Submit Search
Upload
Simple Nobody Knows The Answer .pdf
โข
0 likes
โข
2 views
A
aptex1
Follow
Simple Nobody Knows The Answer Solution Simple Nobody Knows The Answer.
Read less
Read more
Education
Report
Share
Report
Share
1 of 1
Download now
Download to read offline
Recommended
In python,Tkinter is a Graphical user interface package.So,Tkinter tookit for GUI programming supports protocol handler mechanism. Protocol is taking care of how interaction takes place between application and windows manager. self.parent.protocol(\"WM_DELETE_WINDOW\",self.quit_handler) in the above line \"WM_DELETE_WINDOW\" is a protocol.What this protocl does is :it define what is going to happen when a user who uses the application and closes window explicitely using windows manager. Then this protocol \"WM_DELETE_WINDOE\" bypasses to quit_handler(). That quit_handler() asks user \"whether he or she wants to quit or not\" then simply quit the window. Solution In python,Tkinter is a Graphical user interface package.So,Tkinter tookit for GUI programming supports protocol handler mechanism. Protocol is taking care of how interaction takes place between application and windows manager. self.parent.protocol(\"WM_DELETE_WINDOW\",self.quit_handler) in the above line \"WM_DELETE_WINDOW\" is a protocol.What this protocl does is :it define what is going to happen when a user who uses the application and closes window explicitely using windows manager. Then this protocol \"WM_DELETE_WINDOE\" bypasses to quit_handler(). That quit_handler() asks user \"whether he or she wants to quit or not\" then simply quit the window..
Name- Gold leaved white PoplarGenus- Populusspecies- albaAutho.pdf
Name- Gold leaved white PoplarGenus- Populusspecies- albaAutho.pdf
aptex1
ย
If I assume you meant supply is determined as [q_(s)=3p^2-4p] and demand is determined as [q_(d)=-p^2+24] then I would calculate that the equilibrium is where [q_(s)=q_(d)] and p>0. So I set up the equation [3p^2-4p=-p^2+24] I add [p^2] to both sides of the equation yielding [4p^2- 4p=24] I subtract 24 from each side, yielding the quadratic equation [4p^2-4p-24=0] I factor the equation [(2p-6)(2p+4)=0] so that means [2p-6=0] or [2p+4=0] In the former case 2p=6 so p=3, and in the latter 2p=-4 so p=-2. The economic nature of the question requires p>0, so [p!=-2] and thus the equilibrium price is $3.00 each. Then to determine the equilibrium quantity, we solve either q expression for p=3. [q_(s)=3(3)^2-4(3)=3(9)-12=27-12=15] [q_(d)=-(3^2)+24=-9+24=15] So the equilibrium quantity is 15 items. The price and quantity for market equilibrium is 15 items at $3.00 each. Solution If I assume you meant supply is determined as [q_(s)=3p^2-4p] and demand is determined as [q_(d)=-p^2+24] then I would calculate that the equilibrium is where [q_(s)=q_(d)] and p>0. So I set up the equation [3p^2-4p=-p^2+24] I add [p^2] to both sides of the equation yielding [4p^2- 4p=24] I subtract 24 from each side, yielding the quadratic equation [4p^2-4p-24=0] I factor the equation [(2p-6)(2p+4)=0] so that means [2p-6=0] or [2p+4=0] In the former case 2p=6 so p=3, and in the latter 2p=-4 so p=-2. The economic nature of the question requires p>0, so [p!=-2] and thus the equilibrium price is $3.00 each. Then to determine the equilibrium quantity, we solve either q expression for p=3. [q_(s)=3(3)^2-4(3)=3(9)-12=27-12=15] [q_(d)=-(3^2)+24=-9+24=15] So the equilibrium quantity is 15 items. The price and quantity for market equilibrium is 15 items at $3.00 each..
MinOfFourNumbers.javaimport java.util.Scanner;public class MinOf.pdf
MinOfFourNumbers.javaimport java.util.Scanner;public class MinOf.pdf
aptex1
ย
If this is not soluble in water, this must be nonpolar, if it si soluble in hexane, this must be nonpolar as well therefore, we are certain this is nonpolar substance with low vap pressure... From the list, nearest BP for that pressure is chloroform with 60ยบC (vs 58.) which is ok, since no range is given. CCl4 is nonpolar In order to ensure this, you could use a chromatography with previous data, i.e. use chloroform standard and run chromatography vs. unkown. If they behave the same ( same Rf value, and retention time ) then this is most likely chloroform Solution If this is not soluble in water, this must be nonpolar, if it si soluble in hexane, this must be nonpolar as well therefore, we are certain this is nonpolar substance with low vap pressure... From the list, nearest BP for that pressure is chloroform with 60ยบC (vs 58.) which is ok, since no range is given. CCl4 is nonpolar In order to ensure this, you could use a chromatography with previous data, i.e. use chloroform standard and run chromatography vs. unkown. If they behave the same ( same Rf value, and retention time ) then this is most likely chloroform.
molarity = 0.252101.1 =0.001236 M percent =0.251002 =12.5 .pdf
molarity = 0.252101.1 =0.001236 M percent =0.251002 =12.5 .pdf
aptex1
ย
From the graph, we can see that there are three values at which f(x)= 0 These are- x= -6,-2,3 Hence the answer is Option D Solution From the graph, we can see that there are three values at which f(x)= 0 These are- x= -6,-2,3 Hence the answer is Option D.
Initial concentration of Br- = 2.25 x 10e-3M1V1=M2V2therefore M2.pdf
Initial concentration of Br- = 2.25 x 10e-3M1V1=M2V2therefore M2.pdf
aptex1
ย
For a first order reaction rate constant , k = ( 2.303 /t )x log ( a / (a-x)) Where a = initial amount a-x = amount left after time t = a / 10 t = time = ? k = rate constant = 3.43x10 -2 d -2 Plug the values we get t = ( 2.303 /k )x log ( a / (a-x)) = ( 2.303 / 3.43x10 -2 )x log ( a / (a/10)) = 67.14 days Solution For a first order reaction rate constant , k = ( 2.303 /t )x log ( a / (a-x)) Where a = initial amount a-x = amount left after time t = a / 10 t = time = ? k = rate constant = 3.43x10 -2 d -2 Plug the values we get t = ( 2.303 /k )x log ( a / (a-x)) = ( 2.303 / 3.43x10 -2 )x log ( a / (a/10)) = 67.14 days.
import java.util.Scanner;public class HornersPolynomial {ย ย .pdf
import java.util.Scanner;public class HornersPolynomial {ย ย .pdf
aptex1
ย
approximately all of the propoerty crimes are between 3 standard deviations from the mean mean,u = 3377.2 standard deviation,s = 847.4 u - 3s = 835 u + 3s = 5919.4 OPTION B p(Z Solution approximately all of the propoerty crimes are between 3 standard deviations from the mean mean,u = 3377.2 standard deviation,s = 847.4 u - 3s = 835 u + 3s = 5919.4 OPTION B p(Z.
Direct memory access (DMA) is a function that allows an inputoutput.pdf
Direct memory access (DMA) is a function that allows an inputoutput.pdf
aptex1
ย
b) Security requirements Security requirements are the outputs of the risk management activity. Inputs to the risk management and information security strategy include business strategy, business processes, risk assessments, business input analysis, information resources, and regulatory requirements. Solution b) Security requirements Security requirements are the outputs of the risk management activity. Inputs to the risk management and information security strategy include business strategy, business processes, risk assessments, business input analysis, information resources, and regulatory requirements..
Ethanol is miscible in water because of the hydroxyl functional grou.pdf
Ethanol is miscible in water because of the hydroxyl functional grou.pdf
aptex1
ย
the diluted concentration of HCl = (0.120 M x 25.0 mL) / (25.0 + 40.0) mL = 0.0462 M [H+] = [HCl] = 0.0462 M pH = -log[H+] = -log0.0462 = 1.33 Solution the diluted concentration of HCl = (0.120 M x 25.0 mL) / (25.0 + 40.0) mL = 0.0462 M [H+] = [HCl] = 0.0462 M pH = -log[H+] = -log0.0462 = 1.33.
the diluted concentration of HCl = (0.120 M x 25..pdf
the diluted concentration of HCl = (0.120 M x 25..pdf
aptex1
ย
Recommended
In python,Tkinter is a Graphical user interface package.So,Tkinter tookit for GUI programming supports protocol handler mechanism. Protocol is taking care of how interaction takes place between application and windows manager. self.parent.protocol(\"WM_DELETE_WINDOW\",self.quit_handler) in the above line \"WM_DELETE_WINDOW\" is a protocol.What this protocl does is :it define what is going to happen when a user who uses the application and closes window explicitely using windows manager. Then this protocol \"WM_DELETE_WINDOE\" bypasses to quit_handler(). That quit_handler() asks user \"whether he or she wants to quit or not\" then simply quit the window. Solution In python,Tkinter is a Graphical user interface package.So,Tkinter tookit for GUI programming supports protocol handler mechanism. Protocol is taking care of how interaction takes place between application and windows manager. self.parent.protocol(\"WM_DELETE_WINDOW\",self.quit_handler) in the above line \"WM_DELETE_WINDOW\" is a protocol.What this protocl does is :it define what is going to happen when a user who uses the application and closes window explicitely using windows manager. Then this protocol \"WM_DELETE_WINDOE\" bypasses to quit_handler(). That quit_handler() asks user \"whether he or she wants to quit or not\" then simply quit the window..
