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2a What is the thermal diffusivity for a 100m wide granite 
intrusion which takes 240 years to cool via conduction?
2a • Convert years to seconds:
2a • Convert years to seconds: 
240 years = 240 x 365 x 24 x 60 x 60 seconds = 7.57 x 109s
2a • Convert years to seconds: 
240 years = 240 x 365 x 24 x 60 x 60 seconds = 7.57 x 109s 
• Rearrange the first equation for κ and substitute in the values 
you know:
2a • Convert years to seconds: 
240 years = 240 x 365 x 24 x 60 x 60 seconds = 7.57 x 109s 
• Rearrange the first equation for κ and substitute in the values 
you know: 
κ = 
x2 
tCHAR 
= 
1002m2 
7.57 x 109s 
= ퟏ. ퟑퟐ 퐱 ퟏퟎ−ퟔ퐦ퟐ퐬−ퟏ
2b Use this to calculate the specific heat of granite if it has 
density 2.7 x 103kgm-3 and thermal conductivity 2.8Wm- 
1K-1 and check that the units are balanced.
2b • Rearrange the second equation for Cp and substitute in the values you 
know:
2b • Rearrange the second equation for Cp and substitute in the values you 
know: 
κ = 
k 
ρ. Cp
2b • Rearrange the second equation for Cp and substitute in the values you 
know: 
κ = 
k 
ρ. Cp 
κρCp = k
2b • Rearrange the second equation for Cp and substitute in the values you 
know: 
κ = 
k 
ρ. Cp 
κρCp = k 
Cp = 
k 
κρ 
= 
2.8 
1.32 x 10−6 x 2.7 x 103 = ퟕퟖퟓ. ퟔퟑ퐉퐤퐠−ퟏ퐊−ퟏ
2b • Rearrange the second equation for Cp and substitute in the values you 
know: 
κ = 
k 
ρ. Cp 
κρCp = k 
Cp = 
k 
κρ 
= 
2.8 
1.32 x 10−6 x 2.7 x 103 = ퟕퟖퟓ. ퟔퟑ퐉퐤퐠−ퟏ퐊−ퟏ 
• Check the units, remembering 1J = 1Ws:
2b • Rearrange the second equation for Cp and substitute in the values you 
know: 
κ = 
k 
ρ. Cp 
κρCp = k 
Cp = 
k 
κρ 
= 
2.8 
1.32 x 10−6 x 2.7 x 103 = ퟕퟖퟓ. ퟔퟑ퐉퐤퐠−ퟏ퐊−ퟏ 
• Check the units, remembering 1J = 1Ws: 
Wm−1K−1 
m2s−1kgm−3 = 
Js−1m−1K−1 
s−1m−1kg 
= 퐉퐤퐠−ퟏ퐊−ퟏ

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W2 Example 2 Answers

  • 1. 2a What is the thermal diffusivity for a 100m wide granite intrusion which takes 240 years to cool via conduction?
  • 2. 2a • Convert years to seconds:
  • 3. 2a • Convert years to seconds: 240 years = 240 x 365 x 24 x 60 x 60 seconds = 7.57 x 109s
  • 4. 2a • Convert years to seconds: 240 years = 240 x 365 x 24 x 60 x 60 seconds = 7.57 x 109s • Rearrange the first equation for κ and substitute in the values you know:
  • 5. 2a • Convert years to seconds: 240 years = 240 x 365 x 24 x 60 x 60 seconds = 7.57 x 109s • Rearrange the first equation for κ and substitute in the values you know: κ = x2 tCHAR = 1002m2 7.57 x 109s = ퟏ. ퟑퟐ 퐱 ퟏퟎ−ퟔ퐦ퟐ퐬−ퟏ
  • 6. 2b Use this to calculate the specific heat of granite if it has density 2.7 x 103kgm-3 and thermal conductivity 2.8Wm- 1K-1 and check that the units are balanced.
  • 7. 2b • Rearrange the second equation for Cp and substitute in the values you know:
  • 8. 2b • Rearrange the second equation for Cp and substitute in the values you know: κ = k ρ. Cp
  • 9. 2b • Rearrange the second equation for Cp and substitute in the values you know: κ = k ρ. Cp κρCp = k
  • 10. 2b • Rearrange the second equation for Cp and substitute in the values you know: κ = k ρ. Cp κρCp = k Cp = k κρ = 2.8 1.32 x 10−6 x 2.7 x 103 = ퟕퟖퟓ. ퟔퟑ퐉퐤퐠−ퟏ퐊−ퟏ
  • 11. 2b • Rearrange the second equation for Cp and substitute in the values you know: κ = k ρ. Cp κρCp = k Cp = k κρ = 2.8 1.32 x 10−6 x 2.7 x 103 = ퟕퟖퟓ. ퟔퟑ퐉퐤퐠−ퟏ퐊−ퟏ • Check the units, remembering 1J = 1Ws:
  • 12. 2b • Rearrange the second equation for Cp and substitute in the values you know: κ = k ρ. Cp κρCp = k Cp = k κρ = 2.8 1.32 x 10−6 x 2.7 x 103 = ퟕퟖퟓ. ퟔퟑ퐉퐤퐠−ퟏ퐊−ퟏ • Check the units, remembering 1J = 1Ws: Wm−1K−1 m2s−1kgm−3 = Js−1m−1K−1 s−1m−1kg = 퐉퐤퐠−ퟏ퐊−ퟏ