A. So before we can come up with the chemical equation, we firsthave to
understand the components of the salt we are to dissolve.What does it break into? What are the
charges of each component ofthe salt, and their individual chemical formulas? So first we lookat
the name \"strontium iodate\" so we know that it breaks intostrontium with some charge in water
and iodate. Strontium Iodate --> some Strontium + some Iodate (in water) Now for the second
question, what are the charges and the chemicalformula of each part? So for strontium, we know
that it is analkaline earth metal (or in group II), so we know that like Ca orMg, Sr is most likely
to hold a charge of 2+. So we\'ll say that wehave a Sr2+ in solution. How about iodate? By
otherremembering or looking it up we find that it isIO3-. So how would we pair these in a salt?
Since we know that Sr has a2+ charge and iodate has a 1- charge, we know that to balance atotal
charge of 0, we need 2 iodates per Sr making: Sr(IO3)2 as the salt dissolving in solution.This
clearly then breaks into 1 Sr2+ and 2IO3- in water. B. Now that we know the reaction, how do
the two speciesconcentrations relate to themselves in solution? Well we alreadyanswered this
question. By saying that we need to pair 2 iodatesfor each Sr cation, we know that iodate
concentration must bedouble that of the Sr cation in water. Cheers.
Solution
A. So before we can come up with the chemical equation, we firsthave to
understand the components of the salt we are to dissolve.What does it break into? What are the
charges of each component ofthe salt, and their individual chemical formulas? So first we lookat
the name \"strontium iodate\" so we know that it breaks intostrontium with some charge in water
and iodate. Strontium Iodate --> some Strontium + some Iodate (in water) Now for the second
question, what are the charges and the chemicalformula of each part? So for strontium, we know
that it is analkaline earth metal (or in group II), so we know that like Ca orMg, Sr is most likely
to hold a charge of 2+. So we\'ll say that wehave a Sr2+ in solution. How about iodate? By
otherremembering or looking it up we find that it isIO3-. So how would we pair these in a salt?
Since we know that Sr has a2+ charge and iodate has a 1- charge, we know that to balance atotal
charge of 0, we need 2 iodates per Sr making: Sr(IO3)2 as the salt dissolving in solution.This
clearly then breaks into 1 Sr2+ and 2IO3- in water. B. Now that we know the reaction, how do
the two speciesconcentrations relate to themselves in solution? Well we alreadyanswered this
question. By saying that we need to pair 2 iodatesfor each Sr cation, we know that iodate
concentration must bedouble that of the Sr cation in water. Cheers..
The elements in period 6 are those starting with Cs and going acr.pdfannamalassociates
The elements in period 6 are those starting with Cs and going across. Given that the metal reacts
vigorously with water, it must be either from groups 1 or 2 (alkali metals and alkali earth
metals). If you\'ve seen the reaction (or heard about it) between sodium and water (hydrogen is
produced rapidly and enough heat is given off that it explodes!), you\'ve seen this sort of
reaction.
Since the salt has 2 OH groups, it must form a stable +2 ion. This means it comes from group 2.
If the compound was MOH, then it would have been from group 1.
Now that we know it is in the 6th period (row) and 2nd group (column), we can identify the
element as barium (Ba). Also, we know that its outermost electrons occupy the 6s orbital
(because it is in the 6th period), so we can fill up orbitals now:
Ba: 1s2, 2s2, 2p6, 3s2, 3p6, 4s2, 3d10, 4p6, 5s2, 4d10, 5p6, 6s2.
The ordering is slightly different because higher values of n lead to d orbitals of very high
energy, thus, for example, it is preferred to fill the 4s orbital before the 3 d orbital, and the 5p and
6s before considering the 4 f orbitals.
The reaction that occurs is:
Ba(s) + 2H2O(l) -------> Ba(OH)2(aq) + H2(g)
Solution
The elements in period 6 are those starting with Cs and going across. Given that the metal reacts
vigorously with water, it must be either from groups 1 or 2 (alkali metals and alkali earth
metals). If you\'ve seen the reaction (or heard about it) between sodium and water (hydrogen is
produced rapidly and enough heat is given off that it explodes!), you\'ve seen this sort of
reaction.
Since the salt has 2 OH groups, it must form a stable +2 ion. This means it comes from group 2.
If the compound was MOH, then it would have been from group 1.
Now that we know it is in the 6th period (row) and 2nd group (column), we can identify the
element as barium (Ba). Also, we know that its outermost electrons occupy the 6s orbital
(because it is in the 6th period), so we can fill up orbitals now:
Ba: 1s2, 2s2, 2p6, 3s2, 3p6, 4s2, 3d10, 4p6, 5s2, 4d10, 5p6, 6s2.
The ordering is slightly different because higher values of n lead to d orbitals of very high
energy, thus, for example, it is preferred to fill the 4s orbital before the 3 d orbital, and the 5p and
6s before considering the 4 f orbitals.
The reaction that occurs is:
Ba(s) + 2H2O(l) -------> Ba(OH)2(aq) + H2(g).
all the information you need about metals , nonmetals their ores at brief .
dont get scared by no. of slides it will be over within no time.
sorry ,the number pictures are less
The elements in period 6 are those starting with Cs and going acr.pdfannamalassociates
The elements in period 6 are those starting with Cs and going across. Given that the metal reacts
vigorously with water, it must be either from groups 1 or 2 (alkali metals and alkali earth
metals). If you\'ve seen the reaction (or heard about it) between sodium and water (hydrogen is
produced rapidly and enough heat is given off that it explodes!), you\'ve seen this sort of
reaction.
