This document presents a derivation of the relationship between three elastic moduli: Young's modulus (E), bulk modulus (K), and shear modulus (G). It begins by introducing Hooke's law and defining the three elastic moduli based on the type of stress and strain. It then presents the main result - an equation relating E, K, and G with an arbitrary angle φ. The derivation considers a two-dimensional body under shear stress and calculates the strain produced. It then extends this to a three-dimensional body under multi-axial stresses to relate the elastic moduli and Poisson's ratio. Eliminating Poisson's ratio produces the final relationship between E, K, and G.
2. Nazim A. Khan and Kaleem A. Quraishi
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(i) Modulus of Elasticity )(E
e
E n
strainNormal
stressNormal
(1.1)
(ii) Modulus of Rigidity )(G
tanstrainShear
stressShear
se
G (1.2)
(iii) Bulk modulus )(K
e
K n
strainVolumetric
stresscHydrostati
(1.3)
3. Elastic Modul II and Their Relationship by Considering any Arbitrary Angle
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2. MAIN RESULT
The relationship among Young Modulus of Elasticity among ,E Bulk Modulus of
Elasticity K and Rigid Modulus of Elasticity G is given by
24
cos23
9
KG
GK
E (2.1)
where is the angle through which face AD tilted from its original position.
3. DERIVATION
Consider a two dimensional body subjected to shear stress as its lower surface is fixed
and force is applied on the upper surface. Due to produced shear stress the length of
the diagonal DB will increase and length of diagonal AC will increase. The surface
AB will shift rightward to BA as shown in figure.
4. Nazim A. Khan and Kaleem A. Quraishi
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From triangle ADA
AA
AD
AA
tan
BBtanAA (3.1)
2
BB
BD
BDBD
DBdiagonalinproducedStrain 0
(3.2)
From triangle BBB 0
BB
BB
24
cos 0
24
cosBBBB0
(3.3)
From (3.2) and (3.3), we get
2
24
cosBB
DBdiagonalinproducedStrain
(3.4)
From (3.1) and (3.4), we have
2
24
costan
DBdiagonalinproducedStrain
(3.5)
Linear strain produced in diagonal DB
)1(
EEE
(3.6)
From (3.5) and (3.6), we get
2
24
costan
)1(
E
24
costan
)1(2
E
From (1.2), we have
24
cos
)1(2
G
E (3.7)
Consider a three dimensional body of length , breadth b and thickness .t
Suppose the stress induced in the body along length be .x Similarly stress induced
in the body along breadth b and thickness t be y and z respectively. As we know
that strain induced in the direction of force applied is longitudinal or linear strain and
strain induced in the perpendicular direction of force applied is lateral strain.
5. Elastic Modul II and Their Relationship by Considering any Arbitrary Angle
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For calculating the linear strain in the particular direction, lateral strain induced in the
other direction by the same force is to be subtracted for that particular direction.
Strain produced in the length
EEE
e zyx
EEE
e zxy
b
EEE
e
yxz
t
Overall volumetric strain produced is
EEEEEE
eeee zyxzyx
tbV
2
)21(
363
EEE
e nnn
V
)21(
3
V
n
e
E
)21(3 KE (3.8)
Eliminating from (3.7) and (3.8), we get the main result (2.1).
6. Nazim A. Khan and Kaleem A. Quraishi
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REFERENCES
[1] Chakraborti, M.; Strength of Materials, Second Edition, S. K. Kataria and Sons,
New Delhi, 2001.
[2] Ryder, G. H.; Strength of Materials, Third Edition in S. I. Units, Macmillan
Publishers India Limited, New Delhi, 1969; Reprinted in 2011.
[3] Singh, S.; Strength of Materials, Tenth Edition, Khanna Publishers, New Delhi,
2010.
[4] Praveen Ailawalia and Shilpy Budhiraja, Disturbance In Generalized
Thermoelastic Medium with Internal Heat Source Under Hydrostatic Initial
Stress and Rotation, International Journal of Mechanical Engineering and
Technology, 3(3), 2012, pp. 315-330.