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Doris Perdomo



      +∞ 3𝑥𝑑𝑥
10)    5 𝑥 2 +9
                        Sea: u= 𝑥 2 + 9                       𝑑𝑢 = 2𝑥𝑑𝑢                           𝑑𝑢 = 𝑥𝑑𝑥

                       +∞                                +∞                                   +∞
                                𝑑𝑢               1            𝑑𝑢           1                               1
                                   =                             =           ln 𝑢                  =         𝑙𝑛 + ∞ − 𝑙𝑛14
                       14       2𝑢               2   14       𝑢            2              14               2




      +∞    𝑑𝑥                                                  𝑑𝑥
14)   𝑒  𝑥(𝑙𝑛𝑥 )2
                            Sea:         u= lnx           du=    𝑥

                                                                                              ∞
                                 𝑑𝑢                                                                             1 1
                                    =                     𝑢−2 𝑑𝑢 =                  𝑢−1            =             − = −1
                            1    𝑢2                  1                                        1                 ∞ 1




      +𝑎                                                 +∞
21)   −𝑎
           𝑐𝑜𝑠𝜋. 𝑥𝑑𝑥             − 𝑠𝑒𝑛𝜋𝑥                 −𝑎
                                                              =                − 𝑠𝑒𝑛𝜋∞ − 𝑠𝑒𝑛𝜋∞ = 0




       16 𝑑𝑥                        16        −3                                1        16
27)   0 4 𝑥3
               =                   0
                                          𝑥          4   𝑑𝑥 =              4𝑥       4
                                                                                        0
                                                                                              = 4 2−0 =8




       4 𝑥𝑑𝑥                                                                                               𝑑𝑢
29)   0 16−𝑥 2
                  =              𝑆𝑒𝑎 =               𝑢 = 16𝑥 2                 du=-2xdx                −   2
                                                                                                                = 𝑥𝑑𝑥

                          1        16
                                             𝑑𝑢         1         0
                                                                          −1              1 1                    0
                                                                                                            2 16 = − 0−4 =4
                        −                    1       =−               𝑢        2    𝑑𝑢 = − 2𝑢
                          2      0       𝑢       2      2       16                        2
Doris perdomo

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Doris perdomo

  • 1. Doris Perdomo +∞ 3𝑥𝑑𝑥 10) 5 𝑥 2 +9 Sea: u= 𝑥 2 + 9 𝑑𝑢 = 2𝑥𝑑𝑢 𝑑𝑢 = 𝑥𝑑𝑥 +∞ +∞ +∞ 𝑑𝑢 1 𝑑𝑢 1 1 = = ln 𝑢 = 𝑙𝑛 + ∞ − 𝑙𝑛14 14 2𝑢 2 14 𝑢 2 14 2 +∞ 𝑑𝑥 𝑑𝑥 14) 𝑒 𝑥(𝑙𝑛𝑥 )2 Sea: u= lnx du= 𝑥 ∞ 𝑑𝑢 1 1 = 𝑢−2 𝑑𝑢 = 𝑢−1 = − = −1 1 𝑢2 1 1 ∞ 1 +𝑎 +∞ 21) −𝑎 𝑐𝑜𝑠𝜋. 𝑥𝑑𝑥 − 𝑠𝑒𝑛𝜋𝑥 −𝑎 = − 𝑠𝑒𝑛𝜋∞ − 𝑠𝑒𝑛𝜋∞ = 0 16 𝑑𝑥 16 −3 1 16 27) 0 4 𝑥3 = 0 𝑥 4 𝑑𝑥 = 4𝑥 4 0 = 4 2−0 =8 4 𝑥𝑑𝑥 𝑑𝑢 29) 0 16−𝑥 2 = 𝑆𝑒𝑎 = 𝑢 = 16𝑥 2 du=-2xdx − 2 = 𝑥𝑑𝑥 1 16 𝑑𝑢 1 0 −1 1 1 0 2 16 = − 0−4 =4 − 1 =− 𝑢 2 𝑑𝑢 = − 2𝑢 2 0 𝑢 2 2 16 2