Name- Gold leaved white PoplarGenus- Populusspecies- albaAutho.pdf
Name- Gold leaved white PoplarGenus- Populusspecies- albaAutho.pdf
aptex1
ย
If I assume you meant supply is determined as [q_(s)=3p^2-4p] and demand is determined as [q_(d)=-p^2+24] then I would calculate that the equilibrium is where [q_(s)=q_(d)] and p>0. So I set up the equation [3p^2-4p=-p^2+24] I add [p^2] to both sides of the equation yielding [4p^2- 4p=24] I subtract 24 from each side, yielding the quadratic equation [4p^2-4p-24=0] I factor the equation [(2p-6)(2p+4)=0] so that means [2p-6=0] or [2p+4=0] In the former case 2p=6 so p=3, and in the latter 2p=-4 so p=-2. The economic nature of the question requires p>0, so [p!=-2] and thus the equilibrium price is $3.00 each. Then to determine the equilibrium quantity, we solve either q expression for p=3. [q_(s)=3(3)^2-4(3)=3(9)-12=27-12=15] [q_(d)=-(3^2)+24=-9+24=15] So the equilibrium quantity is 15 items. The price and quantity for market equilibrium is 15 items at $3.00 each. Solution If I assume you meant supply is determined as [q_(s)=3p^2-4p] and demand is determined as [q_(d)=-p^2+24] then I would calculate that the equilibrium is where [q_(s)=q_(d)] and p>0. So I set up the equation [3p^2-4p=-p^2+24] I add [p^2] to both sides of the equation yielding [4p^2- 4p=24] I subtract 24 from each side, yielding the quadratic equation [4p^2-4p-24=0] I factor the equation [(2p-6)(2p+4)=0] so that means [2p-6=0] or [2p+4=0] In the former case 2p=6 so p=3, and in the latter 2p=-4 so p=-2. The economic nature of the question requires p>0, so [p!=-2] and thus the equilibrium price is $3.00 each. Then to determine the equilibrium quantity, we solve either q expression for p=3. [q_(s)=3(3)^2-4(3)=3(9)-12=27-12=15] [q_(d)=-(3^2)+24=-9+24=15] So the equilibrium quantity is 15 items. The price and quantity for market equilibrium is 15 items at $3.00 each..
MinOfFourNumbers.javaimport java.util.Scanner;public class MinOf.pdf
MinOfFourNumbers.javaimport java.util.Scanner;public class MinOf.pdf
aptex1
ย
If this is not soluble in water, this must be nonpolar, if it si soluble in hexane, this must be nonpolar as well therefore, we are certain this is nonpolar substance with low vap pressure... From the list, nearest BP for that pressure is chloroform with 60ยบC (vs 58.) which is ok, since no range is given. CCl4 is nonpolar In order to ensure this, you could use a chromatography with previous data, i.e. use chloroform standard and run chromatography vs. unkown. If they behave the same ( same Rf value, and retention time ) then this is most likely chloroform Solution If this is not soluble in water, this must be nonpolar, if it si soluble in hexane, this must be nonpolar as well therefore, we are certain this is nonpolar substance with low vap pressure... From the list, nearest BP for that pressure is chloroform with 60ยบC (vs 58.) which is ok, since no range is given. CCl4 is nonpolar In order to ensure this, you could use a chromatography with previous data, i.e. use chloroform standard and run chromatography vs. unkown. If they behave the same ( same Rf value, and retention time ) then this is most likely chloroform.
molarity = 0.252101.1 =0.001236 M percent =0.251002 =12.5 .pdf
molarity = 0.252101.1 =0.001236 M percent =0.251002 =12.5 .pdf
aptex1
ย
From the graph, we can see that there are three values at which f(x)= 0 These are- x= -6,-2,3 Hence the answer is Option D Solution From the graph, we can see that there are three values at which f(x)= 0 These are- x= -6,-2,3 Hence the answer is Option D.
Initial concentration of Br- = 2.25 x 10e-3M1V1=M2V2therefore M2.pdf
Initial concentration of Br- = 2.25 x 10e-3M1V1=M2V2therefore M2.pdf
aptex1
ย
For a first order reaction rate constant , k = ( 2.303 /t )x log ( a / (a-x)) Where a = initial amount a-x = amount left after time t = a / 10 t = time = ? k = rate constant = 3.43x10 -2 d -2 Plug the values we get t = ( 2.303 /k )x log ( a / (a-x)) = ( 2.303 / 3.43x10 -2 )x log ( a / (a/10)) = 67.14 days Solution For a first order reaction rate constant , k = ( 2.303 /t )x log ( a / (a-x)) Where a = initial amount a-x = amount left after time t = a / 10 t = time = ? k = rate constant = 3.43x10 -2 d -2 Plug the values we get t = ( 2.303 /k )x log ( a / (a-x)) = ( 2.303 / 3.43x10 -2 )x log ( a / (a/10)) = 67.14 days.
import java.util.Scanner;public class HornersPolynomial {ย ย .pdf
import java.util.Scanner;public class HornersPolynomial {ย ย .pdf
aptex1
ย
approximately all of the propoerty crimes are between 3 standard deviations from the mean mean,u = 3377.2 standard deviation,s = 847.4 u - 3s = 835 u + 3s = 5919.4 OPTION B p(Z Solution approximately all of the propoerty crimes are between 3 standard deviations from the mean mean,u = 3377.2 standard deviation,s = 847.4 u - 3s = 835 u + 3s = 5919.4 OPTION B p(Z.
Direct memory access (DMA) is a function that allows an inputoutput.pdf
Direct memory access (DMA) is a function that allows an inputoutput.pdf
aptex1
ย
b) Security requirements Security requirements are the outputs of the risk management activity. Inputs to the risk management and information security strategy include business strategy, business processes, risk assessments, business input analysis, information resources, and regulatory requirements. Solution b) Security requirements Security requirements are the outputs of the risk management activity. Inputs to the risk management and information security strategy include business strategy, business processes, risk assessments, business input analysis, information resources, and regulatory requirements..
Ethanol is miscible in water because of the hydroxyl functional grou.pdf
Ethanol is miscible in water because of the hydroxyl functional grou.pdf
aptex1
ย
the diluted concentration of HCl = (0.120 M x 25.0 mL) / (25.0 + 40.0) mL = 0.0462 M [H+] = [HCl] = 0.0462 M pH = -log[H+] = -log0.0462 = 1.33 Solution the diluted concentration of HCl = (0.120 M x 25.0 mL) / (25.0 + 40.0) mL = 0.0462 M [H+] = [HCl] = 0.0462 M pH = -log[H+] = -log0.0462 = 1.33.
the diluted concentration of HCl = (0.120 M x 25..pdf
the diluted concentration of HCl = (0.120 M x 25..pdf
aptex1
ย
a) [21]+[19] = [40] = [4] {since 40 when divided ny 12 leaves a remainder of 4 } b) [37][27] = [ 999] = [9] { Since now the remiander will be 9 when divided by 45} c) [33]([83] - [67]) = [33] [16] = [528] = [28] d) [18] + [8] = [26] = [0]. Hence additive inverse of [18] is [8]. Solution a) [21]+[19] = [40] = [4] {since 40 when divided ny 12 leaves a remainder of 4 } b) [37][27] = [ 999] = [9] { Since now the remiander will be 9 when divided by 45} c) [33]([83] - [67]) = [33] [16] = [528] = [28] d) [18] + [8] = [26] = [0]. Hence additive inverse of [18] is [8]..
