Arrays
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This C++ function finds a single missing integer in an array by: 1) Calculating the total of all numbers that should be in the full range 2) Summing the numbers in the provided array 3) Returning the difference between the full range total and current array total
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![// finds a single missing integer in an array
unsigned Arrays::MissingInt(unsigned* _arr, unsigned _arrSize)
{
// equation for summing all numbers in a range ('- 1' since _arr starts at 1)
unsigned grandTotal = ((_arrSize * (_arrSize + 1)) / 2) - 1;
// summing of numbers in the array
// since array is short by 1, must reduce by 2 to get actual back index value
unsigned front = 0, back = _arrSize - 2, arrTotal = 0;
// two at a time. ie front and back of array (faster)
// do while instead of for loop because i think it looks better (cleaner)
do{
arrTotal += (_arr[front++] + _arr[back--]);
} while (front < back);
// if odd numbered array, front and back will eventually be the same
// need to add ONE of them to arrTotal (not both)
// did this here to avoid running the check every loop
if (front == back) arrTotal += _arr[front];
// subtracting current total from grand total will return the missing number
return grandTotal - arrTotal;
}
// compares values in array to find a single duplicate (multiple versions)
unsigned Arrays::DuplicatedInt(unsigned* _arr, unsigned _arrSize)
{
#if 1
// fast O(count), but extra memory (hash_map)
hash_map<unsigned, unsigned> dupCheck;
for (unsigned count = 0; count < _arrSize; count++)
{
if (!dupCheck.emplace(_arr[count], _arr[count]).second)
return _arr[count];
}
#endif
#if 0
// double for loop = slow O(n^2), but breaks as soon as it finds a duplicate so O(n * count)
// also no extra variable(s)
for (unsigned countA = 0; countA < _arrSize; countA++)
{
for (unsigned countB = countA + 1; countB < _arrSize; countB++)
{
if (_arr[countA] == _arr[countB])
return _arr[countA];
}
}
#endif
#if 0
// takes time to sort (esp w/ 1,000,000 entries), but less memory (no extra variable(s))
O(nlog(n) + count)?
std::sort(_arr, _arr + _arrSize);
for (unsigned count = 0; count < _arrSize; count++)
{
if (_arr[count] == _arr[count + 1])
return _arr[count];
}
#endif
return -1;
}](https://image.slidesharecdn.com/arrays-151023203215-lva1-app6891/85/Arrays-1-320.jpg)
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Similar to Arrays
i am using C++ codingsource coding Program that sorts an arra.pdf
i am using C++ coding
source coding:
// Program that sorts an array using Heap Sort method
# include
# include
const int MAX = 10 ;
class array
{
private :
int arr[MAX] ;
int count ;
public :
array( ) ;
void add ( int num ) ;
void makeheap( ) ;
void heapsort( ) ;
void display( ) ;
} ;
// initialises data member
array :: array( )
{
count = 0 ;
for ( int i = 0 ; i < MAX ; i++ )
arr[MAX] = 0 ;
}
// adds element to an array
void array :: add ( int num )
{
if ( count < MAX )
{
arr[count] = num ;
count++ ;
}
else
cout << \"\ Array is full\" << endl ;
}
// creates heap from the tree
void array :: makeheap( )
{
for ( int i = 1 ; i < count ; i++ )
{
int val = arr[i] ;
int s = i ;
int f = ( s - 1 ) / 2 ;
while ( s > 0 && arr[f] < val )
{
arr[s] = arr[f] ;
s = f ;
f = ( s - 1 ) / 2 ;
}
arr[s] = val ;
}
}
// sorts heap
void array :: heapsort( )
{
for ( int i = count - 1 ; i > 0 ; i-- )
{
int ivalue = arr[i] ;
arr[i] = arr[0] ;
int f = 0 ;
int s ;
if ( i == 1 )
s = -1 ;
else
s = 1 ;
if ( i > 2 && arr[2] > arr[1] )
s = 2 ;
while ( s >= 0 && ivalue < arr[s] )
{
arr[f] = arr[s] ;
f = s ;
s = 2 * f + 1 ;
if ( s + 1 <= i - 1 && arr[s] < arr[s + 1] )
s++ ;
if ( s > i - 1 )
s = -1 ;
}
arr[f] = ivalue ;
}
}
// displays contents
void array :: display( )
{
for ( int i = 0 ; i < count ; i++ )
cout << arr[i] << \"\\t\" ;
cout << endl ;
}
void main( )
{
array a ;
clrscr();
a.add ( 11 ) ;
a.add ( 2 ) ;
a.add ( 9 ) ;
a.add ( 13 ) ;
a.add ( 57 ) ;
a.add ( 25 ) ;
a.add ( 17 ) ;
a.add ( 1 ) ;
a.add ( 90 ) ;
a.add ( 3 ) ;
a.makeheap( ) ;
cout << \"\ Heap Sort.\ \" ;
cout << \"\ Before Sorting:\ \" ;
a.display( ) ;
a.heapsort( ) ;
cout << \"\ After Sorting:\ \" ;
a.display( ) ;
getch();
}
Solution
i am using C++ coding
source coding:
// Program that sorts an array using Heap Sort method
# include
# include
const int MAX = 10 ;
class array
{
private :
int arr[MAX] ;
int count ;
public :
array( ) ;
void add ( int num ) ;
void makeheap( ) ;
void heapsort( ) ;
void display( ) ;
} ;
// initialises data member
array :: array( )
{
count = 0 ;
for ( int i = 0 ; i < MAX ; i++ )
arr[MAX] = 0 ;
}
// adds element to an array
void array :: add ( int num )
{
if ( count < MAX )
{
arr[count] = num ;
count++ ;
}
else
cout << \"\ Array is full\" << endl ;
}
// creates heap from the tree
void array :: makeheap( )
{
for ( int i = 1 ; i < count ; i++ )
{
int val = arr[i] ;
int s = i ;
int f = ( s - 1 ) / 2 ;
while ( s > 0 && arr[f] < val )
{
arr[s] = arr[f] ;
s = f ;
f = ( s - 1 ) / 2 ;
}
arr[s] = val ;
}
}
// sorts heap
void array :: heapsort( )
{
for ( int i = count - 1 ; i > 0 ; i-- )
{
int ivalue = arr[i] ;
arr[i] = arr[0] ;
int f = 0 ;
int s ;
if ( i == 1 )
s = -1 ;
else
s = 1 ;
if ( i > 2 && arr[2] > arr[1] )
s = 2 ;
while ( s >= 0 && ivalue < arr[s] )
{
arr[f] = arr[s] ;
f = s ;
s = 2 * f + 1 ;
if ( s + 1 <= i - 1 && arr[s] < arr[s + 1] )
s++ ;
if ( s > i - 1 )
s = -1 ;
}
arr[f] = ivalue ;
}
}
// displays contents
void array :: display( )
{
for ( int i = 0 ; i < count ; i++ )
cout << arr[.
