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A Seawater Fish
Tank
Component 1: Short Review
Q1. What is one example of a solution?
Q2. What are two common examples of heterogenous
mixtures that you would find in your kitchen?
Q3. Explain why sea water is a homogenous mixture?
7 m….
Q1. An example of a solution is seawater, a cup of tea
or coffee or a soft drink.
Q2 One example would be orange juice another would
be sago or fruit yoghurt or a bowl of cereal with milk.
Q3. Seawater is a mixture of two pure substances (they
are both compounds): water and salt. The salt dissolves
in the water to make a clear (uniform) homogenous
solution/mixture
Lesson purpose /Intention
The lesson is about homogenous
and heterogenous mixtures. We
want to be sure we know and
understand about solutions and
their concentrations. 3m…
Mixture
Solution
Uniform 5m…
 Select one of the words above and write
one sentence using that word in everyday
language.
 Select one of the words above and write
one sentence using the scientific meaning
of that word.
• The soldier is wearing a
uniform.
• Sea water is a solution.
How much salt?
Joshua asked his mother if he could have a fish tank and as
they live near the sea could he use sea water. His mother
agreed and said that he would have to look after it himself.
She said he could use the kitchen but had to clean up after
himself.
Joshua thought “I wonder just how much salt is in a bucket of
sea water in case I can’t get to the beach if I need to replace
the water, I should be able to make my own.”
Joshua decides to experiment by separating the water from
the salt to find out exactly how much salt there is in 200 mL of
sea water. 25m…
Q1. What would be the best process that Joshua could use to
separate the salt from the sea water?
Q2. What are two very important measurements Joshua must
make in his experiment?
Q3. What other important things does he have to do to make
sure his experiment is fair?
Q1. The best process would be evaporation/ he
should heat the seawater.
Q2. He has to measure the volume of sea water
and the mass/weight of salt left behind.
Q3. To make sure his experiment is fair he must
make sure that all the conditions are the same
while he does the measurements and that he
uses the same measuring devices and seawater
from the same source.
Q1. What piece of equipment does Joshua need to measure the
amount of salt in the 200 mL of sea water?
Q2. Joshua’s three readings for the mass of salt after
evaporation are 6.5 g, 7.0 g and 7.5 g. What value for the
weight/mass of salt should he use?
Q3. Joshua was very accurate with his measurement of the
volume of sea water so what is the concentration of the
seawater in his experiment? Give your answer in grams per
liter. 25m…
Q1. He needs a set of weighing scales, like
those in the kitchen, that measure grams or
parts of kilograms.
Q2. He should use 7.0 g [the average of the
three measurements].
Q3. The concentration is 35 g per liter.
[Working example: 7.0 g in 200 mL of water –
which is 7.0 x 5 for 1 L, which is 35 g/L]
Mass of salt after evaporation
- 6.5g + 7.0g + 7.5g = 21g - 1L/.2L
- = 21g - = 5L
- 21g/3
- = 7grams 7grams x 5L
= 35g/L
- 7grams in 200mL which is;
- 200mL = L
- 200mL x 1L/1,000mL
- 200L/1,000
- .2L
Q1. Did you find Joshua’s experiment interesting?
If so, why?
Q2. Did you find the questions in component 4C
harder than the questions in component 4B? If
so, why? 5m…
THANK YOU!

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Lesson-3_A-Seawater-Fish-Tank.pptx

  • 2. Component 1: Short Review Q1. What is one example of a solution? Q2. What are two common examples of heterogenous mixtures that you would find in your kitchen? Q3. Explain why sea water is a homogenous mixture? 7 m….
  • 3. Q1. An example of a solution is seawater, a cup of tea or coffee or a soft drink. Q2 One example would be orange juice another would be sago or fruit yoghurt or a bowl of cereal with milk. Q3. Seawater is a mixture of two pure substances (they are both compounds): water and salt. The salt dissolves in the water to make a clear (uniform) homogenous solution/mixture
  • 4. Lesson purpose /Intention The lesson is about homogenous and heterogenous mixtures. We want to be sure we know and understand about solutions and their concentrations. 3m…
  • 6.  Select one of the words above and write one sentence using that word in everyday language.  Select one of the words above and write one sentence using the scientific meaning of that word.
  • 7. • The soldier is wearing a uniform. • Sea water is a solution.
  • 8. How much salt? Joshua asked his mother if he could have a fish tank and as they live near the sea could he use sea water. His mother agreed and said that he would have to look after it himself. She said he could use the kitchen but had to clean up after himself. Joshua thought “I wonder just how much salt is in a bucket of sea water in case I can’t get to the beach if I need to replace the water, I should be able to make my own.” Joshua decides to experiment by separating the water from the salt to find out exactly how much salt there is in 200 mL of sea water. 25m…
  • 9. Q1. What would be the best process that Joshua could use to separate the salt from the sea water? Q2. What are two very important measurements Joshua must make in his experiment? Q3. What other important things does he have to do to make sure his experiment is fair?
  • 10. Q1. The best process would be evaporation/ he should heat the seawater. Q2. He has to measure the volume of sea water and the mass/weight of salt left behind. Q3. To make sure his experiment is fair he must make sure that all the conditions are the same while he does the measurements and that he uses the same measuring devices and seawater from the same source.
  • 11. Q1. What piece of equipment does Joshua need to measure the amount of salt in the 200 mL of sea water? Q2. Joshua’s three readings for the mass of salt after evaporation are 6.5 g, 7.0 g and 7.5 g. What value for the weight/mass of salt should he use? Q3. Joshua was very accurate with his measurement of the volume of sea water so what is the concentration of the seawater in his experiment? Give your answer in grams per liter. 25m…
  • 12. Q1. He needs a set of weighing scales, like those in the kitchen, that measure grams or parts of kilograms. Q2. He should use 7.0 g [the average of the three measurements]. Q3. The concentration is 35 g per liter. [Working example: 7.0 g in 200 mL of water – which is 7.0 x 5 for 1 L, which is 35 g/L]
  • 13. Mass of salt after evaporation - 6.5g + 7.0g + 7.5g = 21g - 1L/.2L - = 21g - = 5L - 21g/3 - = 7grams 7grams x 5L = 35g/L - 7grams in 200mL which is; - 200mL = L - 200mL x 1L/1,000mL - 200L/1,000 - .2L
  • 14. Q1. Did you find Joshua’s experiment interesting? If so, why? Q2. Did you find the questions in component 4C harder than the questions in component 4B? If so, why? 5m…