(1) Acid rain occurs when the gases SO2 ,NOx react with water,oxygen, and other chemicals in the atmosphere to form various acidic compounds. Sunlight increases the rate of most of these reactions. The result is a mild solution of sulfuric acid and nitric acid. Acid rain causes acidification of lakes and streams and contributes to damage of trees at high elevations and many sensitive forest soils. (2) 2NO2 + H2O ---> 2HNO3 Given mass of NO2 is , m = 5.47 mg = 5.47 x 10 -3 g Since 1 mg = 10 -3 g Volume of the solution , V = 1.0 L Molar mass of NO2 is = 14 + (2x16) = 46 g/mol So Molarity of NO2 , M = ( mass/Molar mass) / Volume of the solution = ( 5.47 x 10 -3 / 46 ) / 1.0 = 1.189 x 10 -4 M According to the balanced equation, 2 mole of NO2 produces 2 moles of HNO3 So the concentration of HNO3 is = 1.189 x 10 -4 M HNO3 ---> H+ + NO3- 1 mole of HNO3 produces 1 mole of H+ So [H+] = 1.189 x 10 -4 M pH = - log [H+] = -log ( 1.189 x 10 -4 ) = 4 - log 1.189 = 3.92 (3) HNO3 + H2O ----> HNO3 (aq) H2SO4 + H2O ---> H2SO4 (aq) HCl + H2O ---> HCl (aq) (2) 2NO2 + H2O ---> 2HNO3 Given mass of NO2 is , m = 5.47 mg = 5.47 x 10 -3 g Since 1 mg = 10 -3 g Volume of the solution , V = 1.0 L Molar mass of NO2 is = 14 + (2x16) = 46 g/mol So Molarity of NO2 , M = ( mass/Molar mass) / Volume of the solution = ( 5.47 x 10 -3 / 46 ) / 1.0 = 1.189 x 10 -4 M According to the balanced equation, 2 mole of NO2 produces 2 moles of HNO3 So the concentration of HNO3 is = 1.189 x 10 -4 M HNO3 ---> H+ + NO3- 1 mole of HNO3 produces 1 mole of H+ So [H+] = 1.189 x 10 -4 M pH = - log [H+] = -log ( 1.189 x 10 -4 ) = 4 - log 1.189 = 3.92 (3) HNO3 + H2O ----> HNO3 (aq) H2SO4 + H2O ---> H2SO4 (aq) HCl + H2O ---> HCl (aq) Solution (1) Acid rain occurs when the gases SO2 ,NOx react with water,oxygen, and other chemicals in the atmosphere to form various acidic compounds. Sunlight increases the rate of most of these reactions. The result is a mild solution of sulfuric acid and nitric acid. Acid rain causes acidification of lakes and streams and contributes to damage of trees at high elevations and many sensitive forest soils. (2) 2NO2 + H2O ---> 2HNO3 Given mass of NO2 is , m = 5.47 mg = 5.47 x 10 -3 g Since 1 mg = 10 -3 g Volume of the solution , V = 1.0 L Molar mass of NO2 is = 14 + (2x16) = 46 g/mol So Molarity of NO2 , M = ( mass/Molar mass) / Volume of the solution = ( 5.47 x 10 -3 / 46 ) / 1.0 = 1.189 x 10 -4 M According to the balanced equation, 2 mole of NO2 produces 2 moles of HNO3 So the concentration of HNO3 is = 1.189 x 10 -4 M HNO3 ---> H+ + NO3- 1 mole of HNO3 produces 1 mole of H+ So [H+] = 1.189 x 10 -4 M pH = - log [H+] = -log ( 1.189 x 10 -4 ) = 4 - log 1.189 = 3.92 (3) HNO3 + H2O ----> HNO3 (aq) H2SO4 + H2O ---> H2SO4 (aq) HCl + H2O ---> HCl (aq) (2) 2NO2 + H2O ---> 2HNO3 Given mass of NO2 is , m = 5.47 mg = 5.47 x 10 -3 g Since 1 mg = 10 -3 g Volume of the solution , V = 1.0 L Molar mass of NO2 is = 14 + (2x16) = 46 g/mol So Molarity of NO2 , M = ( mass/Molar mass) / Vol.