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answer CO/CO2 = 15 Solution answer CO/CO2 = 15.
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In python,Tkinter is a Graphical user interface package.So,Tkinter tookit for GUI programming supports protocol handler mechanism. Protocol is taking care of how interaction takes place between application and windows manager. self.parent.protocol(\"WM_DELETE_WINDOW\",self.quit_handler) in the above line \"WM_DELETE_WINDOW\" is a protocol.What this protocl does is :it define what is going to happen when a user who uses the application and closes window explicitely using windows manager. Then this protocol \"WM_DELETE_WINDOE\" bypasses to quit_handler(). That quit_handler() asks user \"whether he or she wants to quit or not\" then simply quit the window. Solution In python,Tkinter is a Graphical user interface package.So,Tkinter tookit for GUI programming supports protocol handler mechanism. Protocol is taking care of how interaction takes place between application and windows manager. self.parent.protocol(\"WM_DELETE_WINDOW\",self.quit_handler) in the above line \"WM_DELETE_WINDOW\" is a protocol.What this protocl does is :it define what is going to happen when a user who uses the application and closes window explicitely using windows manager. Then this protocol \"WM_DELETE_WINDOE\" bypasses to quit_handler(). That quit_handler() asks user \"whether he or she wants to quit or not\" then simply quit the window..
Name- Gold leaved white PoplarGenus- Populusspecies- albaAutho.pdf
Name- Gold leaved white PoplarGenus- Populusspecies- albaAutho.pdf
aptex1
If I assume you meant supply is determined as [q_(s)=3p^2-4p] and demand is determined as [q_(d)=-p^2+24] then I would calculate that the equilibrium is where [q_(s)=q_(d)] and p>0. So I set up the equation [3p^2-4p=-p^2+24] I add [p^2] to both sides of the equation yielding [4p^2- 4p=24] I subtract 24 from each side, yielding the quadratic equation [4p^2-4p-24=0] I factor the equation [(2p-6)(2p+4)=0] so that means [2p-6=0] or [2p+4=0] In the former case 2p=6 so p=3, and in the latter 2p=-4 so p=-2. The economic nature of the question requires p>0, so [p!=-2] and thus the equilibrium price is $3.00 each. Then to determine the equilibrium quantity, we solve either q expression for p=3. [q_(s)=3(3)^2-4(3)=3(9)-12=27-12=15] [q_(d)=-(3^2)+24=-9+24=15] So the equilibrium quantity is 15 items. The price and quantity for market equilibrium is 15 items at $3.00 each. Solution If I assume you meant supply is determined as [q_(s)=3p^2-4p] and demand is determined as [q_(d)=-p^2+24] then I would calculate that the equilibrium is where [q_(s)=q_(d)] and p>0. So I set up the equation [3p^2-4p=-p^2+24] I add [p^2] to both sides of the equation yielding [4p^2- 4p=24] I subtract 24 from each side, yielding the quadratic equation [4p^2-4p-24=0] I factor the equation [(2p-6)(2p+4)=0] so that means [2p-6=0] or [2p+4=0] In the former case 2p=6 so p=3, and in the latter 2p=-4 so p=-2. The economic nature of the question requires p>0, so [p!=-2] and thus the equilibrium price is $3.00 each. Then to determine the equilibrium quantity, we solve either q expression for p=3. [q_(s)=3(3)^2-4(3)=3(9)-12=27-12=15] [q_(d)=-(3^2)+24=-9+24=15] So the equilibrium quantity is 15 items. The price and quantity for market equilibrium is 15 items at $3.00 each..
MinOfFourNumbers.javaimport java.util.Scanner;public class MinOf.pdf
MinOfFourNumbers.javaimport java.util.Scanner;public class MinOf.pdf
aptex1
If this is not soluble in water, this must be nonpolar, if it si soluble in hexane, this must be nonpolar as well therefore, we are certain this is nonpolar substance with low vap pressure... From the list, nearest BP for that pressure is chloroform with 60ºC (vs 58.) which is ok, since no range is given. CCl4 is nonpolar In order to ensure this, you could use a chromatography with previous data, i.e. use chloroform standard and run chromatography vs. unkown. If they behave the same ( same Rf value, and retention time ) then this is most likely chloroform Solution If this is not soluble in water, this must be nonpolar, if it si soluble in hexane, this must be nonpolar as well therefore, we are certain this is nonpolar substance with low vap pressure... From the list, nearest BP for that pressure is chloroform with 60ºC (vs 58.) which is ok, since no range is given. CCl4 is nonpolar In order to ensure this, you could use a chromatography with previous data, i.e. use chloroform standard and run chromatography vs. unkown. If they behave the same ( same Rf value, and retention time ) then this is most likely chloroform.
molarity = 0.252101.1 =0.001236 M percent =0.251002 =12.5 .pdf
molarity = 0.252101.1 =0.001236 M percent =0.251002 =12.5 .pdf
aptex1
From the graph, we can see that there are three values at which f(x)= 0 These are- x= -6,-2,3 Hence the answer is Option D Solution From the graph, we can see that there are three values at which f(x)= 0 These are- x= -6,-2,3 Hence the answer is Option D.
Initial concentration of Br- = 2.25 x 10e-3M1V1=M2V2therefore M2.pdf
Initial concentration of Br- = 2.25 x 10e-3M1V1=M2V2therefore M2.pdf
aptex1
For a first order reaction rate constant , k = ( 2.303 /t )x log ( a / (a-x)) Where a = initial amount a-x = amount left after time t = a / 10 t = time = ? k = rate constant = 3.43x10 -2 d -2 Plug the values we get t = ( 2.303 /k )x log ( a / (a-x)) = ( 2.303 / 3.43x10 -2 )x log ( a / (a/10)) = 67.14 days Solution For a first order reaction rate constant , k = ( 2.303 /t )x log ( a / (a-x)) Where a = initial amount a-x = amount left after time t = a / 10 t = time = ? k = rate constant = 3.43x10 -2 d -2 Plug the values we get t = ( 2.303 /k )x log ( a / (a-x)) = ( 2.303 / 3.43x10 -2 )x log ( a / (a/10)) = 67.14 days.
import java.util.Scanner;public class HornersPolynomial { .pdf
import java.util.Scanner;public class HornersPolynomial { .pdf
aptex1
approximately all of the propoerty crimes are between 3 standard deviations from the mean mean,u = 3377.2 standard deviation,s = 847.4 u - 3s = 835 u + 3s = 5919.4 OPTION B p(Z Solution approximately all of the propoerty crimes are between 3 standard deviations from the mean mean,u = 3377.2 standard deviation,s = 847.4 u - 3s = 835 u + 3s = 5919.4 OPTION B p(Z.
