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INDUSTRIAL 
PREPARATION OF AMMONIA
THE HABER PROCESS 
The Haber Process is a method which is used for the 
industrial preparation of ammonia from nitrogen and 
hydrogen under high pressure, optimum temperature and 
in the presence of catalyst .. Temperature, pressure and 
catalyst plays an important role in the economics of the 
process. 
A brief summary of the Haber Process 
The Haber Process combines nitrogen from the air with 
hydrogen derived mainly from natural gas (methane) into 
ammonia. The reaction is reversible and the production of 
ammonia is exothermic. 
A flow scheme for the Haber Process is as follows
The catalyst-- a substance that increases its efficiency 
. 
The pressure 
The pressure varies from one manufacturing plant to another, 
but is always high. 
Recycling 
At each pass of the gases through the reactor, only about 15% 
of the nitrogen and hydrogen converts to ammonia. (This figure 
also varies from plant to plant.) By continual recycling of the 
unreacted nitrogen and hydrogen, the overall conversion is 
about 98%. 
Explaining the conditions 
The proportions of nitrogen and hydrogen 
The mixture of nitrogen and hydrogen going into the reactor is in 
the ratio of 1 volume of nitrogen to 3 volumes of hydrogen. 
Avogadro's Law says that equal volumes of gases at the same 
temperature and pressure contain equal numbers of molecules. 
That means that the gases are going into the reactor in the ratio 
of 1 molecule of nitrogen to 3 of hydrogen. 
That is the proportion demanded by the equation.
The temperature 
Equilibrium considerations 
In order to produce the maximum possible amount of ammonia , 
the position of the equilibrium is to be shifted as far as possible 
to the right The forward reaction (the production of ammonia) is 
exothermic. 
this will be favoured only if the temperature.is lowered According 
to Le Chatelier's Principle, the system will respond by moving 
the position of equilibrium to cancel this - in other words by 
producing more heat. 
In order to get as much ammonia as possible temperatureis to 
be lowered as possible. 
Rate considerations 
The lower the temperature, the slower the reaction becomes. A 
manufacturer is trying to produce as much ammonia as possible 
per day. It makes no sense to try to achieve an equilibrium 
mixture which contains a very high proportion of ammonia if it 
takes several years for the reaction to reach that equilibrium. 
You need the gases to reach equilibrium within the very short 
time that they will be in contact with the catalyst in the reactor. 
The compromise 
400 - 450°C is a compromise temperature producing a 
reasonably high proportion of ammonia in the equilibrium 
mixture (even if it is only 15%), but in a very short time.
The pressure 
Equilibrium considerations 
there are 4 molecules on the left-hand side of the equation, but 
only 2 on the right. 
According to Le Chatelier's Principle, if you increase the 
pressure the system will respond by favouring the reaction which 
produces fewer molecules. That will cause the pressure to fall 
again. 
In order to get as much ammonia as possible in the equilibrium 
mixture, you need as high a pressure as possible. 200 
atmospheres is a high pressure 
Rate considerations 
Increasing the pressure brings the molecules closer together. In 
this particular instance, it will increase their chances of hitting 
and sticking to the surface of the catalyst where they can react. 
The higher the pressure the better in terms of the rate of a gas 
reaction. 
The catalyst 
Equilibrium considerations 
The catalyst has no effect whatsoever on the position of the 
equilibrium. Adding a catalyst doesn't produce any greater 
percentage of ammonia in the equilibrium mixture. Its only 
function is to speed up the reaction. 
Rate considerations 
In the absence of a catalyst the reaction is so slow that virtually 
no reaction happens in any sensible time. The catalyst ensures
that the reaction is fast enough for a dynamic equilibrium to be 
set up within the very short time that the gases are actually in 
the reactor. 
Separating the ammonia 
When the gases leave the reactor they are hot and at a very 
high pressure. Ammonia is easily liquefied under pressure as 
long as it isn't too hot, and so the temperature of the mixture is 
lowered enough for the ammonia to turn to a liquid. The nitrogen 
and hydrogen remain as gases even under these high 
pressures, and can be recycled. 
About reaction rates 
This is the equation for a general reaction which has reached dynamic equilibrium: 
At the beginning of the reaction, the concentrations of A and B were at their maximum. 
That means that the rate of the reaction was at its fastest. 
As A and B react, their concentrations fall. That means that they are less likely to collide 
and react, and so the rate of the forward reaction falls as time goes on. 
In the beginning, there isn't any C and D, so there can't be any reaction between them. 
As time goes on, though, their concentrations in the mixture increase and they are more 
likely to collide and react. 
