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a. A waitress is serving 5 people at a table. She has the 5 dishes they ordered (all 5 different), but
she can't remember who gets what. How many different possible way are there for her to give
the 5 dishes to the 5 people? Explain you answer
b. Based on part (a), if the waitress just hands the dishes out randomly, what is the probability
that she will hand the dishes out correctly
Solution
a. A waitress is serving 5 people at a table. She has the 5 dishes they ordered (all 5 different),
but she can't remember who gets what. How many different possible way are there for her to
give the 5 dishes to the 5 people? Explain you answer different possible ways = 5! =120
WAYS different possible ways first person get dish =5 different possible ways second
person get dish =4 different possible ways third person get dish =3 different possible ways
fourth person get dish =2 different possible way fifth person get dish =1 different possible
ways = 5*4*3*2*1 =120 b. Based on part (a), if the waitress just hands the dishes out
randomly, what is the probability that she will hand the dishes out correctly probability =
1/120 =0.0083

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a. A waitress is serving 5 people at a table. She has the 5 dishes t.pdf

  • 1. a. A waitress is serving 5 people at a table. She has the 5 dishes they ordered (all 5 different), but she can't remember who gets what. How many different possible way are there for her to give the 5 dishes to the 5 people? Explain you answer b. Based on part (a), if the waitress just hands the dishes out randomly, what is the probability that she will hand the dishes out correctly Solution a. A waitress is serving 5 people at a table. She has the 5 dishes they ordered (all 5 different), but she can't remember who gets what. How many different possible way are there for her to give the 5 dishes to the 5 people? Explain you answer different possible ways = 5! =120 WAYS different possible ways first person get dish =5 different possible ways second person get dish =4 different possible ways third person get dish =3 different possible ways fourth person get dish =2 different possible way fifth person get dish =1 different possible ways = 5*4*3*2*1 =120 b. Based on part (a), if the waitress just hands the dishes out randomly, what is the probability that she will hand the dishes out correctly probability = 1/120 =0.0083