Direct memory access (DMA) is a function that allows an inputoutput.pdf
Direct memory access (DMA) is a function that allows an inputoutput.pdf
aptex1
b) Security requirements Security requirements are the outputs of the risk management activity. Inputs to the risk management and information security strategy include business strategy, business processes, risk assessments, business input analysis, information resources, and regulatory requirements. Solution b) Security requirements Security requirements are the outputs of the risk management activity. Inputs to the risk management and information security strategy include business strategy, business processes, risk assessments, business input analysis, information resources, and regulatory requirements..
Ethanol is miscible in water because of the hydroxyl functional grou.pdf
Ethanol is miscible in water because of the hydroxyl functional grou.pdf
aptex1
the diluted concentration of HCl = (0.120 M x 25.0 mL) / (25.0 + 40.0) mL = 0.0462 M [H+] = [HCl] = 0.0462 M pH = -log[H+] = -log0.0462 = 1.33 Solution the diluted concentration of HCl = (0.120 M x 25.0 mL) / (25.0 + 40.0) mL = 0.0462 M [H+] = [HCl] = 0.0462 M pH = -log[H+] = -log0.0462 = 1.33.
the diluted concentration of HCl = (0.120 M x 25..pdf
the diluted concentration of HCl = (0.120 M x 25..pdf
aptex1
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In python,Tkinter is a Graphical user interface package.So,Tkinter tookit for GUI programming supports protocol handler mechanism. Protocol is taking care of how interaction takes place between application and windows manager. self.parent.protocol(\"WM_DELETE_WINDOW\",self.quit_handler) in the above line \"WM_DELETE_WINDOW\" is a protocol.What this protocl does is :it define what is going to happen when a user who uses the application and closes window explicitely using windows manager. Then this protocol \"WM_DELETE_WINDOE\" bypasses to quit_handler(). That quit_handler() asks user \"whether he or she wants to quit or not\" then simply quit the window. Solution In python,Tkinter is a Graphical user interface package.So,Tkinter tookit for GUI programming supports protocol handler mechanism. Protocol is taking care of how interaction takes place between application and windows manager. self.parent.protocol(\"WM_DELETE_WINDOW\",self.quit_handler) in the above line \"WM_DELETE_WINDOW\" is a protocol.What this protocl does is :it define what is going to happen when a user who uses the application and closes window explicitely using windows manager. Then this protocol \"WM_DELETE_WINDOE\" bypasses to quit_handler(). That quit_handler() asks user \"whether he or she wants to quit or not\" then simply quit the window..
Name- Gold leaved white PoplarGenus- Populusspecies- albaAutho.pdf
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aptex1
If I assume you meant supply is determined as [q_(s)=3p^2-4p] and demand is determined as [q_(d)=-p^2+24] then I would calculate that the equilibrium is where [q_(s)=q_(d)] and p>0. So I set up the equation [3p^2-4p=-p^2+24] I add [p^2] to both sides of the equation yielding [4p^2- 4p=24] I subtract 24 from each side, yielding the quadratic equation [4p^2-4p-24=0] I factor the equation [(2p-6)(2p+4)=0] so that means [2p-6=0] or [2p+4=0] In the former case 2p=6 so p=3, and in the latter 2p=-4 so p=-2. The economic nature of the question requires p>0, so [p!=-2] and thus the equilibrium price is $3.00 each. Then to determine the equilibrium quantity, we solve either q expression for p=3. [q_(s)=3(3)^2-4(3)=3(9)-12=27-12=15] [q_(d)=-(3^2)+24=-9+24=15] So the equilibrium quantity is 15 items. The price and quantity for market equilibrium is 15 items at $3.00 each. Solution If I assume you meant supply is determined as [q_(s)=3p^2-4p] and demand is determined as [q_(d)=-p^2+24] then I would calculate that the equilibrium is where [q_(s)=q_(d)] and p>0. So I set up the equation [3p^2-4p=-p^2+24] I add [p^2] to both sides of the equation yielding [4p^2- 4p=24] I subtract 24 from each side, yielding the quadratic equation [4p^2-4p-24=0] I factor the equation [(2p-6)(2p+4)=0] so that means [2p-6=0] or [2p+4=0] In the former case 2p=6 so p=3, and in the latter 2p=-4 so p=-2. The economic nature of the question requires p>0, so [p!=-2] and thus the equilibrium price is $3.00 each. Then to determine the equilibrium quantity, we solve either q expression for p=3. [q_(s)=3(3)^2-4(3)=3(9)-12=27-12=15] [q_(d)=-(3^2)+24=-9+24=15] So the equilibrium quantity is 15 items. The price and quantity for market equilibrium is 15 items at $3.00 each..
MinOfFourNumbers.javaimport java.util.Scanner;public class MinOf.pdf
MinOfFourNumbers.javaimport java.util.Scanner;public class MinOf.pdf
aptex1
If this is not soluble in water, this must be nonpolar, if it si soluble in hexane, this must be nonpolar as well therefore, we are certain this is nonpolar substance with low vap pressure... From the list, nearest BP for that pressure is chloroform with 60ºC (vs 58.) which is ok, since no range is given. CCl4 is nonpolar In order to ensure this, you could use a chromatography with previous data, i.e. use chloroform standard and run chromatography vs. unkown. If they behave the same ( same Rf value, and retention time ) then this is most likely chloroform Solution If this is not soluble in water, this must be nonpolar, if it si soluble in hexane, this must be nonpolar as well therefore, we are certain this is nonpolar substance with low vap pressure... From the list, nearest BP for that pressure is chloroform with 60ºC (vs 58.) which is ok, since no range is given. CCl4 is nonpolar In order to ensure this, you could use a chromatography with previous data, i.e. use chloroform standard and run chromatography vs. unkown. If they behave the same ( same Rf value, and retention time ) then this is most likely chloroform.
molarity = 0.252101.1 =0.001236 M percent =0.251002 =12.5 .pdf
molarity = 0.252101.1 =0.001236 M percent =0.251002 =12.5 .pdf
aptex1
From the graph, we can see that there are three values at which f(x)= 0 These are- x= -6,-2,3 Hence the answer is Option D Solution From the graph, we can see that there are three values at which f(x)= 0 These are- x= -6,-2,3 Hence the answer is Option D.
Initial concentration of Br- = 2.25 x 10e-3M1V1=M2V2therefore M2.pdf
Initial concentration of Br- = 2.25 x 10e-3M1V1=M2V2therefore M2.pdf
aptex1
For a first order reaction rate constant , k = ( 2.303 /t )x log ( a / (a-x)) Where a = initial amount a-x = amount left after time t = a / 10 t = time = ? k = rate constant = 3.43x10 -2 d -2 Plug the values we get t = ( 2.303 /k )x log ( a / (a-x)) = ( 2.303 / 3.43x10 -2 )x log ( a / (a/10)) = 67.14 days Solution For a first order reaction rate constant , k = ( 2.303 /t )x log ( a / (a-x)) Where a = initial amount a-x = amount left after time t = a / 10 t = time = ? k = rate constant = 3.43x10 -2 d -2 Plug the values we get t = ( 2.303 /k )x log ( a / (a-x)) = ( 2.303 / 3.43x10 -2 )x log ( a / (a/10)) = 67.14 days.
import java.util.Scanner;public class HornersPolynomial { .pdf
import java.util.Scanner;public class HornersPolynomial { .pdf
aptex1
approximately all of the propoerty crimes are between 3 standard deviations from the mean mean,u = 3377.2 standard deviation,s = 847.4 u - 3s = 835 u + 3s = 5919.4 OPTION B p(Z Solution approximately all of the propoerty crimes are between 3 standard deviations from the mean mean,u = 3377.2 standard deviation,s = 847.4 u - 3s = 835 u + 3s = 5919.4 OPTION B p(Z.
