Hi, Please find mu codeimport java.util.Random;public class Sup.pdf
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Hi, Please find mu code: import java.util.Random; public class SuperDie { private int sides; private Random rand; public SuperDie(){ // Default constructor sides = 6; rand = new Random(); } // Constructor that lets user define number of sides n. public SuperDie(int n){ sides = n; rand = new Random(); } // Constructor that lets user define number of sides n AND provide their own Random object. public SuperDie(int n, Random r){ sides = n; rand = r; } public int getNumSides(){ return sides; } public void setNumSides(int n){ sides = n; } public int roll(){ return rand.nextInt(sides)+1; } } import java.util.*; class MainDie { public static void main (String[] args) { int value, sides; Random rand = new Random(); SuperDie d1 = new SuperDie(); SuperDie d2 = new SuperDie(20); SuperDie d3 = new SuperDie(10,rand); value = d1.roll(); System.out.println (\"die1 = \" + value); value = d2.roll(); System.out.println (\"die2 = \" + value); value = d3.roll(); System.out.println (\"die3 = \" + value); d1.setNumSides(8); System.out.println (\"die1 = \" + d1.getNumSides()); } } /* Sample Output: die1 = 5 die2 = 5 die3 = 2 die1 = 8 */ Solution Hi, Please find mu code: import java.util.Random; public class SuperDie { private int sides; private Random rand; public SuperDie(){ // Default constructor sides = 6; rand = new Random(); } // Constructor that lets user define number of sides n. public SuperDie(int n){ sides = n; rand = new Random(); } // Constructor that lets user define number of sides n AND provide their own Random object. public SuperDie(int n, Random r){ sides = n; rand = r; } public int getNumSides(){ return sides; } public void setNumSides(int n){ sides = n; } public int roll(){ return rand.nextInt(sides)+1; } } import java.util.*; class MainDie { public static void main (String[] args) { int value, sides; Random rand = new Random(); SuperDie d1 = new SuperDie(); SuperDie d2 = new SuperDie(20); SuperDie d3 = new SuperDie(10,rand); value = d1.roll(); System.out.println (\"die1 = \" + value); value = d2.roll(); System.out.println (\"die2 = \" + value); value = d3.roll(); System.out.println (\"die3 = \" + value); d1.setNumSides(8); System.out.println (\"die1 = \" + d1.getNumSides()); } } /* Sample Output: die1 = 5 die2 = 5 die3 = 2 die1 = 8 */.
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import java.util.*;
class MainDie {
public static void main (String[] args) {
int value, sides;
Random rand = new Random();
SuperDie d1 = new SuperDie();
SuperDie d2 = new SuperDie(20);
SuperDie d3 = new SuperDie(10,rand);
value = d1.roll();
System.out.println ("die1 = " + value);
value = d2.roll();
System.out.println ("die2 = " + value);
value = d3.roll();
System.out.println ("die3 = " + value);
d1.setNumSides(8);
System.out.println ("die1 = " + d1.getNumSides());
}
}
/*
Sample Output:
die1 = 5
die2 = 5
die3 = 2
die1 = 8
*/
Solution
Hi, Please find mu code:
import java.util.Random;](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
Recommended
Composite Pattern
The composite pattern allows objects to be composed into tree structures to represent part-whole hierarchies. It allows clients to treat individual objects and compositions uniformly. The example shows how shapes like lines and rectangles can be composed into pictures. Individual shapes are leaf classes while pictures are composite classes that can group shapes together and be treated the same way as individual shapes by clients.
Polygon .java package chegg2;public class Polygon { Var.pdf
Polygon .java
package chegg2;
public class Polygon {
// Variables
private int numSides;
private double sideLength;
private double xCord;
private double yCord;
// Default Constructor
public Polygon () {
numSides = 3;
sideLength = 5.0;
xCord = 0.0;
yCord = 0.0;
}
// Constructor
public Polygon (int pSides, double numLength, double numXCord, double numYCord) {
numSides = pSides;
sideLength = numLength;
xCord = numXCord;
yCord = numYCord;
}
// Setter
public void setSides(int mSides) {
numSides = mSides;
System.out.println(\"setSides() results: \"+this.numSides);
}
// Getter
public int getSides() {
return numSides;
}
}
TestPolygon .java
package chegg2;
import java.util.Scanner;
public class TestPolygon {
public static void main(String[] args) {
Polygon poly[] = new Polygon[2];
Polygon poly2 = new Polygon();
poly[0] = poly2;
Scanner input = new Scanner(System.in);
for(int i=1; i<2; i++){
Polygon obj = new Polygon();
System.out.println(\"New Polygons\");
System.out.println(\"--------------------------------------------------\");
System.out.print(\"Enter Number of Sides:\");
obj.setSides(input.nextInt());
poly[i] = obj;
} input.close();
System.out.println(\"Polygons\");
System.out.println(\"--------------------------------------------------\");
for(int i=0; i<2; i++) {
poly[i].setSides(poly[i].getSides());
}
}
}
Output:
run:
New Polygons
--------------------------------------------------
Enter Number of Sides:9
setSides() results: 9
Polygons
--------------------------------------------------
setSides() results: 3
setSides() results: 9
BUILD SUCCESSFUL (total time: 1 second)
Solution
Polygon .java
package chegg2;
public class Polygon {
// Variables
private int numSides;
private double sideLength;
private double xCord;
private double yCord;
// Default Constructor
public Polygon () {
numSides = 3;
sideLength = 5.0;
xCord = 0.0;
yCord = 0.0;
}
// Constructor
public Polygon (int pSides, double numLength, double numXCord, double numYCord) {
numSides = pSides;
sideLength = numLength;
xCord = numXCord;
yCord = numYCord;
}
// Setter
public void setSides(int mSides) {
numSides = mSides;
System.out.println(\"setSides() results: \"+this.numSides);
}
// Getter
public int getSides() {
return numSides;
}
}
TestPolygon .java
package chegg2;
import java.util.Scanner;
public class TestPolygon {
public static void main(String[] args) {
Polygon poly[] = new Polygon[2];
Polygon poly2 = new Polygon();
poly[0] = poly2;
Scanner input = new Scanner(System.in);
for(int i=1; i<2; i++){
Polygon obj = new Polygon();
System.out.println(\"New Polygons\");
System.out.println(\"--------------------------------------------------\");
System.out.print(\"Enter Number of Sides:\");
obj.setSides(input.nextInt());
poly[i] = obj;
} input.close();
System.out.println(\"Polygons\");
System.out.println(\"--------------------------------------------------\");
for(int i=0; i<2; i++) {
poly[i].setSides(poly[i].getSides());
}
}
}
Output:
run:
New Polygons
--------------------------------------------.
Need Help with this Java Assignment. Program should be done in JAVA .pdf
Need Help with this Java Assignment. Program should be done in JAVA please
Complete required scripts based on eclipse and troubleshoot the scripts until the tasks are done.
1. Implement a binary search tree (write the code for it), for a height of 2 or higher. Please show
the output if you can Thank you in advance!
Solution
I have compiled this code and checked for errors, worked fine.
Also after the code I have pasted the Output transcript to show what User Inputs I gave and what
all outputs I got.