How do you stop infinite loop Because I believe that it is making a.pdf
How do you stop infinite loop? Because I believe that it is making an infinite circular list.
c++ code:
Here is the list class:
#ifndef LIN_J_LIST
#define LIN_J_LIST
typedef unsigned int uint;
#include
#include
using namespace std;
/**
* a simplified generic singly linked list class to illustrate C++ concepts
* @author Jerry Lin
* @version 2/17/17
*/
template< typename Object >
class List
{
private:
/**
* A class to store data and provide a link to the next node in the list
*/
class Node
{
public:
/**
* The constructor
* @param data the data to be stored in this node
*/
explicit Node( const Object & data )
: data{ data }, next{ nullptr } {}
Object data;
Node * next;
};
public:
/**
* The constructor for an empty list
*/
List()
: size{ 0 }, first{ nullptr }, last{ nullptr } {}
/**
* the copy constructor-creates and copy the list
*/
List( List && rhs ) = delete;
List( const List & rhs )
{
count = 0;
size = 0;
if(rhs.size != 0)
{
push_front(rhs.front());
Node * current = rhs.first;
Node * tempNode = first;
size++;
while(current->next != nullptr)
{
current = current->next;
Node *newNode = new Node(current->data); //transfer the data. basic op.
count++;
tempNode->next = newNode;
last = newNode;
tempNode = tempNode->next;
size++;
}
}
// you document and implement this method
}
/**
* the operator= method-copies the list
*/
List & operator=( List && rhs) = delete;
List & operator=( const List & rhs )
{
count = 0;
size = 0;
if( size != 0 )
{
Node * current = first;
Node * temp;
while( current != nullptr )
{
temp = current;
current = current->next;
delete temp;
}
}
if(rhs.size!= 0)
{
push_front(rhs.front());
Node * current = rhs.first;
Node * tempNode = first; //create a temporary to store
size++;
while(current -> next != nullptr)
{
current = current->next;
Node *newNode = new Node(current->data); //transfer the data. basic op
count++;
tempNode->next = newNode;
last = newNode;
tempNode = tempNode -> next;
size++;
}
}
return *this;
// you document and implement this method
}
/**
* accessor
* @return count
*/
int get_count() const
{
return count;
}
/**
* The destructor that gets rid of everything that\'s in the list and
* resets it to empty. If the list is already empty, do nothing.
*/
~List()
{
if( size != 0 )
{
Node * current = first;
Node * temp;
while( current != nullptr )
{
temp = current;
current = current->next;
delete temp;
}
}
}
/**
* Put a new element onto the beginning of the list
* @param item the data the new element will contain
*/
void push_front( const Object& item )
{
Node * new_node = new Node( item );//basic op.
if(is_empty())
{
last = new_node;
}
else
{
new_node->next = first;
}
first = new_node;
size++;
/* you complete the rest */
}
/**
* Remove the element that\'s at the front of the list. Causes an
* assertion error if the list is empty.
*/
void pop_front()
{
assert( !is_empty() );
Node * temp = first;
if( first == last )
{
first = last = nullptr;
}
else
{
first = first->next;
}
delete temp;
size--;
}
/**
* Accessor to return the da.
Maxima Finding problem In the 2-dimension space, we shall say that .pdf
Maxima Finding problem: In the 2-dimension space, we shall say that a point A=(A1,A2)
dominates a point B=(b1,B2) if A1>B1 and A2>B2. Design an algorithm to find all maximal
points
Solution
we will use a divide and conquer algorithm of O(n log n) complexity which is merge sort.This
will ensure that each recursive call marks the maximal points among those that it is returning, or
return the maximal points as an additional part of the return value, and produce a merged and
corrected list of maximal points, in order, for its caller.The merge sort can be implemented in
c++
MERGE SORT:
/*This is basically a helper function which is used for finding the maximum of two numbers */
int maximum(int x, int y)
{
if(x > y)
{
return x;
}
else
{
return y;
}
}
/* The left is defined as the index of the leftmost element of the subarray;
On the other hand the right is one past the index of the rightmost element */
void merge_helper_function(int *input, int left, int right, int *scratch1)
{
/* This is the base case: one element */
if(right == left + 1)
{
return;
}
else
{
int i = 0;
int length = right - left;
int midpoint_distance = length/2;
/* The l and r are to the positions in the left and right subarrays */
int l = left, r = left + midpoint_distance;
/* now we will sort each subarray */
merge_helper)function(input, left, left + midpoint_distance, scratch);
merge_helper_function(input, left + midpoint_distance, right, scratch);
/* Finally we will merge the arrays together using scratch for temporary storage */
for(i = 0; i < length; i++)
{
/* First we will check to see if any elements remain in the left array; if so,
The next we check if there are any elements left in the right array; if so, we compare
them. Otherwise, we know that the merge must
* use take the element from the left array */
if(l < left + midpoint_distance &&
(r == right || maximum(input[l], input[r]) == input[l]))
{
scratch1[i] = input[l];
l++;
}
else
{
scratch1[i] = input[r];
r++;
}
}
/*Finally we copy the sorted subarray back to the input */
for(i = left; i < right; i++)
{
input[i] = scratch1[i - left];
}
}
}
/*The mergesort function returns true on success
*/
int mergesortfunction(int *input, int size)
{
int *scratchone = (int *)malloc(size * sizeof(int));
if(scratchone != NULL)
{
merge_helper_function(input, 0, size, scratchone);
free(scratchone);
return 1;
}
else
{
return 0;
}
}.