AnswerThe net equation of the reaction catalyzed by the protein c.pdf
AnswerThe net equation of the reaction catalyzed by the protein c.pdf
aptex1
ย
A Shareholder of a company is holding a share in the assets of the company. A shareholder is also entitled to the profits which company makes by using those assets. As the basic fomat of company distinguishes the Management function from the ownership, People managing the company may or maynot be the owners i.e share holders of the company. Regulators often require the companies to obtain approval of the shareholders via a resolution in the shareholders meeting, thus the deciding power rests with the shareholders. However the extent of powers are contained in the Legislature governing that corporation. Shareholders have right in the assets of the corporation not in the day to day mangement of the corporation. Solution A Shareholder of a company is holding a share in the assets of the company. A shareholder is also entitled to the profits which company makes by using those assets. As the basic fomat of company distinguishes the Management function from the ownership, People managing the company may or maynot be the owners i.e share holders of the company. Regulators often require the companies to obtain approval of the shareholders via a resolution in the shareholders meeting, thus the deciding power rests with the shareholders. However the extent of powers are contained in the Legislature governing that corporation. Shareholders have right in the assets of the corporation not in the day to day mangement of the corporation..
Answer i command.The vi editor always starts in command mode. For.pdf
Answer i command.The vi editor always starts in command mode. For.pdf
aptex1
ย
A chemical formula is an expression indicating the atoms and their number in a particular compound. Each element/atom is identified by its symbol and the number of atoms are given in the subscript. For example, one molecule of water contain 2 atoms of hydrogen and one atom of oxygen: H2O Hope this helps Solution A chemical formula is an expression indicating the atoms and their number in a particular compound. Each element/atom is identified by its symbol and the number of atoms are given in the subscript. For example, one molecule of water contain 2 atoms of hydrogen and one atom of oxygen: H2O Hope this helps.
Answer (b) systems security and control.The businesses are now a .pdf
Answer (b) systems security and control.The businesses are now a .pdf
aptex1
ย
2) b) Understory is rich in humidity hence supports fungi 3) a) canopy includes plant crowns 4) c) herbaceous 5) d) leaf litter/soil Solution 2) b) Understory is rich in humidity hence supports fungi 3) a) canopy includes plant crowns 4) c) herbaceous 5) d) leaf litter/soil.
A. Temeperature of refrigeratorsIntervalB. Horspower of .pdf
A. Temeperature of refrigeratorsIntervalB. Horspower of .pdf
aptex1
ย
1 gallon gasoline = 3.785 L = 3.785 x 803 grams Now, total heat produced = weight(in gms) x heat of combustion = 3.785 x 803 x 48 kJ =145889.04 kJ =145.9 MJ IT IS VERY LARGE NUMBER !!!! Solution 1 gallon gasoline = 3.785 L = 3.785 x 803 grams Now, total heat produced = weight(in gms) x heat of combustion = 3.785 x 803 x 48 kJ =145889.04 kJ =145.9 MJ IT IS VERY LARGE NUMBER !!!!.
48. The answer is Botulism. Botulism ia an illness that brings about.pdf
48. The answer is Botulism. Botulism ia an illness that brings about.pdf
aptex1
ย
(A) The answer is b. increases Electricity in the form of electrons are transported through the solution by charged ions of the electrolyte. As the electrolyte concentration increases, so does the number of charge carriers and hence the amount of charge and electricity conducted increases. (B) Acetic acid (CH3COOH) is a weak acid and partially ionizes in water: CH3COOH + H2O => CH3COO- + H3O+ The charged acetate (CH3COO- ) and hydroxonium (H3O+) ions are responsible for electrical conductivity. In 6 M acetic acid, water is in excess and and the ionization proceeds as shown above to give an electrolyte solution with charged ions that conduct electricity. In glacial acetic acid, there is very little water present and ionization is negliglble. Almost all the acetic acid remains in the non-conducting molecular form (CH3COOH) and there are no charged ions present. Thus glacial acetic acid does not conduct electricity. Solution (A) The answer is b. increases Electricity in the form of electrons are transported through the solution by charged ions of the electrolyte. As the electrolyte concentration increases, so does the number of charge carriers and hence the amount of charge and electricity conducted increases. (B) Acetic acid (CH3COOH) is a weak acid and partially ionizes in water: CH3COOH + H2O => CH3COO- + H3O+ The charged acetate (CH3COO- ) and hydroxonium (H3O+) ions are responsible for electrical conductivity. In 6 M acetic acid, water is in excess and and the ionization proceeds as shown above to give an electrolyte solution with charged ions that conduct electricity. In glacial acetic acid, there is very little water present and ionization is negliglble. Almost all the acetic acid remains in the non-conducting molecular form (CH3COOH) and there are no charged ions present. Thus glacial acetic acid does not conduct electricity..
2) b) Understory is rich in humidity hence supports fungi3) a) can.pdf
2) b) Understory is rich in humidity hence supports fungi3) a) can.pdf
aptex1
ย
#include #include #include int check(char*); int k=0; char a[100]; void shift(int,int); int main() { int i,j=0,l=0,m,p,z; do { if(j) cout<<\"Enter the string\"; fgets(a,100,stdin); j=check(a); } while(j); for(i=0;i0 && m!=2;j--) { m=2; if(a[j]==\'+\'||a[j]==\'-\'||a[j]==\'*\'||a[j]==\'/\') l++; } if(m==2) { for(m=j-2,p=1,z=1;z!=2&&m>0;m--) { if(p==1) if(a[m]==\'(\') p=2; if(p==2) { if(a[m]==\'(\'&&(a[m-1]==\'+\' ||a[m-1]==\'-\' ||a[m-1]==\'*\'||a[m-1]==\'/\')) { m--; z=2; } } } j=m; } if(j<0) j=0; else j=j+2; shift(l,j); a[j]=\'(\'; k--; i++; } } if(k) cout<<\"Your putput is\"<<\"\ \"; cout<=0;i--) { if(a[i]==\')\') k++; if(a[i]==\'(\') return 1; } Output: Enter the string 1+2)*3-4)5-6))) Your output is ((1+2)*((3-4)*(5-6)) Solution #include #include #include int check(char*); int k=0; char a[100]; void shift(int,int); int main() { int i,j=0,l=0,m,p,z; do { if(j) cout<<\"Enter the string\"; fgets(a,100,stdin); j=check(a); } while(j); for(i=0;i0 && m!=2;j--) { m=2; if(a[j]==\'+\'||a[j]==\'-\'||a[j]==\'*\'||a[j]==\'/\') l++; } if(m==2) { for(m=j-2,p=1,z=1;z!=2&&m>0;m--) { if(p==1) if(a[m]==\'(\') p=2; if(p==2) { if(a[m]==\'(\'&&(a[m-1]==\'+\' ||a[m-1]==\'-\' ||a[m-1]==\'*\'||a[m-1]==\'/\')) { m--; z=2; } } } j=m; } if(j<0) j=0; else j=j+2; shift(l,j); a[j]=\'(\'; k--; i++; } } if(k) cout<<\"Your putput is\"<<\"\ \"; cout<=0;i--) { if(a[i]==\')\') k++; if(a[i]==\'(\') return 1; } Output: Enter the string 1+2)*3-4)5-6))) Your output is ((1+2)*((3-4)*(5-6)).
