Polygon .java package chegg2;public class Polygon { Var.pdf

•

0 likes•2 views

Polygon .java package chegg2; public class Polygon { // Variables private int numSides; private double sideLength; private double xCord; private double yCord; // Default Constructor public Polygon () { numSides = 3; sideLength = 5.0; xCord = 0.0; yCord = 0.0; } // Constructor public Polygon (int pSides, double numLength, double numXCord, double numYCord) { numSides = pSides; sideLength = numLength; xCord = numXCord; yCord = numYCord; } // Setter public void setSides(int mSides) { numSides = mSides; System.out.println(\"setSides() results: \"+this.numSides); } // Getter public int getSides() { return numSides; } } TestPolygon .java package chegg2; import java.util.Scanner; public class TestPolygon { public static void main(String[] args) { Polygon poly[] = new Polygon[2]; Polygon poly2 = new Polygon(); poly[0] = poly2; Scanner input = new Scanner(System.in); for(int i=1; i<2; i++){ Polygon obj = new Polygon(); System.out.println(\"New Polygons\"); System.out.println(\"--------------------------------------------------\"); System.out.print(\"Enter Number of Sides:\"); obj.setSides(input.nextInt()); poly[i] = obj; } input.close(); System.out.println(\"Polygons\"); System.out.println(\"--------------------------------------------------\"); for(int i=0; i<2; i++) { poly[i].setSides(poly[i].getSides()); } } } Output: run: New Polygons -------------------------------------------------- Enter Number of Sides:9 setSides() results: 9 Polygons -------------------------------------------------- setSides() results: 3 setSides() results: 9 BUILD SUCCESSFUL (total time: 1 second) Solution Polygon .java package chegg2; public class Polygon { // Variables private int numSides; private double sideLength; private double xCord; private double yCord; // Default Constructor public Polygon () { numSides = 3; sideLength = 5.0; xCord = 0.0; yCord = 0.0; } // Constructor public Polygon (int pSides, double numLength, double numXCord, double numYCord) { numSides = pSides; sideLength = numLength; xCord = numXCord; yCord = numYCord; } // Setter public void setSides(int mSides) { numSides = mSides; System.out.println(\"setSides() results: \"+this.numSides); } // Getter public int getSides() { return numSides; } } TestPolygon .java package chegg2; import java.util.Scanner; public class TestPolygon { public static void main(String[] args) { Polygon poly[] = new Polygon[2]; Polygon poly2 = new Polygon(); poly[0] = poly2; Scanner input = new Scanner(System.in); for(int i=1; i<2; i++){ Polygon obj = new Polygon(); System.out.println(\"New Polygons\"); System.out.println(\"--------------------------------------------------\"); System.out.print(\"Enter Number of Sides:\"); obj.setSides(input.nextInt()); poly[i] = obj; } input.close(); System.out.println(\"Polygons\"); System.out.println(\"--------------------------------------------------\"); for(int i=0; i<2; i++) { poly[i].setSides(poly[i].getSides()); } } } Output: run: New Polygons --------------------------------------------.

Education

System.out.println("setSides() results: "+this.numSides);
}
// Getter
public int getSides() {
return numSides;
}
}
TestPolygon .java
package chegg2;
import java.util.Scanner;
public class TestPolygon {
public static void main(String[] args) {
Polygon poly[] = new Polygon[2];
Polygon poly2 = new Polygon();
poly[0] = poly2;
Scanner input = new Scanner(System.in);
for(int i=1; i<2; i++){
Polygon obj = new Polygon();
System.out.println("New Polygons");
System.out.println("--------------------------------------------------");
System.out.print("Enter Number of Sides:");
obj.setSides(input.nextInt());
poly[i] = obj;
} input.close();
System.out.println("Polygons");

System.out.println("--------------------------------------------------");
for(int i=0; i<2; i++) {
poly[i].setSides(poly[i].getSides());
}
}
}
Output:
run:
New Polygons
--------------------------------------------------
Enter Number of Sides:9
setSides() results: 9
Polygons
--------------------------------------------------
setSides() results: 3
setSides() results: 9
BUILD SUCCESSFUL (total time: 1 second)
Solution
Polygon .java
package chegg2;
public class Polygon {
// Variables
private int numSides;
private double sideLength;
private double xCord;
private double yCord;
// Default Constructor
public Polygon () {

numSides = 3;
sideLength = 5.0;
xCord = 0.0;
yCord = 0.0;
}
// Constructor
public Polygon (int pSides, double numLength, double numXCord, double numYCord) {
numSides = pSides;
sideLength = numLength;
xCord = numXCord;
yCord = numYCord;
}
// Setter
public void setSides(int mSides) {
numSides = mSides;
System.out.println("setSides() results: "+this.numSides);
}
// Getter
public int getSides() {
return numSides;
}
}
TestPolygon .java
package chegg2;
import java.util.Scanner;
public class TestPolygon {
public static void main(String[] args) {
Polygon poly[] = new Polygon[2];

Polygon poly2 = new Polygon();
poly[0] = poly2;
Scanner input = new Scanner(System.in);
for(int i=1; i<2; i++){
Polygon obj = new Polygon();
System.out.println("New Polygons");
System.out.println("--------------------------------------------------");
System.out.print("Enter Number of Sides:");
obj.setSides(input.nextInt());
poly[i] = obj;
} input.close();
System.out.println("Polygons");
System.out.println("--------------------------------------------------");
for(int i=0; i<2; i++) {
poly[i].setSides(poly[i].getSides());
}
}
}
Output:
run:
New Polygons
--------------------------------------------------
Enter Number of Sides:9
setSides() results: 9
Polygons

--------------------------------------------------
setSides() results: 3
setSides() results: 9
BUILD SUCCESSFUL (total time: 1 second)

Similar to Polygon .java package chegg2;public class Polygon { Var.pdf

C# 6.0 - April 2014 preview

Paulo Morgado

Design patterns

Ba Tran

Manual tecnic sergi_subirats

Sergi Subirats Cugat

ch12/.DS_Store __MACOSX/ch12/._.DS_Store ch12/section_1/.DS_Store __MACOSX/ch12/section_1/._.DS_Store ch12/section_1/CashRegister.javach12/section_1/CashRegister.java/** A cash register totals up sales and computes change due. */ publicclassCashRegister { privatedouble purchase; privatedouble payment; /** Constructs a cash register with no money in it. */ publicCashRegister() { purchase =0; payment =0; } /** Records the sale of an item. @param amount the price of the item */ publicvoid addItem(double amount) { double newTotal = purchase + amount; purchase = newTotal; } /** Enters the payment received from the customer; should be called once for each coin type. @param coinCount the number of coins @param coinType the type of the coins in the payment */ publicvoid enterPayment(int coinCount,Coin coinType) { payment = payment + coinCount * coinType.getValue(); } /** Computes the change due and resets the machine for the next customer. @return the change due to the customer */ publicdouble giveChange() { double change = payment - purchase; purchase =0; payment =0; return change; } } __MACOSX/ch12/section_1/._CashRegister.java ch12/section_1/CashRegister.java.html 1 /** 2 A cash register totals up sales and computes change due. 3 */ 4 public class CashRegister 5 { 6 private double purchase; 7 private double payment; 8 9 /** 10 Constructs a cash register with no money in it. 11 */ 12 public CashRegister() 13 { 14 purchase = 0; 15 payment = 0; 16 } 17 18 /** 19 Records the sale of an item. 20 @param amount the price of the item 21 */ 22 public void addItem(double amount) 23 { 24 double newTotal = purchase + amount; 25 purchase = newTotal; 26 } 27 28 /** 29 Enters the payment received from the customer; should be called once 30 for each coin type. 31 @param coinCount the number of coins 32 @param coinType the type of the coins in the payment 33 */ 34 public void enterPayment(int coinCount, Coin coinType) 35 { 36 payment = payment + coinCount * coinType.getValue(); 37 } 38 39 /** 40 Computes the change due and resets the machine for the next customer. 41 @return the change due to the customer 42 */ 43 public double giveChange() 44 { 45 double change = payment - purchase; 46 purchase = 0; 47 payment = 0; 48 return change; 49 } 50 } __MACOSX/ch12/section_1/._CashRegister.java.html ch12/section_1/CashRegisterTester.javach12/section_1/CashRegisterTester.java/** This program tests the CashRegister class. */ publicclassCashRegisterTester { publicstaticvoid main(String[] args) { CashRegister register1 =newCashRegister(); register1.addItem(1.95); register1.addItem(0.95); register1.addItem(2.50); Coin dol ...

