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Dynamic routing using FLSM
and VLSM
Presented by: Dr. Amandeep Singh
Poll 1
Subnet is end result of dividing a network
into two or more networks
• Yes
• No
FLSM subnetting
• Step 1:decide total number of sub net required , lets say 2
• Step 2: calculate required network bits for example is assumed case
network one need 30 IP’s and rest IP’s belong to network two
32-5=27 bits
(2^n formula used and 32 is (8.8.8.8 total no of bits ))
• Step 3: calculate subnet mask by converting this binary number to
decimal for eg.
11100000 =224 hence mask will be: 255.255.255.224
• Step 4: Find range by subtracting calculated mask from maximum
possible number 255.255.255.255
255.255.255.255
255.255.255.224
-----------------------
0.0.0.31
3
Range will be
192.10.10.0 to 192.10.10.31
FLSM subnetting
• Step 1:decide total number of sub net required , lets say 2
• Step 2: calculate required network bits for example is assumed case
network one need 30 IP’s and rest IP’s belong to network two
32-5=27 bits
(2^n formula used and 32 is (8.8.8.8 total no of bits ))
• Step 3: calculate subnet mask by converting this binary number to
decimal for eg.
11100000 =224 hence mask will be: 255.255.255.224
• Step 4: Find range by subtracting calculated mask from maximum
possible number 255.255.255.255
255.255.255.255
255.255.255.224
-----------------------
0.0.0.31
4
Range will be
192.10.10.32 to 192.10.10.63
Poll 2
Fixed-length subnet masks can initiate the
IP wastage issue
• Yes
• No
FLSM subnetting
• Step 1:decide total number of sub net required , lets say 2
• Step 2: calculate required network bits for example is assumed case
network one need 30 IP’s and rest IP’s belong to network two
32-5=27 bits
(2^n formula used and 32 is (8.8.8.8 total no of bits ))
• Step 3: calculate subnet mask by converting this binary number to
decimal for eg.
11100000 =224 hence mask will be: 255.255.255.224
• Step 4: Find range by subtracting calculated mask from maximum
possible number 255.255.255.255
255.255.255.255
255.255.255.224
-----------------------
0.0.0.31
6
Range will be
192.10.10.64 to 192.10.10.95
FLSM subnetting
• Step 1:decide total number of sub net required , lets say 2
• Step 2: calculate required network bits for example is assumed case
network one need 30 IP’s and rest IP’s belong to network two
32-5=27 bits
(2^n formula used and 32 is (8.8.8.8 total no of bits ))
• Step 3: calculate subnet mask by converting this binary number to
decimal for eg.
11100000 =224 hence mask will be: 255.255.255.224
• Step 4: Find range by subtracting calculated mask from maximum
possible number 255.255.255.255
255.255.255.255
255.255.255.224
-----------------------
0.0.0.31
7
Range will be
192.10.10.96 to 192.10.10.127
FLSM subnetting
• Step 1:decide total number of sub net required , lets say 2
• Step 2: calculate required network bits for example is assumed case
network one need 30 IP’s and rest IP’s belong to network two
32-5=27 bits
(2^n formula used and 32 is (8.8.8.8 total no of bits ))
• Step 3: calculate subnet mask by converting this binary number to
decimal for eg.
11100000 =224 hence mask will be: 255.255.255.224
• Step 4: Find range by subtracting calculated mask from maximum
possible number 255.255.255.255
255.255.255.255
255.255.255.224
-----------------------
0.0.0.31
8
Range will be
192.10.10.128 to 192.10.10.159
Router 1 setting for RIP
• Router>
• Router>enable
• Router#
• Router#configure terminal
• Enter configuration commands, one per line. End with CNTL/Z.
• Router(config)#router rip
• Router(config-router)#version 1
• Router(config-router)#network 192.10.10.0
• Router(config-router)#network 192.10.10.96
• Router(config-router)#
Router 2 setting for RIP
• Router>
• Router>enable
• Router#
• Router#configure terminal
• Enter configuration commands, one per line. End with CNTL/Z.
