1. 4a Using the other units given in the question, deduce the
units of wind stress. What else is this unit known as?
What is it a measure of?
2. 4a Note: Brackets around 휏 represent its units.
• Replace the values in the first equation for their units:
3. 4a Note: Brackets around 휏 represent its units.
• Replace the values in the first equation for their units:
(τ) = kgm−3. ms−1. ms−1
4. 4a Note: Brackets around 휏 represent its units.
• Replace the values in the first equation for their units:
(τ) = kgm−3. ms−1. ms−1
• Group the same units together and simplify:
5. 4a Note: Brackets around 휏 represent its units.
• Replace the values in the first equation for their units:
(τ) = kgm−3. ms−1. ms−1
• Group the same units together and simplify:
(τ) = kg (m−3. m1. m1)(s−1. s−1)
6. 4a Note: Brackets around 휏 represent its units.
• Replace the values in the first equation for their units:
(τ) = kgm−3. ms−1. ms−1
• Group the same units together and simplify:
(τ) = kg (m−3. m1. m1)(s−1. s−1)
(τ) = 퐤퐠퐦−ퟏ퐬−ퟐ
7. 4a Note: Brackets around 휏 represent its units.
• Replace the values in the first equation for their units:
(τ) = kgm−3. ms−1. ms−1
• Group the same units together and simplify:
(τ) = kg (m−3. m1. m1)(s−1. s−1)
(τ) = 퐤퐠퐦−ퟏ퐬−ퟐ
This unit is also known as a Pascal, Pa. It is a unit of pressure.
8. 4b What wind speed would produce a drag coefficient of 1.05
x 10-3?
9. 4b • Substitute the values you know into the second equation:
10. 4b • Substitute the values you know into the second equation:
1.05 x 10−3 = 0.53 + 0.064U x 10−3
11. 4b • Substitute the values you know into the second equation:
1.05 x 10−3 = 0.53 + 0.064U x 10−3
• Cancel out 10-3:
12. 4b • Substitute the values you know into the second equation:
1.05 x 10−3 = 0.53 + 0.064U x 10−3
• Cancel out 10-3:
1.05 = 0.53 + 0.064U
13. 4b • Substitute the values you know into the second equation:
1.05 x 10−3 = 0.53 + 0.064U x 10−3
• Cancel out 10-3:
1.05 = 0.53 + 0.064U
• Rearrange for U:
14. 4b • Substitute the values you know into the second equation:
1.05 x 10−3 = 0.53 + 0.064U x 10−3
• Cancel out 10-3:
1.05 = 0.53 + 0.064U
• Rearrange for U:
1.05 − 0.53 = 0.064U
15. 4b • Substitute the values you know into the second equation:
1.05 x 10−3 = 0.53 + 0.064U x 10−3
• Cancel out 10-3:
1.05 = 0.53 + 0.064U
• Rearrange for U:
1.05 − 0.53 = 0.064U
U =
1.05 − 0.53
0.064
= ퟖ. ퟏퟐퟓ퐦퐬−ퟏ
16. 4c Using only the first equation for wind stress, calculate the
wind speed needed to produce a wind stress of 4.9 x 10-2
Pa. Assume the density of air is 1.225 kgm3 and the drag
coefficient is 9.46 x 10-4.
19. 4c • Rearrange the first equation for U:
ρACDU2 = τ
U2 =
τ
ρACD
20. 4c • Rearrange the first equation for U:
ρACDU2 = τ
U2 =
τ
ρACD
U =
τ
ρACD
21. 4c • Rearrange the first equation for U:
ρACDU2 = τ
U2 =
τ
ρACD
U =
τ
ρACD
• Substitute in the values you know:
22. 4c • Rearrange the first equation for U:
ρACDU2 = τ
U2 =
τ
ρACD
U =
τ
ρACD
• Substitute in the values you know:
4.9 x 10−2
1.225 x 9.46 x 10−4 = ퟔ. ퟓퟎ퐦퐬−ퟏ