(p+q) p,q F Lp G Lq
then
Td(F, G) Lp/(p+1),∞ p,q F Lp G L1
Td(F, G) Lq/(q+1),∞ p,q F L1 G Lq
Extending the range of exponents
Proposition (Bernicot, 2010)
If for some (p, q), 1  p, q  ∞
Td(F, G) Lpq/(p+q) p,q F Lp G Lq
then
Td(F, G) Lp/(p+1),∞ p,q F Lp G L1
Td(F, G) Lq/(q+1),∞ p,q F L1 G Lq
Proof.
Perform one-dimensional Calder´on-Zygmund decomposition in
each fiber F(·, y) or G(x, ·).
Even simpler in the dyadic setting: there is no contribution of “the
bad part” outside of “the bad set”.
Bounding the continuous version
Let us assume that ψk = φk+1 − φk for some φ Schwartz,
R φ = 1. The general case is obtained by composing with a
bounded Fourier multiplier in the second variable.
Proposition (Jones, Seeger, Wright, 2008)
If ϕ is Schwartz and R ϕ = 1, then the square function
SJSWf :=
k∈Z
Pϕk
f − Ekf
2 1/2
satisfies SJSWf Lp(R) p f Lp(R)
for 1  p  ∞.
Bounding the continuous version
Proposition
Tc(F, G) − Td(F, G) Lpq/(p+q) p,q F Lp G Lq
Bounding the continuous version
Proposition
Tc(F, G) − Td(F, G) Lpq/(p+q) p,q F Lp G Lq
Proof, part 1.
Taux(F, G) :=
k∈Z
(E
(1)
k F)(P
(2)
ψk
G)
Tc(F, G) − Taux(F, G)
≤
k∈Z
P(1)
ϕk
F − E
(1)
k F
2 1/2
S
(1)
JSWF
k∈Z
P
(2)
ψk
G
2 1/2
S(2)G
Bounding the continuous version
Proposition
Tc(F, G) − Td(F, G) Lpq/(p+q) p,q F Lp G Lq
Proof, part 2.
Taux(F, G) = FG −
k∈Z
(∆
(1)
k F)(P
(2)
φk+1
G)
Td(F, G) = FG −
k∈Z
(∆
(1)
k F)(E
(2)
k+1G)
Taux(F, G) − Td(F, G)
≤
k∈Z
∆
(1)
k F
2 1/2
S
(1)
d F
k∈Z
P
(2)
φk
G − E
(2)
k G
2 1/2
S
(2)
JSWG
Endpoint counterexample
We disprove
L∞
(R2
) × Lq
(R2
) → Lq,∞
(R2
)
for 1 ≤ q  ∞.
G(x, y) := 1[0,2−n)(x)
n
k=1
Rk(y)
Rk := k-th Rademacher function =
J⊆[0,1), |J|=2−k+1
(1Jleft
− 1Jright
)
G Lq ∼q 2−n/qn1/2 by Khintchine’s inequality
(∆
(2)
k G)(x, y) = 1[0,2−n)(x)Rk+1(y) for k = 0, 1, . . . , n − 1
Endpoint counterexample
We choose F so that there is no cancellation between different
scales in Td(F, G).
(E
(1)
k F)(x, y) = Rk+1(y) for x ∈ [0, 2−n), k = 0, 1, . . . , n − 1
F(x, y) :=
2Rj (y) − Rj+1(y), for x ∈ [2−j , 2−j+1), j = 1, . . . , n−1
Rn(y), for x ∈ [0, 2−n+1)
Then Td(F, G) = n 1[0,2−n)×[0,1)
Td(F, G) Lq,∞
F L∞ G Lq
q
2−n/qn
2−n/qn1/2
= n1/2
A byproduct of the proof
Theorem (K., 2010)
Θ(2)
(F1, F2, F3, F4) :=
I×J∈C R4
F1(u, v)F2(x, v)F3(u, y)F4(x, y)
ϕd
I (u)ϕd
I (x)ψd
J (v)ψd
J (y) du dv dx dy
Θ(2)
(F1, F2, F3, F4) p1,p2,p3,p4
4
j=1
Fj L
pj ,
for 1
p1
+ 1
p2
+ 1
p3
+ 1
p4
= 1, 2  p1, p2, p3, p4  ∞
Higher-dimensional generalizations are straightforward.
