The document presents a series of calculations involving the reaction between NH4Cl (acid) and NaOH (base) in a 1:1 ratio. It outlines the leftover concentration of NH4Cl, leading to a calculated pH of approximately 1.1675 and a corresponding pOH of about 12.8325. Additionally, it provides the concentration of hydroxide ions [OH-] in the solution as 1.471 x 10^-13 m.

1. NH4Cl = acid
NaOH = base
They react 1:1
Leftover = 0.26-0.192 = 0.068M NH4Cl
pH = -log(0.068) = 1.1675
pH + pOH = 14
pOH = 14 - 1.1675 = 12.8325
[OH-] = 10^-12.8325 = 1.471 * 10^-13 M
Solution
NH4Cl = acid
NaOH = base
They react 1:1
Leftover = 0.26-0.192 = 0.068M NH4Cl
pH = -log(0.068) = 1.1675
pH + pOH = 14
pOH = 14 - 1.1675 = 12.8325
[OH-] = 10^-12.8325 = 1.471 * 10^-13 M