Answer (b) systems security and control.The businesses are now a .pdf
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A chemical formula is an expression indicating the atoms and their number in a particular compound. Each element/atom is identified by its symbol and the number of atoms are given in the subscript. For example, one molecule of water contain 2 atoms of hydrogen and one atom of oxygen: H2O Hope this helps Solution A chemical formula is an expression indicating the atoms and their number in a particular compound. Each element/atom is identified by its symbol and the number of atoms are given in the subscript. For example, one molecule of water contain 2 atoms of hydrogen and one atom of oxygen: H2O Hope this helps.
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Running head NETWORK INFRASTRUTCTURE AND SECURITYNETWORK INFR.docx
Running head: NETWORK INFRASTRUTCTURE AND SECURITY
NETWORK INFRASTRUTCTURE AND SECURITY 11
Project Deliverable 4: Infrastructure and Security
CIS498
June 4, 2017
Introduction
Knight Inc will be growing in the next few years and it will require robust and reliable network infrastructure. The company will need to be sure that it data can be accessed and handled in an environment that is safe and technically sound. The solutions will need to be up to date and be updated regularly. Security is very important and it will be paid the utmost attention to ensure that no bad elements are allowed into the network to cause damage and endanger the company’s data and infrastructure.
Logical and Physical Topographical Layout
Star topology will be used for the physical network. This is where all devices in a network are connected to a central hub. All resources are drawn from this hub including bandwidth that allows access to cloud resources. Star topology simplifies the matter of network management as everything can be deployed from the central hub(Shinde, 2014).
Bus topology will be used for the logical network. It is a topology where a backbone is the anchor on which computers connect to and request data and other resources. The logical network exists on a different subnet and as such can have different topology than the physical network. Computers are identified by IP addresses. Bus topology is good as it provides the computers with capabilities to access data as they need it by simply requesting (Shinde, 2014).
Figure 1 - Physical Layout
Figure 2 - Logical Layout
Network Components
Incorrectly deployed and configured firewalls and intrusion detection systems can be vulnerabilities to their networks. Given that they are meant to monitor traffic coming to and from the network and determine the harmful ones, this will not be accomplished. This makes it easy for malware to access the system. Fixing this requires that the firewall and the intrusion detection system be regularly checked for any signs of vulnerabilities and be fixed accordingly. (Peltier, 2013).
New devices like smartphones and tablets can also cause problems for the network. These are usually used when the company has its operations hosted on a cloud. This then allows for access to data from a variety of devices, which is every device that can access the internet. For companies that allow its employees to use personal devices to access work data, they are especially vulnerable. Viruses could easily be uploaded to the cloud without even the device owner realizing. The fix is to ensure that all mobile devices used to access the cloud are company issued so that they can be assessed and equipped with the necessary security measures (Peltier, 2013).
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Prepare a 3 to 5 paragraph briefing statement which explains the 3 mos.docx
Prepare a 3 to 5 paragraph briefing statement which explains the 3 most important reasons why a company should invest in cybersecurity tools and technologies. Your audience is a group of managers (technical and non-technical) who are participating in a conference on reducing risks associated with insider threats. Provide in-text citations and references for 3 or more authoritative sources. Put the reference list at the end of your posting.
Solution
Reason One
The increasing use of Internet of Thing
In business organization the Internet of thing means the addition of devices which can access the organization data and increase in number of threats of security flaws.
Since these devices weren’t originally registered on network, they may not have enough cybersecurity protections.
so it become easy for cyber criminals to use a device to gain unauthorized access to the hidden data of the organization.
Reason 2
The Breaches are a financial burden
Whenever a breach is discovered, systems are often taken offline to plug the security holes as a result of which the organization may not be able to take more customer order and to fullfil the last order placed, hence it become necessary to include cybersecurity to reduce such financial burden on organization.
Reason 3
the real threats are insider threats
The fraud employee sometimes inflict tremendous harm to take revange with organization or to have a personal profit. The risk associated with this type of threat is that it is very difficult to find such internal loop holes.
Reason 4
Without cybersecurity the reputation of the organization is at risk.
If the organization does\'nt opt the cybersecurity strategy then customer always think that there data is at risk and they will diverge from the organization which really harms the reputation of the organization
.
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Running head NETWORK INFRASTRUTCTURE AND SECURITYNETWORK INFR.docx
Running head: NETWORK INFRASTRUTCTURE AND SECURITY
NETWORK INFRASTRUTCTURE AND SECURITY 11
Project Deliverable 4: Infrastructure and Security
CIS498
June 4, 2017
Introduction
Knight Inc will be growing in the next few years and it will require robust and reliable network infrastructure. The company will need to be sure that it data can be accessed and handled in an environment that is safe and technically sound. The solutions will need to be up to date and be updated regularly. Security is very important and it will be paid the utmost attention to ensure that no bad elements are allowed into the network to cause damage and endanger the company’s data and infrastructure.
Logical and Physical Topographical Layout
Star topology will be used for the physical network. This is where all devices in a network are connected to a central hub. All resources are drawn from this hub including bandwidth that allows access to cloud resources. Star topology simplifies the matter of network management as everything can be deployed from the central hub(Shinde, 2014).
Bus topology will be used for the logical network. It is a topology where a backbone is the anchor on which computers connect to and request data and other resources. The logical network exists on a different subnet and as such can have different topology than the physical network. Computers are identified by IP addresses. Bus topology is good as it provides the computers with capabilities to access data as they need it by simply requesting (Shinde, 2014).
Figure 1 - Physical Layout
Figure 2 - Logical Layout
Network Components
Incorrectly deployed and configured firewalls and intrusion detection systems can be vulnerabilities to their networks. Given that they are meant to monitor traffic coming to and from the network and determine the harmful ones, this will not be accomplished. This makes it easy for malware to access the system. Fixing this requires that the firewall and the intrusion detection system be regularly checked for any signs of vulnerabilities and be fixed accordingly. (Peltier, 2013).
