3- Assume that the DS register contains 0100 and register SI contains.docx
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3. Assume that the DS register contains 0100 and register SI contains 0020. What is the result of following instruction LES DI, [SI] Where the content of memory Location is as follows: Solution the command LES DI , [SI] does the following: it takes the pointer of SI , i.e the address of the memory location SI and breaks it into lower bits and upper bits. then the lower bits are stored in DI and the upper bits are stored in ES. so address of SI is 1027 . lower bit is 27 and upper bit is 10. 27 will be stored in DI . and 10 will be saved in ES. now DI is the lower bit of the register DS. as it is said initially DS 0100 so, initially DI is 00. which is changed to 27. now DS is 0127. .
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![3. Assume that the DS register contains 0100 and register SI contains 0020. What is the result of
following instruction LES DI, [SI] Where the content of memory Location is as follows:
Solution
the command LES DI , [SI] does the following:
it takes the pointer of SI , i.e the address of the memory location SI and breaks it into lower bits
and upper bits.
then the lower bits are stored in DI and the upper bits are stored in ES.
so address of SI is 1027 .
lower bit is 27 and upper bit is 10.
27 will be stored in DI . and 10 will be saved in ES.
now DI is the lower bit of the register DS.
as it is said initially DS 0100 so, initially DI is 00.
which is changed to 27.
now DS is 0127.](https://image.slidesharecdn.com/3-assumethatthedsregistercontains0100andregistersicontains-230126183259-373873f7/85/3-Assume-that-the-DS-register-contains-0100-and-register-SI-contains-docx-1-320.jpg)
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3- The affinity of major cations for soil surfaces typically follows t.docx
3. The affinity of major cations for soil surfaces typically follows this order: Na
Solution
3(a) Higher affinity of ions for soil surface indicates the greater possibility of its retention in the soil i.e., more tightly bound to the soil. This affinity generally increase with charge of ions and reduces with increase in hydrated ionic size. Thus introduction of higher concentration of sodium ion will not affect the composition of the soil much and will increase the sodium ion concentration in the pool water.
(b) Zinc cation is doubly positively charged. Its hydrated radius is much greater than Ca 2+ but slightly greater Mg 2+ . This would lead to similar soil affinity of zinc and magnesium cations. Thus affinity of soil for Zn 2+ is much greater than Na + . Thus there would be no effect of snowmelt water with high sodium concentration on affinity of Zn 2+ for soil.
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3- Review solublity rules and identify each of the following compounds.docx
3. Review solublity rules and identify each of the following compounds as soluble or insoluble in water. State the rule # that applies. NazCO3 CoCO3 K2S BaSO4 Agl Ni(NO3)2 FeS PbCl2 Li20 Mn(C2H302)2 AgCIO3 Sn(SO4)4 Pb(NO3)2 (NH4)2S KI CuSO4 FeF2 AgCl
Solution
all salt of alkali metals and ammonium are soluble in water. All nitrate salts are soluble in water
Na2CO3 soluble
CoCO3 insoluble
K2S soluble
BaSO4 insoluble
Ni(NO3)2 soluble
FeS insoluble
PbCl2 insoluble
Li2O soluble
Mn(C2H3O2)2 soluble
AgClO3 soluble
Sn(SO4)4 insoluble
Pb(NO3)2 soluble
(NH4)2S soluble
KI soluble
CuSO4 soluble
FeF2 insoluble
AgCl soluble
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3- Is the boiling point of a chemical a physical property or chemical.docx
3. Is the boiling point of a chemical a physical property or chemical property? 4. How can we determine the density of a unknown solid? Write a procedur e. 5. Do you think ethanol soluble in water?
Solution
3.
Yes. Boiling point is a physical property. Becuase during this process there is a change of physical state of the substance only but there is no change in chemical composition.
4.
Take a known quantity of the unknown substance and add it to the measuring jas containing full of water. During this process the substance replaces water and mesure the volume fo the water that is replaced by the unknown. It gives the volume of the unknown occupied.
Therefore,
density = mass / volume
5.
Yes. Ethanol is completely miscible with water because ethanol forms intermolecular hydrogen bonds with water molecules.
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3- How does a via allow a designer to route traces across one another.docx
3. How does a via allow a designer to route traces across one another without creating a short circuit between them?
4. List few reasons on why most modern PCB
Solution
Ground is frequently the most common connection in the circuit. Having it continuous on the bottom layer usually makes the most sense for circuit routing.
Pond routing method has been classified into following types for different situations.
Storage indication:
This method is widely using. It is very fast and stable. It evaluates one node at a time.
Dynamic storage indication:
It is same as storage-indication, but re-evaluates outlets devices at each time step. Then it allows ponds to respond to varying tailwater.
Simultaneous routing:
It re-evaluates the outlets at each time step, like DSI. It doesn
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3) why did you collect the aqueous layer inthe extraction- Dont organi.docx
3) why did you collect the aqueous layer inthe extraction? Don’t organic molecules dissolve in organic solvents?
4) 1-pentanol contains an -OH group. Why does it form two separate layers with water?
Solution
3. ans). we collect aqueous layer in the extraction, because organic salts are dissolved in the aqueous layer, which further can be recovered by treating it with acid or base.
yes, organic solvents do dissolve in organic layer. but one of the moleule in the mixture is acidic or basic enough to react with base or acid that has been added in the process of extraction respectively, to form salt and moves from organic layer to aqueous layer.
