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▪ Overhead line insulators are used to separate line conductors from each other and the supporting structures electrically.
▪ Insulators protect the transmission line from over-voltages which occur due to lightning, switching etc.
Properties :
1. High mechanical strength
2. High electrical resistance
3. High relative permittivity of insulating material
4. High ratio of puncture strength to flashover.
Overhead Line Insulators
Main components of an overhead line are
1. Conductors
2. Supports
3. Insulators
4. Cross - Arms
PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof.,
RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
Types Of Insulators
1. Pin type insulators
2. Suspension type insulators
3. Strain insulators
4. Shackle insulators
The most commonly used material for insulators of overhead line is porcelain but glass, steatite and special composition
materials are also used to a limited extent.
Pin type insulators Suspension insulators Strain insulators Shackle insulators
PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof.,
RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
Pin type Insulators
▪ The pin type insulator is secured to the cross-arm on the pole.
▪ There is a groove on the upper end of the insulator for housing the conductor.
▪ The conductor passes through this groove and is bound by the annealed wire of the same material as the conductor.
▪ Pin type insulators are used for transmission and distribution of electric power at voltages upto 33 kV.
▪ Beyond operating voltage of 33 kV, the pin type insulators become too bulky and hence uneconomical.
PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof.,
RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
▪ The electrical breakdown of the insulator can occur either by flash-over or puncture.
Flash-over: In insulator flash-over, electrical discharge occurs by forming an arc between the line conductor and the
insulator pin (which is connected to the cross-arm). The discharge jumps through the air surrounding the insulator
following the shortest distance.
▪ In case of a flash-over, the insulator continues to act according to its designed capacity unless it gets destroyed
due to the excess heat.
Insulator failure
PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof.,
RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
Puncture:
▪ In case of insulator puncture, electrical discharge occurs from conductor to pin through the body of the insulator.
Sufficient thickness of porcelain (or the insulator material) must be provided to avoid a puncture breakdown.
▪ When such breakdown is involved, the insulator is permanently damaged.
Safety factor of insulator: Ratio of puncture strength to flash over voltage.
▪ It is desirable to have high value of safety factor so that a flash-over takes
place before the insulator gets punctured.
▪ For pin type insulators, the value of safety factor is about 10.
PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof.,
RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
Suspension Insulators
▪ Pin insulators become too bulky an uneconomical beyond 33 kV.
So, for voltages higher than 33 kV, suspension insulators are used.
▪ A suspension insulator consists of a number of porcelain discs
connected to each other with metal links in the form of a string.
Line conductor is suspended at the bottom end of the suspension
string which is secured to cross-arm of the tower.
Advantages:
1. Desired number of discs can be connected in series to form an insulator string suitable for particular voltage.
2. If any of the discs in insulator string is damaged, it can be replaced easily. Replacement of the whole string is not
required.
3. The suspension arrangement provides greater flexibility to the line. Suspension insulators are allowed to swing so that
they can take up the position where mechanical stresses are minimum.
▪ Each disc in a suspension insulator string is designed for a low voltage, say 11 kV. The number of discs in a string
depends on the working voltage. Suspension insulators are preferred for transmission lines.
PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof.,
RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
Strain Insulators
▪ At a dead end of a transmission line or at a corner or sharp curve, the transmission line is subjected to a great tensile load.
In order to sustain this great tension, strain insulators are used at dead ends or sharp corners.
▪ For high voltage transmission lines, stain insulator consists of an assembly of suspension insulators. In this case, the
suspension string is arranged horizontally and the insulator discs are in vertical plane.
▪ Two or more suspension strings can be assembled in parallel to sustain greater tensions. For low voltage lines (less than 11
kV), shackle insulators are used as strain insulators.
PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof.,
RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
Shackle Insulators
▪ Shackle insulators are used in low voltage distribution lines as strain insulators.
▪ A shackle insulator can be used vertically as well as horizontally and it can be directly fixed to a pole with a
bolt or to the cross arm.
▪ However, the use of such insulators is decreasing after increasing the use of underground cables for
distribution purpose.
PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof.,
RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
String Efficiency
Figure: Potential Distribution over
Suspension Insulator String
▪ A string of suspension insulators consists of a number of
porcelain discs connected in series through metallic links.
▪ The porcelain portion of each disc is in-between two metal
links. Therefore, each disc forms a capacitor C, known as
mutual capacitance or self-capacitance.