New devices like smartphones and tablets can also cause problems for the network. These are usually used when the company has its operations hosted on a cloud. This then allows for access to data from a variety of devices, which is every device that can access the internet. For companies that allow its employees to use personal devices to access work data, they are especially vulnerable. Viruses could easily be uploaded to the cloud without even the device owner realizing. The fix is to ensure that all mobile devices used to access the cloud are company issued so that they can be assessed and equipped with the necessary security measures (Peltier, 2013).
Old credentials could be used to access the network discreetly without raising suspicions, these could be the credentials of employees that have lef ...
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Data Loss Prevention technologies are needed to protect data coming into and leaving the organization. There are a number of problems and challenges with the many vendors supplying DLP technology. This presenation reviews some of the Myths around Data Loss Prevention.
Prepare a 3 to 5 paragraph briefing statement which explains the 3 mos.docx
Prepare a 3 to 5 paragraph briefing statement which explains the 3 most important reasons why a company should invest in cybersecurity tools and technologies. Your audience is a group of managers (technical and non-technical) who are participating in a conference on reducing risks associated with insider threats. Provide in-text citations and references for 3 or more authoritative sources. Put the reference list at the end of your posting.
Solution
Reason One
The increasing use of Internet of Thing
In business organization the Internet of thing means the addition of devices which can access the organization data and increase in number of threats of security flaws.
Since these devices weren’t originally registered on network, they may not have enough cybersecurity protections.
so it become easy for cyber criminals to use a device to gain unauthorized access to the hidden data of the organization.
Reason 2
The Breaches are a financial burden
Whenever a breach is discovered, systems are often taken offline to plug the security holes as a result of which the organization may not be able to take more customer order and to fullfil the last order placed, hence it become necessary to include cybersecurity to reduce such financial burden on organization.
Reason 3
the real threats are insider threats
The fraud employee sometimes inflict tremendous harm to take revange with organization or to have a personal profit. The risk associated with this type of threat is that it is very difficult to find such internal loop holes.
Reason 4
Without cybersecurity the reputation of the organization is at risk.
If the organization does\'nt opt the cybersecurity strategy then customer always think that there data is at risk and they will diverge from the organization which really harms the reputation of the organization
.
10.1.1.436.3364.pdf
The user requirements of a new system for Railway reservation system may include:
1.Easy-to-use Interface: The new system should have a simple and intuitive user interface that allows users to quickly and easily access the web application and service providers to efficiently respond to requests.
2.Comprehensive Coverage: The new system should have an extensive coverage area that ensures drivers in all locations have access to timely and reliable assistance.
3.Integration with Modern Technologies: The new system should be fully integrated with modern communication channels and technologies, such as mobile devices and GPS, to allow for efficient and accurate communication between drivers and service providers.
4.Fast Response Times: The new system should ensure that service providers can quickly and efficiently respond to service requests, minimizing wait times for drivers in need of assistance.
5.Reliable Service: The new system should provide drivers with access to reliable and trustworthy service providers, ensuring that they receive high-quality service and repairs.
6.24/7 Availability: The new system should be available 24/7, ensuring that drivers can request assistance at any time of the day or night.
7.Transparent Pricing: The new system should provide transparent and fair pricing for all services, ensuring that drivers know what to expect and are not subject to unexpected or unreasonable charges.
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conflicting priorities, business environmental factors, information sensitivity, lack of controls on the Internet, ethical lapses,
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versus affecting productivity: 100 percent security equals 0 percent productivity, but 0 percent security doesn’t equal 100
percent productivity.
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Discussion 300 wordsSearch scholar.google.com or your textbook
Discussion 300 words
Search "scholar.google.com" or your textbook. Discuss how organizations have faced the challenges that incident handlers are challenged with in identifying incidents when resources have been moved to a cloud environment.
Reply to classmate 1: 275 words
Incident Handlers Challenges
The cloud computer helps the people to share their distributed resources which are related to different business organizations. Cloud computing helps business organizations in managing their business around the globe. The cloud computing application helps business organizations in expanding their business at a large level. It can be assessed on web devices from anywhere. Nowadays cloud computing helps the business organizations in meeting the demands of their customers more efficiently. The malicious cloud system has been noticed by the incident handlers which is a core concern for the business organization. Nowadays every business organization is using cloud computing in order to manage their important data and information of the business. The business organization is facing many incidents in their organization which can directly affect the working of their business. The main challenge that has been faced by the incident handlers is the accuracy in identification (John W. Rittinghouse, 2017).
The number of challenges that faced in the cloud environment are as follows:-
1. Challenge of denial of services: - The first main challenge that has been faced by the incident handler is the denial of services. There are various incidents of service attacks which can create a bogus request for preventing the system within the stipulated time. Such physical attack creates a challenge of service denial for the system.
2. Challenge of malicious code: - The second main challenge which can be faced by the incident handler is the challenge of malicious code. It can quickly affect the number of workstations in the business organization. It effects the working of the business organization.
3. Challenge of unauthorized access:- The third main challenge which is being faced by the incident handler is the unauthorized access of the system by the third party in the business organization. It can affect important data and information about the business. The attackers can access the system by the unauthorized way and steal the important data of the business organization.
4. Challenge of inappropriate use:- The fourth main challenge which may be faced by the incident handlers is the challenge of inappropriate use of the system. In the business organization, any employee can provide the illegal copies of the software to the other company employees. They can take advantage of the data and can misuse it.
5. Cloud service provider challenge:- The fifth main challenge that can be faced by the incident handler is the cloud service providers. This situation occurs when there is no control over the actions provided by cloud service provid ...
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Cyber security positions have considerably taken the top list in the job market. Candidates vying for elite positions in the field of cyber security certainly need a clear-cut and detailed guide to channeling their preparation for smooth career growth, beginning with getting a job. We have curated the top cyber security interview questions that will help candidates focus on the key areas. We have classified the regularly asked cyber security interview questions here, in this article into different levels starting from basic general questions to advanced technical ones.
Before we move on to the top cyber security interview questions, it is critical to reflect on the vitality of cyber security in our modern times and how cyber security professionals are catering to the needs of securing a safe cyber ecosystem.