Subsequent research
The next step in the Demeter-Thiele program:
More singular 2D bilinear Hilbert transform
p.v.
R
F(x − t, y) G(x, y − t)
dt
t
A reason for caution:
Bi-parameter bilinear Hilbert transform
p.v.
R2
F(x − s, y − t) G(x + s, y + t)
ds
s
dt
t
satisfies no Lp estimates – Muscalu, Pipher, Tao, Thiele (2004)

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Boundedness of the Twisted Paraproduct

  • 1. Boundedness of the Twisted Paraproduct Vjekoslav Kovaˇc, UCLA Indiana University, Bloomington January 13, 2011 Mathematical Institute, University of Bonn February 3, 2011
  • 2. Ordinary paraproduct Dyadic version Td(f , g) := k∈Z (Ekf )(∆kg) Ekf := |I|=2−k 1 |I| I f 1I , ∆kg := Ek+1g − Ekg Continuous version Tc(f , g) := k∈Z (Pϕk f )(Pψk g) Pϕk f := f ∗ ϕk, Pψk g := g ∗ ψk ϕ, ψ Schwartz, supp( ˆψ) ⊆ {ξ ∈ R : 1 2 ≤|ξ| ≤ 2} ϕk(x) := 2kϕ(2kx), ψk(x) := 2kψ(2kx)
  • 3. Twisted paraproduct Dyadic version Td(F, G) := k∈Z (E (1) k F)(∆ (2) k G) E (1) k martingale averages in the 1st variable ∆ (2) k martingale differences in the 2nd variable Continuous version Tc(F, G) := k∈Z (P(1) ϕk F)(P (2) ψk G) P (1) ϕk , P (2) ψk Littlewood-Paley projections in the 1st and the 2nd variable respectively (P (1) ϕk F)(x, y) := R F(x−t, y)ϕk(t)dt (P (2) ψk G)(x, y) := R G(x, y −t)ψk(t)dt
  • 4. Twisted paraproduct – Estimates We are interested in strong-type estimates T(F, G) Lpq/(p+q)(R2) p,q F Lp(R2) G Lq(R2) weak-type estimates α |T(F, G)| > α (p+q)/pq p,q F Lp(R2) G Lq(R2) Theorem (K., 2010) Operators Td and Tc satisfy the strong bound if 1 < p, q < ∞, 1 p + 1 q > 1 2. Additionally, operators Td and Tc satisfy the weak bound when p = 1, 1 ≤ q < ∞ or q = 1, 1 ≤ p < ∞. The weak estimate fails for p = ∞ or q = ∞.
  • 5. Range of exponents B( ), _ 2 1 C( )_ 2 1 , _ 2 1 1 2 _,1 4 _ )(E D( )_ 2 1 , 0 0,1 2 _ )(A _ 4 1 _1 q p 1_ 1 0 10 the shaded region – the strong estimate two solid sides of the square – the weak estimate two dashed sides of the square – no estimates the white region – unresolved
  • 6. Proof outline B( ), _ 2 1 C( )_ 2 1 , _ 2 1 1 2 _,1 4 _ )(E D( )_ 2 1 , 0 0,1 2 _ )(A _ 4 1 _1 q p 1_ 1 0 10 Dyadic version Td ABC – direct proof, K. (2010) the rest of the shaded region – conditional proof, Bernicot (2010) dashed segments – counterexamples, K. (2010) points D, E – the direct proof simplifies Continuous version Tc transition using the Jones-Seeger-Wright square function
  • 7. Some motivation 1D bilinear Hilbert transform Tα,β(f , g)(x) := p.v. R f (x − αt) g(x − βt) dt t Bounds proved by Lacey and Thiele (1997–1999). 2D bilinear Hilbert transform TA,B(F, G)(x, y) := p.v. R2 F (x, y) − A(s, t) G (x, y) − B(s, t) K(s, t) ds dt |∂α ˆK(ξ, η)| α (ξ2 + η2)−|α|/2 Introduced by Demeter and Thiele (2008). They proved bounds in the range 2 < p, q < ∞, 1 p + 1 q > 1 2, and for almost all cases depending on matrices A and B.