// Java Program to Implement Binary Tree
import java.util.Scanner;
/* Define Class BinaryTreeNode */
class BinaryTreeNode
{
BinaryTreeNode left, right;
int data;
/* Constructor */
public BinaryTreeNode()
{
left = null;
right = null;
data = 0;
}
/* Constructor */
public BinaryTreeNode(int n)
{
left = null;
right = null;
data = n;
}
/* Function to set left node */
public void setLeft(BinaryTreeNode n)
{
left = n;
}
/* Function to set right node */
public void setRight(BinaryTreeNode n)
{
right = n;
}
/* Function to get left node */
public BinaryTreeNode getLeft()
{
return left;
}
/* Function to get right node */
public BinaryTreeNode getRight()
{
return right;
}
/* Function to set data to node */
public void setData(int d)
{
data = d;
}
/* Function to get data from node */
public int getData()
{
return data;
}
}
/* Define anothe Class Operations to perform required operationns on Binary Tree*/
class Operations
{
private BinaryTreeNode root;
/* Constructor */
public Operations()
{
root = null;
}
/* Function to check if tree is empty */
public boolean isEmpty()
{
return root == null;
}
/* Functions to insert data */
public void insert(int data)
{
root = insert(root, data);
}
/* Function to insert data recursively */
private BinaryTreeNode insert(BinaryTreeNode node, int data)
{
if (node == null)
node = new BinaryTreeNode(data);
else
{
if (node.getRight() == null)
node.right = insert(node.right, data);
else
node.left = insert(node.left, data);
}
return node;
}
/* Function to count number of nodes */
public int countNodes()
{
return countNodes(root);
}
/* Function to count number of nodes recursively */
private int countNodes(BinaryTreeNode r)
{
if (r == null)
return 0;
else
{
int l = 1;
l += countNodes(r.getLeft());
l += countNodes(r.getRight());
return l;
}
}
/* Function to search for an element */
public boolean search(int val)
{
return search(root, val);
}
/* Function to search for an element recursively */
private boolean search(BinaryTreeNode r, int val)
{
if (r.getData() == val)
return true;
if (r.getLeft() != null)
if (search(r.getLeft(), val))
return true;
if (r.getRight() != null)
if (search(r.getRight(), val))
return true;
return false;
}
/* Function for inorder traversal */
public void inorder()
{
inorder(root);
}
private void inorder(BinaryTreeNode r)
{
if (r != null)
{
inorder(r.getLeft());
System.out.print(r.getData() +\" \");
inorder(r.getRight());
}
}
/* Function for preorder traversal */
public void preorder()
{
preorder(root);
}
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This document contains Java code that defines a binary tree class with methods for inserting nodes, searching for values, counting nodes, checking if the tree is empty, and traversing the tree in preorder, inorder and postorder manners. A main method is included that allows a user to test the binary tree operations by selecting options from a menu to insert nodes, search, count nodes or check emptiness and displays the results of tree traversals.
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The composite pattern allows objects to be composed into tree structures to represent part-whole hierarchies. It allows clients to treat individual objects and compositions uniformly. The example shows how shapes like lines and rectangles can be composed into pictures. Individual shapes are leaf classes while pictures are composite classes that can group shapes together and be treated the same way as individual shapes by clients.
Polygon .java package chegg2;public class Polygon { Var.pdf
Polygon .java
package chegg2;
public class Polygon {
// Variables
private int numSides;
private double sideLength;
private double xCord;
private double yCord;
// Default Constructor
public Polygon () {
numSides = 3;
sideLength = 5.0;
xCord = 0.0;
yCord = 0.0;
}
// Constructor
public Polygon (int pSides, double numLength, double numXCord, double numYCord) {
numSides = pSides;
sideLength = numLength;
xCord = numXCord;
yCord = numYCord;
}
// Setter
public void setSides(int mSides) {
numSides = mSides;
System.out.println(\"setSides() results: \"+this.numSides);
}
// Getter
public int getSides() {
return numSides;
}
}
TestPolygon .java
package chegg2;
import java.util.Scanner;
public class TestPolygon {
public static void main(String[] args) {
Polygon poly[] = new Polygon[2];
Polygon poly2 = new Polygon();
poly[0] = poly2;
Scanner input = new Scanner(System.in);
for(int i=1; i<2; i++){
Polygon obj = new Polygon();
System.out.println(\"New Polygons\");
System.out.println(\"--------------------------------------------------\");
System.out.print(\"Enter Number of Sides:\");
obj.setSides(input.nextInt());
poly[i] = obj;
} input.close();
System.out.println(\"Polygons\");
System.out.println(\"--------------------------------------------------\");
for(int i=0; i<2; i++) {
poly[i].setSides(poly[i].getSides());
}
}
}
Output:
run:
New Polygons
--------------------------------------------------
Enter Number of Sides:9
setSides() results: 9
Polygons
--------------------------------------------------
setSides() results: 3
setSides() results: 9
BUILD SUCCESSFUL (total time: 1 second)
Solution
Polygon .java
package chegg2;
public class Polygon {
// Variables
private int numSides;
private double sideLength;
private double xCord;
private double yCord;
// Default Constructor
public Polygon () {
numSides = 3;
sideLength = 5.0;
xCord = 0.0;
yCord = 0.0;
}
// Constructor
public Polygon (int pSides, double numLength, double numXCord, double numYCord) {
numSides = pSides;
sideLength = numLength;
xCord = numXCord;
yCord = numYCord;
}
// Setter
public void setSides(int mSides) {
numSides = mSides;
System.out.println(\"setSides() results: \"+this.numSides);
}
// Getter
public int getSides() {
return numSides;
}
}
TestPolygon .java
package chegg2;
import java.util.Scanner;
public class TestPolygon {
public static void main(String[] args) {
Polygon poly[] = new Polygon[2];
Polygon poly2 = new Polygon();
poly[0] = poly2;
Scanner input = new Scanner(System.in);
for(int i=1; i<2; i++){
Polygon obj = new Polygon();
System.out.println(\"New Polygons\");
System.out.println(\"--------------------------------------------------\");
System.out.print(\"Enter Number of Sides:\");
obj.setSides(input.nextInt());
poly[i] = obj;
} input.close();
System.out.println(\"Polygons\");
System.out.println(\"--------------------------------------------------\");
for(int i=0; i<2; i++) {
poly[i].setSides(poly[i].getSides());
}
}
}
Output:
run:
New Polygons
--------------------------------------------.
Need Help with this Java Assignment. Program should be done in JAVA .pdf
Need Help with this Java Assignment. Program should be done in JAVA please
Complete required scripts based on eclipse and troubleshoot the scripts until the tasks are done.
1. Implement a binary search tree (write the code for it), for a height of 2 or higher. Please show
the output if you can Thank you in advance!
Solution
I have compiled this code and checked for errors, worked fine.
Also after the code I have pasted the Output transcript to show what User Inputs I gave and what
all outputs I got.
// Java Program to Implement Binary Tree
import java.util.Scanner;
/* Define Class BinaryTreeNode */
class BinaryTreeNode
{
BinaryTreeNode left, right;
int data;
/* Constructor */
public BinaryTreeNode()
{
left = null;
right = null;
data = 0;
}
/* Constructor */
public BinaryTreeNode(int n)
{
left = null;
right = null;
data = n;
}
/* Function to set left node */
public void setLeft(BinaryTreeNode n)
{
left = n;
}
/* Function to set right node */
public void setRight(BinaryTreeNode n)
{
right = n;
}
/* Function to get left node */
public BinaryTreeNode getLeft()
{
return left;
}
/* Function to get right node */
public BinaryTreeNode getRight()
{
return right;
}
/* Function to set data to node */
public void setData(int d)
{
data = d;
}
/* Function to get data from node */
public int getData()
{
return data;
}
}
/* Define anothe Class Operations to perform required operationns on Binary Tree*/
class Operations
{
private BinaryTreeNode root;
/* Constructor */
public Operations()
{
root = null;
}
/* Function to check if tree is empty */
public boolean isEmpty()
{
return root == null;
}
/* Functions to insert data */
public void insert(int data)
{
root = insert(root, data);
}
/* Function to insert data recursively */
private BinaryTreeNode insert(BinaryTreeNode node, int data)
{
if (node == null)
node = new BinaryTreeNode(data);
else
{
if (node.getRight() == null)
node.right = insert(node.right, data);
else
node.left = insert(node.left, data);
}
return node;
}
/* Function to count number of nodes */
public int countNodes()
{
return countNodes(root);
}
/* Function to count number of nodes recursively */
private int countNodes(BinaryTreeNode r)
{
if (r == null)
return 0;
else
{
int l = 1;
l += countNodes(r.getLeft());
l += countNodes(r.getRight());
return l;
}
}
/* Function to search for an element */
public boolean search(int val)
{
return search(root, val);
}
/* Function to search for an element recursively */
private boolean search(BinaryTreeNode r, int val)
{
if (r.getData() == val)
return true;
if (r.getLeft() != null)
if (search(r.getLeft(), val))
return true;
if (r.getRight() != null)
if (search(r.getRight(), val))
return true;
return false;
}
/* Function for inorder traversal */
public void inorder()
{
inorder(root);
}
private void inorder(BinaryTreeNode r)
{
if (r != null)
{
inorder(r.getLeft());
System.out.print(r.getData() +\" \");
inorder(r.getRight());
}
}
/* Function for preorder traversal */
public void preorder()
{
preorder(root);
}
priva.