Direct memory access (DMA) is a function that allows an inputoutput.pdf
Direct memory access (DMA) is a function that allows an inputoutput.pdf
aptex1
b) Security requirements Security requirements are the outputs of the risk management activity. Inputs to the risk management and information security strategy include business strategy, business processes, risk assessments, business input analysis, information resources, and regulatory requirements. Solution b) Security requirements Security requirements are the outputs of the risk management activity. Inputs to the risk management and information security strategy include business strategy, business processes, risk assessments, business input analysis, information resources, and regulatory requirements..
Ethanol is miscible in water because of the hydroxyl functional grou.pdf
Ethanol is miscible in water because of the hydroxyl functional grou.pdf
aptex1
the diluted concentration of HCl = (0.120 M x 25.0 mL) / (25.0 + 40.0) mL = 0.0462 M [H+] = [HCl] = 0.0462 M pH = -log[H+] = -log0.0462 = 1.33 Solution the diluted concentration of HCl = (0.120 M x 25.0 mL) / (25.0 + 40.0) mL = 0.0462 M [H+] = [HCl] = 0.0462 M pH = -log[H+] = -log0.0462 = 1.33.
the diluted concentration of HCl = (0.120 M x 25..pdf
the diluted concentration of HCl = (0.120 M x 25..pdf
aptex1
Simple Nobody Knows The Answer Solution Simple Nobody Knows The Answer.
Simple Nobody Knows The Answer .pdf
Simple Nobody Knows The Answer .pdf
aptex1
a) [21]+[19] = [40] = [4] {since 40 when divided ny 12 leaves a remainder of 4 } b) [37][27] = [ 999] = [9] { Since now the remiander will be 9 when divided by 45} c) [33]([83] - [67]) = [33] [16] = [528] = [28] d) [18] + [8] = [26] = [0]. Hence additive inverse of [18] is [8]. Solution a) [21]+[19] = [40] = [4] {since 40 when divided ny 12 leaves a remainder of 4 } b) [37][27] = [ 999] = [9] { Since now the remiander will be 9 when divided by 45} c) [33]([83] - [67]) = [33] [16] = [528] = [28] d) [18] + [8] = [26] = [0]. Hence additive inverse of [18] is [8]..
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AnswerThe net equation of the reaction catalyzed by the protein c.pdf
aptex1
A Shareholder of a company is holding a share in the assets of the company. A shareholder is also entitled to the profits which company makes by using those assets. As the basic fomat of company distinguishes the Management function from the ownership, People managing the company may or maynot be the owners i.e share holders of the company. Regulators often require the companies to obtain approval of the shareholders via a resolution in the shareholders meeting, thus the deciding power rests with the shareholders. However the extent of powers are contained in the Legislature governing that corporation. Shareholders have right in the assets of the corporation not in the day to day mangement of the corporation. Solution A Shareholder of a company is holding a share in the assets of the company. A shareholder is also entitled to the profits which company makes by using those assets. As the basic fomat of company distinguishes the Management function from the ownership, People managing the company may or maynot be the owners i.e share holders of the company. Regulators often require the companies to obtain approval of the shareholders via a resolution in the shareholders meeting, thus the deciding power rests with the shareholders. However the extent of powers are contained in the Legislature governing that corporation. Shareholders have right in the assets of the corporation not in the day to day mangement of the corporation..
Answer i command.The vi editor always starts in command mode. For.pdf
Answer i command.The vi editor always starts in command mode. For.pdf
aptex1
A chemical formula is an expression indicating the atoms and their number in a particular compound. Each element/atom is identified by its symbol and the number of atoms are given in the subscript. For example, one molecule of water contain 2 atoms of hydrogen and one atom of oxygen: H2O Hope this helps Solution A chemical formula is an expression indicating the atoms and their number in a particular compound. Each element/atom is identified by its symbol and the number of atoms are given in the subscript. For example, one molecule of water contain 2 atoms of hydrogen and one atom of oxygen: H2O Hope this helps.
Answer (b) systems security and control.The businesses are now a .pdf
Answer (b) systems security and control.The businesses are now a .pdf
aptex1
2) b) Understory is rich in humidity hence supports fungi 3) a) canopy includes plant crowns 4) c) herbaceous 5) d) leaf litter/soil Solution 2) b) Understory is rich in humidity hence supports fungi 3) a) canopy includes plant crowns 4) c) herbaceous 5) d) leaf litter/soil.
A. Temeperature of refrigeratorsIntervalB. Horspower of .pdf
A. Temeperature of refrigeratorsIntervalB. Horspower of .pdf
aptex1
1 gallon gasoline = 3.785 L = 3.785 x 803 grams Now, total heat produced = weight(in gms) x heat of combustion = 3.785 x 803 x 48 kJ =145889.04 kJ =145.9 MJ IT IS VERY LARGE NUMBER !!!! Solution 1 gallon gasoline = 3.785 L = 3.785 x 803 grams Now, total heat produced = weight(in gms) x heat of combustion = 3.785 x 803 x 48 kJ =145889.04 kJ =145.9 MJ IT IS VERY LARGE NUMBER !!!!.
48. The answer is Botulism. Botulism ia an illness that brings about.pdf
48. The answer is Botulism. Botulism ia an illness that brings about.pdf
aptex1
(A) The answer is b. increases Electricity in the form of electrons are transported through the solution by charged ions of the electrolyte. As the electrolyte concentration increases, so does the number of charge carriers and hence the amount of charge and electricity conducted increases. (B) Acetic acid (CH3COOH) is a weak acid and partially ionizes in water: CH3COOH + H2O => CH3COO- + H3O+ The charged acetate (CH3COO- ) and hydroxonium (H3O+) ions are responsible for electrical conductivity. In 6 M acetic acid, water is in excess and and the ionization proceeds as shown above to give an electrolyte solution with charged ions that conduct electricity. In glacial acetic acid, there is very little water present and ionization is negliglble. Almost all the acetic acid remains in the non-conducting molecular form (CH3COOH) and there are no charged ions present. Thus glacial acetic acid does not conduct electricity. Solution (A) The answer is b. increases Electricity in the form of electrons are transported through the solution by charged ions of the electrolyte. As the electrolyte concentration increases, so does the number of charge carriers and hence the amount of charge and electricity conducted increases. (B) Acetic acid (CH3COOH) is a weak acid and partially ionizes in water: CH3COOH + H2O => CH3COO- + H3O+ The charged acetate (CH3COO- ) and hydroxonium (H3O+) ions are responsible for electrical conductivity. In 6 M acetic acid, water is in excess and and the ionization proceeds as shown above to give an electrolyte solution with charged ions that conduct electricity. In glacial acetic acid, there is very little water present and ionization is negliglble. Almost all the acetic acid remains in the non-conducting molecular form (CH3COOH) and there are no charged ions present. Thus glacial acetic acid does not conduct electricity..
