1) Create a function called reverselist that will take a simple list.pdf

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1) Create a function called reverselist that will take a simple list as a parameter and return the reversed list. (We aren’t using the word reverse, since it is also the name of a built-in function.) 2) Create a function called deleteall that will take an item and a list as parameters, and return the list with that item removed. Solution Hi, Please find my function. Please let me know in case of any issue. Let assume structure of node is: /* Link list node */ struct node { int data; struct node* next; }; a) /* Function to reverse the linked list */ struct node* reverse(struct node* head) { struct node* prev = NULL; struct node* current = head; struct node* next; while (current != NULL) { next = current->next; current->next = prev; prev = current; current = next; } return prev; } b) struct node* deleteNode(struct node *head, int item) { if(head == NULL) return NULL; // When node to be deleted is head node if(head->data == item) { return head->next; } // When not first node, follow the normal deletion process // find the previous node struct node *prev = head; while(prev->next != NULL && prev->item != item) prev = prev->next; // Check if node really exists in Linked List if(prev->next == NULL) { printf(\"\ Given node is not present in Linked List\"); }else{ // Remove node from Linked List prev->next = prev->next->next; } return head; }.

Education

if(head == NULL)
return NULL;
// When node to be deleted is head node
if(head->data == item)
{
return head->next;
}
// When not first node, follow the normal deletion process
// find the previous node
struct node *prev = head;
while(prev->next != NULL && prev->item != item)
prev = prev->next;
// Check if node really exists in Linked List
if(prev->next == NULL)
{
printf(" Given node is not present in Linked List");
}else{
// Remove node from Linked List
prev->next = prev->next->next;
}
return head;
}

Similar to 1) Create a function called reverselist that will take a simple list.pdf

Data Structures in C++ I am really new to C++, so links are really hard topic for me. It would be nice if you can provide explanations of what doubly linked lists are and of some of you steps... Thank you In this assignment, you will implement a doubly-linked list class, together with some list operations. To make things easier, you’ll implement a list of int, rather than a template class. Solution A variable helps us to identify the data. For ex: int a = 5; Here 5 is identified through variable a. Now, if we have collection of integers, we need some representation to identify them. We call it array. For ex: int arr[5] This array is nothing but a Data Structure. So, a Data Structure is a way to group the data. There are many Data Structures available like Arrays, Linked List, Doubly-Linked list, Stack, Queue, etc. Doubly-Linked list are the ones where you can traverse from the current node both in left and right directions. Why so many different types of Data Structures are required ? Answer is very simple, grouping of data, storage of data and accessing the data is different. For example, in case of Arrays we store all the data in contiguous locations. What if we are not able to store the data in contiguous locations because we have huge data. Answer is go for Linked List/Doubly-Linked list. Here we can store the data anywhere and link the data through pointers. I will try to provide comments for the code you have given. May be this can help you. #pragma once /* dlist.h Doubly-linked lists of ints */ #include class dlist { public: dlist() { } // Here we are creating a NODE, it has a integer value and two pointers. // One pointer is to move to next node and other to go back to previous node. struct node { int value; node* next; node* prev; }; // To return head pointer, i.e. start of the Doubly-Linked list. node* head() const { return _head; } // To return Tail pointer, i.e. end of the Doubly-Linked list. node* tail() const { return _tail; } // **** Implement ALL the following methods **** // Returns the node at a particular index (0 is the head). node* at(int index){ int cnt = 0; struct node* tmp = head(); while(tmp!=NULL) { if (cnt+1 == index) return tmp; tmp = tmp->next; } } // Insert a new value, after an existing one void insert(node *previous, int value){ // check if the given previous is NULL if (previous == NULL) { printf(\"the given previous node cannot be NULL\"); return; } // allocate new node struct node* new_node =(struct node*) malloc(sizeof(struct node)); // put in the data new_node->data = new_data; // Make next of new node as next of previous new_node->next = previous->next; // Make the next of previous as new_node previous->next = new_node; // Make previous as previous of new_node new_node->prev = previous; // Change previous of new_node\'s next node if (new_node->next != NULL) new_node->next->prev = new_node; } // Delete the given node void del(node* which){ struct node* head_ref = head(); /* base case */ if(*head_ref == NUL.

