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Part I: Architectures
Jaime E. Kardontchik
Stefan Wurster
Hawaii - November 1999
email: kardontchik.jaime@microlinear.com
300 meters on installed MMF
Objectives
§300 meters provides an optimum
coverage of installed multimode fiber
§compare proposed architectures that
could support up to 300 meter link
lengths on 50 um and 62.5 um MMF
Eye Patterns at fiber exit
(1300 nm)
§ Simulations use 1 GbE link model (see Ref
1) including laser rise-time, fiber modal and
chromatic bandwidth, connector loss and
cable attenuation at 1300 nm
§ Simulated architectures:
l PAM-5 + scrambling + 4-WDM @ 1.25 Gbaud/s
l PAM-2 + 8b/10b + 4-WDM @ 3.125 Gbaud/s
l PAM-5 + scrambling + serial @ 5 Gbaud/s
1.25 Gbaud/s - 300 meters
P1
ISI loss = 0 dB
3.125 Gbaud/s - 300 meters
P3 P0
ISI loss = 10*log(P0/P3) ~ 3.5 dB
5 Gbaud/s - 100 meters (*)
(*) eye closed at 200 meters, even with 500 MHz*km fiber
Eye patterns - 300m: Summary
§ ISI is negligible at 1.25 Gbaud/sec
§The system running at 3.125 Gbaud/sec has
a large ISI penalty loss.
§The architecture at 5 Gbaud/s can not be
used with 300 meters fiber (the eye is
already closed at 200 meters)
ISI LOSS vs LINK LENGTH
3.125 Gbaud/s
1.25 Gbaud/s
Receiver Front End
RF
+
-
P
VO
Assume PIN Photo Diode + Trans-Impedance Amplifier
Is = Responsivity * P
<In > = (4kT/Rf) * B2
Electrical SNR = 10 * log (Is / In )
2 2
Is
Small Signal Receiver Front End
A(s)
Is Rd Cp
R
Vo
1 + s/wa
Ao
A(s) =
Rd >> R
R*Cp
1
wp =
Small Signal Transfer Function
1 + j*(1/Q)*(w/wo) - (w/wo)2
1
R *Vo/Is =
Assuming Ao >> 1 and wa << wo we obtain:
wp = wo/Q
This is a 2nd order lowpass. wo = 2*pi*B. Usually, we set
Q = 1/sqrt(2) (Butterworth).
or
Cp wo
Q1
*R =
2*pi*Cp
Q
B
1
*=
Feedback Resistor vs Bandwidth
AMCC’s Transimpedance Amplifiers
S7014 (1 GbE)
S3060 (OC-48)
S3090 (OC-192)
Thermal noise current
Replacing R into the equation for the thermal noise
current, we finally obtain:
8*pi*k*T*Cp
Q * B
2
<In >2 =
The thermal noise power is proportional to the square of
the bandwidth B.
(for an alternative derivation see: Paul E. Green, “Fiber Optic
Networks”, Prentice Hall, 1993, page 297, Eq 8.32)
Electrical SNR @ 300 m
SNR(1.25Gb/s) - SNR(3.125Gb/s) =
= 10*log(P1/P3) + 10*log(B3/B1)2
with B3 = 3.125, B1 = 1.25. Hence,
SNR(1.25Gb/s) - SNR(3.125Gb/s) ~ -5 + 8= +3 dB
Neglecting any coding gain of the 1.25 Gbaud/s system,
the relative SNRs @ 300 meters are:
2
ELECTRICAL SNR vs LINK LENGTH
(coding gain @ 1.25 Gbaud/s not included. It would shift the curve up)
1.25 Gbaud/s
3.125 Gbaud/s
3dB
ELECTRICAL SNR vs LINK LENGTH
(coding gain of 6 dB @ 1.25 Gbaud/s included)
3.125 Gbaud/s
1.25 Gbaud/s
Differential delay skew in 4-WDM
Use:
D =
d
d Vg
1
with D, a function of wavelength, given by Eq 9.10, Ref 1
Integrate:
D * d = d
Vg
1
(Vg = group velocity)
Differential delay skew
Differential delay between two wavelengths:
t2 - t1 = D * d
2
1
L*
where L is the fiber length
Differential Delay Skew
§ Using wavelengths of 1280,1300,1320 and 1340
nm (see Ref 2), the differential delay skew
between the extreme wavelengths is given by:
l t4 - t1 ~ 0.33*L (L in meters, time in psec)
§ @ 300 m the differential delay skew is 100 psec.
§ Assuming one clock recovery per Rx (same
sampling phase for the 4 channels), the 3.125
Gbaud/s system (with only 320 psec baud period)
will be more sensitive to the delay skew penalty.
3.125 Gbaud/s -300 meters - delay skew effects
(superimposed extreme wavelengths’ eye patterns)
Summary of 3 architectures
PAM-5+ serial @ 5 Gbaud/s has a clear optical power
advantage in shorter link lengths (no optical muxes),
but ISI limits it to ~ 100 m link lengths.
8b/10b + 4-WDM@ 3.125 Gbaud/s provides a better
coverage of the (0-200m) space, but at 300m ISI loss
and delay skew penalty are large.
PAM-5 + 4-WDM @ 1.25 Gbaud/s becomes an
attractive alternative, if used with coding gain, to
provide the solution for the (0-300m) coverage space.