The times we live in is defined by the digital transition, in which the internet, electronic devices, and computers have become an integral part of our daily life. Institutions that serve our daily needs, such as banks and hospitals, now rely on internet-connected equipment to give the best possible service. A portion of their data, such as financial and personal information, has become vulnerable to illegal access, posing serious risks. Intruders utilize this information to carry out immoral and criminal goals.
Cyber-attacks have jeopardized the computer system and its arrangements, which has now become a global concern. To safeguard data from security breaches, a comprehensive cyber security policy is needed now more than ever. The rising frequency of cyber-attacks has compelled corporations and organizations working with national security and sensitive data to implement stringent security procedures and restrictions.
Computers, mobile devices, servers, data, electronic systems, networks, and other systems connected to the internet must be protected from harmful attacks. Cybersecurity, which is a combination of the words "cyber" and "security," provides this protection. 'Cyber' imbibes the vast-ranging technology with systems, networks, programs, and data in the aforementioned procedure. The phrase "security" refers to the process of protecting data, networks, applications, and systems. In a nutshell,
cyber security is a combination of principles and approaches that assist prevent unwanted access to data, networks, programs, and devices by meeting the security needs of technological resources (computer-based) and online databases.
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2. Are we protecting ourselves against insider threats?
3. Do we have a cyber security task force in place?
4. Is our BYOD policy secure?
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In python,Tkinter is a Graphical user interface package.So,Tkinter tookit for GUI programming
supports protocol handler mechanism.
Protocol is taking care of how interaction takes place between application and windows manager.
self.parent.protocol(\"WM_DELETE_WINDOW\",self.quit_handler)
in the above line \"WM_DELETE_WINDOW\" is a protocol.What this protocl does is :it define
what is going to happen when a user who uses the application and closes window explicitely
using windows manager.
Then this protocol \"WM_DELETE_WINDOE\" bypasses to quit_handler().
That quit_handler() asks user \"whether he or she wants to quit or not\" then simply quit the
window.
Solution
In python,Tkinter is a Graphical user interface package.So,Tkinter tookit for GUI programming
supports protocol handler mechanism.
Protocol is taking care of how interaction takes place between application and windows manager.
self.parent.protocol(\"WM_DELETE_WINDOW\",self.quit_handler)
in the above line \"WM_DELETE_WINDOW\" is a protocol.What this protocl does is :it define
what is going to happen when a user who uses the application and closes window explicitely
using windows manager.
Then this protocol \"WM_DELETE_WINDOE\" bypasses to quit_handler().
That quit_handler() asks user \"whether he or she wants to quit or not\" then simply quit the
window..
MinOfFourNumbers.javaimport java.util.Scanner;public class MinOf.pdf
If I assume you meant supply is determined as [q_(s)=3p^2-4p] and demand is determined as
[q_(d)=-p^2+24] then I would calculate that the equilibrium is where [q_(s)=q_(d)] and p>0. So I
set up the equation [3p^2-4p=-p^2+24] I add [p^2] to both sides of the equation yielding [4p^2-
4p=24] I subtract 24 from each side, yielding the quadratic equation [4p^2-4p-24=0] I factor the
equation [(2p-6)(2p+4)=0] so that means [2p-6=0] or [2p+4=0] In the former case 2p=6 so p=3,
and in the latter 2p=-4 so p=-2. The economic nature of the question requires p>0, so [p!=-2] and
thus the equilibrium price is $3.00 each. Then to determine the equilibrium quantity, we solve
either q expression for p=3.
[q_(s)=3(3)^2-4(3)=3(9)-12=27-12=15]
[q_(d)=-(3^2)+24=-9+24=15]
So the equilibrium quantity is 15 items.
The price and quantity for market equilibrium is 15 items at $3.00 each.
Solution
If I assume you meant supply is determined as [q_(s)=3p^2-4p] and demand is determined as
[q_(d)=-p^2+24] then I would calculate that the equilibrium is where [q_(s)=q_(d)] and p>0. So I
set up the equation [3p^2-4p=-p^2+24] I add [p^2] to both sides of the equation yielding [4p^2-
4p=24] I subtract 24 from each side, yielding the quadratic equation [4p^2-4p-24=0] I factor the
equation [(2p-6)(2p+4)=0] so that means [2p-6=0] or [2p+4=0] In the former case 2p=6 so p=3,
and in the latter 2p=-4 so p=-2. The economic nature of the question requires p>0, so [p!=-2] and
thus the equilibrium price is $3.00 each. Then to determine the equilibrium quantity, we solve
either q expression for p=3.
[q_(s)=3(3)^2-4(3)=3(9)-12=27-12=15]
[q_(d)=-(3^2)+24=-9+24=15]
So the equilibrium quantity is 15 items.
The price and quantity for market equilibrium is 15 items at $3.00 each..
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10.1.1.436.3364.pdf
The user requirements of a new system for Railway reservation system may include:
1.Easy-to-use Interface: The new system should have a simple and intuitive user interface that allows users to quickly and easily access the web application and service providers to efficiently respond to requests.
2.Comprehensive Coverage: The new system should have an extensive coverage area that ensures drivers in all locations have access to timely and reliable assistance.
3.Integration with Modern Technologies: The new system should be fully integrated with modern communication channels and technologies, such as mobile devices and GPS, to allow for efficient and accurate communication between drivers and service providers.
4.Fast Response Times: The new system should ensure that service providers can quickly and efficiently respond to service requests, minimizing wait times for drivers in need of assistance.
5.Reliable Service: The new system should provide drivers with access to reliable and trustworthy service providers, ensuring that they receive high-quality service and repairs.
6.24/7 Availability: The new system should be available 24/7, ensuring that drivers can request assistance at any time of the day or night.
7.Transparent Pricing: The new system should provide transparent and fair pricing for all services, ensuring that drivers know what to expect and are not subject to unexpected or unreasonable charges.
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Discussion 300 wordsSearch scholar.google.com or your textbook
Discussion 300 words
Search "scholar.google.com" or your textbook. Discuss how organizations have faced the challenges that incident handlers are challenged with in identifying incidents when resources have been moved to a cloud environment.