1.Discuss in detail Emile Durkheim and his contributions to the fiel.pdf
1.Discuss in detail Emile Durkheim and his contributions to the fiel.pdf
aptex1
ย
#include #include #define TRUE 1 /* Put your lab 4 functions prototypes here, as well as the prototype for lab 5 */ double mag(double ax, double ay, double az); int close_to (double tolerance, double point, double value); int clearAll (int *a, int *b, int *c, int *d, int *e, int *f); int main(void) { int t, b1, b2, b3, b4, b5, s; double ax, ay, az; double tolerance = 0.25, point = 1.0, value; int a,b,c,d,e,f; while (TRUE && b2 != 1 && ( mag ( ax, ay, az)-1<(tolerance*3))) { scanf(\"%d, %lf, %lf, %lf, %d, %d, %d, %d, %d, %d\", &t, &ax, &ay, &az, &b1, &b2, &b3, &b4, &b5, &s ); if(close_to(tolerance, point, ax)==1 && a != 1){ printf(\"RIGHT\ \ \"); clearAll ( &a, &b, &c, &d, &e, &f); a = 1; fflush(stdout); } if(close_to(tolerance, point, ay)==1 && b != 1){ printf(\"FRONT\ \ \"); fflush(stdout); clearAll ( &a, &b, &c, &d, &e, &f); b = 1; } if(close_to(tolerance, point, az)==1 && c != 1){ printf(\"TOP\ \ \"); fflush(stdout); clearAll ( &a, &b, &c, &d, &e, &f); c = 1; } if(close_to(tolerance, point, ax)==2 && d != 1){ printf(\"LEFT\ \ \"); fflush(stdout); clearAll ( &a, &b, &c, &d, &e, &f); d = 1; } if(close_to(tolerance, point, ay)==2 && e != 1){ printf(\"BACK\ \ \"); fflush(stdout); clearAll ( &a, &b, &c, &d, &e, &f); e = 1; } if(close_to(tolerance, point, az)==2 && f != 1){ printf(\"BOTTOM\ \ \"); fflush(stdout); clearAll ( &a, &b, &c, &d, &e, &f); f = 1; } return 0; } } /* Put your lab 4 functions here, as well as your new function close_to */ double mag(double ax, double ay, double az){ double y = sqrt(ax*ax + ay*ay + az*az); return y; } int close_to (double tolerance, double point, double value){ if (value>0){ if (sqrt((value-point)*(value-point))<(tolerance)){ return 1; } else{ return 0; } } else{ if(sqrt((value+point)*(value+point))<(tolerance)) //? it used to not have sqrt return 2; } } int clearAll (int *a, int *b, int *c, int *d, int *e, int *f){ *a = *b = *c = *d = *e = *f = 0; } Solution #include #include #define TRUE 1 /* Put your lab 4 functions prototypes here, as well as the prototype for lab 5 */ double mag(double ax, double ay, double az); int close_to (double tolerance, double point, double value); int clearAll (int *a, int *b, int *c, int *d, int *e, int *f); int main(void) { int t, b1, b2, b3, b4, b5, s; double ax, ay, az; double tolerance = 0.25, point = 1.0, value; int a,b,c,d,e,f; while (TRUE && b2 != 1 && ( mag ( ax, ay, az)-1<(tolerance*3))) { scanf(\"%d, %lf, %lf, %lf, %d, %d, %d, %d, %d, %d\", &t, &ax, &ay, &az, &b1, &b2, &b3, &b4, &b5, &s ); if(close_to(tolerance, point, ax)==1 && a != 1){ printf(\"RIGHT\ \ \"); clearAll ( &a, &b, &c, &d, &e, &f); a = 1; fflush(stdout); } if(close_to(tolerance, point, ay)==1 && b != 1){ printf(\"FRONT\ \ \"); fflush(stdout); clearAll ( &a, &b, &c, &d, &e, &f); b = 1; } if(close_to(tolerance, point, az)==1 && c != 1){ printf(\"TOP\ \ \"); fflush(stdout); clearAll ( &a, &b, &c, &d, &e, &f); c = 1; } if(close_to(tolerance, point, ax)==2 && d != 1){ printf(\"LEFT\ \ \"); fflush(stdout); cl.
1) YELLOW FEVERGroup Group IV ((+) ssRNA)Orderย ย Unassigned.pdf
1) YELLOW FEVERGroup Group IV ((+) ssRNA)Orderย ย Unassigned.pdf
aptex1
ย
Thermodynamic entropy is a non-conserved state function that is of great importance in the sciences of physics and chemistry. Historically, the concept of entropy evolved in order to explain why some processes (permitted by conservation laws) occur spontaneously while their time reversals (also permitted by conservation laws) do not; systems tend to progress in the direction of increasing entropy. For isolated systems, entropy never decreases. This fact has several important consequences in science: first, it prohibits \"perpetual motion\" machines; and second, it implies the arrow of entropy has the same directionality as the arrow of time. Increases in entropy correspond to irreversible changes in a system, because some energy is expended as waste heat, limiting the amount of work a system can do. In statistical mechanics, entropy is a measure of the number of ways in which a system may be arranged, often taken to be a measure of \"disorder\" (the higher the entropy, the higher the disorder). This definition describes the entropy as being proportional to the natural logarithm of the number of possible microscopic configurations of the individual atoms and molecules of the system (microstates) which could give rise to the observed macroscopic state (macrostate) of the system. The constant of proportionality is the Boltzmann constant. - Wiki Solution Thermodynamic entropy is a non-conserved state function that is of great importance in the sciences of physics and chemistry. Historically, the concept of entropy evolved in order to explain why some processes (permitted by conservation laws) occur spontaneously while their time reversals (also permitted by conservation laws) do not; systems tend to progress in the direction of increasing entropy. For isolated systems, entropy never decreases. This fact has several important consequences in science: first, it prohibits \"perpetual motion\" machines; and second, it implies the arrow of entropy has the same directionality as the arrow of time. Increases in entropy correspond to irreversible changes in a system, because some energy is expended as waste heat, limiting the amount of work a system can do. In statistical mechanics, entropy is a measure of the number of ways in which a system may be arranged, often taken to be a measure of \"disorder\" (the higher the entropy, the higher the disorder). This definition describes the entropy as being proportional to the natural logarithm of the number of possible microscopic configurations of the individual atoms and molecules of the system (microstates) which could give rise to the observed macroscopic state (macrostate) of the system. The constant of proportionality is the Boltzmann constant. - Wiki.
Thermodynamic entropy is a non-conserved state fu.pdf
Thermodynamic entropy is a non-conserved state fu.pdf
aptex1
ย
I is oxidized by 6 electrons as the oxidation state of I in I- is -1 while in IO3- is +5. Solution I is oxidized by 6 electrons as the oxidation state of I in I- is -1 while in IO3- is +5..
I is oxidized by 6 electrons as the oxidation sta.pdf
I is oxidized by 6 electrons as the oxidation sta.pdf
aptex1
ย
The main difference is that Democritus was not a scientist he was a philosopher as such he only theorized that matter could not be indefinitely divided, that there is a limit (now know to be the atom). Dalton on the other had based his theory of atoms on scientific experimentation and observation. Demeocritus used reason vs. Dalton used scientific method Solution The main difference is that Democritus was not a scientist he was a philosopher as such he only theorized that matter could not be indefinitely divided, that there is a limit (now know to be the atom). Dalton on the other had based his theory of atoms on scientific experimentation and observation. Demeocritus used reason vs. Dalton used scientific method.
The main difference is that Democritus was not a .pdf
The main difference is that Democritus was not a .pdf
aptex1
ย
for acidic nature is should give H+ equation : HSO3- -----> H+ + SO3^2- ANSWER Solution for acidic nature is should give H+ equation : HSO3- -----> H+ + SO3^2- ANSWER.
for acidic nature is should give H+ equation H.pdf
for acidic nature is should give H+ equation H.pdf
aptex1
ย
both are in opposite direction i.e., magnetic north is in geographical south Solution both are in opposite direction i.e., magnetic north is in geographical south.
both are in opposite direction i.e., magnetic nor.pdf
both are in opposite direction i.e., magnetic nor.pdf
aptex1
ย
B) Decrease the energy of activation. C) Change the path of the reaction. D) Increase the collision frequency. Solution B) Decrease the energy of activation. C) Change the path of the reaction. D) Increase the collision frequency..
B) Decrease the energy of activation. C) Change .pdf
B) Decrease the energy of activation. C) Change .pdf
aptex1
ย
answer CO/CO2 = 15 Solution answer CO/CO2 = 15.
answer COCO2 = 15 .pdf
answer COCO2 = 15 .pdf
aptex1
ย
A. So before we can come up with the chemical equation, we firsthave to understand the components of the salt we are to dissolve.What does it break into? What are the charges of each component ofthe salt, and their individual chemical formulas? So first we lookat the name \"strontium iodate\" so we know that it breaks intostrontium with some charge in water and iodate. Strontium Iodate --> some Strontium + some Iodate (in water) Now for the second question, what are the charges and the chemicalformula of each part? So for strontium, we know that it is analkaline earth metal (or in group II), so we know that like Ca orMg, Sr is most likely to hold a charge of 2+. So we\'ll say that wehave a Sr2+ in solution. How about iodate? By otherremembering or looking it up we find that it isIO3-. So how would we pair these in a salt? Since we know that Sr has a2+ charge and iodate has a 1- charge, we know that to balance atotal charge of 0, we need 2 iodates per Sr making: Sr(IO3)2 as the salt dissolving in solution.This clearly then breaks into 1 Sr2+ and 2IO3- in water. B. Now that we know the reaction, how do the two speciesconcentrations relate to themselves in solution? Well we alreadyanswered this question. By saying that we need to pair 2 iodatesfor each Sr cation, we know that iodate concentration must bedouble that of the Sr cation in water. Cheers. Solution A. So before we can come up with the chemical equation, we firsthave to understand the components of the salt we are to dissolve.What does it break into? What are the charges of each component ofthe salt, and their individual chemical formulas? So first we lookat the name \"strontium iodate\" so we know that it breaks intostrontium with some charge in water and iodate. Strontium Iodate --> some Strontium + some Iodate (in water) Now for the second question, what are the charges and the chemicalformula of each part? So for strontium, we know that it is analkaline earth metal (or in group II), so we know that like Ca orMg, Sr is most likely to hold a charge of 2+. So we\'ll say that wehave a Sr2+ in solution. How about iodate? By otherremembering or looking it up we find that it isIO3-. So how would we pair these in a salt? Since we know that Sr has a2+ charge and iodate has a 1- charge, we know that to balance atotal charge of 0, we need 2 iodates per Sr making: Sr(IO3)2 as the salt dissolving in solution.This clearly then breaks into 1 Sr2+ and 2IO3- in water. B. Now that we know the reaction, how do the two speciesconcentrations relate to themselves in solution? Well we alreadyanswered this question. By saying that we need to pair 2 iodatesfor each Sr cation, we know that iodate concentration must bedouble that of the Sr cation in water. Cheers..