• Router(config)#router rip
• Router(config-router)#version 1
• Router(config-router)#network 192.10.10.96
• Router(config-router)#network 192.10.10.32
• Router(config-router)#network 192.10.10.128
• Router(config-router)#
Router 3 setting for RIP
• Router>
• Router>enable
• Router#
• Router#configure terminal
• Enter configuration commands, one per line. End with CNTL/Z.
• Router(config)#router rip
• Router(config-router)#version 1
• Router(config-router)#network 192.10.10.128
• Router(config-router)#network 192.10.10.64
• Router(config-router)#
• Change the all addresses starting from
192 to180 it will become class less
addressing (version 2) for e.g.
• Router>
• Router>enable
• Router#
• Router#configure terminal
• Enter configuration commands, one per line. End with CNTL/Z.
• Router(config)#router rip
• Router(config-router)#version 2
• Router(config-router)#network 180.10.10.0
• Router(config-router)#network 180.10.10.96
• Router(config-router)#
Poll 3
What will be sub netmask for class C, 6 IP
network
A.248
B.250
C.252
D.254
VLSM subnetting
• Step 1:decide total number of sub net required , lets say 2
• Step 2: calculate required network bits for example is assumed case
network one need 8 IP’s and rest IP’s belong to network two
32-3=29 bits
(2^n formula used and 32 is (8.8.8.8 total no of bits ))
• Step 3: calculate subnet mask by converting this binary number to
decimal for eg.
11111000 =248 hence mask will be: 255.255.255.248
• Step 4: Find range by subtracting calculated mask from maximum
possible number 255.255.255.255
255.255.255.255
255.255.255.248
-----------------------
0.0.0.7
16
Range will be
192.10.10.96 to 192.10.10.103
VLSM subnetting (variable
length subnet mask)
• Step 1:decide total number of sub net required , lets say 2
• Step 2: calculate required network bits for example in assumed case
network one need 64 IP’s and rest IP’s belong to network two
32-6=26 bits
(2^n formula used and 32 is (8.8.8.8 total no of bits ))
• Step 3: calculate subnet mask by converting this binary number to
decimal for eg.
11000000 =192 hence mask will be: 255.255.255.192
• Step 4: Find range by subtracting calculated mask from maximum
possible number 255.255.255.255
255.255.255.255
255.255.255.192
-----------------------
0.0.0.63
17
Range will be
192.10.10.0 to 192.10.10.63
VLSM subnetting
• Step 1:decide total number of sub net required , lets say 2
• Step 2: calculate required network bits for example is assumed case
network one need 30 IP’s and rest IP’s belong to network two
32-5=27 bits
(2^n formula used and 32 is (8.8.8.8 total no of bits ))
• Step 3: calculate subnet mask by converting this binary number to
decimal for eg.
11100000 =224 hence mask will be: 255.255.255.224
• Step 4: Find range by subtracting calculated mask from maximum
possible number 255.255.255.255
255.255.255.255
255.255.255.224
-----------------------
0.0.0.31
18
Range will be
192.10.10.64 to 192.10.10.95
Poll 4
What will be sub netmask for class C, two
host network
A.248
B.250
C.252
D.254
VLSM subnetting
• Step 1:decide total number of sub net required , lets say 2
• Step 2: calculate required network bits for example is assumed case
network one need 4 IP’s and rest IP’s belong to network two
32-2=30 bits
(2^n formula used and 32 is (8.8.8.8 total no of bits ))
• Step 3: calculate subnet mask by converting this binary number to
decimal for eg.
11111100 =252 hence mask will be: 255.255.255.252
• Step 4: Find range by subtracting calculated mask from maximum
possible number 255.255.255.255
255.255.255.255
255.255.255.252
-----------------------
0.0.0.3
20
Range will be
192.10.10.96 to 192.10.10.99
VLSM subnetting
• Step 1:decide total number of sub net required , lets say 2
• Step 2: calculate required network bits for example is assumed case
network one need 4 IP’s and rest IP’s belong to network two
32-2=30 bits
(2^n formula used and 32 is (8.8.8.8 total no of bits ))
• Step 3: calculate subnet mask by converting this binary number to
decimal for eg.