Since the salt has 2 OH groups, it must form a stable +2 ion. This means it comes from group 2.
If the compound was MOH, then it would have been from group 1.
Now that we know it is in the 6th period (row) and 2nd group (column), we can identify the
element as barium (Ba). Also, we know that its outermost electrons occupy the 6s orbital
(because it is in the 6th period), so we can fill up orbitals now:
Ba: 1s2, 2s2, 2p6, 3s2, 3p6, 4s2, 3d10, 4p6, 5s2, 4d10, 5p6, 6s2.
The ordering is slightly different because higher values of n lead to d orbitals of very high
energy, thus, for example, it is preferred to fill the 4s orbital before the 3 d orbital, and the 5p and
6s before considering the 4 f orbitals.
The reaction that occurs is:
Ba(s) + 2H2O(l) -------> Ba(OH)2(aq) + H2(g)
Solution
The elements in period 6 are those starting with Cs and going across. Given that the metal reacts
vigorously with water, it must be either from groups 1 or 2 (alkali metals and alkali earth
metals). If you\'ve seen the reaction (or heard about it) between sodium and water (hydrogen is
produced rapidly and enough heat is given off that it explodes!), you\'ve seen this sort of
reaction.
Since the salt has 2 OH groups, it must form a stable +2 ion. This means it comes from group 2.
If the compound was MOH, then it would have been from group 1.
Now that we know it is in the 6th period (row) and 2nd group (column), we can identify the
element as barium (Ba). Also, we know that its outermost electrons occupy the 6s orbital
(because it is in the 6th period), so we can fill up orbitals now:
Ba: 1s2, 2s2, 2p6, 3s2, 3p6, 4s2, 3d10, 4p6, 5s2, 4d10, 5p6, 6s2.
The ordering is slightly different because higher values of n lead to d orbitals of very high
energy, thus, for example, it is preferred to fill the 4s orbital before the 3 d orbital, and the 5p and
6s before considering the 4 f orbitals.
The reaction that occurs is:
Ba(s) + 2H2O(l) -------> Ba(OH)2(aq) + H2(g).
all the information you need about metals , nonmetals their ores at brief .
dont get scared by no. of slides it will be over within no time.
sorry ,the number pictures are less
Class XII d and f- block elements (part 2)Arunesh Gupta
This part contains ionisation enthalpies, oxidation states, metal oxides & oxocations, magnetic properties, coloured ions of d block elements, catalysts, interstitial compounds, alloy formation & some important conceptual questions with answers as hints. Also some reasoning questions are given to test the understanding of properties of d block elements.
Name- Gold leaved white PoplarGenus- Populusspecies- albaAutho.pdfaptex1
In python,Tkinter is a Graphical user interface package.So,Tkinter tookit for GUI programming
supports protocol handler mechanism.
Protocol is taking care of how interaction takes place between application and windows manager.
self.parent.protocol(\"WM_DELETE_WINDOW\",self.quit_handler)
in the above line \"WM_DELETE_WINDOW\" is a protocol.What this protocl does is :it define
what is going to happen when a user who uses the application and closes window explicitely
using windows manager.
Then this protocol \"WM_DELETE_WINDOE\" bypasses to quit_handler().
That quit_handler() asks user \"whether he or she wants to quit or not\" then simply quit the
window.
Solution
In python,Tkinter is a Graphical user interface package.So,Tkinter tookit for GUI programming
supports protocol handler mechanism.
Protocol is taking care of how interaction takes place between application and windows manager.
self.parent.protocol(\"WM_DELETE_WINDOW\",self.quit_handler)
in the above line \"WM_DELETE_WINDOW\" is a protocol.What this protocl does is :it define
what is going to happen when a user who uses the application and closes window explicitely
using windows manager.
Then this protocol \"WM_DELETE_WINDOE\" bypasses to quit_handler().
That quit_handler() asks user \"whether he or she wants to quit or not\" then simply quit the
window..
MinOfFourNumbers.javaimport java.util.Scanner;public class MinOf.pdfaptex1
If I assume you meant supply is determined as [q_(s)=3p^2-4p] and demand is determined as
[q_(d)=-p^2+24] then I would calculate that the equilibrium is where [q_(s)=q_(d)] and p>0. So I
set up the equation [3p^2-4p=-p^2+24] I add [p^2] to both sides of the equation yielding [4p^2-
4p=24] I subtract 24 from each side, yielding the quadratic equation [4p^2-4p-24=0] I factor the
equation [(2p-6)(2p+4)=0] so that means [2p-6=0] or [2p+4=0] In the former case 2p=6 so p=3,
and in the latter 2p=-4 so p=-2. The economic nature of the question requires p>0, so [p!=-2] and
thus the equilibrium price is $3.00 each. Then to determine the equilibrium quantity, we solve
either q expression for p=3.
[q_(s)=3(3)^2-4(3)=3(9)-12=27-12=15]
[q_(d)=-(3^2)+24=-9+24=15]
So the equilibrium quantity is 15 items.
