Cells divide and multiply in number as they proceed through the cell .pdf

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Cells divide and multiply in number as they proceed through the cell cycle. At some point however cells need to stop multiplying and the cell cycle is halted. Given your knowledge on mitosis think of two ways (methods, mechanisms procedures) a cell might stop it self from dividing. Solution Cell cycle is hated when there is damage to DNA or there is not proper DNA replication. At these points cell stops dividing. A) DNA damage: When there is damage in DNA then cell cycle stops dividing to facilitating DNA restore pathways. Methods involves are protein kinases of ATM/ATR own family called Tel1/Mec1 in budding yeast and Tel1/Rad3 in fission yeast. These kinases senses DNA damages and phosphorylate variety of proteins that regulate cell cycle development and DNA restore pathways. B) DNA replication: Accurate replication of the thousands and thousands or billions of DNA base pairs in a eukaryotic genomeis essential. Damaged template, protein and poor supply of dNTPs are most of the many obstacles that must be overcome to duplicate genome. All of those situations can stall replication forks. Stalled forks pose threats to genome integrity due to the fact they could rearrange, damage, or fall apart via disassembly of the replication complex .The pathways that respond to replication stress are signal transduction pathways which might be conserved across evolution. Procedure are ATM/ATR of relatives kinases. These kinases collectively with a trimeric checkpoint clamp (termed nine-1-1 complex) and 5-subunit checkpoint clamp loader (Rad17- RFC2-RFC3-RFC4-RFC5) senses stalled replication forks and transmit a checkpoint .One of principal functions of replication checkpoint is to prevent the onset of mitosis via regulating mitotic control proteins which includes Cdc25. But possibly the maximum essential interest of replication checkpoint is to stabilize and protect replication forks eight. The protein kinase Cds1 (human Chk2 homolog; in human, Chk1 is a purposeful Cds1 homolog) is a important effector of the replication checkpoint within the fission yeast. Cds1 is required to prevent stabilization of replication fork in cells deal with hydroxyurea (HU), a ribonucleotide reductase inhibitor that stalls replication by depleting dNTPs. In the budding yeast Saccharomyces cerevisiae, a failure to set off Rad53 (Chk2 homolog) is related to crumble and regression of replication forks.

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One goal of EHRs is to facilitate providers’ sharing of clinical information with patients to encourage patient involvement in decision-making about treatment plans. What might be some the potential advantages and disadvantages to providers and patients of sharing this information? Solution Advantages of Electronic Health Record (EHR) 1. EHR cuts down the need for maintenance of the records of the patient\'s medical history. 2. The records always remain in the legible format. 3. EMR boosts the interaction even at remote areas 4. Lesser paper-work 5. The treatment can be monitored to check the direction of treatment. In case if the wrong treatment is observed it can be stopped at the right moment Disadvantages: 1. Privacy Breach: The privacy of the patient is breached. 2. Software quality and usability deficiencies provide limitation in its implementation..

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Let E, F and G be three sets. State expressions for the events: only F occurs exactly two of the events occur plz explain ur answer Solution Only F occurs : E u F u G - E - G Explanation : EuFuG is the part tha is all of the circles. From this, i remove E and G, so only F remains. Exactly two of the events occur : (E n F) + (E n G) + (F n G) - 2*(E n F n G) ---> required expression Explanation : EnF is the part common to only E and F AND (all E,F and G) EnG is the part common to only E and G and (all E,F and G) FnG is the part common to only F and G and (all E,F and G) Since when all those were added, the (all E,F and G) was added thrice, i subtracted 2*(E n F n G) to get the required expression.

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In java , I want you to implement a Data Structure known as a Doubly-Ended-Queue. it is a “fair” data structure in that it implements a FIFO (First In First Out ) behavior. As such, it is often used to implement various wait lists in computer systems. For example, jobs waiting to use the CPU, jobs waiting for a printer, jobs waiting to be placed into RAM for execution. In short, whenever we want a fair strategy for waiting we use queues. A DEQUE (Doubly-ended-queue) is a related data structure. Although similar to a Queue, it differs in that it allows for insertions AND deletions from either end of the list (both the front and the rear). Your implementation MUST use a doubly-linked-list implementation. You may not use a static array implementation. Thus, a Deque is a List but it is one which only concerns itself with the first and last positions for any insertion or deletion. The 6 operations supported are : public void insertFront( int item ) - insert the given item (as a node) into the first position of the Deque. public void insertRear( int item ) - insert the given item (as a node) into the last position of the Deque. public int deleteFront( ) - delete and return the element stored in the first node of the Deque. public int deletRear( ) – delete and return the element stored in the last node of the Deque. public boolean isempty( ) - returns true if the Deque is currently empty or false if it is not. public void printDeque( ) - print the integers from the list, one per line, from the first element through to the last in order. Classes Your program must implement the following 3 classes. public class dequeDriver This class will contain your program’s main method. It will need to declare a deque object and process input as indicated below. Your program should prompt the user for the path of an input file. It should open the file for input and process it line by line. Each line of the input file will have one of the following forms. PR IF IR DF DR The meanings of each input is as follows: PR - print the current contents of the deque from front to rear using the printDeque( ) method of the deque object. IF - insert the given int value into the front of the deque. IR - insert the given int value into the rear of the deque. DF - delete the front value from the deque. DR – delete the rear element of the deque. Below is an example input file that your program should be able to process. PR IF 4 IF 5 IF 6 IR 7 PR DR PR DF PR The output for the input file shown above is : EMPTY DEQUE ----- Front ----- 6 5 4 7 ----- Rear ----- ----- Front ----- 6 5 4 ----- Rear ----- ----- Front ----- 5 4 ----- Rear ----- public class dequeNode This class will implement the linked nodes that will be used to implement the deque itself. It should have the following protected data members. protected dequeNode next; // next pointer to next node protected dequeNode prev; // previous pointer to previous node protected int val; // the integer value stored within the dequeNod.

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In humans, the sickle-cell trait is caused by a single detective allele, but sickle-cell disease only occurs in individuals that are homozygous for the sickle-cell allele. Two people carry the trait but do not have sickle-cell disease. What is the probability that they will have two children with sickle-cell disease? 1/16 1/2 3/8 1/4 Solution Answer is 1/2. Parents are carriers. Ss x Ss. The children will be of genotypes SS, Ss, sS, ss..

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Identify three examples of how U.S. society is heteronormative. Solution heteronormativity breaking it down sex assignment,gender identity,gender expression,sexuality,relationships there are many exampls of heteronormative in U.S 1.The Gender Binary- is acknowledgement of existence of men and women. 2 The Patriarchal Gender Roles- 3.Monogamy-even Gayle Rubin explain this hierarchy by“The Charmed Circle in her piece “Thinking Sex 4.White Supremacy-if we talk about heteronormative we need to understand the way in which heteronormativity is racialized -key element of heteronormativity is meeting standards of whiteness. ..

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