Reply to classmate 1: 275 words
Incident Handlers Challenges
The cloud computer helps the people to share their distributed resources which are related to different business organizations. Cloud computing helps business organizations in managing their business around the globe. The cloud computing application helps business organizations in expanding their business at a large level. It can be assessed on web devices from anywhere. Nowadays cloud computing helps the business organizations in meeting the demands of their customers more efficiently. The malicious cloud system has been noticed by the incident handlers which is a core concern for the business organization. Nowadays every business organization is using cloud computing in order to manage their important data and information of the business. The business organization is facing many incidents in their organization which can directly affect the working of their business. The main challenge that has been faced by the incident handlers is the accuracy in identification (John W. Rittinghouse, 2017).
The number of challenges that faced in the cloud environment are as follows:-
1. Challenge of denial of services: - The first main challenge that has been faced by the incident handler is the denial of services. There are various incidents of service attacks which can create a bogus request for preventing the system within the stipulated time. Such physical attack creates a challenge of service denial for the system.
2. Challenge of malicious code: - The second main challenge which can be faced by the incident handler is the challenge of malicious code. It can quickly affect the number of workstations in the business organization. It effects the working of the business organization.
3. Challenge of unauthorized access:- The third main challenge which is being faced by the incident handler is the unauthorized access of the system by the third party in the business organization. It can affect important data and information about the business. The attackers can access the system by the unauthorized way and steal the important data of the business organization.
4. Challenge of inappropriate use:- The fourth main challenge which may be faced by the incident handlers is the challenge of inappropriate use of the system. In the business organization, any employee can provide the illegal copies of the software to the other company employees. They can take advantage of the data and can misuse it.
5. Cloud service provider challenge:- The fifth main challenge that can be faced by the incident handler is the cloud service providers. This situation occurs when there is no control over the actions provided by cloud service provid ...
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Cyber security positions have considerably taken the top list in the job market. Candidates vying for elite positions in the field of cyber security certainly need a clear-cut and detailed guide to channeling their preparation for smooth career growth, beginning with getting a job. We have curated the top cyber security interview questions that will help candidates focus on the key areas. We have classified the regularly asked cyber security interview questions here, in this article into different levels starting from basic general questions to advanced technical ones.
Before we move on to the top cyber security interview questions, it is critical to reflect on the vitality of cyber security in our modern times and how cyber security professionals are catering to the needs of securing a safe cyber ecosystem.
The times we live in is defined by the digital transition, in which the internet, electronic devices, and computers have become an integral part of our daily life. Institutions that serve our daily needs, such as banks and hospitals, now rely on internet-connected equipment to give the best possible service. A portion of their data, such as financial and personal information, has become vulnerable to illegal access, posing serious risks. Intruders utilize this information to carry out immoral and criminal goals.
Cyber-attacks have jeopardized the computer system and its arrangements, which has now become a global concern. To safeguard data from security breaches, a comprehensive cyber security policy is needed now more than ever. The rising frequency of cyber-attacks has compelled corporations and organizations working with national security and sensitive data to implement stringent security procedures and restrictions.
Computers, mobile devices, servers, data, electronic systems, networks, and other systems connected to the internet must be protected from harmful attacks. Cybersecurity, which is a combination of the words "cyber" and "security," provides this protection. 'Cyber' imbibes the vast-ranging technology with systems, networks, programs, and data in the aforementioned procedure. The phrase "security" refers to the process of protecting data, networks, applications, and systems. In a nutshell,
cyber security is a combination of principles and approaches that assist prevent unwanted access to data, networks, programs, and devices by meeting the security needs of technological resources (computer-based) and online databases.
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1. How often do you see non-sanctioned cloud services in use?
2. Are we protecting ourselves against insider threats?
3. Do we have a cyber security task force in place?
4. Is our BYOD policy secure?
5. Do you feel limited by your security budget or staff size?3 guiding priciples to improve data security
The information explosion, the proliferation of endpoint devices, growing user volumes, and new computing models like cloud, social business, and big data have created new security vulnerabilities. To secure sensitive data and address compliance requirements, organizations need to adopt a more proactive and systematic approach. Read this white paper to learn three simple guiding principles to help your organization achieve better security and compliance without impacting production systems or straining already-tight budgets.
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Ethical and security issues on MIS inte 322 assignment.docx
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5 Questions Executives Should Be Asking Their Security Teams
More from aptex1
Name- Gold leaved white PoplarGenus- Populusspecies- albaAutho.pdf
In python,Tkinter is a Graphical user interface package.So,Tkinter tookit for GUI programming
supports protocol handler mechanism.
Protocol is taking care of how interaction takes place between application and windows manager.
self.parent.protocol(\"WM_DELETE_WINDOW\",self.quit_handler)
in the above line \"WM_DELETE_WINDOW\" is a protocol.What this protocl does is :it define
what is going to happen when a user who uses the application and closes window explicitely
using windows manager.
Then this protocol \"WM_DELETE_WINDOE\" bypasses to quit_handler().
That quit_handler() asks user \"whether he or she wants to quit or not\" then simply quit the
window.
Solution
In python,Tkinter is a Graphical user interface package.So,Tkinter tookit for GUI programming
supports protocol handler mechanism.
Protocol is taking care of how interaction takes place between application and windows manager.
self.parent.protocol(\"WM_DELETE_WINDOW\",self.quit_handler)
in the above line \"WM_DELETE_WINDOW\" is a protocol.What this protocl does is :it define
what is going to happen when a user who uses the application and closes window explicitely
using windows manager.
Then this protocol \"WM_DELETE_WINDOE\" bypasses to quit_handler().
That quit_handler() asks user \"whether he or she wants to quit or not\" then simply quit the
window..
MinOfFourNumbers.javaimport java.util.Scanner;public class MinOf.pdf
If I assume you meant supply is determined as [q_(s)=3p^2-4p] and demand is determined as
[q_(d)=-p^2+24] then I would calculate that the equilibrium is where [q_(s)=q_(d)] and p>0. So I
set up the equation [3p^2-4p=-p^2+24] I add [p^2] to both sides of the equation yielding [4p^2-
4p=24] I subtract 24 from each side, yielding the quadratic equation [4p^2-4p-24=0] I factor the
equation [(2p-6)(2p+4)=0] so that means [2p-6=0] or [2p+4=0] In the former case 2p=6 so p=3,
and in the latter 2p=-4 so p=-2. The economic nature of the question requires p>0, so [p!=-2] and
thus the equilibrium price is $3.00 each. Then to determine the equilibrium quantity, we solve
either q expression for p=3.