C++ via C#
This document discusses calling C++ code from C# and summarizes the UrhoSharp library which provides bindings between the C++ Urho3D game engine and C#. Key points:
- C++/CLI, COM, and P/Invoke can be used to call C++ from C#
- UrhoSharp exposes over 200 classes and 5000 methods of the Urho3D API to C# with similar performance
- The binding is generated automatically from Urho3D header and source files using a custom binding generator
- Object lifetime is managed by reference counting between the managed and native memory arenas
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This document discusses eliminating "codejunk", which is unnecessary code that does not contribute meaningful information. It provides examples of codejunk like unused variables, pointless comments, and overly specific variable names. The document encourages maximizing the data to ink ratio in code by removing frills and getting to the essential points. It also notes that what constitutes codejunk depends on context like programming language and project type.
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This document contains Java code that defines a binary tree class with methods for inserting nodes, searching for values, counting nodes, checking if the tree is empty, and traversing the tree in preorder, inorder and postorder manners. A main method is included that allows a user to test the binary tree operations by selecting options from a menu to insert nodes, search, count nodes or check emptiness and displays the results of tree traversals.
Lies Told By The Kotlin Compiler
The Kotlin compiler provides many features of Kotlin that do not exist natively in the JVM by generating bytecode that emulates these features. It uses various techniques like generating additional classes and methods, passing implicit parameters, and implementing functional interfaces to achieve this. The summary decompiles some Kotlin code examples to Java bytecode to illustrate how specific Kotlin features are implemented under the hood.
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Please help me make a UML for Java! Look at the code below and make a.docx
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Die.Java
public class Die {
private int number_of_Sides;
private int currentSide;
public Die(int numSides) {
this.number_of_Sides = number_of_Sides;
roll();
}
public int get_Num_Sides() {
return number_of_Sides;
}
public int get_Current_Side() {
return currentSide;
}
public void roll() {
currentSide = (int) (Math.random() * number_of_Sides) + 1;
}
public String toString() {
return "Die with " + number_of_Sides + " sides showing " + currentSide;
}
}
DiceCollection.Java
public class DiceCollection {
private Die[] dice;
public DiceCollection(int[] numSidesArray) {
dice = new Die[numSidesArray.length];
for (int i = 0; i < numSidesArray.length; i++) {
dice[i] = new Die(numSidesArray[i]);
}
}
public int get_Current_Sum() {
int sum = 0;
for (Die die : dice) {
sum += die.getCurrentSide();
}
return sum;
}
public int get_Min_Possible_Sum() {
int sum = 0;
for (Die die : dice) {
sum += 1;
}
return sum;
}
public int get_Max_Possible_Sum() {
int sum = 0;
for (Die die : dice) {
sum += die.get_Num_Sides();
}
return sum;
}
public void rollAll() {
for (Die die : dice) {
die.roll();
}
}
public String toString() {
StringBuilder sb = new StringBuilder();
for (Die die : dice) {
sb.append(die.toString() + "\n");
}
sb.append("Minimum possible roll: " + getMinPossibleSum() + "\n");
sb.append("Maximum possible roll: " + getMaxPossibleSum() + "\n");
sb.append("Current total showing on the dice: " + getCurrentSum());
return sb.toString();
}
public int[] histogram(int numRolls) {
int[] counters = new int[getMaxPossibleSum() - getMinPossibleSum() + 1];
for (int i = 0; i < numRolls; i++) {
rollAll();
int sum = getCurrentSum();
counters[sum - getMinPossibleSum()]++;
}
return counters;
}
}
Main.java
public class Main {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.print("Enter the no. of dice: ");
int numDice = scanner.nextInt();
int[] sides = new int[numDice];
for (int i = 0; i < numDice; i++) {
System.out.print("Enter the number of sides for die " + (i + 1) + ": ");
sides[i] = scanner.nextInt();
}
DiceCollection diceCollection = new DiceCollection(sides);
System.out.println(diceCollection);
while (true) {
System.out.println("\nSelect an option:");
System.out.println("1. Roll once");
System.out.println("2. Roll 100,000 times");
System.out.println("3. Quit");
int choice = scanner.nextInt();
switch (choice) {
case 1:
diceCollection.roll();
System.out.println(diceCollection);
break;
case 2:
System.out.print("Enter the number of rolls: ");
int numRolls = scanner.nextInt();
int[] histogram = diceCollection.histogram(numRolls);
System.out.println("Histogram of " + numRolls + " rolls:");
for (int i = 0; i < histogram.length; i++) {
if (histogram[i] != 0) {
System.out.println(i + ": " + histogram[i]);
}
}
break;
case 3:
System.exit(0);
default:
System.out.println("Invalid option");
}
}
}
}
Please PUT your UML. Thank you!!
.
Using Java, please write the program for the following prompt in the.pdf
Using Java, please write the program for the following prompt in the first picture. The second
and third picture show a sample execution of the program. Collections and generics are
acceptable to use. You just cannot use java methods to iterate through an array list, it must be
iterated through using a for loop. Thank you! A. Objectives l Use at least one array of Strings.
(10 points) 2. Use at least one 2-dimensional array. (10 points) 3. Use sorting to arrange data. (10
points) 1. Use methods to do separate and rcpetitive work. The main method should not have
more than 20 lines of code (10 points) 5. Implement the project correctly. (50 points) 10 points
will be awarded for use of meaningful identificrs, consistent indentation, cxplanatory comments
in your code and properly formatted output. B. Description Each spring brings hope for National
Football League (NFL) teams, especially for those that had poor win-loss records in the previous
season. The NFL draft is held in April and is the opportunity for teams to improve their roster by
adding those college players considered to be the most talented in the world NFL teams develop
their player rosters through three methods: free-agent signings, trading their players for players
from other teams, and drafting college players who have doclared themselves oligiblc for the
NFL draft. The NFL draft is a two-day event in which all 32 teams take their turns selecting
these players. In this project we are going to simulate a limited version of the draft process. This
simulated draft would involve 8 teams and 32 players. Pick any 8 teams from the actual NFL and
32 players of your choice. Be creative! l. Assign a random winning percentage to each of the
teams for the previous season. 2. Based on the winning percentage, rank the teams in order
starting with the one that had the worst performance 3. Each team can now select players in the
order they were ranked 4, Assign numbers l to 4 to the players randomly indicating the round in
which they can be picked. 5. In each round, the teams in order of their numbers will choose
randomly from the players eligible for that round and select them. 6. At thc end of 4 rounds, cach
of the 8 teams will have 4 players they picked.
Solution
import java.applet.*;
import java.awt.*;
import java.awt.event.*;
import java.awt.geom.*;
import java.awt.image.*;
import java.util.*;
//Primary class for the game
public class Asteroids extends Applet implements Runnable, KeyListener{
/**
*
*/
private static final long serialVersionUID = 1L;
//the main thread becomes the game loop
Thread gameloop;
//use this as a double buffer
BufferedImage backbuffer;
//the main drawing object for the back buffer
Graphics2D g2d;
//toggle for drawing bounding boxes
boolean showBounds = false;
//create the asteroid array
int ASTEROIDS = 20;
Asteroid[] ast = new Asteroid[ASTEROIDS];
//create the bullet array
int BULLETS = 10;
Bullet[] bullet = new Bullet[BULLETS];
int currentBullet = 0;
//the player\'.
import java.util.Scanner;class BinaryNode{ BinaryNode left.pdf
This Java program defines classes to represent nodes and binary search trees. It implements methods to insert, delete, search for nodes in the tree as well as traverse the tree using inorder, preorder and postorder traversal. The main method tests the binary search tree operations by prompting the user to insert, delete, search for nodes and check if the tree is empty.
662305 10
This document discusses class design using inheritance and garbage collection in Java. It describes a Point class with x and y coordinates and a Rectangle class that inherits from Point and adds width and height properties. Code examples show defining the classes, creating Point and Rectangle objects, and drawing them in an applet. The Rectangle class inherits coordinate properties from Point and adds its own methods while Point's static count property tracks the number of objects.
Classes and object
1. A class defines a new user-defined type by encapsulating data members and member functions. Data members store the attributes of an object, while member functions implement the behaviors.