2) b) Understory is rich in humidity hence supports fungi3) a) can.pdf
2) b) Understory is rich in humidity hence supports fungi3) a) can.pdf
aptex1
#include #include #include int check(char*); int k=0; char a[100]; void shift(int,int); int main() { int i,j=0,l=0,m,p,z; do { if(j) cout<<\"Enter the string\"; fgets(a,100,stdin); j=check(a); } while(j); for(i=0;i0 && m!=2;j--) { m=2; if(a[j]==\'+\'||a[j]==\'-\'||a[j]==\'*\'||a[j]==\'/\') l++; } if(m==2) { for(m=j-2,p=1,z=1;z!=2&&m>0;m--) { if(p==1) if(a[m]==\'(\') p=2; if(p==2) { if(a[m]==\'(\'&&(a[m-1]==\'+\' ||a[m-1]==\'-\' ||a[m-1]==\'*\'||a[m-1]==\'/\')) { m--; z=2; } } } j=m; } if(j<0) j=0; else j=j+2; shift(l,j); a[j]=\'(\'; k--; i++; } } if(k) cout<<\"Your putput is\"<<\"\ \"; cout<=0;i--) { if(a[i]==\')\') k++; if(a[i]==\'(\') return 1; } Output: Enter the string 1+2)*3-4)5-6))) Your output is ((1+2)*((3-4)*(5-6)) Solution #include #include #include int check(char*); int k=0; char a[100]; void shift(int,int); int main() { int i,j=0,l=0,m,p,z; do { if(j) cout<<\"Enter the string\"; fgets(a,100,stdin); j=check(a); } while(j); for(i=0;i0 && m!=2;j--) { m=2; if(a[j]==\'+\'||a[j]==\'-\'||a[j]==\'*\'||a[j]==\'/\') l++; } if(m==2) { for(m=j-2,p=1,z=1;z!=2&&m>0;m--) { if(p==1) if(a[m]==\'(\') p=2; if(p==2) { if(a[m]==\'(\'&&(a[m-1]==\'+\' ||a[m-1]==\'-\' ||a[m-1]==\'*\'||a[m-1]==\'/\')) { m--; z=2; } } } j=m; } if(j<0) j=0; else j=j+2; shift(l,j); a[j]=\'(\'; k--; i++; } } if(k) cout<<\"Your putput is\"<<\"\ \"; cout<=0;i--) { if(a[i]==\')\') k++; if(a[i]==\'(\') return 1; } Output: Enter the string 1+2)*3-4)5-6))) Your output is ((1+2)*((3-4)*(5-6)).
1.Discuss in detail Emile Durkheim and his contributions to the fiel.pdf
1.Discuss in detail Emile Durkheim and his contributions to the fiel.pdf
aptex1
#include #include #define TRUE 1 /* Put your lab 4 functions prototypes here, as well as the prototype for lab 5 */ double mag(double ax, double ay, double az); int close_to (double tolerance, double point, double value); int clearAll (int *a, int *b, int *c, int *d, int *e, int *f); int main(void) { int t, b1, b2, b3, b4, b5, s; double ax, ay, az; double tolerance = 0.25, point = 1.0, value; int a,b,c,d,e,f; while (TRUE && b2 != 1 && ( mag ( ax, ay, az)-1<(tolerance*3))) { scanf(\"%d, %lf, %lf, %lf, %d, %d, %d, %d, %d, %d\", &t, &ax, &ay, &az, &b1, &b2, &b3, &b4, &b5, &s ); if(close_to(tolerance, point, ax)==1 && a != 1){ printf(\"RIGHT\ \ \"); clearAll ( &a, &b, &c, &d, &e, &f); a = 1; fflush(stdout); } if(close_to(tolerance, point, ay)==1 && b != 1){ printf(\"FRONT\ \ \"); fflush(stdout); clearAll ( &a, &b, &c, &d, &e, &f); b = 1; } if(close_to(tolerance, point, az)==1 && c != 1){ printf(\"TOP\ \ \"); fflush(stdout); clearAll ( &a, &b, &c, &d, &e, &f); c = 1; } if(close_to(tolerance, point, ax)==2 && d != 1){ printf(\"LEFT\ \ \"); fflush(stdout); clearAll ( &a, &b, &c, &d, &e, &f); d = 1; } if(close_to(tolerance, point, ay)==2 && e != 1){ printf(\"BACK\ \ \"); fflush(stdout); clearAll ( &a, &b, &c, &d, &e, &f); e = 1; } if(close_to(tolerance, point, az)==2 && f != 1){ printf(\"BOTTOM\ \ \"); fflush(stdout); clearAll ( &a, &b, &c, &d, &e, &f); f = 1; } return 0; } } /* Put your lab 4 functions here, as well as your new function close_to */ double mag(double ax, double ay, double az){ double y = sqrt(ax*ax + ay*ay + az*az); return y; } int close_to (double tolerance, double point, double value){ if (value>0){ if (sqrt((value-point)*(value-point))<(tolerance)){ return 1; } else{ return 0; } } else{ if(sqrt((value+point)*(value+point))<(tolerance)) //? it used to not have sqrt return 2; } } int clearAll (int *a, int *b, int *c, int *d, int *e, int *f){ *a = *b = *c = *d = *e = *f = 0; } Solution #include #include #define TRUE 1 /* Put your lab 4 functions prototypes here, as well as the prototype for lab 5 */ double mag(double ax, double ay, double az); int close_to (double tolerance, double point, double value); int clearAll (int *a, int *b, int *c, int *d, int *e, int *f); int main(void) { int t, b1, b2, b3, b4, b5, s; double ax, ay, az; double tolerance = 0.25, point = 1.0, value; int a,b,c,d,e,f; while (TRUE && b2 != 1 && ( mag ( ax, ay, az)-1<(tolerance*3))) { scanf(\"%d, %lf, %lf, %lf, %d, %d, %d, %d, %d, %d\", &t, &ax, &ay, &az, &b1, &b2, &b3, &b4, &b5, &s ); if(close_to(tolerance, point, ax)==1 && a != 1){ printf(\"RIGHT\ \ \"); clearAll ( &a, &b, &c, &d, &e, &f); a = 1; fflush(stdout); } if(close_to(tolerance, point, ay)==1 && b != 1){ printf(\"FRONT\ \ \"); fflush(stdout); clearAll ( &a, &b, &c, &d, &e, &f); b = 1; } if(close_to(tolerance, point, az)==1 && c != 1){ printf(\"TOP\ \ \"); fflush(stdout); clearAll ( &a, &b, &c, &d, &e, &f); c = 1; } if(close_to(tolerance, point, ax)==2 && d != 1){ printf(\"LEFT\ \ \"); fflush(stdout); cl.
