2. Ferrite
Bead
Introduction
A ferrite bead is a passive device that filters high
frequency noise energy over a broad frequency range.
It becomes resistive over its intended frequency range
and dissipates the noise energy in the form of heat.
The ferrite bead is connected in series with the power
supply rail and is often combined with capacitors to
ground on either side of the bead.
This forms a low-pass filter network,
further reducing the high frequency
power supply noise[1].
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3. Introduction
Ferrite beads are categorized by three response regions:
inductive, resistive, and capacitive. To reduce high
frequency noise, the bead must be in the resistive
region, and it acts like a resistor[1].
The inductive region occurs
below the bead crossover
frequency (X = R),
where the bead becomes
inductive and acts like
a inductor[1].
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4. Unwanted resonance
Nevertheless, improper combining ferrite beads with a
decoupling capacitor for low-pass filtering can lead to
unwanted resonance below the bead crossover
frequency (X = R).
Unwanted resonance may amplify ripple and noise in a
given system instead of attenuating it[1].
V+
V-
Ferrite bead, but
acts like a
inductor
Series Resonance
Decoupling
Capacitor
Unwanted resonance frequencies for typical bead filters
are generally in the 0.1 MHz to 10 MHz range.
For typical switching frequencies
in the 300 kHz to 5 MHz range[1].
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5. Unwanted resonance
For example, the ferrite bead used is a TDK
MPZ1608S101A (100 Ω, 3 A, 0603) and the decoupling
capacitor used is a Murata GRM188R71H103KA01 low
ESR ceramic capacitor (10 nF, X7R, 0603).
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6. Unwanted resonance
Apparently, unwanted resonance occurs at ~2.5 MHz
due to (bead-C) combination, which forms series
resonance mechanism.
As mentioned earlier,
this unwanted resonance
may amplify
ripple and noise.
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7. Unwanted resonance and IR Drop
Thus, (bead+C) combination makes PA power supply
unstable and ACLR aggravates.
In addition, the ferrite bead’s large DCR may lead to
large IR drop, which aggravates ACLR as well,
especially at maximum RF output power because
current is large.
PA
Bead
IR Drop = I*DCR
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8. How to solve this problem ?
In terms of DCR, we ought to choose a ferrite bead with
small DCR.
In terms of unwanted resonance, using an additional
RC decoupling filter can reduce the unwanted
resonance[1].
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