  • 8. Some motivation Essentially the only unresolved case was (denoted “Case 6”): T(F, G)(x, y) := p.v. R2 F(x − s, y) G(x, y − t) K(s, t) ds dt Using “cone decomposition” it reduces to bilinear multipliers with symbols ˆK(ξ, η) = k∈Z ˆϕ(2−k ξ) ˆψ(2−k η) which are twisted paraproducts.
  • 9. Bounding the dyadic version ϕd I := |I|−1/21I the Haar scaling function ψd I := |I|−1/2(1Ileft − 1Iright ) the Haar wavelet C = dyadic squares in R2 Td(F, G)(x, y) = I×J∈C R2 F(u, y)G(x, v)ϕd I (u)ϕd I (x)ψd J (v)ψd J (y)dudv Λd(F, G, H) = R2 Td(F, G)(x, y)H(x, y) dx dy = I×J∈C R4 F(u, y)G(x, v)H(x, y) ϕd I (u)ϕd I (x)ψd J (v)ψd J (y) du dx dv dy
  • 10. Introducing trees A finite convex tree is a collection T of dyadic squares such that There exists QT ∈ T , called the root of T , satisfying Q ⊆ QT for every Q ∈ T . Whenever Q1 ⊆ Q2 ⊆ Q3 and Q1, Q3 ∈ T , then also Q2 ∈ T . A leaf of T is a square that is not contained in T , but its parent is. L(T ) = the family of leaves of T Squares in L(T ) partition QT .
  • 11. Local forms For any finite convex tree T we define: ΛT (F, G, H) := I×J∈T R4 F(u, y)G(x, v)H(x, y) ϕd I (u)ϕd I (x)ψd J (v)ψd J (y) du dx dv dy Θ (2) T (F1, F2, F3, F4) := I×J∈T R4 F1(u, v)F2(x, v)F3(u, y)F4(x, y) ϕd I (u)ϕd I (x)ψd J (v)ψd J (y) du dv dx dy Θ (1) T (F1, F2, F3, F4) := I×J∈T R4 F1(u, v)F2(x, v)F3(u, y)F4(x, y) ψd I (u)ψd I (x) ϕd Jleft (v)ϕd Jleft (y) + ϕd Jright (v)ϕd Jright (y) du dv dx dy Observe that ΛT (F, G, H) = Θ (2) T (1, G, F, H).