4.ans.)1-pentanol contains an -OH group and it also contains 5 carbon long chain of hydrophobic group which is the reason for 1-pentanol not to dissolve in water and hence it forms two seperate layers with water.
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3 of 17 Problem 11-31 A mass is oscillating with amplitude A at the en.docx
A mass is oscillating on a spring with amplitude A. The problem asks how far from the equilibrium position the mass is when the elastic potential energy equals half the kinetic energy. The solution shows that when this condition is met, the distance x is equal to 1/sqrt(3) * A.
4) The mold production equipment that uses impeller blades to -ing san.docx
4) The mold production equipment that uses impeller blades to ?ing sand into a ?ask at a reasonably high velocity.
5) What type of equipment is used to pack sand around the pattern by lifting, dropping and squeezing?
6) What is the pattern material used by the evaporation mold process?
7)What material is used to make permanent molds?
Solution
4)
the mould production equipments are used in impeller blades preparation.
green sand,drag,cope, runner and raisers.
5)pack sand around the pattern using equipments are jolting machines,squeezing machine, sand slinger and ramp.
6)polymer spun materials are coated on the pattern material so it can resist the evaporation mold
7)permanent mould are reusable molds so we can prefer metals.
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4) Get a medium test tube and fill it with about 5 mL of water and a f.docx
4) Get a medium test tube and fill it with about 5 mL of water and a few drops of universal indicator. Take a soda straw and gently blow bubbles into the water. Note what happens to the color of the universal indicator What does the color of the universal indicator tell? Q. Balanced chemical equation:
Solution
1. Answer a) Water turns to green when universal indicator is added to it as water is neutral. When soda straw is used to blow bubbles, As straw is basic it reactes with universal indicatoor to give greenish blue colour.
b) Reaction involved can be : H 2 O + NaOH -------> Na - + H 3 O +
.
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3- The affinity of major cations for soil surfaces typically follows t.docx
3. The affinity of major cations for soil surfaces typically follows this order: Na
Solution
3(a) Higher affinity of ions for soil surface indicates the greater possibility of its retention in the soil i.e., more tightly bound to the soil. This affinity generally increase with charge of ions and reduces with increase in hydrated ionic size. Thus introduction of higher concentration of sodium ion will not affect the composition of the soil much and will increase the sodium ion concentration in the pool water.
(b) Zinc cation is doubly positively charged. Its hydrated radius is much greater than Ca 2+ but slightly greater Mg 2+ . This would lead to similar soil affinity of zinc and magnesium cations. Thus affinity of soil for Zn 2+ is much greater than Na + . Thus there would be no effect of snowmelt water with high sodium concentration on affinity of Zn 2+ for soil.
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3- Review solublity rules and identify each of the following compounds.docx
3. Review solublity rules and identify each of the following compounds as soluble or insoluble in water. State the rule # that applies. NazCO3 CoCO3 K2S BaSO4 Agl Ni(NO3)2 FeS PbCl2 Li20 Mn(C2H302)2 AgCIO3 Sn(SO4)4 Pb(NO3)2 (NH4)2S KI CuSO4 FeF2 AgCl
Solution
all salt of alkali metals and ammonium are soluble in water. All nitrate salts are soluble in water
Na2CO3 soluble
CoCO3 insoluble
K2S soluble
BaSO4 insoluble
Ni(NO3)2 soluble
FeS insoluble
PbCl2 insoluble
Li2O soluble
Mn(C2H3O2)2 soluble
AgClO3 soluble
Sn(SO4)4 insoluble
Pb(NO3)2 soluble
(NH4)2S soluble
KI soluble
CuSO4 soluble
FeF2 insoluble
AgCl soluble
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3- Is the boiling point of a chemical a physical property or chemical.docx
3. Is the boiling point of a chemical a physical property or chemical property? 4. How can we determine the density of a unknown solid? Write a procedur e. 5. Do you think ethanol soluble in water?
Solution
3.
Yes. Boiling point is a physical property. Becuase during this process there is a change of physical state of the substance only but there is no change in chemical composition.
4.
Take a known quantity of the unknown substance and add it to the measuring jas containing full of water. During this process the substance replaces water and mesure the volume fo the water that is replaced by the unknown. It gives the volume of the unknown occupied.
Therefore,
density = mass / volume
5.
Yes. Ethanol is completely miscible with water because ethanol forms intermolecular hydrogen bonds with water molecules.
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3- How does a via allow a designer to route traces across one another.docx
3. How does a via allow a designer to route traces across one another without creating a short circuit between them?
4. List few reasons on why most modern PCB
Solution
Ground is frequently the most common connection in the circuit. Having it continuous on the bottom layer usually makes the most sense for circuit routing.
Pond routing method has been classified into following types for different situations.
Storage indication:
This method is widely using. It is very fast and stable. It evaluates one node at a time.
Dynamic storage indication:
It is same as storage-indication, but re-evaluates outlets devices at each time step. Then it allows ponds to respond to varying tailwater.
Simultaneous routing:
It re-evaluates the outlets at each time step, like DSI. It doesn
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3) why did you collect the aqueous layer inthe extraction- Dont organi.docx
3) why did you collect the aqueous layer inthe extraction? Don’t organic molecules dissolve in organic solvents?