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Write a program in C that does the following: a) Builds a simple linked list consisting of 10 nodes each of which contains a random integer between 50 and 100 inclusive. The list is to be built in main() and must be a local variable in main(). b) Includes a user-defined function named printout(arg) that takes in the head pointer of the already-built linked list as an argument and prints out the contents of the linked list to the screen, starting from the head of the list to the tail. See the output below. Node #0 contains 53 Node #1 contains 78 Node #2 contains 95 . . . Node #20 contains 100 c) Includes a user-defined function called sum() that adds up the contents of the data members of each node in the list, and prints out the total as follows: The sum total of all nodes in this list is d) Includes a user-defined function called reverse() that takes in the head pointer of the already- built linked list as an argument and will physically reverse the order of the nodes in the list (i.e., the new head will be the old tail and the new tail will be the old head of the list). Use the function printout() to output its contents now in reverse order. This does NOT mean that it will be read backwards, but rather, the reversed list will be read from head to tail! ** PLEASE MAKE SURE THIS PROGRAM WORKS IN C LANGUAGE !! Solution #include #include /* Link list node */ struct node { int data; struct node* next; }; /* Function to reverse the linked list */ static void reverse(struct node** head_ref) { struct node* prev = NULL; struct node* current = *head_ref; struct node* next; while (current != NULL) { next = current->next; current->next = prev; prev = current; current = next; } *head_ref = prev; } /* Function to push a node */ void push(struct node** head_ref, int new_data) { /* allocate node */ struct node* new_node = (struct node*) malloc(sizeof(struct node)); /* put in the data */ new_node->data = new_data; /* link the old list off the new node */ new_node->next = (*head_ref); /* move the head to point to the new node */ (*head_ref) = new_node; } /* Function to print linked list */ void printList(struct node *head) { struct node *temp = head; int i=0; while(temp != NULL) { printf(\"Node #%d contains %d\ \",i, temp->data); temp = temp->next; i++; } } void sum(struct node *head) { int sum=0; struct node *temp = head; while(temp != NULL) { //printf(\"%d \", temp->data); sum+=temp->data; temp = temp->next; } printf(\"\ The sum total of all nodes in this list is %d\ \",sum); } /* Driver program to test above function*/ int main() { /* Start with the empty list */ struct node* head = NULL; int i,t; for(i=0;i<10;i++) { // (rand() % 51) generates random number between 0 and 50 adding 50 generates random number beween 50 and 100 both inclusive t=(rand() % 51)+50; push(&head, t); } printf(\"Given linked list\ \"); printList(head); sum(head); reverse(&head); printf(\"\ Reversed Linked list \ \"); printList(head); return 0; }.

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Conint29

LinkedDoublyLists.ppt

veenatanmaipatlolla

I need to implment a function that can reverse a single linked list. Not just print it, but actually change the order of the list. THIS MUST BE DONE USING RECURSION EX: a, b, c, d -> d, c, b, a You have access to the start of the list. Code must be in C++ Solution #include using namespace std; struct node { char data; struct node* next; }; void reverse(struct node* head) { if (head == NULL) //base case return; reverse(head->next); //calling function recursively cout<data<<\",\"; } //add data to the front of the linked list void add(struct node** head_ref, char data) { //create new node struct node* newnode=new node(); //adding data newnode->data = data; //adding node to the front newnode->next = (*head_ref); //making new node head (*head_ref) = newnode; } int main() { // create linked list a, b, c, d struct node* head = NULL; add(&head, \'d\'); add(&head, \'c\'); add(&head, \'b\'); add(&head, \'a\'); reverse(head); return 0; } //OUTPUT*********** d,c,b,a, //OUTPUT*********** //This code has been tested on g++ compiler,Please ask in case of any doubt,Thanks..