11111100 =252 hence mask will be: 255.255.255.252
• Step 4: Find range by subtracting calculated mask from maximum
possible number 255.255.255.255
255.255.255.255
255.255.255.252
-----------------------
0.0.0.3
21
Range will be
192.10.10.100 to 192.10.10.103
VLSM subnetting
• Step 1:decide total number of sub net required , lets say 2
• Step 2: calculate required network bits for example is assumed case
network one need 4 IP’s and rest IP’s belong to network two
32-2=30 bits
(2^n formula used and 32 is (8.8.8.8 total no of bits ))
• Step 3: calculate subnet mask by converting this binary number to
decimal for eg.
11111100 =252 hence mask will be: 255.255.255.252
• Step 4: Find range by subtracting calculated mask from maximum
possible number 255.255.255.255
255.255.255.255
255.255.255.252
-----------------------
0.0.0.3
22
Range will be
192.10.10.104 to 192.10.10.107
Router 1 setting for RIP
• Router>
• Router>enable
• Router#
• Router#configure terminal
• Enter configuration commands, one per line. End with CNTL/Z.
• Router(config)#router rip
• Router(config-router)#version 1
• Router(config-router)#network 192.10.10.0
• Router(config-router)#network 192.10.10.100
• Router(config-router)#
Router 2 setting for RIP
• Router>
• Router>enable
• Router#
• Router#configure terminal
• Enter configuration commands, one per line. End with CNTL/Z.
• Router(config)#router rip
• Router(config-router)#version 1
• Router(config-router)#network 192.10.10.64
• Router(config-router)#network 192.10.10.100
• Router(config-router)#network 192.10.10.104
• Router(config-router)#
Router 3 setting for RIP
• Router>
• Router>enable
• Router#
• Router#configure terminal
• Enter configuration commands, one per line. End with CNTL/Z.
• Router(config)#router rip
• Router(config-router)#version 1
• Router(config-router)#network 192.10.10.104
• Router(config-router)#network 192.10.10.96
• Router(config-router)#

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6a52807edaf99ecbfafb8ecf2439b542b3623dea-1647242881015.pdf

  • 1. Dynamic routing using FLSM and VLSM Presented by: Dr. Amandeep Singh
  • 2. Poll 1 Subnet is end result of dividing a network into two or more networks • Yes • No
  • 3. FLSM subnetting • Step 1:decide total number of sub net required , lets say 2 • Step 2: calculate required network bits for example is assumed case network one need 30 IP’s and rest IP’s belong to network two 32-5=27 bits (2^n formula used and 32 is (8.8.8.8 total no of bits )) • Step 3: calculate subnet mask by converting this binary number to decimal for eg. 11100000 =224 hence mask will be: 255.255.255.224 • Step 4: Find range by subtracting calculated mask from maximum possible number 255.255.255.255 255.255.255.255 255.255.255.224 ----------------------- 0.0.0.31 3 Range will be 192.10.10.0 to 192.10.10.31
  • 4. FLSM subnetting • Step 1:decide total number of sub net required , lets say 2 • Step 2: calculate required network bits for example is assumed case network one need 30 IP’s and rest IP’s belong to network two 32-5=27 bits (2^n formula used and 32 is (8.8.8.8 total no of bits )) • Step 3: calculate subnet mask by converting this binary number to decimal for eg. 11100000 =224 hence mask will be: 255.255.255.224 • Step 4: Find range by subtracting calculated mask from maximum possible number 255.255.255.255 255.255.255.255 255.255.255.224 ----------------------- 0.0.0.31 4 Range will be 192.10.10.32 to 192.10.10.63
  • 5. Poll 2 Fixed-length subnet masks can initiate the IP wastage issue • Yes • No
  • 6. FLSM subnetting • Step 1:decide total number of sub net required , lets say 2 • Step 2: calculate required network bits for example is assumed case network one need 30 IP’s and rest IP’s belong to network two 32-5=27 bits (2^n formula used and 32 is (8.8.8.8 total no of bits )) • Step 3: calculate subnet mask by converting this binary number to decimal for eg. 11100000 =224 hence mask will be: 255.255.255.224 • Step 4: Find range by subtracting calculated mask from maximum possible number 255.255.255.255 255.255.255.255 255.255.255.224 ----------------------- 0.0.0.31 6 Range will be 192.10.10.64 to 192.10.10.95