Merge Sort implementation in C++ The implementation for Mergesort gi.pdf
Merge Sort implementation in C++ The implementation for Mergesort given in Section 7.4 takes
an array as input and soils that array. At the beginning of Section 7.4 there is a simple
pseudocode implementation for sorting a linked list using Mergesort. Implement both a linked
list-based version of Mergesort and the array-based version of Mergesort. and compare and
analyze their running times.
Solution
/* Merger sort array-based version */
/* C program for Merge Sort */
#include
#include
// Merges two subarrays of arr[].
// First subarray is arr[l..m]
// Second subarray is arr[m+1..r]
void merge(int arr[], int l, int m, int r)
{
int i, j, k;
int n1 = m - l + 1;
int n2 = r - m;
/* create temp arrays */
int L[n1], R[n2];
/* Copy data to temp arrays L[] and R[] */
for (i = 0; i < n1; i++)
L[i] = arr[l + i];
for (j = 0; j < n2; j++)
R[j] = arr[m + 1+ j];
/* Merge the temp arrays back into arr[l..r]*/
i = 0; // Initial index of first subarray
j = 0; // Initial index of second subarray
k = l; // Initial index of merged subarray
while (i < n1 && j < n2)
{
if (L[i] <= R[j])
{
arr[k] = L[i];
i++;
}
else
{
arr[k] = R[j];
j++;
}
k++;
}
/* Copy the remaining elements of L[], if there
are any */
while (i < n1)
{
arr[k] = L[i];
i++;
k++;
}
/* Copy the remaining elements of R[], if there
are any */
while (j < n2)
{
arr[k] = R[j];
j++;
k++;
}
}
/* l is for left index and r is right index of the
sub-array of arr to be sorted */
void mergeSort(int arr[], int l, int r)
{
if (l < r)
{
// Same as (l+r)/2, but avoids overflow for
// large l and h
int m = l+(r-l)/2;
// Sort first and second halves
mergeSort(arr, l, m);
mergeSort(arr, m+1, r);
merge(arr, l, m, r);
}
}
/* UTILITY FUNCTIONS */
/* Function to print an array */
void printArray(int A[], int size)
{
int i;
for (i=0; i < size; i++)
printf(\"%d \", A[i]);
printf(\"\ \");
}
/* Driver program to test above functions */
int main()
{
int arr[] = {12, 11, 13, 5, 6, 7};
int arr_size = sizeof(arr)/sizeof(arr[0]);
printf(\"Given array is \ \");
printArray(arr, arr_size);
mergeSort(arr, 0, arr_size - 1);
printf(\"\ Sorted array is \ \");
printArray(arr, arr_size);
return 0;
}
--------------------------------------------------------------------------------------------------------------------
/* merge sort link-list version
#include
#include
/* Link list node */
struct node
{
int data;
struct node* next;
};
/* function prototypes */
struct node* SortedMerge(struct node* a, struct node* b);
void FrontBackSplit(struct node* source,
struct node** frontRef, struct node** backRef);
/* sorts the linked list by changing next pointers (not data) */
void MergeSort(struct node** headRef)
{
struct node* head = *headRef;
struct node* a;
struct node* b;
/* Base case -- length 0 or 1 */
if ((head == NULL) || (head->next == NULL))
{
return;
}
/* Split head into \'a\' and \'b\' sublists */
FrontBackSplit(head, &a, &b);
/* Recursively sort the sublists */
MergeSort(&a);
MergeSort(&b);
/* answer = merge the two sorted lists together */
*.