1) YELLOW FEVERGroup Group IV ((+) ssRNA)Order Unassigned.pdf
1) YELLOW FEVERGroup Group IV ((+) ssRNA)Order Unassigned.pdf
aptex1
Thermodynamic entropy is a non-conserved state function that is of great importance in the sciences of physics and chemistry. Historically, the concept of entropy evolved in order to explain why some processes (permitted by conservation laws) occur spontaneously while their time reversals (also permitted by conservation laws) do not; systems tend to progress in the direction of increasing entropy. For isolated systems, entropy never decreases. This fact has several important consequences in science: first, it prohibits \"perpetual motion\" machines; and second, it implies the arrow of entropy has the same directionality as the arrow of time. Increases in entropy correspond to irreversible changes in a system, because some energy is expended as waste heat, limiting the amount of work a system can do. In statistical mechanics, entropy is a measure of the number of ways in which a system may be arranged, often taken to be a measure of \"disorder\" (the higher the entropy, the higher the disorder). This definition describes the entropy as being proportional to the natural logarithm of the number of possible microscopic configurations of the individual atoms and molecules of the system (microstates) which could give rise to the observed macroscopic state (macrostate) of the system. The constant of proportionality is the Boltzmann constant. - Wiki Solution Thermodynamic entropy is a non-conserved state function that is of great importance in the sciences of physics and chemistry. Historically, the concept of entropy evolved in order to explain why some processes (permitted by conservation laws) occur spontaneously while their time reversals (also permitted by conservation laws) do not; systems tend to progress in the direction of increasing entropy. For isolated systems, entropy never decreases. This fact has several important consequences in science: first, it prohibits \"perpetual motion\" machines; and second, it implies the arrow of entropy has the same directionality as the arrow of time. Increases in entropy correspond to irreversible changes in a system, because some energy is expended as waste heat, limiting the amount of work a system can do. In statistical mechanics, entropy is a measure of the number of ways in which a system may be arranged, often taken to be a measure of \"disorder\" (the higher the entropy, the higher the disorder). This definition describes the entropy as being proportional to the natural logarithm of the number of possible microscopic configurations of the individual atoms and molecules of the system (microstates) which could give rise to the observed macroscopic state (macrostate) of the system. The constant of proportionality is the Boltzmann constant. - Wiki.
Thermodynamic entropy is a non-conserved state fu.pdf
Thermodynamic entropy is a non-conserved state fu.pdf
aptex1
I is oxidized by 6 electrons as the oxidation state of I in I- is -1 while in IO3- is +5. Solution I is oxidized by 6 electrons as the oxidation state of I in I- is -1 while in IO3- is +5..
I is oxidized by 6 electrons as the oxidation sta.pdf
I is oxidized by 6 electrons as the oxidation sta.pdf
aptex1
The main difference is that Democritus was not a scientist he was a philosopher as such he only theorized that matter could not be indefinitely divided, that there is a limit (now know to be the atom). Dalton on the other had based his theory of atoms on scientific experimentation and observation. Demeocritus used reason vs. Dalton used scientific method Solution The main difference is that Democritus was not a scientist he was a philosopher as such he only theorized that matter could not be indefinitely divided, that there is a limit (now know to be the atom). Dalton on the other had based his theory of atoms on scientific experimentation and observation. Demeocritus used reason vs. Dalton used scientific method.
The main difference is that Democritus was not a .pdf
The main difference is that Democritus was not a .pdf
aptex1
for acidic nature is should give H+ equation : HSO3- -----> H+ + SO3^2- ANSWER Solution for acidic nature is should give H+ equation : HSO3- -----> H+ + SO3^2- ANSWER.
for acidic nature is should give H+ equation H.pdf
for acidic nature is should give H+ equation H.pdf
aptex1
both are in opposite direction i.e., magnetic north is in geographical south Solution both are in opposite direction i.e., magnetic north is in geographical south.
both are in opposite direction i.e., magnetic nor.pdf
both are in opposite direction i.e., magnetic nor.pdf
aptex1
B) Decrease the energy of activation. C) Change the path of the reaction. D) Increase the collision frequency. Solution B) Decrease the energy of activation. C) Change the path of the reaction. D) Increase the collision frequency..
B) Decrease the energy of activation. C) Change .pdf
B) Decrease the energy of activation. C) Change .pdf
aptex1
A. So before we can come up with the chemical equation, we firsthave to understand the components of the salt we are to dissolve.What does it break into? What are the charges of each component ofthe salt, and their individual chemical formulas? So first we lookat the name \"strontium iodate\" so we know that it breaks intostrontium with some charge in water and iodate. Strontium Iodate --> some Strontium + some Iodate (in water) Now for the second question, what are the charges and the chemicalformula of each part? So for strontium, we know that it is analkaline earth metal (or in group II), so we know that like Ca orMg, Sr is most likely to hold a charge of 2+. So we\'ll say that wehave a Sr2+ in solution. How about iodate? By otherremembering or looking it up we find that it isIO3-. So how would we pair these in a salt? Since we know that Sr has a2+ charge and iodate has a 1- charge, we know that to balance atotal charge of 0, we need 2 iodates per Sr making: Sr(IO3)2 as the salt dissolving in solution.This clearly then breaks into 1 Sr2+ and 2IO3- in water. B. Now that we know the reaction, how do the two speciesconcentrations relate to themselves in solution? Well we alreadyanswered this question. By saying that we need to pair 2 iodatesfor each Sr cation, we know that iodate concentration must bedouble that of the Sr cation in water. Cheers. Solution A. So before we can come up with the chemical equation, we firsthave to understand the components of the salt we are to dissolve.What does it break into? What are the charges of each component ofthe salt, and their individual chemical formulas? So first we lookat the name \"strontium iodate\" so we know that it breaks intostrontium with some charge in water and iodate. Strontium Iodate --> some Strontium + some Iodate (in water) Now for the second question, what are the charges and the chemicalformula of each part? So for strontium, we know that it is analkaline earth metal (or in group II), so we know that like Ca orMg, Sr is most likely to hold a charge of 2+. So we\'ll say that wehave a Sr2+ in solution. How about iodate? By otherremembering or looking it up we find that it isIO3-. So how would we pair these in a salt? Since we know that Sr has a2+ charge and iodate has a 1- charge, we know that to balance atotal charge of 0, we need 2 iodates per Sr making: Sr(IO3)2 as the salt dissolving in solution.This clearly then breaks into 1 Sr2+ and 2IO3- in water. B. Now that we know the reaction, how do the two speciesconcentrations relate to themselves in solution? Well we alreadyanswered this question. By saying that we need to pair 2 iodatesfor each Sr cation, we know that iodate concentration must bedouble that of the Sr cation in water. Cheers..