  • 7. FLSM subnetting • Step 1:decide total number of sub net required , lets say 2 • Step 2: calculate required network bits for example is assumed case network one need 30 IP’s and rest IP’s belong to network two 32-5=27 bits (2^n formula used and 32 is (8.8.8.8 total no of bits )) • Step 3: calculate subnet mask by converting this binary number to decimal for eg. 11100000 =224 hence mask will be: 255.255.255.224 • Step 4: Find range by subtracting calculated mask from maximum possible number 255.255.255.255 255.255.255.255 255.255.255.224 ----------------------- 0.0.0.31 7 Range will be 192.10.10.96 to 192.10.10.127
  • 8. FLSM subnetting • Step 1:decide total number of sub net required , lets say 2 • Step 2: calculate required network bits for example is assumed case network one need 30 IP’s and rest IP’s belong to network two 32-5=27 bits (2^n formula used and 32 is (8.8.8.8 total no of bits )) • Step 3: calculate subnet mask by converting this binary number to decimal for eg. 11100000 =224 hence mask will be: 255.255.255.224 • Step 4: Find range by subtracting calculated mask from maximum possible number 255.255.255.255 255.255.255.255 255.255.255.224 ----------------------- 0.0.0.31 8 Range will be 192.10.10.128 to 192.10.10.159
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  • 10. Router 1 setting for RIP • Router> • Router>enable • Router# • Router#configure terminal • Enter configuration commands, one per line. End with CNTL/Z. • Router(config)#router rip • Router(config-router)#version 1 • Router(config-router)#network 192.10.10.0 • Router(config-router)#network 192.10.10.96 • Router(config-router)#
  • 11. Router 2 setting for RIP • Router> • Router>enable • Router# • Router#configure terminal • Enter configuration commands, one per line. End with CNTL/Z. • Router(config)#router rip • Router(config-router)#version 1 • Router(config-router)#network 192.10.10.96 • Router(config-router)#network 192.10.10.32 • Router(config-router)#network 192.10.10.128 • Router(config-router)#
  • 12. Router 3 setting for RIP • Router> • Router>enable • Router# • Router#configure terminal • Enter configuration commands, one per line. End with CNTL/Z. • Router(config)#router rip • Router(config-router)#version 1 • Router(config-router)#network 192.10.10.128 • Router(config-router)#network 192.10.10.64 • Router(config-router)#
  • 13. • Change the all addresses starting from 192 to180 it will become class less addressing (version 2) for e.g. • Router> • Router>enable • Router# • Router#configure terminal • Enter configuration commands, one per line. End with CNTL/Z. • Router(config)#router rip • Router(config-router)#version 2 • Router(config-router)#network 180.10.10.0 • Router(config-router)#network 180.10.10.96 • Router(config-router)#
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  • 15. Poll 3 What will be sub netmask for class C, 6 IP network A.248 B.250 C.252 D.254
  • 16. VLSM subnetting • Step 1:decide total number of sub net required , lets say 2 • Step 2: calculate required network bits for example is assumed case network one need 8 IP’s and rest IP’s belong to network two 32-3=29 bits (2^n formula used and 32 is (8.8.8.8 total no of bits )) • Step 3: calculate subnet mask by converting this binary number to decimal for eg. 11111000 =248 hence mask will be: 255.255.255.248 • Step 4: Find range by subtracting calculated mask from maximum possible number 255.255.255.255 255.255.255.255 255.255.255.248 ----------------------- 0.0.0.7 16 Range will be 192.10.10.96 to 192.10.10.103
  • 17. VLSM subnetting (variable length subnet mask) • Step 1:decide total number of sub net required , lets say 2 • Step 2: calculate required network bits for example in assumed case network one need 64 IP’s and rest IP’s belong to network two 32-6=26 bits (2^n formula used and 32 is (8.8.8.8 total no of bits )) • Step 3: calculate subnet mask by converting this binary number to decimal for eg. 11000000 =192 hence mask will be: 255.255.255.192 • Step 4: Find range by subtracting calculated mask from maximum possible number 255.255.255.255 255.255.255.255 255.255.255.192 ----------------------- 0.0.0.63 17 Range will be 192.10.10.0 to 192.10.10.63
