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1
Design and drawing of RCC
Structures
SHUBHAMCE2014,
Civil Engineering Department,
UPTU, LUCKNOW,
Mob: 7906743940
Email:
shubhamce2014@gmail.com
2
DETAILING OF BEAMS
3
Learning out Come
• Introduction
• Simply supported rectangular beams
• Continuous rectangular beams
• Cantilever rectangular beams
• Flanged beams
4
Introduction
• Carries Transverse External Loads That
Cause Bending Moment, Shear Forces And In
Some Cases Torsion
• Concrete is strong in compression and very
weak in tension.
• Steel reinforcement is used to take up tensile
stresses in reinforced concrete beams.
• Mild steel bars or Deformed or High yield
strength deformed bars (HYSD)
• HYSD bars have ribs on the surface and this
increases the bond strength at least by 40%
5
Introduction
6
•Drawinsg generally include a bar
bending schedule
•The bar bending schedule describes the
length and number, position and the
shape of the bar
Introduction
Sl.No.
Type of
bar and
mark
Shape No.
Length in
m
Weight
per unit
length
in Kg
Weight
in Kg
7
•Anchorage in steel bars is normally
provided in the form of bends and hooks
•The anchorage value of bend of bar is
taken as 4 times the diameter of bar for
every 450 bend subjected to maximum of
16 times the diameter of bar.
Introduction
8
Standard hooks
9
• The beams are classified as:
• According to shape: Rectangular, T,
L, Circular etc
• According to supporting conditions:
Simply supported, fixed, continuous
and cantilever beams
• According to reinforcement: Singly
reinforced and doubly reinforced
Introduction
10
• Minimum cover in beams must be 25
mm or shall not be less than the
larger diameter of bar for all steel
reinforcement including links.
• Nominal cover specified in Table 16
and 16A of IS456-2000 should be
used to satisfy the durability criteria.
Introduction
11
Generally a beam consists of following steel
reinforcements:
•Longitudinal reinforcement at tension and
compression face.
•Shear reinforcements in the form of vertical
stirrups and or bent up longitudinal bars are
provided.
•Side face reinforcement in the web of the beam
is provided when the depth of the web in a beam
exceeds 750 mm. (0.1% of the web area and shall
be distributed equally on two faces at a spacing
not exceeding 300 mm or web thickness
whichever is less)
Introduction
12
Specification for the reinforcement in beams is given in
clause 8.1 to 8.6 of SP34
13
14
15
16
17
Different forms of stirrups used in beams
18
Typical drawing of a simply supported beam
19
20
PROBLEM No. 1
Draw the Longitudinal section, cross section and prepare bar
bending schedule of a rectangular simply supported RCC beam with
the following data:
Clear span =3.5m
Width of beam = 220mm
Overall depth of beam = 300mm
Bearing width in support = 200 mm
Main reinforcement = 5 Nos -12 mm diameter bars with 2 bars bent
up at L/7 from centre of support
Anchor/hanger bars= 2-10 mm diameter
Stirrups = 6 mm diameter @ 200 mm c/c.
Materials : Mild steel, M20 grade concrete
21
PROBLEM No. 1
22
PROBLEM No. 1 contd.
Bar Bending Schedule:
Bottom straight bar (12 dia)= Total length of beam +2 x16 φ-2 x 3 φ
-2 x end cover
= (3500+2 x 200)+26 x 12-2 x 25 =4162≈4200 mm
Length of bent up bar (12 dia)= Length of straight bar +2 x (0.42 x
depth of bend) =4162+2 x 0.42 x 250 =4372≈4400 mm
Length of hanger bar (10 dia)= Length of straight bar =4162≈4200 mm
Stirrups:
Number of stirrups = Length of bar (end to end)/c/c distance of
stirrup= [(3500+2x200)-2x25]/200 = 17
Length of stirrup = 2 ( A+B)+24 φ of stirrup = 2x(250+170)+24 x 6
= 984 mm ≈ 1000 mm
23
PROBLEM No. 1 contd.