The price and quantity for market equilibrium is 15 items at $3.00 each.
Solution
If I assume you meant supply is determined as [q_(s)=3p^2-4p] and demand is determined as
[q_(d)=-p^2+24] then I would calculate that the equilibrium is where [q_(s)=q_(d)] and p>0. So I
set up the equation [3p^2-4p=-p^2+24] I add [p^2] to both sides of the equation yielding [4p^2-
4p=24] I subtract 24 from each side, yielding the quadratic equation [4p^2-4p-24=0] I factor the
equation [(2p-6)(2p+4)=0] so that means [2p-6=0] or [2p+4=0] In the former case 2p=6 so p=3,
and in the latter 2p=-4 so p=-2. The economic nature of the question requires p>0, so [p!=-2] and
thus the equilibrium price is $3.00 each. Then to determine the equilibrium quantity, we solve
either q expression for p=3.
[q_(s)=3(3)^2-4(3)=3(9)-12=27-12=15]
[q_(d)=-(3^2)+24=-9+24=15]
So the equilibrium quantity is 15 items.
The price and quantity for market equilibrium is 15 items at $3.00 each..
molarity = 0.252101.1 =0.001236 M percent =0.251002 =12.5 .pdfaptex1
If this is not soluble in water, this must be nonpolar,
if it si soluble in hexane, this must be nonpolar as well
therefore, we are certain this is nonpolar substance
with low vap pressure...
From the list, nearest BP for that pressure is chloroform with 60ºC (vs 58.) which is ok, since no
range is given.
CCl4 is nonpolar
In order to ensure this, you could use a chromatography with previous data, i.e. use chloroform
standard and run chromatography vs. unkown. If they behave the same ( same Rf value, and
retention time ) then this is most likely chloroform
Solution
If this is not soluble in water, this must be nonpolar,
if it si soluble in hexane, this must be nonpolar as well
therefore, we are certain this is nonpolar substance
with low vap pressure...
From the list, nearest BP for that pressure is chloroform with 60ºC (vs 58.) which is ok, since no
range is given.
CCl4 is nonpolar
In order to ensure this, you could use a chromatography with previous data, i.e. use chloroform
standard and run chromatography vs. unkown. If they behave the same ( same Rf value, and
retention time ) then this is most likely chloroform.
Initial concentration of Br- = 2.25 x 10e-3M1V1=M2V2therefore M2.pdfaptex1
From the graph, we can see that there are three values at which f(x)= 0
These are- x= -6,-2,3
Hence the answer is Option D
Solution
From the graph, we can see that there are three values at which f(x)= 0
These are- x= -6,-2,3
Hence the answer is Option D.
import java.util.Scanner;public class HornersPolynomial { .pdfaptex1
For a first order reaction rate constant , k = ( 2.303 /t )x log ( a / (a-x))
Where
a = initial amount
a-x = amount left after time t = a / 10
t = time = ?
k = rate constant = 3.43x10 -2 d -2
Plug the values we get t = ( 2.303 /k )x log ( a / (a-x))
= ( 2.303 / 3.43x10 -2 )x log ( a / (a/10))
= 67.14 days
Solution
For a first order reaction rate constant , k = ( 2.303 /t )x log ( a / (a-x))
Where
a = initial amount
a-x = amount left after time t = a / 10
t = time = ?
k = rate constant = 3.43x10 -2 d -2
Plug the values we get t = ( 2.303 /k )x log ( a / (a-x))
= ( 2.303 / 3.43x10 -2 )x log ( a / (a/10))
= 67.14 days.
Direct memory access (DMA) is a function that allows an inputoutput.pdfaptex1
approximately all of the propoerty crimes are between 3 standard deviations from the mean
mean,u = 3377.2
standard deviation,s = 847.4
u - 3s = 835
u + 3s = 5919.4
OPTION B
p(Z
Solution
approximately all of the propoerty crimes are between 3 standard deviations from the mean
mean,u = 3377.2
standard deviation,s = 847.4
u - 3s = 835
u + 3s = 5919.4
OPTION B
p(Z.
Ethanol is miscible in water because of the hydroxyl functional grou.pdfaptex1
b) Security requirements
Security requirements are the outputs of the risk management activity. Inputs to the risk
management and information security strategy include business strategy, business processes, risk
assessments, business input analysis, information resources, and regulatory requirements.
Solution
b) Security requirements
Security requirements are the outputs of the risk management activity. Inputs to the risk
management and information security strategy include business strategy, business processes, risk
assessments, business input analysis, information resources, and regulatory requirements..
the diluted concentration of HCl = (0.120 M x 25..pdfaptex1
the diluted concentration of HCl = (0.120 M x 25.0 mL) / (25.0 + 40.0) mL =
0.0462 M [H+] = [HCl] = 0.0462 M pH = -log[H+] = -log0.0462 = 1.33
Solution
the diluted concentration of HCl = (0.120 M x 25.0 mL) / (25.0 + 40.0) mL =
0.0462 M [H+] = [HCl] = 0.0462 M pH = -log[H+] = -log0.0462 = 1.33.
AnswerThe net equation of the reaction catalyzed by the protein c.pdfaptex1
a) [21]+[19] = [40] = [4] {since 40 when divided ny 12 leaves a remainder of 4 }
b) [37][27] = [ 999] = [9] { Since now the remiander will be 9 when divided by 45}
c) [33]([83] - [67]) = [33] [16] = [528] = [28]
d) [18] + [8] = [26] = [0]. Hence additive inverse of [18] is [8].
