A. Temeperature of refrigeratorsIntervalB. Horspower of .pdf
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2) b) Understory is rich in humidity hence supports fungi 3) a) canopy includes plant crowns 4) c) herbaceous 5) d) leaf litter/soil Solution 2) b) Understory is rich in humidity hence supports fungi 3) a) canopy includes plant crowns 4) c) herbaceous 5) d) leaf litter/soil.
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Name- Gold leaved white PoplarGenus- Populusspecies- albaAutho.pdf
In python,Tkinter is a Graphical user interface package.So,Tkinter tookit for GUI programming
supports protocol handler mechanism.
Protocol is taking care of how interaction takes place between application and windows manager.
self.parent.protocol(\"WM_DELETE_WINDOW\",self.quit_handler)
in the above line \"WM_DELETE_WINDOW\" is a protocol.What this protocl does is :it define
what is going to happen when a user who uses the application and closes window explicitely
using windows manager.
Then this protocol \"WM_DELETE_WINDOE\" bypasses to quit_handler().
That quit_handler() asks user \"whether he or she wants to quit or not\" then simply quit the
window.
Solution
In python,Tkinter is a Graphical user interface package.So,Tkinter tookit for GUI programming
supports protocol handler mechanism.
Protocol is taking care of how interaction takes place between application and windows manager.
self.parent.protocol(\"WM_DELETE_WINDOW\",self.quit_handler)
in the above line \"WM_DELETE_WINDOW\" is a protocol.What this protocl does is :it define
what is going to happen when a user who uses the application and closes window explicitely
using windows manager.
Then this protocol \"WM_DELETE_WINDOE\" bypasses to quit_handler().
That quit_handler() asks user \"whether he or she wants to quit or not\" then simply quit the
window..
MinOfFourNumbers.javaimport java.util.Scanner;public class MinOf.pdf
If I assume you meant supply is determined as [q_(s)=3p^2-4p] and demand is determined as
[q_(d)=-p^2+24] then I would calculate that the equilibrium is where [q_(s)=q_(d)] and p>0. So I
set up the equation [3p^2-4p=-p^2+24] I add [p^2] to both sides of the equation yielding [4p^2-
4p=24] I subtract 24 from each side, yielding the quadratic equation [4p^2-4p-24=0] I factor the
equation [(2p-6)(2p+4)=0] so that means [2p-6=0] or [2p+4=0] In the former case 2p=6 so p=3,
and in the latter 2p=-4 so p=-2. The economic nature of the question requires p>0, so [p!=-2] and
thus the equilibrium price is $3.00 each. Then to determine the equilibrium quantity, we solve
either q expression for p=3.
[q_(s)=3(3)^2-4(3)=3(9)-12=27-12=15]
[q_(d)=-(3^2)+24=-9+24=15]
So the equilibrium quantity is 15 items.
The price and quantity for market equilibrium is 15 items at $3.00 each.
Solution
If I assume you meant supply is determined as [q_(s)=3p^2-4p] and demand is determined as
[q_(d)=-p^2+24] then I would calculate that the equilibrium is where [q_(s)=q_(d)] and p>0. So I
set up the equation [3p^2-4p=-p^2+24] I add [p^2] to both sides of the equation yielding [4p^2-
4p=24] I subtract 24 from each side, yielding the quadratic equation [4p^2-4p-24=0] I factor the
equation [(2p-6)(2p+4)=0] so that means [2p-6=0] or [2p+4=0] In the former case 2p=6 so p=3,
and in the latter 2p=-4 so p=-2. The economic nature of the question requires p>0, so [p!=-2] and
thus the equilibrium price is $3.00 each. Then to determine the equilibrium quantity, we solve
either q expression for p=3.
[q_(s)=3(3)^2-4(3)=3(9)-12=27-12=15]
[q_(d)=-(3^2)+24=-9+24=15]
So the equilibrium quantity is 15 items.
The price and quantity for market equilibrium is 15 items at $3.00 each..
molarity = 0.252101.1 =0.001236 M percent =0.251002 =12.5 .pdf
If this is not soluble in water, this must be nonpolar,
if it si soluble in hexane, this must be nonpolar as well
therefore, we are certain this is nonpolar substance
with low vap pressure...
From the list, nearest BP for that pressure is chloroform with 60ºC (vs 58.) which is ok, since no
range is given.
CCl4 is nonpolar
In order to ensure this, you could use a chromatography with previous data, i.e. use chloroform
standard and run chromatography vs. unkown. If they behave the same ( same Rf value, and
retention time ) then this is most likely chloroform
Solution
If this is not soluble in water, this must be nonpolar,
if it si soluble in hexane, this must be nonpolar as well
therefore, we are certain this is nonpolar substance
with low vap pressure...
From the list, nearest BP for that pressure is chloroform with 60ºC (vs 58.) which is ok, since no
range is given.
CCl4 is nonpolar
In order to ensure this, you could use a chromatography with previous data, i.e. use chloroform
standard and run chromatography vs. unkown. If they behave the same ( same Rf value, and
retention time ) then this is most likely chloroform.
Initial concentration of Br- = 2.25 x 10e-3M1V1=M2V2therefore M2.pdf
From the graph, we can see that there are three values at which f(x)= 0
These are- x= -6,-2,3
Hence the answer is Option D
Solution
From the graph, we can see that there are three values at which f(x)= 0
These are- x= -6,-2,3
Hence the answer is Option D.
import java.util.Scanner;public class HornersPolynomial { .pdf
For a first order reaction rate constant , k = ( 2.303 /t )x log ( a / (a-x))
Where
a = initial amount
a-x = amount left after time t = a / 10
t = time = ?
k = rate constant = 3.43x10 -2 d -2
Plug the values we get t = ( 2.303 /k )x log ( a / (a-x))
= ( 2.303 / 3.43x10 -2 )x log ( a / (a/10))
= 67.14 days
Solution
For a first order reaction rate constant , k = ( 2.303 /t )x log ( a / (a-x))
Where
a = initial amount
a-x = amount left after time t = a / 10
t = time = ?
k = rate constant = 3.43x10 -2 d -2
Plug the values we get t = ( 2.303 /k )x log ( a / (a-x))
= ( 2.303 / 3.43x10 -2 )x log ( a / (a/10))
= 67.14 days.
Direct memory access (DMA) is a function that allows an inputoutput.pdf
approximately all of the propoerty crimes are between 3 standard deviations from the mean
mean,u = 3377.2
standard deviation,s = 847.4
u - 3s = 835
u + 3s = 5919.4
OPTION B
p(Z
Solution
approximately all of the propoerty crimes are between 3 standard deviations from the mean
mean,u = 3377.2
standard deviation,s = 847.4
u - 3s = 835
u + 3s = 5919.4
OPTION B
p(Z.
