The part a) seems to be correct. You got the equation for lnK and plotted the graph. As for the part b), you need to go back to the graph and figure out what happens with lnK with increasing temperature: if the temperature increases, then the 1/T decreases. So, on X axis we a going from the right to the left. This direction the lnK value increases. Therefore K increases. Bottom line, from the graph you see that increasing temperature shifts the equilibrium to the right (the products side). According to the Le Chatelier\'s principle for this reaction the equilibrium should shift to the products side with increasing temperature because the dissociation reaction is reaction endothermic and requires heat to proceed forward. Overall, the results from the graph are consistent with the Le Chatelier\'s principle. Solution The part a) seems to be correct. You got the equation for lnK and plotted the graph. As for the part b), you need to go back to the graph and figure out what happens with lnK with increasing temperature: if the temperature increases, then the 1/T decreases. So, on X axis we a going from the right to the left. This direction the lnK value increases. Therefore K increases. Bottom line, from the graph you see that increasing temperature shifts the equilibrium to the right (the products side). According to the Le Chatelier\'s principle for this reaction the equilibrium should shift to the products side with increasing temperature because the dissociation reaction is reaction endothermic and requires heat to proceed forward. Overall, the results from the graph are consistent with the Le Chatelier\'s principle..

1. The part a) seems to be correct. You got the equation for lnK and plotted the graph.
As for the part b), you need to go back to the graph and figure out what happens with lnK with
increasing temperature: if the temperature increases, then the 1/T decreases. So, on X axis we a
going from the right to the left. This direction the lnK value increases. Therefore K increases.
Bottom line, from the graph you see that increasing temperature shifts the equilibrium to the
right (the products side). According to the Le Chatelier's principle for this reaction the
equilibrium should shift to the products side with increasing temperature because the dissociation
reaction is reaction endothermic and requires heat to proceed forward. Overall, the results from
the graph are consistent with the Le Chatelier's principle.
Solution
The part a) seems to be correct. You got the equation for lnK and plotted the graph.
As for the part b), you need to go back to the graph and figure out what happens with lnK with
increasing temperature: if the temperature increases, then the 1/T decreases. So, on X axis we a
going from the right to the left. This direction the lnK value increases. Therefore K increases.
Bottom line, from the graph you see that increasing temperature shifts the equilibrium to the
right (the products side). According to the Le Chatelier's principle for this reaction the
equilibrium should shift to the products side with increasing temperature because the dissociation
reaction is reaction endothermic and requires heat to proceed forward. Overall, the results from
the graph are consistent with the Le Chatelier's principle.