Solution
a) [21]+[19] = [40] = [4] {since 40 when divided ny 12 leaves a remainder of 4 }
b) [37][27] = [ 999] = [9] { Since now the remiander will be 9 when divided by 45}
c) [33]([83] - [67]) = [33] [16] = [528] = [28]
d) [18] + [8] = [26] = [0]. Hence additive inverse of [18] is [8]..
Answer i command.The vi editor always starts in command mode. For.pdfaptex1
A Shareholder of a company is holding a share in the assets of the company. A shareholder is
also entitled to the profits which company makes by using those assets. As the basic fomat of
company distinguishes the Management function from the ownership, People managing the
company may or maynot be the owners i.e share holders of the company. Regulators often
require the companies to obtain approval of the shareholders via a resolution in the shareholders
meeting, thus the deciding power rests with the shareholders. However the extent of powers are
contained in the Legislature governing that corporation.
Shareholders have right in the assets of the corporation not in the day to day mangement of the
corporation.
Solution
A Shareholder of a company is holding a share in the assets of the company. A shareholder is
also entitled to the profits which company makes by using those assets. As the basic fomat of
company distinguishes the Management function from the ownership, People managing the
company may or maynot be the owners i.e share holders of the company. Regulators often
require the companies to obtain approval of the shareholders via a resolution in the shareholders
meeting, thus the deciding power rests with the shareholders. However the extent of powers are
contained in the Legislature governing that corporation.
Shareholders have right in the assets of the corporation not in the day to day mangement of the
corporation..
Answer (b) systems security and control.The businesses are now a .pdfaptex1
A chemical formula is an expression indicating the atoms and their number in a particular
compound.
Each element/atom is identified by its symbol and the number of atoms are given in the
subscript.
For example, one molecule of water contain 2 atoms of hydrogen and one atom of oxygen:
H2O
Hope this helps
Solution
A chemical formula is an expression indicating the atoms and their number in a particular
compound.
Each element/atom is identified by its symbol and the number of atoms are given in the
subscript.
For example, one molecule of water contain 2 atoms of hydrogen and one atom of oxygen:
H2O
Hope this helps.
A. Temeperature of refrigeratorsIntervalB. Horspower of .pdfaptex1
2) b) Understory is rich in humidity hence supports fungi
3) a) canopy includes plant crowns
4) c) herbaceous
5) d) leaf litter/soil
Solution
2) b) Understory is rich in humidity hence supports fungi
3) a) canopy includes plant crowns
4) c) herbaceous
5) d) leaf litter/soil.
48. The answer is Botulism. Botulism ia an illness that brings about.pdfaptex1
1 gallon gasoline = 3.785 L = 3.785 x 803 grams
Now, total heat produced = weight(in gms) x heat of combustion = 3.785 x 803 x 48 kJ
=145889.04 kJ =145.9 MJ
IT IS VERY LARGE NUMBER !!!!
Solution
1 gallon gasoline = 3.785 L = 3.785 x 803 grams
Now, total heat produced = weight(in gms) x heat of combustion = 3.785 x 803 x 48 kJ
=145889.04 kJ =145.9 MJ
IT IS VERY LARGE NUMBER !!!!.
2) b) Understory is rich in humidity hence supports fungi3) a) can.pdfaptex1
(A) The answer is b. increases
Electricity in the form of electrons are transported through the solution by charged ions of the
electrolyte. As the electrolyte concentration increases, so does the number of charge carriers and
hence the amount of charge and electricity conducted increases.
(B) Acetic acid (CH3COOH) is a weak acid and partially ionizes in water:
CH3COOH + H2O => CH3COO- + H3O+
The charged acetate (CH3COO- ) and hydroxonium (H3O+) ions are responsible for electrical
conductivity.
In 6 M acetic acid, water is in excess and and the ionization proceeds as shown above to give an
electrolyte solution with charged ions that conduct electricity.
In glacial acetic acid, there is very little water present and ionization is negliglble. Almost all the
acetic acid remains in the non-conducting molecular form (CH3COOH) and there are no charged
ions present. Thus glacial acetic acid does not conduct electricity.
Solution
(A) The answer is b. increases
Electricity in the form of electrons are transported through the solution by charged ions of the
electrolyte. As the electrolyte concentration increases, so does the number of charge carriers and
hence the amount of charge and electricity conducted increases.
(B) Acetic acid (CH3COOH) is a weak acid and partially ionizes in water:
CH3COOH + H2O => CH3COO- + H3O+
The charged acetate (CH3COO- ) and hydroxonium (H3O+) ions are responsible for electrical
conductivity.
In 6 M acetic acid, water is in excess and and the ionization proceeds as shown above to give an
electrolyte solution with charged ions that conduct electricity.
In glacial acetic acid, there is very little water present and ionization is negliglble. Almost all the
acetic acid remains in the non-conducting molecular form (CH3COOH) and there are no charged
ions present. Thus glacial acetic acid does not conduct electricity..
