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VEER SURENDRA SAI UNIVERSITY OF TECHNOLOGY
BURLA, ODISHA
DEPARTMENT OF MECHANICAL ENGINEERING
ENGINEERING THERMODYNAMICS
Lecture Notes
Disclaimer
This document does not claim any originality and cannot be used as a substitute for prescribed
textbooks. The information presented here is merely a collection by the committee members for
their respective teaching assignments. Various sources as mentioned at the reference of the
document as well as freely available material from internet were consulted for preparing this
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Further, this document is not intended to be used for commercial purpose and the committee
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accuracy or completeness of the contents of this document and specifically disclaim any implied
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be liable for any loss of profit or any other commercial damages, including but not limited to
special, incidental, consequential, or other damages.
ENGINEERING THERMODYNAMICS
What is Thermodynamics?
 Thermodynamics is a science dealing with Energy and its transformation and its effect on the
physical properties of substances.
 It deals with equilibrium and feasibility of a process.
 Deals with the relationship between heat and work and the properties of systems in
equilibrium.
Scope of Thermodynamics:
 Steam power plant
 Separation and Liquification Plant
 Refrigeration
 Air-conditioning and Heating Devices.
 Internal combustion engine
 Chemical power plants
 Turbines
 Compressors, etc
The principles of thermodynamics are summarized in the form of four thermodynamic laws:
The Zeroth Law deals with thermal equilibrium and provides a means for measuring
temperatures.
The First Law deals with the conservation of energy and introduces the concept of
internal energy.
The Second Law of thermodynamics provides with the guidelines on the conversion of
internal energy of matter into work. It also introduces the concept of entropy.
The Third Law of thermodynamics defines the absolute zero of entropy. The entropy of
a pure crystalline substance at absolute zero temperature is zero.
Different Approaches of Thermodynamics :
Write the difference between Macroscopic and Microscopic approach of Thermodynamics:
Macroscopic Approach Microscopic Approach
1.Macroscopic approach is known as Classical
Thermodynamics.
1. Microscopic approach is known as
Statistical Thermodynamics
2. Attention is focussed on a certain quantity of
matter without taking into account the events
occuring at molecular level.
2. A knowledge of the structure of matter
under consideration is essential.
3. Only a few variables are used to describe the
state of the matter under consideration.
3. A large no. of variables are required for a
complete specification of the state of matter
under consideration.
4. The values of the variables used to describe
the state of the matter are easily measurable.
4. The variables used to describe the state of
matter cannot be measured easily and precisely
Define Thermodynamic System?
A thermodynamic system is defined as a definite quantity of matter or a region of space within a
prescribed boundary upon which attention is focussed in the analysis of a problem.
Surrounding: Everything external to the system is Surroundings.
Boundary:
 The surface which separates the system from the surrounding.
 System and surrounding interact through boundary in the form of Heat and Work.
 Boundary can be real (or) imaginary.
 Boundary can be fixed (or) moving.
System and Surrounding put together is known as Universe
Interaction Between System and Surrounding
Based on the type of interaction, the systems are classified as
• CLOSED SYSTEM
• OPEN SYSTEM
• ISOLATED SYSTEM
CLOSED SYSTEM (Control Mass) : It is also termed as control mass or fixed mass analysis.
There is no mass transfer across the system boundary but energy in the form of Heat or Work
can cross the system boundary.
Eg. A certain amount of gas enclosed in a cylinder piston arrangement.
Open System(Control Volume): The open system is one in which both mass and energy can
cross the boundary of the system.
Open system is also termed as control volume analysis.
Write down the concept of Control Volume:
A large engineering problems involve mass flow in and out of a system and therefore, are
modeled as control volumes.
Control volume refers to a definite volume on which attention is focussed for energy analysis.
Examples: Nozzles, Diffusers, Turbines, Compressors,
Heat Exchanger, De-superheater, Throttling valves,
I.C engine etc.
Control Surface: The closed surface that surrounds the control volume is called CONTROL
SURFACE. Mass as well as energy crosses the control surface. Control surface can be real or
imaginary.
Isolated System: The isolated system is one in which there is no interaction between the system
and the surroundings that neither the mass nor the energy interactions. Therefore it is of fixed
mass and energy.
Note:
Mass Transfer
Energy
Transfer
Type of System
No Yes Closed System
Yes Yes Open System
No No Isolated System
Yes No Impossible
What do you mean by Property?
Any observable characteristics required to describe the conditions or state of a system is known
as Thermodynamic property of a system.
Properties
Differentiate Intensive and Extensive Property?
Extensive Property Intensive Property
1. Extensive properties are dependent on the mass
of a system.
1. Intensive properties are independent of
the mass of a system.
2.Extensive properties are additive. 2. Intensive properties are not additive.
Intensive
(Independent of mass)
Extensive
(Depends on mass)
3. Its value for an overall system is the sum of its
values for the parts into which the system is
divided.
3. Its value remains the same whether one
considers the whole system or only a part
of it.
4.Example:mass(m),volume(V),Energy(E),Enthalp
y(H) etc.
4.Example:Pressure(P),Temperature(T),De
nsity etc.
5. Uppercase letters are used for extensive
properties except mass.
5. Lowercase letters are used for intensive
properties except pressure(P) and temp.(T)
Specific property= Extensive property/mass.
Example: Specific volume (v) = Volume(V)/mass(m)
Specific enthalpy (h) = Enthalpy(H)/mass(m)
Specific entropy (s) = Entropy(S)/mass(m)
State:
 It is the condition of a system as defined by the values of all it’s properties.
 It gives a complete description of the system.
 Any operation in which one or more properties of a system change is called change of
state .
Path and Process:
 The series of state through a system passes during a change of state is Path of the system.
 If the path followed by the system during change of state is specified or defined
completely, then it is called a process.
We can allow one of the properties to remain a constant during a process.
Isothermal Constant Temperature (T)
Isobaric Constant Pressure (P)
Isochoric Constant Volume (V)
Isentropic Constant Entropy (s)
Isenthalpic Constant Enthalpy (h)
Cycle: When a system in a given initial state undergoes a series of processes and returns to
initial state at the end of process, then the system is said to have undergone a thermodynamic
cycle.
DIFFERENTIATE BETWEEN POINT FUNCTION VS PATH FUNCTION
Point Function Path Function
1. Any quantity whose change is independent of
the path is known as point function.
1. Any quantity, the value of which depends
on the path followed during a change of state
is known as path function.
2. The magnitude of such quantity in a process
depends on the state.
2. The magnitude of such quantity in a process
is equal to the area under the curve on a
property diagram.
3. These are exact differential. 3.These are inexact differential. Inexact
differential is denoted by δ
4. Properties are the examples of point function
like pressure(P), volume(V),Temp.(T),Energy
etc.
4. Ex: Heat and work
Thermodynamic Equilibrium
A system is said to exist in a state of Thermodynamic Equilibrium when no changes in
macroscopic property is observed if the system is isolated from its surrounding.