ch12.DS_Store__MACOSXch12._.DS_Storech12section_1.D.docx

cravennichole326

Answer: Note: Provided code shows several bugs, hence I implemented a separate code as per the given program specifications Program code: import java.util.Scanner; //declares fraction class class Fraction { //private data members for the class private int numerators,denominators; //default constructor public Fraction() { } //parameterised constructor for the class public Fraction(int numerators, int denominators) { //assigns numerator this.numerators = numerators; //checks the denominator if(denominators == 0) { System.out.println(\"denominator Shouldn\'t be ZERO \"); System.out.println(\"Program Exiting.....\"); System.exit(0); } this.denominators = denominators; } //parameterised constructor public Fraction(int numerators) { this.numerators = numerators; } //method TO string public String toString() { return \"\"+numerators+\" / \"+denominators; } //methods Equals() @Override public boolean equals(Object obj) { if (obj == null) { return false; } if (getClass() != obj.getClass()) { return false; } final Fraction other = (Fraction) obj; if (this.numerators != other.numerators) { return false; } if (this.denominators != other.denominators) { return false; } return true; } //method GCD declaration public int GCD(int a, int b) { //declares local variables int x = 0, GCD = 0; int max = a > b ? a : b; int min = a < b ? a : b; for(int i = 1; i <= min; i++) { x = max * i; if(x % min == 0) { GCD = x; break; } } //returns GCD return GCD; } //Method to read public static Fraction read() { Scanner sc1 = new Scanner(System.in); System.out.print(\"Enter Fraction numerators : \"); int num1 = sc1.nextInt(); System.out.print(\"Enter Fraction denominators : \"); int den1 = sc1.nextInt(); System.out.println(); Fraction f1 = new Fraction(num1,den1); return f1; } //Method definition to add() public Fraction add(Fraction other1) { int GCD = GCD(this.denominators,other.denominators); int numb1 = this.numerators * (GCD/this.denominators); int numb2 = other1.numerators *(GCD/other.denominators); int num1 = 0, den1 = 0; num1 = numb1 + numb2; den1 = GCD; return new Fraction(num1,den1); } //method definition to add() public Fraction add(int temp1) { //defines the number variable int num1 = this.denominators * temp1 + this.numerators; return new Fraction(num1,this.denominators); } //method definition to subract public Fraction subtract(Fraction other1) { int GCD = GCD(this.denominators,other.denominators); int numb1 = this.numerators *(GCD/this.denominators); int numb2 = other1.numerators *(GCD/other1.denominators); int num1 = 0, den1 = 0; num1 = numb1 - numb2; den1 = GCD; return new Fraction(num1,den1); } //Method definition to multiply public Fraction multiply(Fraction other1) { int num1 = 0, den1 = 0; num1 = this.numerators * other1.numerators; den1 = this.denominators * other1.denominators; return new Fraction(num1,den1); } //method definition to Multiply public Fraction multiply(int temp1) { int num 1= this.numerators * temp1; return new Fraction(num1,this.denomina.

AnswerNote Provided code shows several bugs, hence I implemented.pdf

Lecture4

Lecture4

Dcom vs. corba

We are happy to invite you to the Speakers’ Corner today, on Thursday May 29, from 18.30 till 19.30 at SkyPoint to meet Thomas Vervik, Head of Development Bipper Communications who will talk on “How to save money on QA - Dependency Injection and automated testing on Android” Thomas is Head of Development for Bipper Communications, and has been managing the company's team in Kiev since February 2012. Originally a seasoned Java server backend/frontend developer, he has the last two years started mobile development, first with HTML 5 and later Android. Mobile development has since its birth around 2008 gone from simple apps to more complex enterprise similar software. The increase in size and complexity yields the need for structuring the code differently in order to handle the new complexity. The tools used to handle this complexity has been applied to server side development for years, but mobile development has been lagging behind. But not anymore. New frameworks built on proven paradigms are emerging, and in this Speakers Corner we will introduce Dependency Injection for Android, the motivation for its use, and one of the implementations - Dagger. Dependency Injection has several advantages, but in this presentation we will focus on how it enables to write proper automated tests.

Dependency Injection for Android @ Ciklum speakers corner Kiev 29. May 2014

First Tuesday Bergen

Dependency Injection for Android

First Tuesday Bergen

Not so long ago Microsoft announced a new language trageting on front-end developers. Everybody's reaction was like: Why?!! Is it just Microsoft darting back to Google?! So, why a new language? JavaScript has its bad parts. Mostly you can avoid them or workaraund. You can emulate class-based OOP style, modules, scoping and even run-time typing. But that is doomed to be clumsy. That's not in the language design. Google has pointed out these flaws, provided a new language and failed. Will the story of TypeScript be any different?