A. So before we can come up with the chemical equ.pdf
A. So before we can come up with the chemical equ.pdf
aptex1
ย
A) 1 and 3 are meso isomers. B) 2 and 4 are not identical as 2 is R,R and 4 is S,S C) They are all not identical D) 1 and 2 are not enantiomers, thery are diasteriomers. Solution A) 1 and 3 are meso isomers. B) 2 and 4 are not identical as 2 is R,R and 4 is S,S C) They are all not identical D) 1 and 2 are not enantiomers, thery are diasteriomers..
A) 1 and 3 are meso isomers. B) 2 and 4 are not i.pdf
A) 1 and 3 are meso isomers. B) 2 and 4 are not i.pdf
aptex1
ย
Wizards are very useful for creating a good user experience. In all businesses, interactive sessions are most beneficial. To improve the user experience, wizards in Odoo provide an interactive session. For creating wizards, we can use transient models or abstract models. This gives features of a model class except the data storing. Transient and abstract models have permanent database persistence. For them, database tables are made, and the records in such tables are kept until they are specifically erased.
How to Create and Manage Wizard in Odoo 17
How to Create and Manage Wizard in Odoo 17
Celine George
ย
Basic Civil Engineering notes first year Notes Building notes Selection of site for Building Layout of a Building What is Burjis, Mutam Building Bye laws Basic Concept of sunlight ventilation in building National Building Code of India Set back or building line Types of Buildings Floor Space Index (F.S.I) Institutional Vs Educational Building Components & function Sills, Lintels, Cantilever Doors, Windows and Ventilators Types of Foundation AND THEIR USES Plinth Area Shallow and Deep Foundation Super Built-up & carpet area Floor Area Ratio (F.A.R) RCC Reinforced Cement Concrete RCC VS PCC
Basic Civil Engineering first year Notes- Chapter 4 Building.pptx
Basic Civil Engineering first year Notes- Chapter 4 Building.pptx
Denish Jangid
ย
General Principles of Intellectual Property: Concepts of Intellectual Property (IP), Intellectual Property Protection (IPP), Intellectual Property Rights (IPR);
General Principles of Intellectual Property: Concepts of Intellectual Proper...
General Principles of Intellectual Property: Concepts of Intellectual Proper...
Poonam Aher Patil
ย
Wednesday 20 March 2024, 09:30-15:30
Wellbeing inclusion and digital dystopias.pptx
Wellbeing inclusion and digital dystopias.pptx
Jisc
ย
Brief pharmacology of Remifentanil
REMIFENTANIL: An Ultra short acting opioid.pptx
REMIFENTANIL: An Ultra short acting opioid.pptx
Dr. Ravikiran H M Gowda
ย
More Related Content
More from aptex1
a) [21]+[19] = [40] = [4] {since 40 when divided ny 12 leaves a remainder of 4 } b) [37][27] = [ 999] = [9] { Since now the remiander will be 9 when divided by 45} c) [33]([83] - [67]) = [33] [16] = [528] = [28] d) [18] + [8] = [26] = [0]. Hence additive inverse of [18] is [8]. Solution a) [21]+[19] = [40] = [4] {since 40 when divided ny 12 leaves a remainder of 4 } b) [37][27] = [ 999] = [9] { Since now the remiander will be 9 when divided by 45} c) [33]([83] - [67]) = [33] [16] = [528] = [28] d) [18] + [8] = [26] = [0]. Hence additive inverse of [18] is [8]..
AnswerThe net equation of the reaction catalyzed by the protein c.pdf
AnswerThe net equation of the reaction catalyzed by the protein c.pdf
aptex1
ย
A Shareholder of a company is holding a share in the assets of the company. A shareholder is also entitled to the profits which company makes by using those assets. As the basic fomat of company distinguishes the Management function from the ownership, People managing the company may or maynot be the owners i.e share holders of the company. Regulators often require the companies to obtain approval of the shareholders via a resolution in the shareholders meeting, thus the deciding power rests with the shareholders. However the extent of powers are contained in the Legislature governing that corporation. Shareholders have right in the assets of the corporation not in the day to day mangement of the corporation. Solution A Shareholder of a company is holding a share in the assets of the company. A shareholder is also entitled to the profits which company makes by using those assets. As the basic fomat of company distinguishes the Management function from the ownership, People managing the company may or maynot be the owners i.e share holders of the company. Regulators often require the companies to obtain approval of the shareholders via a resolution in the shareholders meeting, thus the deciding power rests with the shareholders. However the extent of powers are contained in the Legislature governing that corporation. Shareholders have right in the assets of the corporation not in the day to day mangement of the corporation..
Answer i command.The vi editor always starts in command mode. For.pdf
Answer i command.The vi editor always starts in command mode. For.pdf
aptex1
ย
A chemical formula is an expression indicating the atoms and their number in a particular compound. Each element/atom is identified by its symbol and the number of atoms are given in the subscript. For example, one molecule of water contain 2 atoms of hydrogen and one atom of oxygen: H2O Hope this helps Solution A chemical formula is an expression indicating the atoms and their number in a particular compound. Each element/atom is identified by its symbol and the number of atoms are given in the subscript. For example, one molecule of water contain 2 atoms of hydrogen and one atom of oxygen: H2O Hope this helps.
Answer (b) systems security and control.The businesses are now a .pdf
Answer (b) systems security and control.The businesses are now a .pdf
aptex1
ย
2) b) Understory is rich in humidity hence supports fungi 3) a) canopy includes plant crowns 4) c) herbaceous 5) d) leaf litter/soil Solution 2) b) Understory is rich in humidity hence supports fungi 3) a) canopy includes plant crowns 4) c) herbaceous 5) d) leaf litter/soil.
A. Temeperature of refrigeratorsIntervalB. Horspower of .pdf
A. Temeperature of refrigeratorsIntervalB. Horspower of .pdf
aptex1
ย
1 gallon gasoline = 3.785 L = 3.785 x 803 grams Now, total heat produced = weight(in gms) x heat of combustion = 3.785 x 803 x 48 kJ =145889.04 kJ =145.9 MJ IT IS VERY LARGE NUMBER !!!! Solution 1 gallon gasoline = 3.785 L = 3.785 x 803 grams Now, total heat produced = weight(in gms) x heat of combustion = 3.785 x 803 x 48 kJ =145889.04 kJ =145.9 MJ IT IS VERY LARGE NUMBER !!!!.
48. The answer is Botulism. Botulism ia an illness that brings about.pdf
48. The answer is Botulism. Botulism ia an illness that brings about.pdf
aptex1
ย
(A) The answer is b. increases Electricity in the form of electrons are transported through the solution by charged ions of the electrolyte. As the electrolyte concentration increases, so does the number of charge carriers and hence the amount of charge and electricity conducted increases. (B) Acetic acid (CH3COOH) is a weak acid and partially ionizes in water: CH3COOH + H2O => CH3COO- + H3O+ The charged acetate (CH3COO- ) and hydroxonium (H3O+) ions are responsible for electrical conductivity. In 6 M acetic acid, water is in excess and and the ionization proceeds as shown above to give an electrolyte solution with charged ions that conduct electricity. In glacial acetic acid, there is very little water present and ionization is negliglble. Almost all the acetic acid remains in the non-conducting molecular form (CH3COOH) and there are no charged ions present. Thus glacial acetic acid does not conduct electricity. Solution (A) The answer is b. increases Electricity in the form of electrons are transported through the solution by charged ions of the electrolyte. As the electrolyte concentration increases, so does the number of charge carriers and hence the amount of charge and electricity conducted increases. (B) Acetic acid (CH3COOH) is a weak acid and partially ionizes in water: CH3COOH + H2O => CH3COO- + H3O+ The charged acetate (CH3COO- ) and hydroxonium (H3O+) ions are responsible for electrical conductivity. In 6 M acetic acid, water is in excess and and the ionization proceeds as shown above to give an electrolyte solution with charged ions that conduct electricity. In glacial acetic acid, there is very little water present and ionization is negliglble. Almost all the acetic acid remains in the non-conducting molecular form (CH3COOH) and there are no charged ions present. Thus glacial acetic acid does not conduct electricity..
