3. SR NO TOPIC/ SECTION NAME DURATION IN LECTURERS
1 BASIC MATHEMATICS 5 5/5/20 to 9/5/20/
2 CLASSICAL MECHANICS
a) MOTION IN ST LINE
b) MOTION IN PLANE
c) LAWS OF MOTION
d) WORK POWER AND ENERGY
e) ROTATIONAL MOTION
15
3
3
3
3
3
10/5/20 to 24/5/20
3 THERMAL SECTION
1)THERMAL PROPERTIES OF MATTER
2)THERMODYANAMICS
3)KINETIC THEORY OF GAS
5
2
1
2
25/5/20 to 29/5/20
4 MECHANICAL PROPERTIES OF SOLID 1 30/5/20
5 MECHANICAL PROPERTIES OF FLUID 4 31/5/20 to 3/6/20
6 ELCTROSTATICS 5 4/6/20 to 8/6/20
7 MAGNETISM 5 9/6/20 to 13/6/20
8 OPTICS 5 14/6/20 to 18/6/20
11 th FOUNDATION COURSE SCHEDULE
6. WHAT IS RADIAN ?
An arc of a circle is a "portion" of the circumference of the circle.
The length of an arc is simply the length of its "portion" of the circumference
The circumference itself can be considered a full circle arc length.
7.
8. One radian is the central angle that subtends an arc length of one radius
Find the length of an arc subtended by an angle of 7π/4 radians in a circle of radius
20 centimeters.
S=θr=7π/4 ×20=35π=109.5557 cm
Practice Ex.. Find length of an arc 3π/4 radians
9. In a circle, the arc measure of the entire circle is 360º
and the arc length of the entire circle is represented by the formula
circumference of the circle =2πr
Using S=rθ
but S= 2πr for full circle
Putting 2πr=rθ
we get θ=2π
The arc measure of the central angle of an entire circle is 360º and the radian measure of
the central angle of an entire circle = 2π.
360º (degrees) = 2π (radians)
10. 360 deg=2π rad
80 deg= ?
80×2π/360
ie 80×π/180
= 0.44π rad
= 1.396 rad
Ex :Convert 40 deg into radian
ANS: 40×π/180 =0.698 radian
π=3.14159264
11. TO CONVERT RADIAN INTO DEGREE
2π rad=360 deg
4 rad= ?
Ie 4×360/2π
4×180/π
= 720 π
=229.1831deg
EX Convert 2 rad into degree
ANS: 2×180/π =114.591 deg
15. Each degree is split up into 60 parts, each part being 1/60 of a degree. These parts are
called minutes. Each minute is split up into 60 parts, each part being 1/60 of a minute.
These parts are called seconds.
TO CALCULATE MOST CORRECT ANGLE
एका डीग्री चे ६० समान भाग के ल्यावर एक भाग म्हणजे १ ममननट ,१ ममननटाचे ६०
समान के ल्यावर १ भाग म्हणजे सेकं द. जसे एक तासाचे ६० भाग के ल्यावर एक भाग
म्हणजे ममननट आणण १ ममनीटाचे ६० भाग के ल्यावर १ भाग म्हणजे सेकं द ससत .
16. CONVERT 40.3472DEG INTO DEGREE,MINUTE AND SECONDS
STEP 1: THERE ARE 40 DEGREES FULL
STEP 2 :NOW REMAINING 0.3472 DEGREES
STEP 3:NOW 1 DEGREE=60 MINUTE THEN
O.3472 DEGREE= ?