  • 18. VLSM subnetting • Step 1:decide total number of sub net required , lets say 2 • Step 2: calculate required network bits for example is assumed case network one need 30 IP’s and rest IP’s belong to network two 32-5=27 bits (2^n formula used and 32 is (8.8.8.8 total no of bits )) • Step 3: calculate subnet mask by converting this binary number to decimal for eg. 11100000 =224 hence mask will be: 255.255.255.224 • Step 4: Find range by subtracting calculated mask from maximum possible number 255.255.255.255 255.255.255.255 255.255.255.224 ----------------------- 0.0.0.31 18 Range will be 192.10.10.64 to 192.10.10.95
  • 19. Poll 4 What will be sub netmask for class C, two host network A.248 B.250 C.252 D.254
  • 20. VLSM subnetting • Step 1:decide total number of sub net required , lets say 2 • Step 2: calculate required network bits for example is assumed case network one need 4 IP’s and rest IP’s belong to network two 32-2=30 bits (2^n formula used and 32 is (8.8.8.8 total no of bits )) • Step 3: calculate subnet mask by converting this binary number to decimal for eg. 11111100 =252 hence mask will be: 255.255.255.252 • Step 4: Find range by subtracting calculated mask from maximum possible number 255.255.255.255 255.255.255.255 255.255.255.252 ----------------------- 0.0.0.3 20 Range will be 192.10.10.96 to 192.10.10.99
  • 21. VLSM subnetting • Step 1:decide total number of sub net required , lets say 2 • Step 2: calculate required network bits for example is assumed case network one need 4 IP’s and rest IP’s belong to network two 32-2=30 bits (2^n formula used and 32 is (8.8.8.8 total no of bits )) • Step 3: calculate subnet mask by converting this binary number to decimal for eg. 11111100 =252 hence mask will be: 255.255.255.252 • Step 4: Find range by subtracting calculated mask from maximum possible number 255.255.255.255 255.255.255.255 255.255.255.252 ----------------------- 0.0.0.3 21 Range will be 192.10.10.100 to 192.10.10.103
  • 22. VLSM subnetting • Step 1:decide total number of sub net required , lets say 2 • Step 2: calculate required network bits for example is assumed case network one need 4 IP’s and rest IP’s belong to network two 32-2=30 bits (2^n formula used and 32 is (8.8.8.8 total no of bits )) • Step 3: calculate subnet mask by converting this binary number to decimal for eg. 11111100 =252 hence mask will be: 255.255.255.252 • Step 4: Find range by subtracting calculated mask from maximum possible number 255.255.255.255 255.255.255.255 255.255.255.252 ----------------------- 0.0.0.3 22 Range will be 192.10.10.104 to 192.10.10.107
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  • 31. Router 1 setting for RIP • Router> • Router>enable • Router# • Router#configure terminal • Enter configuration commands, one per line. End with CNTL/Z. • Router(config)#router rip • Router(config-router)#version 1 • Router(config-router)#network 192.10.10.0 • Router(config-router)#network 192.10.10.100 • Router(config-router)#
  • 32. Router 2 setting for RIP • Router> • Router>enable • Router# • Router#configure terminal • Enter configuration commands, one per line. End with CNTL/Z. • Router(config)#router rip • Router(config-router)#version 1 • Router(config-router)#network 192.10.10.64 • Router(config-router)#network 192.10.10.100 • Router(config-router)#network 192.10.10.104 • Router(config-router)#
  • 33. Router 3 setting for RIP • Router> • Router>enable • Router# • Router#configure terminal • Enter configuration commands, one per line. End with CNTL/Z. • Router(config)#router rip • Router(config-router)#version 1 • Router(config-router)#network 192.10.10.104 • Router(config-router)#network 192.10.10.96 • Router(config-router)#