2. An object is an instance of a class that allocates memory for the class's data members. Objects are declared by specifying the class name followed by an identifier. Member functions manipulate the data members of an object using dot or arrow operators.
3. A class's data members and member functions can be accessed privately, publicly, or protected. Constructors initialize new objects by setting initial values for data members. Destructors release resources when objects are destroyed.
PROGRAM 2 – Fraction Class Problem For this programming as.pdf
PROGRAM 2 – Fraction Class
Problem For this programming assignment, you are to implement the Fraction class design
given below (and discussed in class). You are also to develop an appropriate test driver that
thoroughly tests the class.
Fraction Class Design Implement the following class design. Make sure to use implement the
methods to have the same names as given below, with the same number and types of parameters.
public class Fraction {
private int numer;
private int denom;
// alternate constructor
public Fraction(int numer, int denom)
throws InvalidDenominatorException {
}
// copy constructor
public Fraction(Fraction otherFrac) {
}
// getters
public int getNumer() {
}
public int getDenom() {
}
// standard methods
public String toString() {
}
public boolean equals(Fraction rFrac) {
}
// fraction operators
public Fraction add(Fraction rFrac) {
}
public Fraction sub(Fraction rFrac) {
}
public Fraction mult(Fraction rFrac) {
}
public Fraction div(Fraction rFrac) {
}
public boolean isSimplestForm() {
}
public Fraction reduce() {
}
public boolean properFrac() {
}
public Fraction abs() {
}
public boolean lessThan(Fraction rFrac) {
}
public boolean greaterThan(Fraction rFrac) {
}
public double convertToDecimal() {
}
public Fraction invert() {
}
}
Note that objects of type Fraction are immutable. Also, the alternate constructor throws an
InvalidDenominatorException if passed a denominator value of 0. This exception type is not
predefined in Java, so you must define it as follow as another class in your Java project files:
public class InvalidDenominatorException extends RuntimeException { } // nothing to
implement
This creates an exception of type RuntimeException. RuntimeExceptions do not need to be
caught when thrown. However, your test driver should have the code for catching this exception
where appropriate.
For example, if your test driver excutes the following,
Fraction frac1 = new Fraction(1,2);
then there is no need to catch the possible exception, since it is clear that the denominator is not
0. However, if the value are input by the user, then there is a chance that a denominator vaue of 0
could be entered, and therefore the code for catching the possible exception is needed,
int numer, denom;
Fraction frac1;
Scanner input = new Scanner(System.in);
Boolean valid_input = false;
while (!valid_input) try {
System.out.print(“Enter numerator denominator: “);
numer = input.nextInt();
denom = input.nextInt();
frac1 = new Fraction(numer,denom);
valid_input = true;
}
catch (InvalidDenominatorException e) {
System.out.println(“Denominator of Zero found – Please reenter”);
}
catch (InputMismatchException e) {
System.out.println(“Non-digit character found – Please reenter”);
} etc.
Considerations
Makes sure the equals method returns true for any two fractions that are arithmetically equal.
Make sure that the equals, lessThan and greaterThan methods do not alter the values of the
fractions being compared. You may consider the use of private methods .
Dotnet unit 4
This document discusses interfaces in C# and .NET. It defines interfaces as collections of related members that define behaviors that classes can choose to support. It describes how to define interfaces using the interface keyword, implement interfaces in classes using a comma separated list, and obtain interface references from objects using casting, the "as" and "is" keywords. It also covers explicit interface implementation to avoid name clashes, interfaces as parameters and return types, and building interface hierarchies.
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The State of JavaScript (2015)
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1. C.HIV is a virus it can be tansmitted through body fluids liks .pdf
1. C.
HIV is a virus it can be tansmitted through body fluids liks semen and blood and it causes AIDS.
2. D.
3.C.
4.B.
5.A.
6.B.
Solution
1. C.
HIV is a virus it can be tansmitted through body fluids liks semen and blood and it causes AIDS.
2. D.
3.C.
4.B.
5.A.
6.B..
#include iostream #include cstddefusing namespace std;temp.pdf
#include
#include
using namespace std;
template class Node{
private:
T value;
Node *next;
public:
Node();
Node (T data);
T remove();
T getValue();
Node* getNext();
void setValue(T data);
void setNext(Node *nextNode);
};
template
Node::Node(){
T value =NULL;
}
template
Node::Node(T data){
T value=data;
}
template
T Node::getValue(){
return value;
}
template
Node* Node::getNext(){
return next;
}
template
void Node::setValue(T data){
T value=data;
}
template
void Node::setNext(Node *nextNode){
next=nextNode;
}
template class MyLinkedList{
Node start;
//Define a constructor
MyLinkedList()
{
start->setValue(0);
start->setNext(NULL);
}
//Member Functions:
// Adds a new element to the list
void add (T val)
{
/* creating a new node to hold value*/
Nodetemp(val,NULL);
/* If no start node till now, this node is made as start node*/
if (start->next == NULL)
{
start.setNext(temp);
}
/* if start node exists, insert new node at end of list*/
else
{
s = start->next;
/* locating end of list*/
while (s->next != NULL)
{
s= s->next;
}
temp->next = NULL;
/* attaching new node */
s->next = temp;
cout<<\"Element Inserted\"<next->next != NULL)
{
s = s->next;
}
//After locating the end node
ptr=s->next;
s->next=NULL;
//deletting end node
return ptr;
}
}
//Prints elements of the list
void printContent()
{
struct node *ptr = start;
cout<data;
ptr=ptr->next;
}
}
}
//Prints total number of elements
int getSize()
{
struct node *ptr, *s;
int count=0;
if (start == NULL)
{
cout<<\"The List is empty\"<next;
count=1;
while (ptr != NULL)
{
count++;
ptr=ptr->next;
}
return count;
}
//Returns true if there is no element in the list.
bool empty()
{
if(start==NULL)
{
return empty;
}
}
};
Solution
#include
#include
using namespace std;
template class Node{
private:
T value;
Node *next;
public:
Node();
Node (T data);
T remove();
T getValue();
Node* getNext();
void setValue(T data);
void setNext(Node *nextNode);
};
template
Node::Node(){
T value =NULL;
}
template
Node::Node(T data){
T value=data;
}
template
T Node::getValue(){
return value;
}
template
Node* Node::getNext(){
return next;
}
template
void Node::setValue(T data){
T value=data;
}
template
void Node::setNext(Node *nextNode){
next=nextNode;
}
template class MyLinkedList{
Node start;
//Define a constructor
MyLinkedList()
{
start->setValue(0);
start->setNext(NULL);
}
//Member Functions:
// Adds a new element to the list
void add (T val)
{
/* creating a new node to hold value*/
Nodetemp(val,NULL);
/* If no start node till now, this node is made as start node*/
if (start->next == NULL)
{
start.setNext(temp);
}
/* if start node exists, insert new node at end of list*/
else
{
s = start->next;
/* locating end of list*/
while (s->next != NULL)
{
s= s->next;
}
temp->next = NULL;
/* attaching new node */
s->next = temp;
cout<<\"Element Inserted\"<next->next != NULL)
{
s = s->next;
}
//After locating the end node
ptr=s->next;
s->next=NULL;
//deletting end node
return ptr;
}
}
//Prints elements of the list
void printContent()
{
struct .
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Please help me make a UML for Java! Look at the code below and make a.docx
Please help me make a UML for Java! Look at the code below and make a UML for it.