At the state of equilibrium, the properties of the system are uniform and only one value can be
assigned to it.
A system will be in a state of thermodynamic equilibrium, if the condition for following three
types of equilibrium are satisfied.
Thermal Equilibrium (Equality of Temperature):
A state of thermal equilibrium can be described as one in which the temperature of the system is
uniform.
Mechanical Equilibrium(Equality of Pressure):
In the absence of any unbalanced force within the system itself and also between the system and
the surroundings, the system is said to be in a state of mechanical equilibrium.
 Mechanical equilibrium is related to pressure.
 A system is in mechanical equilibrium if there is no change in pressure at any point of
the system .
Chemical Equilibrium(Equality of chemical potential):
 A system is in chemical equilibrium when its chemical composition does not change with
time, that is no chemical reaction occurs .
 It is related to chemical potential.
QUASI-STATIC PROCESS
A quasi-static process is one in which the deviation from thermodynamic equilibrium is
infinitesimal.
Characteristics:
 Infinite slowness is the characteristic feature of this process.
 A quasi-static process is thus a succession of equilibrium states.
 It can be represented as a continuous line on the property diagram.
 It is also known as a reversible process.
REVERSIBLE PROCESS
Reversible process is one which is performed in such a way that at the end of the process both
the system and surrounding may be restored to their initial state without producing any changes
in rest of the Universe.
Reasons for studying Reversible Process:
1.They are easy to analyze.
2. They served as an idealized process to which actual process can be compared.
3.They are taken for consideration because work producing devices such as steam turbine,
automobile engines etc delivers the max. work and work consuming devices like compressors,
pumps etc consumes the least work.
Characteristics of Reversible Process
 A Reversible process is carried out infinitely slowly with an infinitesimal gradient so that
every state pass through by the system is in equilibrium.
 It is possible to execute the process in either of the direction.
 No dissipative effect such as friction, loss in a resistor, etc are present.
 Heat and work interactions of the system and the surroundings in the reverse process are equal
and opposite in direction to the same in the forward process.
Examples:
1. Frictionless isothermal expansion or compression of a fluid.
2. Frictionless adiabatic expansion or compression of a fluid.
3. Elastic stretching of a solid.
4. Electric current with zero resistance.
IRREVERSIBLE PROCESS
An irreversible process is one that is carried out in such a way that the system and surrounding
can not be exactly restored to their respective initial state at the end of the reverse process, that a
net change occurs in the Universe.
Note: In an irreversible the surrounding would always be affected by loss of work and gain of
low temperature heat, which can be considered as waste heat for the surrounding.
Causes of an Irreversibility:
The irreversibility of a process may be due to either one or both of the following.
(i) Lack of Equilibrium.
(ii) Involvement of Dissipative effects.
Lack of Equilibrium(Mechanical,Thermal,Chemical)
The lack of equilibrium between the system and the surroundings or between the two systems
causes a spontaneous change which makes the process irreversible.
Examples:
1. Heat transfer through a finite temperature difference.
2. Compression or Expansion through a finite pressure difference between the system and
the surroundings.
3. Free expansion or Unrestrained expansion.
4. Mixing of substances.
Dissipative Effects:
Dissipation results in the transformation of work into molecular energy of the system.
Examples:
1. Friction.
2. Flow of electricity through a resistor.
3. Paddle wheel work transfer. etc
Characteristics of an Irreversible Process:
1. It can be carried out in one direction only.
2. It occurs at a finite rate.
3. During an irreversible process, the system is not in equilibrium.
An irreversible process cannot be reversed without causing permanent changes in the
surroundings.
Heat & Work Transfer
Thermodynamic Work: Work is said to be done by a system if the sole effect on things
external to the system can be reduced to the raising of a weight.
Displacement (or) pdV Work:
Expression for pdV Work:
2
12
1
( *piston area* )
* *
=
W dW
p displacement
p A dL
pdV
W pdV
Sign Convention for work transfer:
Work done by the system is positive and Work done on the system is negative.
Work done during various Quasi-static Processes:
Constant Pressure Proces:
2
1
1 2 2 1( )
V
V
W pdV p V V
Constant Volume Process:
2
1
1 2 0
V
V
W pdV
Constant Temperature Process:
2
1
1 2
V
V
W pdV
Polytropic Process n
pV C , where n is a constant
2
1
1 1
1 1
2
1 2 1 1 1 1
1
ln
V
V
pV pV C
pV
p
V
VdV
W pV pV
V V
2
1
2
1
1 1 2 2
1 1
1 2
1 1
1 1 2 2
( )
=
1
n n n
n
n
V
V
V n
n
V
pV pV p V C
pV
p
V
W pdV
pV
dV
V
pV p V
n
Heat Transfer: Energy transfer by virtue of temperature difference is called Heat Transfer. Heat
Transfer is also a boundary phenomenon.
Specific Heat: It is the amount of heat required to raise the temperature of unit mass of a
substance by unit degree.
For Solids and Liquids
cp = cv = c
For Gases
cp – specific heat capacity at constant pressure
cv – specific heat capacity at constant volume
Latent Heat: It is the amount of heat transferred to cause a phase change.
FIRST LAW OF THERMODYNAMICS
 This is based on Law of Conservation of Energy.
 This is also called as First Principle.
For a closed system, undergoing a cycle
Sum of all Work transfers = Sum of all Heat Transfers
(W1+W2+W3+…..) = Σ(Q1 +Q2+Q3+……….)
Σ(W) = Σ(Q)
For a closed system,undergoing a Process
Whenever heat is absorbed by a system it increases its internal energy and does some work.
Q = ΔE + W
Where Q – heat absorbed by the system
W – Work output from the system
ΔE – Change in Stored Energy of the system
Show that Energy is a property of the system
For path A,
A A AQ W E (1)
dW dQ
For path B,
B B BQ W E (2)
For path B,
C C CQ W E (3)
For Cycle 1-A-2-B-1,
A B A BW W Q Q (4)
( )A A B BQ W Q W
A BE E (A)
For Cycle 1-A-2-C-1,
A C A CW W Q Q
( )A A C CQ W Q W
A CE E (C)
Comparing A and C
B CE E
Enthalpy:
 It is the energy content of the flowing fluid.
 It is defined by the summation of internal energy and flow work.
H = U + PV
Note: For an ideal gas h = u + Pv.
= u + RT
So, h = f(T)
Define Cv with the help internal energy and Temperature:
The amount of heat required to raise the temperature of unit mass of a substance by 1o
C in a
reversible constant volume process.
v
v
u
C
T
vC is also defined as the change of internal energy of the substance per unit change in
temperature at constant volume.
Define Cp with the help enthalpy and Temperature:
The amount of heat required to raise the temperature of unit mass of a substance by 1o
C in a
reversible constant pressure process.
p
p
h
C
T
pC is also defined as the change of internal energy of the substance per unit change in
temperature at constant pressure.