TypeScript Introduction

Dmitry Sheiko

Test Engine

guestcdaa2dc

Jersey Guice AOP

Domenico Briganti

Creating a Facebook Clone - Part XX.pdf

ShaiAlmog1

C++ via C#

Egor Bogatov

C++ Programming - 9th Study

Chris Ohk

//operating system linux,ubuntu,Mac /*********************GeometricObject.java**********************/ public abstract class GeometricObject { private String color = \"white\"; private boolean filled; // default constructure public GeometricObject() { super(); // TODO Auto-generated constructor stub } // construct a Geometric Object // parameterized constructure public GeometricObject(String color, boolean filled) { this.color = color; this.filled = filled; } /** Getter method for color */ public String getColor() { return color; } /** Setter method for color */ public void setColor(String color) { this.color = color; } /** * Getter method for filled. Since filled is boolean, so the gret method * name is isFilled */ public boolean isFilled() { return filled; } /** Setter method for filled */ public void setFilled(boolean filled) { this.filled = filled; } /** Abstract method for FindArea */ public abstract double findArea(); /** Abstract method for findPerimeter */ public abstract double findPerimeter(); } /*****************************Octagon.java**************/ public class Octagon extends GeometricObject implements Cloneable, Comparable { private double side; /** construct a Octagon with specified side */ public Octagon(double side) { super(); this.side = side; } /** Implement the abstract method findArea in GeometricObject */ @Override public double findArea() { double area = (2 + 4 / Math.sqrt(2)) * side * side; return area; } /** Implement the abstract method findArea in findPerimeter */ @Override public double findPerimeter() { double perimeter = 8 * side; return perimeter; } /** Implement the compareTo method in Comparable interface */ @Override public int compareTo(Object o) { // TODO Auto-generated method stub return 0; } public Object clone() throws CloneNotSupportedException { return super.clone(); } } /*******************App.java*******************/ public class App { public static void main(String[] args) { Octagon a1 = new Octagon(5);//creating object of octagon System.out.println(\"Area of a1 is \" + a1.findArea()); System.out.println(\"Perimeter of a1 is \" + a1.findPerimeter()); Object a2; try { a2 = a1.clone(); String result = (a1.compareTo(a2) == 0) ? \"a1 and its clone a2 have the same area\" : \"a1 and its clone a2 have different areas\"; System.out.println(\"Compare a1 and its clone a2:\ \\t \" + result); System.out.println(\"Hashcode of a1: \" + a1.hashCode()); System.out.println(\"Hashcode of a2: \" + a2.hashCode()); System.out.println(\"Displaying a1: \" + a1); System.out.println(\"Displaying a2: \" + a2); } catch (CloneNotSupportedException e) { e.printStackTrace(); } } } /*****************output***************/ gopal@gopal:~/Desktop/chegg$ javac GeometricObject.java gopal@gopal:~/Desktop/chegg$ javac Octagon.java gopal@gopal:~/Desktop/chegg$ javac App.java gopal@gopal:~/Desktop/chegg$ java App Area of a1 is 120.71067811865476 Perimeter of a1 is 40.0 Compare a1 and its clone a2: a1 and its clone a2 have the same area .

operating system linux,ubuntu,Mac Geometri.pdf

aquadreammail

OOP Lab Report.docx

ArafatSahinAfridi

Test Engine

guestcdaa2dc

Static Analysis in IDEA

HamletDRC

Similar to Polygon .java package chegg2;public class Polygon { Var.pdf (20)

C# 6.0 - April 2014 preview

Design patterns

Manual tecnic sergi_subirats

ch12.DS_Store__MACOSXch12._.DS_Storech12section_1.D.docx

AnswerNote Provided code shows several bugs, hence I implemented.pdf

Lecture4

Dcom vs. corba

Dependency Injection for Android @ Ciklum speakers corner Kiev 29. May 2014

Dependency Injection for Android

TypeScript Introduction

Test Engine

Jersey Guice AOP

Creating a Facebook Clone - Part XX.pdf

C++ via C#

C++ Programming - 9th Study

operating system linux,ubuntu,Mac Geometri.pdf

OOP Lab Report.docx

Test Engine

Static Analysis in IDEA

More from aplolomedicalstoremr

You have to leave solids and liquids out of the equation. This leaves only product B for the product, nothing for the reactants. Initially there was no product B. At equilibrium: you determine the molarity by multiplying 2.5% by (0.5M/10L)= .00125 = which rounds to answer E) 1.3e-3 it was a trick question. Solution You have to leave solids and liquids out of the equation. This leaves only product B for the product, nothing for the reactants. Initially there was no product B. At equilibrium: you determine the molarity by multiplying 2.5% by (0.5M/10L)= .00125 = which rounds to answer E) 1.3e-3 it was a trick question..

You have to leave solids and liquids out of the equation. This lea.pdf

aplolomedicalstoremr

Tungsten is a body centered cubic latticeSolutionTungsten is a.pdf

aplolomedicalstoremr

This is the final code which meets your requirement.Than you Card.java import java.util.Random; public class Card { //declaring instance variables private String suit; private int face_value; public static int count=52; //Creating an instance of Random class reference Random rand; //Default Constructor public Card() { super(); //Passing random class object to the Random class reference rand = new Random(); } //Getters and setters public String getSuit() { return suit; } public void setSuit(String suit) { this.suit = suit; } public int getFace_value() { return face_value; } public void setFace_value(int face_value) { this.face_value = face_value; } public int getCount() { return count; } //This shuffle() method will shuffle the deck public void shuffle() { //Picking a card from the deck randomly and find its face value and suit this.face_value = 1 + rand.nextInt((9) + 1); int suit_random_value = 1 + rand.nextInt((3) + 1); if(suit_random_value==1) { this.suit=\"Clubs\"; } else if(suit_random_value==2) { this.suit=\"hearts\"; } else if(suit_random_value==3) { this.suit=\"Spades\"; } else if(suit_random_value==4) { this.suit=\"diamonds\"; } this.count=count-1; } } ________________________________________________________________________ DriverClass.java public class DriverClass { public static void main(String[] args) { //creating an array which can hold 52 Card class Objects Card c[]=new Card[52]; //Creating 52 card class objects and storing them into an array for(int i=0;i<52;i++) { //Creating Card class Object c[i]=new Card(); } //Displaying each card face value and its suit. for(int i=0;i<52;i++) { //Shuffling the deck before every card picking from the deck c[i].shuffle(); //Displaying randomly picked card face value and its suit System.out.println(c[i].getFace_value()+\" of \"+c[i].getSuit()+\" Cards remaining \"+c[i].getCount()); } } } _________________________________________________________________________ Output: 8 of diamonds Cards remaining 51 4 of Clubs Cards remaining 50 9 of Clubs Cards remaining 49 7 of Spades Cards remaining 48 9 of diamonds Cards remaining 47 7 of diamonds Cards remaining 46 4 of diamonds Cards remaining 45 9 of Clubs Cards remaining 44 5 of hearts Cards remaining 43 7 of Spades Cards remaining 42 10 of Clubs Cards remaining 41 7 of diamonds Cards remaining 40 8 of diamonds Cards remaining 39 6 of hearts Cards remaining 38 4 of hearts Cards remaining 37 6 of Spades Cards remaining 36 4 of Clubs Cards remaining 35 3 of diamonds Cards remaining 34 9 of diamonds Cards remaining 33 3 of diamonds Cards remaining 32 5 of Spades Cards remaining 31 4 of Clubs Cards remaining 30 3 of Spades Cards remaining 29 6 of diamonds Cards remaining 28 3 of hearts Cards remaining 27 9 of hearts Cards remaining 26 7 of hearts Cards remaining 25 3 of hearts Cards remaining 24 10 of Clubs Cards remaining 23 2 of hearts Cards remaining 22 9 of Clubs Cards remaining 21 8 of diamonds Cards remaining 20 8 of Clubs Cards remaining 19 2 of h.