▪ Capacitance also exists between metal fitting of each disc and
tower or earth. This is known as shunt capacitance C1. Due to
shunt capacitance, charging current is not the same through all
the discs of the string.
▪ The disc nearest to the line conductor will have the maximum
voltage, because charging current through the string has the
maximum value at the disc nearest to the conductor.
PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof.,
RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
▪ Due to the presence of shunt capacitance the voltage impressed on a string of suspension insulators does not distribute
itself uniformly across the individual discs. The unit nearest to the conductor is under maximum electrical stress and is
likely to be punctured.
▪ The voltage applied across the string of suspension insulators is not uniformly distributed across various units or discs.
This unequal potential distribution is undesirable and is usually expressed in terms of string efficiency.
▪ The ratio of voltage across the whole string to the product of number of discs and the voltage across the disc nearest to
the conductor is known as string efficiency i.e.,
▪ The greater the string efficiency, the more uniform is the voltage distribution. Thus 100% string efficiency is an ideal
case for which the voltage across each disc will be exactly the same.
PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof.,
RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
Figure: Equivalent circuit for a 3-
disc string
Let self capacitance of each disc = C
shunt capacitance C1 is some fraction K of self-capacitance
i.e., C1 = KC.
Starting from the cross-arm or tower, the voltage across each unit is V1,V2 and
V3 respectively.
PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof.,
RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
▪ The greater the value of K (= C1/C), the more non-uniform is the potential across the discs and lesser is the string
efficiency.
▪ The inequality in voltage distribution increases with the increase of number of discs in the string. Therefore, shorter
string has more efficiency than the larger one.
PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof.,
RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
Methods of Improving String Efficiency
▪ Due to the presence of potential distribution in a string of suspension insulators is not uniform.
▪ If the insulation of the highest stressed insulator (i.e. nearest to conductor) breaks down or flash over takes place, the
breakdown of other units will take place in succession. So it is needed to equalize the potential across the various units of
the string i.e. to improve the string efficiency.
▪ The various methods of improving the string efficiency are
1. By grading the insulators.
2. By using longer cross-arms.
3. By using a guard ring.
▪ In the method of grading of insulators, insulators of different dimensions are so chosen that each has a different
capacitance.
▪ The insulators are capacitance graded i.e. they are assembled in the string in such a way that the top unit has the
minimum capacitance, increasing progressively as the bottom unit (i.e., nearest to conductor) is reached.
PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof.,
RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
Figure: By using longer cross-arms
▪ The value of string efficiency depends upon the value of K i.e., ratio of shunt
capacitance to mutual capacitance.
▪ The lesser the value of K, the greater is the string efficiency and more uniform is the
voltage distribution.
▪ The value of K can be decreased by reducing the shunt capacitance. In order to reduce
shunt capacitance, the distance of conductor from tower must be increased i.e., longer
cross-arms should be used.
▪ The potential across each unit in a string can be equalized by using a guard ring
which is a metal ring electrically connected to the conductor and surrounding the
bottom insulator.
▪ The guard ring is contoured in such a way that shunt capacitance currents i1, i2 etc. are
equal to metal fitting line capacitance currents i1’, i2’ etc.
▪ The result is that same charging current I flows through each unit of string.
Consequently, there will be uniform potential distribution across the units.
Figure: By using a guard ring
PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof.,
RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
The difference in level between points of supports and the lowest point on the conductor is called sag.
Sag in overhead lines
▪ It is desirable that
1. The conductor sag should be kept to a minimum in order to reduce the conductor material required and to avoid extra pole
height for sufficient clearance above ground level.
2. Tension in the conductor should be low to avoid the mechanical failure of conductor and to permit the use of less strong
supports.
▪ Low conductor tension and minimum sag are not possible since low sag means a tight wire and high tension, whereas a
low tension means a loose wire and increased sag. Therefore, in an overhead line, the sag should be so adjusted that
tension in the conductors is within safe limits.
PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof.,
RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
▪ When the conductor is suspended between two supports at the same
level, it takes the shape of catenary and parabola, if the sag is very
small compared with the span.
▪ The tension at supports is approximately equal to the horizontal
tension acting at any point on the wire. Thus if T is the tension at the
support B, then T = TO.