Application of First law to different Thermodynamic process:
Process Index=n Q W= PdV P-V-T Relation
Rev. Const.Vol. Q U
= 2 1( )vmC T T
W=0 1 2
1 2
P P
T T
Rev.Const.pressure n=0 Q H
= 2 1( )pmC T T
2 1( )W P V V
= 2 1( )mR T T
1 2
1 2
V V
T T
Rev. Isothermal n=1
2
1 1
1
ln
V
Q W PV
V
2
1 1
1
ln
V
W PV
V
1 1 2 2PV PV
Rev.Adiabatic n=γ Q=0 1 1 2 2
1
PV PV
W 1 1 2 2PV PV
Rev.Polytropic n Q U W 1 1 2 2
1
PV PV
W
n
1 1 2 2
n n
PV PV
MODULE-2
SECOND LAW OF THERMODYNAMICS
State the limitations of first law of thermodynamics?
1. First Law places no restriction on the direction of a process.
2. It does not ensure whether the process is feasible or not.
3. This law does not differentiate heat and work. It is concerned with the quantity of energy and
the transformation of energy from one form to another with no regard to its quality.
Aspects of the second law
1. To identify the direction of process.
2. Establishing conditions for equilibrium.
3. It also asserts that energy has quality as well as quantity.
3. It is also used in determining the theoretical limits for the performance of heat engines and
refrigerators.
4. Defining a temperature scale independent of the properties of any thermometric substance.
Thermal Energy Reservoir (TER): It is a hypothetical body with a relatively large thermal
energy capacity that can supply or absorb finite amount of heat without undergoing any change
in temperature. Examples: Oceans, rivers, atmospheric air etc.
 TER that supplies energy in the form of heat is called a source
 TER that absorbs energy in the form of heat is called a sink
Heat Engines: Heat engine is a cyclic device, used to convert heat to work. Heat engine can be
characterized by the following points.
1. They receive heat from a high temperature source (solar energy, oil-furnace etc.)
2. They convert part of this heat to work (usually in the form of a rotating shaft)
3. They reject the remaining waste heat to a low temperature sink (the atmosphere, rivers, etc)
4.They opertate on a cycle.
Q1 = amount of heat supplied to steam in boiler from a high-temperature source.
Q2 = amount of heat rejected from steam in condenser to a low temperature sink.
W = net work output of this heat engine.
Thermal efficiency: The fraction of the heat input that is converted to net work output is a
measure of the performance of the heat engine.
Net work output
( )
Total heat input
Thermal efficiency
th
1
W
Q
2
th
1
Q
1
Q
Refrigerator: Refrigerators are cyclic devices, used to transfer heat from a low temperature
medium to a high temperature medium.
The working fluid used in the refrigeration cycle is called a refrigerant. The most frequently used
refrigeration cycle is the vapor-compression refrigeration cycle.
Coefficient of Performance (COP)
2
R
QDesired output
COP
Required input W
2
R
1 2
Q
COP
Q Q
Heat Pumps: Heat pumps are another cyclic devices, used to transfer heat from a low
temperature medium to a high temperature medium.
The objective of a heat pump is to maintain a heated space at a high temperature. This is
accomplished by absorbing heat from a low temperature source, such as cold outside air in
winter and supplying this heat to the high temperature medium such as a house.
1
HP
QDesired output
COP
Required input W
1
HP
1 2
Q
COP
Q Q
Relation between HPCOP and RCOP
HPCOP = RCOP +1
(Refrigerator)
Statements of Second Law
Kelvin-Planck Statement of the Second law
It is impossible for any device that operates on a cycle to receive heat from a single reservoir and
produce a net amount of work.
(A heat engine that violates the Kelvin-Planck statement)
Clausius Statement:
It is impossible to construct a device that operates in a cycle and produce no effect other than the
transfer of heat from a low temperature body to a high temperature body.
Equivalence of Kelvin Planck and Clausius Statements:
The equivalence of the statement is demonstrated by showing that the violation of each
statement implies the violation of other.
CASE-1: Violation of Kelvin-planck statement leads to violation of Clausius statement
A refrigerator that violates the Clausius
statementof the second law
Violation of Kelvin-Planck
statement
CASE-2: Violation of Clausius statement leads to violation of Kelvin-planck statement
Thus violation Kelvin Planck Statement has lead to the violation of
Clausius Statement
Thus Violation of Clausius Statement has lead to violation of Kelvin Planck Statements
Carnot Cycle: Carnot cycle is a reversible cycle that is composed of four reversible processes,
two isothermal and two adiabatic.
 Process 1 - 2 (Reversible Isothermal Heat Addition)
 Process 2 – 3 (Reversible Adiabatic Expansion)
 Process 3 – 4 (Reversible Isothermal Heat Rejection)
 Process 4 – 1 ( Revesible Adiabatic Compression)
Σ(Q net)cycle = Σ( Wnet)cycle
Qadd – Qrej = We – Wc
net add rej
add add
2
1
2
1
W Q - Q
Q Q
= 1 -
From T-S diagram
T ( S)
= 1
T ( S)
T
= 1
T
rej
add
Q
Q
Carnot’s Theorem:
1. The efficiency of an irreversible heat engine is always less than efficiency of a reversible one
operating between the same two reservoirs.
2. The efficiencies of all reversible heat engines operating between the same reservoirs are the
same.
Clausius Inequality
The cyclc integral of
Q
T
is always less than or equal to zero.
Mathematically it can be expressed as 0
Q
T
. The equality in the Clausius inequality holds
for totally or just reversible cycle and the inequality for the irreversible ones.
Reversible Engine
1 1
2 2
1 2
1 2
1 2
1 2
( )
0
0
Q T
Q T
or
Q Q
T T
Q Q
T T
dQ
T
For an Irreversible Engine
1 2I 1 2RQ Q Q Q
and therefore
2I 2RQ Q
Consequently, for an irreversible heat engine
1 2I 0Q Q Q
1 2I
1 2
0
Q QQ
T T T
So we conclude that for all irreversible heat engine
0
Q
T
Entropy:
Entropy is defined as
rev
Q
dS
T
The T ds Relations:
But
and
Thus, The first TdS equation is obtained as
The second TdS equation is obtained by using the definition of enthalpy .
( )
rev rev
rev
rev
Q dU W
Q TdS
W PdV
TdS dU PdV
h u pv
dH dU d PV dU PdV VdP
TdS dH (Since )
The equations can be written on a unit mass basis as
VdP TdS dU PdV
TdS
Tds du Pdv
Tds dh vdP
Entropy change of an ideal gas
The entropy change between two states of an ideal gas canbe obtained from the ideal gas
equation and the combined equation of the first first and second laws.