This is the final code which meets your requirement.Than youCard.j.pdf

aplolomedicalstoremr

Statistics is the mathematical science involving the collection, analysis and interpretation of data. A number of specialties have evolved to apply statistical theory and methods to various disciplines. Certain topics have \"statistical\" in their name but relate to manipulations of probability distributions rather than to statistical analysis. · Actuarial science is the discipline that applies mathematical and statistical methods to assess risk in the insurance and financeindustries. · Astrostatistics is the discipline that applies statistical analysis to the understanding of astronomical data. · Biostatistics is a branch of biology that studies biological phenomena and observations by means of statistical analysis, and includes medical statistics. · Business analytics is a rapidly developing business process that applies statistical methods to data sets (often very large) to develop new insights and understanding of business performance & opportunities · Chemometrics is the science of relating measurements made on a chemical system or process to the state of the system via application of mathematical or statistical methods. · Demography is the statistical study of all populations. It can be a very general science that can be applied to any kind of dynamic population, that is, one that changes over time or space. · Econometrics is a branch of economics that applies statistical methods to the empirical study of economic theories and relationships. · Environmental statistics is the application of statistical methods to environmental science. Weather, climate, air and water quality are included, as are studies of plant and animal populations. · Epidemiology is the study of factors affecting the health and illness of populations, and serves as the foundation and logic of interventions made in the interest of public health and preventive medicine. · Geostatistics is a branch of geography that deals with the analysis of data from disciplines such as petroleum geology, hydrogeology, hydrology, meteorology,oceanography, geochemistry, geography. · Machine Learning · Operations research (or Operational Research) is an interdisciplinary branch of applied mathematics and formal science that uses methods such as mathematical modeling, statistics, and algorithms to arrive at optimal or near optimal solutions to complex problems. · Population ecology is a sub-field of ecology that deals with the dynamics of species populations and how these populations interact with the environment. · Psychometric is the theory and technique of educational and psychological measurement of knowledge, abilities, attitudes, and personality traits. · Quality control reviews the factors involved in manufacturing and production; it can make use of statistical sampling of product items to aid decisions in process control or in accepting deliveries. · Quantitative psychology is the science of statistically explaining and changing mental processes and behaviors in humans. · Reliabi.

Statistics is the mathematical science involving the collection, ana.pdf

aplolomedicalstoremr

Secondary phloem Apples (Malus communis, M. pumila, & M. sylvestris), pears (Pyrus communis) and quince (Cydonia oblonga) belong to the rose family (Rosaceae), and include literally hundreds of cultivated varieties. In the apple, the original ancestral species is obscured by so many cultivated variations throughout the centuries that some authors lump them all into one species, Malus domestica. They all originated in western Asia (or Eurasia) and are characterized by fleshy fruits called pomes. In the pome, a thick, fleshy hypanthium layer (also called the floral cup or calyx tube) surrounds (and is fused with) the seed-bearing ovary or core. The sepals, petals and stamens arise from the rim of the hypanthium. Since the ovary is situated below the attachment of the sepals, petals and stamens, it is termed \"inferior\" in technical plant taxonomy books. The fleshy hypanthium of a rose (Rosa) surrounds a cluster of small one-seeded achenes. Since the achenes represent separate ripened ovaries all derived from a single flower, the entire structure (called a rose hip) can be considered an aggregate fruit or etaerio. Rose hips are eaten raw and are ground up as a supplemental source of vitamin C (ascorbic acid). Bing cherries (Prunus avium) showing the long stalk (pedicel) and fleshy drupe containng a hard, stony, seed-bearing endocarp. Sweet cherries such as these are usually considered to belong to P. avium, while sour cherries belong to the P. cerasus group. There are literally hundreds of varieties of cherries. Maraschino cherries are made from sweet cherries which have been bleached, deseeded, and soaked in a sugar solution to which red food coloring and flavoring have been added. Maraschino cherries are commonly covered with chocolate, placed as a decorative topping in ice cream sundies, and in mixed drinks. The raspberry or hindberry is the edible fruit of a multitude of plant species in the genus Rubus, most of which are in the subgenusIdaeobatus; the name also applies to these plants themselves. Raspberries are perennial, with woody stems. Raspberries are grown for the fresh fruit market and for commercial processing into individually quick frozen (IQF) fruit, purée, juice, or as dried fruit used in a variety of grocery products. Traditionally, raspberries were a mid-summer crop, but with new technology, cultivars, and transportation, they can now be obtained year-round. Raspberries need ample sun and water for optimal development. Raspberries thrive in well-drained soil with a pH of between 6 and 7 with ample organic matter to assist in retaining water. While moisture is essential, wet and heavy soils or excess irrigation can bring on Phytophthora root rot which is one of the most serious pest problems facing red raspberry. As a cultivated plant in moist temperate regions, it is easy to grow and has a tendency to spread unless pruned. Escaped raspberries frequently appear as garden weeds, spread by seeds found in bird droppings. An indiv.

Secondary phloemApples (Malus communis, M. pumila, & M. sylvestr.pdf

aplolomedicalstoremr

probability that the trajectory falls between 1.2 and 1.4 =(1.4-1.2).pdf

aplolomedicalstoremr

Output: Fibonacci till 20: 0 1 1 2 3 5 8 13 21 34 55 89 144 233 377 610 987 1597 2584 4181 Program: import java.util.*; import java.lang.*; import java.io.*; public class Main { public static void main (String[] args) throws java.lang.Exception { final int LIMIT = 20; int[] fib = new int[LIMIT]; // init fib 0 and first val fib[0] = 0; fib[1] = 1; for (int i = 2; i < LIMIT; ++i) { fib[i] = fib[i - 1] + fib[i - 2]; } System.out.println(\"Fibonacci till \" + LIMIT + \":\"); for (int i = 0; i < LIMIT; ++i) { System.out.println(fib[i]); } } } Iterative solution is more efficient than recursive. The iterative solution do not compute the same values again and again as recursive solution. Also because we are not using recursion the os stack is not used hence computation is faster. Solution Output: Fibonacci till 20: 0 1 1 2 3 5 8 13 21 34 55 89 144 233 377 610 987 1597 2584 4181 Program: import java.util.*; import java.lang.*; import java.io.*; public class Main { public static void main (String[] args) throws java.lang.Exception { final int LIMIT = 20; int[] fib = new int[LIMIT]; // init fib 0 and first val fib[0] = 0; fib[1] = 1; for (int i = 2; i < LIMIT; ++i) { fib[i] = fib[i - 1] + fib[i - 2]; } System.out.println(\"Fibonacci till \" + LIMIT + \":\"); for (int i = 0; i < LIMIT; ++i) { System.out.println(fib[i]); } } } Iterative solution is more efficient than recursive. The iterative solution do not compute the same values again and again as recursive solution. Also because we are not using recursion the os stack is not used hence computation is faster..

OutputFibonacci till 20 0 1 1 2 3 5 8 13 21 .pdf

aplolomedicalstoremr

Matter is made up of electrically charge particle but the Constituents of objects have opposite charges, adding up to electric neutrality overall. Think of it in this way that two bring two nucleus very close together we need a lot of energy because when we talk about nucleus it\'s only the +ve(protons) charge we are talking about. That is why the fusion of two atoms is very tough task. But in case of atoms or molecules that are the smallest entity of matter that can individually exist; it always contain equal number of proton and electron and hence are electrically neutral on a whole. Atom being neutral on whole there no force on other atoms Solution Matter is made up of electrically charge particle but the Constituents of objects have opposite charges, adding up to electric neutrality overall. Think of it in this way that two bring two nucleus very close together we need a lot of energy because when we talk about nucleus it\'s only the +ve(protons) charge we are talking about. That is why the fusion of two atoms is very tough task. But in case of atoms or molecules that are the smallest entity of matter that can individually exist; it always contain equal number of proton and electron and hence are electrically neutral on a whole. Atom being neutral on whole there no force on other atoms.

