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ot t) Pm 1 is ul 9g niv ti oh ec il Solution The molecule has the formula AX4E2 , according to VSEPR theory A is the central atom X is the bonded atom E is the lone pair of electrons Thus the cnetral atom has 6 pairs of electrons, with octahedral electron geometry .Due to the presence of two lone pairs the molecular geometry is square planar with both the lone pairs occupying the axial positions. option e.

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Explain how enzymes work, explaining the four major types of metabolic reactions enzymes perform. Include: (Metabolism, catabolism, anabolism, substrate product, active site, induced fit, competative and non competative inhibitors, allosteric regulation, cofactors and coenzymes, hydrolysis and dehydration reactions, Redox Reactions, NADH, FADH2, phosphorylation, exergonic/ endergonic reactions, ATP, isomerization reactions, feedback inhibition) Solution Enzymes are biological molecules (typically proteins) that significantly speed up the rate of virtually all of the chemical reactions that take place within cells. They are vital for life and serve a wide range of important functions in the body, such as aiding in digestion and metabolism. Substrate binding[edit] Enzymes must bind their substrates before they can catalyse any chemical reaction. Enzymes are usually very specific as to what substrates they bind and then the chemical reaction catalysed. Specificity is achieved by binding pockets with complementary shape, charge and hydrophilic/hydrophobic characteristics to the substrates. Enzymes can therefore distinguish between very similar substrate molecules to be chemoselective, regioselective and stereospecific. Some of the enzymes showing the highest specificity and accuracy are involved in the copying and expression of the genome. Some of these enzymes have \"proof-reading\" mechanisms. Here, an enzyme such as DNA polymerase catalyzes a reaction in a first step and then checks that the product is correct in a second step. This two-step process results in average error rates of less than 1 error in 100 million reactions in high-fidelity mammalian polymerases.:5.3.1 Similar proofreading mechanisms are also found in RNA polymerase, aminoacyl tRNA synthetases and ribosomes. Conversely, some enzymes display enzyme promiscuity, having broad specificity and acting on a range of different physiologically relevant substrates. Many enzymes possess small side activities which arose fortuitously (i.e. neutrally), which may be the starting point for the evolutionary selection of a new function. Enzyme changes shape by induced fit upon substrate binding to form enzyme-substrate complex. Hexokinase has a large induced fit motion that closes over the substrates adenosine triphosphate and xylose. Binding sites in blue, substrates in black and Mg2+ cofactor in yellow. (PDB: 2E2N, 2E2Q) \"Lock and key\" model To explain the observed specificity of enzymes, in 1894 Emil Fischer proposed that both the enzyme and the substrate possess specific complementary geometric shapes that fit exactly into one another.This is often referred to as \"the lock and key\" model:8.3.2 This early model explains enzyme specificity, but fails to explain the stabilization of the transition state that enzymes achieve. Induced fit model In 1958, Daniel Koshland suggested a modification to the lock and key model: since enzymes are rather flexible structures, the active site is conti.