Entropy change for different process:
Process Entropy change 2 1s s
Reversible constant volume process
Reversible constant pressure process
2 2 2
1 1 1
2 2
2 1
1 1
Tds = du + Pdv
But,
du = c and P = (RT)/v
Therefore,
RT
Tds = c
c
s c ln ln
v
v
v
v
dT
dT dv
v
or
dT dv
ds R
T v
T v
s R
T v
2 2 2
1 1 1
2 2
2 1
1 1
, Tds =
Now,
dh = c and v = (RT)/P
ds = c
c
s c ln ln
p
p
P
p
Again dh vdP
dT
dT RT
dP
T PT
dT dP
ds R
T P
T P
s R
T P
2
2 1
1
s c lnv
T
s
T
2
2 1
1
s c lnv
T
s
T
2
2 1
1
s c lnp
T
s
T
Reversible isothermal process
Reversible adiabatic process 2 1s s
Polytropic process
Basic components of IC engine
2 2
2 1 2 1
1 1
ln ln
P v
s s R or s s R
P v
2 2 2
1 1 1
2 2 2
1 1 1
c
c
v
p
dT dv
ds R
T v
dT dP
or ds R
T P
Internal Combustion engine
Spark ignition engine Compression ignition engine
These engines are petrol engine and
they work on Otto cycle
These engines are diesel engine and
they work on Diesel cycle
Engine Terminology:
1.Top Dead Center (TDC): Position of the piston when it stops at the furthest point away from
the crankshaft.
– Top because this position is at the top of the engines (not always), and dead because the piston
stops as this point.
– When the piston is at TDC, the volume in the cylinder is a minimum called the clearance
volume.
2. Bottom Dead Center (BDC): Position of the piston when it stops at the point closest to the
crankshaft. Volume of the cylinder is maximum.
3. Stroke : Distance traveled by the piston from one extreme position to the other : TDC to BDC
or BDC to TDC.
4. Bore :It is defined as cylinder diameter or piston face diameter; piston face diameter is same
as cylinder diameter( minus small clearance).
5. Swept volume/Displacement volume : Volume displaced by the piston as it travels through
one stroke.
– Swept volume is defined as stroke times bore.
– Displacement can be given for one cylinder or entire engine (one cylinder times number of
cylinders).
Clearance volume : It is the minimum volume of the cylinder available for the charge (air or air
fuel mixture) when the piston reaches at its outermost point (top dead center or outer dead
center) during compression stroke of the cycle.
– Minimum volume of combustion chamber with piston at TDC.
Compression ratio : The ratio of total volume to clearance volume of the cylinder is the
compression ratio of the engine.
– Typically compression ratio for SI engines varies form 8 to 12 and for CI engines it varies
from 12 to 24
Otto cycle:
The processes in Otto cycle are
 (1 – 2) Isentropic Compression
 (2 – 3) Constant volume heat addition.
 (3 – 4) Isentropic Expansion.
 (4 – 1) Constant volume heat rejection.
Efficiency of Otto Cycle
Diesel cycle
The processes in Diesel cycle are:
 (1 – 2) Isentropic Compression
 (2 – 3) Constant pressure heat addition.
 (3 – 4) Isentropic Expansion.
3 4 2 1
3 4 3 4 3 1
1
2 1 2 1 1
1
3 11
1
1
C ( ) C T 1
C (T ) C T (1 r )
1
= C 1 r
1
1
W
Work ratio =
net
Otto
v v
k
v v k
net p k
k
otto
k
net
turb
W
Heat Supplied
Wnet W W
W T T
r
W T
W T T
r
r
W
( 1)1
3
1 k
ine
T
r
T
 (4 – 1) Constant volume heat rejection.
Efficiency of Diesel cycle
3 2 4 1
3 2 4 1
th
3 2
4
1
14 1
3 2 3
2
2
1
2
Now
=1
Now
( ) and ( )
( ) ( )
Hence η
( )
1
( )
1
(( ))
1
net
Diesel
in out
in
in p out v
p v
p
W
Heat Supplied
q
q q
q
c T T q c T T
c T T c T T
c T T
T
T
TT T
T T T
T
T
T v
T
11
2
1
3 3
3 2
2 2
4 4
4 1
1 1
31 4
2 2 1
Substituting the values of
1
Also since = , hence = ρ
where ρ is the cut-off ratio.
Again since , ρ
, , and , the value of thermal efficiency
cv r
T v
p p
T v
T p
v v
T p
TT T
T T T
1
th
1 ρ 1
η 1
ρ 1cr
Dual cycle:
Processes in Dual cycle:
1. (1-2) Isentropic compression
2. (2-3) Constant volume heat addition
3. (3-4) Constant pressure heat addition
4. (4-1) Isentropic expansion
5. (5-1) Constant volume heat rejection.
Efficiency of Dual cycle
3 2 4 3 5 1
3 2 4 3
5 1
3 2 4 3
1
,
ρ 1
1-
( (ρ 1)
η
c ( ) ( ) ( )
=
( ) ( )
( )
η 1
( ) ( )
1
1)
Dual
in out
dual
in
v p v
v p
dual
p
c p p
Efficiency
r
r r
q q
q
T T c T T c T T
c T T c T T
T T
T T T T
r
Comparision between SI engine and CI engine
SI engine CI engine
Working cycle is Otto cycle. Working cycle is diesel cycle.
Petrol or gasoline or high
octane fuel is used.
Diesel or high cetane fuel is
used.
High self-ignition temperature. Low self-ignition temperature.
Fuel and air introduced as a
gaseous mixture in the suction
stroke.
Fuel is injected directly into the
combustion chamber at high
pressure at the end of
compression stroke.
Carburettor used to provide the
mixture. Throttle controls the
quantity of mixture introduced.
Injector and high pressure pump
used to supply of fuel. Quantity
of fuel regulated in pump.
Use of spark plug for ignition
system
Self-ignition by the compression
of air which increased the
temperature required for
combustion
Compression ratio is 6 to 10.5 Compression ratio is 14 to 22
Higher maximum RPM due to
lower weight
Lower maximum RPM
Maximum efficiency lower due
to lower compression ratio
Higher maximum efficiency due
to higher compression ratio
Lighter Heavier due to higher pressures
Valve timing diagram
The exact moment at which the inlet and outlet valve opens and closes with reference to the
position of the piston and crank shown diagrammatically is known as valve timing diagram. It is
expressed in terms of degree crank angle. The theoretical valve timing diagram is shown in Fig.
But actual valve timing diagram is different from theoretical due to two factors-mechanical and
dynamic factors. Figure 4 shows the actual valve timing diagram for four stroke low speed or
high speed engine.
Opening and closing of inlet valve
 Inlet valve opens 12 to 30ᵒ CA before TDCto facilitate silent operation of the engine under
high speed. It increases the volumetric efficiency.
 Inlet valve closes 10-60ᵒ CA after TDC due to inertia movement of fresh charge into
cylinder i.e. ram effect.
Figure represents the actual valve timing diagram for low and high speed engine.
Opening and closing of exhaust valve
Exhaust valve opens 25 to 55ᵒ CA before BDC to reduce the work required to expel out the
burnt gases from the cylinder. At the end of expansion stroke, the pressure inside the chamber is
high, hence work to expel out the gases increases.