[q_(s)=3(3)^2-4(3)=3(9)-12=27-12=15]
[q_(d)=-(3^2)+24=-9+24=15]
So the equilibrium quantity is 15 items.
The price and quantity for market equilibrium is 15 items at $3.00 each.
Solution
If I assume you meant supply is determined as [q_(s)=3p^2-4p] and demand is determined as
[q_(d)=-p^2+24] then I would calculate that the equilibrium is where [q_(s)=q_(d)] and p>0. So I
set up the equation [3p^2-4p=-p^2+24] I add [p^2] to both sides of the equation yielding [4p^2-
4p=24] I subtract 24 from each side, yielding the quadratic equation [4p^2-4p-24=0] I factor the
equation [(2p-6)(2p+4)=0] so that means [2p-6=0] or [2p+4=0] In the former case 2p=6 so p=3,
and in the latter 2p=-4 so p=-2. The economic nature of the question requires p>0, so [p!=-2] and
thus the equilibrium price is $3.00 each. Then to determine the equilibrium quantity, we solve
either q expression for p=3.
[q_(s)=3(3)^2-4(3)=3(9)-12=27-12=15]
[q_(d)=-(3^2)+24=-9+24=15]
So the equilibrium quantity is 15 items.
The price and quantity for market equilibrium is 15 items at $3.00 each..
molarity = 0.252101.1 =0.001236 M percent =0.251002 =12.5 .pdf
If this is not soluble in water, this must be nonpolar,
if it si soluble in hexane, this must be nonpolar as well
therefore, we are certain this is nonpolar substance
with low vap pressure...
From the list, nearest BP for that pressure is chloroform with 60ºC (vs 58.) which is ok, since no
range is given.
CCl4 is nonpolar
In order to ensure this, you could use a chromatography with previous data, i.e. use chloroform
standard and run chromatography vs. unkown. If they behave the same ( same Rf value, and
retention time ) then this is most likely chloroform
Solution
If this is not soluble in water, this must be nonpolar,
if it si soluble in hexane, this must be nonpolar as well
therefore, we are certain this is nonpolar substance
with low vap pressure...
From the list, nearest BP for that pressure is chloroform with 60ºC (vs 58.) which is ok, since no
range is given.
CCl4 is nonpolar
In order to ensure this, you could use a chromatography with previous data, i.e. use chloroform
standard and run chromatography vs. unkown. If they behave the same ( same Rf value, and
retention time ) then this is most likely chloroform.
Initial concentration of Br- = 2.25 x 10e-3M1V1=M2V2therefore M2.pdf
From the graph, we can see that there are three values at which f(x)= 0
These are- x= -6,-2,3
Hence the answer is Option D
Solution
From the graph, we can see that there are three values at which f(x)= 0
These are- x= -6,-2,3
Hence the answer is Option D.
import java.util.Scanner;public class HornersPolynomial { .pdf
For a first order reaction rate constant , k = ( 2.303 /t )x log ( a / (a-x))
Where
a = initial amount
a-x = amount left after time t = a / 10
t = time = ?
k = rate constant = 3.43x10 -2 d -2
Plug the values we get t = ( 2.303 /k )x log ( a / (a-x))
= ( 2.303 / 3.43x10 -2 )x log ( a / (a/10))
= 67.14 days
Solution
For a first order reaction rate constant , k = ( 2.303 /t )x log ( a / (a-x))
Where
a = initial amount
a-x = amount left after time t = a / 10
t = time = ?
k = rate constant = 3.43x10 -2 d -2
Plug the values we get t = ( 2.303 /k )x log ( a / (a-x))
= ( 2.303 / 3.43x10 -2 )x log ( a / (a/10))
= 67.14 days.
Direct memory access (DMA) is a function that allows an inputoutput.pdf
approximately all of the propoerty crimes are between 3 standard deviations from the mean
mean,u = 3377.2
standard deviation,s = 847.4
u - 3s = 835
u + 3s = 5919.4
OPTION B
p(Z
Solution
approximately all of the propoerty crimes are between 3 standard deviations from the mean
mean,u = 3377.2
standard deviation,s = 847.4
u - 3s = 835
u + 3s = 5919.4
OPTION B
p(Z.
Ethanol is miscible in water because of the hydroxyl functional grou.pdf
b) Security requirements
Security requirements are the outputs of the risk management activity. Inputs to the risk
management and information security strategy include business strategy, business processes, risk
assessments, business input analysis, information resources, and regulatory requirements.
Solution
b) Security requirements
Security requirements are the outputs of the risk management activity. Inputs to the risk
management and information security strategy include business strategy, business processes, risk
assessments, business input analysis, information resources, and regulatory requirements..
the diluted concentration of HCl = (0.120 M x 25..pdf
the diluted concentration of HCl = (0.120 M x 25.0 mL) / (25.0 + 40.0) mL =
0.0462 M [H+] = [HCl] = 0.0462 M pH = -log[H+] = -log0.0462 = 1.33
Solution
the diluted concentration of HCl = (0.120 M x 25.0 mL) / (25.0 + 40.0) mL =
0.0462 M [H+] = [HCl] = 0.0462 M pH = -log[H+] = -log0.0462 = 1.33.
Simple Nobody Knows The Answer .pdf
Simple Nobody Knows The Answer
Solution
Simple Nobody Knows The Answer.
AnswerThe net equation of the reaction catalyzed by the protein c.pdf
a) [21]+[19] = [40] = [4] {since 40 when divided ny 12 leaves a remainder of 4 }
b) [37][27] = [ 999] = [9] { Since now the remiander will be 9 when divided by 45}
c) [33]([83] - [67]) = [33] [16] = [528] = [28]
d) [18] + [8] = [26] = [0]. Hence additive inverse of [18] is [8].