Explain how enzymes work, explaining the four major types of metabol.pdf

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Develop an inventory management system for an electronics store. The inventory system should have the following functionalities .BuildInventory: reada text file containing electronics products information and store them in an array of pointers .Shownventory display all inventory items .ShowDefectInventory: display inventory items that are defective Terminate: to save cument inventory to a text file This lab assignment illustrates the following concepts: -Text file readings and writings .Arrays of pointers and dynamic memory allocations with new and delete Inheritance .C++ type casting: static cast Class Design You need at least three classes class Inventory System: (minimum implementation specified below). This class stores Inyentoryltem objects (which are in fact Inventory item base class pointers to derived Product objects and member functions to manipulate those Product objects as shown below. .Private data members Store Name Store ID ltem List (array of pointers to Inventory Item objects, max of 512) ltem Count (tracking how many items are currently stored in the array) .Constructors (initialize all pointers in the array to NULL in addition to what\'s described below .Default constructor: set data members to 0 (for integers), 0.0 (for float/double), or NULL (for pointers) as appropriate. Also invoke this function to initialize a seed for the random generator srand (time (NULL), (to be used later by Product class to genearte random values for Product ID. See Code Helper section at the end of the lab specs.) .Non-default constructor: taking a string for store name, an integer for store ID. Call srand as shown above Destructor: de-allocate dynamic memory in the amay off pointers (up to Item Count elements) .Public member functions: BuildInventory: read a text file containing Product records (one Product per line), dynamically allocate Product objects and store the objects in the array ItemList (an array of Inventoryltem pointers). It should also update Item Count as needed Shownventory: display all Products in the inventory. Output must be properly formatted and aligned (usingfield with and floating data with 2 digits after decimal point). Note that if you invoke the Display function using the pointers from the array only Invent tem (base objec) information will be displayed. Extra work is needed to properly display Products (derived objects) information ntory: display only defective Products Terminate: iterate thru the array of pointers to write Product objects in the array to a text file in the same format as they were read in. You may use a different file name for wniting .mutator cessors for store name, store id, and item count Solution /* import com.incors.plaf.*; import com.incors.plaf.kunststoff.*; import com.incors.plaf.kunststoff.themes.*; */ public class MainForm extends JFrame implements WindowListener{ /************************ Variable declaration start **********************/ //The form container variable JPanel Panel1; JDeskto.

Develop an inventory management system for an electronics store. The .pdf

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Describe one event from your daily life when you have changed your original attitude, and one event when you could not change your original attitude. For the event when you changed your original attitude, explain how you changed your attitude and what led to the change. For the event when you could not change your original attitude, explain what did not work. Submission Requirements: Submit your responses in a Microsoft Word document of the following specifications:•Font: Arial; 12-Point •Line Spacing: Double •Length: 300–500 words Evaluation Criteria:•Did you describe one event from your daily life when you have changed your original attitude? •Did you describe one event from your daily life when you have not changed your original attitude? •Did you explain how you changed your attitude and what led to the change? •Did you explain what did not work when you could not change your original attitude? •Did you provide your answers in complete sentences with few grammatical errors? Solution Instance where I changed my Attitude - I don\'t believe in charity and philanthropy. I had this firm belief that money given to NGOs and trusts in grants is mis-used. I always believed in commercial models and never realized that texcept for a few most of development agencies are working for the welfare of people. When I came acrossNanhi Kali NGO which works for girl child education I was sure that this is another fraud NGOs which improperly utilizes the money earned in grant. But when I visited the centre and saw the real impact on ground then my eyes remained wide open. They were doing awesome work and even there financial statements were also showing this. This instance changed my attitude towards NGOs. What made me Change - The critical factor which made me change my attitude is my interaction with foundation and meeting with a few girls who really got benefits from the activities of NGO. The interaction helped me understand their model in a better way. When I analyzed their financials I realized that manpower is working at half the salaries and highly motivated and focused towards the cause. This all made me change my attitude. Instance Where my attitude remained same - Based on the learnings from my experiences in past I believed that people in politics are not good at heart. Politicians should ideally be social worker and should have a motive of public welfare but noboday remember their promises once elected. I always had this image of politicans in mind. A lot of people tried to convince me that new breed of politicans are good and not greedy but I remained and still firm on my attitude that all politicans are not good people. Reasons behind my attitude - This attitude had been built over a period of time. There is no substantial argument against my attitude which can make me think. This is why I still beleive that none of the politician is good person..