Ethanol is miscible in water because of the hydroxyl functional grou.pdf
b) Security requirements
Security requirements are the outputs of the risk management activity. Inputs to the risk
management and information security strategy include business strategy, business processes, risk
assessments, business input analysis, information resources, and regulatory requirements.
Solution
b) Security requirements
Security requirements are the outputs of the risk management activity. Inputs to the risk
management and information security strategy include business strategy, business processes, risk
assessments, business input analysis, information resources, and regulatory requirements..
the diluted concentration of HCl = (0.120 M x 25..pdf
the diluted concentration of HCl = (0.120 M x 25.0 mL) / (25.0 + 40.0) mL =
0.0462 M [H+] = [HCl] = 0.0462 M pH = -log[H+] = -log0.0462 = 1.33
Solution
the diluted concentration of HCl = (0.120 M x 25.0 mL) / (25.0 + 40.0) mL =
0.0462 M [H+] = [HCl] = 0.0462 M pH = -log[H+] = -log0.0462 = 1.33.
Recommended
Name- Gold leaved white PoplarGenus- Populusspecies- albaAutho.pdf
In python,Tkinter is a Graphical user interface package.So,Tkinter tookit for GUI programming
supports protocol handler mechanism.
Protocol is taking care of how interaction takes place between application and windows manager.
self.parent.protocol(\"WM_DELETE_WINDOW\",self.quit_handler)
in the above line \"WM_DELETE_WINDOW\" is a protocol.What this protocl does is :it define
what is going to happen when a user who uses the application and closes window explicitely
using windows manager.
Then this protocol \"WM_DELETE_WINDOE\" bypasses to quit_handler().
That quit_handler() asks user \"whether he or she wants to quit or not\" then simply quit the
window.
Solution
In python,Tkinter is a Graphical user interface package.So,Tkinter tookit for GUI programming
supports protocol handler mechanism.
Protocol is taking care of how interaction takes place between application and windows manager.
self.parent.protocol(\"WM_DELETE_WINDOW\",self.quit_handler)
in the above line \"WM_DELETE_WINDOW\" is a protocol.What this protocl does is :it define
what is going to happen when a user who uses the application and closes window explicitely
using windows manager.
Then this protocol \"WM_DELETE_WINDOE\" bypasses to quit_handler().
That quit_handler() asks user \"whether he or she wants to quit or not\" then simply quit the
window..
MinOfFourNumbers.javaimport java.util.Scanner;public class MinOf.pdf
If I assume you meant supply is determined as [q_(s)=3p^2-4p] and demand is determined as
[q_(d)=-p^2+24] then I would calculate that the equilibrium is where [q_(s)=q_(d)] and p>0. So I
set up the equation [3p^2-4p=-p^2+24] I add [p^2] to both sides of the equation yielding [4p^2-
4p=24] I subtract 24 from each side, yielding the quadratic equation [4p^2-4p-24=0] I factor the
equation [(2p-6)(2p+4)=0] so that means [2p-6=0] or [2p+4=0] In the former case 2p=6 so p=3,
and in the latter 2p=-4 so p=-2. The economic nature of the question requires p>0, so [p!=-2] and
thus the equilibrium price is $3.00 each. Then to determine the equilibrium quantity, we solve
either q expression for p=3.
[q_(s)=3(3)^2-4(3)=3(9)-12=27-12=15]
[q_(d)=-(3^2)+24=-9+24=15]
So the equilibrium quantity is 15 items.
The price and quantity for market equilibrium is 15 items at $3.00 each.
Solution
If I assume you meant supply is determined as [q_(s)=3p^2-4p] and demand is determined as
[q_(d)=-p^2+24] then I would calculate that the equilibrium is where [q_(s)=q_(d)] and p>0. So I
set up the equation [3p^2-4p=-p^2+24] I add [p^2] to both sides of the equation yielding [4p^2-
4p=24] I subtract 24 from each side, yielding the quadratic equation [4p^2-4p-24=0] I factor the
equation [(2p-6)(2p+4)=0] so that means [2p-6=0] or [2p+4=0] In the former case 2p=6 so p=3,
and in the latter 2p=-4 so p=-2. The economic nature of the question requires p>0, so [p!=-2] and
thus the equilibrium price is $3.00 each. Then to determine the equilibrium quantity, we solve
either q expression for p=3.
[q_(s)=3(3)^2-4(3)=3(9)-12=27-12=15]
[q_(d)=-(3^2)+24=-9+24=15]
So the equilibrium quantity is 15 items.
The price and quantity for market equilibrium is 15 items at $3.00 each..
molarity = 0.252101.1 =0.001236 M percent =0.251002 =12.5 .pdf
If this is not soluble in water, this must be nonpolar,
if it si soluble in hexane, this must be nonpolar as well
therefore, we are certain this is nonpolar substance
with low vap pressure...
From the list, nearest BP for that pressure is chloroform with 60ºC (vs 58.) which is ok, since no
range is given.
CCl4 is nonpolar
In order to ensure this, you could use a chromatography with previous data, i.e. use chloroform
standard and run chromatography vs. unkown. If they behave the same ( same Rf value, and
retention time ) then this is most likely chloroform
Solution
If this is not soluble in water, this must be nonpolar,
if it si soluble in hexane, this must be nonpolar as well
therefore, we are certain this is nonpolar substance
with low vap pressure...
From the list, nearest BP for that pressure is chloroform with 60ºC (vs 58.) which is ok, since no
range is given.
CCl4 is nonpolar
In order to ensure this, you could use a chromatography with previous data, i.e. use chloroform
standard and run chromatography vs. unkown. If they behave the same ( same Rf value, and
retention time ) then this is most likely chloroform.
Initial concentration of Br- = 2.25 x 10e-3M1V1=M2V2therefore M2.pdf
From the graph, we can see that there are three values at which f(x)= 0
These are- x= -6,-2,3
Hence the answer is Option D
Solution
From the graph, we can see that there are three values at which f(x)= 0
These are- x= -6,-2,3
Hence the answer is Option D.
import java.util.Scanner;public class HornersPolynomial { .pdf
For a first order reaction rate constant , k = ( 2.303 /t )x log ( a / (a-x))
Where
a = initial amount
a-x = amount left after time t = a / 10
t = time = ?
k = rate constant = 3.43x10 -2 d -2
Plug the values we get t = ( 2.303 /k )x log ( a / (a-x))
= ( 2.303 / 3.43x10 -2 )x log ( a / (a/10))
= 67.14 days
Solution
For a first order reaction rate constant , k = ( 2.303 /t )x log ( a / (a-x))
Where
a = initial amount
a-x = amount left after time t = a / 10
t = time = ?
k = rate constant = 3.43x10 -2 d -2
Plug the values we get t = ( 2.303 /k )x log ( a / (a-x))
= ( 2.303 / 3.43x10 -2 )x log ( a / (a/10))
= 67.14 days.