Class XII d and f- block elements (part 2)Arunesh Gupta
This part contains ionisation enthalpies, oxidation states, metal oxides & oxocations, magnetic properties, coloured ions of d block elements, catalysts, interstitial compounds, alloy formation & some important conceptual questions with answers as hints. Also some reasoning questions are given to test the understanding of properties of d block elements.
Name- Gold leaved white PoplarGenus- Populusspecies- albaAutho.pdfaptex1
In python,Tkinter is a Graphical user interface package.So,Tkinter tookit for GUI programming
supports protocol handler mechanism.
Protocol is taking care of how interaction takes place between application and windows manager.
self.parent.protocol(\"WM_DELETE_WINDOW\",self.quit_handler)
in the above line \"WM_DELETE_WINDOW\" is a protocol.What this protocl does is :it define
what is going to happen when a user who uses the application and closes window explicitely
using windows manager.
Then this protocol \"WM_DELETE_WINDOE\" bypasses to quit_handler().
That quit_handler() asks user \"whether he or she wants to quit or not\" then simply quit the
window.
Solution
In python,Tkinter is a Graphical user interface package.So,Tkinter tookit for GUI programming
supports protocol handler mechanism.
Protocol is taking care of how interaction takes place between application and windows manager.
self.parent.protocol(\"WM_DELETE_WINDOW\",self.quit_handler)
in the above line \"WM_DELETE_WINDOW\" is a protocol.What this protocl does is :it define
what is going to happen when a user who uses the application and closes window explicitely
using windows manager.
Then this protocol \"WM_DELETE_WINDOE\" bypasses to quit_handler().
That quit_handler() asks user \"whether he or she wants to quit or not\" then simply quit the
window..
MinOfFourNumbers.javaimport java.util.Scanner;public class MinOf.pdfaptex1
If I assume you meant supply is determined as [q_(s)=3p^2-4p] and demand is determined as
[q_(d)=-p^2+24] then I would calculate that the equilibrium is where [q_(s)=q_(d)] and p>0. So I
set up the equation [3p^2-4p=-p^2+24] I add [p^2] to both sides of the equation yielding [4p^2-
4p=24] I subtract 24 from each side, yielding the quadratic equation [4p^2-4p-24=0] I factor the
equation [(2p-6)(2p+4)=0] so that means [2p-6=0] or [2p+4=0] In the former case 2p=6 so p=3,
and in the latter 2p=-4 so p=-2. The economic nature of the question requires p>0, so [p!=-2] and
thus the equilibrium price is $3.00 each. Then to determine the equilibrium quantity, we solve
either q expression for p=3.
[q_(s)=3(3)^2-4(3)=3(9)-12=27-12=15]
[q_(d)=-(3^2)+24=-9+24=15]
So the equilibrium quantity is 15 items.
The price and quantity for market equilibrium is 15 items at $3.00 each.
Solution
If I assume you meant supply is determined as [q_(s)=3p^2-4p] and demand is determined as
[q_(d)=-p^2+24] then I would calculate that the equilibrium is where [q_(s)=q_(d)] and p>0. So I
set up the equation [3p^2-4p=-p^2+24] I add [p^2] to both sides of the equation yielding [4p^2-
4p=24] I subtract 24 from each side, yielding the quadratic equation [4p^2-4p-24=0] I factor the
equation [(2p-6)(2p+4)=0] so that means [2p-6=0] or [2p+4=0] In the former case 2p=6 so p=3,
and in the latter 2p=-4 so p=-2. The economic nature of the question requires p>0, so [p!=-2] and
thus the equilibrium price is $3.00 each. Then to determine the equilibrium quantity, we solve
either q expression for p=3.
[q_(s)=3(3)^2-4(3)=3(9)-12=27-12=15]
[q_(d)=-(3^2)+24=-9+24=15]
So the equilibrium quantity is 15 items.
The price and quantity for market equilibrium is 15 items at $3.00 each..
molarity = 0.252101.1 =0.001236 M percent =0.251002 =12.5 .pdfaptex1
If this is not soluble in water, this must be nonpolar,
if it si soluble in hexane, this must be nonpolar as well
therefore, we are certain this is nonpolar substance
with low vap pressure...
From the list, nearest BP for that pressure is chloroform with 60ºC (vs 58.) which is ok, since no
range is given.
CCl4 is nonpolar
In order to ensure this, you could use a chromatography with previous data, i.e. use chloroform
standard and run chromatography vs. unkown. If they behave the same ( same Rf value, and
retention time ) then this is most likely chloroform
Solution
If this is not soluble in water, this must be nonpolar,
if it si soluble in hexane, this must be nonpolar as well
therefore, we are certain this is nonpolar substance
with low vap pressure...
From the list, nearest BP for that pressure is chloroform with 60ºC (vs 58.) which is ok, since no
range is given.
CCl4 is nonpolar
In order to ensure this, you could use a chromatography with previous data, i.e. use chloroform
standard and run chromatography vs. unkown. If they behave the same ( same Rf value, and
retention time ) then this is most likely chloroform.
