This document contains information about assignments for a class including:
1) A circuit with a pulse voltage source, MOSFET, and load resistor that is simulated to analyze the output voltage waveform.
2) A second circuit with a pulse voltage source, resistor, inductor, and capacitor that is analyzed to determine the average power.
3) A third circuit that is analyzed using AC analysis to determine the average power passing through a resistor between 300Hz and 18kHz.
1. CSCE 585 FALL 2014
ASSIGNMENT 1
OLADIRAN OLALEYE
Ogo8842
(2.2) Frequency (f) = 1 / Period (T) = 1 / 20 ms = 50 Hertz. In the waveform,
current also repeats with a period of 20ms (50 Hertz).
From the waveform, the peak absolute value current is about 30u amps.
(2.3) avgpwr= 3.3417E-07 from= 0.0000E+00 to= 2.0000E-02
(3.2.2repeat): Frequency = no No frequency. Justified since th current is
rectified.
(3.2.3repeat): avgpwr= 4.5000E-01 from= 0.0000E+00 to= 2.0000E-02
(3.3) avgpwr= 4.5000E-01 from= 3.0000E+02 to= 1.8000E+04
The circuit is a low-pass filter and blocks AC but passes DC to the Rload
resistor. Hence, the reason why the voltage across the resistor is rectified.