4) 1-pentanol contains an -OH group. Why does it form two separate layers with water?
Solution
3. ans). we collect aqueous layer in the extraction, because organic salts are dissolved in the aqueous layer, which further can be recovered by treating it with acid or base.
yes, organic solvents do dissolve in organic layer. but one of the moleule in the mixture is acidic or basic enough to react with base or acid that has been added in the process of extraction respectively, to form salt and moves from organic layer to aqueous layer.
4.ans.)1-pentanol contains an -OH group and it also contains 5 carbon long chain of hydrophobic group which is the reason for 1-pentanol not to dissolve in water and hence it forms two seperate layers with water.
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3 of 17 Problem 11-31 A mass is oscillating with amplitude A at the en.docx
A mass is oscillating on a spring with amplitude A. The problem asks how far from the equilibrium position the mass is when the elastic potential energy equals half the kinetic energy. The solution shows that when this condition is met, the distance x is equal to 1/sqrt(3) * A.
4) The mold production equipment that uses impeller blades to -ing san.docx
4) The mold production equipment that uses impeller blades to ?ing sand into a ?ask at a reasonably high velocity.
5) What type of equipment is used to pack sand around the pattern by lifting, dropping and squeezing?
6) What is the pattern material used by the evaporation mold process?
7)What material is used to make permanent molds?
Solution
4)
the mould production equipments are used in impeller blades preparation.
green sand,drag,cope, runner and raisers.
5)pack sand around the pattern using equipments are jolting machines,squeezing machine, sand slinger and ramp.
6)polymer spun materials are coated on the pattern material so it can resist the evaporation mold
7)permanent mould are reusable molds so we can prefer metals.
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4) Get a medium test tube and fill it with about 5 mL of water and a f.docx
4) Get a medium test tube and fill it with about 5 mL of water and a few drops of universal indicator. Take a soda straw and gently blow bubbles into the water. Note what happens to the color of the universal indicator What does the color of the universal indicator tell? Q. Balanced chemical equation:
Solution
1. Answer a) Water turns to green when universal indicator is added to it as water is neutral. When soda straw is used to blow bubbles, As straw is basic it reactes with universal indicatoor to give greenish blue colour.
b) Reaction involved can be : H 2 O + NaOH -------> Na - + H 3 O +
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4) (30 pts) What is pH of (show all your work) A) 0-038 M solution of.docx
4) (30 pts) What is pH of (show all your work) A) 0.038 M solution of KOH B) 0.0022 M solution of Ca(OH)2 D C) 0.038 M solution of HF D) 0.0022 M solution of H2S E) 000022 M solution of H2S
Solution
Answer -
A-
pOH = -log(OH-) =-log(0.038) = 1.42
We know that,
pH +pOH = 14
pH = 14-1.42 = 12.58
B. 1 mol of Ca(OH)2 produce two moles of OH-
pOH = -log(2*0.0022) = 2.356
pH = 14-2.356 = 11.644
C- HF produce H+ ions in the solution.
pH= -log(H+) = -log( 0.038) = 1.42
D. it gives twom moles of H+ for each mole of H2S
pH = -log(2*0.0022) = 2.356
E. SAme as above-
pH =-log(0.00022*2) = 3.356
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3x + (-3y) - (4x) + y -Solution -3x + (-3y) - (4x) + y -3x-(4x) + (-3.docx
3x + (-3y) - (4x) + y =
Solution
=3x + (-3y) - (4x) + y
=3x-(4x) + (-3y)+y Move like terms closer to each other to make sure you see them all
=-1x + -2y combine the coefficients of the variables
=-x-2y
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37) The Schwarzschild radius of a black hole is that radial distance f.docx
37) The Schwarzschild radius of a black hole is that radial distance from the center of a sphere within which not even light can escape. It was first discovered mathematically by Schwarzschild in 1916 after Einstein published his general relativity theory. It can be calculated from a star\'s mass M as: R- 2GM/c2. Take the radius of both stars A and B as the Schwarzschild radius. If the mass of star A is twice as much as the mass of star B, the average density of star A, compared to star B will be A) the same. B) twice as much. C) half as much. D) four times as much. E) one-fourth as much.
Solution
The schwarzcchild radius of star A will also be twice that of star B
Density of star A is proportional to 2M/(2*R)³=M/4R³
Density of start B=M/R³
Therrfore, density of star A is one fourth that of start B
Correct option is E
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36- During the year ended December 31- 2015- Anderson Hospital (operat.docx
36. During the year ended December 31, 2015, Anderson Hospital (operated as a private not-for-profit entity) received and incurred the following: How should this hospital report each of these items?
Solution
Explanation:
Donate Medicines
Donate Services (replacing salaried workers)
Donate Services (not replacing salaried workers) = Not Recorded
Interest Income = Revenue is an increase in unrestricted net assets
Charges to patients = Increase in unrestricted net assets shown as net patient service revenues.
Charity Care
Bad debts = Amount is anticipated and recorded as an expense that decrease unrestricted net assets and reduce carrying amount of the receivables
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32- What is the formula for hydrosulfuric acid- What is the formula fo.docx
32. What is the formula for hydrosulfuric acid? What is the formula for sulfurous acid? What is the
formula for sulfuric acid? What is an indicator?
This is actually one question.
Solution
Answer:
Hydrosulfuric acid: H2S. The oxidation state of Sulfur=-2 and H=+1, so the charge is balanced when we use two Hydrogen\'s.