Die.Java
public class Die {
private int number_of_Sides;
private int currentSide;
public Die(int numSides) {
this.number_of_Sides = number_of_Sides;
roll();
}
public int get_Num_Sides() {
return number_of_Sides;
}
public int get_Current_Side() {
return currentSide;
}
public void roll() {
currentSide = (int) (Math.random() * number_of_Sides) + 1;
}
public String toString() {
return "Die with " + number_of_Sides + " sides showing " + currentSide;
}
}
DiceCollection.Java
public class DiceCollection {
private Die[] dice;
public DiceCollection(int[] numSidesArray) {
dice = new Die[numSidesArray.length];
for (int i = 0; i < numSidesArray.length; i++) {
dice[i] = new Die(numSidesArray[i]);
}
}
public int get_Current_Sum() {
int sum = 0;
for (Die die : dice) {
sum += die.getCurrentSide();
}
return sum;
}
public int get_Min_Possible_Sum() {
int sum = 0;
for (Die die : dice) {
sum += 1;
}
return sum;
}
public int get_Max_Possible_Sum() {
int sum = 0;
for (Die die : dice) {
sum += die.get_Num_Sides();
}
return sum;
}
public void rollAll() {
for (Die die : dice) {
die.roll();
}
}
public String toString() {
StringBuilder sb = new StringBuilder();
for (Die die : dice) {
sb.append(die.toString() + "\n");
}
sb.append("Minimum possible roll: " + getMinPossibleSum() + "\n");
sb.append("Maximum possible roll: " + getMaxPossibleSum() + "\n");
sb.append("Current total showing on the dice: " + getCurrentSum());
return sb.toString();
}
public int[] histogram(int numRolls) {
int[] counters = new int[getMaxPossibleSum() - getMinPossibleSum() + 1];
for (int i = 0; i < numRolls; i++) {
rollAll();
int sum = getCurrentSum();
counters[sum - getMinPossibleSum()]++;
}
return counters;
}
}
Main.java
public class Main {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.print("Enter the no. of dice: ");
int numDice = scanner.nextInt();
int[] sides = new int[numDice];
for (int i = 0; i < numDice; i++) {
System.out.print("Enter the number of sides for die " + (i + 1) + ": ");
sides[i] = scanner.nextInt();
}
DiceCollection diceCollection = new DiceCollection(sides);
System.out.println(diceCollection);
while (true) {
System.out.println("\nSelect an option:");
System.out.println("1. Roll once");
System.out.println("2. Roll 100,000 times");
System.out.println("3. Quit");
int choice = scanner.nextInt();
switch (choice) {
case 1:
diceCollection.roll();
System.out.println(diceCollection);
break;
case 2:
System.out.print("Enter the number of rolls: ");
int numRolls = scanner.nextInt();
int[] histogram = diceCollection.histogram(numRolls);
System.out.println("Histogram of " + numRolls + " rolls:");
for (int i = 0; i < histogram.length; i++) {
if (histogram[i] != 0) {
System.out.println(i + ": " + histogram[i]);
}
}
break;
case 3:
System.exit(0);
default:
System.out.println("Invalid option");
}
}
}
}
Please PUT your UML. Thank you!!
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Using Java, please write the program for the following prompt in the.pdf
Using Java, please write the program for the following prompt in the first picture. The second
and third picture show a sample execution of the program. Collections and generics are
acceptable to use. You just cannot use java methods to iterate through an array list, it must be
iterated through using a for loop. Thank you! A. Objectives l Use at least one array of Strings.
(10 points) 2. Use at least one 2-dimensional array. (10 points) 3. Use sorting to arrange data. (10
points) 1. Use methods to do separate and rcpetitive work. The main method should not have
more than 20 lines of code (10 points) 5. Implement the project correctly. (50 points) 10 points
will be awarded for use of meaningful identificrs, consistent indentation, cxplanatory comments
in your code and properly formatted output. B. Description Each spring brings hope for National
Football League (NFL) teams, especially for those that had poor win-loss records in the previous
season. The NFL draft is held in April and is the opportunity for teams to improve their roster by
adding those college players considered to be the most talented in the world NFL teams develop
their player rosters through three methods: free-agent signings, trading their players for players
from other teams, and drafting college players who have doclared themselves oligiblc for the
NFL draft. The NFL draft is a two-day event in which all 32 teams take their turns selecting
these players. In this project we are going to simulate a limited version of the draft process. This
simulated draft would involve 8 teams and 32 players. Pick any 8 teams from the actual NFL and
32 players of your choice. Be creative! l. Assign a random winning percentage to each of the
teams for the previous season. 2. Based on the winning percentage, rank the teams in order
starting with the one that had the worst performance 3. Each team can now select players in the
order they were ranked 4, Assign numbers l to 4 to the players randomly indicating the round in
which they can be picked. 5. In each round, the teams in order of their numbers will choose
randomly from the players eligible for that round and select them. 6. At thc end of 4 rounds, cach
of the 8 teams will have 4 players they picked.
Solution
import java.applet.*;
import java.awt.*;
import java.awt.event.*;
import java.awt.geom.*;
import java.awt.image.*;
import java.util.*;
//Primary class for the game
public class Asteroids extends Applet implements Runnable, KeyListener{
/**
*
*/
private static final long serialVersionUID = 1L;
//the main thread becomes the game loop
Thread gameloop;
//use this as a double buffer
BufferedImage backbuffer;
//the main drawing object for the back buffer
Graphics2D g2d;
//toggle for drawing bounding boxes
boolean showBounds = false;
//create the asteroid array
int ASTEROIDS = 20;
Asteroid[] ast = new Asteroid[ASTEROIDS];
//create the bullet array
int BULLETS = 10;
Bullet[] bullet = new Bullet[BULLETS];
int currentBullet = 0;
//the player\'.
import java.util.Scanner;class BinaryNode{ BinaryNode left.pdf
This Java program defines classes to represent nodes and binary search trees. It implements methods to insert, delete, search for nodes in the tree as well as traverse the tree using inorder, preorder and postorder traversal. The main method tests the binary search tree operations by prompting the user to insert, delete, search for nodes and check if the tree is empty.
662305 10
This document discusses class design using inheritance and garbage collection in Java. It describes a Point class with x and y coordinates and a Rectangle class that inherits from Point and adds width and height properties. Code examples show defining the classes, creating Point and Rectangle objects, and drawing them in an applet. The Rectangle class inherits coordinate properties from Point and adds its own methods while Point's static count property tracks the number of objects.
Classes and object
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PROGRAM 2 – Fraction Class Problem For this programming as.pdf
PROGRAM 2 – Fraction Class
Problem For this programming assignment, you are to implement the Fraction class design
given below (and discussed in class). You are also to develop an appropriate test driver that
thoroughly tests the class.
Fraction Class Design Implement the following class design. Make sure to use implement the
methods to have the same names as given below, with the same number and types of parameters.
public class Fraction {
private int numer;
private int denom;
// alternate constructor
public Fraction(int numer, int denom)
throws InvalidDenominatorException {
}
// copy constructor
public Fraction(Fraction otherFrac) {
}
// getters
public int getNumer() {
}
public int getDenom() {
}
// standard methods
public String toString() {
}
public boolean equals(Fraction rFrac) {
}
// fraction operators
public Fraction add(Fraction rFrac) {
}
public Fraction sub(Fraction rFrac) {
}
public Fraction mult(Fraction rFrac) {
}
public Fraction div(Fraction rFrac) {
}
public boolean isSimplestForm() {
}
public Fraction reduce() {
}
public boolean properFrac() {
}
public Fraction abs() {
}
public boolean lessThan(Fraction rFrac) {
}
public boolean greaterThan(Fraction rFrac) {
}
public double convertToDecimal() {
}
public Fraction invert() {
}
}
Note that objects of type Fraction are immutable. Also, the alternate constructor throws an
InvalidDenominatorException if passed a denominator value of 0. This exception type is not
predefined in Java, so you must define it as follow as another class in your Java project files:
public class InvalidDenominatorException extends RuntimeException { } // nothing to
implement
This creates an exception of type RuntimeException. RuntimeExceptions do not need to be
caught when thrown. However, your test driver should have the code for catching this exception
where appropriate.
For example, if your test driver excutes the following,
Fraction frac1 = new Fraction(1,2);
then there is no need to catch the possible exception, since it is clear that the denominator is not
0. However, if the value are input by the user, then there is a chance that a denominator vaue of 0
could be entered, and therefore the code for catching the possible exception is needed,
int numer, denom;
Fraction frac1;
Scanner input = new Scanner(System.in);
Boolean valid_input = false;
while (!valid_input) try {
System.out.print(“Enter numerator denominator: “);
numer = input.nextInt();
denom = input.nextInt();
frac1 = new Fraction(numer,denom);
valid_input = true;
}
catch (InvalidDenominatorException e) {
System.out.println(“Denominator of Zero found – Please reenter”);
}
catch (InputMismatchException e) {
System.out.println(“Non-digit character found – Please reenter”);
} etc.