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Part 1)
#include
#include
#include
#include
/*Error handling for pthread_create and pthread_join*/
/*from the pthread_create man page*/
#define handle_error_en(en, msg) \\
do { errno = en; perror(msg); exit(EXIT_FAILURE); } while (0)
/* # of running threads */
volatile int running_threads = 0;
pthread_t thread[3]; /*Descriptors for our 3 threads*/
int numOfElements;/*Total # of elements from the user*/
struct Results{ /*Struct to hold the statistical results*/
int min;
int max;
int average;
}Results;
/*This function finds the minimum element of an array*/
void *findMin(void *array_ptr){
int i; /*counter*/
int *elements = (int*)array_ptr; /*re reference void array pointer*/
Results.min = elements[0]; /*set minimum to first element */
for(i = 0; i < numOfElements; i++){ /*iterate through array*/
if(elements[i] < Results.min){ /*if the current element is less than the current min*/
Results.min = elements[i]; /*store the new min*/
}
}
running_threads -= 1; /*Decrement thread count*/
return NULL;
}
/*This function finds the maximum element of an array*/
void *findMax(void *array_ptr){
int i; /*counter*/
int *elements = (int*)array_ptr; /*re reference void array pointer*/
for(i = 0; i < numOfElements; i++){ /*iterate through array*/
if(elements[i] > Results.max){ /*store the new max*/
Results.max = elements[i];
}
}
running_threads -= 1; /*Decrement thread count*/
return NULL;
}
/*This function finds the average of an array*/
void *findAverage(void *array_ptr){
int i; /*counter*/
int *elements = (int*)array_ptr; /*re reference void array pointer*/
for(i = 0; i < numOfElements; i++){ /*iterate through array*/
Results.average += elements[i]; /*add element @ i to average*/
}
Results.average = Results.average/numOfElements; /*Divide the sum by the number of
elements*/
running_threads -= 1; /*Decrement running threads counter*/
return NULL;
}
/* This method accepts a int n(initial size of array) and
pointer to an array and returns # of elements in the array
*/
int getArrayInput(int n, int *array_ptr){
int input;/*Store user input */
int numberOfElements = 0;/*Number of Integers inputed*/
printf(\"Creating Dynamic Array...\ -\ \");
for(;;){ /*infinite loop*/
printf(\"Enter a positive value:\ Negative Number to Stop\ -\ \");
//Get Int from console, store at address of input
if (scanf(\"%d\",&input) != 1){
printf(\"\ Oops that wasn\'t an Integer\ lets try filling the array again\ Remember
INTEGERS only!\ \");
exit(EXIT_FAILURE);
}
if (input >= 0){
if (numberOfElements == n){
n += 1; //Make room for the current input
array_ptr = realloc(array_ptr, n * sizeof(int));//realloc array and set pointer
}
array_ptr[numberOfElements++] = input;//Store input at next empty element
} else {
printf(\"\ Number of Integers: %d\ \", numberOfElements);
break;
}
}
return numberOfElements;
}
/*This function joins our n number of threads */
void joinThreads(int numberOfThreads){
int i; /*count*/
int s; /*error #*/
while(numberOfThreads >= 0){ /*Join our threads*/
s = pthread_jo.
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Can you give an example of a binary heap program
Can you give an example of a binary heap program
Solution
/*
* C Program to Implement a Heap & provide Insertion & Deletion Operation
*/
#include
int array[100], n;
main()
{
int choice, num;
n = 0;/*Represents number of nodes in the heap*/
while(1)
{
printf(\"1.Insert the element \ \");
printf(\"2.Delete the element \ \");
printf(\"3.Display all elements \ \");
printf(\"4.Quit \ \");
printf(\"Enter your choice : \");
scanf(\"%d\", &choice);
switch(choice)
{
case 1:
printf(\"Enter the element to be inserted to the list : \");
scanf(\"%d\", &num);
insert(num, n);
n = n + 1;
break;
case 2:
printf(\"Enter the elements to be deleted from the list: \");
scanf(\"%d\", &num);
delete(num);
break;
case 3:
display();
break;
case 4:
exit(0);
default:
printf(\"Invalid choice \ \");
}/*End of switch */
}/*End of while */
}/*End of main()*/
display()
{
int i;
if (n == 0)
{
printf(\"Heap is empty \ \");
return;
}
for (i = 0; i < n; i++)
printf(\"%d \", array[i]);
printf(\"\ \");
}/*End of display()*/
insert(int num, int location)
{
int parentnode;
while (location > 0)
{
parentnode =(location - 1)/2;
if (num <= array[parentnode])
{
array[location] = num;
return;
}
array[location] = array[parentnode];
location = parentnode;
}/*End of while*/
array[0] = num; /*assign number to the root node */
}/*End of insert()*/
delete(int num)
{
int left, right, i, temp, parentnode;
for (i = 0; i < num; i++) {
if (num == array[i])
break;
}
if (num != array[i])
{
printf(\"%d not found in heap list\ \", num);
return;
}
array[i] = array[n - 1];
n = n - 1;
parentnode =(i - 1) / 2; /*find parentnode of node i */
if (array[i] > array[parentnode])
{
insert(array[i], i);
return;
}
left = 2 * i + 1; /*left child of i*/
right = 2 * i + 2; /* right child of i*/
while (right < n)
{
if (array[i] >= array[left] && array[i] >= array[right])
return;
if (array[right] <= array[left])
{
temp = array[i];
array[i] = array[left];
array[left] = temp;
i = left;
}
else
{
temp = array[i];
array[i] = array[right];
array[right] = temp;
i = right;
}
left = 2 * i + 1;
right = 2 * i + 2;
}/*End of while*/
if (left == n - 1 && array[i]) {
temp = array[i];
array[i] = array[left];
array[left] = temp;
}
}
Output:.
Object oriented programming; operator overloading array
In programming, operator overloading, sometimes termed operator ad hoc polymorphism, is a specific case of polymorphism, where different operators have different implementations depending on their arguments. Operator overloading is generally defined by a programming language, a programmer, or both.
check the modifed code now you will get all operations done.termin.pdf
check the modifed code now you will get all operations done.
terminal will display add, subtract, multiply and div operation and dounday condition too.