A. So before we can come up with the chemical equ.pdf
A. So before we can come up with the chemical equ.pdf
aptex1
A) 1 and 3 are meso isomers. B) 2 and 4 are not identical as 2 is R,R and 4 is S,S C) They are all not identical D) 1 and 2 are not enantiomers, thery are diasteriomers. Solution A) 1 and 3 are meso isomers. B) 2 and 4 are not identical as 2 is R,R and 4 is S,S C) They are all not identical D) 1 and 2 are not enantiomers, thery are diasteriomers..
A) 1 and 3 are meso isomers. B) 2 and 4 are not i.pdf
A) 1 and 3 are meso isomers. B) 2 and 4 are not i.pdf
aptex1
This presentation is from the Paper 206: The African Literature, Unit 4 - Poems and I choose the topic The Significance of Rituals in Shaping 'A Dance of the Forests’.
Sensory_Experience_and_Emotional_Resonance_in_Gabriel_Okaras_The_Piano_and_Th...
Sensory_Experience_and_Emotional_Resonance_in_Gabriel_Okaras_The_Piano_and_Th...
Pooja Bhuva
FSB Advising Checklist
FSB Advising Checklist - Orientation 2024
FSB Advising Checklist - Orientation 2024
Elizabeth Walsh
This presentation is from the Paper 207: Contemporary Literature in English, Unit 1: Amitav Ghosh’s Gun Island (2019) and I choose the topic Exploring Existential Depths: Susan Macleod's Journey and the Philosophical Realm.
Exploring_the_Narrative_Style_of_Amitav_Ghoshs_Gun_Island.pptx
Exploring_the_Narrative_Style_of_Amitav_Ghoshs_Gun_Island.pptx
Pooja Bhuva
Here is the slideshow presentation from the HMCS Vancouver Pre-Deployment Brief on May 9th, 2024.
HMCS Vancouver Pre-Deployment Brief - May 2024 (Web Version).pptx
HMCS Vancouver Pre-Deployment Brief - May 2024 (Web Version).pptx
marlenawright1
This presentation covers the essential parameters of Unit 2 Operations Processes of the subject Operations & Supply Chain Management. Topics Covered: Volume Variety and Flow. Types of Processes and Operations Systems - Continuous Flow system and intermittent flow systems.Job Production, Batch Production, Assembly line and Continuous Flow, Process and Product Layout. Design of Service Systems, Service Blueprinting.
OSCM Unit 2_Operations Processes & Systems
OSCM Unit 2_Operations Processes & Systems
Sandeep D Chaudhary
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a) [21]+[19] = [40] = [4] {since 40 when divided ny 12 leaves a remainder of 4 } b) [37][27] = [ 999] = [9] { Since now the remiander will be 9 when divided by 45} c) [33]([83] - [67]) = [33] [16] = [528] = [28] d) [18] + [8] = [26] = [0]. Hence additive inverse of [18] is [8]. Solution a) [21]+[19] = [40] = [4] {since 40 when divided ny 12 leaves a remainder of 4 } b) [37][27] = [ 999] = [9] { Since now the remiander will be 9 when divided by 45} c) [33]([83] - [67]) = [33] [16] = [528] = [28] d) [18] + [8] = [26] = [0]. Hence additive inverse of [18] is [8]..
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A Shareholder of a company is holding a share in the assets of the company. A shareholder is also entitled to the profits which company makes by using those assets. As the basic fomat of company distinguishes the Management function from the ownership, People managing the company may or maynot be the owners i.e share holders of the company. Regulators often require the companies to obtain approval of the shareholders via a resolution in the shareholders meeting, thus the deciding power rests with the shareholders. However the extent of powers are contained in the Legislature governing that corporation. Shareholders have right in the assets of the corporation not in the day to day mangement of the corporation. Solution A Shareholder of a company is holding a share in the assets of the company. A shareholder is also entitled to the profits which company makes by using those assets. As the basic fomat of company distinguishes the Management function from the ownership, People managing the company may or maynot be the owners i.e share holders of the company. Regulators often require the companies to obtain approval of the shareholders via a resolution in the shareholders meeting, thus the deciding power rests with the shareholders. However the extent of powers are contained in the Legislature governing that corporation. Shareholders have right in the assets of the corporation not in the day to day mangement of the corporation..
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A chemical formula is an expression indicating the atoms and their number in a particular compound. Each element/atom is identified by its symbol and the number of atoms are given in the subscript. For example, one molecule of water contain 2 atoms of hydrogen and one atom of oxygen: H2O Hope this helps Solution A chemical formula is an expression indicating the atoms and their number in a particular compound. Each element/atom is identified by its symbol and the number of atoms are given in the subscript. For example, one molecule of water contain 2 atoms of hydrogen and one atom of oxygen: H2O Hope this helps.
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1 gallon gasoline = 3.785 L = 3.785 x 803 grams Now, total heat produced = weight(in gms) x heat of combustion = 3.785 x 803 x 48 kJ =145889.04 kJ =145.9 MJ IT IS VERY LARGE NUMBER !!!! Solution 1 gallon gasoline = 3.785 L = 3.785 x 803 grams Now, total heat produced = weight(in gms) x heat of combustion = 3.785 x 803 x 48 kJ =145889.04 kJ =145.9 MJ IT IS VERY LARGE NUMBER !!!!.
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aptex1
(A) The answer is b. increases Electricity in the form of electrons are transported through the solution by charged ions of the electrolyte. As the electrolyte concentration increases, so does the number of charge carriers and hence the amount of charge and electricity conducted increases. (B) Acetic acid (CH3COOH) is a weak acid and partially ionizes in water: CH3COOH + H2O => CH3COO- + H3O+ The charged acetate (CH3COO- ) and hydroxonium (H3O+) ions are responsible for electrical conductivity. In 6 M acetic acid, water is in excess and and the ionization proceeds as shown above to give an electrolyte solution with charged ions that conduct electricity. In glacial acetic acid, there is very little water present and ionization is negliglble. Almost all the acetic acid remains in the non-conducting molecular form (CH3COOH) and there are no charged ions present. Thus glacial acetic acid does not conduct electricity. Solution (A) The answer is b. increases Electricity in the form of electrons are transported through the solution by charged ions of the electrolyte. As the electrolyte concentration increases, so does the number of charge carriers and hence the amount of charge and electricity conducted increases. (B) Acetic acid (CH3COOH) is a weak acid and partially ionizes in water: CH3COOH + H2O => CH3COO- + H3O+ The charged acetate (CH3COO- ) and hydroxonium (H3O+) ions are responsible for electrical conductivity. In 6 M acetic acid, water is in excess and and the ionization proceeds as shown above to give an electrolyte solution with charged ions that conduct electricity. In glacial acetic acid, there is very little water present and ionization is negliglble. Almost all the acetic acid remains in the non-conducting molecular form (CH3COOH) and there are no charged ions present. Thus glacial acetic acid does not conduct electricity..
