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Example 2:
How much voltage must you apply across a
10μF capacitor to cause an AC current of
25mA at 50 Hz to flow
25mA at 50 Hz to flow

XC =
1 / 2 π f C

 
 =
1 / 2 x 3.1416 x 50 x 10 x 10-6

 
 =
318.5 Ω
Now, V
=
 I XC

 
    =
 25 x 10-3 x 318.5



     =
 7.96 V
Example 3:
Using this example where the is a 10V AC
supply at 60 Hz applied to a simple capacitive
circuit with a 100 μF capacitor, let’s calculate
the current.
XC =1 / 2 π f C

 
 =
 / 2 x 3.1416 x 60 x (100 x 10-6)
     1

 
 =
 6.52 Ω
     2
I
=
 V / XC

 
 =
 10 / 26.52

 
 =
 0.3770 A
3.3.6 Example 2

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3.3.6 Example 2

  • 1. Example 2: How much voltage must you apply across a 10μF capacitor to cause an AC current of 25mA at 50 Hz to flow
  • 2. 25mA at 50 Hz to flow XC = 1 / 2 π f C = 1 / 2 x 3.1416 x 50 x 10 x 10-6 = 318.5 Ω
  • 3. Now, V = I XC = 25 x 10-3 x 318.5 = 7.96 V
  • 4.
  • 5. Example 3: Using this example where the is a 10V AC supply at 60 Hz applied to a simple capacitive circuit with a 100 μF capacitor, let’s calculate the current.
  • 6. XC =1 / 2 π f C = / 2 x 3.1416 x 60 x (100 x 10-6) 1 = 6.52 Ω 2
  • 7. I = V / XC = 10 / 26.52 = 0.3770 A