#include
using namespace std;
class Array
{
private:
int start;
int end;
int *array;
public:
Array(int n);
Array(int n, int m);
int &operator[](int index);
Array &operator=(Array a);
bool operator==(Array &a);
bool operator!=(Array &a);
friend ostream &operator<<(ostream &out, Array &a);
friend Array &operator+(Array &a, Array&b);
friend Array &operator-(Array &a, Array&b);
friend Array &operator*(Array &a, Array&b);
friend Array &operator/(Array &a, Array&b);
};
Array::Array(int n)
{
start = 0;
end = n-1;
array = new int[n];
for (int i = 0; i < n; i++)
array[i] = i+1;
}
Array::Array(int n, int m)
{
start = n;
end = m-1;
array = new int[m-n];
for (int i = 0; i < m-n; i++)
array[i] = start + i;
}
int &Array::operator[](int index)
{
if (index >= start && index <= end)
{
return (array[index-start]);
}
cout << \"Error: Index out of bounds.\" << endl;
int temp = 0;
return temp;
//return *array;
}
Array &Array::operator=(Array a)
{
start = a.start;
end = a.end;
for(int i = 0; i < end - start; ++i)
{
array[i] = a.array[i];
}
return *this;
}
bool Array::operator==(Array &a)
{
for(int i = 0; i < end - start; ++i)
{
if(array[i] != a.array[i])
return false;
}
return true;
}
bool Array::operator!=(Array &a){
return *this == a;
}
ostream &operator<<(ostream &out, Array &b)
{
for(int i = 0; i < b.end - b.start; ++i)
{
out << \"(\" << i + b.start << \")\" << b.array[i] << \" \";
}
return out;
}
Array &operator+(Array &a, Array&b)
{
Array arr(a.end - a.start);
for(int i = 0; i < a.end - a.start; ++i)
{
arr.array[i] = a.array[i] + b.array[i];
}
return arr;
}
Array &operator-(Array &a, Array&b)
{
Array arr(a.end - a.start);
for(int i = 0; i < a.end - a.start; ++i)
{
arr.array[i] = a.array[i] - b.array[i];
}
return arr;
}
Array &operator*(Array &a, Array&b)
{
Array arr(a.end - a.start);
for(int i = 0; i < a.end - a.start; ++i)
{
arr.array[i] = a.array[i] * b.array[i];
}
return arr;
}
Array &operator/(Array &a, Array&b)
{
Array arr(a.end - a.start);
for(int i = 0; i < a.end - a.start; ++i)
{
if (a.array[i]!=0)
arr.array[i] = b.array[i] / a.array[i];
}
return arr;
}
int main()
{
Array test(10);
Array Ary1(10,25);
Array Ary2(-5,10);
Array Ary3(15,30);
int i;
int j;
for (i = 0; i < 10; i++)
test[i] = i+1;
cout << \"Test array output\" << endl;
for (i = 0; i < 10; i++)
cout << test[i] << \" \";
cout << endl;
i = -5;
while (i < 10)
{
Ary2[i] = i*2;
i++;
}
cout << \"\ \";
cout << \"Ary2 array otuput\" << endl;
for (i = -5; i < 10; i++)
cout << Ary2[i] << \" \";
cout << endl;
i = 10; j = -5;
while ( i < 25 )
{ Ary1[ i ] = i*100;
Ary2[j] = j * 200;
i++; j++;
};
cout << \"Ary1 array output\" << endl;
cout << Ary1 << endl;
cout << endl;
cout << \"\ \";
cout << \"Ary2 array output\" << endl;
cout << Ary2 << endl;
cout << endl;
cout << \"\ \";
for (i=0;i<14;i++)
Ary3[i+15] = Ary1[i+10] + Ary2[i+-5];
cout << \"Ary3 array Addi.
Program In C You are required to write an interactive C program that.pdf
Program In C You are required to write an interactive C program that prompts the user for
commands, accepts commands from the keyboard (stdin) and executes those commands. When a
command requires output, it must be written to stdout. The program must continue to accept and
process commands until the user types the end command ourput, it must be writen to stdout. The
program must continue to accept and proces.commands The program deals with linked lists.
Each node of such a list contains a string of length at most 10, a positive integer (i.e., an integer
value 2 1) and a pointer to the next node of the list. For any node, the string and the integer
stored in that node will be referred to as the symbol and count for that node respectively. At all
times, the list must satisfy the following two important properties. 1. The symbols appearing in
the list are all distinct; that is, no two nodes have the same symbol. 2. When the list is scanned
from left to right, the counts must be in non-increasing order. An example of such a linked list is
shown below. Search 4 Maxval4 begin/ Loop head
Solution
/**********************************************/
/****** NAMES ******************** COMMANDS ***/
/* Insert Command : ins str */
/* Delete Command : del str */
/* Forced Delete Command : fde val */
/* Print Statistics Command : pst */
/* Print List Command : prl */
/* Print using Count Range Command: pcr v1 v2 */
/* Print Prefix Command : ppr str */
/* Print Suffix Command : psu str */
/* End Command : end */
/***********************************************/
#include
#include
#include
#define CSIZE 4
#define SSIZE 11
/* Struct for each node in the linked list */
struct node
{
int count;
char symbol[SSIZE];
struct node *next;
};
struct node *head;
/* Prototypes for the functions */
void insert(char *);
void delete(char *);
void forced_delete(int value);
void print_stats();
void print_list();
void print_count(int, int);
void print_prefix(char pre[]);
void print_suffix(char suf[]);
void sort_list();
/****************
** Main Method **
****************/
int main(void)
{
int count;
char symbol[SSIZE];
char cmd[CSIZE];
int v1;
int v2;
/* Enter commands */
printf(\"Command? \"); fflush(stdout);
scanf(\"%s\", cmd);
/* Check for command*/
while(strcmp(cmd,\"end\") != 0)
{
/* check which function to use */
if(strcmp(cmd,\"ins\") == 0) { scanf(\"%s\", symbol); insert(symbol); }
if(strcmp(cmd,\"del\") == 0) { scanf(\"%s\", symbol); delete(symbol); }
else if(strcmp(cmd,\"fde\")==0){scanf(\"%d\",&count); forced_delete(count); }
if(strcmp(cmd,\"pst\") == 0) { print_stats();}
if(strcmp(cmd,\"prl\") == 0) { print_list(); }
if(strcmp(cmd,\"pcr\") == 0) { scanf(\"%d %d\",&v1,&v2); print_count(v1,v2); }
if(strcmp(cmd,\"ppr\") == 0) { scanf(\"%s\", symbol); print_prefix(symbol);}
if(strcmp(cmd,\"psu\") == 0) { scanf(\"%s\", symbol); print_suffix(symbol);}
printf(\"Command? \"); fflush(stdout);
scanf(\"%s\", cmd);
}// End of While Loop
return 0;
}// End of main method
/*********.