Solution
a) [21]+[19] = [40] = [4] {since 40 when divided ny 12 leaves a remainder of 4 }
b) [37][27] = [ 999] = [9] { Since now the remiander will be 9 when divided by 45}
c) [33]([83] - [67]) = [33] [16] = [528] = [28]
d) [18] + [8] = [26] = [0]. Hence additive inverse of [18] is [8]..
Answer i command.The vi editor always starts in command mode. For.pdf
A Shareholder of a company is holding a share in the assets of the company. A shareholder is
also entitled to the profits which company makes by using those assets. As the basic fomat of
company distinguishes the Management function from the ownership, People managing the
company may or maynot be the owners i.e share holders of the company. Regulators often
require the companies to obtain approval of the shareholders via a resolution in the shareholders
meeting, thus the deciding power rests with the shareholders. However the extent of powers are
contained in the Legislature governing that corporation.
Shareholders have right in the assets of the corporation not in the day to day mangement of the
corporation.
Solution
A Shareholder of a company is holding a share in the assets of the company. A shareholder is
also entitled to the profits which company makes by using those assets. As the basic fomat of
company distinguishes the Management function from the ownership, People managing the
company may or maynot be the owners i.e share holders of the company. Regulators often
require the companies to obtain approval of the shareholders via a resolution in the shareholders
meeting, thus the deciding power rests with the shareholders. However the extent of powers are
contained in the Legislature governing that corporation.
Shareholders have right in the assets of the corporation not in the day to day mangement of the
corporation..
A. Temeperature of refrigeratorsIntervalB. Horspower of .pdf
2) b) Understory is rich in humidity hence supports fungi
3) a) canopy includes plant crowns
4) c) herbaceous
5) d) leaf litter/soil
Solution
2) b) Understory is rich in humidity hence supports fungi
3) a) canopy includes plant crowns
4) c) herbaceous
5) d) leaf litter/soil.
48. The answer is Botulism. Botulism ia an illness that brings about.pdf
1 gallon gasoline = 3.785 L = 3.785 x 803 grams
Now, total heat produced = weight(in gms) x heat of combustion = 3.785 x 803 x 48 kJ
=145889.04 kJ =145.9 MJ
IT IS VERY LARGE NUMBER !!!!
Solution
1 gallon gasoline = 3.785 L = 3.785 x 803 grams
Now, total heat produced = weight(in gms) x heat of combustion = 3.785 x 803 x 48 kJ
=145889.04 kJ =145.9 MJ
IT IS VERY LARGE NUMBER !!!!.
2) b) Understory is rich in humidity hence supports fungi3) a) can.pdf
(A) The answer is b. increases
Electricity in the form of electrons are transported through the solution by charged ions of the
electrolyte. As the electrolyte concentration increases, so does the number of charge carriers and
hence the amount of charge and electricity conducted increases.
(B) Acetic acid (CH3COOH) is a weak acid and partially ionizes in water:
CH3COOH + H2O => CH3COO- + H3O+
The charged acetate (CH3COO- ) and hydroxonium (H3O+) ions are responsible for electrical
conductivity.
In 6 M acetic acid, water is in excess and and the ionization proceeds as shown above to give an
electrolyte solution with charged ions that conduct electricity.
In glacial acetic acid, there is very little water present and ionization is negliglble. Almost all the
acetic acid remains in the non-conducting molecular form (CH3COOH) and there are no charged
ions present. Thus glacial acetic acid does not conduct electricity.
Solution
(A) The answer is b. increases
Electricity in the form of electrons are transported through the solution by charged ions of the
electrolyte. As the electrolyte concentration increases, so does the number of charge carriers and
hence the amount of charge and electricity conducted increases.
(B) Acetic acid (CH3COOH) is a weak acid and partially ionizes in water:
CH3COOH + H2O => CH3COO- + H3O+
The charged acetate (CH3COO- ) and hydroxonium (H3O+) ions are responsible for electrical
conductivity.
In 6 M acetic acid, water is in excess and and the ionization proceeds as shown above to give an
electrolyte solution with charged ions that conduct electricity.
In glacial acetic acid, there is very little water present and ionization is negliglble. Almost all the
acetic acid remains in the non-conducting molecular form (CH3COOH) and there are no charged
ions present. Thus glacial acetic acid does not conduct electricity..
1.Discuss in detail Emile Durkheim and his contributions to the fiel.pdf
#include
#include
#include
int check(char*);
int k=0;
char a[100];
void shift(int,int);
int main()
{
int i,j=0,l=0,m,p,z;
do
{
if(j)
cout<<\"Enter the string\";
fgets(a,100,stdin);
j=check(a);
} while(j);
for(i=0;i0 && m!=2;j--)
{
m=2;
if(a[j]==\'+\'||a[j]==\'-\'||a[j]==\'*\'||a[j]==\'/\')
l++;
}
if(m==2)
{
for(m=j-2,p=1,z=1;z!=2&&m>0;m--)
{
if(p==1)
if(a[m]==\'(\')
p=2;
if(p==2)
{
if(a[m]==\'(\'&&(a[m-1]==\'+\' ||a[m-1]==\'-\' ||a[m-1]==\'*\'||a[m-1]==\'/\'))
{
m--;
z=2;
}
}
}
j=m;
}
if(j<0)
j=0;
else
j=j+2;
shift(l,j);
a[j]=\'(\';
k--;
i++;
}
}
if(k)
cout<<\"Your putput is\"<<\"\ \";
cout<=0;i--)
{
if(a[i]==\')\')
k++;
if(a[i]==\'(\')
return 1;
}
Output:
Enter the string 1+2)*3-4)5-6)))
Your output is
((1+2)*((3-4)*(5-6))
Solution
#include
#include
#include
int check(char*);
int k=0;
char a[100];
void shift(int,int);
int main()
{
int i,j=0,l=0,m,p,z;
do
{
if(j)
cout<<\"Enter the string\";
fgets(a,100,stdin);
j=check(a);
} while(j);
for(i=0;i0 && m!=2;j--)
{
m=2;
if(a[j]==\'+\'||a[j]==\'-\'||a[j]==\'*\'||a[j]==\'/\')
l++;
}
if(m==2)
{
for(m=j-2,p=1,z=1;z!=2&&m>0;m--)
{
if(p==1)
if(a[m]==\'(\')
p=2;
if(p==2)
{
if(a[m]==\'(\'&&(a[m-1]==\'+\' ||a[m-1]==\'-\' ||a[m-1]==\'*\'||a[m-1]==\'/\'))
{
m--;
z=2;
}
}
}
j=m;
}
if(j<0)
j=0;
else
j=j+2;
shift(l,j);
a[j]=\'(\';
k--;
i++;
}
}
if(k)
cout<<\"Your putput is\"<<\"\ \";
cout<=0;i--)
{
if(a[i]==\')\')
k++;
if(a[i]==\'(\')
return 1;
}
Output:
Enter the string 1+2)*3-4)5-6)))
Your output is
((1+2)*((3-4)*(5-6)).