With time, the rate of the reaction between C and D increases:
Eventually, the rates of the two reactions will become equal. A and B will be converting 
into C and D at exactly the same rate as C and D convert back into A and B again. 
At this point there won't be any further change in the amounts of A, B, C and D in the 
mixture. As fast as something is being removed, it is being replaced again by the 
reverse reaction. We have reached a position of dynamic equilibrium. 
A summary 
A dynamic equilibrium occurs when you have a reversible reaction in a closed system. 
Nothing can be added to the system or taken away from it apart from energy. 
At equilibrium, the quantities of everything present in the mixture remain constant, 
although the reactions are still continuing. This is because the rates of the forward and 
the back reactions are equal.
LE CHATELIER'S PRINCIPLE 
A statement of Le Chatelier's Principle 
 If a dynamic equilibrium is disturbed by 
changing the conditions, the position of 
equilibrium moves to cancel the change. 
Using Le Chatelier's Principle with a change of 
concentration 
Suppose an equilibrium established between four substances A, 
B, C and D. 
What would happen if you changed the conditions by 
increasing the concentration of A? 
According to Le Chatelier, the position of equilibrium will move in 
such a way as to cancel the change. That means that the 
position of equilibrium will move so that the concentration of A 
decreases again - by reacting it with B and turning it into C + D. 
The position of equilibrium moves to the right.
What would happen if you changed the conditions by 
decreasing the concentration of A? 
According to Le Chatelier, the position of equilibrium will move 
so that the concentration of A increases again. That means that 
more C and D will react to replace the A that has been removed. 
The position of equilibrium moves to the left. 
. 
Using Le Chatelier's Principle with a change of pressure 
This only applies to reactions involving gases: 
What would happen if you changed the conditions by 
increasing the pressure? 
According to Le Chatelier, the position of equilibrium will move in 
such a way as to Cancel the change. That means that the 
position of equilibrium will move so that the pressure is reduced 
again. 
Pressure is caused by gas molecules hitting the sides of their 
container. The more molecules you have in the container, the 
higher the pressure will be. The system can reduce the pressure 
by reacting in such a way as to produce fewer molecules.
In this case, there are 3 molecules on the left-hand side of the 
equation, but only 2 on the right. By forming more C and D, the 
system causes the pressure to reduce. 
Increasing the pressure on a gas reaction shifts the position of 
equilibrium towards the side with fewer molecules. 
What would happen if you changed the conditions by 
decreasing the pressure? 
The equilibrium will move in such a way that the pressure 
increases again. It can do that by producing more molecules. In 
this case, the position of equilibrium will move towards the left-hand 
side of the reaction. 
What happens if there are the same number of molecules 
on both sides of the equilibrium reaction? 
In this case, increasing the pressure has no effect whatsoever 
on the position of the equilibrium. Because you have the same 
numbers of molecules on both sides, the equilibrium can't move 
in any way that will reduce the pressure again.
Using Le Chatelier's Principle with a change of temperature 
. Assume that our forward reaction is exothermic (heat is 
evolved): 
This shows that 250 kJ is evolved (hence the negative sign) 
when 1 mole of A reacts completely with 2 moles of B. For 
reversible reactions, the value is always given as if the reaction 
was one-way in the forward direction. 
The back reaction (the conversion of C and D into A and B) 
would be endothermic by exactly the same amount. 
What would happen if you changed the conditions by 
increasing the temperature? 
According to Le Chatelier, the position of equilibrium will move in 
such a way as to cancel the change. That means that the 
position of equilibrium will move so that the temperature is 
reduced again. 
Suppose the system is in equilibrium at 300°C, and you increase 
the temperature to 500°C. How can the reaction counteract the 
change you have made? How can it cool itself down again? 
To cool down, it needs to absorb the extra heat that you have 
just put in. In the case we are looking at, the back 
reaction absorbs heat. The position of equilibrium therefore 
moves to the left. The new equilibrium mixture contains more A
and B, and less C and D. 
What would happen if you changed the conditions by 
decreasing the temperature? 
The equilibrium will move in such a way that the temperature 
increases again. 
Suppose the system is in equilibrium at 500°C and you reduce 
the temperature to 400°C. The reaction will tend to heat itself up 
again to return to the original temperature. It can do that by 
favouring the exothermic reaction. 
The position of equilibrium will move to the right. More A and B 
are converted into C and D at the lower temperature. 
Summary 
 Increasing the temperature of a system in dynamic 
equilibrium favours the endothermic reaction. The system 
counteracts the change you have made by absorbing the 
extra heat. 