Describe one event from your daily life when you have changed your o.pdf

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All answers must be in your own words Provide a good, understandable definition of the following 40, using your own words (do not simply copy words from the book). Retaliation Blood feud Vendetta Civil death Inquisition Corporal punishment Brank Criminology Mamertine Prison Sanctuary Bridewell Jail fever Age of Enlightenment Classical School of Criminology Workhouse Gaols Banishment Transportation Hulks Penitentiary Pennsylvania System Outside cell Inside cell Eastern Penitentiary Auburn System Cell block Congregate system System of silence Lockstep formation Prison stripes Treadmill Solitary confinement Indeterminate sentence Irish system Reformatory Industrial prison Alcatraz Lock psychosis Convict bogey Ombudsman Ticket of Leave Solution Retaliation – In the event of attack by the enemy, do the fierce counter attack from our side. Blood feud – It is lengthy fighting in the families going on for the generations. It involves killing of various members of the families. Vendetta – Person whose relative has been killed seeks revenge from the murderer. Civil death – It is the loss of the civil rights which is the result of act of government in the some of conviction of civil people. Inquisition – Out of curiosity asking many question on the related topic. Corporal punishment – It is the type of punishment which involves physical pain. It involves mutilation, flogging branding etc. Brank – It is the birdcage- like instrument put on prisonr’s head with sharp plates that would cut tongues and mouths once involved in the gossips Criminology – This is the branch of science which involves study of crime and criminals. Mamertine Prison – In the early age in the Rome confinement are under the main sewers where survival is very difficult even for few days.. Sanctuary – It means taking shelter or refuge from the danger or pursuit. Bridewell – It is called for city jail or reform center or jail for pity offender. Jail fever – It is the former name to the typhus. It is commonly occurred in the jail so got he name from its origin. Age of Enlightenment – European politics, philosophy, science and communications were radically reoriented during beginning of the 18th century and then throughout of the 18th century. This period is known as Age of Enlightenment. Classical School of Criminology – It is the body of thought which understands the nature of crime and suggests the best form of punishment to the crime. Looking at the severity of the punishment in the early 18th century philosopher come up with this type of thoughts. Workhouse – It is the place where unemployed people who can not support themselves were given shelter and employment. Gaols – It the synonym to the jail. It is the place of confinement to the criminals. Banishment – As an act of punishment offender are sent away from the designated place or country known as banishment. Transportation – It is the act of movement of goods or people from one place to another place. Hulks – It is an old ship whi.

All answers must be in your own wordsProvide a good, understandabl.pdf

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C programming tweak needed for a specific program. This is the complete program up and running. except for one modification that my teacher is requiring but it is confusing me. The program needs to allocate disjoint memory and use that. right now im allocating a continous block of memory on the heap but I need it to do disjoing memory instead. // Purpose: Program will allow a reseller to save their sales and calculate their profits. // Also able to view highest profitable items and remove any sales they no longer want in their sales inventory. #define _CRT_SECURE_NO_WARNINGS #include #include #include #define PAUSE system(\"pause\") #define CLS system(\"cls\"); //#define FLUSH fflush(stdin); //////////////// SRUCTS BELOW ////////////////////////// typedef struct { char itemName[40]; float purchasePrice; float soldPrice; float shippingPrice; float ebayFee; float payPalFee; float profit; }SALES; ////////// FUNCTION PROTOTYPE BELOW ///////////// void addSale(SALES *Inventory, int *InventoryCounter); void displayMenu(int *InventoryCounter); void displayProfit(int *InventoryCounter, SALES *Inventory); void displaySales(int *InventoryCounter, SALES *Inventory); int getChoice(int *InventoryCounter); void searchSale(SALES* Inventory, int InventoryCounter); void sortProfits(SALES* Inventory, int InventoryCounter); void removeSale(SALES* Inventory, int *InventoryCounter); main() { int SIZE; int userChoice; int InventoryCounter = 0; //printf(\"*********************\ \"); //printf(\"* Welcome Reseller! *\ \"); //printf(\"*********************\ \"); printf(\"Enter the size of todays inventory:\"); scanf(\"%i\", &SIZE); SALES *Inventory; Inventory = calloc(SIZE, sizeof(SALES));//Using dynamic memory to allocate space on the heap do { userChoice = getChoice(&InventoryCounter); switch (userChoice) { case 1:// Add a Sale if (InventoryCounter == SIZE) // statement checks so we dont exceed the size of the inventory user wants to enter. { printf(\"You Have Reached Max Inventory \ \"); PAUSE; } else { addSale(&(Inventory[InventoryCounter]), &InventoryCounter); } break; case 2: // Display all sales records displaySales(&InventoryCounter, Inventory); PAUSE; break; case 3: // Display all profits sortProfits(Inventory, InventoryCounter); displayProfit(&InventoryCounter, Inventory); PAUSE; break; case 4: // Display Inventory searchSale(Inventory, InventoryCounter); break; case 5:// remove a sale removeSale(Inventory, &InventoryCounter); break; case 6: // Quit break; default: printf(\"Please choose a valid option\ \"); PAUSE; break; }// end of switch } while (userChoice != 6); free(Inventory); } // End of main //////////////////////////////////////////// FUNCTIONS BELOW ////////////////////////////////////////////////// void addSale(SALES *Inventory, int *InventoryCounter)// Function that adds sale and calculates the fees in the background. { float payPalFee = 0; // variable to store the paypal fee from 1 sale float ebayFee = 0; // variable to store ebay fee for 1 sale.