Pointers and arrays
This provides complete explanation about pointers and arrays. It also explains how to use pointers to process multi dimensional arrays.
I have written the code but cannot complete the assignment please help.pdf
I have written the code but cannot complete the assignment please help me to complete.
Please don't just copy other s answers as your own.
// Insertion sort
/*
#include <ctime>
#include <iostream>
using namespace std;
void insertionSort(int arr[], int n) {
int i, key, j;
for (i = 1; i < n; i++) {
key = arr[i];
j = i - 1;
// Move elements of arr[0..i-1], that are greater than key, to one position ahead of their current
position
while (j >= 0 && arr[j] > key) {
arr[j + 1] = arr[j];
j = j - 1;
}
arr[j + 1] = key;
}
}
int main() {
int n;
cout << "Enter the size of the array: ";
cin >> n;
int arr[n];
cout << "Enter the elements of the array: ";
for (int i = 0; i < n; i++) {
cin >> arr[i];
}
int num = sizeof(arr) / sizeof(arr[0]);
clock_t start, end;
double timetaken;
start = clock();
insertionSort(arr, num);
end = clock();
cout << "Sorted array: \n";
for (int i = 0; i < n; i++)
cout << arr[i] << " ";
cout << endl;
timetaken = ((double) (end - start)) / CLOCKS_PER_SEC;
cout << "Time taken : " << fixed << timetaken << "s" << endl;
return 0;
}
*/
// Shell Sort
/*
#include <ctime>
#include <iostream>
using namespace std;
int shellSort(int arr[], int n) {
for (int gap = n/2; gap > 0; gap /= 2) {
for (int i = gap; i < n; i += 1) {
int temp = arr[i];
int j;
for (j = i; j >= gap && arr[j - gap] > temp; j -= gap)
arr[j] = arr[j - gap];
arr[j] = temp;
}
}
return 0;
}
void printArray(int arr[], int n) {
for (int i=0; i<n; i++)
cout << arr[i] << " ";
}
int main() {
int n;
cout << "Enter the size of the array: ";
cin >> n;
int arr[n];
cout << "Enter the elements of the array: ";
for (int i = 0; i < n; i++) {
cin >> arr[i];
}
int num = sizeof(arr) / sizeof(arr[0]);
clock_t start, end;
double timetaken;
start = clock();
shellSort(arr, num);
end = clock();
cout << "\nArray after sorting: \n";
printArray(arr, n);
cout << endl;
timetaken = (double)(end - start) / CLOCKS_PER_SEC;
cout << "Time taken : " << fixed << timetaken << "s" << endl;
return 0;
}
*/
// MergeSort
/*
#include <ctime>
#include <iostream>
using namespace std;
void merge(int arr[], int l, int m, int r) {
int i, j, k;
int n1 = m - l + 1;
int n2 = r - m;
int L[n1], R[n2];
for (i = 0; i < n1; i++)
L[i] = arr[l + i];
for (j = 0; j < n2; j++)
R[j] = arr[m + 1 + j];
i = 0;
j = 0;
k = l;
while (i < n1 && j < n2) {
if (L[i] <= R[j]) {
arr[k] = L[i];
i++;
}
else {
arr[k] = R[j];
j++;
}
k++;
}
while (i < n1) {
arr[k] = L[i];
i++;
k++;
}
while (j < n2) {
arr[k] = R[j];
j++;
k++;
}
}
void mergeSort(int arr[], int l, int r) {
if (l < r) {
int m = l + (r - l) / 2;
mergeSort(arr, l, m);
mergeSort(arr, m + 1, r);
merge(arr, l, m, r);
}
}
int main() {
int n;
cout << "Enter the size of the array: ";
cin >> n;
int arr[n];
cout << "Enter the elements of the array: ";
for (int i = 0; i < n; i++) {
cin >> arr[i];
}
int arr_size = sizeof(arr) / sizeof(arr[0]);
clock_t start;
clock_t end;
double timetaken;
start = clock();
mergeSort(arr, 0, arr_size - 1);
end = clock();
timetaken = (double)(end - start) / CLOCKS_PER_SEC;
.
a) Write the recursive function in C++ to sort a set of data using M.pdf
a) Write the recursive function in C++ to sort a set of data using Merge Sort
b) Given a set of data as below:
5 10 15 29 34 42 79 87
Ans:)
merge sort:
merge sort is a one of the sorting technicis a sorting technique which divides the array into 2 sub
arrays which have size 2 and merge adjacent pair. so that after first process you have n/2 array of
size 2. this process is repeated until only one array remaining of size n.