 Decreasing the temperature of a system in dynamic 
equilibrium favours the exothermic reaction. The system 
counteracts the change you have made by producing 
more heat. 
.
Le Chatelier's Principle and catalysts 
adding a catalyst makes absolutely no difference to the 
position of equilibrium, and Le Chatelier's Principle doesn't 
apply to them. 
This is because a catalyst speeds up the forward and back 
reaction to the same extent. Because adding a catalyst doesn't 
affect the relative rates of the two reactions, it can't affect the 
position of equilibrium.

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Industrial preparation of ammonia

  • 2. THE HABER PROCESS The Haber Process is a method which is used for the industrial preparation of ammonia from nitrogen and hydrogen under high pressure, optimum temperature and in the presence of catalyst .. Temperature, pressure and catalyst plays an important role in the economics of the process. A brief summary of the Haber Process The Haber Process combines nitrogen from the air with hydrogen derived mainly from natural gas (methane) into ammonia. The reaction is reversible and the production of ammonia is exothermic. A flow scheme for the Haber Process is as follows
  • 3. The catalyst-- a substance that increases its efficiency . The pressure The pressure varies from one manufacturing plant to another, but is always high. Recycling At each pass of the gases through the reactor, only about 15% of the nitrogen and hydrogen converts to ammonia. (This figure also varies from plant to plant.) By continual recycling of the unreacted nitrogen and hydrogen, the overall conversion is about 98%. Explaining the conditions The proportions of nitrogen and hydrogen The mixture of nitrogen and hydrogen going into the reactor is in the ratio of 1 volume of nitrogen to 3 volumes of hydrogen. Avogadro's Law says that equal volumes of gases at the same temperature and pressure contain equal numbers of molecules. That means that the gases are going into the reactor in the ratio of 1 molecule of nitrogen to 3 of hydrogen. That is the proportion demanded by the equation.
  • 4. The temperature Equilibrium considerations In order to produce the maximum possible amount of ammonia , the position of the equilibrium is to be shifted as far as possible to the right The forward reaction (the production of ammonia) is exothermic. this will be favoured only if the temperature.is lowered According to Le Chatelier's Principle, the system will respond by moving the position of equilibrium to cancel this - in other words by producing more heat. In order to get as much ammonia as possible temperatureis to be lowered as possible. Rate considerations The lower the temperature, the slower the reaction becomes. A manufacturer is trying to produce as much ammonia as possible per day. It makes no sense to try to achieve an equilibrium mixture which contains a very high proportion of ammonia if it takes several years for the reaction to reach that equilibrium. You need the gases to reach equilibrium within the very short time that they will be in contact with the catalyst in the reactor. The compromise 400 - 450°C is a compromise temperature producing a reasonably high proportion of ammonia in the equilibrium mixture (even if it is only 15%), but in a very short time.
  • 5. The pressure Equilibrium considerations there are 4 molecules on the left-hand side of the equation, but only 2 on the right. According to Le Chatelier's Principle, if you increase the pressure the system will respond by favouring the reaction which produces fewer molecules. That will cause the pressure to fall again. In order to get as much ammonia as possible in the equilibrium mixture, you need as high a pressure as possible. 200 atmospheres is a high pressure Rate considerations Increasing the pressure brings the molecules closer together. In this particular instance, it will increase their chances of hitting and sticking to the surface of the catalyst where they can react. The higher the pressure the better in terms of the rate of a gas reaction. The catalyst Equilibrium considerations The catalyst has no effect whatsoever on the position of the equilibrium. Adding a catalyst doesn't produce any greater percentage of ammonia in the equilibrium mixture. Its only function is to speed up the reaction. Rate considerations In the absence of a catalyst the reaction is so slow that virtually no reaction happens in any sensible time. The catalyst ensures
  • 6. that the reaction is fast enough for a dynamic equilibrium to be set up within the very short time that the gases are actually in the reactor. Separating the ammonia When the gases leave the reactor they are hot and at a very high pressure. Ammonia is easily liquefied under pressure as long as it isn't too hot, and so the temperature of the mixture is lowered enough for the ammonia to turn to a liquid. The nitrogen and hydrogen remain as gases even under these high pressures, and can be recycled. About reaction rates This is the equation for a general reaction which has reached dynamic equilibrium: At the beginning of the reaction, the concentrations of A and B were at their maximum. That means that the rate of the reaction was at its fastest. As A and B react, their concentrations fall. That means that they are less likely to collide and react, and so the rate of the forward reaction falls as time goes on. In the beginning, there isn't any C and D, so there can't be any reaction between them. As time goes on, though, their concentrations in the mixture increase and they are more likely to collide and react. With time, the rate of the reaction between C and D increases:
  • 7. Eventually, the rates of the two reactions will become equal. A and B will be converting into C and D at exactly the same rate as C and D convert back into A and B again. At this point there won't be any further change in the amounts of A, B, C and D in the mixture. As fast as something is being removed, it is being replaced again by the reverse reaction. We have reached a position of dynamic equilibrium. A summary A dynamic equilibrium occurs when you have a reversible reaction in a closed system. Nothing can be added to the system or taken away from it apart from energy. At equilibrium, the quantities of everything present in the mixture remain constant, although the reactions are still continuing. This is because the rates of the forward and the back reactions are equal.