Direct memory access (DMA) is a function that allows an inputoutput.pdf
approximately all of the propoerty crimes are between 3 standard deviations from the mean
mean,u = 3377.2
standard deviation,s = 847.4
u - 3s = 835
u + 3s = 5919.4
OPTION B
p(Z
Solution
approximately all of the propoerty crimes are between 3 standard deviations from the mean
mean,u = 3377.2
standard deviation,s = 847.4
u - 3s = 835
u + 3s = 5919.4
OPTION B
p(Z.
Ethanol is miscible in water because of the hydroxyl functional grou.pdf
b) Security requirements
Security requirements are the outputs of the risk management activity. Inputs to the risk
management and information security strategy include business strategy, business processes, risk
assessments, business input analysis, information resources, and regulatory requirements.
Solution
b) Security requirements
Security requirements are the outputs of the risk management activity. Inputs to the risk
management and information security strategy include business strategy, business processes, risk
assessments, business input analysis, information resources, and regulatory requirements..
the diluted concentration of HCl = (0.120 M x 25..pdf
the diluted concentration of HCl = (0.120 M x 25.0 mL) / (25.0 + 40.0) mL =
0.0462 M [H+] = [HCl] = 0.0462 M pH = -log[H+] = -log0.0462 = 1.33
Solution
the diluted concentration of HCl = (0.120 M x 25.0 mL) / (25.0 + 40.0) mL =
0.0462 M [H+] = [HCl] = 0.0462 M pH = -log[H+] = -log0.0462 = 1.33.
Simple Nobody Knows The Answer .pdf
Simple Nobody Knows The Answer
Solution
Simple Nobody Knows The Answer.
AnswerThe net equation of the reaction catalyzed by the protein c.pdf
a) [21]+[19] = [40] = [4] {since 40 when divided ny 12 leaves a remainder of 4 }
b) [37][27] = [ 999] = [9] { Since now the remiander will be 9 when divided by 45}
c) [33]([83] - [67]) = [33] [16] = [528] = [28]
d) [18] + [8] = [26] = [0]. Hence additive inverse of [18] is [8].
Solution
a) [21]+[19] = [40] = [4] {since 40 when divided ny 12 leaves a remainder of 4 }
b) [37][27] = [ 999] = [9] { Since now the remiander will be 9 when divided by 45}
c) [33]([83] - [67]) = [33] [16] = [528] = [28]
d) [18] + [8] = [26] = [0]. Hence additive inverse of [18] is [8]..
Answer i command.The vi editor always starts in command mode. For.pdf
A Shareholder of a company is holding a share in the assets of the company. A shareholder is
also entitled to the profits which company makes by using those assets. As the basic fomat of
company distinguishes the Management function from the ownership, People managing the
company may or maynot be the owners i.e share holders of the company. Regulators often
require the companies to obtain approval of the shareholders via a resolution in the shareholders
meeting, thus the deciding power rests with the shareholders. However the extent of powers are
contained in the Legislature governing that corporation.
Shareholders have right in the assets of the corporation not in the day to day mangement of the
corporation.
Solution
A Shareholder of a company is holding a share in the assets of the company. A shareholder is
also entitled to the profits which company makes by using those assets. As the basic fomat of
company distinguishes the Management function from the ownership, People managing the
company may or maynot be the owners i.e share holders of the company. Regulators often
require the companies to obtain approval of the shareholders via a resolution in the shareholders
meeting, thus the deciding power rests with the shareholders. However the extent of powers are
contained in the Legislature governing that corporation.
Shareholders have right in the assets of the corporation not in the day to day mangement of the
corporation..
Answer (b) systems security and control.The businesses are now a .pdf
A chemical formula is an expression indicating the atoms and their number in a particular
compound.
Each element/atom is identified by its symbol and the number of atoms are given in the
subscript.
For example, one molecule of water contain 2 atoms of hydrogen and one atom of oxygen:
H2O
Hope this helps
Solution
A chemical formula is an expression indicating the atoms and their number in a particular
compound.
Each element/atom is identified by its symbol and the number of atoms are given in the
subscript.
For example, one molecule of water contain 2 atoms of hydrogen and one atom of oxygen:
H2O
Hope this helps.
48. The answer is Botulism. Botulism ia an illness that brings about.pdf
1 gallon gasoline = 3.785 L = 3.785 x 803 grams
Now, total heat produced = weight(in gms) x heat of combustion = 3.785 x 803 x 48 kJ
=145889.04 kJ =145.9 MJ
IT IS VERY LARGE NUMBER !!!!
Solution
1 gallon gasoline = 3.785 L = 3.785 x 803 grams
Now, total heat produced = weight(in gms) x heat of combustion = 3.785 x 803 x 48 kJ
=145889.04 kJ =145.9 MJ
IT IS VERY LARGE NUMBER !!!!.
2) b) Understory is rich in humidity hence supports fungi3) a) can.pdf
(A) The answer is b. increases
Electricity in the form of electrons are transported through the solution by charged ions of the
electrolyte. As the electrolyte concentration increases, so does the number of charge carriers and
hence the amount of charge and electricity conducted increases.
(B) Acetic acid (CH3COOH) is a weak acid and partially ionizes in water:
CH3COOH + H2O => CH3COO- + H3O+
The charged acetate (CH3COO- ) and hydroxonium (H3O+) ions are responsible for electrical
conductivity.
In 6 M acetic acid, water is in excess and and the ionization proceeds as shown above to give an
electrolyte solution with charged ions that conduct electricity.
In glacial acetic acid, there is very little water present and ionization is negliglble. Almost all the
acetic acid remains in the non-conducting molecular form (CH3COOH) and there are no charged
ions present. Thus glacial acetic acid does not conduct electricity.
Solution
(A) The answer is b. increases
Electricity in the form of electrons are transported through the solution by charged ions of the
electrolyte. As the electrolyte concentration increases, so does the number of charge carriers and
hence the amount of charge and electricity conducted increases.
(B) Acetic acid (CH3COOH) is a weak acid and partially ionizes in water:
CH3COOH + H2O => CH3COO- + H3O+
The charged acetate (CH3COO- ) and hydroxonium (H3O+) ions are responsible for electrical
conductivity.
In 6 M acetic acid, water is in excess and and the ionization proceeds as shown above to give an
electrolyte solution with charged ions that conduct electricity.
In glacial acetic acid, there is very little water present and ionization is negliglble. Almost all the
acetic acid remains in the non-conducting molecular form (CH3COOH) and there are no charged
ions present. Thus glacial acetic acid does not conduct electricity..