24
PROBLEM No. 2
Draw the Longitudinal section, cross section and
prepare bar bending schedule of a rectangular simply
supported RCC beam with the following data:
Clear span =4.5m
Width of beam = 250mm
Overall depth of beam = 300mm
Main reinforcement = 5 Nos -18 mm diameter bars with 2 bars
bent up at 900mm from inside of each end support
Anchor/hanger bars= 2-12 mm diameter
Stirrups = 6 mm diameter @ 200 mm c/c.
Concrete cover = 25 mm
Materials : HYSD bars, M20 grade concrete
25
PROBLEM No. 2
26
PROBLEM No. 2 contd.
Bar Bending Schedule:
Bottom straight bar (18 dia)= Total length of beam -2 x end cover
= (4500+2 x 200) -2 x 25 =4850 mm
Length of bent up bar (18 dia) = Length of straight bar +2 x (0.42 x
depth of bend) =4850+2 x 0.42 x 250 =5050 mm
Length of hanger bar (12 dia)= Length of straight bar =4850 mm
Stirrups:
Number of stirrups = Length of bar (end to end)/c/c distance of
stirrup = [(4500+2x200)-2x25]/200 = 24.25 ≈ 25
Length of stirrup = 2 ( A+B)+24 φ of stirrup
= 2x(250+200)+24 x 6 = 1044 mm ≈ 1100 mm
27
PROBLEM No. 2 contd.
28
29
PROBLEM No. 3
Draw the Longitudinal section and two cross sections one near the
support and other near the mid span of a RCC continuous beam with
the following data:
Clear span of beams = 3m each
Width of beam = 200mm
Overall depth of beam = 300mm
Width in intermediate supports = 200 mm
Main reinforcement = 4 Nos -12 mm diameter bars with 2 bars bent up
Anchor/hanger bars= 2-10 mm diameter
Stirrups = 6 mm diameter @ 300 mm c/c.
Materials : HYSD bars and M20 grade concrete
30
PROBLEM No. 3
31
PROBLEM No. 4
A rectangular beam of cross section 300 x 450 mm is
supported on 4 columns which are equally spaced at 3m
c/c. The columns are of 300 mm x 300 mm in section. The
reinforcement consists of 4 bars of a6 mm diameter (+ve
reinforcement) at mid span and 4 bars of 16 mm diameter at
all supports (-ve reinforcement). Anchor bars consists of a
2-16 mm diameter. Stirrups are of 8 mm diameter 2 legged
vertical at 200 c/c throughout. Grade of concrete is M20 and
type of steel is Fe 415.
Draw longitudinal section and important cross sections.
32
PROBLEM No. 4
33
34
PROBLEM No. 5
Draw to scale of 1:20 the Longitudinal section and two cross-
section of a cantilever beam projecting 3.2 from a support using
following data
Clear span =3.2m
Overall depth at free end = 150 mm
Overall depth at fixed end = 450 mm
Width of cantilever beam = 300 mm
Main steel = 4-28 mm dia with two bars curtailed
at 1.5m from support
Anchor bars = 2 Nos. 16 mm dia
Nominal stirrups = 6mm dia at 40 mm c/c
Bearing at fixed end = 300 mm
Use M20 concrete and Fe 415 steel
35
PROBLEM No. 5
36
PROBLEM No. 6
A cantilever beam with 3.2m length is resting over a masonry wall and
supporting a slab over it. Draw to a suitable scale Longitudinal section,
two cross-sections and sectional plan with the following data:
Size of beam = 300 mm x 350 mm at free end and 300 mm x 450 mm at
fixed end and in the wall up to a length of 4.8m
Main steel: 4 nos. of 25 mm dia bars, two bars curtailed at 1.2m from
free end
Hanger bars: 2 nos. 16mm.