Initial concentration of Br- = 2.25 x 10e-3M1V1=M2V2therefore M2.pdfaptex1
From the graph, we can see that there are three values at which f(x)= 0
These are- x= -6,-2,3
Hence the answer is Option D
Solution
From the graph, we can see that there are three values at which f(x)= 0
These are- x= -6,-2,3
Hence the answer is Option D.
import java.util.Scanner;public class HornersPolynomial { .pdfaptex1
For a first order reaction rate constant , k = ( 2.303 /t )x log ( a / (a-x))
Where
a = initial amount
a-x = amount left after time t = a / 10
t = time = ?
k = rate constant = 3.43x10 -2 d -2
Plug the values we get t = ( 2.303 /k )x log ( a / (a-x))
= ( 2.303 / 3.43x10 -2 )x log ( a / (a/10))
= 67.14 days
Solution
For a first order reaction rate constant , k = ( 2.303 /t )x log ( a / (a-x))
Where
a = initial amount
a-x = amount left after time t = a / 10
t = time = ?
k = rate constant = 3.43x10 -2 d -2
Plug the values we get t = ( 2.303 /k )x log ( a / (a-x))
= ( 2.303 / 3.43x10 -2 )x log ( a / (a/10))
= 67.14 days.
Direct memory access (DMA) is a function that allows an inputoutput.pdfaptex1
approximately all of the propoerty crimes are between 3 standard deviations from the mean
mean,u = 3377.2
standard deviation,s = 847.4
u - 3s = 835
u + 3s = 5919.4
OPTION B
p(Z
Solution
approximately all of the propoerty crimes are between 3 standard deviations from the mean
mean,u = 3377.2
standard deviation,s = 847.4
u - 3s = 835
u + 3s = 5919.4
OPTION B
p(Z.
Ethanol is miscible in water because of the hydroxyl functional grou.pdfaptex1
b) Security requirements
Security requirements are the outputs of the risk management activity. Inputs to the risk
management and information security strategy include business strategy, business processes, risk
assessments, business input analysis, information resources, and regulatory requirements.
Solution
b) Security requirements
Security requirements are the outputs of the risk management activity. Inputs to the risk
management and information security strategy include business strategy, business processes, risk
assessments, business input analysis, information resources, and regulatory requirements..
the diluted concentration of HCl = (0.120 M x 25..pdfaptex1
the diluted concentration of HCl = (0.120 M x 25.0 mL) / (25.0 + 40.0) mL =
0.0462 M [H+] = [HCl] = 0.0462 M pH = -log[H+] = -log0.0462 = 1.33
Solution
the diluted concentration of HCl = (0.120 M x 25.0 mL) / (25.0 + 40.0) mL =
0.0462 M [H+] = [HCl] = 0.0462 M pH = -log[H+] = -log0.0462 = 1.33.
AnswerThe net equation of the reaction catalyzed by the protein c.pdfaptex1
a) [21]+[19] = [40] = [4] {since 40 when divided ny 12 leaves a remainder of 4 }
b) [37][27] = [ 999] = [9] { Since now the remiander will be 9 when divided by 45}
c) [33]([83] - [67]) = [33] [16] = [528] = [28]
d) [18] + [8] = [26] = [0]. Hence additive inverse of [18] is [8].
Solution
a) [21]+[19] = [40] = [4] {since 40 when divided ny 12 leaves a remainder of 4 }
b) [37][27] = [ 999] = [9] { Since now the remiander will be 9 when divided by 45}
c) [33]([83] - [67]) = [33] [16] = [528] = [28]
d) [18] + [8] = [26] = [0]. Hence additive inverse of [18] is [8]..
Answer i command.The vi editor always starts in command mode. For.pdfaptex1
A Shareholder of a company is holding a share in the assets of the company. A shareholder is
also entitled to the profits which company makes by using those assets. As the basic fomat of
company distinguishes the Management function from the ownership, People managing the
company may or maynot be the owners i.e share holders of the company. Regulators often
require the companies to obtain approval of the shareholders via a resolution in the shareholders
meeting, thus the deciding power rests with the shareholders. However the extent of powers are
contained in the Legislature governing that corporation.
Shareholders have right in the assets of the corporation not in the day to day mangement of the
corporation.
Solution
A Shareholder of a company is holding a share in the assets of the company. A shareholder is
also entitled to the profits which company makes by using those assets. As the basic fomat of
company distinguishes the Management function from the ownership, People managing the
company may or maynot be the owners i.e share holders of the company. Regulators often
require the companies to obtain approval of the shareholders via a resolution in the shareholders
meeting, thus the deciding power rests with the shareholders. However the extent of powers are
contained in the Legislature governing that corporation.
Shareholders have right in the assets of the corporation not in the day to day mangement of the
corporation..
Answer (b) systems security and control.The businesses are now a .pdfaptex1
A chemical formula is an expression indicating the atoms and their number in a particular
compound.
Each element/atom is identified by its symbol and the number of atoms are given in the
subscript.
For example, one molecule of water contain 2 atoms of hydrogen and one atom of oxygen:
H2O
Hope this helps
Solution
A chemical formula is an expression indicating the atoms and their number in a particular
compound.
Each element/atom is identified by its symbol and the number of atoms are given in the
subscript.
For example, one molecule of water contain 2 atoms of hydrogen and one atom of oxygen:
H2O
Hope this helps.
A. Temeperature of refrigeratorsIntervalB. Horspower of .pdfaptex1
2) b) Understory is rich in humidity hence supports fungi
3) a) canopy includes plant crowns
4) c) herbaceous
5) d) leaf litter/soil
Solution
2) b) Understory is rich in humidity hence supports fungi
3) a) canopy includes plant crowns
4) c) herbaceous
5) d) leaf litter/soil.