1.Discuss in detail Emile Durkheim and his contributions to the fiel.pdf
#include
#include
#include
int check(char*);
int k=0;
char a[100];
void shift(int,int);
int main()
{
int i,j=0,l=0,m,p,z;
do
{
if(j)
cout<<\"Enter the string\";
fgets(a,100,stdin);
j=check(a);
} while(j);
for(i=0;i0 && m!=2;j--)
{
m=2;
if(a[j]==\'+\'||a[j]==\'-\'||a[j]==\'*\'||a[j]==\'/\')
l++;
}
if(m==2)
{
for(m=j-2,p=1,z=1;z!=2&&m>0;m--)
{
if(p==1)
if(a[m]==\'(\')
p=2;
if(p==2)
{
if(a[m]==\'(\'&&(a[m-1]==\'+\' ||a[m-1]==\'-\' ||a[m-1]==\'*\'||a[m-1]==\'/\'))
{
m--;
z=2;
}
}
}
j=m;
}
if(j<0)
j=0;
else
j=j+2;
shift(l,j);
a[j]=\'(\';
k--;
i++;
}
}
if(k)
cout<<\"Your putput is\"<<\"\ \";
cout<=0;i--)
{
if(a[i]==\')\')
k++;
if(a[i]==\'(\')
return 1;
}
Output:
Enter the string 1+2)*3-4)5-6)))
Your output is
((1+2)*((3-4)*(5-6))
Solution
#include
#include
#include
int check(char*);
int k=0;
char a[100];
void shift(int,int);
int main()
{
int i,j=0,l=0,m,p,z;
do
{
if(j)
cout<<\"Enter the string\";
fgets(a,100,stdin);
j=check(a);
} while(j);
for(i=0;i0 && m!=2;j--)
{
m=2;
if(a[j]==\'+\'||a[j]==\'-\'||a[j]==\'*\'||a[j]==\'/\')
l++;
}
if(m==2)
{
for(m=j-2,p=1,z=1;z!=2&&m>0;m--)
{
if(p==1)
if(a[m]==\'(\')
p=2;
if(p==2)
{
if(a[m]==\'(\'&&(a[m-1]==\'+\' ||a[m-1]==\'-\' ||a[m-1]==\'*\'||a[m-1]==\'/\'))
{
m--;
z=2;
}
}
}
j=m;
}
if(j<0)
j=0;
else
j=j+2;
shift(l,j);
a[j]=\'(\';
k--;
i++;
}
}
if(k)
cout<<\"Your putput is\"<<\"\ \";
cout<=0;i--)
{
if(a[i]==\')\')
k++;
if(a[i]==\'(\')
return 1;
}
Output:
Enter the string 1+2)*3-4)5-6)))
Your output is
((1+2)*((3-4)*(5-6)).
1) YELLOW FEVERGroup Group IV ((+) ssRNA)Order Unassigned.pdf
#include
#include
#define TRUE 1
/* Put your lab 4 functions prototypes here, as well as the prototype for lab 5 */
double mag(double ax, double ay, double az);
int close_to (double tolerance, double point, double value);
int clearAll (int *a, int *b, int *c, int *d, int *e, int *f);
int main(void) {
int t, b1, b2, b3, b4, b5, s;
double ax, ay, az;
double tolerance = 0.25, point = 1.0, value;
int a,b,c,d,e,f;
while (TRUE && b2 != 1 && ( mag ( ax, ay, az)-1<(tolerance*3))) {
scanf(\"%d, %lf, %lf, %lf, %d, %d, %d, %d, %d, %d\", &t, &ax, &ay, &az, &b1, &b2, &b3,
&b4, &b5, &s );
if(close_to(tolerance, point, ax)==1 && a != 1){
printf(\"RIGHT\ \ \");
clearAll ( &a, &b, &c, &d, &e, &f);
a = 1;
fflush(stdout);
}
if(close_to(tolerance, point, ay)==1 && b != 1){
printf(\"FRONT\ \ \");
fflush(stdout);
clearAll ( &a, &b, &c, &d, &e, &f);
b = 1;
}
if(close_to(tolerance, point, az)==1 && c != 1){
printf(\"TOP\ \ \");
fflush(stdout);
clearAll ( &a, &b, &c, &d, &e, &f);
c = 1;
}
if(close_to(tolerance, point, ax)==2 && d != 1){
printf(\"LEFT\ \ \");
fflush(stdout);
clearAll ( &a, &b, &c, &d, &e, &f);
d = 1;
}
if(close_to(tolerance, point, ay)==2 && e != 1){
printf(\"BACK\ \ \");
fflush(stdout);
clearAll ( &a, &b, &c, &d, &e, &f);
e = 1;
}
if(close_to(tolerance, point, az)==2 && f != 1){
printf(\"BOTTOM\ \ \");
fflush(stdout);
clearAll ( &a, &b, &c, &d, &e, &f);
f = 1;
}
return 0;
}
}
/* Put your lab 4 functions here, as well as your new function close_to */
double mag(double ax, double ay, double az){
double y = sqrt(ax*ax + ay*ay + az*az);
return y;
}
int close_to (double tolerance, double point, double value){
if (value>0){
if (sqrt((value-point)*(value-point))<(tolerance)){
return 1;
}
else{
return 0;
}
}
else{
if(sqrt((value+point)*(value+point))<(tolerance)) //? it used to not have sqrt
return 2;
}
}
int clearAll (int *a, int *b, int *c, int *d, int *e, int *f){
*a = *b = *c = *d = *e = *f = 0;
}
Solution
#include
#include
#define TRUE 1
/* Put your lab 4 functions prototypes here, as well as the prototype for lab 5 */
double mag(double ax, double ay, double az);
int close_to (double tolerance, double point, double value);
int clearAll (int *a, int *b, int *c, int *d, int *e, int *f);
int main(void) {
int t, b1, b2, b3, b4, b5, s;
double ax, ay, az;
double tolerance = 0.25, point = 1.0, value;
int a,b,c,d,e,f;
while (TRUE && b2 != 1 && ( mag ( ax, ay, az)-1<(tolerance*3))) {
scanf(\"%d, %lf, %lf, %lf, %d, %d, %d, %d, %d, %d\", &t, &ax, &ay, &az, &b1, &b2, &b3,
&b4, &b5, &s );
if(close_to(tolerance, point, ax)==1 && a != 1){
printf(\"RIGHT\ \ \");
clearAll ( &a, &b, &c, &d, &e, &f);
a = 1;
fflush(stdout);
}
if(close_to(tolerance, point, ay)==1 && b != 1){
printf(\"FRONT\ \ \");
fflush(stdout);
clearAll ( &a, &b, &c, &d, &e, &f);
b = 1;
}
if(close_to(tolerance, point, az)==1 && c != 1){
printf(\"TOP\ \ \");
fflush(stdout);
clearAll ( &a, &b, &c, &d, &e, &f);
c = 1;
}
if(close_to(tolerance, point, ax)==2 && d != 1){
printf(\"LEFT\ \ \");
fflush(stdout);
cl.