1) YELLOW FEVERGroup Group IV ((+) ssRNA)Order Unassigned.pdf
#include
#include
#define TRUE 1
/* Put your lab 4 functions prototypes here, as well as the prototype for lab 5 */
double mag(double ax, double ay, double az);
int close_to (double tolerance, double point, double value);
int clearAll (int *a, int *b, int *c, int *d, int *e, int *f);
int main(void) {
int t, b1, b2, b3, b4, b5, s;
double ax, ay, az;
double tolerance = 0.25, point = 1.0, value;
int a,b,c,d,e,f;
while (TRUE && b2 != 1 && ( mag ( ax, ay, az)-1<(tolerance*3))) {
scanf(\"%d, %lf, %lf, %lf, %d, %d, %d, %d, %d, %d\", &t, &ax, &ay, &az, &b1, &b2, &b3,
&b4, &b5, &s );
if(close_to(tolerance, point, ax)==1 && a != 1){
printf(\"RIGHT\ \ \");
clearAll ( &a, &b, &c, &d, &e, &f);
a = 1;
fflush(stdout);
}
if(close_to(tolerance, point, ay)==1 && b != 1){
printf(\"FRONT\ \ \");
fflush(stdout);
clearAll ( &a, &b, &c, &d, &e, &f);
b = 1;
}
if(close_to(tolerance, point, az)==1 && c != 1){
printf(\"TOP\ \ \");
fflush(stdout);
clearAll ( &a, &b, &c, &d, &e, &f);
c = 1;
}
if(close_to(tolerance, point, ax)==2 && d != 1){
printf(\"LEFT\ \ \");
fflush(stdout);
clearAll ( &a, &b, &c, &d, &e, &f);
d = 1;
}
if(close_to(tolerance, point, ay)==2 && e != 1){
printf(\"BACK\ \ \");
fflush(stdout);
clearAll ( &a, &b, &c, &d, &e, &f);
e = 1;
}
if(close_to(tolerance, point, az)==2 && f != 1){
printf(\"BOTTOM\ \ \");
fflush(stdout);
clearAll ( &a, &b, &c, &d, &e, &f);
f = 1;
}
return 0;
}
}
/* Put your lab 4 functions here, as well as your new function close_to */
double mag(double ax, double ay, double az){
double y = sqrt(ax*ax + ay*ay + az*az);
return y;
}
int close_to (double tolerance, double point, double value){
if (value>0){
if (sqrt((value-point)*(value-point))<(tolerance)){
return 1;
}
else{
return 0;
}
}
else{
if(sqrt((value+point)*(value+point))<(tolerance)) //? it used to not have sqrt
return 2;
}
}
int clearAll (int *a, int *b, int *c, int *d, int *e, int *f){
*a = *b = *c = *d = *e = *f = 0;
}
Solution
#include
#include
#define TRUE 1
/* Put your lab 4 functions prototypes here, as well as the prototype for lab 5 */
double mag(double ax, double ay, double az);
int close_to (double tolerance, double point, double value);
int clearAll (int *a, int *b, int *c, int *d, int *e, int *f);
int main(void) {
int t, b1, b2, b3, b4, b5, s;
double ax, ay, az;
double tolerance = 0.25, point = 1.0, value;
int a,b,c,d,e,f;
while (TRUE && b2 != 1 && ( mag ( ax, ay, az)-1<(tolerance*3))) {
scanf(\"%d, %lf, %lf, %lf, %d, %d, %d, %d, %d, %d\", &t, &ax, &ay, &az, &b1, &b2, &b3,
&b4, &b5, &s );
if(close_to(tolerance, point, ax)==1 && a != 1){
printf(\"RIGHT\ \ \");
clearAll ( &a, &b, &c, &d, &e, &f);
a = 1;
fflush(stdout);
}
if(close_to(tolerance, point, ay)==1 && b != 1){
printf(\"FRONT\ \ \");
fflush(stdout);
clearAll ( &a, &b, &c, &d, &e, &f);
b = 1;
}
if(close_to(tolerance, point, az)==1 && c != 1){
printf(\"TOP\ \ \");
fflush(stdout);
clearAll ( &a, &b, &c, &d, &e, &f);
c = 1;
}
if(close_to(tolerance, point, ax)==2 && d != 1){
printf(\"LEFT\ \ \");
fflush(stdout);
cl.
Thermodynamic entropy is a non-conserved state fu.pdf
Thermodynamic entropy is a non-conserved state function that is of great
importance in the sciences of physics and chemistry. Historically, the concept of entropy evolved
in order to explain why some processes (permitted by conservation laws) occur spontaneously
while their time reversals (also permitted by conservation laws) do not; systems tend to progress
in the direction of increasing entropy. For isolated systems, entropy never decreases. This fact
has several important consequences in science: first, it prohibits \"perpetual motion\" machines;
and second, it implies the arrow of entropy has the same directionality as the arrow of time.