  • 12. A notion from additive combinatorics For Q = I × J ∈ C we define: Gowers box inner-product and norm [F1, F2, F3, F4] (Q) := 1 |Q|2 I I J J F1(u, v)F2(x, v)F3(u, y)F4(x, y) du dx dv dy F (Q) := [F, F, F, F] 1/4 (Q) The box Cauchy-Schwarz inequality: [F1, F2, F3, F4] (Q) ≤ F1 (Q) F2 (Q) F3 (Q) F4 (Q) A special case of Brascamp-Lieb inequalities: F (Q) ≤ 1 |Q| Q |F|2 1/2
  • 13. Local forms For any finite collection of squares F we define: ΞF (F1, F2, F3, F4) := Q∈F |Q| F1, F2, F3, F4 (Q) = I×J∈F R4 F1(u, v)F2(x, v)F3(u, y)F4(x, y) ϕd I (u)ϕd I (x)ϕd J (v)ϕd J (y) du dv dx dy A single-scale estimate: ΞL(T )(F1, F2, F3, F4) ≤ |QT | 4 j=1 max Q∈L(T ) Fj (Q)
  • 14. Telescoping identity over trees Lemma (Telescoping identity) For any finite convex tree T with root QT we have Θ (1) T (F1, F2, F3, F4) + Θ (2) T (F1, F2, F3, F4) = ΞL(T )(F1, F2, F3, F4) − Ξ{QT }(F1, F2, F3, F4)
  • 15. Telescoping identity over trees Lemma (Telescoping identity) For any finite convex tree T with root QT we have Θ (1) T (F1, F2, F3, F4) + Θ (2) T (F1, F2, F3, F4) = ΞL(T )(F1, F2, F3, F4) − Ξ{QT }(F1, F2, F3, F4) Proof, part 1. When T consists of only one square, the identity reduces to j∈{left,right} ψd I (u)ψd I (x)ϕd Jj (v)ϕd Jj (y) + ϕd I (u)ϕd I (x)ψd J (v)ψd J (y) = i,j∈{left,right} ϕd Ii (u)ϕd Ii (x)ϕd Jj (v)ϕd Jj (y) − ϕd I (u)ϕd I (x)ϕd J (v)ϕd J (y)
  • 16. Telescoping identity over trees Lemma (Telescoping identity) For any finite convex tree T with root QT we have Θ (1) T (F1, F2, F3, F4) + Θ (2) T (F1, F2, F3, F4) = ΞL(T )(F1, F2, F3, F4) − Ξ{QT }(F1, F2, F3, F4) Proof, part 2. For a general finite convex tree T the following sum Q∈T Q is a child of Q Ξ{Q} − Ξ{Q} telescopes into the right hand side.
  • 17. Reduction inequalities Lemma (Reduction inequalities) Θ (1) T (F1, F2, F3, F4) ≤ Θ (1) T (F1, F1, F3, F3) 1 2 Θ (1) T (F2, F2, F4, F4) 1 2 Θ (2) T (F1, F2, F3, F4) ≤ Θ (2) T (F1, F2, F1, F2) 1 2 Θ (2) T (F3, F4, F3, F4) 1 2
  • 18. Reduction inequalities Lemma (Reduction inequalities) Θ (1) T (F1, F2, F3, F4) ≤ Θ (1) T (F1, F1, F3, F3) 1 2 Θ (1) T (F2, F2, F4, F4) 1 2 Θ (2) T (F1, F2, F3, F4) ≤ Θ (2) T (F1, F2, F1, F2) 1 2 Θ (2) T (F3, F4, F3, F4) 1 2 Proof. Rewrite Θ (2) T (F1, F2, F3, F4) as I×J∈T R2 R F1(u, v)F2(x, v)ψd J (v)dv · R F3(u, y)F4(x, y)ψd J (y)dy ϕd I (u)ϕd I (x) du dx and apply the Cauchy-Schwarz inequality, first over (u, x) ∈ I × I, and then over I × J ∈ T .