Basically acid means it contains Hydrogen ions.
Sulfurous acid: H2SO3. It is weak and unstable acid. It is formed when SO2 reacts with water. It is intermediate in acid rain.
Sulfuric acid: H2SO4. It is stable strong acid and highly exothermic when it dissolved in water.
Indicator: The substances which show a color change when react with acids and bases.
Example: Litmus paper. Blue litmus turns into red when it is contacted with acid and red litmus turns into blue when it is contacted with base.
Thanks and please let me know if you have any doubt.
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30- Higher speed image receptors generally produce images with a) Bet.docx
30. Higher speed image receptors generally produce images with
a)Â Â Â Â Â Â Â Â Â Â Â Â Â Better resolution
b)Â Â Â Â Â Â Â Â Â Â Â Â Â Increased noise
c)Â Â Â Â Â Â Â Â Â Â Â Â Â Higher contrast
d)Â Â Â Â Â Â Â Â Â Â Â Â Â Increased density
e)Â Â Â Â Â Â Â Â Â Â Â Â Wide latitude
Solution
Option B is correct
Higher speed image receptors generally produce images with increased noise as it have to recieve images at higher speeds
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Problem 3 Given 5-81 g of C11H22011- calculate the following- moles of.docx
Problem 3 Given 5.81 g of C11H22011, calculate the following: moles of C11H22011 0.0176 mol You are correct Your receipt no. is Previous Tries 4 4 number of oxygen atoms in C11H22011 1oxygen atoms Submit Answr Incorrect. Tries 1/5 Previous Tries mass of carbon atoms in C11H22011 Submit Answer Incorrect. Tries 1/5 Previous Tries
Solution
Given that
5.81 g of C11H22O11
Molar mass of C11H22O11= 330.286 g/mol
Numbe rof mole s= amount in g/ molar mass
=5.81g / 330.286 g/mol
=0.0176 mole C11H22O11
1 mole of C11H22O11 contains =11 mole O
And 1 mole = 6.022*10^23 atoms
So 1 mole C11H22O11=6.6242 *10^24 atoms O
There are 11 mole C
Mass of C = number of mole s* molar mass
=11*12.01
= 132.11 g C
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QUESTION 11 Another name for the spread in a Eurocurrency loan is the.docx
QUESTION 11
Another name for the spread in a Eurocurrency loan is the _______.
drawdown
term
LIBOR rate
Margin
5 points
QUESTION 12
Leading and lagging strategies have several advantages EXCEPT
no formal note of indebtedness is needed
governments are less like to interfere with payments on intercompany accounts
interest must be charged on all intercompany accounts
intercompany accounts up to six months are interest free
Solution
11- Margin
12- no formal note of indebtedness is needed.
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QUESTION 1 The following complex is yellow in color What color of ligh.docx
QUESTION 1 The following complex is yellow in color What color of light does this complex absorb? O yellow O green ?blue QUESTION 2 The following complex is yellow in color: Is this complex likely to be low spin or high spin? O low spin ?high spin QUESTION 3 The following complex is yellow in color How many unpaired electrons does this complex poss0s8?
Solution
1. Any substance gives the color complementary to the color which it absorbs . The complementary color of yellow is violet .Hence it absorbs violet colour of light and appears yellow in colour.
2. Fe is in +3 oxidation state and 3d^5 configuration and thus high spin complex due presence of 5 unpaired e-s .Secondly as it shows colour so it is high spin as color is a property of inspired e-s .
3. 5 unpaired e-s as calculated in 2 question.
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Propane (molar mass 44-11 g-mol) boils at -42-1C- Ethanol has almost t.docx
Propane (molar mass 44.11 g/mol) boils at -42.1°C. Ethanol has almost the same molar mass (46.07 g/mol), but boils at 78.5°C. Which of the following BEST explains the reason for the large discrepancy in boiling point?
A. Â Â Propane is ionic and, therefore, has a lower boiling point.
B. Â Â Ethanol is ionic and, therefore, has a higher boiling point.
C. Â Â Both compounds only exhibit van der Waals forces.
D. Â Â Both compounds are polar. Ethanol is more polar than Propane.
E. Â Â Ethanol exhibits hydrogen bonding.
F. Â Â Propane exhibits hydrogen bonding.
Solution
ethanol is having high boiling point than propane
because in ethanol, the -OH group can form intermolecular hydrogen bonding. so there is association of molecules
which it leads to greater boiling point.
whereas in case of propane, no such hydrogen bonding is possible.
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QUESTION 1 1 points S Saved What is the concentration of H2S in a satu.docx
QUESTION 1 1 points S Saved What is the concentration of H2S in a saturated solution of H2S? Not enough information in the lab manual to decide. Smaller than 1.0 x 10-8 1.0 M O Greater than 6 M 1.3 M 0.10 M QUESTION 2 4 points Save Answer Match each type of ion to the method used to separate it Silver ions A. Precipitated by adding HCl. B. Precipitated using H2S in a very acidic sol C. Precipitated using H2S in a slightly basic solution. D. Precipitated by adding ammonium carbonate. E. Precipitated by adding sodium sulfide in a weakly basic uion Copper (1) ions Zinc ions Calcium ions solution.
Solution
Ans 1 : 0.10 M
The concentration of H2S in a saturated solution of H2S is 0.10 M.
