32- What is the formula for hydrosulfuric acid- What is the formula fo.docx
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32. What is the formula for hydrosulfuric acid? What is the formula for sulfurous acid? What is the formula for sulfuric acid? What is an indicator? This is actually one question. Solution Answer: Hydrosulfuric acid: H2S. The oxidation state of Sulfur=-2 and H=+1, so the charge is balanced when we use two Hydrogen\'s. Basically acid means it contains Hydrogen ions. Sulfurous acid: H2SO3. It is weak and unstable acid. It is formed when SO2 reacts with water. It is intermediate in acid rain. Sulfuric acid: H2SO4. It is stable strong acid and highly exothermic when it dissolved in water. Indicator: The substances which show a color change when react with acids and bases. Example: Litmus paper. Blue litmus turns into red when it is contacted with acid and red litmus turns into blue when it is contacted with base. Thanks and please let me know if you have any doubt. .
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Yes. Boiling point is a physical property. Becuase during this process there is a change of physical state of the substance only but there is no change in chemical composition.
4.
Take a known quantity of the unknown substance and add it to the measuring jas containing full of water. During this process the substance replaces water and mesure the volume fo the water that is replaced by the unknown. It gives the volume of the unknown occupied.
Therefore,
density = mass / volume
5.
Yes. Ethanol is completely miscible with water because ethanol forms intermolecular hydrogen bonds with water molecules.
.
3- How does a via allow a designer to route traces across one another.docx
3. How does a via allow a designer to route traces across one another without creating a short circuit between them?
4. List few reasons on why most modern PCB
Solution
Ground is frequently the most common connection in the circuit. Having it continuous on the bottom layer usually makes the most sense for circuit routing.
Pond routing method has been classified into following types for different situations.
Storage indication:
This method is widely using. It is very fast and stable. It evaluates one node at a time.
Dynamic storage indication:
It is same as storage-indication, but re-evaluates outlets devices at each time step. Then it allows ponds to respond to varying tailwater.
Simultaneous routing:
It re-evaluates the outlets at each time step, like DSI. It doesn
.
3- Assume that the DS register contains 0100 and register SI contains.docx
3. Assume that the DS register contains 0100 and register SI contains 0020. What is the result of following instruction LES DI, [SI] Where the content of memory Location is as follows:
Solution
the command LES DI , [SI] does the following:
it takes the pointer of SI , i.e the address of the memory location SI and breaks it into lower bits and upper bits.
then the lower bits are stored in DI and the upper bits are stored in ES.
so address of SI is 1027 .
lower bit is 27 and upper bit is 10.
27 will be stored in DI . and 10 will be saved in ES.
now DI is the lower bit of the register DS.
as it is said initially DS 0100 so, initially DI is 00.
which is changed to 27.
now DS is 0127.
.
3) why did you collect the aqueous layer inthe extraction- Dont organi.docx
3) why did you collect the aqueous layer inthe extraction? Don’t organic molecules dissolve in organic solvents?
4) 1-pentanol contains an -OH group. Why does it form two separate layers with water?
Solution
3. ans). we collect aqueous layer in the extraction, because organic salts are dissolved in the aqueous layer, which further can be recovered by treating it with acid or base.
yes, organic solvents do dissolve in organic layer. but one of the moleule in the mixture is acidic or basic enough to react with base or acid that has been added in the process of extraction respectively, to form salt and moves from organic layer to aqueous layer.
4.ans.)1-pentanol contains an -OH group and it also contains 5 carbon long chain of hydrophobic group which is the reason for 1-pentanol not to dissolve in water and hence it forms two seperate layers with water.
.
3 of 17 Problem 11-31 A mass is oscillating with amplitude A at the en.docx
A mass is oscillating on a spring with amplitude A. The problem asks how far from the equilibrium position the mass is when the elastic potential energy equals half the kinetic energy. The solution shows that when this condition is met, the distance x is equal to 1/sqrt(3) * A.
4) The mold production equipment that uses impeller blades to -ing san.docx
4) The mold production equipment that uses impeller blades to ?ing sand into a ?ask at a reasonably high velocity.
5) What type of equipment is used to pack sand around the pattern by lifting, dropping and squeezing?
6) What is the pattern material used by the evaporation mold process?
7)What material is used to make permanent molds?
Solution
4)
the mould production equipments are used in impeller blades preparation.
green sand,drag,cope, runner and raisers.
5)pack sand around the pattern using equipments are jolting machines,squeezing machine, sand slinger and ramp.
