PERCENT
COMPOSITION
Section 6.1
THE LAW OF DEFINITE
PROPORTIONS
• The elements in a chemical
compound are always present in
the SAME proportions by mass
• Ex: H2O: the proportion of
Hydrogen and Oxygen stays
constant
MASS PERCENT OF AN
ELEMENT
% Composition = Mass of element x 100%
Mass of compound
MASS PERCENT OF AN
ELEMENT
• Mass percent of hydrogen in
water:
• Mass of H2 = 2 (1.01) = 2.02 g/mol
• Mass of H2O= 18.02 g/mol (Molar
mass)
• % mass of H2 = mass of H2 100%
• mass of H2O
= 2.02 g/mol x 100%
18.02 g/mol
= 11.2 %
PERCENT COMPOSITION
• Tells you the mass
percent (%) of all
elements in a molecule
PERCENT COMPOSITION
Ex 1: A compound with a mass of
48.72 g is found to have 32.69 g
of zinc and 16.03g of sulfur. What
is the percent composition of the
compound?
Given:
Mass of compound 48.72 g
Mass of Zn = 32.69 g
Mass of S = 16.03 g
PERCENT COMPOSITION
• % Zn = 32.69g x 100%
48.72g
• % S = 16.03g x 100%
48.72g
= 67.10%
= 32.9%
PERCENT COMPOSITION
• Can also be calculated using the chemical
formula
• Ex 2: What is the % composition of each
of the elements in C9H8O?
• = 9(12.01g/mol) + 8(1.01g/mol) + 16g/mol
= 108.09 + 8.08 + 16
= 132.17g/mol
O
H
C
M 8
9
PERCENT COMPOSITION
• % C = 108.09 g x 100%
132.17g
= 81.78 %
• % H = 8.08g x 100%
132.17 g
= 6.11 %
• % O = 16.00g x 100%
132.17 g
= 12. 10%
PERCENT COMPOSITION
• Sometimes chemists use %
composition when they have
unknown compounds to
determine the mass of the
elements that make up the
compound
HOMEWORK
• READ Section 6.1
• Page 260: # 1-9
• Page 264: # 11-18
• Page 266: # 21-30

5) PERCENT COMPOSITION.ppt Empirical formula calculation

  • 1.
  • 2.
    THE LAW OFDEFINITE PROPORTIONS • The elements in a chemical compound are always present in the SAME proportions by mass • Ex: H2O: the proportion of Hydrogen and Oxygen stays constant
  • 3.
    MASS PERCENT OFAN ELEMENT % Composition = Mass of element x 100% Mass of compound
  • 4.
    MASS PERCENT OFAN ELEMENT • Mass percent of hydrogen in water: • Mass of H2 = 2 (1.01) = 2.02 g/mol • Mass of H2O= 18.02 g/mol (Molar mass) • % mass of H2 = mass of H2 100% • mass of H2O = 2.02 g/mol x 100% 18.02 g/mol = 11.2 %
  • 5.
    PERCENT COMPOSITION • Tellsyou the mass percent (%) of all elements in a molecule
  • 6.
    PERCENT COMPOSITION Ex 1:A compound with a mass of 48.72 g is found to have 32.69 g of zinc and 16.03g of sulfur. What is the percent composition of the compound? Given: Mass of compound 48.72 g Mass of Zn = 32.69 g Mass of S = 16.03 g
  • 7.
    PERCENT COMPOSITION • %Zn = 32.69g x 100% 48.72g • % S = 16.03g x 100% 48.72g = 67.10% = 32.9%
  • 8.
    PERCENT COMPOSITION • Canalso be calculated using the chemical formula • Ex 2: What is the % composition of each of the elements in C9H8O? • = 9(12.01g/mol) + 8(1.01g/mol) + 16g/mol = 108.09 + 8.08 + 16 = 132.17g/mol O H C M 8 9
  • 9.
    PERCENT COMPOSITION • %C = 108.09 g x 100% 132.17g = 81.78 % • % H = 8.08g x 100% 132.17 g = 6.11 % • % O = 16.00g x 100% 132.17 g = 12. 10%
  • 10.
    PERCENT COMPOSITION • Sometimeschemists use % composition when they have unknown compounds to determine the mass of the elements that make up the compound
  • 11.
    HOMEWORK • READ Section6.1 • Page 260: # 1-9 • Page 264: # 11-18 • Page 266: # 21-30