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kf kb
v = k C(0,t) = i/nFA
mole/cm2-s = cm/s × mole/cm3 = (coul/s)(mole/coul)(1/cm2)
 is a transmission coefficient
Electrode Kinetics: Charge transfer control (Activation Polarization)
v = kC(0,t) = i/nFA i = nFAkC(0,t)
inet = nFA[kf CO(0,t) - kbCR(0,t)]
vf = kf CO(0,t)
O + e- = R
vb= kbCR(0,t)
vnet=vf-vb = kf CO(0,t) - kbCR(0,t)
Since v is measured in moles/cm2-s if we multiply by the number of coulombs per mole
(nFA) in the rate equation we get a current.
Now consider a 1e- redox reaction
We can write a rate expression for
each and the net rate is just the
difference.
O+e- R
Apply and E > Eo so that (E-Eo ) > 0. The activation barrier for the anodic reaction
has been reduced by and that for the cathodic reduction reaction
Has been increased by .
Reaction coordinate Reaction coordinate
The effect of applied potential on activation free energy
f = F/RT
Application of a potential greater
than Eo reduces the Act. Barrier for
the oxidation (anodic) process and
the activation barrier for the reduction
(cathodic) process.
and these Act. Free energies we
write the forward and backward
rate constants as,
From our general expression for the
rate constant,
where
Inserting these relations in to inet = nFA[kf CO(0,t) - kbCR(0,t)] yields,
Note that if we set i = 0
Then E = Eequil and we recover the Nernst Equation.
Even though the net current is zero at the equilibrium potential, the oxidation and
reduction currents are not – they just add together to yield zero since they are equal
In magnitude. We can express this so-called exchange current (or exchange current density)
In terms of either ia or ic,
or
Raising both sides of to the –α power yields
And substitution into the expression for the exchange current yields an expression
For io in terms of the bulk concentrations of O and R,
dividing
by the expression for io
and after a bit of algebraic manipulation
If the surface and bulk concentrations of O and R are equal then there are NO mass
transfer effects. The system is under activation (charge transfer)control.
Butler-Volmer Equation
The symmetry factor, α
α is dependent on the energy landscape in transitioning from O to R and vice versa.
This term together with the io term in the B-V equation contains lots of buried physics,
much if it poorly understood.
Butler-Volmer Equation
There are two regimes of behavior:
High η: At 298 K this occurs when
Tafel Equation
Low η:
Tafel Plot
charge transfer resistance Rct
Electrode kinetics
Electrode kinetics

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Electrode kinetics

  • 1. kf kb v = k C(0,t) = i/nFA mole/cm2-s = cm/s × mole/cm3 = (coul/s)(mole/coul)(1/cm2)  is a transmission coefficient Electrode Kinetics: Charge transfer control (Activation Polarization)
  • 2. v = kC(0,t) = i/nFA i = nFAkC(0,t) inet = nFA[kf CO(0,t) - kbCR(0,t)] vf = kf CO(0,t) O + e- = R vb= kbCR(0,t) vnet=vf-vb = kf CO(0,t) - kbCR(0,t) Since v is measured in moles/cm2-s if we multiply by the number of coulombs per mole (nFA) in the rate equation we get a current. Now consider a 1e- redox reaction We can write a rate expression for each and the net rate is just the difference.
  • 3. O+e- R Apply and E > Eo so that (E-Eo ) > 0. The activation barrier for the anodic reaction has been reduced by and that for the cathodic reduction reaction Has been increased by . Reaction coordinate Reaction coordinate The effect of applied potential on activation free energy
  • 4. f = F/RT Application of a potential greater than Eo reduces the Act. Barrier for the oxidation (anodic) process and the activation barrier for the reduction (cathodic) process. and these Act. Free energies we write the forward and backward rate constants as, From our general expression for the rate constant, where
  • 5. Inserting these relations in to inet = nFA[kf CO(0,t) - kbCR(0,t)] yields,
  • 6. Note that if we set i = 0 Then E = Eequil and we recover the Nernst Equation. Even though the net current is zero at the equilibrium potential, the oxidation and reduction currents are not – they just add together to yield zero since they are equal In magnitude. We can express this so-called exchange current (or exchange current density) In terms of either ia or ic, or
  • 7. Raising both sides of to the –α power yields And substitution into the expression for the exchange current yields an expression For io in terms of the bulk concentrations of O and R, dividing by the expression for io
  • 8. and after a bit of algebraic manipulation If the surface and bulk concentrations of O and R are equal then there are NO mass transfer effects. The system is under activation (charge transfer)control. Butler-Volmer Equation
  • 9. The symmetry factor, α α is dependent on the energy landscape in transitioning from O to R and vice versa. This term together with the io term in the B-V equation contains lots of buried physics, much if it poorly understood.
  • 10. Butler-Volmer Equation There are two regimes of behavior: High η: At 298 K this occurs when Tafel Equation Low η: Tafel Plot charge transfer resistance Rct