Stirrups: 6mm dia 2 legged stirrups @ 200 mm c/c the support length
and @100 mm c/c from fixed end up to length of 1m @ 150mm c/c up to
curtailed bars and remaining @ 200 c/c.
Use M20 concrete and Fe 415 steel
37
PROBLEM No. 2
38
39
PROBLEM No. 7
A beam has following data
Clear span = 4m
Support width = 300mm
Size of web = 350 x 400
Size of flange = 1200 x 120mm
Main reinforcement in two layers : 3-20 tor + 3-16 tor and to be
curtailed at a distance 400 mm from inner face of support
Hanger bars: 3- 20 tor
Stirrups: 2L-8 tor @ 200 c/c
Use M20 concrete and Fe 415 steel
Draw longitudinal and cross section if the beam is
1. T-beam
2. Inverted T-beam
3. L-Beam
40
PROBLEM No. 5
41
42
PROBLEM No. 5
43
PROBLEM No. 5
44
Do it Yourself
1. Draw the longitudinal section and typical cross sections ( at centre
and support), and show the reinforcement details in a simply supported
rectangular beam of size 300 mm x 500 mm, clear span 5m supported
on walls of 0.3m, use a suitable scale
Reinforcements:
Main: 4 No. 16mm dia with 2 No. cranked at 1m from centre of
support. Stirrup holders 2 Nos. of 12 mm dia
Stirrups: 2 legged 8 mm dia stirrups at 250 mm c/c in the central 2m
span and 2 legged 8 mm dia stirrups at 150 mm c/c in the remaining
portion. Assume concrete M 20 grade and steel Fe 415, and suitable
cover. Prepare the bar bending schedule and calculate quantity of steel
and concrete required.
45
Do it Yourself
2. Prepare the bar bending schedule and estimate quantity of steel and
concrete after drawing the longitudinal and cross section. Other details
are
Span of beam = 4.2 m
Cross section at support end 300 x 600 mm and cross section at
free end 300 x 150 mm
Reinforcements:
Main tension steel: 4-20 mm dia, 2 bars are curtailed at a distance
of 2m from free end
Hanger bars: 1-12 mm dia
Two legged stirrups 8mm dia @ 140 mm c/c for full length.
46
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Beam Design and Drawing of RCC Structures

  • 1. 1 Design and drawing of RCC Structures SHUBHAMCE2014, Civil Engineering Department, UPTU, LUCKNOW, Mob: 7906743940 Email: shubhamce2014@gmail.com
  • 3. 3 Learning out Come • Introduction • Simply supported rectangular beams • Continuous rectangular beams • Cantilever rectangular beams • Flanged beams
  • 4. 4 Introduction • Carries Transverse External Loads That Cause Bending Moment, Shear Forces And In Some Cases Torsion • Concrete is strong in compression and very weak in tension. • Steel reinforcement is used to take up tensile stresses in reinforced concrete beams. • Mild steel bars or Deformed or High yield strength deformed bars (HYSD) • HYSD bars have ribs on the surface and this increases the bond strength at least by 40%
  • 6. 6 •Drawinsg generally include a bar bending schedule •The bar bending schedule describes the length and number, position and the shape of the bar Introduction Sl.No. Type of bar and mark Shape No. Length in m Weight per unit length in Kg Weight in Kg
  • 7. 7 •Anchorage in steel bars is normally provided in the form of bends and hooks •The anchorage value of bend of bar is taken as 4 times the diameter of bar for every 450 bend subjected to maximum of 16 times the diameter of bar. Introduction
  • 9. 9 • The beams are classified as: • According to shape: Rectangular, T, L, Circular etc • According to supporting conditions: Simply supported, fixed, continuous and cantilever beams • According to reinforcement: Singly reinforced and doubly reinforced Introduction
  • 10. 10 • Minimum cover in beams must be 25 mm or shall not be less than the larger diameter of bar for all steel reinforcement including links. • Nominal cover specified in Table 16 and 16A of IS456-2000 should be used to satisfy the durability criteria. Introduction