6)polymer spun materials are coated on the pattern material so it can resist the evaporation mold
7)permanent mould are reusable molds so we can prefer metals.
.
4) Get a medium test tube and fill it with about 5 mL of water and a f.docx
4) Get a medium test tube and fill it with about 5 mL of water and a few drops of universal indicator. Take a soda straw and gently blow bubbles into the water. Note what happens to the color of the universal indicator What does the color of the universal indicator tell? Q. Balanced chemical equation:
Solution
1. Answer a) Water turns to green when universal indicator is added to it as water is neutral. When soda straw is used to blow bubbles, As straw is basic it reactes with universal indicatoor to give greenish blue colour.
b) Reaction involved can be : H 2 O + NaOH -------> Na - + H 3 O +
.
4) (30 pts) What is pH of (show all your work) A) 0-038 M solution of.docx
4) (30 pts) What is pH of (show all your work) A) 0.038 M solution of KOH B) 0.0022 M solution of Ca(OH)2 D C) 0.038 M solution of HF D) 0.0022 M solution of H2S E) 000022 M solution of H2S
Solution
Answer -
A-
pOH = -log(OH-) =-log(0.038) = 1.42
We know that,
pH +pOH = 14
pH = 14-1.42 = 12.58
B. 1 mol of Ca(OH)2 produce two moles of OH-
pOH = -log(2*0.0022) = 2.356
pH = 14-2.356 = 11.644
C- HF produce H+ ions in the solution.
pH= -log(H+) = -log( 0.038) = 1.42
D. it gives twom moles of H+ for each mole of H2S
pH = -log(2*0.0022) = 2.356
E. SAme as above-
pH =-log(0.00022*2) = 3.356
.
3x + (-3y) - (4x) + y -Solution -3x + (-3y) - (4x) + y -3x-(4x) + (-3.docx
3x + (-3y) - (4x) + y =
Solution
=3x + (-3y) - (4x) + y
=3x-(4x) + (-3y)+y Move like terms closer to each other to make sure you see them all
=-1x + -2y combine the coefficients of the variables
=-x-2y
.
37) The Schwarzschild radius of a black hole is that radial distance f.docx
37) The Schwarzschild radius of a black hole is that radial distance from the center of a sphere within which not even light can escape. It was first discovered mathematically by Schwarzschild in 1916 after Einstein published his general relativity theory. It can be calculated from a star\'s mass M as: R- 2GM/c2. Take the radius of both stars A and B as the Schwarzschild radius. If the mass of star A is twice as much as the mass of star B, the average density of star A, compared to star B will be A) the same. B) twice as much. C) half as much. D) four times as much. E) one-fourth as much.
Solution
The schwarzcchild radius of star A will also be twice that of star B
Density of star A is proportional to 2M/(2*R)³=M/4R³
Density of start B=M/R³
Therrfore, density of star A is one fourth that of start B
Correct option is E
.
36- During the year ended December 31- 2015- Anderson Hospital (operat.docx
36. During the year ended December 31, 2015, Anderson Hospital (operated as a private not-for-profit entity) received and incurred the following: How should this hospital report each of these items?
Solution
Explanation:
Donate Medicines
Donate Services (replacing salaried workers)
Donate Services (not replacing salaried workers) = Not Recorded
Interest Income = Revenue is an increase in unrestricted net assets
Charges to patients = Increase in unrestricted net assets shown as net patient service revenues.
Charity Care
Bad debts = Amount is anticipated and recorded as an expense that decrease unrestricted net assets and reduce carrying amount of the receivables
.
30- Higher speed image receptors generally produce images with a) Bet.docx
30. Higher speed image receptors generally produce images with
a)Â Â Â Â Â Â Â Â Â Â Â Â Â Better resolution
b)Â Â Â Â Â Â Â Â Â Â Â Â Â Increased noise
c)Â Â Â Â Â Â Â Â Â Â Â Â Â Higher contrast
d)Â Â Â Â Â Â Â Â Â Â Â Â Â Increased density
e)Â Â Â Â Â Â Â Â Â Â Â Â Wide latitude
Solution
Option B is correct
Higher speed image receptors generally produce images with increased noise as it have to recieve images at higher speeds
.