Considerations
Makes sure the equals method returns true for any two fractions that are arithmetically equal.
Make sure that the equals, lessThan and greaterThan methods do not alter the values of the
fractions being compared. You may consider the use of private methods .
Dotnet unit 4
This document discusses interfaces in C# and .NET. It defines interfaces as collections of related members that define behaviors that classes can choose to support. It describes how to define interfaces using the interface keyword, implement interfaces in classes using a comma separated list, and obtain interface references from objects using casting, the "as" and "is" keywords. It also covers explicit interface implementation to avoid name clashes, interfaces as parameters and return types, and building interface hierarchies.
Tank Battle - A simple game powered by JMonkey engine
A simple two player java-based game powered by JMonkey game engine which implements many standard object oriented design patterns such as Singleton, Composite, Strategy and etc.
Sceneform SDK на практиці - UA Mobile 2019
Тема нативних движків, що спрощують роботу з 3D графікою для Android, є головним болем багатьох розробників. У той час як для iOS існує SceneKit, розробники під Android були змушені або йти в крос-платформені рішення (Unity3d, LibGDX і т.п.) або використовувати самописні/опенсорсні рішення з обмеженим функціоналом. Поява Sceneform SDK вирішує не тільки цю проблему але й інкапсулює в собі роботу з ArCore SDK, відкриваючи для розробників можливість нативної реалізації AR рішень, не вдаючись до стороннього SDK.
В рамках доповіді будуть розглянуті практичні можливості та обмеження Sceneform SDK стосовно проектів з доповненою реальністю (AR). Так само будуть розглянуті такі теми як SLAM, ArCore SDK, розпізнавання та трекінг маркерів на основі зображень, Cloud Anchors та існуючі альтернативи на ринку.
Sceneform SDK на практиці - UA Mobile 2019
Тема нативних движків, що спрощують роботу з 3D графікою для Android, є головним болем багатьох розробників. У той час як для iOS існує SceneKit, розробники під Android були змушені або йти в крос-платформені рішення (Unity3d, LibGDX і т.п.) або використовувати самописні/опенсорсні рішення з обмеженим функціоналом. Поява Sceneform SDK вирішує не тільки цю проблему але й інкапсулює в собі роботу з ArCore SDK, відкриваючи для розробників можливість нативної реалізації AR рішень, не вдаючись до стороннього SDK.
В рамках доповіді будуть розглянуті практичні можливості та обмеження Sceneform SDK стосовно проектів з доповненою реальністю (AR). Так само будуть розглянуті такі теми як SLAM, ArCore SDK, розпізнавання та трекінг маркерів на основі зображень, Cloud Anchors та існуючі альтернативи на ринку.
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Talk au Tech2Day concernant l'approche RDD pour RestDrivenDomain qui nous permet chez Lucca de développer des domaines métiers exposés directement via des API REST.
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Constructors and Destructors
The complete study of constructors, types of constructors, overloading constructors, advantages and disadvantages, and destructors
The State of JavaScript (2015)
- JavaScript has come a long way from its early days of form validation and image rollovers in 1995 to modern innovations like ES2015, Promises, async/await, and Web Assembly.
- Today, JavaScript features like classes, arrow functions, and template strings in ES2015 are widely adopted, and new standards like Promises, generators, and async programming have revolutionized asynchronous JavaScript.
- Emerging web platform technologies like Web Components, Service Workers, and CSS Paint enable new kinds of custom elements, offline/progressive web apps, and painting APIs, while proposals like decorators, value types, and module loading continue pushing the language forward.
C# 6.0 - April 2014 preview
Paulo Morgado presented an overview of new features in C# 6.0. Some key points:
- The .NET Compiler Platform ("Roslyn") reimplements the C# and VB compilers in C# with public APIs.
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- Many features are still being implemented or considered for inclusion in C# 6.0 based on the April 2014 preview release.
- The presentation demonstrated examples of the new C# 6.0 language features and their syntax. Attendees were encouraged to try
2016 gunma.web games-and-asm.js
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Intro to object oriented programming
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Similar to Hi, Please find mu codeimport java.util.Random;public class Sup.pdf (20)
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Please help me make a UML for Java! Look at the code below and make a.docx
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Using Java, please write the program for the following prompt in the.pdf
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import java.util.Scanner;class BinaryNode{ BinaryNode left.pdf
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PROGRAM 2 – Fraction Class Problem For this programming as.pdf
PROGRAM 2 – Fraction Class Problem For this programming as.pdf
Tank Battle - A simple game powered by JMonkey engine
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Web2Day 2017 - Concilier DomainDriveDesign et API REST
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More from karan8801
1. C.HIV is a virus it can be tansmitted through body fluids liks .pdf
1. C.
HIV is a virus it can be tansmitted through body fluids liks semen and blood and it causes AIDS.
2. D.
3.C.
4.B.
5.A.
6.B.
Solution
1. C.
HIV is a virus it can be tansmitted through body fluids liks semen and blood and it causes AIDS.
2. D.
3.C.
4.B.
5.A.
6.B..
#include iostream #include cstddefusing namespace std;temp.pdf
#include
#include
using namespace std;
template class Node{
private:
T value;
Node *next;
public:
Node();
Node (T data);
T remove();
T getValue();
Node* getNext();
void setValue(T data);
void setNext(Node *nextNode);
};
template
Node::Node(){
T value =NULL;
}
template
Node::Node(T data){
T value=data;
}
template
T Node::getValue(){
return value;
}
template
Node* Node::getNext(){
return next;
}
template
void Node::setValue(T data){
T value=data;
}
template
void Node::setNext(Node *nextNode){
next=nextNode;
}
template class MyLinkedList{
Node start;
//Define a constructor
MyLinkedList()
{
start->setValue(0);
start->setNext(NULL);
}
//Member Functions:
// Adds a new element to the list
void add (T val)
{
/* creating a new node to hold value*/
Nodetemp(val,NULL);
/* If no start node till now, this node is made as start node*/
if (start->next == NULL)
{
start.setNext(temp);
}
/* if start node exists, insert new node at end of list*/
else
{
s = start->next;
/* locating end of list*/
while (s->next != NULL)
{
s= s->next;
}
temp->next = NULL;
/* attaching new node */
s->next = temp;
cout<<\"Element Inserted\"<next->next != NULL)
{
s = s->next;
}
//After locating the end node
ptr=s->next;
s->next=NULL;
//deletting end node
return ptr;
}
}
//Prints elements of the list
void printContent()
{
struct node *ptr = start;
cout<data;
ptr=ptr->next;
}
}
}
//Prints total number of elements
int getSize()
{
struct node *ptr, *s;
int count=0;
if (start == NULL)
{
cout<<\"The List is empty\"<next;
count=1;
while (ptr != NULL)
{
count++;
ptr=ptr->next;
}
return count;
}
//Returns true if there is no element in the list.
bool empty()
{
if(start==NULL)
{
return empty;
}
}
};
Solution
#include
#include
using namespace std;
template class Node{
private:
T value;
Node *next;
public:
Node();
Node (T data);
T remove();
T getValue();
Node* getNext();
void setValue(T data);
void setNext(Node *nextNode);
};
template
Node::Node(){
T value =NULL;
}
template
Node::Node(T data){
T value=data;
}
template
T Node::getValue(){
return value;
}
template
Node* Node::getNext(){
return next;
}
template
void Node::setValue(T data){
T value=data;
}
template
void Node::setNext(Node *nextNode){
next=nextNode;
}
template class MyLinkedList{
Node start;
//Define a constructor
MyLinkedList()
{
start->setValue(0);
start->setNext(NULL);
}
//Member Functions:
// Adds a new element to the list
void add (T val)
{
/* creating a new node to hold value*/
Nodetemp(val,NULL);
/* If no start node till now, this node is made as start node*/
if (start->next == NULL)
{
start.setNext(temp);
}
/* if start node exists, insert new node at end of list*/
else
{
s = start->next;
/* locating end of list*/
while (s->next != NULL)
{
s= s->next;
}
temp->next = NULL;
/* attaching new node */
s->next = temp;
cout<<\"Element Inserted\"<next->next != NULL)
{
s = s->next;
}
//After locating the end node
ptr=s->next;
s->next=NULL;
//deletting end node
return ptr;
}
}
//Prints elements of the list
void printContent()
{
struct .