  • 19. Single tree estimate For any finite convex tree T we have: Proposition (Single tree estimate) Θ (2) T (F1, F2, F3, F4) |QT | 4 j=1 max Q∈L(T ) Fj (Q) ΛT (F, G, H) |QT | max Q∈L(T ) F (Q) max Q∈L(T ) G (Q) max Q∈L(T ) H (Q)
  • 20. Proof of the single tree estimate Θ (2) T (F1, F2, F3, F4) ww '' Θ (2) T (F1, F2, F1, F2) Θ (2) T (F3, F4, F3, F4) Θ (1) T (F1, F2, F1, F2) ~~ Θ (1) T (F3, F4, F3, F4) ~~ Θ (1) T (F1, F1, F1, F1) Θ (1) T (F2, F2, F2, F2) Θ (1) T (F3, F3, F3, F3) Θ (1) T (F4, F4, F4, F4)
  • 21. Proof of the single tree estimate How do we control Θ (1) T (Fj , Fj , Fj , Fj ) ? Θ (1) T (Fj , Fj , Fj , Fj ) ≥0 + Θ (2) T (Fj , Fj , Fj , Fj ) ≥0 + Ξ{QT }(Fj , Fj , Fj , Fj ) ≥0 if Fj ≥0 = ΞL(T )(Fj , Fj , Fj , Fj )
  • 22. Estimates in the local L2 range Proposition |Λd(F, G, H)| p,q,r F Lp G Lq H Lr for 1 p + 1 q + 1 r = 1, 2 p, q, r ∞
  • 23. Estimates in the local L2 range Proposition |Λd(F, G, H)| p,q,r F Lp G Lq H Lr for 1 p + 1 q + 1 r = 1, 2 p, q, r ∞ Proof, part 1. PF k := Q : 2k ≤ supQ ⊇Q F (Q ) 2k+1 MF k = maximal squares in PF k PG k , MG k , PH k , MH k defined analogously Pk1,k2,k3 := PF k1 ∩ PG k2 ∩ PH k3 Mk1,k2,k3 = maximal squares in Pk1,k2,k3
  • 24. Estimates in the local L2 range Proposition |Λd(F, G, H)| p,q,r F Lp G Lq H Lr for 1 p + 1 q + 1 r = 1, 2 p, q, r ∞ Proof, part 2. For each Q ∈ Mk1,k2,k3 TQ := {Q ∈ Pk1,k2,k3 : Q ⊆ Q} is a convex tree with root Q. We apply the single tree estimate to each of the trees TQ. It remains to show k1,k2,k3∈Z 2k1+k2+k3 Q∈Mk1,k2,k3 |Q| p,q,r F Lp G Lq H Lr
  • 25. Estimates in the local L2 range Proposition |Λd(F, G, H)| p,q,r F Lp G Lq H Lr for 1 p + 1 q + 1 r = 1, 2 p, q, r ∞ Proof, part 3. i.e. k1,k2,k3∈Z 2k1+k2+k3 min Q∈MF k1 |Q|, Q∈MG k2 |Q|, Q∈MH k3 |Q| p,q,r F Lp G Lq H Lr i.e. k∈Z 2pk Q∈MF k |Q| p F p Lp , k∈Z 2qk Q∈MG k |Q| q G q Lq , k∈Z 2rk Q∈MH k |Q| r H r Lr
  • 26. Estimates in the local L2 range Proposition |Λd(F, G, H)| p,q,r F Lp G Lq H Lr for 1 p + 1 q + 1 r = 1, 2 p, q, r ∞ Proof, part 4. M2F := sup Q∈C 1 |Q| Q |F|2 1/2 1Q For each Q ∈ MF k we have 1 |Q| Q |F|2 1/2 ≥ F (Q) ≥ 2k and so by disjointness Q∈MF k |Q| ≤ |{M2F ≥ 2k }| k∈Z 2pk |{M2F ≥ 2k }| ∼p M2F p Lp p F p Lp
  • 27. Extending the range of exponents Proposition (Bernicot, 2010) If for some (p, q), 1 p, q ∞ Td(F, G) Lpq/(p+q) p,q F Lp G Lq then Td(F, G) Lp/(p+1),∞ p,q F Lp G L1 Td(F, G) Lq/(q+1),∞ p,q F L1 G Lq
  • 28. Extending the range of exponents Proposition (Bernicot, 2010) If for some (p, q), 1 p, q ∞ Td(F, G) Lpq/(p+q) p,q F Lp G Lq then Td(F, G) Lp/(p+1),∞ p,q F Lp G L1 Td(F, G) Lq/(q+1),∞ p,q F L1 G Lq Proof. Perform one-dimensional Calder´on-Zygmund decomposition in each fiber F(·, y) or G(x, ·). Even simpler in the dyadic setting: there is no contribution of “the bad part” outside of “the bad set”.