C programming tweak needed for a specific program.This is the comp.pdf

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Add to BST.java a method height() that computes the height of the tree. Develop two implementations: a recursive method (which takes linear time and space proportional to the height), and method like size() that adds a field to each node in the tree (and takes linear space and constant time per query) Solution Answer: /*BST.java a method height() that computes the height of the tree. Developing two implementations: a recursive method, and method like size() that adds a field to each node in the tree **/ public class SplayBST, Value> { private Node root; // root of the BST // BST helper node data type private class Node { private Key key; // key private Value value; // associated data private Node left, right; // left and right subtrees public Node(Key key, Value value) { this.key = key; this.value = value; } } public boolean contains(Key key) { return get(key) != null; } // return value associated with the given key // if no such value, return null public Value get(Key key) { root = splay(root, key); int cmp = key.compareTo(root.key); if (cmp == 0) return root.value; else return null; } /* * Splay tree insertion. **/ public void put(Key key, Value value) { // splay key to root if (root == null) { root = new Node(key, value); return; } root = splay(root, key); int cmp = key.compareTo(root.key); // Insert new node at root if (cmp < 0) { Node n = new Node(key, value); n.left = root.left; n.right = root; root.left = null; root = n; } // Insert new node at root else if (cmp > 0) { Node n = new Node(key, value); n.right = root.right; n.left = root; root.right = null; root = n; } // It was a duplicate key. Simply replace the value else { root.value = value; } } /* * Splay tree deletion. **/ /* *This splays the key, then does a slightly modified Hibbard deletion on the root (if it is the node to be deleted, if it is not, the key was not in the tree). *The modification is that rather than swapping the root (call it node A) with its successor, it\'s successor (call it Node B) is moved to the root position *by splaying for the deletion key in A\'s right subtree. Finally, A\'s right child is made the new root\'s right child. */ public void remove(Key key) { if (root == null) return; // empty tree root = splay(root, key); int cmp = key.compareTo(root.key); if (cmp == 0) { if (root.left == null) { root = root.right; } else { Node x = root.right; root = root.left; splay(root, key); root.right = x; } } // else: it wasn\'t in the tree to remove } /* * Splay tree function. **/ // splay key in the tree rooted at Node h. If a node with that key exists, // it is splayed to the root of the tree. If it does not, the last node // along the search path for the key is splayed to the root. private Node splay(Node h, Key key) { if (h == null) return null; int cmp1 = key.compareTo(h.key); if (cmp1 < 0) { // key not in tree, so we\'re done if (h.left == null) { return h; } int cmp2 = key.compareTo(h.left.key); if (cmp2 < 0) { h.left.left = splay(h.left.left, key); h = rot.

Add to BST.java a method height() that computes the height of the tr.pdf

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Write an awareness objective for a newly formed adolescent chemical dependency program whose target market consists of judeges and social workers who refer to the facility. How would this objective change for the trial level of the hierarchy of effects? Solution Answer: The objectives are: 1. To create primary level awareness to the people who uses this service frequently and also those who refer our facility, 2. To find out the ways to help people in different situations and making an sustainable ecosystem. This objective (twin objectives) would become altered in case of implementation of them in real situation..