I need to implment a function that can reverse a single linked list..pdf

rohit219406

I need help implementing a Stack with this java programming assignment: Given a doubly linked list (code provided below) implement a Stack. You must use the doubly link list class and utilize it as an object in your implementation of the stack. A Stack is a Last in First Out (LiFO) structure which translates to the processes of outputting the last element which was inputted in the collection. The Stack is based on the process of putting things on top of one another and taking the item on top (think of a stack of papers). Operations to implement: push (E): Add an element to the start of the sequence pop: Remove an element from the start of the sequence Peek: Return the first element of the sequence without removing it atIndex(x): Return the element at the given index (x) Or throw an exception if it is out of bound (if you can control the user input then do that instead) Size: Return the size of the Stack isEmpty: Boolean, returns true if the Stack is empty Empty: Empty the Stack Code Part 1: public class DoublyLinkedList{ private DNode head; private DNode tail; private int size; public DoublyLinkedList(){ // construct an empty list this.tail = new DNode (null, null, this.head); this.head = new DNode (null, this.tail, null); this.size = 0; } public DoublyLinkedList(DNode next){ // constructs a list // out of a single node this.tail = new DNode (null, null, next); this.head = new DNode (null, next, null); next.changeNext(this.tail); next.changePrev(this.head); this.size = 1; } public DoublyLinkedList(Object [] objectArray){ // construct a list out of // an array this.tail = new DNode (null, null, this.head); this.head = new DNode (null, this.tail, null); DNode temp = this.head; for (Object e : objectArray) { //Anonomus function new DNode (e, temp.getNext(),temp).insertBetweenNodes(temp, temp.getNext()); temp = temp.getNext(); this.size += 1; } } public void addToFrontofList(Object toAdd){ // Appends the begining // of the list DNode temp = new DNode (toAdd, this.head.getNext(), this.head); this.head.getNext().changePrev(temp); this.head.changeNext(temp); this.size += 1; } public void addToendofList (Object toAdd) // appends the end of the list // with a node { DNode temp = new DNode (toAdd, this.tail, this.tail.getPrev()); this.tail.getPrev().changeNext(temp); this.tail.changePrev(temp); this.size += 1; } public void insertAfterNode(DNode current, Object input)// Inserts a new // a new node after // current node { current.insertAfterNode(input); this.size += 1; } public int getSize() // returns the size of the list { return this.size; } public String toString() { String result = \"\"; for (DNode temp = this.head.getNext(); temp.hasNext(); temp = temp.getNext()) { result += temp.getValue(); result += \" -> \"; } result += \"End of list\"; return result; } } and code part2: public class DNode{ private Object e; // place holder for the type of object the //collection is storing private DNode next; // reference to the next node in the sequence // of.

I need help implementing a Stack with this java programming assignme.pdf

sauravmanwanicp

C++ Please write the whole code that is needed for this assignment- wr.docx

BrianGHiNewmanv

Once you have all the structures working as intended, it is time to compare the performances of the 2. Use runBenchmark() to start. a. First, generate an increasing number (N) of random integers (1000, 5000, 10000, 50000, 75000, 100000, 500000 or as far as your computing power will let you) i. Time and print how long it takes to insert the random integers into an initially empty BST. Do not print the tree. You can get a random list using the java class Random, located in java.util.Random. To test the speed of the insertion algorithm, you should use the System.currentTimeMillis() method, which returns a long that contains the current time (in milliseconds). Call System.currentTimeMillis() before and after the algorithm runs and subtract the two times. (Instant.now() is an alternative way of recording the time.) ii. Time and print how long it takes to insert the same random integers into an initially empty AVL tree. Do not print the tree. iii. If T(N) is the time function, how does the growth of TBST(N) compare with the growth of TAVL(N)? Plot a simple graph to of time against N for the two types of BSTs to visualize your results. b. Second, generate a list of k random integers. k is also some large value. i. Time how long it takes to search your various N-node BSTs for all k random integers. It does not matter whether the search succeeds. ii. Time how long it takes to search your N-node AVL trees for the same k random integers. iii. Compare the growth rates of these two search time-functions with a graph the same way you did in part a. public class BinarySearchTree<AnyType extends Comparable<? super AnyType>> { protected BinaryNode<AnyType> root; public BinarySearchTree() { root = null; } /** * Insert into the tree; duplicates are ignored. * * @param x the item to insert. * @param root * @return */ protected BinaryNode<AnyType> insert(AnyType x, BinaryNode<AnyType> root) { // If the root is null, we've reached an empty leaf node, so we create a new node // with the value x and return it if (root == null) { return new BinaryNode<>(x, null, null); } // Compare the value of x to the value stored in the root node int compareResult = x.compareTo(root.element); // If x is less than the value stored in the root node, we insert it into the left subtree if (compareResult < 0) { root.left = insert(x, root.left); } // If x is greater than the value stored in the root node, we insert it into the right subtree else if (compareResult > 0) { root.right = insert(x, root.right); } // If x is equal to the value stored in the root node, we ignore it since the tree does not allow duplicates return root; } /** * Counts the number of leaf nodes in this tree. * * @param t The root of the tree. * @return */ private int countLeafNodes(BinaryNode<AnyType> root) { // If the root is null, it means the tree is empty, so we return 0 if (root == null) { return 0; } // If the root has no children, it means it is a leaf node, so we return 1 if (root.left == .