Calculation of Sag
▪ In an overhead line, the sag should be so adjusted that tension in
the conductors is within safe limits.
When supports are at equal levels:
▪ As shown in figure let us consider a conductor between two
equi-level supports A and B with O as the lowest point, will be at
the mid-span.
PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof.,
RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
Lets consider
Length of span = l
Weight per unit length of conductor = w and
Tension in the conductor = T.
▪ Taking the lowest point O as the origin and consider a point P on the conductor. Let the co-ordinates of point P be x
and y. Assuming that the curvature is so small that curved length is equal to its horizontal projection OP = x.
▪ On the portion ‘OP’of the conductor there are two forces acting, given as
1. The weight ‘wx’of conductor acting at a distance x/2 from O and
2. The tension T acting at O.
PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof.,
RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
When supports are at unequal levels
▪ Conductors suspended between the supports in hilly areas become unequal level, as shown in the figure a conductor
suspended between two supports A and B which are at different levels and O is the lowest point on the conductor.
Let
l = Span length
h = Difference in levels between two supports
x1 = Distance of support at lower level (i.e., A) from O
x2 = Distance of support at higher level (i.e. B) from O
T = Tension in the conductor
▪ If w is the weight per unit length of the conductor, then
At support A, x = x1 and y = S1.
since
PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof.,
RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof.,
RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
Effect of wind and ice loading
▪ The tension is governed by conductor weight, effects of wind, ice loading and temperature variations.
▪ In actual practice, a conductor may have ice coating and simultaneously subjected to wind pressure. The weight of ice
acts vertically downwards i.e., in the same direction as the weight of conductor.
▪ The force due to the wind is assumed to act horizontally i.e., at right angle to the projected surface of the conductor.
Hence, the total force on the conductor is the vector sum of horizontal and vertical forces.
PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof.,
RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
When the conductor has wind and ice loading also, the following points may be noted:
The conductor sets itself in a plane at an angle  to the vertical where
The sag in the conductor is given by
Hence S represents the slant sag in a direction making an angle  to the vertical. If no specific mention is made in the
problem, then slant slag is calculated by using the above formula.
The vertical sag = S cos 
PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof.,
RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT

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Overhead line insulators & SAG calculations

  • 1.
  • 2. ▪ Overhead line insulators are used to separate line conductors from each other and the supporting structures electrically. ▪ Insulators protect the transmission line from over-voltages which occur due to lightning, switching etc. Properties : 1. High mechanical strength 2. High electrical resistance 3. High relative permittivity of insulating material 4. High ratio of puncture strength to flashover. Overhead Line Insulators Main components of an overhead line are 1. Conductors 2. Supports 3. Insulators 4. Cross - Arms PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof., RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
  • 3. Types Of Insulators 1. Pin type insulators 2. Suspension type insulators 3. Strain insulators 4. Shackle insulators The most commonly used material for insulators of overhead line is porcelain but glass, steatite and special composition materials are also used to a limited extent. Pin type insulators Suspension insulators Strain insulators Shackle insulators PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof., RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
  • 4. Pin type Insulators ▪ The pin type insulator is secured to the cross-arm on the pole. ▪ There is a groove on the upper end of the insulator for housing the conductor. ▪ The conductor passes through this groove and is bound by the annealed wire of the same material as the conductor. ▪ Pin type insulators are used for transmission and distribution of electric power at voltages upto 33 kV. ▪ Beyond operating voltage of 33 kV, the pin type insulators become too bulky and hence uneconomical. PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof., RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
  • 5. ▪ The electrical breakdown of the insulator can occur either by flash-over or puncture. Flash-over: In insulator flash-over, electrical discharge occurs by forming an arc between the line conductor and the insulator pin (which is connected to the cross-arm). The discharge jumps through the air surrounding the insulator following the shortest distance. ▪ In case of a flash-over, the insulator continues to act according to its designed capacity unless it gets destroyed due to the excess heat. Insulator failure PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof., RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
  • 6. Puncture: ▪ In case of insulator puncture, electrical discharge occurs from conductor to pin through the body of the insulator. Sufficient thickness of porcelain (or the insulator material) must be provided to avoid a puncture breakdown. ▪ When such breakdown is involved, the insulator is permanently damaged. Safety factor of insulator: Ratio of puncture strength to flash over voltage. ▪ It is desirable to have high value of safety factor so that a flash-over takes place before the insulator gets punctured. ▪ For pin type insulators, the value of safety factor is about 10. PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof., RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
