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Source Conversion
R in series with it. It should be kept in
mind that a voltage source-series
resistance combination is equivalent to
(or replaceable by) a current source-
parallel resistance combination if, and
only if their
1. respective open-circuit voltages are
equal, and
2. respective short-circuit currents are
equal.
Use Source Conversion technique to find the load current I in
the circuit of Fig. I1 = 2 A.
Calculate the direction and magnitude of the current through the 5 ohm resistor
between points A and B of Fig by source transformation and nodal method.
By using repeated source transformations and nodal analysis,
find the value of voltage v in Fig.
Use source transformation technique nodal to find the current flowing through the 2 ohm
resistor
Using nodal voltage method, compute the power dissipated in the 9- ohm resistor of Fig
By applying nodal method of network analysis, find current in the 15 ohm resistor
of the network shown in Fig.
Superposition Theorem
Use Superposition theorem to find current I in the circuit shown in Fig
Using Superposition theorem, find the current through the 40 ohm
resistor of the circuit shown in Fig.
Solve for the power delivered to the 10 ohm resistor in the circuit shown in Fig.
Compute the power dissipated in the 9-W resistor of Fig. by applying the Superposition
principle.
Using Superposition theorem, find the value of the output voltage V0 in the circuit of Fig.
V0 = V01 + V02 + V03 = 2 + 4 - 4 = 2 V
Use Superposition theorem, to find the voltage V in Fig
V = V1 + V2 + V3 = 3 + 20 - 12 = 11 V
Determine using superposition theorem, the voltage across the 4 ohm resistor
shown in Fig.
Use Superposition theorem to calculate the voltage drop across the 3 ohm resistor of Fig. below All resistance
values are in ohms. [18 V]
For the circuit shown in Fig. find the current in R = 8 ohm resistance in the branch AB
using superposition theorem. [0.875 A]
Thevenin Theorem
Definition of Thevenin’s Theorem
Convert the circuit shown in Fig., to a single voltage source in series with a single resistor.
Using Thevenin theorem, calculate the current flowing through the 4 ohm resistor of Fig.
For the circuit shown in Fig., calculate the current in the 10 ohm resistance. Use
Thevenin’s theorem only.
Find Thevenin’s equivalent circuit for the network shown in Fig. for the terminal pair AB.
Norton’s Theorem
This theorem is an alternative to the Thevenin’s theorem. In fact, it is the dual of Thevenin’s theorem.
Whereas Thevenin’s theorem reduces a two-terminal active network of linear resistances and generators
to an equivalent constant-voltage source and series resistance, Norton’s theorem replaces the network by
an equivalent constant-current source and a parallel resistance.
Apply Norton’s theorem to calculate current flowing through 5 ohm resistor of Fig
Find the voltage across points A and B in the network shown in Fig. by using
Norton’s theorem.

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SPT.pptx

  • 1. Source Conversion R in series with it. It should be kept in mind that a voltage source-series resistance combination is equivalent to (or replaceable by) a current source- parallel resistance combination if, and only if their 1. respective open-circuit voltages are equal, and 2. respective short-circuit currents are equal.
  • 2.
  • 3. Use Source Conversion technique to find the load current I in the circuit of Fig. I1 = 2 A.
  • 4.
  • 5. Calculate the direction and magnitude of the current through the 5 ohm resistor between points A and B of Fig by source transformation and nodal method.
  • 6.
  • 7. By using repeated source transformations and nodal analysis, find the value of voltage v in Fig.
  • 8. Use source transformation technique nodal to find the current flowing through the 2 ohm resistor
  • 9. Using nodal voltage method, compute the power dissipated in the 9- ohm resistor of Fig
  • 10. By applying nodal method of network analysis, find current in the 15 ohm resistor of the network shown in Fig.
  • 12.
  • 13. Use Superposition theorem to find current I in the circuit shown in Fig
  • 14. Using Superposition theorem, find the current through the 40 ohm resistor of the circuit shown in Fig.
  • 15. Solve for the power delivered to the 10 ohm resistor in the circuit shown in Fig.
  • 16. Compute the power dissipated in the 9-W resistor of Fig. by applying the Superposition principle.
  • 17. Using Superposition theorem, find the value of the output voltage V0 in the circuit of Fig. V0 = V01 + V02 + V03 = 2 + 4 - 4 = 2 V
  • 18. Use Superposition theorem, to find the voltage V in Fig V = V1 + V2 + V3 = 3 + 20 - 12 = 11 V
  • 19. Determine using superposition theorem, the voltage across the 4 ohm resistor shown in Fig.
  • 20. Use Superposition theorem to calculate the voltage drop across the 3 ohm resistor of Fig. below All resistance values are in ohms. [18 V]
  • 21. For the circuit shown in Fig. find the current in R = 8 ohm resistance in the branch AB using superposition theorem. [0.875 A]
  • 23.
  • 25. Convert the circuit shown in Fig., to a single voltage source in series with a single resistor.
  • 26. Using Thevenin theorem, calculate the current flowing through the 4 ohm resistor of Fig.
  • 27. For the circuit shown in Fig., calculate the current in the 10 ohm resistance. Use Thevenin’s theorem only.
  • 28. Find Thevenin’s equivalent circuit for the network shown in Fig. for the terminal pair AB.
  • 29. Norton’s Theorem This theorem is an alternative to the Thevenin’s theorem. In fact, it is the dual of Thevenin’s theorem. Whereas Thevenin’s theorem reduces a two-terminal active network of linear resistances and generators to an equivalent constant-voltage source and series resistance, Norton’s theorem replaces the network by an equivalent constant-current source and a parallel resistance.
  • 30.
  • 31.
  • 32. Apply Norton’s theorem to calculate current flowing through 5 ohm resistor of Fig
  • 33. Find the voltage across points A and B in the network shown in Fig. by using Norton’s theorem.