48. The answer is Botulism. Botulism ia an illness that brings about.pdfaptex1
1 gallon gasoline = 3.785 L = 3.785 x 803 grams
Now, total heat produced = weight(in gms) x heat of combustion = 3.785 x 803 x 48 kJ
=145889.04 kJ =145.9 MJ
IT IS VERY LARGE NUMBER !!!!
Solution
1 gallon gasoline = 3.785 L = 3.785 x 803 grams
Now, total heat produced = weight(in gms) x heat of combustion = 3.785 x 803 x 48 kJ
=145889.04 kJ =145.9 MJ
IT IS VERY LARGE NUMBER !!!!.
2) b) Understory is rich in humidity hence supports fungi3) a) can.pdfaptex1
(A) The answer is b. increases
Electricity in the form of electrons are transported through the solution by charged ions of the
electrolyte. As the electrolyte concentration increases, so does the number of charge carriers and
hence the amount of charge and electricity conducted increases.
(B) Acetic acid (CH3COOH) is a weak acid and partially ionizes in water:
CH3COOH + H2O => CH3COO- + H3O+
The charged acetate (CH3COO- ) and hydroxonium (H3O+) ions are responsible for electrical
conductivity.
In 6 M acetic acid, water is in excess and and the ionization proceeds as shown above to give an
electrolyte solution with charged ions that conduct electricity.
In glacial acetic acid, there is very little water present and ionization is negliglble. Almost all the
acetic acid remains in the non-conducting molecular form (CH3COOH) and there are no charged
ions present. Thus glacial acetic acid does not conduct electricity.
Solution
(A) The answer is b. increases
Electricity in the form of electrons are transported through the solution by charged ions of the
electrolyte. As the electrolyte concentration increases, so does the number of charge carriers and
hence the amount of charge and electricity conducted increases.
(B) Acetic acid (CH3COOH) is a weak acid and partially ionizes in water:
CH3COOH + H2O => CH3COO- + H3O+
The charged acetate (CH3COO- ) and hydroxonium (H3O+) ions are responsible for electrical
conductivity.
In 6 M acetic acid, water is in excess and and the ionization proceeds as shown above to give an
electrolyte solution with charged ions that conduct electricity.
In glacial acetic acid, there is very little water present and ionization is negliglble. Almost all the
acetic acid remains in the non-conducting molecular form (CH3COOH) and there are no charged
ions present. Thus glacial acetic acid does not conduct electricity..
Thermodynamic entropy is a non-conserved state fu.pdfaptex1
Thermodynamic entropy is a non-conserved state function that is of great
importance in the sciences of physics and chemistry. Historically, the concept of entropy evolved
in order to explain why some processes (permitted by conservation laws) occur spontaneously
while their time reversals (also permitted by conservation laws) do not; systems tend to progress
in the direction of increasing entropy. For isolated systems, entropy never decreases. This fact
has several important consequences in science: first, it prohibits \"perpetual motion\" machines;
and second, it implies the arrow of entropy has the same directionality as the arrow of time.
Increases in entropy correspond to irreversible changes in a system, because some energy is
expended as waste heat, limiting the amount of work a system can do. In statistical mechanics,
entropy is a measure of the number of ways in which a system may be arranged, often taken to
be a measure of \"disorder\" (the higher the entropy, the higher the disorder). This definition
describes the entropy as being proportional to the natural logarithm of the number of possible
microscopic configurations of the individual atoms and molecules of the system (microstates)
which could give rise to the observed macroscopic state (macrostate) of the system. The constant
of proportionality is the Boltzmann constant. - Wiki
Solution
Thermodynamic entropy is a non-conserved state function that is of great
importance in the sciences of physics and chemistry. Historically, the concept of entropy evolved
in order to explain why some processes (permitted by conservation laws) occur spontaneously
while their time reversals (also permitted by conservation laws) do not; systems tend to progress
in the direction of increasing entropy. For isolated systems, entropy never decreases. This fact
has several important consequences in science: first, it prohibits \"perpetual motion\" machines;
and second, it implies the arrow of entropy has the same directionality as the arrow of time.
Increases in entropy correspond to irreversible changes in a system, because some energy is
expended as waste heat, limiting the amount of work a system can do. In statistical mechanics,
entropy is a measure of the number of ways in which a system may be arranged, often taken to
be a measure of \"disorder\" (the higher the entropy, the higher the disorder). This definition
describes the entropy as being proportional to the natural logarithm of the number of possible
microscopic configurations of the individual atoms and molecules of the system (microstates)
which could give rise to the observed macroscopic state (macrostate) of the system. The constant
of proportionality is the Boltzmann constant. - Wiki.
I is oxidized by 6 electrons as the oxidation sta.pdfaptex1
I is oxidized by 6 electrons as the oxidation state of I in I- is -1 while in IO3- is +5.
Solution
I is oxidized by 6 electrons as the oxidation state of I in I- is -1 while in IO3- is +5..
