2. f x f x dx
n
f x n1 c
f x f x dx
n
n 1
3. f x f x dx
n
f x n1 c
f x f x dx
n
n 1
e.g. i a) Find
d
dx
1 x 3
4. f x f x dx
n
f x n1 c
f x f x dx
n
n 1
e.g. i a) Find
d
dx
1 x 3
1 x 3 1 x 3 2 3 x 2
1
d 1
dx 2
3x 2
2 1 x3
6. x2
b) Hence find; 1 x 3
dx
x2 2 3x 2
1 x 3
dx
3 2 1 x 3
dx
7. x2
b) Hence find; 1 x 3
dx
x2 2 3x 2
1 x 3
dx
3 2 1 x 3
dx
2
1 x3 c
3
8. x2
b) Hence find; 1 x 3
dx
x2 2 3x 2
1 x 3
dx
3 2 1 x 3
dx
2
1 x3 c
3
ii x 2 x 2 dx
9. x2
b) Hence find; 1 x 3
dx
x2 2 3x 2
1 x 3
dx
3 2 1 x 3
dx
2
1 x3 c
3
ii x 2 x 2 dx
1
2 x 2 x 2 dx
2
10. x2
b) Hence find; 1 x 3
dx
x2 2 3x 2
1 x 3
dx
3 2 1 x 3
dx
2
1 x3 c
3
ii x 2 x 2 dx
1
2 x 2 x 2 dx
2
2 x 2 2 c
3
1 2
2 3
11. x2
b) Hence find; 1 x 3
dx
x2 2 3x 2
1 x 3
dx
3 2 1 x 3
dx
2
1 x3 c
3
ii x 2 x 2 dx
1
2 x 2 x 2 dx
2
2 x 2 2 c
3
1 2
2 3
2 x 2 2 x 2 c
1
3
12. x2
b) Hence find; 1 x 3
dx
x2 2 3x 2
1 x 3
dx
3 2 1 x 3
dx
2
1 x3 c
3
ii x 2 x 2 dx OR x 2 x 2 dx
1
2 x 2 x 2 dx
2
2 x 2 2 c
3
1 2
2 3
2 x 2 2 x 2 c
1
3
13. x2
b) Hence find; 1 x 3
dx
x2 2 3x 2
1 x 3
dx
3 2 1 x 3
dx
2
1 x3 c
3
ii x 2 x 2 dx OR x 2 x 2 dx u 2 x2
1
2 x 2 x 2 dx
2
2 x 2 2 c
3
1 2
2 3
2 x 2 2 x 2 c
1
3
14. x2
b) Hence find; 1 x 3
dx
x2 2 3x 2
1 x 3
dx
3 2 1 x 3
dx
2
1 x3 c
3
ii x 2 x 2 dx OR x 2 x 2 dx u 2 x2
1 du
2 x 2 x 2 dx 2x
2 dx
du 2 xdx
2 x 2 2 c
3
1 2
2 3
2 x 2 2 x 2 c
1
3
15. x2
b) Hence find; 1 x 3
dx
x2 2 3x 2
1 x 3
dx
3 2 1 x 3
dx
2
1 x3 c
3
ii x 2 x 2 dx OR x 2 x 2 dx u 2 x2
1 du
2 x 2 x 2 dx u 2x
2 dx
du 2 xdx
2 x 2 2 c
3
1 2
2 3
2 x 2 2 x 2 c
1
3
16. x2
b) Hence find; 1 x 3
dx
x2 2 3x 2
1 x 3
dx
3 2 1 x 3
dx
2
1 x3 c
3
ii x 2 x 2 dx OR x 2 x 2 dx u 2 x2
1 du
2 x 2 x 2 dx 1 u 2x
2 du dx
2
du 2 xdx
2 x 2 2 c
3
1 2
2 3
2 x 2 2 x 2 c
1
3
17. x2
b) Hence find; 1 x 3
dx
x2 2 3x 2
1 x 3
dx
3 2 1 x 3
dx
2
1 x3 c
3
ii x 2 x 2 dx OR x 2 x 2 dx u 2 x2
1 du
2 x 2 x 2 dx 1 u 2x
2 du dx
2
du 2 xdx
2 x 2 2 c
3
1 2 1
1 2
2 3 u du
2
2 x 2 2 x 2 c
1
3
18. x2
b) Hence find; 1 x 3
dx
x2 2 3x 2
1 x 3
dx
3 2 1 x 3
dx
2
1 x3 c
3
ii x 2 x 2 dx OR x 2 x 2 dx u 2 x2
1 du
2 x 2 x 2 dx 1 u 2x
2 du dx
2
du 2 xdx
2 x 2 2 c
3
1 2 1
1 2
2 3 u du
2
2 x 2 2 x 2 c
1 1 2 2
3
3 u c
2 3
19. x2
b) Hence find; 1 x 3
dx
x2 2 3x 2
1 x 3
dx
3 2 1 x 3
dx
2
1 x3 c
3
ii x 2 x 2 dx OR x 2 x 2 dx u 2 x2
1 du
2 x 2 x 2 dx 1 u 2x
2 du dx
2
du 2 xdx
2 x 2 2 c
3
1 2 1
1 2
2 3 u du
2
2 x 2 2 x 2 c
1 1 2 2
3
3 u c
2 3
2 x 2 2 x 2 c
1
3