  • 11. 11 Generally a beam consists of following steel reinforcements: •Longitudinal reinforcement at tension and compression face. •Shear reinforcements in the form of vertical stirrups and or bent up longitudinal bars are provided. •Side face reinforcement in the web of the beam is provided when the depth of the web in a beam exceeds 750 mm. (0.1% of the web area and shall be distributed equally on two faces at a spacing not exceeding 300 mm or web thickness whichever is less) Introduction
  • 12. 12 Specification for the reinforcement in beams is given in clause 8.1 to 8.6 of SP34
  • 13. 13
  • 14. 14
  • 15. 15
  • 16. 16
  • 17. 17 Different forms of stirrups used in beams
  • 18. 18 Typical drawing of a simply supported beam
  • 19. 19
  • 20. 20 PROBLEM No. 1 Draw the Longitudinal section, cross section and prepare bar bending schedule of a rectangular simply supported RCC beam with the following data: Clear span =3.5m Width of beam = 220mm Overall depth of beam = 300mm Bearing width in support = 200 mm Main reinforcement = 5 Nos -12 mm diameter bars with 2 bars bent up at L/7 from centre of support Anchor/hanger bars= 2-10 mm diameter Stirrups = 6 mm diameter @ 200 mm c/c. Materials : Mild steel, M20 grade concrete
  • 22. 22 PROBLEM No. 1 contd. Bar Bending Schedule: Bottom straight bar (12 dia)= Total length of beam +2 x16 φ-2 x 3 φ -2 x end cover = (3500+2 x 200)+26 x 12-2 x 25 =4162≈4200 mm Length of bent up bar (12 dia)= Length of straight bar +2 x (0.42 x depth of bend) =4162+2 x 0.42 x 250 =4372≈4400 mm Length of hanger bar (10 dia)= Length of straight bar =4162≈4200 mm Stirrups: Number of stirrups = Length of bar (end to end)/c/c distance of stirrup= [(3500+2x200)-2x25]/200 = 17 Length of stirrup = 2 ( A+B)+24 φ of stirrup = 2x(250+170)+24 x 6 = 984 mm ≈ 1000 mm
  • 24. 24 PROBLEM No. 2 Draw the Longitudinal section, cross section and prepare bar bending schedule of a rectangular simply supported RCC beam with the following data: Clear span =4.5m Width of beam = 250mm Overall depth of beam = 300mm Main reinforcement = 5 Nos -18 mm diameter bars with 2 bars bent up at 900mm from inside of each end support Anchor/hanger bars= 2-12 mm diameter Stirrups = 6 mm diameter @ 200 mm c/c. Concrete cover = 25 mm Materials : HYSD bars, M20 grade concrete
  • 26. 26 PROBLEM No. 2 contd. Bar Bending Schedule: Bottom straight bar (18 dia)= Total length of beam -2 x end cover = (4500+2 x 200) -2 x 25 =4850 mm Length of bent up bar (18 dia) = Length of straight bar +2 x (0.42 x depth of bend) =4850+2 x 0.42 x 250 =5050 mm Length of hanger bar (12 dia)= Length of straight bar =4850 mm Stirrups: Number of stirrups = Length of bar (end to end)/c/c distance of stirrup = [(4500+2x200)-2x25]/200 = 24.25 ≈ 25 Length of stirrup = 2 ( A+B)+24 φ of stirrup = 2x(250+200)+24 x 6 = 1044 mm ≈ 1100 mm
  • 28. 28
  • 29. 29 PROBLEM No. 3 Draw the Longitudinal section and two cross sections one near the support and other near the mid span of a RCC continuous beam with the following data: Clear span of beams = 3m each Width of beam = 200mm Overall depth of beam = 300mm Width in intermediate supports = 200 mm Main reinforcement = 4 Nos -12 mm diameter bars with 2 bars bent up Anchor/hanger bars= 2-10 mm diameter Stirrups = 6 mm diameter @ 300 mm c/c. Materials : HYSD bars and M20 grade concrete
  • 31. 31 PROBLEM No. 4 A rectangular beam of cross section 300 x 450 mm is supported on 4 columns which are equally spaced at 3m c/c. The columns are of 300 mm x 300 mm in section. The reinforcement consists of 4 bars of a6 mm diameter (+ve reinforcement) at mid span and 4 bars of 16 mm diameter at all supports (-ve reinforcement). Anchor bars consists of a 2-16 mm diameter. Stirrups are of 8 mm diameter 2 legged vertical at 200 c/c throughout. Grade of concrete is M20 and type of steel is Fe 415. Draw longitudinal section and important cross sections.