Problem 3 Given 5-81 g of C11H22011- calculate the following- moles of.docx
Problem 3 Given 5.81 g of C11H22011, calculate the following: moles of C11H22011 0.0176 mol You are correct Your receipt no. is Previous Tries 4 4 number of oxygen atoms in C11H22011 1oxygen atoms Submit Answr Incorrect. Tries 1/5 Previous Tries mass of carbon atoms in C11H22011 Submit Answer Incorrect. Tries 1/5 Previous Tries
Solution
Given that
5.81 g of C11H22O11
Molar mass of C11H22O11= 330.286 g/mol
Numbe rof mole s= amount in g/ molar mass
=5.81g / 330.286 g/mol
=0.0176 mole C11H22O11
1 mole of C11H22O11 contains =11 mole O
And 1 mole = 6.022*10^23 atoms
So 1 mole C11H22O11=6.6242 *10^24 atoms O
There are 11 mole C
Mass of C = number of mole s* molar mass
=11*12.01
= 132.11 g C
.
QUESTION 11 Another name for the spread in a Eurocurrency loan is the.docx
QUESTION 11
Another name for the spread in a Eurocurrency loan is the _______.
drawdown
term
LIBOR rate
Margin
5 points
QUESTION 12
Leading and lagging strategies have several advantages EXCEPT
no formal note of indebtedness is needed
governments are less like to interfere with payments on intercompany accounts
interest must be charged on all intercompany accounts
intercompany accounts up to six months are interest free
Solution
11- Margin
12- no formal note of indebtedness is needed.
.
QUESTION 1 The following complex is yellow in color What color of ligh.docx
QUESTION 1 The following complex is yellow in color What color of light does this complex absorb? O yellow O green ?blue QUESTION 2 The following complex is yellow in color: Is this complex likely to be low spin or high spin? O low spin ?high spin QUESTION 3 The following complex is yellow in color How many unpaired electrons does this complex poss0s8?
Solution
1. Any substance gives the color complementary to the color which it absorbs . The complementary color of yellow is violet .Hence it absorbs violet colour of light and appears yellow in colour.
2. Fe is in +3 oxidation state and 3d^5 configuration and thus high spin complex due presence of 5 unpaired e-s .Secondly as it shows colour so it is high spin as color is a property of inspired e-s .
3. 5 unpaired e-s as calculated in 2 question.
.
Propane (molar mass 44-11 g-mol) boils at -42-1C- Ethanol has almost t.docx
Propane (molar mass 44.11 g/mol) boils at -42.1°C. Ethanol has almost the same molar mass (46.07 g/mol), but boils at 78.5°C. Which of the following BEST explains the reason for the large discrepancy in boiling point?
A. Â Â Propane is ionic and, therefore, has a lower boiling point.
B. Â Â Ethanol is ionic and, therefore, has a higher boiling point.
C. Â Â Both compounds only exhibit van der Waals forces.
D. Â Â Both compounds are polar. Ethanol is more polar than Propane.
E. Â Â Ethanol exhibits hydrogen bonding.
F. Â Â Propane exhibits hydrogen bonding.
Solution
ethanol is having high boiling point than propane
because in ethanol, the -OH group can form intermolecular hydrogen bonding. so there is association of molecules
which it leads to greater boiling point.
whereas in case of propane, no such hydrogen bonding is possible.
.
QUESTION 1 1 points S Saved What is the concentration of H2S in a satu.docx
QUESTION 1 1 points S Saved What is the concentration of H2S in a saturated solution of H2S? Not enough information in the lab manual to decide. Smaller than 1.0 x 10-8 1.0 M O Greater than 6 M 1.3 M 0.10 M QUESTION 2 4 points Save Answer Match each type of ion to the method used to separate it Silver ions A. Precipitated by adding HCl. B. Precipitated using H2S in a very acidic sol C. Precipitated using H2S in a slightly basic solution. D. Precipitated by adding ammonium carbonate. E. Precipitated by adding sodium sulfide in a weakly basic uion Copper (1) ions Zinc ions Calcium ions solution.
Solution
Ans 1 : 0.10 M
The concentration of H2S in a saturated solution of H2S is 0.10 M.
The solubility of H2S is 0.00016 g / 100 g
So the concentration = number of moles / volume of solution in L
which comes approximately 0.10 M
.
Question 1 (4 points) Provide the correct family name for the structur.docx
Question 1 (4 points) Provide the correct family name for the structure given. The question does not ask for the name of the functional group. Spelling counts. Save
Solution
Answer = Family Name is = Alcohol
the alcohol general formula is R-OH
and the above compound is alchol group
if carbon attached to 3 hydrogens then it is Methyl Alcohol
2 hydrogens and 1 carbon then it is Primary Alcohol
1 hydrogen and 2 carbons then it is Secondary Alcohol
3 carbons then it is Tertiary Alcohol
.
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