Thermodynamic entropy is a non-conserved state fu.pdf
Thermodynamic entropy is a non-conserved state function that is of great
importance in the sciences of physics and chemistry. Historically, the concept of entropy evolved
in order to explain why some processes (permitted by conservation laws) occur spontaneously
while their time reversals (also permitted by conservation laws) do not; systems tend to progress
in the direction of increasing entropy. For isolated systems, entropy never decreases. This fact
has several important consequences in science: first, it prohibits \"perpetual motion\" machines;
and second, it implies the arrow of entropy has the same directionality as the arrow of time.
Increases in entropy correspond to irreversible changes in a system, because some energy is
expended as waste heat, limiting the amount of work a system can do. In statistical mechanics,
entropy is a measure of the number of ways in which a system may be arranged, often taken to
be a measure of \"disorder\" (the higher the entropy, the higher the disorder). This definition
describes the entropy as being proportional to the natural logarithm of the number of possible
microscopic configurations of the individual atoms and molecules of the system (microstates)
which could give rise to the observed macroscopic state (macrostate) of the system. The constant
of proportionality is the Boltzmann constant. - Wiki
Solution
Thermodynamic entropy is a non-conserved state function that is of great
importance in the sciences of physics and chemistry. Historically, the concept of entropy evolved
in order to explain why some processes (permitted by conservation laws) occur spontaneously
while their time reversals (also permitted by conservation laws) do not; systems tend to progress
in the direction of increasing entropy. For isolated systems, entropy never decreases. This fact
has several important consequences in science: first, it prohibits \"perpetual motion\" machines;
and second, it implies the arrow of entropy has the same directionality as the arrow of time.
Increases in entropy correspond to irreversible changes in a system, because some energy is
expended as waste heat, limiting the amount of work a system can do. In statistical mechanics,
entropy is a measure of the number of ways in which a system may be arranged, often taken to
be a measure of \"disorder\" (the higher the entropy, the higher the disorder). This definition
describes the entropy as being proportional to the natural logarithm of the number of possible
microscopic configurations of the individual atoms and molecules of the system (microstates)
which could give rise to the observed macroscopic state (macrostate) of the system. The constant
of proportionality is the Boltzmann constant. - Wiki.
I is oxidized by 6 electrons as the oxidation sta.pdf
I is oxidized by 6 electrons as the oxidation state of I in I- is -1 while in IO3- is +5.
Solution
I is oxidized by 6 electrons as the oxidation state of I in I- is -1 while in IO3- is +5..
The main difference is that Democritus was not a .pdf
The main difference is that Democritus was not a scientist he was a philosopher as
such he only theorized that matter could not be indefinitely divided, that there is a limit (now
know to be the atom). Dalton on the other had based his theory of atoms on scientific
experimentation and observation. Demeocritus used reason vs. Dalton used scientific method
Solution
The main difference is that Democritus was not a scientist he was a philosopher as
such he only theorized that matter could not be indefinitely divided, that there is a limit (now
know to be the atom). Dalton on the other had based his theory of atoms on scientific
experimentation and observation. Demeocritus used reason vs. Dalton used scientific method.
for acidic nature is should give H+ equation H.pdf
for acidic nature is should give H+ equation : HSO3- -----> H+ + SO3^2-
ANSWER
Solution
for acidic nature is should give H+ equation : HSO3- -----> H+ + SO3^2-
ANSWER.
both are in opposite direction i.e., magnetic nor.pdf
both are in opposite direction i.e., magnetic north is in geographical south
Solution
both are in opposite direction i.e., magnetic north is in geographical south.
B) Decrease the energy of activation. C) Change .pdf
B) Decrease the energy of activation. C) Change the path of the reaction. D)
Increase the collision frequency.
Solution
B) Decrease the energy of activation. C) Change the path of the reaction. D)
Increase the collision frequency..
A. So before we can come up with the chemical equ.pdf
A. So before we can come up with the chemical equation, we firsthave to
understand the components of the salt we are to dissolve.What does it break into? What are the
charges of each component ofthe salt, and their individual chemical formulas? So first we lookat
the name \"strontium iodate\" so we know that it breaks intostrontium with some charge in water
and iodate. Strontium Iodate --> some Strontium + some Iodate (in water) Now for the second
question, what are the charges and the chemicalformula of each part? So for strontium, we know
that it is analkaline earth metal (or in group II), so we know that like Ca orMg, Sr is most likely
to hold a charge of 2+. So we\'ll say that wehave a Sr2+ in solution. How about iodate? By
otherremembering or looking it up we find that it isIO3-. So how would we pair these in a salt?
Since we know that Sr has a2+ charge and iodate has a 1- charge, we know that to balance atotal
charge of 0, we need 2 iodates per Sr making: Sr(IO3)2 as the salt dissolving in solution.This
clearly then breaks into 1 Sr2+ and 2IO3- in water. B. Now that we know the reaction, how do
the two speciesconcentrations relate to themselves in solution? Well we alreadyanswered this
question. By saying that we need to pair 2 iodatesfor each Sr cation, we know that iodate
concentration must bedouble that of the Sr cation in water. Cheers.
Solution
A. So before we can come up with the chemical equation, we firsthave to
understand the components of the salt we are to dissolve.What does it break into? What are the
charges of each component ofthe salt, and their individual chemical formulas? So first we lookat
the name \"strontium iodate\" so we know that it breaks intostrontium with some charge in water
and iodate. Strontium Iodate --> some Strontium + some Iodate (in water) Now for the second
question, what are the charges and the chemicalformula of each part? So for strontium, we know
that it is analkaline earth metal (or in group II), so we know that like Ca orMg, Sr is most likely
to hold a charge of 2+. So we\'ll say that wehave a Sr2+ in solution. How about iodate? By
otherremembering or looking it up we find that it isIO3-. So how would we pair these in a salt?
Since we know that Sr has a2+ charge and iodate has a 1- charge, we know that to balance atotal
charge of 0, we need 2 iodates per Sr making: Sr(IO3)2 as the salt dissolving in solution.This
clearly then breaks into 1 Sr2+ and 2IO3- in water. B. Now that we know the reaction, how do
the two speciesconcentrations relate to themselves in solution? Well we alreadyanswered this
question. By saying that we need to pair 2 iodatesfor each Sr cation, we know that iodate
concentration must bedouble that of the Sr cation in water. Cheers..
A) 1 and 3 are meso isomers. B) 2 and 4 are not i.pdf
A) 1 and 3 are meso isomers. B) 2 and 4 are not identical as 2 is R,R and 4 is S,S C)
They are all not identical D) 1 and 2 are not enantiomers, thery are diasteriomers.