Matter is made up of electrically charge particle but the Constituen.pdf

aplolomedicalstoremr

it is a polynomial of degree 3Solutionit is a polynomial of de.pdf

aplolomedicalstoremr

JUnit is a Regression Testing Framework used by developers to implement unit testing in Java, and accelerate programming speed and increase the quality of code. JUnit Framework can be easily integrated with either of the following Features of JUnit Test Framework JUnit test framework provides the following important features Fixtures Fixtures is a fixed state of a set of objects used as a baseline for running tests. The purpose of a test fixture is to ensure that there is a well-known and fixed environment in which tests are run so that results are repeatable Test Suites A test suite bundles a few unit test cases and runs them together. In JUnit, both @RunWith and @Suite annotation are used to run the suite test. Test Runners Test runner is used for executing the test cases. Here is an example that assumes the test class TestJunit already exists. JUnit Classes JUnit classes are important classes, used in writing and testing JUnits. Some of the important classes are Assert Contains a set of assert methods. TestCase Contains a test case that defines the fixture to run multiple tests. TestResult Contains methods to collect the results of executing a test case. Solution JUnit is a Regression Testing Framework used by developers to implement unit testing in Java, and accelerate programming speed and increase the quality of code. JUnit Framework can be easily integrated with either of the following Features of JUnit Test Framework JUnit test framework provides the following important features Fixtures Fixtures is a fixed state of a set of objects used as a baseline for running tests. The purpose of a test fixture is to ensure that there is a well-known and fixed environment in which tests are run so that results are repeatable Test Suites A test suite bundles a few unit test cases and runs them together. In JUnit, both @RunWith and @Suite annotation are used to run the suite test. Test Runners Test runner is used for executing the test cases. Here is an example that assumes the test class TestJunit already exists. JUnit Classes JUnit classes are important classes, used in writing and testing JUnits. Some of the important classes are Assert Contains a set of assert methods. TestCase Contains a test case that defines the fixture to run multiple tests. TestResult Contains methods to collect the results of executing a test case..

JUnit is a Regression Testing Framework used by developers to implem.pdf

aplolomedicalstoremr

Intitially take a graph sheet and plot the points and the whole figure as it is. Next draw the velocity diagram.Due to technical issues, I am not able to upload the graphical representation. Apply corialis acceleration component at link 6. Solution Intitially take a graph sheet and plot the points and the whole figure as it is. Next draw the velocity diagram.Due to technical issues, I am not able to upload the graphical representation. Apply corialis acceleration component at link 6..

Intitially take a graph sheet and plot the points and the whole figu.pdf

aplolomedicalstoremr

Incapsula Enterprise is the best mitigation service provider with the gold award winner and the other two with silver and bronze award are F5 Silverline DDOS Protection and Arbor Cloud respectively With DDoS attacks growing in complexity and size daily, you need a DDoS protection service with a robust network and variety of mitigation techniques to thwart any attacks directed at your site. We found that Incapsula Enterprise, F5 Silverline DDoS Protection and Arbor Cloud offered the best protection. Incapsula’s growing global network and scrubbing capacities equip it with the size needed to prevent large-scale volumetric attacks,27 data centers are connected which are located all over the world, the service is prepared for even the most advanced DDoS attacks. In addition to enormous network capacity and a high number of data centers, Incapsula hosts a variety of mitigation techniques that intercept application layer, volumetric and protocol attacks. With the recent acquisition of Defense.net, F5 has adjusted its service to offer cloud-based mitigation technique, on-site and hybrid deployment methods,both hardware and the cloud is used, F5 Silverline Protection is equipped for sophisticated DDoS attacks. This service surpasses Incapsula in scrubbing capacity, it provides 2TB of bandwidth to filter, clean and remove infected traffic. While the service does not offer unlimited mitigation, this protection service can be used on-demand or always on, customizing it to fit the needs of any company. Third one comes Arbor Cloud which offers a large network and scrubbing capacity and have 1.14TB of bandwidth, this server prepare the system for specialised volumetric attacks.variety of protection techniques are provided by this service including IP blocking, rate limiting, automatic bot discernment and more. While the cloud-based mitigation techniques are impressive, Arbor is known for its hardware. The service is in a unique position, it\'s hardware is the challenge for it\'s competitors similar mitigation techniques is provided by all DDOS mitigation service providers to keep an eye on any attacks and constant monitoring, they differ in price, deployment methods and network size.It is not necessary that bigger mean better, the services that offer larger networks and more mitigation technologies allow for more customization that you employ the best protection service for your IT infrastructure. Solution Incapsula Enterprise is the best mitigation service provider with the gold award winner and the other two with silver and bronze award are F5 Silverline DDOS Protection and Arbor Cloud respectively With DDoS attacks growing in complexity and size daily, you need a DDoS protection service with a robust network and variety of mitigation techniques to thwart any attacks directed at your site. We found that Incapsula Enterprise, F5 Silverline DDoS Protection and Arbor Cloud offered the best protection. Incapsula’s growing global network and scrubbing capacit.

Incapsula Enterprise is the best mitigation service provider with th.pdf

aplolomedicalstoremr

Go with the most obvious one first... Carboxylic Acids: will have a really broad and large absorption range in the 3500-2500cm-1 area (aka. the \"valley of the acid\") as well as a carbonyl peak in the 1700cm-1 area. That would be spectrum 4. Alcohols:will also have a strong and broad absorption in the 3500-3000cm-1 region, but nowhere near as broad as the acid. It just looks like a really fat absorption line, rather than a well... Anyway, the characteristic spectrum for the alcohol is spectrum 5. Amines:lucky for you, the amine given in this question is a primary amine. There\'s going to be two N-H stretching peaks in the 3300cm-1 region. There\'s also no carbonyl on the structure given, so there should be no C=O stretching at 1700cm-1.This is spectrum 3. Don\'t worry about the small absorption in the 1500-1700cm-1 area. Now for the fine details... The ester and aldehyde spectra are pretty similar, but aldehydes absorb at around 2750cm-1. It\'s not totally clear on the spectra in the question but it looks like there\'s a 2750cm-1 absorption in spectrum 2, so I\'d say that spectrum 2 is the aldehyde, and spectrum 1 is the ester. Summary: Spectrum 1 = structure B Spectrum 2 = structure E Spectrum 3 = structure C Spectrum 4 = structure D Spectrum 5 = structure A Solution Go with the most obvious one first... Carboxylic Acids: will have a really broad and large absorption range in the 3500-2500cm-1 area (aka. the \"valley of the acid\") as well as a carbonyl peak in the 1700cm-1 area. That would be spectrum 4. Alcohols:will also have a strong and broad absorption in the 3500-3000cm-1 region, but nowhere near as broad as the acid. It just looks like a really fat absorption line, rather than a well... Anyway, the characteristic spectrum for the alcohol is spectrum 5. Amines:lucky for you, the amine given in this question is a primary amine. There\'s going to be two N-H stretching peaks in the 3300cm-1 region. There\'s also no carbonyl on the structure given, so there should be no C=O stretching at 1700cm-1.This is spectrum 3. Don\'t worry about the small absorption in the 1500-1700cm-1 area. Now for the fine details... The ester and aldehyde spectra are pretty similar, but aldehydes absorb at around 2750cm-1. It\'s not totally clear on the spectra in the question but it looks like there\'s a 2750cm-1 absorption in spectrum 2, so I\'d say that spectrum 2 is the aldehyde, and spectrum 1 is the ester. Summary: Spectrum 1 = structure B Spectrum 2 = structure E Spectrum 3 = structure C Spectrum 4 = structure D Spectrum 5 = structure A.