ie O.3472×60= 20.832 MINUTES
STEP 4:NOW REMAINING 0.832 MINUTES
1 MINUTE = 60 SECONDS
0.832 MINUTE =?
ie 0.832×60= 49.92 SECONDS
STEP 5:40 DEGREE,20 MINUTES ,49.92SECONDS
REPRESENTATION
40O20’.49.92,,
18. Reduce the following numbers of radians to degrees, minutes, and seconds.
(a). 0.47623radian b). 0.25412.radian
Lets Explore
Step 1:Convert 0.47623 radian to degree 0.47623×180/π =27.286degree
Step 2:degree into degree ,minutes and seconds
= 27 full degree
= 0.286×60 = 17.16 minutes
= 0.16×60 = 9.6 seconds
= 27 17’ 9.6”
= 27 degree,17 minutes ,9.6 seconds
19. To convert 12 28 ‘in radian
STEP 1: Convert given value in degree
= 12 is in full degree
= convert 28’ in degree
= 1 deg =60’
= ? = 28 ‘
= 28×1/60
STEP 2 ie = 0.466 deg so total is
= 12+ 0.466 = 12.466 deg
STEP 3 Now convert this in radian
= 12.466×π/180
= 0.217 radian
To convert 36 12’ in radian
STEP 1 :Convert given value in degree
= 36 is in full degree
= convert 12’ in degree
= 1 deg =60’
= ? = 12 ‘
= 12×1/60
= 0.2 deg so total is
= 36+0.2= 36.2 deg
= Now convert this in radian
= 36.2×π/180
= 0.631 radian
20.
21. 1 convert following degree into radian
a) 40 b) 60 c) 180 d )210
2 convert following radian into degree
a) 3 b) 8 c) 12 d) 6
3)Convert 50.3212 deg into deg, minute ,seconds
4) Reduce following radian into deg, minute, seconds
a) 0.3692 radian b) 0.2345 radian
5)Express following angle in radian
56 deg 14 minutes
Mob No For Doubt 9890068536
TIME FOR DOUBT SESSION 10 AM 12 NOON
22. WORKSHEET 1 ANSWERS
1 a) 0.698rad b)1.047 rad c) 3.141 rad d) 3.665 rad
2 a)171.8 deg b)458.366 deg c)687.549 deg d)343.77 deg
27. Given Cosϴ= 3/5 Calculate all other T ratios
ϴ
3
4
5
Sin ϴ=4/5 Tan ϴ=4/3
Cot ϴ=3/4 Sec ϴ=5/3
Cosec ϴ=5/4
28. 1ST QUADRANT2ND QUARDANT
3RD QUARDANT 4TH QUARDANT
0
360
90
180
270
ALL PositiveSin /Cosec
both positive
Tan /Cot
Both positive
Cos/Sec
Both positive
π/2
π
3π/2
2π
C
A
S
TRULE OF CAST
30. ददलेल्या सँगलची VALUE कशी काढावी
स्टेप १ : ददलेल्या ANGLELA ९० ककं वा १८० च्या स्वरूपात बदलावे
जसे कक sin (१२०)= sin (९०+३०)
न ट १: ९०/९० ससे करावे काय येतं = १ येतं
१ इव्हन आहे कक ऑड आहे ,उत्तर आहे ऑड ,सशावेळी function
बदलते म्हणजे sin चे cos ह ते
i.e. sin (९०+३०)= +cos ३० ( + का घेतले आहे ? ९०+३० म्हणजे
second quadrant जजथे sin positive ससते )
or
जसे कक sin (१२०) = sin (१८०-६०)
न ट २: १८०/९० ससे करावे काय येतं = २ येतं
२ इव्हन आहे कक ऑड आहे ,उत्तर आहे इव्हन ,सशावेळी function
बदलत नाही म्हणजे sin चे sin च राहते
i.e. sin (१२०)=sin (१८०-६०)=+sin ६०=cos ३० (पुन्हा त च प्रश्न + का
घेतले आहे १८०-६० म्हणजे second quadrant जजथे sin positive ससते
सशा पद्धतीने कु ठलाही value काढता येते
31. Ex if n=1
sin ( 2×1×π+ θ)
= sin(2π + θ)
= sin ϴ
1st Quadrant
2π
All positive
36. Find values of following
ii)180/90=2 even ,means no
change in function
(180+30 ) is Third quadrant where
tan positive ie +tan 30
iii) 270/90=3 odd, means change
in function
Ie sin will come cos, and( 270+30)
is Fourth Quadrant
Where sin negative ie –cos 30
iv) 180/90=2 even ,means no change in function ie
Cos will remain cos.
(180-60) is second quadrant where
cos negative ie –cos60