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which of these prokaryotes are most likely to be found in the immedi.pdf

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2. Why is only one end point observed for citric acid even though it .pdf

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10. Benefits and costs of International Trade : Search for a newspaper article from any English newspaper that discusses the advantages or disadvantages of international trade. Copy and paste the weblink into this Forum and discuss one or two main points of the article. Please give detailed answer with examples and elaborations. Solution The web is a awesome invention. Since of its introduction into schooling and its availability to just about any individual, the world will mainly never be the identical. Persons of all a while can go surfing 24/7 looking for something they want. The elderly woman who\'s unable to drive can log onto the web and shop for groceries, fill a prescription or even chat together with her grandchildren via web cam. Collectors now not have got to scour flea markets and yard revenue on weekends to find coveted gadgets so as to add to their collections all they need to do is go browsing to Ebay and publish a bid. Something can be purchased on line now. Garb, jewellery, furniture...Even take-out. As a instructor i\'ve discovered the web to be extremely valuable in planning classes. The web has a plethora of websites created in particular for lecturers to share suggestions, change information, and share records (thanks enotes!). Probably young people stand to gain the most from making use of the web. Additionally to being in a position to express themselves and show creativity on websites like MySpace and Twitter, they can also use the web for school tasks and homework. Still, for every pro, there is a con. I feel that scholars regularly count too much in the internet. They do not look to have an understanding of that simply considering the fact that some thing is on Google, that does not make it a riskless supply. I are not able to depend the number of occasions a scholar has became in an essay that includes unsuitable data from web sites which were created with the aid of any person who is not an authority on the topic. Chat rooms have emerge as the brand new playground for sexual predators. The web gives them the anonymity they have got to entice unsuspecting youngsters into inappropriate conversations and in some circumstances meeting up with them. There are laws that preserve predators far from parks and schools, however none retaining them off the web. With out suitable supervision, kids can accidentally go online to pornographic web pages. Even adults can fall prey to identity theft and stolen passwords if they don\'t seem to be careful about the matters they are downloading onto their laptop. Advantages and drawbacks of web use amongst kids and adults can be considered from quite a lot of angles - objectively, or subjectively. If a individual is in favor of science, then he/she would find extra advantages than negative aspects for its use. However, if a man or woman believes in guide work and that technology could one day be used to replace human work, then the he/she may just view web use to be more damaging than .

10. Benefits and costs of International Trade Search for a newspap.pdf

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Why does the pattern in a shift register shift only one bit position each time it is clocked? please no hand written answers Solution Beacuse if we move all bits at a time there will be no buffers to store the bits temporarily and then shift the data to next position for each bit. Hence , first Least significant bit(LSB) is moved out the the others follow for each step upto the MSB most significant bit is moved by one bit position..

Why does the pattern in a shift register shift only one bit position.pdf

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Use the Internet to identify three network firewalls, and create a table that compares their features. Note if they are rule-based or settings-based, perform stateless or stateful packet filtering, what additional features they include (IDS, content filtering, and so on), their costs, and so on. Solution Below is the table : Firewall Capability Packet Filters Application-layer Gateways Stateful Inspection Communication Information Partial Partial Yes Communication-derived State No Partial Yes Application-derived State No Yes Yes Information Manipulation Partial Yes Yes If you take packet filters, for example, historically they are implemented on routers, are filters on user defined content, such as IP addresses. packet filters examine a packet at the network layer and are application independent, which allows them to deliver good performance and scaleability. However, they are the least secure type of firewall, especially when filtering services such as FTP. As with application gateways, he security is improved by examining all application layers, bringing context information into the decision process. However, they do this by breaking the client/server model. Every client/server communication requires two connections: one from the client to the firewall and one from the firewall to the server. In addition, each proxy requires a different application process, or daemon, making scaleability and support for new applications a problem. The Stateful Inspection introduced by Check Point overcomes the limitations of the previous two approaches by providing full application-layer awareness without breaking the client/server model. With Stateful Inspection, the packet is intercepted at the network layer. It extracts state- related information required for the security decision from all application layers and maintains this information in dynamic state tables for evaluating subsequent connection attempts. This provides a solution which is highly secure and offers maximum performance, scaleability, and extensibility. Firewall Capability Packet Filters Application-layer Gateways Stateful Inspection Communication Information Partial Partial Yes Communication-derived State No Partial Yes Application-derived State No Yes Yes Information Manipulation Partial Yes Yes.