Exhaust valve closes 10 to 30ᵒ CA after TDC to avoid the compression of burnt gases in next
cycle. Kinetic energy of the burnt gas can assist maximum exhausting of the gas. It also increases
the volumetric efficiency.
Valve overlap
During this time both the intake and exhaust valves are open. The intake valve is opened before
the exhaust gases have completely left the cylinder, and their considerable velocity assists in
drawing in the fresh charge. Engine designers aim to close the exhaust valve just as the fresh
charge from the intake valve reaches it, to prevent either loss of fresh charge or unscavenged
exhaust gas.

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Engineering Thermodynamics Lecture Notes

  • 1. VEER SURENDRA SAI UNIVERSITY OF TECHNOLOGY BURLA, ODISHA DEPARTMENT OF MECHANICAL ENGINEERING ENGINEERING THERMODYNAMICS Lecture Notes
  • 2. Disclaimer This document does not claim any originality and cannot be used as a substitute for prescribed textbooks. The information presented here is merely a collection by the committee members for their respective teaching assignments. Various sources as mentioned at the reference of the document as well as freely available material from internet were consulted for preparing this document. The ownership of the information lies with the respective authors or institutions. Further, this document is not intended to be used for commercial purpose and the committee members are not accountable for any issues, legal or otherwise, arising out of use of this document. The committee members make no representations or warranties with respect to the accuracy or completeness of the contents of this document and specifically disclaim any implied warranties of merchantability or fitness for a particular purpose. The committee members shall be liable for any loss of profit or any other commercial damages, including but not limited to special, incidental, consequential, or other damages.
  • 3. ENGINEERING THERMODYNAMICS What is Thermodynamics?  Thermodynamics is a science dealing with Energy and its transformation and its effect on the physical properties of substances.  It deals with equilibrium and feasibility of a process.  Deals with the relationship between heat and work and the properties of systems in equilibrium. Scope of Thermodynamics:  Steam power plant  Separation and Liquification Plant  Refrigeration  Air-conditioning and Heating Devices.  Internal combustion engine  Chemical power plants  Turbines  Compressors, etc The principles of thermodynamics are summarized in the form of four thermodynamic laws:
  • 4. The Zeroth Law deals with thermal equilibrium and provides a means for measuring temperatures. The First Law deals with the conservation of energy and introduces the concept of internal energy. The Second Law of thermodynamics provides with the guidelines on the conversion of internal energy of matter into work. It also introduces the concept of entropy. The Third Law of thermodynamics defines the absolute zero of entropy. The entropy of a pure crystalline substance at absolute zero temperature is zero. Different Approaches of Thermodynamics : Write the difference between Macroscopic and Microscopic approach of Thermodynamics: Macroscopic Approach Microscopic Approach 1.Macroscopic approach is known as Classical Thermodynamics. 1. Microscopic approach is known as Statistical Thermodynamics 2. Attention is focussed on a certain quantity of matter without taking into account the events occuring at molecular level. 2. A knowledge of the structure of matter under consideration is essential.
  • 5. 3. Only a few variables are used to describe the state of the matter under consideration. 3. A large no. of variables are required for a complete specification of the state of matter under consideration. 4. The values of the variables used to describe the state of the matter are easily measurable. 4. The variables used to describe the state of matter cannot be measured easily and precisely Define Thermodynamic System? A thermodynamic system is defined as a definite quantity of matter or a region of space within a prescribed boundary upon which attention is focussed in the analysis of a problem. Surrounding: Everything external to the system is Surroundings. Boundary:  The surface which separates the system from the surrounding.  System and surrounding interact through boundary in the form of Heat and Work.  Boundary can be real (or) imaginary.  Boundary can be fixed (or) moving. System and Surrounding put together is known as Universe Interaction Between System and Surrounding
  • 6. Based on the type of interaction, the systems are classified as • CLOSED SYSTEM • OPEN SYSTEM • ISOLATED SYSTEM CLOSED SYSTEM (Control Mass) : It is also termed as control mass or fixed mass analysis. There is no mass transfer across the system boundary but energy in the form of Heat or Work can cross the system boundary. Eg. A certain amount of gas enclosed in a cylinder piston arrangement. Open System(Control Volume): The open system is one in which both mass and energy can cross the boundary of the system. Open system is also termed as control volume analysis.
  • 7. Write down the concept of Control Volume: A large engineering problems involve mass flow in and out of a system and therefore, are modeled as control volumes. Control volume refers to a definite volume on which attention is focussed for energy analysis. Examples: Nozzles, Diffusers, Turbines, Compressors, Heat Exchanger, De-superheater, Throttling valves, I.C engine etc. Control Surface: The closed surface that surrounds the control volume is called CONTROL SURFACE. Mass as well as energy crosses the control surface. Control surface can be real or imaginary. Isolated System: The isolated system is one in which there is no interaction between the system and the surroundings that neither the mass nor the energy interactions. Therefore it is of fixed mass and energy.
  • 8. Note: Mass Transfer Energy Transfer Type of System No Yes Closed System Yes Yes Open System No No Isolated System Yes No Impossible What do you mean by Property? Any observable characteristics required to describe the conditions or state of a system is known as Thermodynamic property of a system. Properties Differentiate Intensive and Extensive Property? Extensive Property Intensive Property 1. Extensive properties are dependent on the mass of a system. 1. Intensive properties are independent of the mass of a system. 2.Extensive properties are additive. 2. Intensive properties are not additive. Intensive (Independent of mass) Extensive (Depends on mass)
  • 9. 3. Its value for an overall system is the sum of its values for the parts into which the system is divided. 3. Its value remains the same whether one considers the whole system or only a part of it. 4.Example:mass(m),volume(V),Energy(E),Enthalp y(H) etc. 4.Example:Pressure(P),Temperature(T),De nsity etc. 5. Uppercase letters are used for extensive properties except mass. 5. Lowercase letters are used for intensive properties except pressure(P) and temp.(T) Specific property= Extensive property/mass. Example: Specific volume (v) = Volume(V)/mass(m) Specific enthalpy (h) = Enthalpy(H)/mass(m) Specific entropy (s) = Entropy(S)/mass(m) State:  It is the condition of a system as defined by the values of all it’s properties.  It gives a complete description of the system.  Any operation in which one or more properties of a system change is called change of state . Path and Process:  The series of state through a system passes during a change of state is Path of the system.  If the path followed by the system during change of state is specified or defined completely, then it is called a process. We can allow one of the properties to remain a constant during a process. Isothermal Constant Temperature (T) Isobaric Constant Pressure (P) Isochoric Constant Volume (V) Isentropic Constant Entropy (s) Isenthalpic Constant Enthalpy (h)
  • 10. Cycle: When a system in a given initial state undergoes a series of processes and returns to initial state at the end of process, then the system is said to have undergone a thermodynamic cycle. DIFFERENTIATE BETWEEN POINT FUNCTION VS PATH FUNCTION Point Function Path Function 1. Any quantity whose change is independent of the path is known as point function. 1. Any quantity, the value of which depends on the path followed during a change of state is known as path function. 2. The magnitude of such quantity in a process depends on the state. 2. The magnitude of such quantity in a process is equal to the area under the curve on a property diagram. 3. These are exact differential. 3.These are inexact differential. Inexact differential is denoted by δ 4. Properties are the examples of point function like pressure(P), volume(V),Temp.(T),Energy etc. 4. Ex: Heat and work
  • 11. Thermodynamic Equilibrium A system is said to exist in a state of Thermodynamic Equilibrium when no changes in macroscopic property is observed if the system is isolated from its surrounding. At the state of equilibrium, the properties of the system are uniform and only one value can be assigned to it. A system will be in a state of thermodynamic equilibrium, if the condition for following three types of equilibrium are satisfied. Thermal Equilibrium (Equality of Temperature): A state of thermal equilibrium can be described as one in which the temperature of the system is uniform. Mechanical Equilibrium(Equality of Pressure): In the absence of any unbalanced force within the system itself and also between the system and the surroundings, the system is said to be in a state of mechanical equilibrium.  Mechanical equilibrium is related to pressure.  A system is in mechanical equilibrium if there is no change in pressure at any point of the system .
