Lesson 10.4B : Factoring out GCMF
Factor Completely – to express as the product
of prime factors
Ex. Factor completely : 24
6 4
2 3 2 2
2  2  2  3
Factor the following completely:
1) 5x2
2) 14x2
y3
GCF of 12 and 18 GCF = 6
GCMF : Greatest Common Monomial Factor – The
greatest monomial that is a factor (will divide EVENLY
into) of all the given monomials.
GCF of 12x4
y3
and 18xy5
GCF = 6xy3
To find the GCMF of two or more Monomials
•First find the GCF of the coefficients
•Find the largest power of each variable that is
COMMON to all the monomials
•The GCMF = product of GCF of coefficients and
common variable factors
Ex. Find GCMF of 12x2
and 18x
GCF of coefficients = 6
Common variable(s) : only have one x in common
GCMF = 6x
Find GCMF of 21x2
and 35x5
GCF of Coefficients = 7
Common variable factors : two x’s
GCMF = 7x2
Find GCMF of 24x2
y3
and 36x3
y
GCF of coefficients = 12
Common variable factors : two x’s and one y
GCMF = 12x2
y
NOW, we are going to use GCMF’s to Factor
Quadratic Expressions. Factoring Out the GCMF is
the inverse (un-doing) of the Distributive Property
To factor – undoing distributive property
1) Perform Distributive Property: 6(2 + 3)
12 + 18
Factor : 12 + 18
6 (2 + 3)
2) Use Distributive Property to simplify: 3(x + 7)
3x + 21
Factor: 3x + 21
3(x + 7)
3) Factor: 12x2
y – 14xy3
2xy(6x – 7y2
)
3x(x) + 3x(5)
3x2
+ 15x
Ex.Distribute 3x(x + 5) Means to multiply the 3x
through the (x + 5)
Ex. Factor 3x2
+ 15x Means to Divide the GCMF
out of the polynomial (divide
each term by GCMF)
GCMF = 3x Recall how to divide by monomial
x
x
x
3
15
3 2

x
x
x
x
x








3
5
3
3
3
Divide (3x2
+ 15x) by GCMF (3x)
Factored form is 3x(x + 5)
x
x
x
x
3
15
3
3 2

 5

x
To factor a polynomial by factoring out the GCMF:
1) Find the GCMF
2) Divide the polynomial (each term of the
polynomial) by the GCMF
3) Write the polynomial as the product of the
GCMF and the result from step #2
Example: Factor
1) 15x2
– 9
Step 1) GCMF = 3
Step 2) Divide 15x2
– 9 by the GCMF
3
5
3
9
3
15
3
9
15 2
2
2





x
x
x
Step 3) Write as a product of GCMF and result of step 2
3(5x2
– 3)
Factor
1) 28a3
-12a2
GCMF = 4a2
Factored Form
4a2
(7a – 3)
2) 15a – 25b + 20
GCMF = 5
Factored Form
5(3a-5b+4)
3) 16x5
– 14x3
+ 26x2
GCMF = 2x2
Factored Form
2x2
(8x3
– 7x + 13)
Homework : Worksheet

April 2fffffffffffidididjsjjd3_Lesson_10_4bad.ppt

  • 1.
    Lesson 10.4B :Factoring out GCMF Factor Completely – to express as the product of prime factors Ex. Factor completely : 24 6 4 2 3 2 2 2  2  2  3 Factor the following completely: 1) 5x2 2) 14x2 y3
  • 2.
    GCF of 12and 18 GCF = 6 GCMF : Greatest Common Monomial Factor – The greatest monomial that is a factor (will divide EVENLY into) of all the given monomials. GCF of 12x4 y3 and 18xy5 GCF = 6xy3
  • 3.
    To find theGCMF of two or more Monomials •First find the GCF of the coefficients •Find the largest power of each variable that is COMMON to all the monomials •The GCMF = product of GCF of coefficients and common variable factors
  • 4.
    Ex. Find GCMFof 12x2 and 18x GCF of coefficients = 6 Common variable(s) : only have one x in common GCMF = 6x Find GCMF of 21x2 and 35x5 GCF of Coefficients = 7 Common variable factors : two x’s GCMF = 7x2
  • 5.
    Find GCMF of24x2 y3 and 36x3 y GCF of coefficients = 12 Common variable factors : two x’s and one y GCMF = 12x2 y NOW, we are going to use GCMF’s to Factor Quadratic Expressions. Factoring Out the GCMF is the inverse (un-doing) of the Distributive Property
  • 6.
    To factor –undoing distributive property 1) Perform Distributive Property: 6(2 + 3) 12 + 18 Factor : 12 + 18 6 (2 + 3) 2) Use Distributive Property to simplify: 3(x + 7) 3x + 21 Factor: 3x + 21 3(x + 7) 3) Factor: 12x2 y – 14xy3 2xy(6x – 7y2 )
  • 7.
    3x(x) + 3x(5) 3x2 +15x Ex.Distribute 3x(x + 5) Means to multiply the 3x through the (x + 5) Ex. Factor 3x2 + 15x Means to Divide the GCMF out of the polynomial (divide each term by GCMF) GCMF = 3x Recall how to divide by monomial x x x 3 15 3 2  x x x x x         3 5 3 3 3 Divide (3x2 + 15x) by GCMF (3x) Factored form is 3x(x + 5) x x x x 3 15 3 3 2   5  x
  • 8.
    To factor apolynomial by factoring out the GCMF: 1) Find the GCMF 2) Divide the polynomial (each term of the polynomial) by the GCMF 3) Write the polynomial as the product of the GCMF and the result from step #2
  • 9.
    Example: Factor 1) 15x2 –9 Step 1) GCMF = 3 Step 2) Divide 15x2 – 9 by the GCMF 3 5 3 9 3 15 3 9 15 2 2 2      x x x Step 3) Write as a product of GCMF and result of step 2 3(5x2 – 3)
  • 10.
    Factor 1) 28a3 -12a2 GCMF =4a2 Factored Form 4a2 (7a – 3) 2) 15a – 25b + 20 GCMF = 5 Factored Form 5(3a-5b+4) 3) 16x5 – 14x3 + 26x2 GCMF = 2x2 Factored Form 2x2 (8x3 – 7x + 13)
  • 11.