Use the Internet to identify three network firewalls, and create a t.pdf

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To vaccinate or not to vaccinate: Is the influenza Virus vaccine Safe? Who should be vaccinated? Are you planning to get a flu-shot? Are you going to encourage your family members to get a flu-shot? Solution Influenza is the respiratory illness caused by influenza virus.This virus can cause mild to severe illness and finally leads to death. So inorder to avoid such a bad condition,vaccination should be done for our body for every 6 months or atleast once in a year. Influenza is also known as \"flu\" which infects the respiratory tract ie., nose,throat and lungs.The name of influenza vaccine is also called as FLUZONE which saves us from influenza virus. Yes am planning to get a flu shot because i dont want to risk my life by getting viral diseases and i also encourage my family members to have a flu-shot because not only myself, i also want my family members to say away from viral diseases. So i suggest my family members to have a flu-shot for every 6 months or once in a year..

To vaccinate or not to vaccinate Is the influenza Virus vaccine Saf.pdf

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this file has a complete array-based MultiSet, but not the code needed to support its Iterator. Complete the Iterator\'s next() and hasNext() methods. Solution Hi, I have implemented required methods. Please let me know in case of any issue. import java.util.Collection; import java.util.Iterator; import java.util.NoSuchElementException; public class ArrayMultiSet implements Collection { /** Array in which the elements in this multiset are stored. */ private E[] _store; /** * Array indices below this amount contain the active elements in this collection. */ private int _size; /** * Modification counter used to preserve the fail-fast nature of its iterators. */ private long _modCount; /** * Create a new empty multiset. */ public ArrayMultiSet() { _modCount = 0; clear(); } /** * Remove all of the elements within the instance and invalidate any current iterators. */ @SuppressWarnings(\"unchecked\") @Override public void clear() { _store = (E[]) (new Object[16]); _size = 0; // maintains the class invariant } /** * Update the multiset so that it includes all of the elements from before the call AND the given element. * * @param e Item to be added to this collection. */ @SuppressWarnings(\"unchecked\") @Override public boolean add(E e) { // Check if we do not have enough space in the underlying array to store the // new element if (_size == _store.length) { // We do not have space, so create a new larger space (doubling the size // is the most time efficient) E[] newStore = (E[]) new Object[_store.length * 2]; // Copy all of the references into the new array for (int i = 0; i < _store.length; i++ ) { newStore[i] = _store[i]; } _store = newStore; // An easier, more efficient way of coding this (but less useful for // teaching) would instead be: // _store = Arrays.copyOf(_store, _store.length * 2); } // Add the element to the store _store[_size] = e; // Finally, we can increase _size, since this change will no longer violate // any class invariants. _size += 1; return true; } /** * Return true if at least one element in the multiset is equal to the given object. When {@code obj} is null, it must * use the {@code ==} operator to perform these checks, but when {@code obj} is not null, the {@link Object#equals} * method is used. * * @param obj Object (or null) for which we will search * @return {@code true} if {@code obj} was found; {@code false} if a match could not be found. */ @Override public boolean contains(Object obj) { // Only scan through _size, since those are the only \"real\" entries for the // multiset. for (int i = 0; i < _size; i++ ) { // When obj is null, we need to use == if ((obj == null) && (_store[i] == null)) { return true; } // Otherwise, we use .equals() to find a match else if ((obj != null) && obj.equals(_store[i])) { return true; } // No else clause, since the match could be at a higher index! } // Checked all VALID indices, so the result must be: return false; } @Override public int size() { return _size; } /** * Remove the ele.

this file has a complete array-based MultiSet, but not the code need.pdf

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The ____ is the measure of central location that also is the most fr.pdf