Solution
A) 1 and 3 are meso isomers. B) 2 and 4 are not identical as 2 is R,R and 4 is S,S C)
They are all not identical D) 1 and 2 are not enantiomers, thery are diasteriomers..
Template Jadual Bertugas Kelas (Boleh Edit)
Jadual Bertugas kelas dalam bentuk softcopy PowerPoint. Cikgu boleh download >> edit >> print >> laminate. Semoga bermanfaat.
Digital Tools and AI for Teaching Learning and Research
This Presentation in details discusses on Digital Tools and AI for Teaching Learning and Research
How to Break the cycle of negative Thoughts
We all have good and bad thoughts from time to time and situation to situation. We are bombarded daily with spiraling thoughts(both negative and positive) creating all-consuming feel , making us difficult to manage with associated suffering. Good thoughts are like our Mob Signal (Positive thought) amidst noise(negative thought) in the atmosphere. Negative thoughts like noise outweigh positive thoughts. These thoughts often create unwanted confusion, trouble, stress and frustration in our mind as well as chaos in our physical world. Negative thoughts are also known as “distorted thinking”.
The approach at University of Liverpool.pptx
How libraries can support authors with open access requirements for UKRI funded books
Wednesday 22 May 2024, 14:00-15:00.
The Challenger.pdf DNHS Official Publication
Read| The latest issue of The Challenger is here! We are thrilled to announce that our school paper has qualified for the NATIONAL SCHOOLS PRESS CONFERENCE (NSPC) 2024. Thank you for your unwavering support and trust. Dive into the stories that made us stand out!
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Simple Nobody Knows The Answer .pdf
Simple Nobody Knows The Answer
Solution
Simple Nobody Knows The Answer.
AnswerThe net equation of the reaction catalyzed by the protein c.pdf
a) [21]+[19] = [40] = [4] {since 40 when divided ny 12 leaves a remainder of 4 }
b) [37][27] = [ 999] = [9] { Since now the remiander will be 9 when divided by 45}
c) [33]([83] - [67]) = [33] [16] = [528] = [28]
d) [18] + [8] = [26] = [0]. Hence additive inverse of [18] is [8].
Solution
a) [21]+[19] = [40] = [4] {since 40 when divided ny 12 leaves a remainder of 4 }
b) [37][27] = [ 999] = [9] { Since now the remiander will be 9 when divided by 45}
c) [33]([83] - [67]) = [33] [16] = [528] = [28]
d) [18] + [8] = [26] = [0]. Hence additive inverse of [18] is [8]..
Answer i command.The vi editor always starts in command mode. For.pdf
A Shareholder of a company is holding a share in the assets of the company. A shareholder is
also entitled to the profits which company makes by using those assets. As the basic fomat of
company distinguishes the Management function from the ownership, People managing the
company may or maynot be the owners i.e share holders of the company. Regulators often
require the companies to obtain approval of the shareholders via a resolution in the shareholders
meeting, thus the deciding power rests with the shareholders. However the extent of powers are
contained in the Legislature governing that corporation.
Shareholders have right in the assets of the corporation not in the day to day mangement of the
corporation.
Solution
A Shareholder of a company is holding a share in the assets of the company. A shareholder is
also entitled to the profits which company makes by using those assets. As the basic fomat of
company distinguishes the Management function from the ownership, People managing the
company may or maynot be the owners i.e share holders of the company. Regulators often
require the companies to obtain approval of the shareholders via a resolution in the shareholders
meeting, thus the deciding power rests with the shareholders. However the extent of powers are
contained in the Legislature governing that corporation.
Shareholders have right in the assets of the corporation not in the day to day mangement of the
corporation..
Answer (b) systems security and control.The businesses are now a .pdf
A chemical formula is an expression indicating the atoms and their number in a particular
compound.
Each element/atom is identified by its symbol and the number of atoms are given in the
subscript.
For example, one molecule of water contain 2 atoms of hydrogen and one atom of oxygen:
H2O
Hope this helps
Solution
A chemical formula is an expression indicating the atoms and their number in a particular
compound.
Each element/atom is identified by its symbol and the number of atoms are given in the
subscript.
For example, one molecule of water contain 2 atoms of hydrogen and one atom of oxygen:
H2O
Hope this helps.
48. The answer is Botulism. Botulism ia an illness that brings about.pdf
1 gallon gasoline = 3.785 L = 3.785 x 803 grams
Now, total heat produced = weight(in gms) x heat of combustion = 3.785 x 803 x 48 kJ
=145889.04 kJ =145.9 MJ
IT IS VERY LARGE NUMBER !!!!
Solution
1 gallon gasoline = 3.785 L = 3.785 x 803 grams
Now, total heat produced = weight(in gms) x heat of combustion = 3.785 x 803 x 48 kJ
=145889.04 kJ =145.9 MJ
IT IS VERY LARGE NUMBER !!!!.
2) b) Understory is rich in humidity hence supports fungi3) a) can.pdf
(A) The answer is b. increases
Electricity in the form of electrons are transported through the solution by charged ions of the
electrolyte. As the electrolyte concentration increases, so does the number of charge carriers and
hence the amount of charge and electricity conducted increases.
(B) Acetic acid (CH3COOH) is a weak acid and partially ionizes in water:
CH3COOH + H2O => CH3COO- + H3O+
The charged acetate (CH3COO- ) and hydroxonium (H3O+) ions are responsible for electrical
conductivity.
In 6 M acetic acid, water is in excess and and the ionization proceeds as shown above to give an
electrolyte solution with charged ions that conduct electricity.
In glacial acetic acid, there is very little water present and ionization is negliglble. Almost all the
acetic acid remains in the non-conducting molecular form (CH3COOH) and there are no charged
ions present. Thus glacial acetic acid does not conduct electricity.
Solution
(A) The answer is b. increases
Electricity in the form of electrons are transported through the solution by charged ions of the
electrolyte. As the electrolyte concentration increases, so does the number of charge carriers and
hence the amount of charge and electricity conducted increases.
(B) Acetic acid (CH3COOH) is a weak acid and partially ionizes in water:
CH3COOH + H2O => CH3COO- + H3O+
The charged acetate (CH3COO- ) and hydroxonium (H3O+) ions are responsible for electrical
conductivity.
In 6 M acetic acid, water is in excess and and the ionization proceeds as shown above to give an
electrolyte solution with charged ions that conduct electricity.
In glacial acetic acid, there is very little water present and ionization is negliglble. Almost all the
acetic acid remains in the non-conducting molecular form (CH3COOH) and there are no charged
ions present. Thus glacial acetic acid does not conduct electricity..