2) b) Understory is rich in humidity hence supports fungi3) a) can.pdf
2) b) Understory is rich in humidity hence supports fungi3) a) can.pdf
aptex1
ย
#include #include #include int check(char*); int k=0; char a[100]; void shift(int,int); int main() { int i,j=0,l=0,m,p,z; do { if(j) cout<<\"Enter the string\"; fgets(a,100,stdin); j=check(a); } while(j); for(i=0;i0 && m!=2;j--) { m=2; if(a[j]==\'+\'||a[j]==\'-\'||a[j]==\'*\'||a[j]==\'/\') l++; } if(m==2) { for(m=j-2,p=1,z=1;z!=2&&m>0;m--) { if(p==1) if(a[m]==\'(\') p=2; if(p==2) { if(a[m]==\'(\'&&(a[m-1]==\'+\' ||a[m-1]==\'-\' ||a[m-1]==\'*\'||a[m-1]==\'/\')) { m--; z=2; } } } j=m; } if(j<0) j=0; else j=j+2; shift(l,j); a[j]=\'(\'; k--; i++; } } if(k) cout<<\"Your putput is\"<<\"\ \"; cout<=0;i--) { if(a[i]==\')\') k++; if(a[i]==\'(\') return 1; } Output: Enter the string 1+2)*3-4)5-6))) Your output is ((1+2)*((3-4)*(5-6)) Solution #include #include #include int check(char*); int k=0; char a[100]; void shift(int,int); int main() { int i,j=0,l=0,m,p,z; do { if(j) cout<<\"Enter the string\"; fgets(a,100,stdin); j=check(a); } while(j); for(i=0;i0 && m!=2;j--) { m=2; if(a[j]==\'+\'||a[j]==\'-\'||a[j]==\'*\'||a[j]==\'/\') l++; } if(m==2) { for(m=j-2,p=1,z=1;z!=2&&m>0;m--) { if(p==1) if(a[m]==\'(\') p=2; if(p==2) { if(a[m]==\'(\'&&(a[m-1]==\'+\' ||a[m-1]==\'-\' ||a[m-1]==\'*\'||a[m-1]==\'/\')) { m--; z=2; } } } j=m; } if(j<0) j=0; else j=j+2; shift(l,j); a[j]=\'(\'; k--; i++; } } if(k) cout<<\"Your putput is\"<<\"\ \"; cout<=0;i--) { if(a[i]==\')\') k++; if(a[i]==\'(\') return 1; } Output: Enter the string 1+2)*3-4)5-6))) Your output is ((1+2)*((3-4)*(5-6)).
1.Discuss in detail Emile Durkheim and his contributions to the fiel.pdf
1.Discuss in detail Emile Durkheim and his contributions to the fiel.pdf
aptex1
ย
#include #include #define TRUE 1 /* Put your lab 4 functions prototypes here, as well as the prototype for lab 5 */ double mag(double ax, double ay, double az); int close_to (double tolerance, double point, double value); int clearAll (int *a, int *b, int *c, int *d, int *e, int *f); int main(void) { int t, b1, b2, b3, b4, b5, s; double ax, ay, az; double tolerance = 0.25, point = 1.0, value; int a,b,c,d,e,f; while (TRUE && b2 != 1 && ( mag ( ax, ay, az)-1<(tolerance*3))) { scanf(\"%d, %lf, %lf, %lf, %d, %d, %d, %d, %d, %d\", &t, &ax, &ay, &az, &b1, &b2, &b3, &b4, &b5, &s ); if(close_to(tolerance, point, ax)==1 && a != 1){ printf(\"RIGHT\ \ \"); clearAll ( &a, &b, &c, &d, &e, &f); a = 1; fflush(stdout); } if(close_to(tolerance, point, ay)==1 && b != 1){ printf(\"FRONT\ \ \"); fflush(stdout); clearAll ( &a, &b, &c, &d, &e, &f); b = 1; } if(close_to(tolerance, point, az)==1 && c != 1){ printf(\"TOP\ \ \"); fflush(stdout); clearAll ( &a, &b, &c, &d, &e, &f); c = 1; } if(close_to(tolerance, point, ax)==2 && d != 1){ printf(\"LEFT\ \ \"); fflush(stdout); clearAll ( &a, &b, &c, &d, &e, &f); d = 1; } if(close_to(tolerance, point, ay)==2 && e != 1){ printf(\"BACK\ \ \"); fflush(stdout); clearAll ( &a, &b, &c, &d, &e, &f); e = 1; } if(close_to(tolerance, point, az)==2 && f != 1){ printf(\"BOTTOM\ \ \"); fflush(stdout); clearAll ( &a, &b, &c, &d, &e, &f); f = 1; } return 0; } } /* Put your lab 4 functions here, as well as your new function close_to */ double mag(double ax, double ay, double az){ double y = sqrt(ax*ax + ay*ay + az*az); return y; } int close_to (double tolerance, double point, double value){ if (value>0){ if (sqrt((value-point)*(value-point))<(tolerance)){ return 1; } else{ return 0; } } else{ if(sqrt((value+point)*(value+point))<(tolerance)) //? it used to not have sqrt return 2; } } int clearAll (int *a, int *b, int *c, int *d, int *e, int *f){ *a = *b = *c = *d = *e = *f = 0; } Solution #include #include #define TRUE 1 /* Put your lab 4 functions prototypes here, as well as the prototype for lab 5 */ double mag(double ax, double ay, double az); int close_to (double tolerance, double point, double value); int clearAll (int *a, int *b, int *c, int *d, int *e, int *f); int main(void) { int t, b1, b2, b3, b4, b5, s; double ax, ay, az; double tolerance = 0.25, point = 1.0, value; int a,b,c,d,e,f; while (TRUE && b2 != 1 && ( mag ( ax, ay, az)-1<(tolerance*3))) { scanf(\"%d, %lf, %lf, %lf, %d, %d, %d, %d, %d, %d\", &t, &ax, &ay, &az, &b1, &b2, &b3, &b4, &b5, &s ); if(close_to(tolerance, point, ax)==1 && a != 1){ printf(\"RIGHT\ \ \"); clearAll ( &a, &b, &c, &d, &e, &f); a = 1; fflush(stdout); } if(close_to(tolerance, point, ay)==1 && b != 1){ printf(\"FRONT\ \ \"); fflush(stdout); clearAll ( &a, &b, &c, &d, &e, &f); b = 1; } if(close_to(tolerance, point, az)==1 && c != 1){ printf(\"TOP\ \ \"); fflush(stdout); clearAll ( &a, &b, &c, &d, &e, &f); c = 1; } if(close_to(tolerance, point, ax)==2 && d != 1){ printf(\"LEFT\ \ \"); fflush(stdout); cl.
1) YELLOW FEVERGroup Group IV ((+) ssRNA)Orderย ย Unassigned.pdf
1) YELLOW FEVERGroup Group IV ((+) ssRNA)Orderย ย Unassigned.pdf
aptex1
ย
Thermodynamic entropy is a non-conserved state function that is of great importance in the sciences of physics and chemistry. Historically, the concept of entropy evolved in order to explain why some processes (permitted by conservation laws) occur spontaneously while their time reversals (also permitted by conservation laws) do not; systems tend to progress in the direction of increasing entropy. For isolated systems, entropy never decreases. This fact has several important consequences in science: first, it prohibits \"perpetual motion\" machines; and second, it implies the arrow of entropy has the same directionality as the arrow of time. Increases in entropy correspond to irreversible changes in a system, because some energy is expended as waste heat, limiting the amount of work a system can do. In statistical mechanics, entropy is a measure of the number of ways in which a system may be arranged, often taken to be a measure of \"disorder\" (the higher the entropy, the higher the disorder). This definition describes the entropy as being proportional to the natural logarithm of the number of possible microscopic configurations of the individual atoms and molecules of the system (microstates) which could give rise to the observed macroscopic state (macrostate) of the system. The constant of proportionality is the Boltzmann constant. - Wiki Solution Thermodynamic entropy is a non-conserved state function that is of great importance in the sciences of physics and chemistry. Historically, the concept of entropy evolved in order to explain why some processes (permitted by conservation laws) occur spontaneously while their time reversals (also permitted by conservation laws) do not; systems tend to progress in the direction of increasing entropy. For isolated systems, entropy never decreases. This fact has several important consequences in science: first, it prohibits \"perpetual motion\" machines; and second, it implies the arrow of entropy has the same directionality as the arrow of time. Increases in entropy correspond to irreversible changes in a system, because some energy is expended as waste heat, limiting the amount of work a system can do. In statistical mechanics, entropy is a measure of the number of ways in which a system may be arranged, often taken to be a measure of \"disorder\" (the higher the entropy, the higher the disorder). This definition describes the entropy as being proportional to the natural logarithm of the number of possible microscopic configurations of the individual atoms and molecules of the system (microstates) which could give rise to the observed macroscopic state (macrostate) of the system. The constant of proportionality is the Boltzmann constant. - Wiki.
