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Definite Integration
Course- Diploma
Semester-II
Subject- Advanced Mathematics
Unit- V
RAI UNIVERSITY, AHMEDABAD
Unit-V Definite Integration
RAI UNIVERSITY, AHMEDABAD
5. Definite integration
5.1 Definition— If ( ) is continuous in the interval [ , ] and ( ) is an antiderivative of
( ), then
5.2 Elementary properties of definite integral—
1. ∫ ( ) = − ∫ ( )
2. ∫ ( ) = ∫ ( ) = ∫ ( )
3. ∫ ( ) =
4. ∫ ( ) = ∫ ( ) + ∫ ( ) , < <
5. ∫ ( + − ) = ∫ ( )
6. ∫ ( − ) = ∫ ( )
7. ∫ ( ) =
∫ ( )
8. ∫ ( ) =
∫ ( ) ( − ) = ( )
( − ) = − ( )
5.3 Standard properties of definite integral—
1. If ( ) ≥ is defined and continuous on[ , ], then ∫ ( ) ≥
2. If ( ) ≤ is defined and continuous on[ , ], then ∫ ( ) ≤
3. If ( ) ≤ ( ) is defined and continuous on[ , ], then ∫ ( ) ≤ ∫ ( )
( ) = ( ) − ( )
Unit-V Definite Integration
RAI UNIVERSITY, AHMEDABAD
4. If ( ) and ( ) be two functions defined and continuous on [a, b] then—
( ) ( ) ≤ ( ) ( )
5. The mean value theorem—
Statement— If ( ) is continuous on [ , ], then at least one value of = in ( , )
such that—
( ) = ∫ ( )
Where ( ) is called as average or mean value of ( ) on [ , ].
Example— Integrate ∫ .
Solution—∫
= = − =
Example— Integrate ∫
Solution—∫
= |− cos |
= − cos — cos 0
= 0 − (−1) = 1
Example— Integrate ∫
Solution— ∫
= ∫ − ∫
( )
(∫ )
= − ∫
= [ − ∫ ]
= [ − ]
= ( − ) − ( 1 − 1)
= ( − ) + 1 = 1
Example— Evaluate ∫
Solution—∫ 3 2
= ∫ 2 3 2
= ∫ ( 5 + )
Unit-V Definite Integration
RAI UNIVERSITY, AHMEDABAD
= − 5 −
= − 5 − − − 0 − 0
= (0 − 0) − − − 1
=
EXERCISE
Question— Evaluate ∫ sin 4 cos 3 .
Question— Integrate ∫ (2 + 1) .
Question— Integrate ∫ cos .
Question— Integrate ∫ ( ) .
Unit-V Definite Integration
RAI UNIVERSITY, AHMEDABAD
Reference—
1. mathworld.wolfram.com
2. www.mathsisfun.com
3. tutorial.math.lamar.edu
4. en.wikipedia.org/wiki/Integral
5. https://www.khanacademy.org
6. www.sosmath.com

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Definite Integration Course

  • 1. Definite Integration Course- Diploma Semester-II Subject- Advanced Mathematics Unit- V RAI UNIVERSITY, AHMEDABAD
  • 2. Unit-V Definite Integration RAI UNIVERSITY, AHMEDABAD 5. Definite integration 5.1 Definition— If ( ) is continuous in the interval [ , ] and ( ) is an antiderivative of ( ), then 5.2 Elementary properties of definite integral— 1. ∫ ( ) = − ∫ ( ) 2. ∫ ( ) = ∫ ( ) = ∫ ( ) 3. ∫ ( ) = 4. ∫ ( ) = ∫ ( ) + ∫ ( ) , < < 5. ∫ ( + − ) = ∫ ( ) 6. ∫ ( − ) = ∫ ( ) 7. ∫ ( ) = ∫ ( ) 8. ∫ ( ) = ∫ ( ) ( − ) = ( ) ( − ) = − ( ) 5.3 Standard properties of definite integral— 1. If ( ) ≥ is defined and continuous on[ , ], then ∫ ( ) ≥ 2. If ( ) ≤ is defined and continuous on[ , ], then ∫ ( ) ≤ 3. If ( ) ≤ ( ) is defined and continuous on[ , ], then ∫ ( ) ≤ ∫ ( ) ( ) = ( ) − ( )
  • 3. Unit-V Definite Integration RAI UNIVERSITY, AHMEDABAD 4. If ( ) and ( ) be two functions defined and continuous on [a, b] then— ( ) ( ) ≤ ( ) ( ) 5. The mean value theorem— Statement— If ( ) is continuous on [ , ], then at least one value of = in ( , ) such that— ( ) = ∫ ( ) Where ( ) is called as average or mean value of ( ) on [ , ]. Example— Integrate ∫ . Solution—∫ = = − = Example— Integrate ∫ Solution—∫ = |− cos | = − cos — cos 0 = 0 − (−1) = 1 Example— Integrate ∫ Solution— ∫ = ∫ − ∫ ( ) (∫ ) = − ∫ = [ − ∫ ] = [ − ] = ( − ) − ( 1 − 1) = ( − ) + 1 = 1 Example— Evaluate ∫ Solution—∫ 3 2 = ∫ 2 3 2 = ∫ ( 5 + )
  • 4. Unit-V Definite Integration RAI UNIVERSITY, AHMEDABAD = − 5 − = − 5 − − − 0 − 0 = (0 − 0) − − − 1 = EXERCISE Question— Evaluate ∫ sin 4 cos 3 . Question— Integrate ∫ (2 + 1) . Question— Integrate ∫ cos . Question— Integrate ∫ ( ) .
  • 5. Unit-V Definite Integration RAI UNIVERSITY, AHMEDABAD Reference— 1. mathworld.wolfram.com 2. www.mathsisfun.com 3. tutorial.math.lamar.edu 4. en.wikipedia.org/wiki/Integral 5. https://www.khanacademy.org 6. www.sosmath.com