The main difference is that Democritus was not a .pdfaptex1
The main difference is that Democritus was not a scientist he was a philosopher as
such he only theorized that matter could not be indefinitely divided, that there is a limit (now
know to be the atom). Dalton on the other had based his theory of atoms on scientific
experimentation and observation. Demeocritus used reason vs. Dalton used scientific method
Solution
The main difference is that Democritus was not a scientist he was a philosopher as
such he only theorized that matter could not be indefinitely divided, that there is a limit (now
know to be the atom). Dalton on the other had based his theory of atoms on scientific
experimentation and observation. Demeocritus used reason vs. Dalton used scientific method.
How to Split Bills in the Odoo 17 POS ModuleCeline George
Bills have a main role in point of sale procedure. It will help to track sales, handling payments and giving receipts to customers. Bill splitting also has an important role in POS. For example, If some friends come together for dinner and if they want to divide the bill then it is possible by POS bill splitting. This slide will show how to split bills in odoo 17 POS.
This is a presentation by Dada Robert in a Your Skill Boost masterclass organised by the Excellence Foundation for South Sudan (EFSS) on Saturday, the 25th and Sunday, the 26th of May 2024.
He discussed the concept of quality improvement, emphasizing its applicability to various aspects of life, including personal, project, and program improvements. He defined quality as doing the right thing at the right time in the right way to achieve the best possible results and discussed the concept of the "gap" between what we know and what we do, and how this gap represents the areas we need to improve. He explained the scientific approach to quality improvement, which involves systematic performance analysis, testing and learning, and implementing change ideas. He also highlighted the importance of client focus and a team approach to quality improvement.
Students, digital devices and success - Andreas Schleicher - 27 May 2024..pptxEduSkills OECD
Andreas Schleicher presents at the OECD webinar ‘Digital devices in schools: detrimental distraction or secret to success?’ on 27 May 2024. The presentation was based on findings from PISA 2022 results and the webinar helped launch the PISA in Focus ‘Managing screen time: How to protect and equip students against distraction’ https://www.oecd-ilibrary.org/education/managing-screen-time_7c225af4-en and the OECD Education Policy Perspective ‘Students, digital devices and success’ can be found here - https://oe.cd/il/5yV
The Art Pastor's Guide to Sabbath | Steve ThomasonSteve Thomason
What is the purpose of the Sabbath Law in the Torah. It is interesting to compare how the context of the law shifts from Exodus to Deuteronomy. Who gets to rest, and why?
Welcome to TechSoup New Member Orientation and Q&A (May 2024).pdfTechSoup
In this webinar you will learn how your organization can access TechSoup's wide variety of product discount and donation programs. From hardware to software, we'll give you a tour of the tools available to help your nonprofit with productivity, collaboration, financial management, donor tracking, security, and more.
Unit 8 - Information and Communication Technology (Paper I).pdfThiyagu K
This slides describes the basic concepts of ICT, basics of Email, Emerging Technology and Digital Initiatives in Education. This presentations aligns with the UGC Paper I syllabus.
A. So before we can come up with the chemical equ.pdf
1. A. So before we can come up with the chemical equation, we firsthave to
understand the components of the salt we are to dissolve.What does it break into? What are the
charges of each component ofthe salt, and their individual chemical formulas? So first we lookat
the name "strontium iodate" so we know that it breaks intostrontium with some charge in water
and iodate. Strontium Iodate --> some Strontium + some Iodate (in water) Now for the second
question, what are the charges and the chemicalformula of each part? So for strontium, we know
that it is analkaline earth metal (or in group II), so we know that like Ca orMg, Sr is most likely
to hold a charge of 2+. So we'll say that wehave a Sr2+ in solution. How about iodate? By
otherremembering or looking it up we find that it isIO3-. So how would we pair these in a salt?
Since we know that Sr has a2+ charge and iodate has a 1- charge, we know that to balance atotal
charge of 0, we need 2 iodates per Sr making: Sr(IO3)2 as the salt dissolving in solution.This
clearly then breaks into 1 Sr2+ and 2IO3- in water. B. Now that we know the reaction, how do
the two speciesconcentrations relate to themselves in solution? Well we alreadyanswered this
question. By saying that we need to pair 2 iodatesfor each Sr cation, we know that iodate
concentration must bedouble that of the Sr cation in water. Cheers.
Solution
A. So before we can come up with the chemical equation, we firsthave to
understand the components of the salt we are to dissolve.What does it break into? What are the
charges of each component ofthe salt, and their individual chemical formulas? So first we lookat
the name "strontium iodate" so we know that it breaks intostrontium with some charge in water
and iodate. Strontium Iodate --> some Strontium + some Iodate (in water) Now for the second
question, what are the charges and the chemicalformula of each part? So for strontium, we know
that it is analkaline earth metal (or in group II), so we know that like Ca orMg, Sr is most likely
to hold a charge of 2+. So we'll say that wehave a Sr2+ in solution. How about iodate? By
otherremembering or looking it up we find that it isIO3-. So how would we pair these in a salt?
Since we know that Sr has a2+ charge and iodate has a 1- charge, we know that to balance atotal
charge of 0, we need 2 iodates per Sr making: Sr(IO3)2 as the salt dissolving in solution.This
clearly then breaks into 1 Sr2+ and 2IO3- in water. B. Now that we know the reaction, how do
the two speciesconcentrations relate to themselves in solution? Well we alreadyanswered this
question. By saying that we need to pair 2 iodatesfor each Sr cation, we know that iodate
concentration must bedouble that of the Sr cation in water. Cheers.