Once you have all the structures working as intended- it is time to co.docx

farrahkur54

Please need help on following program using c++ language. Please include all header files and main file with their own title. Extend the class linkedListType by adding the following operations: Write a function that returns the info of the kth element of the linked list. If no such element exists, terminate the program. Write a function that deletes the kth element of the linked list. If no such element exists, terminate the program. Provide the definitions of these functions in the class linkedListType. Also, write a program to test these functions. (Use either the class unorderedLinkedList or the class orderedLinkedList to test your function.) Solution C++ Code for the given problem is below..... ..................................................... /* * C++ Program to Implement Singly Linked List */ #include #include #include //using namespace std; /* * Node Declaration */ typedef struct nodetype { int info; nodetype *next ; } node; /* * Class Declaration */ class linkedListType { public: void insfrombeg( node **head, int); void delfromkth(node **head,int); void findthekthnode(node *head,int); void traverse(node *head); int item,ch,kth; node *ptr,*head,*temp; }; /* * Main :contains menu */ void main() { int item,ch,kth; node *ptr,*head,*temp; linkedListType s1; clrscr(); while (1) { while(1) { cout<<\"PRESS (1) FOR INSERT INTO LIST\"<>ch; switch(ch) { case 1: cout<<\"ENTER THE VALUE \"<>item; s1.insfrombeg(&head,item); break; case 2: s1.traverse(head); break; case 3: cout<<\"ENTER THE Kth Element which you want\'s to delete\"<>kth; s1.delfromkth(&head,kth); break; case 4: cout<<\"ENTER THE Kth Element which you want\'s to search \ \"<>kth; s1.findthekthnode(head,kth); break; case 5: exit(1); } } // getch(); } } /* * Inserting element in beginning */ void linkedListType::insfrombeg(node **head,int item) { temp= ( node * ) malloc (sizeof( node )); temp->info= item; temp->next= NULL; if(*head == NULL) { temp->next= *head; *head= temp; } else { temp->next= *head; *head= temp; } } /* * Delete element at a given position */ void linkedListType::delfromkth(node **head,int kth) { node* temp1=*head,*temp2; if(*head ==NULL) { cout<<\"LINK LIST IS EMPTY\ \"<next; free(temp); } else for(int j=0;jnext; temp2= temp1->next; temp1->next=temp2->next; free(temp2); } /* * Searching an element */ void linkedListType::findthekthnode(node *head,int kth) { ptr=head; int i=1; while((ptr!=NULL)) { if(i==kth) { cout<<\"\ The Element at\"<< kth<< \"position with value is \\t \"<info<info<next; i++; } } } /* * Traverse Link List */ void linkedListType::traverse(node *head) { ptr = head; while((ptr->next)->next!=NULL) { cout<info<<\"\\t\"; ptr=ptr->next; } cout< #include #include typedef struct nodetype { int info; nodetype *next ; } node; int item,ch,kth,total=1; node *ptr,*head,*temp; void insfrombeg( node **head, int); void delfromkth(node **head,int); void findthekthnode(node *head,int); void traverse(node *head); void main() { clrscr(); while(1) { printf(\"PRESS .