Increases in entropy correspond to irreversible changes in a system, because some energy is
expended as waste heat, limiting the amount of work a system can do. In statistical mechanics,
entropy is a measure of the number of ways in which a system may be arranged, often taken to
be a measure of \"disorder\" (the higher the entropy, the higher the disorder). This definition
describes the entropy as being proportional to the natural logarithm of the number of possible
microscopic configurations of the individual atoms and molecules of the system (microstates)
which could give rise to the observed macroscopic state (macrostate) of the system. The constant
of proportionality is the Boltzmann constant. - Wiki
Solution
Thermodynamic entropy is a non-conserved state function that is of great
importance in the sciences of physics and chemistry. Historically, the concept of entropy evolved
in order to explain why some processes (permitted by conservation laws) occur spontaneously
while their time reversals (also permitted by conservation laws) do not; systems tend to progress
in the direction of increasing entropy. For isolated systems, entropy never decreases. This fact
has several important consequences in science: first, it prohibits \"perpetual motion\" machines;
and second, it implies the arrow of entropy has the same directionality as the arrow of time.
Increases in entropy correspond to irreversible changes in a system, because some energy is
expended as waste heat, limiting the amount of work a system can do. In statistical mechanics,
entropy is a measure of the number of ways in which a system may be arranged, often taken to
be a measure of \"disorder\" (the higher the entropy, the higher the disorder). This definition
describes the entropy as being proportional to the natural logarithm of the number of possible
microscopic configurations of the individual atoms and molecules of the system (microstates)
which could give rise to the observed macroscopic state (macrostate) of the system. The constant
of proportionality is the Boltzmann constant. - Wiki.
I is oxidized by 6 electrons as the oxidation sta.pdf
I is oxidized by 6 electrons as the oxidation state of I in I- is -1 while in IO3- is +5.
Solution
I is oxidized by 6 electrons as the oxidation state of I in I- is -1 while in IO3- is +5..
The main difference is that Democritus was not a .pdf
The main difference is that Democritus was not a scientist he was a philosopher as
such he only theorized that matter could not be indefinitely divided, that there is a limit (now
know to be the atom). Dalton on the other had based his theory of atoms on scientific
experimentation and observation. Demeocritus used reason vs. Dalton used scientific method
Solution
The main difference is that Democritus was not a scientist he was a philosopher as
such he only theorized that matter could not be indefinitely divided, that there is a limit (now
know to be the atom). Dalton on the other had based his theory of atoms on scientific
experimentation and observation. Demeocritus used reason vs. Dalton used scientific method.
for acidic nature is should give H+ equation H.pdf
for acidic nature is should give H+ equation : HSO3- -----> H+ + SO3^2-
ANSWER
Solution
for acidic nature is should give H+ equation : HSO3- -----> H+ + SO3^2-
ANSWER.
More from aptex1 (20)
Name- Gold leaved white PoplarGenus- Populusspecies- albaAutho.pdf
Name- Gold leaved white PoplarGenus- Populusspecies- albaAutho.pdf
MinOfFourNumbers.javaimport java.util.Scanner;public class MinOf.pdf
MinOfFourNumbers.javaimport java.util.Scanner;public class MinOf.pdf
molarity = 0.252101.1 =0.001236 M percent =0.251002 =12.5 .pdf
molarity = 0.252101.1 =0.001236 M percent =0.251002 =12.5 .pdf
Initial concentration of Br- = 2.25 x 10e-3M1V1=M2V2therefore M2.pdf
Initial concentration of Br- = 2.25 x 10e-3M1V1=M2V2therefore M2.pdf
import java.util.Scanner;public class HornersPolynomial { .pdf
import java.util.Scanner;public class HornersPolynomial { .pdf
Direct memory access (DMA) is a function that allows an inputoutput.pdf
Direct memory access (DMA) is a function that allows an inputoutput.pdf
Ethanol is miscible in water because of the hydroxyl functional grou.pdf
Ethanol is miscible in water because of the hydroxyl functional grou.pdf
the diluted concentration of HCl = (0.120 M x 25..pdf
the diluted concentration of HCl = (0.120 M x 25..pdf
AnswerThe net equation of the reaction catalyzed by the protein c.pdf
AnswerThe net equation of the reaction catalyzed by the protein c.pdf
Answer i command.The vi editor always starts in command mode. For.pdf
Answer i command.The vi editor always starts in command mode. For.pdf
A. Temeperature of refrigeratorsIntervalB. Horspower of .pdf
A. Temeperature of refrigeratorsIntervalB. Horspower of .pdf
48. The answer is Botulism. Botulism ia an illness that brings about.pdf
48. The answer is Botulism. Botulism ia an illness that brings about.pdf
2) b) Understory is rich in humidity hence supports fungi3) a) can.pdf
2) b) Understory is rich in humidity hence supports fungi3) a) can.pdf
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- 1. Answer: (b) systems security and control. The businesses are now a days technology driven, IT plays a greater role in the organizations structure. The most of the problems faced by businesses are as a result for pure IT misfunction or mismanagement. the more powerful the IT of the organization the greater is its capability to succeed. The most common difficulties faced by IT teams is the threat of poor secirty and control of the sensitive data of the company. Although high secured and system control measures are taken there is a lot of mismanagement that leads to the theft and hacking of the sensitive information of the companies. one such problem is the misuse of access given to the employees for data handling. Due to negligence people reveal their passwords to others which leads to most of data theft from the systems due to unauthorised access. Also in cloud computing environments data is stored through online that involves a third party service provider which has higher risk for misuse of data. Getting a trusted party for cloud computing services and the contractal terms are the headache for the management. Solution Answer: (b) systems security and control. The businesses are now a days technology driven, IT plays a greater role in the organizations structure. The most of the problems faced by businesses are as a result for pure IT misfunction or mismanagement. the more powerful the IT of the organization the greater is its capability to succeed. The most common difficulties faced by IT teams is the threat of poor secirty and control of the sensitive data of the company. Although high secured and system control measures are taken there is a lot of mismanagement that leads to the theft and hacking of the sensitive information of the companies. one such problem is the misuse of access given to the employees for data handling. Due to negligence people reveal their passwords to others which leads to most of data theft from the systems due to unauthorised access. Also in cloud computing environments data is stored through online that involves a third party service provider which has higher risk for misuse of data. Getting a trusted party for cloud computing services and the contractal terms are the headache for the management.