The solubility of H2S is 0.00016 g / 100 g
So the concentration = number of moles / volume of solution in L
which comes approximately 0.10 M
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Question 1 (4 points) Provide the correct family name for the structur.docx
Question 1 (4 points) Provide the correct family name for the structure given. The question does not ask for the name of the functional group. Spelling counts. Save
Solution
Answer = Family Name is = Alcohol
the alcohol general formula is R-OH
and the above compound is alchol group
if carbon attached to 3 hydrogens then it is Methyl Alcohol
2 hydrogens and 1 carbon then it is Primary Alcohol
1 hydrogen and 2 carbons then it is Secondary Alcohol
3 carbons then it is Tertiary Alcohol
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Q-12-13-14 Double Replacement reactions 12- barium acetate + zinc iodi.docx
Q:12,13,14
Double Replacement reactions 12. barium acetate + zinc iodide 13. hydrofluoric acid + lithium hydroxide- 14. What mass of precipitate forms from 1.0 g of lead (IV) chloride mixed with sodium oxide?
Solution
12.Barium acetate upon reaction with zinc iodide produces Barium iodide and zinc acetate.
Ba(C2H3O2)2 (aq) + ZnI2 (aq) --> BaI2 (aq) + Zn(C2H3O2)2 (s)
13.Hydrofluoric acid upon reaction with lithium hydroxide produces Lithium fluoride and water.
HF(aq)+LiOH(aq)----->LiF(aq)+H2O(l)
14.The balanced equation is
PbCl4 +2Na2O---> PbO2(s)+4NaCl
Molarmass (g/mol). 349. 239.2
1 mol=349 g of PbCl4 produces 1 mol= 239.2 g of PbO2 precipitate
1 g of PbCl4 produces (239.2/349)=0.685 g of precipitate PbO2
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Q1 from the following information Prepare journal entries to record th.docx
Q1 from the following information Prepare journal entries to record the issue of shares, declaration and payment of dividend . on June 1, 2014. Jaguar & Co issued 50,000 shares of $10 each. . The corporation has 500,000 shares outstanding. on January 1, 2015. . on Jan 1, 2015 The company declared $1 per share cash dividend to stockholders. . January 10 is the date of record. . On January 20, is the date of payment of dividend?
Solution
Journal Entries
Jun 1\' 2014 Cash A/c...................Dr 500000
To Capital A/c 500000
On record date :
Jan 10\'2015 Dividends Delared A/c........Dr 500000
To Dividend Payable A/c 500000
On payment of dividend:
Jan 20 \'2015 Dividend payable A/c ....Dr 500000
To Cash A/c 500000
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Python 3-5-1 Write a function create_2d that takes as input two intege.docx
Python 3.5.1
Write a function create_2d that takes as input two integers height and width, and that creates and returns a 2D list (i.e., a list of lists) with values that are the row number multiplied by the column number.
Solution
def create_2d(height,width):
list2=[]#list for storing list of lists
for x in range(height):#outer loop for rows
list1=[]#list inner
for y in range(width):#inner loop for columns
list1.append(x*y)#row * column
list2.append(list1)#adding list1 with products of single row to list2
print(list2)#prints list
create_2d(2,3) #function calling
output:
[[0, 0, 0], [0, 1, 2]]
as index number starts from zero so
matrix will be
0*0 0*1 0*2
1*0 1*1 1*2
.
Puleva Milenario SA- a company located in Toledo- Spain- manufactures.docx
Puleva Milenario SA, a company located in Toledo, Spain, manufactures and sells two models of luxuriously finished cutlery
Solution
1) a) Prepare a contribution format income statement showing both euro and percent columns for each product and for the company as a whole. ( Input all amounts as positive values except losses which should be indicated by minus sign. Round your euro answers to 2 decimal places. Omit the \"
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public class forLoop public static void main(Stringp-- args) { for(i -.docx
public class forLoop
public static void main(Stringp[] args)
{
for(i = 4, i < 20, i++)
{
System.out.println(i)
}
}
Please answer all of the following questions: Please put Question numbers with responses and explanations
Question 1: What would the .java file be named?
Question 2: What bugs would need to be fixed for this program to work? (Hint: there are 4)
Question 3: The program will still work, but what programming styles not being adhered to?
Question 4: How many iterations occur before the for loop terminates?
Question 5: What is the last integer printed before termination?
Solution
you havent declared datatype for i;
for(int i=0, i<20, i++)
then it will work and the loop runs untill i becomes 21
so loop runs 16 times
last intezer is 20
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Provide an example of aquifer and geologic properties that lend to one.docx
Provide an example of aquifer and geologic properties that lend to one of the four possible saturated hydraulic conductivity combinations of heterogeneity/homogeneity and isotropy/anisotropy? What led to the existence of this combination? How might this affect the movement of groundwater?
Solution
Aquifier is a body of permeable rock which can contain or transmit water
An aquifier with homogeneous combination will have same properties at all locations which vary little in K,n,b and constant in T and S
An aquifier with heterogenous combination will vary
In isotopy condition the hydraullic properties are equal in all directions
In anisotropy condition one or more hydraullic properties flow in the direction of flow
Mechanical chemical and thermal engeries cause this combination
The moment of flow depends on gravity and molecular attraction
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Provide a stre tor donfoin Haf is osisfet oit the Allowing hata l20 pt.docx
Provide a stre tor donfoin Haf is osisfet oit the Allowing hata l20 pts): has leate formuleC tio gna
Solution
ANSWER:
Structure: Molecular formula C4H6O2 indicates carboxylic acid ester with one unsaturated carbon linkage (double bond).