Please need help on following program using c++ language. Please inc.pdf

nitinarora01

Data structures

Jauhar Amir

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LinkedDoublyLists.ppt

I need to implment a function that can reverse a single linked list..pdf

I need help implementing a Stack with this java programming assignme.pdf

C++ Please write the whole code that is needed for this assignment- wr.docx

Once you have all the structures working as intended- it is time to co.docx

Please need help on following program using c++ language. Please inc.pdf

Data structures

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What were the driving forces behind the creation of the FAA and ICAO.pdf

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write two paragraphs on the polices to reduce income inequality and poverty. Explain the content of these policies and make a comparative assessment.! Solution Poverty is of two type-primary and secondary. In the former people face lack of resource and wealth to meet up the subsistence. On the otherhand, the later is one where people face impediment to have command and control over his rights. Former one is more severe. To reduce that many policies could be taken. For instance reduction in umemployment. This mainly belongs to LDCs. Disguised, cyclical unempyoment is an acute phenomenon of LDCs. Hence, poverty can be reduced by providing the unemployed people a justified employment. Next, progressive taxation can also be prudential to redistribute wealth but whether that can actually happen in reality without any obstacle or not is questionable as rich tax payers will not be too happy with it and even they are sources of finance of politics. When politics enter into cost- benefit analysis economy gets distorted from his efficient point. Most important point is to give benefits to poor, viz. subsidy, rationing etc. Even they can be provided minimum wage programme for specific time, viz. MNREGA in India. Lastly, in many cases producers exploit labourer. Hence, by implementing minimum wage law this can be cure out. Inequality refers to the unequal distribution of wealth among people. Payment must be equal to marginal product ensures inequality in the economy. But there should be a certain upper bound to that, beyond that it can be boomerang for the economy and it can act as an obstacle to growth. To reduce this progressive tax is an important tool. Taking wealth as a form of tax and redistributing that via expenditure for a certain group or for all reduce the inequality. Providing employment programme, implementing minimum wage laws, benefits in kinds, levying direct and indirect taxes on certain commodities can be effective to redistribute the wealth and reducing poverty. Inequality and poverty are to some extent overlapped and complements of each others. Hence, targetting to reduce one can be fruitful and its effect can tricle down to the other as a bless. Normative economics support the above views with no doubts but implementation of it in practice in many times often become difficult due to self centered persons, politics, social and emotional reasons and so on..

write two paragraphs on the polices to reduce income inequality and .pdf

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Where might you find the gametophytes of… Where might you find the g.pdf

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What single , unique characteristic of a protist would be considered most animal - like ? Fungus - like ? Plant - like ? What single , unique characteristic of a protist would be considered most animal - like ? Fungus - like ? Plant - like ? Solution Kingdom protista iis the most diverse group of eukaryotic organisms. They exhibit most diverese forms of obtaining nutrition, movement etc. Like animals, protozoan protists, do not make their own food, rather they obtain food from their environment. Thus they are heterotrophs, that move around and obtain food. Like fungus, protists occur in both unicellular and multicellular forms, feeding on decaying organic matter, and reproducing by forming spores. Also,some protists resemble plants and algae as they are autotrophs and they produce their own food. Presence of chloroplast have been found in some species of protists..

What single , unique characteristic of a protist would be conside.pdf

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What are the indications that Sarcodina, Apicomplexa and Ciliophora may have been derived from ancestral Phytomastigophorea? Solution Normally Phytomastigophorea is composed of species such as \"phytoflagellates\" in which these species have associated with presence of chloroplasts so that they are photosynthetic. Sarcodina have some ancestral indications similar to that of Apicomplexa and Ciliophora & related to species in Phytomastigophorea, mainly Sarcodina, Apicomplexa and Ciliophora are lacking, mitochondria and some of them have \"photosynthetic pigments\". Some of the cilipohornas are associated with cilia where species of Apicomplexa have parasitic nature similar to Phytomastigophorea.

What are the indications that Sarcodina, Apicomplexa and Ciliophora .pdf

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