Go with the most obvious one first...Carboxylic Acids will have a.pdf

aplolomedicalstoremr

Flexible benefit plans gives employees a choice between qualified benefits (non taxable) and cash. An example of qualified benefits is medical plans. Flexible benefit plans includes health insurance and retirement benefits. The 2 main types of flexible benefit plans are cafeteria plans and flexible spending accounts. Under the cafeteria plan, employees have the option of choosing from several different benefit packages. Employees can select the option of receiving some or all of the employer\'s nontaxable benefits or receiving cash or other taxable benefits. The benefits offered under cafeteria plans are health and group insurance, medical reimbursement schemes for non-insured expenses and vacation days. Flexible spending accounts (FSA) is another prevalant flexible benefit plan. FSA is a tax deferred savings account. These accounts are formed by employers and helps the employee in meeting certain medical expenses that are not a part of employer\'s insurance plan. Solution Flexible benefit plans gives employees a choice between qualified benefits (non taxable) and cash. An example of qualified benefits is medical plans. Flexible benefit plans includes health insurance and retirement benefits. The 2 main types of flexible benefit plans are cafeteria plans and flexible spending accounts. Under the cafeteria plan, employees have the option of choosing from several different benefit packages. Employees can select the option of receiving some or all of the employer\'s nontaxable benefits or receiving cash or other taxable benefits. The benefits offered under cafeteria plans are health and group insurance, medical reimbursement schemes for non-insured expenses and vacation days. Flexible spending accounts (FSA) is another prevalant flexible benefit plan. FSA is a tax deferred savings account. These accounts are formed by employers and helps the employee in meeting certain medical expenses that are not a part of employer\'s insurance plan..

Flexible benefit plans gives employees a choice between qualified be.pdf

aplolomedicalstoremr

f(x) = cos(x)Solutionf(x) = cos(x).pdf

aplolomedicalstoremr

Environment: Let assume the environment is a grid of colored tiles(WHITE,BLUE,GREEN,BLACK,YELLOW).Robot is standing on a tile.Every tile has a(X,Y) Position We use a function getTileColor(x,y) to know color of current tile(x,y position). ALGORITHM: TRESUREHUNT(x,y) 1. color=getColor(x,y) 2. IF color=YELLOW 3. Return \"tiles\"+x+y+\" Is a tresure\" 4. ELSE IF color=WHITE 5. TRESUREHUNT(x,y-1) // move to front tile by decrementing y by 1 6 ELSE IF color=BLUE 7. TRESUREHUNT(x-1,y) // move to left bydecrementing x by 1 8. ELSE IF color=GREEN 9. TRESUREHUNT(x+1,y) // move to right tile by incrementing x by 1 10. ELSE IF color=BLACK 11. TRESUREHUNT(x,y+2) // move to front tile by incrementint y by 2 12. ELSE 13. Return \"Unsucessfull\" 12.END iF C++ CODE //for simplicity i represent entite grid in a 2;D array .Each cell is viewed as a tile.It contains arbitary color values,0-BLACK //1-BLUE,2;GREEN,14;YELLOW,15-WHITE //accordingly the x,y value is changed. if current cell(tile)=15(WHITE) robot moves to front tile. // so x=x-1 and y=y #include #include void tresurehunt(int x,int y); int grid[][7]={ {1, 1, 1, 14,2, 0, 15}, {0, 1, 1, 1, 0, 0, 2}, {2, 2 ,1, 0, 15,14,1}, {15,15,14,0, 1, 2, 1}, {15,0, 0, 1, 2, 2, 14}, {14,14,14,15,0, 2, 2}, {15,15,15,1, 1, 2, 1}}; int main() { tresurehunt(4,4); return 0; } void tresurehunt(int x,int y) { //int color=getpixel(x,y); int color=grid[x][y]; if(color==YELLOW) { cout<<\"Tresure is in:\"< Solution Environment: Let assume the environment is a grid of colored tiles(WHITE,BLUE,GREEN,BLACK,YELLOW).Robot is standing on a tile.Every tile has a(X,Y) Position We use a function getTileColor(x,y) to know color of current tile(x,y position). ALGORITHM: TRESUREHUNT(x,y) 1. color=getColor(x,y) 2. IF color=YELLOW 3. Return \"tiles\"+x+y+\" Is a tresure\" 4. ELSE IF color=WHITE 5. TRESUREHUNT(x,y-1) // move to front tile by decrementing y by 1 6 ELSE IF color=BLUE 7. TRESUREHUNT(x-1,y) // move to left bydecrementing x by 1 8. ELSE IF color=GREEN 9. TRESUREHUNT(x+1,y) // move to right tile by incrementing x by 1 10. ELSE IF color=BLACK 11. TRESUREHUNT(x,y+2) // move to front tile by incrementint y by 2 12. ELSE 13. Return \"Unsucessfull\" 12.END iF C++ CODE //for simplicity i represent entite grid in a 2;D array .Each cell is viewed as a tile.It contains arbitary color values,0-BLACK //1-BLUE,2;GREEN,14;YELLOW,15-WHITE //accordingly the x,y value is changed. if current cell(tile)=15(WHITE) robot moves to front tile. // so x=x-1 and y=y #include #include void tresurehunt(int x,int y); int grid[][7]={ {1, 1, 1, 14,2, 0, 15}, {0, 1, 1, 1, 0, 0, 2}, {2, 2 ,1, 0, 15,14,1}, {15,15,14,0, 1, 2, 1}, {15,0, 0, 1, 2, 2, 14}, {14,14,14,15,0, 2, 2}, {15,15,15,1, 1, 2, 1}}; int main() { tresurehunt(4,4); return 0; } void tresurehunt(int x,int y) { //int color=getpixel(x,y); int color=grid[x][y]; if(color==YELLOW) { cout<<\"Tresure is in:\"<.

EnvironmentLet assume the environment is a grid of colored tiles(.pdf

aplolomedicalstoremr

Classification of organisms is based upon a number of physical and physiological features. The structure and organization of reproductive organs remains in important feature usually used to distinguish organisms. Some of the features can be discussed as below: 1. Fruiting body: A very broad classification can be made on the basis whether the fruiting body is present or not. Presence of a fleshy or modified cover around the seed is a characteristic feature of angiosperms whereas a naked seed located directly above a vegetative structure of a plant is a feature of gymnosperms. 2. Spores sacs: Spore releasing sacs are characteristic features found on the lower scales of the leaf blades of lower and higher ferns. Their arrangement and mode of release determines the nature, frequency and ease of sexual reproduction in these lower plants. 3. Pollens: Higher plants, including both angiosperms and gymnosperms utilize pollen grains for sexual reproduction. The mode of transfer of pollen determines the geographical range of pollination in plants. Sulphur shower is a critical example for sexual reproduction in pines (gymnosperms) which distinguishes them from other trees. 4. Sporocarp: A sporocarp or a fruiting body is a bulging of the vegetative extension from the main structure of a lower fungi which contains a group of cells which either follow meiotic division or mitotic division and serve as the reproductive structures. Their growth and nature can be monitored microscopically and the fungus can be thus classified appropriately. Some algae also contain a unique localization and arrangement of haploid cells called spores which can be present in singles or doublets and thus represent a very unique discrimination from other organisms. These, these set of information provide an insight into usability of features of a reproductive structure for classification of organisms. Solution Classification of organisms is based upon a number of physical and physiological features. The structure and organization of reproductive organs remains in important feature usually used to distinguish organisms. Some of the features can be discussed as below: 1. Fruiting body: A very broad classification can be made on the basis whether the fruiting body is present or not. Presence of a fleshy or modified cover around the seed is a characteristic feature of angiosperms whereas a naked seed located directly above a vegetative structure of a plant is a feature of gymnosperms. 2. Spores sacs: Spore releasing sacs are characteristic features found on the lower scales of the leaf blades of lower and higher ferns. Their arrangement and mode of release determines the nature, frequency and ease of sexual reproduction in these lower plants. 3. Pollens: Higher plants, including both angiosperms and gymnosperms utilize pollen grains for sexual reproduction. The mode of transfer of pollen determines the geographical range of pollination in plants. Sulphur shower is a critical example for.