  • 12. Chemical Equilibrium(Equality of chemical potential):  A system is in chemical equilibrium when its chemical composition does not change with time, that is no chemical reaction occurs .  It is related to chemical potential. QUASI-STATIC PROCESS A quasi-static process is one in which the deviation from thermodynamic equilibrium is infinitesimal. Characteristics:  Infinite slowness is the characteristic feature of this process.  A quasi-static process is thus a succession of equilibrium states.  It can be represented as a continuous line on the property diagram.  It is also known as a reversible process. REVERSIBLE PROCESS Reversible process is one which is performed in such a way that at the end of the process both the system and surrounding may be restored to their initial state without producing any changes in rest of the Universe. Reasons for studying Reversible Process: 1.They are easy to analyze.
  • 13. 2. They served as an idealized process to which actual process can be compared. 3.They are taken for consideration because work producing devices such as steam turbine, automobile engines etc delivers the max. work and work consuming devices like compressors, pumps etc consumes the least work. Characteristics of Reversible Process  A Reversible process is carried out infinitely slowly with an infinitesimal gradient so that every state pass through by the system is in equilibrium.  It is possible to execute the process in either of the direction.  No dissipative effect such as friction, loss in a resistor, etc are present.  Heat and work interactions of the system and the surroundings in the reverse process are equal and opposite in direction to the same in the forward process. Examples: 1. Frictionless isothermal expansion or compression of a fluid. 2. Frictionless adiabatic expansion or compression of a fluid. 3. Elastic stretching of a solid. 4. Electric current with zero resistance. IRREVERSIBLE PROCESS An irreversible process is one that is carried out in such a way that the system and surrounding can not be exactly restored to their respective initial state at the end of the reverse process, that a net change occurs in the Universe. Note: In an irreversible the surrounding would always be affected by loss of work and gain of low temperature heat, which can be considered as waste heat for the surrounding. Causes of an Irreversibility: The irreversibility of a process may be due to either one or both of the following. (i) Lack of Equilibrium. (ii) Involvement of Dissipative effects.
  • 14. Lack of Equilibrium(Mechanical,Thermal,Chemical) The lack of equilibrium between the system and the surroundings or between the two systems causes a spontaneous change which makes the process irreversible. Examples: 1. Heat transfer through a finite temperature difference. 2. Compression or Expansion through a finite pressure difference between the system and the surroundings. 3. Free expansion or Unrestrained expansion. 4. Mixing of substances. Dissipative Effects: Dissipation results in the transformation of work into molecular energy of the system. Examples: 1. Friction. 2. Flow of electricity through a resistor. 3. Paddle wheel work transfer. etc Characteristics of an Irreversible Process: 1. It can be carried out in one direction only. 2. It occurs at a finite rate. 3. During an irreversible process, the system is not in equilibrium. An irreversible process cannot be reversed without causing permanent changes in the surroundings.
  • 15. Heat & Work Transfer Thermodynamic Work: Work is said to be done by a system if the sole effect on things external to the system can be reduced to the raising of a weight. Displacement (or) pdV Work: Expression for pdV Work: 2 12 1 ( *piston area* ) * * = W dW p displacement p A dL pdV W pdV
  • 16. Sign Convention for work transfer: Work done by the system is positive and Work done on the system is negative. Work done during various Quasi-static Processes: Constant Pressure Proces: 2 1 1 2 2 1( ) V V W pdV p V V Constant Volume Process:
  • 17. 2 1 1 2 0 V V W pdV Constant Temperature Process: 2 1 1 2 V V W pdV Polytropic Process n pV C , where n is a constant 2 1 1 1 1 1 2 1 2 1 1 1 1 1 ln V V pV pV C pV p V VdV W pV pV V V
  • 18. 2 1 2 1 1 1 2 2 1 1 1 2 1 1 1 1 2 2 ( ) = 1 n n n n n V V V n n V pV pV p V C pV p V W pdV pV dV V pV p V n Heat Transfer: Energy transfer by virtue of temperature difference is called Heat Transfer. Heat Transfer is also a boundary phenomenon. Specific Heat: It is the amount of heat required to raise the temperature of unit mass of a substance by unit degree. For Solids and Liquids cp = cv = c For Gases cp – specific heat capacity at constant pressure cv – specific heat capacity at constant volume Latent Heat: It is the amount of heat transferred to cause a phase change.
  • 19. FIRST LAW OF THERMODYNAMICS  This is based on Law of Conservation of Energy.  This is also called as First Principle. For a closed system, undergoing a cycle Sum of all Work transfers = Sum of all Heat Transfers (W1+W2+W3+…..) = Σ(Q1 +Q2+Q3+……….) Σ(W) = Σ(Q) For a closed system,undergoing a Process Whenever heat is absorbed by a system it increases its internal energy and does some work. Q = ΔE + W Where Q – heat absorbed by the system W – Work output from the system ΔE – Change in Stored Energy of the system Show that Energy is a property of the system For path A, A A AQ W E (1) dW dQ
  • 20. For path B, B B BQ W E (2) For path B, C C CQ W E (3) For Cycle 1-A-2-B-1, A B A BW W Q Q (4) ( )A A B BQ W Q W A BE E (A) For Cycle 1-A-2-C-1, A C A CW W Q Q ( )A A C CQ W Q W A CE E (C) Comparing A and C B CE E Enthalpy:  It is the energy content of the flowing fluid.  It is defined by the summation of internal energy and flow work. H = U + PV Note: For an ideal gas h = u + Pv. = u + RT So, h = f(T) Define Cv with the help internal energy and Temperature: The amount of heat required to raise the temperature of unit mass of a substance by 1o C in a reversible constant volume process.