  • 7. Suspension Insulators ▪ Pin insulators become too bulky an uneconomical beyond 33 kV. So, for voltages higher than 33 kV, suspension insulators are used. ▪ A suspension insulator consists of a number of porcelain discs connected to each other with metal links in the form of a string. Line conductor is suspended at the bottom end of the suspension string which is secured to cross-arm of the tower. Advantages: 1. Desired number of discs can be connected in series to form an insulator string suitable for particular voltage. 2. If any of the discs in insulator string is damaged, it can be replaced easily. Replacement of the whole string is not required. 3. The suspension arrangement provides greater flexibility to the line. Suspension insulators are allowed to swing so that they can take up the position where mechanical stresses are minimum. ▪ Each disc in a suspension insulator string is designed for a low voltage, say 11 kV. The number of discs in a string depends on the working voltage. Suspension insulators are preferred for transmission lines. PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof., RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
  • 8. Strain Insulators ▪ At a dead end of a transmission line or at a corner or sharp curve, the transmission line is subjected to a great tensile load. In order to sustain this great tension, strain insulators are used at dead ends or sharp corners. ▪ For high voltage transmission lines, stain insulator consists of an assembly of suspension insulators. In this case, the suspension string is arranged horizontally and the insulator discs are in vertical plane. ▪ Two or more suspension strings can be assembled in parallel to sustain greater tensions. For low voltage lines (less than 11 kV), shackle insulators are used as strain insulators. PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof., RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
  • 9. Shackle Insulators ▪ Shackle insulators are used in low voltage distribution lines as strain insulators. ▪ A shackle insulator can be used vertically as well as horizontally and it can be directly fixed to a pole with a bolt or to the cross arm. ▪ However, the use of such insulators is decreasing after increasing the use of underground cables for distribution purpose. PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof., RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
  • 10. String Efficiency Figure: Potential Distribution over Suspension Insulator String ▪ A string of suspension insulators consists of a number of porcelain discs connected in series through metallic links. ▪ The porcelain portion of each disc is in-between two metal links. Therefore, each disc forms a capacitor C, known as mutual capacitance or self-capacitance. ▪ Capacitance also exists between metal fitting of each disc and tower or earth. This is known as shunt capacitance C1. Due to shunt capacitance, charging current is not the same through all the discs of the string. ▪ The disc nearest to the line conductor will have the maximum voltage, because charging current through the string has the maximum value at the disc nearest to the conductor. PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof., RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
  • 11. ▪ Due to the presence of shunt capacitance the voltage impressed on a string of suspension insulators does not distribute itself uniformly across the individual discs. The unit nearest to the conductor is under maximum electrical stress and is likely to be punctured. ▪ The voltage applied across the string of suspension insulators is not uniformly distributed across various units or discs. This unequal potential distribution is undesirable and is usually expressed in terms of string efficiency. ▪ The ratio of voltage across the whole string to the product of number of discs and the voltage across the disc nearest to the conductor is known as string efficiency i.e., ▪ The greater the string efficiency, the more uniform is the voltage distribution. Thus 100% string efficiency is an ideal case for which the voltage across each disc will be exactly the same. PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof., RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
  • 12. Figure: Equivalent circuit for a 3- disc string Let self capacitance of each disc = C shunt capacitance C1 is some fraction K of self-capacitance i.e., C1 = KC. Starting from the cross-arm or tower, the voltage across each unit is V1,V2 and V3 respectively. PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof., RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
  • 13. ▪ The greater the value of K (= C1/C), the more non-uniform is the potential across the discs and lesser is the string efficiency. ▪ The inequality in voltage distribution increases with the increase of number of discs in the string. Therefore, shorter string has more efficiency than the larger one. PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof., RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
  • 14. Methods of Improving String Efficiency ▪ Due to the presence of potential distribution in a string of suspension insulators is not uniform. ▪ If the insulation of the highest stressed insulator (i.e. nearest to conductor) breaks down or flash over takes place, the breakdown of other units will take place in succession. So it is needed to equalize the potential across the various units of the string i.e. to improve the string efficiency. ▪ The various methods of improving the string efficiency are 1. By grading the insulators. 2. By using longer cross-arms. 3. By using a guard ring. ▪ In the method of grading of insulators, insulators of different dimensions are so chosen that each has a different capacitance. ▪ The insulators are capacitance graded i.e. they are assembled in the string in such a way that the top unit has the minimum capacitance, increasing progressively as the bottom unit (i.e., nearest to conductor) is reached. PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof., RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