  • 33. 33
  • 34. 34 PROBLEM No. 5 Draw to scale of 1:20 the Longitudinal section and two cross- section of a cantilever beam projecting 3.2 from a support using following data Clear span =3.2m Overall depth at free end = 150 mm Overall depth at fixed end = 450 mm Width of cantilever beam = 300 mm Main steel = 4-28 mm dia with two bars curtailed at 1.5m from support Anchor bars = 2 Nos. 16 mm dia Nominal stirrups = 6mm dia at 40 mm c/c Bearing at fixed end = 300 mm Use M20 concrete and Fe 415 steel
  • 36. 36 PROBLEM No. 6 A cantilever beam with 3.2m length is resting over a masonry wall and supporting a slab over it. Draw to a suitable scale Longitudinal section, two cross-sections and sectional plan with the following data: Size of beam = 300 mm x 350 mm at free end and 300 mm x 450 mm at fixed end and in the wall up to a length of 4.8m Main steel: 4 nos. of 25 mm dia bars, two bars curtailed at 1.2m from free end Hanger bars: 2 nos. 16mm. Stirrups: 6mm dia 2 legged stirrups @ 200 mm c/c the support length and @100 mm c/c from fixed end up to length of 1m @ 150mm c/c up to curtailed bars and remaining @ 200 c/c. Use M20 concrete and Fe 415 steel
  • 38. 38
  • 39. 39 PROBLEM No. 7 A beam has following data Clear span = 4m Support width = 300mm Size of web = 350 x 400 Size of flange = 1200 x 120mm Main reinforcement in two layers : 3-20 tor + 3-16 tor and to be curtailed at a distance 400 mm from inner face of support Hanger bars: 3- 20 tor Stirrups: 2L-8 tor @ 200 c/c Use M20 concrete and Fe 415 steel Draw longitudinal and cross section if the beam is 1. T-beam 2. Inverted T-beam 3. L-Beam
  • 41. 41
  • 44. 44 Do it Yourself 1. Draw the longitudinal section and typical cross sections ( at centre and support), and show the reinforcement details in a simply supported rectangular beam of size 300 mm x 500 mm, clear span 5m supported on walls of 0.3m, use a suitable scale Reinforcements: Main: 4 No. 16mm dia with 2 No. cranked at 1m from centre of support. Stirrup holders 2 Nos. of 12 mm dia Stirrups: 2 legged 8 mm dia stirrups at 250 mm c/c in the central 2m span and 2 legged 8 mm dia stirrups at 150 mm c/c in the remaining portion. Assume concrete M 20 grade and steel Fe 415, and suitable cover. Prepare the bar bending schedule and calculate quantity of steel and concrete required.
  • 45. 45 Do it Yourself 2. Prepare the bar bending schedule and estimate quantity of steel and concrete after drawing the longitudinal and cross section. Other details are Span of beam = 4.2 m Cross section at support end 300 x 600 mm and cross section at free end 300 x 150 mm Reinforcements: Main tension steel: 4-20 mm dia, 2 bars are curtailed at a distance of 2m from free end Hanger bars: 1-12 mm dia Two legged stirrups 8mm dia @ 140 mm c/c for full length.