  • 21. v v u C T vC is also defined as the change of internal energy of the substance per unit change in temperature at constant volume. Define Cp with the help enthalpy and Temperature: The amount of heat required to raise the temperature of unit mass of a substance by 1o C in a reversible constant pressure process. p p h C T pC is also defined as the change of internal energy of the substance per unit change in temperature at constant pressure. Application of First law to different Thermodynamic process: Process Index=n Q W= PdV P-V-T Relation Rev. Const.Vol. Q U = 2 1( )vmC T T W=0 1 2 1 2 P P T T Rev.Const.pressure n=0 Q H = 2 1( )pmC T T 2 1( )W P V V = 2 1( )mR T T 1 2 1 2 V V T T Rev. Isothermal n=1 2 1 1 1 ln V Q W PV V 2 1 1 1 ln V W PV V 1 1 2 2PV PV Rev.Adiabatic n=γ Q=0 1 1 2 2 1 PV PV W 1 1 2 2PV PV Rev.Polytropic n Q U W 1 1 2 2 1 PV PV W n 1 1 2 2 n n PV PV
  • 22. MODULE-2 SECOND LAW OF THERMODYNAMICS State the limitations of first law of thermodynamics? 1. First Law places no restriction on the direction of a process. 2. It does not ensure whether the process is feasible or not. 3. This law does not differentiate heat and work. It is concerned with the quantity of energy and the transformation of energy from one form to another with no regard to its quality. Aspects of the second law 1. To identify the direction of process. 2. Establishing conditions for equilibrium. 3. It also asserts that energy has quality as well as quantity. 3. It is also used in determining the theoretical limits for the performance of heat engines and refrigerators. 4. Defining a temperature scale independent of the properties of any thermometric substance. Thermal Energy Reservoir (TER): It is a hypothetical body with a relatively large thermal energy capacity that can supply or absorb finite amount of heat without undergoing any change in temperature. Examples: Oceans, rivers, atmospheric air etc.  TER that supplies energy in the form of heat is called a source  TER that absorbs energy in the form of heat is called a sink Heat Engines: Heat engine is a cyclic device, used to convert heat to work. Heat engine can be characterized by the following points. 1. They receive heat from a high temperature source (solar energy, oil-furnace etc.) 2. They convert part of this heat to work (usually in the form of a rotating shaft) 3. They reject the remaining waste heat to a low temperature sink (the atmosphere, rivers, etc) 4.They opertate on a cycle.
  • 23. Q1 = amount of heat supplied to steam in boiler from a high-temperature source. Q2 = amount of heat rejected from steam in condenser to a low temperature sink. W = net work output of this heat engine. Thermal efficiency: The fraction of the heat input that is converted to net work output is a measure of the performance of the heat engine. Net work output ( ) Total heat input Thermal efficiency th 1 W Q 2 th 1 Q 1 Q Refrigerator: Refrigerators are cyclic devices, used to transfer heat from a low temperature medium to a high temperature medium. The working fluid used in the refrigeration cycle is called a refrigerant. The most frequently used refrigeration cycle is the vapor-compression refrigeration cycle. Coefficient of Performance (COP) 2 R QDesired output COP Required input W 2 R 1 2 Q COP Q Q
  • 24. Heat Pumps: Heat pumps are another cyclic devices, used to transfer heat from a low temperature medium to a high temperature medium. The objective of a heat pump is to maintain a heated space at a high temperature. This is accomplished by absorbing heat from a low temperature source, such as cold outside air in winter and supplying this heat to the high temperature medium such as a house. 1 HP QDesired output COP Required input W 1 HP 1 2 Q COP Q Q Relation between HPCOP and RCOP HPCOP = RCOP +1 (Refrigerator)
  • 25. Statements of Second Law Kelvin-Planck Statement of the Second law It is impossible for any device that operates on a cycle to receive heat from a single reservoir and produce a net amount of work. (A heat engine that violates the Kelvin-Planck statement) Clausius Statement: It is impossible to construct a device that operates in a cycle and produce no effect other than the transfer of heat from a low temperature body to a high temperature body.
  • 26. Equivalence of Kelvin Planck and Clausius Statements: The equivalence of the statement is demonstrated by showing that the violation of each statement implies the violation of other. CASE-1: Violation of Kelvin-planck statement leads to violation of Clausius statement A refrigerator that violates the Clausius statementof the second law Violation of Kelvin-Planck statement
  • 27. CASE-2: Violation of Clausius statement leads to violation of Kelvin-planck statement Thus violation Kelvin Planck Statement has lead to the violation of Clausius Statement
  • 28. Thus Violation of Clausius Statement has lead to violation of Kelvin Planck Statements
  • 29. Carnot Cycle: Carnot cycle is a reversible cycle that is composed of four reversible processes, two isothermal and two adiabatic.  Process 1 - 2 (Reversible Isothermal Heat Addition)  Process 2 – 3 (Reversible Adiabatic Expansion)  Process 3 – 4 (Reversible Isothermal Heat Rejection)  Process 4 – 1 ( Revesible Adiabatic Compression) Σ(Q net)cycle = Σ( Wnet)cycle Qadd – Qrej = We – Wc net add rej add add 2 1 2 1 W Q - Q Q Q = 1 - From T-S diagram T ( S) = 1 T ( S) T = 1 T rej add Q Q
  • 30. Carnot’s Theorem: 1. The efficiency of an irreversible heat engine is always less than efficiency of a reversible one operating between the same two reservoirs. 2. The efficiencies of all reversible heat engines operating between the same reservoirs are the same. Clausius Inequality The cyclc integral of Q T is always less than or equal to zero. Mathematically it can be expressed as 0 Q T . The equality in the Clausius inequality holds for totally or just reversible cycle and the inequality for the irreversible ones. Reversible Engine 1 1 2 2 1 2 1 2 1 2 1 2 ( ) 0 0 Q T Q T or Q Q T T Q Q T T dQ T
  • 31. For an Irreversible Engine 1 2I 1 2RQ Q Q Q and therefore 2I 2RQ Q Consequently, for an irreversible heat engine 1 2I 0Q Q Q 1 2I 1 2 0 Q QQ T T T So we conclude that for all irreversible heat engine 0 Q T Entropy: Entropy is defined as rev Q dS T The T ds Relations: But and Thus, The first TdS equation is obtained as The second TdS equation is obtained by using the definition of enthalpy . ( ) rev rev rev rev Q dU W Q TdS W PdV TdS dU PdV h u pv dH dU d PV dU PdV VdP TdS dH (Since ) The equations can be written on a unit mass basis as VdP TdS dU PdV TdS Tds du Pdv Tds dh vdP