IR frequency at 2950 and 2700 indicates double bond stretching and frequency at 1710 indicates ester carbonyl group.
NMR shows triplet at 9.6 ppm and doublet at 2.3 ppm.
The predicted structure is
Interpretation:
This is due to tautomer forms.
Singlet due to ester CH3 is not shown in the question
Why not the isomeric compound Vinyl acetate?
The reasons:
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Provide detailed example of what audit working papers would look like-.docx
Provide detailed example of what audit working papers would look like. What are some items you need to include in these working papers and what is the importance of these times?
Solution
Audit Working papers: They are the documents that are used to record all audit evidence that are obtained during the various auditing carried out in the company like Financial statement auditing, Internal auditing, Investigations and informations system auditing.
Some of the items that needs to be included in the working papers are as follows:
1. Heading
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4) (30 pts) What is pH of (show all your work) A) 0-038 M solution of.docx
4) (30 pts) What is pH of (show all your work) A) 0.038 M solution of KOH B) 0.0022 M solution of Ca(OH)2 D C) 0.038 M solution of HF D) 0.0022 M solution of H2S E) 000022 M solution of H2S
Solution
Answer -
A-
pOH = -log(OH-) =-log(0.038) = 1.42
We know that,
pH +pOH = 14
pH = 14-1.42 = 12.58
B. 1 mol of Ca(OH)2 produce two moles of OH-
pOH = -log(2*0.0022) = 2.356
pH = 14-2.356 = 11.644
C- HF produce H+ ions in the solution.
pH= -log(H+) = -log( 0.038) = 1.42
D. it gives twom moles of H+ for each mole of H2S
pH = -log(2*0.0022) = 2.356
E. SAme as above-
pH =-log(0.00022*2) = 3.356
.
3x + (-3y) - (4x) + y -Solution -3x + (-3y) - (4x) + y -3x-(4x) + (-3.docx
3x + (-3y) - (4x) + y =
Solution
=3x + (-3y) - (4x) + y
=3x-(4x) + (-3y)+y Move like terms closer to each other to make sure you see them all
=-1x + -2y combine the coefficients of the variables
=-x-2y
.
37) The Schwarzschild radius of a black hole is that radial distance f.docx
37) The Schwarzschild radius of a black hole is that radial distance from the center of a sphere within which not even light can escape. It was first discovered mathematically by Schwarzschild in 1916 after Einstein published his general relativity theory. It can be calculated from a star\'s mass M as: R- 2GM/c2. Take the radius of both stars A and B as the Schwarzschild radius. If the mass of star A is twice as much as the mass of star B, the average density of star A, compared to star B will be A) the same. B) twice as much. C) half as much. D) four times as much. E) one-fourth as much.
Solution
The schwarzcchild radius of star A will also be twice that of star B
Density of star A is proportional to 2M/(2*R)³=M/4R³
Density of start B=M/R³
Therrfore, density of star A is one fourth that of start B
Correct option is E
.
36- During the year ended December 31- 2015- Anderson Hospital (operat.docx
36. During the year ended December 31, 2015, Anderson Hospital (operated as a private not-for-profit entity) received and incurred the following: How should this hospital report each of these items?
Solution
Explanation:
Donate Medicines
Donate Services (replacing salaried workers)
Donate Services (not replacing salaried workers) = Not Recorded
Interest Income = Revenue is an increase in unrestricted net assets
Charges to patients = Increase in unrestricted net assets shown as net patient service revenues.
Charity Care
Bad debts = Amount is anticipated and recorded as an expense that decrease unrestricted net assets and reduce carrying amount of the receivables
.
32- What is the formula for hydrosulfuric acid- What is the formula fo.docx
32. What is the formula for hydrosulfuric acid? What is the formula for sulfurous acid? What is the
formula for sulfuric acid? What is an indicator?
This is actually one question.
Solution
Answer:
Hydrosulfuric acid: H2S. The oxidation state of Sulfur=-2 and H=+1, so the charge is balanced when we use two Hydrogen\'s.
Basically acid means it contains Hydrogen ions.
Sulfurous acid: H2SO3. It is weak and unstable acid. It is formed when SO2 reacts with water. It is intermediate in acid rain.
Sulfuric acid: H2SO4. It is stable strong acid and highly exothermic when it dissolved in water.
Indicator: The substances which show a color change when react with acids and bases.
Example: Litmus paper. Blue litmus turns into red when it is contacted with acid and red litmus turns into blue when it is contacted with base.
Thanks and please let me know if you have any doubt.
.
30- Higher speed image receptors generally produce images with a) Bet.docx
30. Higher speed image receptors generally produce images with
a)Â Â Â Â Â Â Â Â Â Â Â Â Â Better resolution
b)Â Â Â Â Â Â Â Â Â Â Â Â Â Increased noise
c)Â Â Â Â Â Â Â Â Â Â Â Â Â Higher contrast
d)Â Â Â Â Â Â Â Â Â Â Â Â Â Increased density
e)Â Â Â Â Â Â Â Â Â Â Â Â Wide latitude
Solution
Option B is correct
Higher speed image receptors generally produce images with increased noise as it have to recieve images at higher speeds
.