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aptex1
#include #include #include int check(char*); int k=0; char a[100]; void shift(int,int); int main() { int i,j=0,l=0,m,p,z; do { if(j) cout<<\"Enter the string\"; fgets(a,100,stdin); j=check(a); } while(j); for(i=0;i0 && m!=2;j--) { m=2; if(a[j]==\'+\'||a[j]==\'-\'||a[j]==\'*\'||a[j]==\'/\') l++; } if(m==2) { for(m=j-2,p=1,z=1;z!=2&&m>0;m--) { if(p==1) if(a[m]==\'(\') p=2; if(p==2) { if(a[m]==\'(\'&&(a[m-1]==\'+\' ||a[m-1]==\'-\' ||a[m-1]==\'*\'||a[m-1]==\'/\')) { m--; z=2; } } } j=m; } if(j<0) j=0; else j=j+2; shift(l,j); a[j]=\'(\'; k--; i++; } } if(k) cout<<\"Your putput is\"<<\"\ \"; cout<=0;i--) { if(a[i]==\')\') k++; if(a[i]==\'(\') return 1; } Output: Enter the string 1+2)*3-4)5-6))) Your output is ((1+2)*((3-4)*(5-6)) Solution #include #include #include int check(char*); int k=0; char a[100]; void shift(int,int); int main() { int i,j=0,l=0,m,p,z; do { if(j) cout<<\"Enter the string\"; fgets(a,100,stdin); j=check(a); } while(j); for(i=0;i0 && m!=2;j--) { m=2; if(a[j]==\'+\'||a[j]==\'-\'||a[j]==\'*\'||a[j]==\'/\') l++; } if(m==2) { for(m=j-2,p=1,z=1;z!=2&&m>0;m--) { if(p==1) if(a[m]==\'(\') p=2; if(p==2) { if(a[m]==\'(\'&&(a[m-1]==\'+\' ||a[m-1]==\'-\' ||a[m-1]==\'*\'||a[m-1]==\'/\')) { m--; z=2; } } } j=m; } if(j<0) j=0; else j=j+2; shift(l,j); a[j]=\'(\'; k--; i++; } } if(k) cout<<\"Your putput is\"<<\"\ \"; cout<=0;i--) { if(a[i]==\')\') k++; if(a[i]==\'(\') return 1; } Output: Enter the string 1+2)*3-4)5-6))) Your output is ((1+2)*((3-4)*(5-6)).
1.Discuss in detail Emile Durkheim and his contributions to the fiel.pdf
1.Discuss in detail Emile Durkheim and his contributions to the fiel.pdf
aptex1
#include #include #define TRUE 1 /* Put your lab 4 functions prototypes here, as well as the prototype for lab 5 */ double mag(double ax, double ay, double az); int close_to (double tolerance, double point, double value); int clearAll (int *a, int *b, int *c, int *d, int *e, int *f); int main(void) { int t, b1, b2, b3, b4, b5, s; double ax, ay, az; double tolerance = 0.25, point = 1.0, value; int a,b,c,d,e,f; while (TRUE && b2 != 1 && ( mag ( ax, ay, az)-1<(tolerance*3))) { scanf(\"%d, %lf, %lf, %lf, %d, %d, %d, %d, %d, %d\", &t, &ax, &ay, &az, &b1, &b2, &b3, &b4, &b5, &s ); if(close_to(tolerance, point, ax)==1 && a != 1){ printf(\"RIGHT\ \ \"); clearAll ( &a, &b, &c, &d, &e, &f); a = 1; fflush(stdout); } if(close_to(tolerance, point, ay)==1 && b != 1){ printf(\"FRONT\ \ \"); fflush(stdout); clearAll ( &a, &b, &c, &d, &e, &f); b = 1; } if(close_to(tolerance, point, az)==1 && c != 1){ printf(\"TOP\ \ \"); fflush(stdout); clearAll ( &a, &b, &c, &d, &e, &f); c = 1; } if(close_to(tolerance, point, ax)==2 && d != 1){ printf(\"LEFT\ \ \"); fflush(stdout); clearAll ( &a, &b, &c, &d, &e, &f); d = 1; } if(close_to(tolerance, point, ay)==2 && e != 1){ printf(\"BACK\ \ \"); fflush(stdout); clearAll ( &a, &b, &c, &d, &e, &f); e = 1; } if(close_to(tolerance, point, az)==2 && f != 1){ printf(\"BOTTOM\ \ \"); fflush(stdout); clearAll ( &a, &b, &c, &d, &e, &f); f = 1; } return 0; } } /* Put your lab 4 functions here, as well as your new function close_to */ double mag(double ax, double ay, double az){ double y = sqrt(ax*ax + ay*ay + az*az); return y; } int close_to (double tolerance, double point, double value){ if (value>0){ if (sqrt((value-point)*(value-point))<(tolerance)){ return 1; } else{ return 0; } } else{ if(sqrt((value+point)*(value+point))<(tolerance)) //? it used to not have sqrt return 2; } } int clearAll (int *a, int *b, int *c, int *d, int *e, int *f){ *a = *b = *c = *d = *e = *f = 0; } Solution #include #include #define TRUE 1 /* Put your lab 4 functions prototypes here, as well as the prototype for lab 5 */ double mag(double ax, double ay, double az); int close_to (double tolerance, double point, double value); int clearAll (int *a, int *b, int *c, int *d, int *e, int *f); int main(void) { int t, b1, b2, b3, b4, b5, s; double ax, ay, az; double tolerance = 0.25, point = 1.0, value; int a,b,c,d,e,f; while (TRUE && b2 != 1 && ( mag ( ax, ay, az)-1<(tolerance*3))) { scanf(\"%d, %lf, %lf, %lf, %d, %d, %d, %d, %d, %d\", &t, &ax, &ay, &az, &b1, &b2, &b3, &b4, &b5, &s ); if(close_to(tolerance, point, ax)==1 && a != 1){ printf(\"RIGHT\ \ \"); clearAll ( &a, &b, &c, &d, &e, &f); a = 1; fflush(stdout); } if(close_to(tolerance, point, ay)==1 && b != 1){ printf(\"FRONT\ \ \"); fflush(stdout); clearAll ( &a, &b, &c, &d, &e, &f); b = 1; } if(close_to(tolerance, point, az)==1 && c != 1){ printf(\"TOP\ \ \"); fflush(stdout); clearAll ( &a, &b, &c, &d, &e, &f); c = 1; } if(close_to(tolerance, point, ax)==2 && d != 1){ printf(\"LEFT\ \ \"); fflush(stdout); cl.