  • 29. Bounding the continuous version Let us assume that ψk = φk+1 − φk for some φ Schwartz, R φ = 1. The general case is obtained by composing with a bounded Fourier multiplier in the second variable. Proposition (Jones, Seeger, Wright, 2008) If ϕ is Schwartz and R ϕ = 1, then the square function SJSWf := k∈Z Pϕk f − Ekf 2 1/2 satisfies SJSWf Lp(R) p f Lp(R) for 1 p ∞.
  • 30. Bounding the continuous version Proposition Tc(F, G) − Td(F, G) Lpq/(p+q) p,q F Lp G Lq
  • 31. Bounding the continuous version Proposition Tc(F, G) − Td(F, G) Lpq/(p+q) p,q F Lp G Lq Proof, part 1. Taux(F, G) := k∈Z (E (1) k F)(P (2) ψk G) Tc(F, G) − Taux(F, G) ≤ k∈Z P(1) ϕk F − E (1) k F 2 1/2 S (1) JSWF k∈Z P (2) ψk G 2 1/2 S(2)G
  • 32. Bounding the continuous version Proposition Tc(F, G) − Td(F, G) Lpq/(p+q) p,q F Lp G Lq Proof, part 2. Taux(F, G) = FG − k∈Z (∆ (1) k F)(P (2) φk+1 G) Td(F, G) = FG − k∈Z (∆ (1) k F)(E (2) k+1G) Taux(F, G) − Td(F, G) ≤ k∈Z ∆ (1) k F 2 1/2 S (1) d F k∈Z P (2) φk G − E (2) k G 2 1/2 S (2) JSWG
  • 33. Endpoint counterexample We disprove L∞ (R2 ) × Lq (R2 ) → Lq,∞ (R2 ) for 1 ≤ q ∞. G(x, y) := 1[0,2−n)(x) n k=1 Rk(y) Rk := k-th Rademacher function = J⊆[0,1), |J|=2−k+1 (1Jleft − 1Jright ) G Lq ∼q 2−n/qn1/2 by Khintchine’s inequality (∆ (2) k G)(x, y) = 1[0,2−n)(x)Rk+1(y) for k = 0, 1, . . . , n − 1
  • 34. Endpoint counterexample We choose F so that there is no cancellation between different scales in Td(F, G). (E (1) k F)(x, y) = Rk+1(y) for x ∈ [0, 2−n), k = 0, 1, . . . , n − 1 F(x, y) := 2Rj (y) − Rj+1(y), for x ∈ [2−j , 2−j+1), j = 1, . . . , n−1 Rn(y), for x ∈ [0, 2−n+1) Then Td(F, G) = n 1[0,2−n)×[0,1) Td(F, G) Lq,∞ F L∞ G Lq q 2−n/qn 2−n/qn1/2 = n1/2
  • 35. A byproduct of the proof Theorem (K., 2010) Θ(2) (F1, F2, F3, F4) := I×J∈C R4 F1(u, v)F2(x, v)F3(u, y)F4(x, y) ϕd I (u)ϕd I (x)ψd J (v)ψd J (y) du dv dx dy Θ(2) (F1, F2, F3, F4) p1,p2,p3,p4 4 j=1 Fj L pj , for 1 p1 + 1 p2 + 1 p3 + 1 p4 = 1, 2 p1, p2, p3, p4 ∞ Higher-dimensional generalizations are straightforward.
  • 36. Subsequent research The next step in the Demeter-Thiele program: More singular 2D bilinear Hilbert transform p.v. R F(x − t, y) G(x, y − t) dt t A reason for caution: Bi-parameter bilinear Hilbert transform p.v. R2 F(x − s, y − t) G(x + s, y + t) ds s dt t satisfies no Lp estimates – Muscalu, Pipher, Tao, Thiele (2004)