Classification of organisms is based upon a number of physical and p.pdf

aplolomedicalstoremr

Assets=Liabilities+Paid in capital+Retained earnings1..pdf

aplolomedicalstoremr

Hypothesis Test for population variance If we have a sample fro.pdf

aplolomedicalstoremr

ANSWER: Fundamental configurations of Windows printer Deployments: The Following sections describe four fundamental configuraions that are the basis of most Windows Printer Deployments 1.Direct Printing 2.Locally Attached printer Sharing 3.Network-attached Printing 4.Network-Attached printer sharing you can scale these configurations up to accommodate a network of virtually any size. 1.DIRECT PRINTING: The simplest print architecture consists of one print device connected to one computer, also known as a locally attached print device, as shown in Figure 2-13. When you connect a print device directly to a Windows Server 2012 R2 computer and print from an application running on that system, the computer supplies the printer, printer driver, and print server functions. 2.LOCALLY ATTACHED PRINTER SHARING: In addition to printing from an application running on that computer, you can also share the printer (and the print device) with other users on the same network. In this arrangement, the computer with the locally attached print device functions as a print server. Figure 2-14 shows the other computers on the network, which are known as the print clients. In the default Windows Server 2012 R2 printer-sharing configuration, each client uses its own printer and printer driver. As before, the application running on the client computer sends the print job to the printer and the printer driver renders the job, based on the capabilities of the print device. The main advantage of this printing arrangement is that multiple users, located anywhere on the network, can send jobs to a single print device connected to a computer functioning as a print server. The downside is that processing the print jobs for many users can impose a significant burden on the print server. Although any Windows computer can function as a print server, you should use a workstation for this purpose only when you have no more than a handful of print clients to support or you have a very light printing volume. 3.NETWORK-ATTACHED PRINTING: The printing solutions discussed thus far involve print devices connected directly to a computer using a USB or other port. Print devices do not necessarily have to be attached to computers, however. You can connect a print device directly to the network instead. Many print device models are equipped with network interface adapters, enabling you to attach a standard network cable. Some print devices have expansion slots into which you can install a network printing adapter you have purchased separately. Finally, for print devices with no networking capabilities, standalone network print servers are available, which connect to the network and enable you to attach one or more print devices. Print devices so equipped have their own IP addresses and typically have an embedded web-based configuration interface. With network-attached print devices, the primary deployment decision the administrator must make is to decide which computer will function as th.

ANSWERFundamental configurations of Windows printer Deployments.pdf

aplolomedicalstoremr

More from aplolomedicalstoremr (20)

You have to leave solids and liquids out of the equation. This lea.pdf

Tungsten is a body centered cubic latticeSolutionTungsten is a.pdf

This is the final code which meets your requirement.Than youCard.j.pdf

Statistics is the mathematical science involving the collection, ana.pdf

Secondary phloemApples (Malus communis, M. pumila, & M. sylvestr.pdf

probability that the trajectory falls between 1.2 and 1.4 =(1.4-1.2).pdf

OutputFibonacci till 20 0 1 1 2 3 5 8 13 21 .pdf

Matter is made up of electrically charge particle but the Constituen.pdf

it is a polynomial of degree 3Solutionit is a polynomial of de.pdf

JUnit is a Regression Testing Framework used by developers to implem.pdf

Intitially take a graph sheet and plot the points and the whole figu.pdf

Incapsula Enterprise is the best mitigation service provider with th.pdf

Go with the most obvious one first...Carboxylic Acids will have a.pdf

Flexible benefit plans gives employees a choice between qualified be.pdf

f(x) = cos(x)Solutionf(x) = cos(x).pdf

EnvironmentLet assume the environment is a grid of colored tiles(.pdf

Classification of organisms is based upon a number of physical and p.pdf

Assets=Liabilities+Paid in capital+Retained earnings1..pdf

Hypothesis Test for population variance If we have a sample fro.pdf

ANSWERFundamental configurations of Windows printer Deployments.pdf

Recently uploaded

An overview of the various scriptures in Hinduism

Dabee Kamal

Major project report on Tata Motors and its marketing strategies

AmanpreetKaur157993

How To Create Editable Tree View in Odoo 17

Celine George

ĐỀ THAM KHẢO KÌ THI TUYỂN SINH VÀO LỚP 10 MÔN TIẾNG ANH FORM 50 CÂU TRẮC NGHI...

Nguyen Thanh Tu Collection

When Quality Assurance Meets Innovation in Higher Education - Report launch w...

Gary Wood

24 ĐỀ THAM KHẢO KÌ THI TUYỂN SINH VÀO LỚP 10 MÔN TIẾNG ANH SỞ GIÁO DỤC HẢI DƯ...

Nguyen Thanh Tu Collection

UChicago CMSC 23320 - The Best Commit Messages of 2024

Borja Sotomayor

Mattingly "AI and Prompt Design: LLMs with NER"

National Information Standards Organization (NISO)

Photos from our Spring Gala 2024. Thank you for making our 2024 Spring Gala unforgettable! Whether you attended or supported us with a donation, we extend our heartfelt thanks for celebrating School-Community Partnerships alongside ExpandED Schools. Special appreciation to our honorees, Rachel Skaistis and Cravath, Swaine, & Moore LLP, for their unwavering support in advancing educational equity. Your contributions have profoundly impacted countless young New Yorkers, and we’re proud to have you as part of our community. Our gratitude also extends to our Board of Directors, sponsors, city partners, community-based organizations, and the inspiring young people who joined us. Your support fuels our mission, and we’re endlessly thankful for your dedication. While we celebrate our gala’s success, our work continues. As you view the evening’s highlights, consider how you can further empower young New Yorkers and educators with your donation, no matter the size. Donate today: https://www.expandedschools.org/support-our-work/donate/

Spring gala 2024 photo slideshow - Celebrating School-Community Partnerships

expandedwebsite

AIM of Education-Teachers Training-2024.ppt

Nishitharanjan Rout

diagnosting testing bsc 2nd sem.pptx....

Ritu480198

Transparency, Recognition and the role of eSealing - Ildiko Mazar and Koen No...

EADTU

Andreas Schleicher presents at the launch of What does child empowerment mean...