  • 8. LE CHATELIER'S PRINCIPLE A statement of Le Chatelier's Principle  If a dynamic equilibrium is disturbed by changing the conditions, the position of equilibrium moves to cancel the change. Using Le Chatelier's Principle with a change of concentration Suppose an equilibrium established between four substances A, B, C and D. What would happen if you changed the conditions by increasing the concentration of A? According to Le Chatelier, the position of equilibrium will move in such a way as to cancel the change. That means that the position of equilibrium will move so that the concentration of A decreases again - by reacting it with B and turning it into C + D. The position of equilibrium moves to the right.
  • 9. What would happen if you changed the conditions by decreasing the concentration of A? According to Le Chatelier, the position of equilibrium will move so that the concentration of A increases again. That means that more C and D will react to replace the A that has been removed. The position of equilibrium moves to the left. . Using Le Chatelier's Principle with a change of pressure This only applies to reactions involving gases: What would happen if you changed the conditions by increasing the pressure? According to Le Chatelier, the position of equilibrium will move in such a way as to Cancel the change. That means that the position of equilibrium will move so that the pressure is reduced again. Pressure is caused by gas molecules hitting the sides of their container. The more molecules you have in the container, the higher the pressure will be. The system can reduce the pressure by reacting in such a way as to produce fewer molecules.
  • 10. In this case, there are 3 molecules on the left-hand side of the equation, but only 2 on the right. By forming more C and D, the system causes the pressure to reduce. Increasing the pressure on a gas reaction shifts the position of equilibrium towards the side with fewer molecules. What would happen if you changed the conditions by decreasing the pressure? The equilibrium will move in such a way that the pressure increases again. It can do that by producing more molecules. In this case, the position of equilibrium will move towards the left-hand side of the reaction. What happens if there are the same number of molecules on both sides of the equilibrium reaction? In this case, increasing the pressure has no effect whatsoever on the position of the equilibrium. Because you have the same numbers of molecules on both sides, the equilibrium can't move in any way that will reduce the pressure again.
  • 11. Using Le Chatelier's Principle with a change of temperature . Assume that our forward reaction is exothermic (heat is evolved): This shows that 250 kJ is evolved (hence the negative sign) when 1 mole of A reacts completely with 2 moles of B. For reversible reactions, the value is always given as if the reaction was one-way in the forward direction. The back reaction (the conversion of C and D into A and B) would be endothermic by exactly the same amount. What would happen if you changed the conditions by increasing the temperature? According to Le Chatelier, the position of equilibrium will move in such a way as to cancel the change. That means that the position of equilibrium will move so that the temperature is reduced again. Suppose the system is in equilibrium at 300°C, and you increase the temperature to 500°C. How can the reaction counteract the change you have made? How can it cool itself down again? To cool down, it needs to absorb the extra heat that you have just put in. In the case we are looking at, the back reaction absorbs heat. The position of equilibrium therefore moves to the left. The new equilibrium mixture contains more A
  • 12. and B, and less C and D. What would happen if you changed the conditions by decreasing the temperature? The equilibrium will move in such a way that the temperature increases again. Suppose the system is in equilibrium at 500°C and you reduce the temperature to 400°C. The reaction will tend to heat itself up again to return to the original temperature. It can do that by favouring the exothermic reaction. The position of equilibrium will move to the right. More A and B are converted into C and D at the lower temperature. Summary  Increasing the temperature of a system in dynamic equilibrium favours the endothermic reaction. The system counteracts the change you have made by absorbing the extra heat.  Decreasing the temperature of a system in dynamic equilibrium favours the exothermic reaction. The system counteracts the change you have made by producing more heat. .
  • 13. Le Chatelier's Principle and catalysts adding a catalyst makes absolutely no difference to the position of equilibrium, and Le Chatelier's Principle doesn't apply to them. This is because a catalyst speeds up the forward and back reaction to the same extent. Because adding a catalyst doesn't affect the relative rates of the two reactions, it can't affect the position of equilibrium.