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The following exercise from part A to part D should be completed using Unix commands such as (grep, sed, and regular expressions) Part A: How would you list all of the ordinary files in your directory that are not user- executable? Part B: Devise a sequence to display the extensions of all files in the current directory along with a count of each extension. Solution Part B: find recursively prints all filenames sed deletes from every filename the prefix until the file extension uniq assumes sorted input -c does the counting ex: $ find . -type f | sed \'s/.*\\.//\' | sort | uniq -c 16 avi 29 jpg PartA: ls lists files and directories. If the pathname is a file, ls displays information on the file according to the requested options. This command is useful for distinguishing between directories, ordinary files, and executable files. Notice how its output differs from ls without arguments. -a lists all entries including those starting with a period (.). -b Displays non-printable characters as octal bytes with the form \\ooo. -C puts output into columns, sorted vertically; this is the default output format to the terminal. -c Uses the creation time of the file for sorting (-t) or displaying (-l). -d Does not display the contents of named directories, but show information on the directories themselves. -F Puts a / after each directory name, a * after every executable file, a | after every FIFO file, a @ after every symbolic link and a = after every socket..

The following exercise from part A to part D should be completed usi.pdf

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1.Contrast financial and managerial accounting on the basis of use.pdf

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Subject :- Project Management How does the WBS differ from the project network? Why is \"slack\" important to the project manager? Solution WBS refers to a deliverable oriented hierarchical decomposition of the work to be executed by the project team to accomplish the project objectives and create the required deliverabless A project network is a graphical flow chart and has early and late starts, the project job plan that is developed from the WBS .It is used to identify the critical path and understand how best to sequnce the activities. Slack is important when managing a project because it\'s is very rare that things don\'t change while working on a project. Budgets change, schedules change, available resources change and so do task priorities. Without slack time it\'ll be very challenging to be able to manage the project in a flexible way without causing tasks to be stuck or not have time to handle urgent things that were introduced.

Subject - Project ManagementHow does the WBS differ from the proj.pdf

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Question 14: 14A) What are homologous chromosome and when do they depart? 14B) What is crossing over and when does it take place? Solution 14A) Homologous= same loci. these chromosomes have the same set of genes at the same loci and they depart during anaphase, being pulled apart by centromeres. 14B) when homologous chromosomes pair up during meiosis, the sister chromatids gets exchanged at their respective loci to provide a new mix of the trait. this exchange of genes or segments of chromatids among homologous chromosomes is known as crossing over and it takes place during metaphase of meiosis I..

Question 1414A) What are homologous chromosome and when do they d.pdf

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Ronnon, Inc. is a producer of infrastructure equipment for Internet Service Providers. Ronnon\'s sales forecast for 2010 and 2011 is $40 million and S46 million, respectively. Stockholders\' equity as of January 1, 2010 was $32 million. The company\'s net profit margin after tax is 10% and it expects to pay annual dividends of 40% of net income. Current asset requirements are planned at 30% of sales and current liabilities are planned at 10% of sales. Net fixed assets are projected to be 1 10% of sales and long-term liabilities are expected to be 30% of total assets 41. Total asset requirements for 2011 will be: A. $34.4 million B. $37.2 million C. $56.0 million D. $64.4 million 42. Total liabilities and stockholders\' equity before outside financing for 2010 will be: A. $56.0 million B. $64.4 million C. $55.2 million D. $61.1 million Solution 41)current asset = 46*.30=13.8 Net fixed asset = 46*110%= 50.60 Total asset requirement = 13.8+50.6= 64.4 correct option is \"D\" 42)Total asset for 2010 = [40*30%] +[40*110%] 12+ 44 56 Liabilities = [40*10%]+[56*30%] 4 +16.8 20.8 Net income =40*10% = 4 Net income after dividend = 4[1- .40]= 2.4 equity before financing = 32+2.4= 34.4 liabilities and equity before financing = 20.8+34.4= 55.2 correct option is \"C\".

Ronnon, Inc. is a producer of infrastructure equipment for Internet S.pdf

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