EduSkills OECD

Observing-Correct-Grammar-in-Making-Definitions.pptx

AdelaideRefugio

Rich Dad Poor Dad ( PDFDrive.com )--.pdf

Jerry Chew

How to Manage Website in Odoo 17 Studio App.pptx

Celine George

Mattingly "AI & Prompt Design: Named Entity Recognition"

National Information Standards Organization (NISO)

TỔNG HỢP HƠN 100 ĐỀ THI THỬ TỐT NGHIỆP THPT TOÁN 2024 - TỪ CÁC TRƯỜNG, TRƯỜNG...

Nguyen Thanh Tu Collection

Program code examples (known also as worked examples) play a crucial role in learning how to program. Instructors use examples extensively to demonstrate the semantics of the programming language being taught and to highlight the fundamental coding patterns. Programming textbooks allocate considerable space to present and explain code examples. To make the process of studying code examples more interactive, CS education researchers developed a range of tools to engage students in the study of code examples. These tools include codecasts (codemotion,codecast,elicasts), interactive example explorers (WebEx, PCEX), and tutoring systems (DeepTutor). An important component in all types of worked examples is code explanations associated with specific code lines or code chunks of an example. The explanations connect examples with general programming knowledge explaining the role and function of code fragments or their behavior. In textbooks, these explanations are usually presented as comments in the code or as explanations on the margins. The example explorer tools allow students to examine these explanations interactively. Tutoring systems, which engage students in explaining the code, use these model explanations to check student responses and provide scaffolding. In all these cases, to make a worked example re-usable beyond its presentation in a lecture, the explanations have to be authored by instructors or domain experts i.e., produced and integrated into a specific system. As the experience of the last 10 years demonstrated, these explanations are hard to obtain. Those already collected are usually “locked” in a specific example-focused system and can’t be reused. The purpose of this working group is to support broader re-used of worked examples augmented with explanations. Our current plan is to develop а standard approach to represent explained examples. This approach will enable an example created for any of the existing systems to be explored in a standard format and imported into any other example-focused system. We plan to follow a successful experience of the PEML working group focused on re-using programming exercises.

SPLICE Working Group:Reusable Code Examples

Peter Brusilovsky

The Story of Village Palampur Class 9 Free Study Material PDF

Vivekanand Anglo Vedic Academy

Recently uploaded (20)

An overview of the various scriptures in Hinduism

Major project report on Tata Motors and its marketing strategies

How To Create Editable Tree View in Odoo 17

ĐỀ THAM KHẢO KÌ THI TUYỂN SINH VÀO LỚP 10 MÔN TIẾNG ANH FORM 50 CÂU TRẮC NGHI...

When Quality Assurance Meets Innovation in Higher Education - Report launch w...

24 ĐỀ THAM KHẢO KÌ THI TUYỂN SINH VÀO LỚP 10 MÔN TIẾNG ANH SỞ GIÁO DỤC HẢI DƯ...

UChicago CMSC 23320 - The Best Commit Messages of 2024

Mattingly "AI and Prompt Design: LLMs with NER"

Spring gala 2024 photo slideshow - Celebrating School-Community Partnerships

AIM of Education-Teachers Training-2024.ppt

diagnosting testing bsc 2nd sem.pptx....

Transparency, Recognition and the role of eSealing - Ildiko Mazar and Koen No...

Andreas Schleicher presents at the launch of What does child empowerment mean...

Observing-Correct-Grammar-in-Making-Definitions.pptx

Rich Dad Poor Dad ( PDFDrive.com )--.pdf

How to Manage Website in Odoo 17 Studio App.pptx

Mattingly "AI & Prompt Design: Named Entity Recognition"

TỔNG HỢP HƠN 100 ĐỀ THI THỬ TỐT NGHIỆP THPT TOÁN 2024 - TỪ CÁC TRƯỜNG, TRƯỜNG...

SPLICE Working Group:Reusable Code Examples

The Story of Village Palampur Class 9 Free Study Material PDF

Polygon .java package chegg2;public class Polygon { Var.pdf

1. Polygon .java package chegg2; public class Polygon { // Variables private int numSides; private double sideLength; private double xCord; private double yCord; // Default Constructor public Polygon () { numSides = 3; sideLength = 5.0; xCord = 0.0; yCord = 0.0; } // Constructor public Polygon (int pSides, double numLength, double numXCord, double numYCord) { numSides = pSides; sideLength = numLength; xCord = numXCord; yCord = numYCord; } // Setter public void setSides(int mSides) { numSides = mSides;

2. System.out.println("setSides() results: "+this.numSides); } // Getter public int getSides() { return numSides; } } TestPolygon .java package chegg2; import java.util.Scanner; public class TestPolygon { public static void main(String[] args) { Polygon poly[] = new Polygon[2]; Polygon poly2 = new Polygon(); poly[0] = poly2; Scanner input = new Scanner(System.in); for(int i=1; i<2; i++){ Polygon obj = new Polygon(); System.out.println("New Polygons"); System.out.println("--------------------------------------------------"); System.out.print("Enter Number of Sides:"); obj.setSides(input.nextInt()); poly[i] = obj; } input.close(); System.out.println("Polygons");

3. System.out.println("--------------------------------------------------"); for(int i=0; i<2; i++) { poly[i].setSides(poly[i].getSides()); } } } Output: run: New Polygons -------------------------------------------------- Enter Number of Sides:9 setSides() results: 9 Polygons -------------------------------------------------- setSides() results: 3 setSides() results: 9 BUILD SUCCESSFUL (total time: 1 second) Solution Polygon .java package chegg2; public class Polygon { // Variables private int numSides; private double sideLength; private double xCord; private double yCord; // Default Constructor public Polygon () {

4. numSides = 3; sideLength = 5.0; xCord = 0.0; yCord = 0.0; } // Constructor public Polygon (int pSides, double numLength, double numXCord, double numYCord) { numSides = pSides; sideLength = numLength; xCord = numXCord; yCord = numYCord; } // Setter public void setSides(int mSides) { numSides = mSides; System.out.println("setSides() results: "+this.numSides); } // Getter public int getSides() { return numSides; } } TestPolygon .java package chegg2; import java.util.Scanner; public class TestPolygon { public static void main(String[] args) { Polygon poly[] = new Polygon[2];

5. Polygon poly2 = new Polygon(); poly[0] = poly2; Scanner input = new Scanner(System.in); for(int i=1; i<2; i++){ Polygon obj = new Polygon(); System.out.println("New Polygons"); System.out.println("--------------------------------------------------"); System.out.print("Enter Number of Sides:"); obj.setSides(input.nextInt()); poly[i] = obj; } input.close(); System.out.println("Polygons"); System.out.println("--------------------------------------------------"); for(int i=0; i<2; i++) { poly[i].setSides(poly[i].getSides()); } } } Output: run: New Polygons -------------------------------------------------- Enter Number of Sides:9 setSides() results: 9 Polygons

6. -------------------------------------------------- setSides() results: 3 setSides() results: 9 BUILD SUCCESSFUL (total time: 1 second)

Polygon .java package chegg2;public class Polygon { Var.pdf

Recommended

Recommended

More Related Content

Similar to Polygon .java package chegg2;public class Polygon { Var.pdf

Similar to Polygon .java package chegg2;public class Polygon { Var.pdf (20)

More from aplolomedicalstoremr

More from aplolomedicalstoremr (20)

Recently uploaded

Recently uploaded (20)

Polygon .java package chegg2;public class Polygon { Var.pdf