a)
ans)
Source code: C++ program
// Program that sorts an array using merge sort
# include
# include
const int MAX = 4 ;
class array
{
private :
int *arr ;
int size ;
int count ;
public :
array( ) ;
array ( int sz ) ;
void add ( int num ) ;
void display( ) ;
static void sort ( int *a, int sz ) ;
void merge ( array &a, array &b ) ;
~array( ) ;
} ;
// initializes data member
array :: array( )
{
count = size = 0 ;
arr = NULL ;
}
// initialises data member
array :: array( int sz )
{
count = 0 ;
size = sz ;
arr = new int[sz] ;
}
// adds a new element to the array
void array :: add ( int num )
{
if ( count < size )
{
arr[count] = num ;
count++ ;
}
else
cout << \"\ Array is full\" << endl ;
}
// displays elements in an array
void array :: display( )
{
for ( int i = 0 ; i < count ; i++ )
cout << arr[i] << \"\\t\" ;
cout << endl ;
}
// merges two arrays
void array :: merge ( array &a, array &b )
{
sort ( a.arr, a.size ) ;
sort ( b.arr, b.size ) ;
size = a.count + b.count ;
arr = new int[size] ;
int i, j, k ;
for ( i = j = k = 0 ; j < a.count || k < b.count ; )
{
if ( a.arr[j] <= b.arr[k] )
arr[i++] = a.arr[j++] ;
else
arr[i++] = b.arr[k++] ;
count++ ;
if ( j == a.count || k == b.count )
break ;
}
for ( ; j < a.count ; )
{
arr[i++] = a.arr[j++] ;
count++ ;
}
for ( ; k < b.count ; )
{
arr[i++] = b.arr[k++] ;
count++ ;
}
}
// sorts an array
void array :: sort ( int *a, int sz )
{
int temp ;
for ( int i = 0 ; i <= sz - 2 ; i++ )
{
for ( int j = i + 1 ; j <= sz - 1 ; j++ )
{
if ( a[i] > a[j] )
{
temp = a[i] ;
a[i] = a[j] ;
a[j] = temp ;
}
}
}
}
// deallocates memory
array :: ~array( )
{
delete arr ;
}
void main( )
{
array a ( MAX ) ;
clrscr();
a.add ( 29 ) ;
a.add ( 5) ;
a.add ( 10) ;
a.add ( 15 ) ;
cout << \"\ Merge sort.\ \" ;
cout << \"\ First array: \" << endl ;
a.display( ) ;
array b ( MAX ) ;
b.add ( 34 ) ;
b.add ( 87 ) ;
b.add ( 79 ) ;
b.add ( 42) ;
cout << \"\ Second array: \" << endl ;
b.display( ) ;
array c ;
c.merge ( a, b ) ;
cout << \"\ Array after sorting: \" << endl ;
c.display( ) ;
getch();
}
i)insert
// initializes data member
array :: array( )
{
count = size = 0 ;
arr = NULL ;
}
// initialises data member
array :: array( int sz )
{
count = 0 ;
size = sz ;
arr = new int[sz] ;
}
// adds a new element to the array
void array :: add ( int num )
{
if ( count < size )
{
arr[count] = num ;
count++ ;
}
else
cout << \"\ Array is full\" << endl ;
}
the above code is used to inset of data in array.
ii. Selection
// displays elements in an array
void array :: display( )
{
for ( int i = 0 ; i < count ; i++ )
cout << arr[i] << \"\\t\.
c++ program I need to sort arrays using an insertion sort and a mer.pdf
c++ program: I need to sort arrays using an insertion sort and a merge sort (I already have). I
need to use these sorting methods to sort input arrays in the form of randomly generated numbers
in the size of 20, 100 and 200. So I need 3 randomily generated arrays and sorted and outputed
by both sorting method. I currently have it as given arrays and need help changing them to
randomily generated arrays
Here is my code so far:
#include
using namespace std;
void InsertionSort(int arr[],int size){
int temp,j;
for(int i=0; i=0){
arr[j+1] = arr[j];
j--;
}
arr[j+1] = temp;
}
}
//Merges two sub-arrays. First sub-array is arr[l..m],second is arr[m+1..r]
void merge(int arr[], int l, int m, int r){
int i, j, k;
int n1 = m - l + 1;
int n2 = r - m;
//Create temp arrays
int L[n1], R[n2];
//Copy data to temp arrays L[] and R[]
for (i = 0; i < n1; i++)
L[i] = arr[l + i];
for (j = 0; j < n2; j++)
R[j] = arr[m + 1+ j];
/* Merge arrays back into arr[l..r]*/
i = 0;
j = 0;
k = l;
while (i < n1 && j < n2){
if (L[i] <= R[j]){
arr[k] = L[i];
i++;
}
else{
arr[k] = R[j];
j++;
}
k++;
}
//Copy the remaining elements of L[], if there are any
while (i < n1){
arr[k] = L[i];
i++;
k++;
}
//Copy the remaining elements of R[], if there are any
while (j < n2){
arr[k] = R[j];
j++;
k++;
}
}
//l is left index and r is right index of the sub-array of array to be sorted
void MergeSort(int arr[], int l, int r){
if (l < r){
// Same as (l+r)/2, but avoids overflow for large l and h
int m = l+(r-l)/2;
// Sort first and second halves
MergeSort(arr, l, m);
MergeSort(arr, m+1, r);
merge(arr, l, m, r);
}
}
void printArray(int arr[], int size){//Function to print array
int i;
for (i=0; i < size; i++)
cout << arr[i] <<\" \";
cout << endl;
}
int main(){
int size = 20;
int array1[] = {17,33,88,54,96,82,12,36,69,74,79,66,32,11,1,98,76,55,3,4};
int array2[] = {20,1,19,2,18,3,17,4,16,5,15,6,14,7,13,8,12,9,11,10};
int array3[] = {220,209,198,187,176,165,154,143,132,121,110,99,88,77,66,55,44,33,22,11};
int array4[] = {15,35,85,100,40,90,70,65,25,5,10,30,55,75,80,95,20,45,50,60};
int array5[] = {100,99,98,97,96,95,94,93,92,91,90,89,88,87,86,85,84,83,82,81};
//Output for array1
cout << \"Original array 1: \ \";
printArray(array1, size);
InsertionSort(array1, size);
cout << \"Array 1 sorted by INSERTION SORT: \ \";
printArray(array1, size);
cout << \"\ \";
//Output for array2
cout << \"Original array 2: \ \";
printArray(array2, size);
MergeSort(array2,0,size);
cout << \"Array 2 sorted by MERGE SORT: \ \";
printArray(array2, size);
cout << \"\ \";
//Output for array3
cout << \"Original array 3: \ \";
printArray(array3, size);
InsertionSort(array3, size);
cout << \"Array 3 sorted by INSERTION SORT: \ \";
printArray(array3, size);
cout << \"\ \";
//Output for array4
cout << \"Original array 4: \ \";
printArray(array4, size);
MergeSort(array4,0,size);
cout << \"Array 4 sorted by MERGE SORT: \ \";
printArray(array4, size);
cout << \"\ \";
//Output for array5
cout << \"Original array 5: \ \";
printArray(arr.