1) YELLOW FEVERGroup Group IV ((+) ssRNA)Order Unassigned.pdf
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aptex1
Thermodynamic entropy is a non-conserved state function that is of great importance in the sciences of physics and chemistry. Historically, the concept of entropy evolved in order to explain why some processes (permitted by conservation laws) occur spontaneously while their time reversals (also permitted by conservation laws) do not; systems tend to progress in the direction of increasing entropy. For isolated systems, entropy never decreases. This fact has several important consequences in science: first, it prohibits \"perpetual motion\" machines; and second, it implies the arrow of entropy has the same directionality as the arrow of time. Increases in entropy correspond to irreversible changes in a system, because some energy is expended as waste heat, limiting the amount of work a system can do. In statistical mechanics, entropy is a measure of the number of ways in which a system may be arranged, often taken to be a measure of \"disorder\" (the higher the entropy, the higher the disorder). This definition describes the entropy as being proportional to the natural logarithm of the number of possible microscopic configurations of the individual atoms and molecules of the system (microstates) which could give rise to the observed macroscopic state (macrostate) of the system. The constant of proportionality is the Boltzmann constant. - Wiki Solution Thermodynamic entropy is a non-conserved state function that is of great importance in the sciences of physics and chemistry. Historically, the concept of entropy evolved in order to explain why some processes (permitted by conservation laws) occur spontaneously while their time reversals (also permitted by conservation laws) do not; systems tend to progress in the direction of increasing entropy. For isolated systems, entropy never decreases. This fact has several important consequences in science: first, it prohibits \"perpetual motion\" machines; and second, it implies the arrow of entropy has the same directionality as the arrow of time. Increases in entropy correspond to irreversible changes in a system, because some energy is expended as waste heat, limiting the amount of work a system can do. In statistical mechanics, entropy is a measure of the number of ways in which a system may be arranged, often taken to be a measure of \"disorder\" (the higher the entropy, the higher the disorder). This definition describes the entropy as being proportional to the natural logarithm of the number of possible microscopic configurations of the individual atoms and molecules of the system (microstates) which could give rise to the observed macroscopic state (macrostate) of the system. The constant of proportionality is the Boltzmann constant. - Wiki.
Thermodynamic entropy is a non-conserved state fu.pdf
Thermodynamic entropy is a non-conserved state fu.pdf
aptex1
I is oxidized by 6 electrons as the oxidation state of I in I- is -1 while in IO3- is +5. Solution I is oxidized by 6 electrons as the oxidation state of I in I- is -1 while in IO3- is +5..
I is oxidized by 6 electrons as the oxidation sta.pdf
I is oxidized by 6 electrons as the oxidation sta.pdf
aptex1
The main difference is that Democritus was not a scientist he was a philosopher as such he only theorized that matter could not be indefinitely divided, that there is a limit (now know to be the atom). Dalton on the other had based his theory of atoms on scientific experimentation and observation. Demeocritus used reason vs. Dalton used scientific method Solution The main difference is that Democritus was not a scientist he was a philosopher as such he only theorized that matter could not be indefinitely divided, that there is a limit (now know to be the atom). Dalton on the other had based his theory of atoms on scientific experimentation and observation. Demeocritus used reason vs. Dalton used scientific method.
The main difference is that Democritus was not a .pdf
The main difference is that Democritus was not a .pdf
aptex1
for acidic nature is should give H+ equation : HSO3- -----> H+ + SO3^2- ANSWER Solution for acidic nature is should give H+ equation : HSO3- -----> H+ + SO3^2- ANSWER.
for acidic nature is should give H+ equation H.pdf
for acidic nature is should give H+ equation H.pdf
aptex1
both are in opposite direction i.e., magnetic north is in geographical south Solution both are in opposite direction i.e., magnetic north is in geographical south.
both are in opposite direction i.e., magnetic nor.pdf
both are in opposite direction i.e., magnetic nor.pdf
aptex1
B) Decrease the energy of activation. C) Change the path of the reaction. D) Increase the collision frequency. Solution B) Decrease the energy of activation. C) Change the path of the reaction. D) Increase the collision frequency..
B) Decrease the energy of activation. C) Change .pdf
B) Decrease the energy of activation. C) Change .pdf
aptex1
A. So before we can come up with the chemical equation, we firsthave to understand the components of the salt we are to dissolve.What does it break into? What are the charges of each component ofthe salt, and their individual chemical formulas? So first we lookat the name \"strontium iodate\" so we know that it breaks intostrontium with some charge in water and iodate. Strontium Iodate --> some Strontium + some Iodate (in water) Now for the second question, what are the charges and the chemicalformula of each part? So for strontium, we know that it is analkaline earth metal (or in group II), so we know that like Ca orMg, Sr is most likely to hold a charge of 2+. So we\'ll say that wehave a Sr2+ in solution. How about iodate? By otherremembering or looking it up we find that it isIO3-. So how would we pair these in a salt? Since we know that Sr has a2+ charge and iodate has a 1- charge, we know that to balance atotal charge of 0, we need 2 iodates per Sr making: Sr(IO3)2 as the salt dissolving in solution.This clearly then breaks into 1 Sr2+ and 2IO3- in water. B. Now that we know the reaction, how do the two speciesconcentrations relate to themselves in solution? Well we alreadyanswered this question. By saying that we need to pair 2 iodatesfor each Sr cation, we know that iodate concentration must bedouble that of the Sr cation in water. Cheers. Solution A. So before we can come up with the chemical equation, we firsthave to understand the components of the salt we are to dissolve.What does it break into? What are the charges of each component ofthe salt, and their individual chemical formulas? So first we lookat the name \"strontium iodate\" so we know that it breaks intostrontium with some charge in water and iodate. Strontium Iodate --> some Strontium + some Iodate (in water) Now for the second question, what are the charges and the chemicalformula of each part? So for strontium, we know that it is analkaline earth metal (or in group II), so we know that like Ca orMg, Sr is most likely to hold a charge of 2+. So we\'ll say that wehave a Sr2+ in solution. How about iodate? By otherremembering or looking it up we find that it isIO3-. So how would we pair these in a salt? Since we know that Sr has a2+ charge and iodate has a 1- charge, we know that to balance atotal charge of 0, we need 2 iodates per Sr making: Sr(IO3)2 as the salt dissolving in solution.This clearly then breaks into 1 Sr2+ and 2IO3- in water. B. Now that we know the reaction, how do the two speciesconcentrations relate to themselves in solution? Well we alreadyanswered this question. By saying that we need to pair 2 iodatesfor each Sr cation, we know that iodate concentration must bedouble that of the Sr cation in water. Cheers..
A. So before we can come up with the chemical equ.pdf
A. So before we can come up with the chemical equ.pdf
aptex1
A) 1 and 3 are meso isomers. B) 2 and 4 are not identical as 2 is R,R and 4 is S,S C) They are all not identical D) 1 and 2 are not enantiomers, thery are diasteriomers. Solution A) 1 and 3 are meso isomers. B) 2 and 4 are not identical as 2 is R,R and 4 is S,S C) They are all not identical D) 1 and 2 are not enantiomers, thery are diasteriomers..
A) 1 and 3 are meso isomers. B) 2 and 4 are not i.pdf
A) 1 and 3 are meso isomers. B) 2 and 4 are not i.pdf
aptex1
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