NH4Cl = acid NaOH = base They react 1:1 Leftover = 0.26-0.192 = 0.068M NH4Cl pH = -log(0.068) = 1.1675 pH + pOH = 14 pOH = 14 - 1.1675 = 12.8325 [OH-] = 10^-12.8325 = 1.471 * 10^-13 M Solution NH4Cl = acid NaOH = base They react 1:1 Leftover = 0.26-0.192 = 0.068M NH4Cl pH = -log(0.068) = 1.1675 pH + pOH = 14 pOH = 14 - 1.1675 = 12.8325 [OH-] = 10^-12.8325 = 1.471 * 10^-13 M.