1.Discuss in detail Emile Durkheim and his contributions to the fiel.pdf
#include
#include
#include
int check(char*);
int k=0;
char a[100];
void shift(int,int);
int main()
{
int i,j=0,l=0,m,p,z;
do
{
if(j)
cout<<\"Enter the string\";
fgets(a,100,stdin);
j=check(a);
} while(j);
for(i=0;i0 && m!=2;j--)
{
m=2;
if(a[j]==\'+\'||a[j]==\'-\'||a[j]==\'*\'||a[j]==\'/\')
l++;
}
if(m==2)
{
for(m=j-2,p=1,z=1;z!=2&&m>0;m--)
{
if(p==1)
if(a[m]==\'(\')
p=2;
if(p==2)
{
if(a[m]==\'(\'&&(a[m-1]==\'+\' ||a[m-1]==\'-\' ||a[m-1]==\'*\'||a[m-1]==\'/\'))
{
m--;
z=2;
}
}
}
j=m;
}
if(j<0)
j=0;
else
j=j+2;
shift(l,j);
a[j]=\'(\';
k--;
i++;
}
}
if(k)
cout<<\"Your putput is\"<<\"\ \";
cout<=0;i--)
{
if(a[i]==\')\')
k++;
if(a[i]==\'(\')
return 1;
}
Output:
Enter the string 1+2)*3-4)5-6)))
Your output is
((1+2)*((3-4)*(5-6))
Solution
#include
#include
#include
int check(char*);
int k=0;
char a[100];
void shift(int,int);
int main()
{
int i,j=0,l=0,m,p,z;
do
{
if(j)
cout<<\"Enter the string\";
fgets(a,100,stdin);
j=check(a);
} while(j);
for(i=0;i0 && m!=2;j--)
{
m=2;
if(a[j]==\'+\'||a[j]==\'-\'||a[j]==\'*\'||a[j]==\'/\')
l++;
}
if(m==2)
{
for(m=j-2,p=1,z=1;z!=2&&m>0;m--)
{
if(p==1)
if(a[m]==\'(\')
p=2;
if(p==2)
{
if(a[m]==\'(\'&&(a[m-1]==\'+\' ||a[m-1]==\'-\' ||a[m-1]==\'*\'||a[m-1]==\'/\'))
{
m--;
z=2;
}
}
}
j=m;
}
if(j<0)
j=0;
else
j=j+2;
shift(l,j);
a[j]=\'(\';
k--;
i++;
}
}
if(k)
cout<<\"Your putput is\"<<\"\ \";
cout<=0;i--)
{
if(a[i]==\')\')
k++;
if(a[i]==\'(\')
return 1;
}
Output:
Enter the string 1+2)*3-4)5-6)))
Your output is
((1+2)*((3-4)*(5-6)).
1) YELLOW FEVERGroup Group IV ((+) ssRNA)Order Unassigned.pdf
#include
#include
#define TRUE 1
/* Put your lab 4 functions prototypes here, as well as the prototype for lab 5 */
double mag(double ax, double ay, double az);
int close_to (double tolerance, double point, double value);
int clearAll (int *a, int *b, int *c, int *d, int *e, int *f);
int main(void) {
int t, b1, b2, b3, b4, b5, s;
double ax, ay, az;
double tolerance = 0.25, point = 1.0, value;
int a,b,c,d,e,f;
while (TRUE && b2 != 1 && ( mag ( ax, ay, az)-1<(tolerance*3))) {
scanf(\"%d, %lf, %lf, %lf, %d, %d, %d, %d, %d, %d\", &t, &ax, &ay, &az, &b1, &b2, &b3,
&b4, &b5, &s );
if(close_to(tolerance, point, ax)==1 && a != 1){
printf(\"RIGHT\ \ \");
clearAll ( &a, &b, &c, &d, &e, &f);
a = 1;
fflush(stdout);
}
if(close_to(tolerance, point, ay)==1 && b != 1){
printf(\"FRONT\ \ \");
fflush(stdout);
clearAll ( &a, &b, &c, &d, &e, &f);
b = 1;
}
if(close_to(tolerance, point, az)==1 && c != 1){
printf(\"TOP\ \ \");
fflush(stdout);
clearAll ( &a, &b, &c, &d, &e, &f);
c = 1;
}
if(close_to(tolerance, point, ax)==2 && d != 1){
printf(\"LEFT\ \ \");
fflush(stdout);
clearAll ( &a, &b, &c, &d, &e, &f);
d = 1;
}
if(close_to(tolerance, point, ay)==2 && e != 1){
printf(\"BACK\ \ \");
fflush(stdout);
clearAll ( &a, &b, &c, &d, &e, &f);
e = 1;
}
if(close_to(tolerance, point, az)==2 && f != 1){
printf(\"BOTTOM\ \ \");
fflush(stdout);
clearAll ( &a, &b, &c, &d, &e, &f);
f = 1;
}
return 0;
}
}
/* Put your lab 4 functions here, as well as your new function close_to */
double mag(double ax, double ay, double az){
double y = sqrt(ax*ax + ay*ay + az*az);
return y;
}
int close_to (double tolerance, double point, double value){
if (value>0){
if (sqrt((value-point)*(value-point))<(tolerance)){
return 1;
}
else{
return 0;
}
}
else{
if(sqrt((value+point)*(value+point))<(tolerance)) //? it used to not have sqrt
return 2;
}
}
int clearAll (int *a, int *b, int *c, int *d, int *e, int *f){
*a = *b = *c = *d = *e = *f = 0;
}
Solution
#include
#include
#define TRUE 1
/* Put your lab 4 functions prototypes here, as well as the prototype for lab 5 */
double mag(double ax, double ay, double az);
int close_to (double tolerance, double point, double value);
int clearAll (int *a, int *b, int *c, int *d, int *e, int *f);
int main(void) {
int t, b1, b2, b3, b4, b5, s;
double ax, ay, az;
double tolerance = 0.25, point = 1.0, value;
int a,b,c,d,e,f;
while (TRUE && b2 != 1 && ( mag ( ax, ay, az)-1<(tolerance*3))) {
scanf(\"%d, %lf, %lf, %lf, %d, %d, %d, %d, %d, %d\", &t, &ax, &ay, &az, &b1, &b2, &b3,
&b4, &b5, &s );
if(close_to(tolerance, point, ax)==1 && a != 1){
printf(\"RIGHT\ \ \");
clearAll ( &a, &b, &c, &d, &e, &f);
a = 1;
fflush(stdout);
}
if(close_to(tolerance, point, ay)==1 && b != 1){
printf(\"FRONT\ \ \");
fflush(stdout);
clearAll ( &a, &b, &c, &d, &e, &f);
b = 1;
}
if(close_to(tolerance, point, az)==1 && c != 1){
printf(\"TOP\ \ \");
fflush(stdout);
clearAll ( &a, &b, &c, &d, &e, &f);
c = 1;
}
if(close_to(tolerance, point, ax)==2 && d != 1){
printf(\"LEFT\ \ \");
fflush(stdout);
cl.