omparative historical research is a method of social science that e.pdf
omparative historical research is a method of social science that examines historical events in
order to create explanations that are valid beyond a particular time and place, either by direct
comparison to other historical events, theory building, or reference to the present
day.[1]Generally, it involves comparisons of social processes across times and places. It overlaps
with historical sociology. While the disciplines ofhistory and sociology have always been
connected, they have connected in different ways at different times (see \'Major researchers\'
below). This form of research may use any of several theoretical orientations. It is distinguished
by the types of questions it asks, not the theoretical framework it employs (see \'Illustrations\'
below)
Some commentators have identified three waves of historical comparative research.[2] The first
wave of historical comparative research concerned how societies came to be modern, i.e. based
on individual and rational action, with exact definitions varying widely. Some of the major
researchers in this mode were Alexis de Tocqueville,[3]Karl Marx,[4]Emile Durkheim,[5]Max
Weber,[6] and W.E.B. Du Bois.[7] The second wave reacted to a perceived ahistorical body of
theory and sought to show how social systems were not static, but developed over time.[8]
Notable authors of this wave include Barrington Moore, Jr.,[9]Theda Skocpol,[10]Charles
Tilly,[11]Michael Mann,[12] and Mark Gould.[13] Some have placed the Annales school and
Pierre Bourdieu in this general group, despite their stylistic differences.[14] The current wave of
historical comparative research sociology is often but not exclusively post-structural in its
theoretical orientation. Influential current authors include Julia Adams,[15] Anne Laura
Stoler,[16]Philip Gorski,[17] and James Mahoney.[18]
There are four major methods that researchers use to collect historical data. These are archival
data, secondary sources, running records, and recollections. The archival data, or primary
sources, are typically the resources that researchers rely most heavily on. Archival data includes
official documents and other items that would be found in archives, museums, etc. Secondary
sources are the works of other historians who have written history. Running records are ongoing
series of statistical or other sorts of data, such as census data, ship\'s registries, property deeds,
etc. Finally recollections include sources such as autobiographies, memoirs or diaries.[19]
There are four stages, as discussed by Schutt, to systematic qualitative comparative historical
studies: (1) develop the premise of the investigation, identifying events, concepts, etc., that may
explain the phenomena; (2) choose the case(s) (location- nation, region) to examine; (3) use what
Theda Skocpol has termed as \"interpretive historical sociology\" and examine the similarities
and the differences; and (4) based on the information gathered, propose a causal explanation for
the pheno.
where is it .pdf
This very short document appears to be asking "where is it" but does not provide any other context or information. It repeats the phrase "where is it" twice but gives no indication of what "it" refers to or where one might expect to find it. The document on its own does not give enough information to form a meaningful summary.
The name of the reaction is aldol condesation (Cl.pdf
The name of the reaction is aldol condesation (Claisen) (it usesbase to form a
enolate and it atacks over the diketone one time andthen it atacks again intramolecular to form
the ring), the -OHformed in the condesation are eliminated to form the two doublebonds. The
functional group present in the product is a ketone andthe hydroxi groups that were eliminated.
Solution
The name of the reaction is aldol condesation (Claisen) (it usesbase to form a
enolate and it atacks over the diketone one time andthen it atacks again intramolecular to form
the ring), the -OHformed in the condesation are eliminated to form the two doublebonds. The
functional group present in the product is a ketone andthe hydroxi groups that were eliminated..
Step1 3 moles of H2O react with Cr metal = 2moles.pdf
Step1 3 moles of H2O react with Cr metal = 2moles Step2 3.17 moles of H2O will
react with Cr = 2x3.17/3 =6.14/3 =2.057
Solution
Step1 3 moles of H2O react with Cr metal = 2moles Step2 3.17 moles of H2O will
react with Cr = 2x3.17/3 =6.14/3 =2.057.
Part A neutralizes acids - base Part B produces.pdf
Part A: neutralizes acids - base Part B: produces OH^- in water - base Part C: has a
soapy feel - base Part D: turns litmus red - acid
Solution
Part A: neutralizes acids - base Part B: produces OH^- in water - base Part C: has a
soapy feel - base Part D: turns litmus red - acid.
Lewis Acid Base Reaction .pdf
Lewis acid-base reactions involve the sharing of electron pairs between reactants. A Lewis acid is an electron pair acceptor that has an empty orbital, while a Lewis base is an electron pair donor that has a lone pair of electrons. When a Lewis acid and base interact, the base donates an electron pair to form a new bond with the empty orbital on the acid.
KOH ==== K+ (aq) + OH-(aq) [OH-] =9.710^-5 [H.pdf
KOH ====> K+ (aq) + OH-(aq) [OH-] =9.7*10^-5 [H+][OH-] = 1.0*10^-14
[H+] = (1.0*10^-14)/(9.7*10^-5) = 1.03*10^-10 pH = -log[H+] = -log(1.03*10^-10) = 9.987 =
10 pH+pOH=14 pOh = 14-pH = 14-10=4
Solution
KOH ====> K+ (aq) + OH-(aq) [OH-] =9.7*10^-5 [H+][OH-] = 1.0*10^-14
[H+] = (1.0*10^-14)/(9.7*10^-5) = 1.03*10^-10 pH = -log[H+] = -log(1.03*10^-10) = 9.987 =
10 pH+pOH=14 pOh = 14-pH = 14-10=4.
It is a reaction for secondary amines .Option 2 i.pdf
It is a reaction for secondary amines .Option 2 is correct.
Solution
It is a reaction for secondary amines .Option 2 is correct..
fluorene is mobile phase and fluorenone is statio.pdf
fluorene is mobile phase and fluorenone is stationary phase because : Mostly,it
depends on the solvent you are using, but lets assume you use pentane as the solvent for fluorene
and diethyl ether as the solvent for fluorenone. Used in this order, fluorene should actaully move
slower down the column due to the the polarity of the alumina and the nonpolarity of the solvent
(pentane). Since fluorene is less polar so, remember the rule like dissolves like? Well, this kind
of applies to chromatography wherein rather than dissolve just replace it with moves with, so like
moves with like. That being said the pentane will \"carry\" the fluorene through the alumina
slower than the latter (which I will explain). Fluorenone is polar because of its C=O bond, that
being said the dielectric constant of diethyl ether is 4.3 which means it has intermediate polarity
(remember that pentane has a dielectric constant of 2.1 I think, so it is nonpolar). Since the
alumina, diethyl ether, and the fluorenone are all polar, the fluorenone will travel faster through
the alumina than would the fluorene, because there is no attraction between all these polar
compounds which will allow it to move faster, rather than a nonpolar and polar chemical having
an attration towards each other and thus moving more slowly.
Solution
fluorene is mobile phase and fluorenone is stationary phase because : Mostly,it
depends on the solvent you are using, but lets assume you use pentane as the solvent for fluorene
and diethyl ether as the solvent for fluorenone. Used in this order, fluorene should actaully move
slower down the column due to the the polarity of the alumina and the nonpolarity of the solvent
(pentane). Since fluorene is less polar so, remember the rule like dissolves like? Well, this kind
of applies to chromatography wherein rather than dissolve just replace it with moves with, so like
moves with like. That being said the pentane will \"carry\" the fluorene through the alumina
slower than the latter (which I will explain). Fluorenone is polar because of its C=O bond, that
being said the dielectric constant of diethyl ether is 4.3 which means it has intermediate polarity
(remember that pentane has a dielectric constant of 2.1 I think, so it is nonpolar). Since the
alumina, diethyl ether, and the fluorenone are all polar, the fluorenone will travel faster through
the alumina than would the fluorene, because there is no attraction between all these polar
compounds which will allow it to move faster, rather than a nonpolar and polar chemical having
an attration towards each other and thus moving more slowly..
equivalent mass is 27.9 . so Molecular massmole.pdf
equivalent mass is 27.9 . so Molecular mass/moles of electrons per mole = 27.9
looking at the table for atomic masses, the closest we get is for moles of electrons per mole = 2
that is , molecular weight = 55.8 which is for Iron Hence Y is Iron ( Fe )
Solution
equivalent mass is 27.9 . so Molecular mass/moles of electrons per mole = 27.9
looking at the table for atomic masses, the closest we get is for moles of electrons per mole = 2
that is , molecular weight = 55.8 which is for Iron Hence Y is Iron ( Fe ).