Thermodynamic entropy is a non-conserved state fu.pdf
Thermodynamic entropy is a non-conserved state fu.pdf
aptex1
ย
I is oxidized by 6 electrons as the oxidation state of I in I- is -1 while in IO3- is +5. Solution I is oxidized by 6 electrons as the oxidation state of I in I- is -1 while in IO3- is +5..
I is oxidized by 6 electrons as the oxidation sta.pdf
I is oxidized by 6 electrons as the oxidation sta.pdf
aptex1
ย
The main difference is that Democritus was not a scientist he was a philosopher as such he only theorized that matter could not be indefinitely divided, that there is a limit (now know to be the atom). Dalton on the other had based his theory of atoms on scientific experimentation and observation. Demeocritus used reason vs. Dalton used scientific method Solution The main difference is that Democritus was not a scientist he was a philosopher as such he only theorized that matter could not be indefinitely divided, that there is a limit (now know to be the atom). Dalton on the other had based his theory of atoms on scientific experimentation and observation. Demeocritus used reason vs. Dalton used scientific method.
The main difference is that Democritus was not a .pdf
The main difference is that Democritus was not a .pdf
aptex1
ย
for acidic nature is should give H+ equation : HSO3- -----> H+ + SO3^2- ANSWER Solution for acidic nature is should give H+ equation : HSO3- -----> H+ + SO3^2- ANSWER.
for acidic nature is should give H+ equation H.pdf
for acidic nature is should give H+ equation H.pdf
aptex1
ย
both are in opposite direction i.e., magnetic north is in geographical south Solution both are in opposite direction i.e., magnetic north is in geographical south.
both are in opposite direction i.e., magnetic nor.pdf
both are in opposite direction i.e., magnetic nor.pdf
aptex1
ย
B) Decrease the energy of activation. C) Change the path of the reaction. D) Increase the collision frequency. Solution B) Decrease the energy of activation. C) Change the path of the reaction. D) Increase the collision frequency..
B) Decrease the energy of activation. C) Change .pdf
B) Decrease the energy of activation. C) Change .pdf
aptex1
ย
answer CO/CO2 = 15 Solution answer CO/CO2 = 15.
answer COCO2 = 15 .pdf
answer COCO2 = 15 .pdf
aptex1
ย
A. So before we can come up with the chemical equation, we firsthave to understand the components of the salt we are to dissolve.What does it break into? What are the charges of each component ofthe salt, and their individual chemical formulas? So first we lookat the name \"strontium iodate\" so we know that it breaks intostrontium with some charge in water and iodate. Strontium Iodate --> some Strontium + some Iodate (in water) Now for the second question, what are the charges and the chemicalformula of each part? So for strontium, we know that it is analkaline earth metal (or in group II), so we know that like Ca orMg, Sr is most likely to hold a charge of 2+. So we\'ll say that wehave a Sr2+ in solution. How about iodate? By otherremembering or looking it up we find that it isIO3-. So how would we pair these in a salt? Since we know that Sr has a2+ charge and iodate has a 1- charge, we know that to balance atotal charge of 0, we need 2 iodates per Sr making: Sr(IO3)2 as the salt dissolving in solution.This clearly then breaks into 1 Sr2+ and 2IO3- in water. B. Now that we know the reaction, how do the two speciesconcentrations relate to themselves in solution? Well we alreadyanswered this question. By saying that we need to pair 2 iodatesfor each Sr cation, we know that iodate concentration must bedouble that of the Sr cation in water. Cheers. Solution A. So before we can come up with the chemical equation, we firsthave to understand the components of the salt we are to dissolve.What does it break into? What are the charges of each component ofthe salt, and their individual chemical formulas? So first we lookat the name \"strontium iodate\" so we know that it breaks intostrontium with some charge in water and iodate. Strontium Iodate --> some Strontium + some Iodate (in water) Now for the second question, what are the charges and the chemicalformula of each part? So for strontium, we know that it is analkaline earth metal (or in group II), so we know that like Ca orMg, Sr is most likely to hold a charge of 2+. So we\'ll say that wehave a Sr2+ in solution. How about iodate? By otherremembering or looking it up we find that it isIO3-. So how would we pair these in a salt? Since we know that Sr has a2+ charge and iodate has a 1- charge, we know that to balance atotal charge of 0, we need 2 iodates per Sr making: Sr(IO3)2 as the salt dissolving in solution.This clearly then breaks into 1 Sr2+ and 2IO3- in water. B. Now that we know the reaction, how do the two speciesconcentrations relate to themselves in solution? Well we alreadyanswered this question. By saying that we need to pair 2 iodatesfor each Sr cation, we know that iodate concentration must bedouble that of the Sr cation in water. Cheers..
A. So before we can come up with the chemical equ.pdf
A. So before we can come up with the chemical equ.pdf
aptex1
ย
A) 1 and 3 are meso isomers. B) 2 and 4 are not identical as 2 is R,R and 4 is S,S C) They are all not identical D) 1 and 2 are not enantiomers, thery are diasteriomers. Solution A) 1 and 3 are meso isomers. B) 2 and 4 are not identical as 2 is R,R and 4 is S,S C) They are all not identical D) 1 and 2 are not enantiomers, thery are diasteriomers..
A) 1 and 3 are meso isomers. B) 2 and 4 are not i.pdf
A) 1 and 3 are meso isomers. B) 2 and 4 are not i.pdf
aptex1
ย
More from aptex1
(17)
AnswerThe net equation of the reaction catalyzed by the protein c.pdf
AnswerThe net equation of the reaction catalyzed by the protein c.pdf
ย
Answer i command.The vi editor always starts in command mode. For.pdf
Answer i command.The vi editor always starts in command mode. For.pdf
ย
Answer (b) systems security and control.The businesses are now a .pdf
Answer (b) systems security and control.The businesses are now a .pdf
ย
A. Temeperature of refrigeratorsIntervalB. Horspower of .pdf
A. Temeperature of refrigeratorsIntervalB. Horspower of .pdf
ย
48. The answer is Botulism. Botulism ia an illness that brings about.pdf
48. The answer is Botulism. Botulism ia an illness that brings about.pdf
ย
2) b) Understory is rich in humidity hence supports fungi3) a) can.pdf
2) b) Understory is rich in humidity hence supports fungi3) a) can.pdf
ย
1.Discuss in detail Emile Durkheim and his contributions to the fiel.pdf
1.Discuss in detail Emile Durkheim and his contributions to the fiel.pdf
ย
1) YELLOW FEVERGroup Group IV ((+) ssRNA)Orderย ย Unassigned.pdf
1) YELLOW FEVERGroup Group IV ((+) ssRNA)Orderย ย Unassigned.pdf
ย
Thermodynamic entropy is a non-conserved state fu.pdf
Thermodynamic entropy is a non-conserved state fu.pdf
ย
I is oxidized by 6 electrons as the oxidation sta.pdf
I is oxidized by 6 electrons as the oxidation sta.pdf
ย
The main difference is that Democritus was not a .pdf
The main difference is that Democritus was not a .pdf
ย
for acidic nature is should give H+ equation H.pdf
for acidic nature is should give H+ equation H.pdf
ย
both are in opposite direction i.e., magnetic nor.pdf
both are in opposite direction i.e., magnetic nor.pdf
ย
B) Decrease the energy of activation. C) Change .pdf
B) Decrease the energy of activation. C) Change .pdf
ย
answer COCO2 = 15 .pdf
answer COCO2 = 15 .pdf
ย
A. So before we can come up with the chemical equ.pdf
A. So before we can come up with the chemical equ.pdf
ย
A) 1 and 3 are meso isomers. B) 2 and 4 are not i.pdf
A) 1 and 3 are meso isomers. B) 2 and 4 are not i.pdf
ย
Recently uploaded
Wizards are very useful for creating a good user experience. In all businesses, interactive sessions are most beneficial. To improve the user experience, wizards in Odoo provide an interactive session. For creating wizards, we can use transient models or abstract models. This gives features of a model class except the data storing. Transient and abstract models have permanent database persistence. For them, database tables are made, and the records in such tables are kept until they are specifically erased.
How to Create and Manage Wizard in Odoo 17
How to Create and Manage Wizard in Odoo 17
Celine George
ย
Basic Civil Engineering notes first year Notes Building notes Selection of site for Building Layout of a Building What is Burjis, Mutam Building Bye laws Basic Concept of sunlight ventilation in building National Building Code of India Set back or building line Types of Buildings Floor Space Index (F.S.I) Institutional Vs Educational Building Components & function Sills, Lintels, Cantilever Doors, Windows and Ventilators Types of Foundation AND THEIR USES Plinth Area Shallow and Deep Foundation Super Built-up & carpet area Floor Area Ratio (F.A.R) RCC Reinforced Cement Concrete RCC VS PCC
Basic Civil Engineering first year Notes- Chapter 4 Building.pptx
Basic Civil Engineering first year Notes- Chapter 4 Building.pptx
Denish Jangid
ย
General Principles of Intellectual Property: Concepts of Intellectual Property (IP), Intellectual Property Protection (IPP), Intellectual Property Rights (IPR);
General Principles of Intellectual Property: Concepts of Intellectual Proper...