  • 32. Entropy change of an ideal gas The entropy change between two states of an ideal gas canbe obtained from the ideal gas equation and the combined equation of the first first and second laws. Entropy change for different process: Process Entropy change 2 1s s Reversible constant volume process Reversible constant pressure process 2 2 2 1 1 1 2 2 2 1 1 1 Tds = du + Pdv But, du = c and P = (RT)/v Therefore, RT Tds = c c s c ln ln v v v v dT dT dv v or dT dv ds R T v T v s R T v 2 2 2 1 1 1 2 2 2 1 1 1 , Tds = Now, dh = c and v = (RT)/P ds = c c s c ln ln p p P p Again dh vdP dT dT RT dP T PT dT dP ds R T P T P s R T P 2 2 1 1 s c lnv T s T 2 2 1 1 s c lnv T s T 2 2 1 1 s c lnp T s T
  • 33. Reversible isothermal process Reversible adiabatic process 2 1s s Polytropic process Basic components of IC engine 2 2 2 1 2 1 1 1 ln ln P v s s R or s s R P v 2 2 2 1 1 1 2 2 2 1 1 1 c c v p dT dv ds R T v dT dP or ds R T P Internal Combustion engine Spark ignition engine Compression ignition engine These engines are petrol engine and they work on Otto cycle These engines are diesel engine and they work on Diesel cycle
  • 34. Engine Terminology: 1.Top Dead Center (TDC): Position of the piston when it stops at the furthest point away from the crankshaft. – Top because this position is at the top of the engines (not always), and dead because the piston stops as this point. – When the piston is at TDC, the volume in the cylinder is a minimum called the clearance volume. 2. Bottom Dead Center (BDC): Position of the piston when it stops at the point closest to the crankshaft. Volume of the cylinder is maximum. 3. Stroke : Distance traveled by the piston from one extreme position to the other : TDC to BDC or BDC to TDC. 4. Bore :It is defined as cylinder diameter or piston face diameter; piston face diameter is same as cylinder diameter( minus small clearance). 5. Swept volume/Displacement volume : Volume displaced by the piston as it travels through one stroke. – Swept volume is defined as stroke times bore. – Displacement can be given for one cylinder or entire engine (one cylinder times number of cylinders). Clearance volume : It is the minimum volume of the cylinder available for the charge (air or air fuel mixture) when the piston reaches at its outermost point (top dead center or outer dead center) during compression stroke of the cycle. – Minimum volume of combustion chamber with piston at TDC. Compression ratio : The ratio of total volume to clearance volume of the cylinder is the compression ratio of the engine. – Typically compression ratio for SI engines varies form 8 to 12 and for CI engines it varies from 12 to 24 Otto cycle: The processes in Otto cycle are  (1 – 2) Isentropic Compression  (2 – 3) Constant volume heat addition.
  • 35.  (3 – 4) Isentropic Expansion.  (4 – 1) Constant volume heat rejection. Efficiency of Otto Cycle Diesel cycle The processes in Diesel cycle are:  (1 – 2) Isentropic Compression  (2 – 3) Constant pressure heat addition.  (3 – 4) Isentropic Expansion. 3 4 2 1 3 4 3 4 3 1 1 2 1 2 1 1 1 3 11 1 1 C ( ) C T 1 C (T ) C T (1 r ) 1 = C 1 r 1 1 W Work ratio = net Otto v v k v v k net p k k otto k net turb W Heat Supplied Wnet W W W T T r W T W T T r r W ( 1)1 3 1 k ine T r T
  • 36.  (4 – 1) Constant volume heat rejection. Efficiency of Diesel cycle 3 2 4 1 3 2 4 1 th 3 2 4 1 14 1 3 2 3 2 2 1 2 Now =1 Now ( ) and ( ) ( ) ( ) Hence η ( ) 1 ( ) 1 (( )) 1 net Diesel in out in in p out v p v p W Heat Supplied q q q q c T T q c T T c T T c T T c T T T T TT T T T T T T T v T 11 2 1 3 3 3 2 2 2 4 4 4 1 1 1 31 4 2 2 1 Substituting the values of 1 Also since = , hence = ρ where ρ is the cut-off ratio. Again since , ρ , , and , the value of thermal efficiency cv r T v p p T v T p v v T p TT T T T T 1 th 1 ρ 1 η 1 ρ 1cr
  • 37. Dual cycle: Processes in Dual cycle: 1. (1-2) Isentropic compression 2. (2-3) Constant volume heat addition 3. (3-4) Constant pressure heat addition 4. (4-1) Isentropic expansion 5. (5-1) Constant volume heat rejection. Efficiency of Dual cycle 3 2 4 3 5 1 3 2 4 3 5 1 3 2 4 3 1 , ρ 1 1- ( (ρ 1) η c ( ) ( ) ( ) = ( ) ( ) ( ) η 1 ( ) ( ) 1 1) Dual in out dual in v p v v p dual p c p p Efficiency r r r q q q T T c T T c T T c T T c T T T T T T T T r
  • 38. Comparision between SI engine and CI engine SI engine CI engine Working cycle is Otto cycle. Working cycle is diesel cycle. Petrol or gasoline or high octane fuel is used. Diesel or high cetane fuel is used. High self-ignition temperature. Low self-ignition temperature. Fuel and air introduced as a gaseous mixture in the suction stroke. Fuel is injected directly into the combustion chamber at high pressure at the end of compression stroke. Carburettor used to provide the mixture. Throttle controls the quantity of mixture introduced. Injector and high pressure pump used to supply of fuel. Quantity of fuel regulated in pump. Use of spark plug for ignition system Self-ignition by the compression of air which increased the temperature required for combustion Compression ratio is 6 to 10.5 Compression ratio is 14 to 22 Higher maximum RPM due to lower weight Lower maximum RPM Maximum efficiency lower due to lower compression ratio Higher maximum efficiency due to higher compression ratio Lighter Heavier due to higher pressures Valve timing diagram The exact moment at which the inlet and outlet valve opens and closes with reference to the position of the piston and crank shown diagrammatically is known as valve timing diagram. It is expressed in terms of degree crank angle. The theoretical valve timing diagram is shown in Fig.
  • 39. But actual valve timing diagram is different from theoretical due to two factors-mechanical and dynamic factors. Figure 4 shows the actual valve timing diagram for four stroke low speed or high speed engine. Opening and closing of inlet valve  Inlet valve opens 12 to 30ᵒ CA before TDCto facilitate silent operation of the engine under high speed. It increases the volumetric efficiency.  Inlet valve closes 10-60ᵒ CA after TDC due to inertia movement of fresh charge into cylinder i.e. ram effect. Figure represents the actual valve timing diagram for low and high speed engine. Opening and closing of exhaust valve Exhaust valve opens 25 to 55ᵒ CA before BDC to reduce the work required to expel out the burnt gases from the cylinder. At the end of expansion stroke, the pressure inside the chamber is high, hence work to expel out the gases increases.
  • 40. Exhaust valve closes 10 to 30ᵒ CA after TDC to avoid the compression of burnt gases in next cycle. Kinetic energy of the burnt gas can assist maximum exhausting of the gas. It also increases the volumetric efficiency. Valve overlap During this time both the intake and exhaust valves are open. The intake valve is opened before the exhaust gases have completely left the cylinder, and their considerable velocity assists in drawing in the fresh charge. Engine designers aim to close the exhaust valve just as the fresh charge from the intake valve reaches it, to prevent either loss of fresh charge or unscavenged exhaust gas.