Introduction to Functional Programming with Scala
Scala é uma linguagem funcional que roda na JVM. Ela possui todas as vantagens da programação funcional, com a vantagem de ser facilmente integrada com Java, além de possuir uma stack completa de desenvolvimento e deploy. Nessa palestra, daremos os primeiros passos para quem quer trabalhar com Scala. Falaremos de imutabilidade, Traits, funções e expressões lambda entre outros tópicos
#include stdafx.h using namespace std; #include stdlib.h.docx
#include stdafx.h using namespace std; #include stdlib.h
Write a program that obtains the execution time of selection sort, bu.pdf
Write a java program called Question39 that does the following: Gets input for temperature
Utilizing a branching statement: If temperature is 76-100, call method outputHot passing the
temperature input as an argument. If temperature is 0-39, call method outputCold passing the
temperature input as an argument. If temperature is 40 to 75, call method outputJustRight
passing the temperature input as an argument. If temperature is outside these ranges, output
“Temperature outside range” to the screen. Be precise, import modules, include comments,
prologue, etc. as needed.
Solution
Question39.java
import java.util.Scanner;
public class Question39 {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter temperature: \");
int temp = scan.nextInt();
if(temp >=76 && temp <=100){
outputHot(temp);
}
else if(temp >=0 && temp <=39){
outputCold(temp);
}
else if(temp >=40 && temp <=75){
outputJustRight(temp);
}
else{
System.out.println(\"Temperature outside range\");
}
}
public static void outputHot(int temp){
System.out.println(\"Temperature \"+temp+\" Hot \");
}
public static void outputCold(int temp){
System.out.println(\"Temperature \"+temp+\" Cold \");
}
public static void outputJustRight(int temp){
System.out.println(\"Temperature \"+temp+\" Just Right \");
}
}
Output:
Enter temperature:
45
Temperature 45 Just Right.
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Part 1)#include stdio.h #include stdlib.h #include pthrea.pdf
Part 1)#include stdio.h #include stdlib.h #include pthrea.pdf
Can you give an example of a binary heap programCan you give an .pdf
Can you give an example of a binary heap programCan you give an .pdf
Object oriented programming; operator overloading array
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check the modifed code now you will get all operations done.termin.pdf
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I have written the code but cannot complete the assignment please help.pdf
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a) Write the recursive function in C++ to sort a set of data using M.pdf
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#include stdafx.h using namespace std; #include stdlib.h.docx
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Arrays
- 1. // finds a single missing integer in an array unsigned Arrays::MissingInt(unsigned* _arr, unsigned _arrSize) { // equation for summing all numbers in a range ('- 1' since _arr starts at 1) unsigned grandTotal = ((_arrSize * (_arrSize + 1)) / 2) - 1; // summing of numbers in the array // since array is short by 1, must reduce by 2 to get actual back index value unsigned front = 0, back = _arrSize - 2, arrTotal = 0; // two at a time. ie front and back of array (faster) // do while instead of for loop because i think it looks better (cleaner) do{ arrTotal += (_arr[front++] + _arr[back--]); } while (front < back); // if odd numbered array, front and back will eventually be the same // need to add ONE of them to arrTotal (not both) // did this here to avoid running the check every loop if (front == back) arrTotal += _arr[front]; // subtracting current total from grand total will return the missing number return grandTotal - arrTotal; } // compares values in array to find a single duplicate (multiple versions) unsigned Arrays::DuplicatedInt(unsigned* _arr, unsigned _arrSize) { #if 1 // fast O(count), but extra memory (hash_map) hash_map<unsigned, unsigned> dupCheck; for (unsigned count = 0; count < _arrSize; count++) { if (!dupCheck.emplace(_arr[count], _arr[count]).second) return _arr[count]; } #endif #if 0 // double for loop = slow O(n^2), but breaks as soon as it finds a duplicate so O(n * count) // also no extra variable(s) for (unsigned countA = 0; countA < _arrSize; countA++) { for (unsigned countB = countA + 1; countB < _arrSize; countB++) { if (_arr[countA] == _arr[countB]) return _arr[countA]; } } #endif #if 0 // takes time to sort (esp w/ 1,000,000 entries), but less memory (no extra variable(s)) O(nlog(n) + count)? std::sort(_arr, _arr + _arrSize); for (unsigned count = 0; count < _arrSize; count++) { if (_arr[count] == _arr[count + 1]) return _arr[count]; } #endif return -1; }