General Principles of Intellectual Property: Concepts of Intellectual Proper...
Poonam Aher Patil
ย
Wednesday 20 March 2024, 09:30-15:30
Wellbeing inclusion and digital dystopias.pptx
Wellbeing inclusion and digital dystopias.pptx
Jisc
ย
Brief pharmacology of Remifentanil
REMIFENTANIL: An Ultra short acting opioid.pptx
REMIFENTANIL: An Ultra short acting opioid.pptx
Dr. Ravikiran H M Gowda
ย
Python notes for Unit 1 Avanthi PG College
Python Notes for mca i year students osmania university.docx
Python Notes for mca i year students osmania university.docx
Ramakrishna Reddy Bijjam
ย
Enhance user experience in Odoo 17 by adding tooltips to fields. Tooltips provide helpful hints or additional information when users hover over specific fields, improving usability and guiding users through the system.
How to Add a Tool Tip to a Field in Odoo 17
How to Add a Tool Tip to a Field in Odoo 17
Celine George
ย
Here is the slide show presentation from the Pre-Deployment Brief for HMCS Max Bernays from May 8th, 2024.
HMCS Max Bernays Pre-Deployment Brief (May 2024).pptx
HMCS Max Bernays Pre-Deployment Brief (May 2024).pptx
Esquimalt MFRC
ย
This presentation is from the Paper 210A: Research Project Writing: Dissertation Writing and I choose the topic Beyond Borders: Understanding Anime and Manga Fandom: A Comprehensive Audience Analysis.
Beyond_Borders_Understanding_Anime_and_Manga_Fandom_A_Comprehensive_Audience_...
Beyond_Borders_Understanding_Anime_and_Manga_Fandom_A_Comprehensive_Audience_...
Pooja Bhuva
ย
21st_Century_Skills_Framework_Final_Presentation_2.pptx
21st_Century_Skills_Framework_Final_Presentation_2.pptx
21st_Century_Skills_Framework_Final_Presentation_2.pptx
JoelynRubio1
ย
FSB Advising Checklist
FSB Advising Checklist - Orientation 2024
FSB Advising Checklist - Orientation 2024
Elizabeth Walsh
ย
lecture1428550358.pdf for mechanical engineering
Details on CBSE Compartment Exam.pptx1111
Details on CBSE Compartment Exam.pptx1111
GangaMaiya1
ย
NO1 Top Black Magic Specialist In Lahore Black magic In Pakistan Kala Ilam Expert Specialist In Canada Amil Baba In UK +92322-6382012
NO1 Top Black Magic Specialist In Lahore Black magic In Pakistan Kala Ilam Ex...
NO1 Top Black Magic Specialist In Lahore Black magic In Pakistan Kala Ilam Ex...
Amil baba
ย
Fictional Salesman/Saleswoman
FICTIONAL SALESMAN/SALESMAN SNSW 2024.pdf
FICTIONAL SALESMAN/SALESMAN SNSW 2024.pdf
Pondicherry University
ย
Chinese philosophy
Philosophy of china and it's charactistics
Philosophy of china and it's charactistics
hameyhk98
ย
๐๐๐ฌ๐ฌ๐จ๐ง ๐๐ฎ๐ญ๐๐จ๐ฆ๐๐ฌ: -Discern accommodations and modifications within inclusive classroom environments, distinguishing between their respective roles and applications. -Through critical analysis of hypothetical scenarios, learners will adeptly select appropriate accommodations and modifications, honing their ability to foster an inclusive learning environment for students with disabilities or unique challenges.
Understanding Accommodations and Modifications
Understanding Accommodations and Modifications
MJDuyan
ย
This presentation is from the Paper 209: Research Methodology and I choose the topic Interdisciplinary Insights: Data Collection Methods.
Interdisciplinary_Insights_Data_Collection_Methods.pptx
Interdisciplinary_Insights_Data_Collection_Methods.pptx
Pooja Bhuva
ย
Open Tools for Research, Learning, Sharing in Agriculture and Society as a whole. Remote lecture by Marc Dusseiller and Fernando "nano" Castro on open science hardware for agriculture and edication, held for students of microbiology at UGM, Yogyakarta (remote - online )
dusjagr & nano talk on open tools for agriculture research and learning
dusjagr & nano talk on open tools for agriculture research and learning
Marc Dusseiller Dusjagr
ย
This presentation covers the essential parameters of Unit 2 Operations Processes of the subject Operations & Supply Chain Management. Topics Covered: Volume Variety and Flow. Types of Processes and Operations Systems - Continuous Flow system and intermittent flow systems.Job Production, Batch Production, Assembly line and Continuous Flow, Process and Product Layout. Design of Service Systems, Service Blueprinting.
OSCM Unit 2_Operations Processes & Systems
OSCM Unit 2_Operations Processes & Systems
Sandeep D Chaudhary
ย
Meaning of Emotional intelligence, Dimension of Emotional Intelligence- Selfawareness, self-motivation, empathy, Social Skills, Mayer &Saloveys(1997) Cognitive model of EI, Golemans (1995) model of EI B. Spiritual intelligence, Methods to learn & develop spiritual Intelligence- Meditation, Detached Observation, Reflection, Connecting, Practice
Unit 3 Emotional Intelligence and Spiritual Intelligence.pdf
Unit 3 Emotional Intelligence and Spiritual Intelligence.pdf
Dr Vijay Vishwakarma
ย
Recently uploaded
(20)
How to Create and Manage Wizard in Odoo 17
How to Create and Manage Wizard in Odoo 17
ย
Basic Civil Engineering first year Notes- Chapter 4 Building.pptx
Basic Civil Engineering first year Notes- Chapter 4 Building.pptx
ย
General Principles of Intellectual Property: Concepts of Intellectual Proper...
General Principles of Intellectual Property: Concepts of Intellectual Proper...
ย
Wellbeing inclusion and digital dystopias.pptx
Wellbeing inclusion and digital dystopias.pptx
ย
REMIFENTANIL: An Ultra short acting opioid.pptx
REMIFENTANIL: An Ultra short acting opioid.pptx
ย
Python Notes for mca i year students osmania university.docx
Python Notes for mca i year students osmania university.docx
ย
How to Add a Tool Tip to a Field in Odoo 17
How to Add a Tool Tip to a Field in Odoo 17
ย
HMCS Max Bernays Pre-Deployment Brief (May 2024).pptx
HMCS Max Bernays Pre-Deployment Brief (May 2024).pptx
ย
Beyond_Borders_Understanding_Anime_and_Manga_Fandom_A_Comprehensive_Audience_...
Beyond_Borders_Understanding_Anime_and_Manga_Fandom_A_Comprehensive_Audience_...
ย
21st_Century_Skills_Framework_Final_Presentation_2.pptx
21st_Century_Skills_Framework_Final_Presentation_2.pptx
ย
FSB Advising Checklist - Orientation 2024
FSB Advising Checklist - Orientation 2024
ย
Details on CBSE Compartment Exam.pptx1111
Details on CBSE Compartment Exam.pptx1111
ย
NO1 Top Black Magic Specialist In Lahore Black magic In Pakistan Kala Ilam Ex...
NO1 Top Black Magic Specialist In Lahore Black magic In Pakistan Kala Ilam Ex...
ย
FICTIONAL SALESMAN/SALESMAN SNSW 2024.pdf
FICTIONAL SALESMAN/SALESMAN SNSW 2024.pdf
ย
Philosophy of china and it's charactistics
Philosophy of china and it's charactistics
ย
Understanding Accommodations and Modifications
Understanding Accommodations and Modifications
ย
Interdisciplinary_Insights_Data_Collection_Methods.pptx
Interdisciplinary_Insights_Data_Collection_Methods.pptx
ย
dusjagr & nano talk on open tools for agriculture research and learning
dusjagr & nano talk on open tools for agriculture research and learning
ย
OSCM Unit 2_Operations Processes & Systems
OSCM Unit 2_Operations Processes & Systems
ย
Unit 3 Emotional Intelligence and Spiritual Intelligence.pdf
Unit 3 Emotional Intelligence and Spiritual Intelligence.pdf
ย
Simple Nobody Knows The Answer .pdf
1.
Simple Nobody Knows
The Answer Solution Simple Nobody Knows The Answer
Download now