There is no solutionSolutionThere is no solution.pdf
The document repeats the phrase "There is no solution" with no other context or information provided. It consists of three short sentences stating "There is no solution" with no explanation or details given about what problem is being referred to or discussed.
This is a case of allopatric speciation. In this case lice from gori.pdf
This is a case of allopatric speciation. In this case lice from gorilla moved and solutes into two
different species. So this is case of geographical speciation where species become apart from
each other to an extent that they cannot interbreed.
Solution
This is a case of allopatric speciation. In this case lice from gorilla moved and solutes into two
different species. So this is case of geographical speciation where species become apart from
each other to an extent that they cannot interbreed..
d. 8 The bonding electrons are the electrons taki.pdf
The document discusses the bonding electrons in a carbon dioxide (CO2) molecule. Carbon is centered between two hydrogen atoms and one oxygen atom. Carbon shares two electrons with each hydrogen atom, for a total of four electrons shared with hydrogen. Carbon also shares four electrons with the oxygen atom. Therefore, the total number of bonding electrons is the four shared with hydrogen plus the four shared with oxygen, which is eight.
The genetical changes of single locus are responsible for divergent .pdf
The genetical changes of single locus are responsible for divergent branches of Y chromosome
phylogenetic tree in different geographical locations elicit the human origins. The mitochondrial
DNA sequences of Neanderthals and modern humans were compared and analyzed. The
Hominins species were found to be 30000 year old and were compared with Neanderthal
specimens.
The relationships between these populations have drawn with the help of the age of specimens
plotted against the average genetic distance. The Hominins type sequences are very rare when
compared with the modern European samples. The prehistoric Europeans had shown constant
number of differences when compared to today’s Europeans and Neanderthals.
The Neanderthals have shown the genetic continuity in modern human’s genealogy. The
Neanderthals had shown clear discontinuity with the Hominins from upper Paleolithic period to
the similar ages. The Neanderthals and early anatomical modern humans were thought to be
regional populations of the same evolving species connected by gene flow and both the archaic
and modern humans contribute in different proportions to the present human gene pool.
The transition and demographic replacement separated the population as Neanderthals and
modern humans are considered just as one population observed at different times. The multi
regional models predict that at least some level of genetic continuity can be observed from
archaic Neanderthal forms to the contemporary Hominins forms and up to today’s Europeans.
The results have not matched with the view that the Neanderthal were genetically related with
the anatomically modern ancestors of current Europeans or contributed to the present day human
gene pool.
Solution
The genetical changes of single locus are responsible for divergent branches of Y chromosome
phylogenetic tree in different geographical locations elicit the human origins. The mitochondrial
DNA sequences of Neanderthals and modern humans were compared and analyzed. The
Hominins species were found to be 30000 year old and were compared with Neanderthal
specimens.
The relationships between these populations have drawn with the help of the age of specimens
plotted against the average genetic distance. The Hominins type sequences are very rare when
compared with the modern European samples. The prehistoric Europeans had shown constant
number of differences when compared to today’s Europeans and Neanderthals.
The Neanderthals have shown the genetic continuity in modern human’s genealogy. The
Neanderthals had shown clear discontinuity with the Hominins from upper Paleolithic period to
the similar ages. The Neanderthals and early anatomical modern humans were thought to be
regional populations of the same evolving species connected by gene flow and both the archaic
and modern humans contribute in different proportions to the present human gene pool.
The transition and demographic replacement separated the population as Neanderthals and
modern humans .
The corrects answers areThr and Asn are polar amino acids.Isole.pdf
The corrects answers are:
Thr and Asn are polar amino acids.
Isoleucine has more than one stereocenter (chiral center)
The Leu side chain does not from hydrogen bonds with other amino acids
Solution
The corrects answers are:
Thr and Asn are polar amino acids.
Isoleucine has more than one stereocenter (chiral center)
The Leu side chain does not from hydrogen bonds with other amino acids.
Since Z4 has an element of order 4,Z4, its a cyclic group of order 4.pdf
Since Z4 has an element of order 4,Z4, its a cyclic group of order 4
i.e Z4 = ( 0,1,2,3)
U(8) = { 1,3,5,7} while each element of U(8) has order 1 or 2
So, isomorphic Z4 and U(8) are not isomorphic.
Solution
Since Z4 has an element of order 4,Z4, its a cyclic group of order 4
i.e Z4 = ( 0,1,2,3)
U(8) = { 1,3,5,7} while each element of U(8) has order 1 or 2
So, isomorphic Z4 and U(8) are not isomorphic..
More from karan8801 (20)
1. C.HIV is a virus it can be tansmitted through body fluids liks .pdf
1. C.HIV is a virus it can be tansmitted through body fluids liks .pdf
#include iostream #include cstddefusing namespace std;temp.pdf
#include iostream #include cstddefusing namespace std;temp.pdf
omparative historical research is a method of social science that e.pdf
omparative historical research is a method of social science that e.pdf
The name of the reaction is aldol condesation (Cl.pdf
The name of the reaction is aldol condesation (Cl.pdf
Step1 3 moles of H2O react with Cr metal = 2moles.pdf
Step1 3 moles of H2O react with Cr metal = 2moles.pdf
Part A neutralizes acids - base Part B produces.pdf
Part A neutralizes acids - base Part B produces.pdf
It is a reaction for secondary amines .Option 2 i.pdf
It is a reaction for secondary amines .Option 2 i.pdf
fluorene is mobile phase and fluorenone is statio.pdf
fluorene is mobile phase and fluorenone is statio.pdf
equivalent mass is 27.9 . so Molecular massmole.pdf
equivalent mass is 27.9 . so Molecular massmole.pdf
There is no solutionSolutionThere is no solution.pdf
There is no solutionSolutionThere is no solution.pdf
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Hi, Please find mu codeimport java.util.Random;public class Sup.pdf
- 1. Hi, Please find mu code: import java.util.Random; public class SuperDie { private int sides; private Random rand; public SuperDie(){ // Default constructor sides = 6; rand = new Random(); } // Constructor that lets user define number of sides n. public SuperDie(int n){ sides = n; rand = new Random(); } // Constructor that lets user define number of sides n AND provide their own Random object. public SuperDie(int n, Random r){ sides = n; rand = r; } public int getNumSides(){ return sides; } public void setNumSides(int n){ sides = n; } public int roll(){ return rand.nextInt(sides)+1; }
- 2. } import java.util.*; class MainDie { public static void main (String[] args) { int value, sides; Random rand = new Random(); SuperDie d1 = new SuperDie(); SuperDie d2 = new SuperDie(20); SuperDie d3 = new SuperDie(10,rand); value = d1.roll(); System.out.println ("die1 = " + value); value = d2.roll(); System.out.println ("die2 = " + value); value = d3.roll(); System.out.println ("die3 = " + value); d1.setNumSides(8); System.out.println ("die1 = " + d1.getNumSides()); } } /* Sample Output: die1 = 5 die2 = 5 die3 = 2 die1 = 8 */ Solution Hi, Please find mu code: import java.util.Random;
- 3. public class SuperDie { private int sides; private Random rand; public SuperDie(){ // Default constructor sides = 6; rand = new Random(); } // Constructor that lets user define number of sides n. public SuperDie(int n){ sides = n; rand = new Random(); } // Constructor that lets user define number of sides n AND provide their own Random object. public SuperDie(int n, Random r){ sides = n; rand = r; } public int getNumSides(){ return sides; } public void setNumSides(int n){ sides = n; } public int roll(){ return rand.nextInt(sides)+1; } } import java.util.*; class MainDie {
- 4. public static void main (String[] args) { int value, sides; Random rand = new Random(); SuperDie d1 = new SuperDie(); SuperDie d2 = new SuperDie(20); SuperDie d3 = new SuperDie(10,rand); value = d1.roll(); System.out.println ("die1 = " + value); value = d2.roll(); System.out.println ("die2 = " + value); value = d3.roll(); System.out.println ("die3 = " + value); d1.setNumSides(8); System.out.println ("die1 = " + d1.getNumSides()); } } /* Sample Output: die1 = 5 die2 = 5 die3 = 2 die1 = 8 */