  • 15. Figure: By using longer cross-arms ▪ The value of string efficiency depends upon the value of K i.e., ratio of shunt capacitance to mutual capacitance. ▪ The lesser the value of K, the greater is the string efficiency and more uniform is the voltage distribution. ▪ The value of K can be decreased by reducing the shunt capacitance. In order to reduce shunt capacitance, the distance of conductor from tower must be increased i.e., longer cross-arms should be used. ▪ The potential across each unit in a string can be equalized by using a guard ring which is a metal ring electrically connected to the conductor and surrounding the bottom insulator. ▪ The guard ring is contoured in such a way that shunt capacitance currents i1, i2 etc. are equal to metal fitting line capacitance currents i1’, i2’ etc. ▪ The result is that same charging current I flows through each unit of string. Consequently, there will be uniform potential distribution across the units. Figure: By using a guard ring PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof., RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
  • 16. The difference in level between points of supports and the lowest point on the conductor is called sag. Sag in overhead lines ▪ It is desirable that 1. The conductor sag should be kept to a minimum in order to reduce the conductor material required and to avoid extra pole height for sufficient clearance above ground level. 2. Tension in the conductor should be low to avoid the mechanical failure of conductor and to permit the use of less strong supports. ▪ Low conductor tension and minimum sag are not possible since low sag means a tight wire and high tension, whereas a low tension means a loose wire and increased sag. Therefore, in an overhead line, the sag should be so adjusted that tension in the conductors is within safe limits. PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof., RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
  • 17. ▪ When the conductor is suspended between two supports at the same level, it takes the shape of catenary and parabola, if the sag is very small compared with the span. ▪ The tension at supports is approximately equal to the horizontal tension acting at any point on the wire. Thus if T is the tension at the support B, then T = TO. Calculation of Sag ▪ In an overhead line, the sag should be so adjusted that tension in the conductors is within safe limits. When supports are at equal levels: ▪ As shown in figure let us consider a conductor between two equi-level supports A and B with O as the lowest point, will be at the mid-span. PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof., RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
  • 18. Lets consider Length of span = l Weight per unit length of conductor = w and Tension in the conductor = T. ▪ Taking the lowest point O as the origin and consider a point P on the conductor. Let the co-ordinates of point P be x and y. Assuming that the curvature is so small that curved length is equal to its horizontal projection OP = x. ▪ On the portion ‘OP’of the conductor there are two forces acting, given as 1. The weight ‘wx’of conductor acting at a distance x/2 from O and 2. The tension T acting at O. PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof., RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
  • 19. When supports are at unequal levels ▪ Conductors suspended between the supports in hilly areas become unequal level, as shown in the figure a conductor suspended between two supports A and B which are at different levels and O is the lowest point on the conductor. Let l = Span length h = Difference in levels between two supports x1 = Distance of support at lower level (i.e., A) from O x2 = Distance of support at higher level (i.e. B) from O T = Tension in the conductor ▪ If w is the weight per unit length of the conductor, then At support A, x = x1 and y = S1. since PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof., RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
  • 20. PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof., RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
  • 21. Effect of wind and ice loading ▪ The tension is governed by conductor weight, effects of wind, ice loading and temperature variations. ▪ In actual practice, a conductor may have ice coating and simultaneously subjected to wind pressure. The weight of ice acts vertically downwards i.e., in the same direction as the weight of conductor. ▪ The force due to the wind is assumed to act horizontally i.e., at right angle to the projected surface of the conductor. Hence, the total force on the conductor is the vector sum of horizontal and vertical forces. PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof., RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT
  • 22. When the conductor has wind and ice loading also, the following points may be noted: The conductor sets itself in a plane at an angle  to the vertical where The sag in the conductor is given by Hence S represents the slant sag in a direction making an angle  to the vertical. If no specific mention is made in the problem, then slant slag is calculated by using the above formula. The vertical sag = S cos  PATHAKAMURI NARESH (Ph.D.) ,Asst. Prof., RAGHU ENGINEERING COLLEGE (a) overhead line insulators & sag EEE DEPARTMENT