(continues in Part II)

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10G-Base-T - 300m on installed MMF

  • 1. Part I: Architectures Jaime E. Kardontchik Stefan Wurster Hawaii - November 1999 email: kardontchik.jaime@microlinear.com 300 meters on installed MMF
  • 2. Objectives §300 meters provides an optimum coverage of installed multimode fiber §compare proposed architectures that could support up to 300 meter link lengths on 50 um and 62.5 um MMF
  • 3. Eye Patterns at fiber exit (1300 nm) § Simulations use 1 GbE link model (see Ref 1) including laser rise-time, fiber modal and chromatic bandwidth, connector loss and cable attenuation at 1300 nm § Simulated architectures: l PAM-5 + scrambling + 4-WDM @ 1.25 Gbaud/s l PAM-2 + 8b/10b + 4-WDM @ 3.125 Gbaud/s l PAM-5 + scrambling + serial @ 5 Gbaud/s
  • 4. 1.25 Gbaud/s - 300 meters P1 ISI loss = 0 dB
  • 5. 3.125 Gbaud/s - 300 meters P3 P0 ISI loss = 10*log(P0/P3) ~ 3.5 dB
  • 6. 5 Gbaud/s - 100 meters (*) (*) eye closed at 200 meters, even with 500 MHz*km fiber
  • 7. Eye patterns - 300m: Summary § ISI is negligible at 1.25 Gbaud/sec §The system running at 3.125 Gbaud/sec has a large ISI penalty loss. §The architecture at 5 Gbaud/s can not be used with 300 meters fiber (the eye is already closed at 200 meters)
  • 8. ISI LOSS vs LINK LENGTH 3.125 Gbaud/s 1.25 Gbaud/s
  • 9. Receiver Front End RF + - P VO Assume PIN Photo Diode + Trans-Impedance Amplifier Is = Responsivity * P <In > = (4kT/Rf) * B2 Electrical SNR = 10 * log (Is / In ) 2 2 Is
  • 10. Small Signal Receiver Front End A(s) Is Rd Cp R Vo 1 + s/wa Ao A(s) = Rd >> R R*Cp 1 wp =
  • 11. Small Signal Transfer Function 1 + j*(1/Q)*(w/wo) - (w/wo)2 1 R *Vo/Is = Assuming Ao >> 1 and wa << wo we obtain: wp = wo/Q This is a 2nd order lowpass. wo = 2*pi*B. Usually, we set Q = 1/sqrt(2) (Butterworth). or Cp wo Q1 *R = 2*pi*Cp Q B 1 *=
  • 12. Feedback Resistor vs Bandwidth AMCC’s Transimpedance Amplifiers S7014 (1 GbE) S3060 (OC-48) S3090 (OC-192)
  • 13. Thermal noise current Replacing R into the equation for the thermal noise current, we finally obtain: 8*pi*k*T*Cp Q * B 2 <In >2 = The thermal noise power is proportional to the square of the bandwidth B. (for an alternative derivation see: Paul E. Green, “Fiber Optic Networks”, Prentice Hall, 1993, page 297, Eq 8.32)
  • 14. Electrical SNR @ 300 m SNR(1.25Gb/s) - SNR(3.125Gb/s) = = 10*log(P1/P3) + 10*log(B3/B1)2 with B3 = 3.125, B1 = 1.25. Hence, SNR(1.25Gb/s) - SNR(3.125Gb/s) ~ -5 + 8= +3 dB Neglecting any coding gain of the 1.25 Gbaud/s system, the relative SNRs @ 300 meters are: 2
  • 15. ELECTRICAL SNR vs LINK LENGTH (coding gain @ 1.25 Gbaud/s not included. It would shift the curve up) 1.25 Gbaud/s 3.125 Gbaud/s 3dB
  • 16. ELECTRICAL SNR vs LINK LENGTH (coding gain of 6 dB @ 1.25 Gbaud/s included) 3.125 Gbaud/s 1.25 Gbaud/s
  • 17. Differential delay skew in 4-WDM Use: D = d d Vg 1 with D, a function of wavelength, given by Eq 9.10, Ref 1 Integrate: D * d = d Vg 1 (Vg = group velocity)
  • 18. Differential delay skew Differential delay between two wavelengths: t2 - t1 = D * d 2 1 L* where L is the fiber length
  • 19. Differential Delay Skew § Using wavelengths of 1280,1300,1320 and 1340 nm (see Ref 2), the differential delay skew between the extreme wavelengths is given by: l t4 - t1 ~ 0.33*L (L in meters, time in psec) § @ 300 m the differential delay skew is 100 psec. § Assuming one clock recovery per Rx (same sampling phase for the 4 channels), the 3.125 Gbaud/s system (with only 320 psec baud period) will be more sensitive to the delay skew penalty.
  • 20. 3.125 Gbaud/s -300 meters - delay skew effects (superimposed extreme wavelengths’ eye patterns)
  • 21. Summary of 3 architectures PAM-5+ serial @ 5 Gbaud/s has a clear optical power advantage in shorter link lengths (no optical muxes), but ISI limits it to ~ 100 m link lengths. 8b/10b + 4-WDM@ 3.125 Gbaud/s provides a better coverage of the (0-200m) space, but at 300m ISI loss and delay skew penalty are large. PAM-5 + 4-WDM @ 1.25 Gbaud/s becomes an attractive alternative, if used with coding gain, to provide the solution for the (0-300m) coverage space. (continues in Part II)