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How can this problem be solved using arrays alone? (without functions or anytheing else) i
couldnt figure out how to display the arrays side by side.
Declare two integer arrays list1 and list2 of size 10. Fill both arrays with the random numbers
from 5 to 25. Display two arrays side to side as shown in the sample output. Input an integer n
Check if if n is found in any of the arrays and print its location if it is found. Please note that
your output will be different because the arrays are initialized randomly Sample input / output:
Array #1 - Array #2 25 9 8 5 Array #1 - Array #2 6 25 5 5 25 23 25 20 25 5 Enter a number: 13
Enter a number: 17 13 was found in 1 arrau Location of 13 in Array #1 : 2 17 was found in both
arraus Location of 17 in Array #1: 9 Location of 17 in Array #2:
Solution
#include <iostream>
#include <cstdlib> /* srand, rand */
#include <ctime> // time
#include<iomanip>
using namespace std;
int main() {
int list1[10],list2[10],n,flag1 = 0,flag2=0,pos1 = -1,pos2=-1;
srand(1000);
for(int i=0;i<10;i++){
list1[i] = rand()%21+5;
list2[i] = rand()%21+5;
}
cout<<"Array #1 - Array #2"<<endl;
for(int i=0;i<10;i++){
cout<<" "<<list1[i]<<" "<<list2[i]<<endl;
}
cout<<"Enter a number : ";
cin>>n;
for(int i=0;i<10;i++){
if(list1[i]==n){
flag1 = 1;
pos1 = i;
break;
}
}
for(int i=0;i<10;i++){
if(list2[i]==n){
flag2 = 1;
pos2 = i;
break;
}
}
if(flag1 && flag2){
cout<<n<<" was found in both arrays"<<endl;
cout<<"Location of "<<n<<" found in array #1 :"<<pos1<<endl;
cout<<"Location of "<<n<<" found in array #2 :"<<pos2<<endl;
}
else if(flag1){
cout<<n<<" was found in 1 array"<<endl;
cout<<"Location of "<<n<<" found in array #1 :"<<pos1<<endl;
}
else if(flag2){
cout<<n<<" was found in 1 array"<<endl;
cout<<"Location of "<<n<<" found in array #2 :"<<pos2<<endl;
}
else
cout<<n<<" was not found in any array"<<endl;
return 0;
}

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How can this problem be solved using arrays alone- (without functions.docx

  • 1. How can this problem be solved using arrays alone? (without functions or anytheing else) i couldnt figure out how to display the arrays side by side. Declare two integer arrays list1 and list2 of size 10. Fill both arrays with the random numbers from 5 to 25. Display two arrays side to side as shown in the sample output. Input an integer n Check if if n is found in any of the arrays and print its location if it is found. Please note that your output will be different because the arrays are initialized randomly Sample input / output: Array #1 - Array #2 25 9 8 5 Array #1 - Array #2 6 25 5 5 25 23 25 20 25 5 Enter a number: 13 Enter a number: 17 13 was found in 1 arrau Location of 13 in Array #1 : 2 17 was found in both arraus Location of 17 in Array #1: 9 Location of 17 in Array #2: Solution #include <iostream> #include <cstdlib> /* srand, rand */ #include <ctime> // time #include<iomanip> using namespace std; int main() { int list1[10],list2[10],n,flag1 = 0,flag2=0,pos1 = -1,pos2=-1; srand(1000); for(int i=0;i<10;i++){ list1[i] = rand()%21+5; list2[i] = rand()%21+5; } cout<<"Array #1 - Array #2"<<endl; for(int i=0;i<10;i++){ cout<<" "<<list1[i]<<" "<<list2[i]<<endl; } cout<<"Enter a number : "; cin>>n; for(int i=0;i<10;i++){ if(list1[i]==n){ flag1 = 1;
  • 2. pos1 = i; break; } } for(int i=0;i<10;i++){ if(list2[i]==n){ flag2 = 1; pos2 = i; break; } } if(flag1 && flag2){ cout<<n<<" was found in both arrays"<<endl; cout<<"Location of "<<n<<" found in array #1 :"<<pos1<<endl; cout<<"Location of "<<n<<" found in array #2 :"<<pos2<<endl; } else if(flag1){ cout<<n<<" was found in 1 array"<<endl; cout<<"Location of "<<n<<" found in array #1 :"<<pos1<<endl; } else if(flag2){ cout<<n<<" was found in 1 array"<<endl; cout<<"Location of "<<n<<" found in array #2 :"<<pos2<<endl; } else cout<<n<<" was not found in any array"<<endl; return 0; }