Problem 3 Given 5-81 g of C11H22011- calculate the following- moles of.docx
Problem 3 Given 5.81 g of C11H22011, calculate the following: moles of C11H22011 0.0176 mol You are correct Your receipt no. is Previous Tries 4 4 number of oxygen atoms in C11H22011 1oxygen atoms Submit Answr Incorrect. Tries 1/5 Previous Tries mass of carbon atoms in C11H22011 Submit Answer Incorrect. Tries 1/5 Previous Tries
Solution
Given that
5.81 g of C11H22O11
Molar mass of C11H22O11= 330.286 g/mol
Numbe rof mole s= amount in g/ molar mass
=5.81g / 330.286 g/mol
=0.0176 mole C11H22O11
1 mole of C11H22O11 contains =11 mole O
And 1 mole = 6.022*10^23 atoms
So 1 mole C11H22O11=6.6242 *10^24 atoms O
There are 11 mole C
Mass of C = number of mole s* molar mass
=11*12.01
= 132.11 g C
.
QUESTION 11 Another name for the spread in a Eurocurrency loan is the.docx
QUESTION 11
Another name for the spread in a Eurocurrency loan is the _______.
drawdown
term
LIBOR rate
Margin
5 points
QUESTION 12
Leading and lagging strategies have several advantages EXCEPT
no formal note of indebtedness is needed
governments are less like to interfere with payments on intercompany accounts
interest must be charged on all intercompany accounts
intercompany accounts up to six months are interest free
Solution
11- Margin
12- no formal note of indebtedness is needed.
.
QUESTION 1 The following complex is yellow in color What color of ligh.docx
QUESTION 1 The following complex is yellow in color What color of light does this complex absorb? O yellow O green ?blue QUESTION 2 The following complex is yellow in color: Is this complex likely to be low spin or high spin? O low spin ?high spin QUESTION 3 The following complex is yellow in color How many unpaired electrons does this complex poss0s8?
Solution
1. Any substance gives the color complementary to the color which it absorbs . The complementary color of yellow is violet .Hence it absorbs violet colour of light and appears yellow in colour.
2. Fe is in +3 oxidation state and 3d^5 configuration and thus high spin complex due presence of 5 unpaired e-s .Secondly as it shows colour so it is high spin as color is a property of inspired e-s .
3. 5 unpaired e-s as calculated in 2 question.
.
Propane (molar mass 44-11 g-mol) boils at -42-1C- Ethanol has almost t.docx
Propane (molar mass 44.11 g/mol) boils at -42.1°C. Ethanol has almost the same molar mass (46.07 g/mol), but boils at 78.5°C. Which of the following BEST explains the reason for the large discrepancy in boiling point?
A. Â Â Propane is ionic and, therefore, has a lower boiling point.
B. Â Â Ethanol is ionic and, therefore, has a higher boiling point.
C. Â Â Both compounds only exhibit van der Waals forces.
D. Â Â Both compounds are polar. Ethanol is more polar than Propane.
E. Â Â Ethanol exhibits hydrogen bonding.
F. Â Â Propane exhibits hydrogen bonding.
Solution
ethanol is having high boiling point than propane
because in ethanol, the -OH group can form intermolecular hydrogen bonding. so there is association of molecules
which it leads to greater boiling point.
whereas in case of propane, no such hydrogen bonding is possible.
.
QUESTION 1 1 points S Saved What is the concentration of H2S in a satu.docx
QUESTION 1 1 points S Saved What is the concentration of H2S in a saturated solution of H2S? Not enough information in the lab manual to decide. Smaller than 1.0 x 10-8 1.0 M O Greater than 6 M 1.3 M 0.10 M QUESTION 2 4 points Save Answer Match each type of ion to the method used to separate it Silver ions A. Precipitated by adding HCl. B. Precipitated using H2S in a very acidic sol C. Precipitated using H2S in a slightly basic solution. D. Precipitated by adding ammonium carbonate. E. Precipitated by adding sodium sulfide in a weakly basic uion Copper (1) ions Zinc ions Calcium ions solution.
Solution
Ans 1 : 0.10 M
The concentration of H2S in a saturated solution of H2S is 0.10 M.
The solubility of H2S is 0.00016 g / 100 g
So the concentration = number of moles / volume of solution in L
which comes approximately 0.10 M
.
Question 1 (4 points) Provide the correct family name for the structur.docx
Question 1 (4 points) Provide the correct family name for the structure given. The question does not ask for the name of the functional group. Spelling counts. Save
Solution
Answer = Family Name is = Alcohol
the alcohol general formula is R-OH
and the above compound is alchol group
if carbon attached to 3 hydrogens then it is Methyl Alcohol
2 hydrogens and 1 carbon then it is Primary Alcohol
1 hydrogen and 2 carbons then it is Secondary Alcohol
3 carbons then it is Tertiary Alcohol
.
Q-12-13-14 Double Replacement reactions 12- barium acetate + zinc iodi.docx
Q:12,13,14
Double Replacement reactions 12. barium acetate + zinc iodide 13. hydrofluoric acid + lithium hydroxide- 14. What mass of precipitate forms from 1.0 g of lead (IV) chloride mixed with sodium oxide?
Solution
12.Barium acetate upon reaction with zinc iodide produces Barium iodide and zinc acetate.