Thermodynamic entropy is a non-conserved state fu.pdf
Thermodynamic entropy is a non-conserved state function that is of great
importance in the sciences of physics and chemistry. Historically, the concept of entropy evolved
in order to explain why some processes (permitted by conservation laws) occur spontaneously
while their time reversals (also permitted by conservation laws) do not; systems tend to progress
in the direction of increasing entropy. For isolated systems, entropy never decreases. This fact
has several important consequences in science: first, it prohibits \"perpetual motion\" machines;
and second, it implies the arrow of entropy has the same directionality as the arrow of time.
Increases in entropy correspond to irreversible changes in a system, because some energy is
expended as waste heat, limiting the amount of work a system can do. In statistical mechanics,
entropy is a measure of the number of ways in which a system may be arranged, often taken to
be a measure of \"disorder\" (the higher the entropy, the higher the disorder). This definition
describes the entropy as being proportional to the natural logarithm of the number of possible
microscopic configurations of the individual atoms and molecules of the system (microstates)
which could give rise to the observed macroscopic state (macrostate) of the system. The constant
of proportionality is the Boltzmann constant. - Wiki
Solution
Thermodynamic entropy is a non-conserved state function that is of great
importance in the sciences of physics and chemistry. Historically, the concept of entropy evolved
in order to explain why some processes (permitted by conservation laws) occur spontaneously
while their time reversals (also permitted by conservation laws) do not; systems tend to progress
in the direction of increasing entropy. For isolated systems, entropy never decreases. This fact
has several important consequences in science: first, it prohibits \"perpetual motion\" machines;
and second, it implies the arrow of entropy has the same directionality as the arrow of time.
Increases in entropy correspond to irreversible changes in a system, because some energy is
expended as waste heat, limiting the amount of work a system can do. In statistical mechanics,
entropy is a measure of the number of ways in which a system may be arranged, often taken to
be a measure of \"disorder\" (the higher the entropy, the higher the disorder). This definition
describes the entropy as being proportional to the natural logarithm of the number of possible
microscopic configurations of the individual atoms and molecules of the system (microstates)
which could give rise to the observed macroscopic state (macrostate) of the system. The constant
of proportionality is the Boltzmann constant. - Wiki.
I is oxidized by 6 electrons as the oxidation sta.pdf
I is oxidized by 6 electrons as the oxidation state of I in I- is -1 while in IO3- is +5.
Solution
I is oxidized by 6 electrons as the oxidation state of I in I- is -1 while in IO3- is +5..
The main difference is that Democritus was not a .pdf
The main difference is that Democritus was not a scientist he was a philosopher as
such he only theorized that matter could not be indefinitely divided, that there is a limit (now
know to be the atom). Dalton on the other had based his theory of atoms on scientific
experimentation and observation. Demeocritus used reason vs. Dalton used scientific method
Solution
The main difference is that Democritus was not a scientist he was a philosopher as
such he only theorized that matter could not be indefinitely divided, that there is a limit (now
know to be the atom). Dalton on the other had based his theory of atoms on scientific
experimentation and observation. Demeocritus used reason vs. Dalton used scientific method.
for acidic nature is should give H+ equation H.pdf
for acidic nature is should give H+ equation : HSO3- -----> H+ + SO3^2-
ANSWER
Solution
for acidic nature is should give H+ equation : HSO3- -----> H+ + SO3^2-
ANSWER.
both are in opposite direction i.e., magnetic nor.pdf
both are in opposite direction i.e., magnetic north is in geographical south
Solution
both are in opposite direction i.e., magnetic north is in geographical south.
B) Decrease the energy of activation. C) Change .pdf
B) Decrease the energy of activation. C) Change the path of the reaction. D)
Increase the collision frequency.
Solution
B) Decrease the energy of activation. C) Change the path of the reaction. D)
Increase the collision frequency..
A. So before we can come up with the chemical equ.pdf
A. So before we can come up with the chemical equation, we firsthave to
understand the components of the salt we are to dissolve.What does it break into? What are the
charges of each component ofthe salt, and their individual chemical formulas? So first we lookat
the name \"strontium iodate\" so we know that it breaks intostrontium with some charge in water
and iodate. Strontium Iodate --> some Strontium + some Iodate (in water) Now for the second
question, what are the charges and the chemicalformula of each part? So for strontium, we know
that it is analkaline earth metal (or in group II), so we know that like Ca orMg, Sr is most likely
to hold a charge of 2+. So we\'ll say that wehave a Sr2+ in solution. How about iodate? By
otherremembering or looking it up we find that it isIO3-. So how would we pair these in a salt?
Since we know that Sr has a2+ charge and iodate has a 1- charge, we know that to balance atotal
charge of 0, we need 2 iodates per Sr making: Sr(IO3)2 as the salt dissolving in solution.This
clearly then breaks into 1 Sr2+ and 2IO3- in water. B. Now that we know the reaction, how do
the two speciesconcentrations relate to themselves in solution? Well we alreadyanswered this
question. By saying that we need to pair 2 iodatesfor each Sr cation, we know that iodate
concentration must bedouble that of the Sr cation in water. Cheers.
Solution
A. So before we can come up with the chemical equation, we firsthave to
understand the components of the salt we are to dissolve.What does it break into? What are the
charges of each component ofthe salt, and their individual chemical formulas? So first we lookat
the name \"strontium iodate\" so we know that it breaks intostrontium with some charge in water
and iodate. Strontium Iodate --> some Strontium + some Iodate (in water) Now for the second
question, what are the charges and the chemicalformula of each part? So for strontium, we know
that it is analkaline earth metal (or in group II), so we know that like Ca orMg, Sr is most likely
to hold a charge of 2+. So we\'ll say that wehave a Sr2+ in solution. How about iodate? By
otherremembering or looking it up we find that it isIO3-. So how would we pair these in a salt?
Since we know that Sr has a2+ charge and iodate has a 1- charge, we know that to balance atotal
charge of 0, we need 2 iodates per Sr making: Sr(IO3)2 as the salt dissolving in solution.This
clearly then breaks into 1 Sr2+ and 2IO3- in water. B. Now that we know the reaction, how do
the two speciesconcentrations relate to themselves in solution? Well we alreadyanswered this
question. By saying that we need to pair 2 iodatesfor each Sr cation, we know that iodate
concentration must bedouble that of the Sr cation in water. Cheers..
A) 1 and 3 are meso isomers. B) 2 and 4 are not i.pdf
A) 1 and 3 are meso isomers. B) 2 and 4 are not identical as 2 is R,R and 4 is S,S C)
They are all not identical D) 1 and 2 are not enantiomers, thery are diasteriomers.
Solution
A) 1 and 3 are meso isomers. B) 2 and 4 are not identical as 2 is R,R and 4 is S,S C)
They are all not identical D) 1 and 2 are not enantiomers, thery are diasteriomers..
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