Ba(C2H3O2)2 (aq) + ZnI2 (aq) --> BaI2 (aq) + Zn(C2H3O2)2 (s)
13.Hydrofluoric acid upon reaction with lithium hydroxide produces Lithium fluoride and water.
HF(aq)+LiOH(aq)----->LiF(aq)+H2O(l)
14.The balanced equation is
PbCl4 +2Na2O---> PbO2(s)+4NaCl
Molarmass (g/mol). 349. 239.2
1 mol=349 g of PbCl4 produces 1 mol= 239.2 g of PbO2 precipitate
1 g of PbCl4 produces (239.2/349)=0.685 g of precipitate PbO2
.
Q1 from the following information Prepare journal entries to record th.docx
Q1 from the following information Prepare journal entries to record the issue of shares, declaration and payment of dividend . on June 1, 2014. Jaguar & Co issued 50,000 shares of $10 each. . The corporation has 500,000 shares outstanding. on January 1, 2015. . on Jan 1, 2015 The company declared $1 per share cash dividend to stockholders. . January 10 is the date of record. . On January 20, is the date of payment of dividend?
Solution
Journal Entries
Jun 1\' 2014 Cash A/c...................Dr 500000
To Capital A/c 500000
On record date :
Jan 10\'2015 Dividends Delared A/c........Dr 500000
To Dividend Payable A/c 500000
On payment of dividend:
Jan 20 \'2015 Dividend payable A/c ....Dr 500000
To Cash A/c 500000
.
Python 3-5-1 Write a function create_2d that takes as input two intege.docx
Python 3.5.1
Write a function create_2d that takes as input two integers height and width, and that creates and returns a 2D list (i.e., a list of lists) with values that are the row number multiplied by the column number.
Solution
def create_2d(height,width):
list2=[]#list for storing list of lists
for x in range(height):#outer loop for rows
list1=[]#list inner
for y in range(width):#inner loop for columns
list1.append(x*y)#row * column
list2.append(list1)#adding list1 with products of single row to list2
print(list2)#prints list
create_2d(2,3) #function calling
output:
[[0, 0, 0], [0, 1, 2]]
as index number starts from zero so
matrix will be
0*0 0*1 0*2
1*0 1*1 1*2
.
Puleva Milenario SA- a company located in Toledo- Spain- manufactures.docx
Puleva Milenario SA, a company located in Toledo, Spain, manufactures and sells two models of luxuriously finished cutlery
Solution
1) a) Prepare a contribution format income statement showing both euro and percent columns for each product and for the company as a whole. ( Input all amounts as positive values except losses which should be indicated by minus sign. Round your euro answers to 2 decimal places. Omit the \"
.
public class forLoop public static void main(Stringp-- args) { for(i -.docx
public class forLoop
public static void main(Stringp[] args)
{
for(i = 4, i < 20, i++)
{
System.out.println(i)
}
}
Please answer all of the following questions: Please put Question numbers with responses and explanations
Question 1: What would the .java file be named?
Question 2: What bugs would need to be fixed for this program to work? (Hint: there are 4)
Question 3: The program will still work, but what programming styles not being adhered to?
Question 4: How many iterations occur before the for loop terminates?
Question 5: What is the last integer printed before termination?
Solution
you havent declared datatype for i;
for(int i=0, i<20, i++)
then it will work and the loop runs untill i becomes 21
so loop runs 16 times
last intezer is 20
.
Provide an example of aquifer and geologic properties that lend to one.docx
Provide an example of aquifer and geologic properties that lend to one of the four possible saturated hydraulic conductivity combinations of heterogeneity/homogeneity and isotropy/anisotropy? What led to the existence of this combination? How might this affect the movement of groundwater?
Solution
Aquifier is a body of permeable rock which can contain or transmit water
An aquifier with homogeneous combination will have same properties at all locations which vary little in K,n,b and constant in T and S
An aquifier with heterogenous combination will vary
In isotopy condition the hydraullic properties are equal in all directions
In anisotropy condition one or more hydraullic properties flow in the direction of flow
Mechanical chemical and thermal engeries cause this combination
The moment of flow depends on gravity and molecular attraction
.
Provide a stre tor donfoin Haf is osisfet oit the Allowing hata l20 pt.docx
Provide a stre tor donfoin Haf is osisfet oit the Allowing hata l20 pts): has leate formuleC tio gna
Solution
ANSWER:
Structure: Molecular formula C4H6O2 indicates carboxylic acid ester with one unsaturated carbon linkage (double bond).
IR frequency at 2950 and 2700 indicates double bond stretching and frequency at 1710 indicates ester carbonyl group.
NMR shows triplet at 9.6 ppm and doublet at 2.3 ppm.
The predicted structure is
Interpretation:
This is due to tautomer forms.
Singlet due to ester CH3 is not shown in the question
Why not the isomeric compound Vinyl acetate?
The reasons:
.
Provide detailed example of what audit working papers would look like-.docx
Provide detailed example of what audit working papers would look like. What are some items you need to include in these working papers and what is the importance of these times?
Solution
Audit Working papers: They are the documents that are used to record all audit evidence that are obtained during the various auditing carried out in the company like Financial statement auditing, Internal auditing, Investigations and informations system auditing.
Some of the items that needs to be included in the working papers are as follows:
1. Heading
.
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