1. Prepared By Mr Seelan 3cm
Hp: 90691139
Home use only
3cm
3cm
15 cm
3cm
3cm
52 more cubes
3cm 3cm 3cm 3cm
12cm
Needed = 5 + 11 + 12 + 12 + 12 = 52 more cubes
Mark out theFirstrd layer needsaddcubescubes each
Similarly,Mark out th layersneeds 12first the height
2nd3 and 5 need to required for
remaining layerare needed
4thlayer needdimensionscubes
52 more the to 12 11cubes
layer cubes add 5

2. x 4 parts = 12 units
9
3 1 part = 3 units
x3 x y
1 x3
3 5 parts = 15 units
3 + 12
3 Shaded Area of Y : Total area of figure
z 3 : 3 + 12 + 9 +5
5 3 : 29
Prepared By Mr Seelan
Hp: 90691139
Home use only z
Divide 15 unitsArea 3 isYto 3 and29 units parts
Shaded is 3whole unshadedthe 5 parts
Make both shaded 29 is unshaded
Area ofinto of figure
1 part, = units is 3
shaded units same

3. 2
The height of triangle AEC is 3 times the height of triangle ADC. The shaded area is 34 cm
Find the length of the base AC. E
2cm
2
34cm
D 2cm6cm Divide this into 3 units
2cm 2cm
A C
B
17cm
Height of triangle ADC = 6cm ÷ 3 = 2cm
Area = 1 unit
Area of triangle ADC = 1 x Base x Height
2
17 = 1 x AC x 2 cm 2
2 2 units = 34 cm2
AC = 17 cm 1 unit = 34 cm ÷ 2
Area = 3units 2
= 17 cm
Prepared By Mr Seelan
Hp: 90691139
Home use only
DB ismanyAEC2cm the shadedof ADC. So area=of AEC is also 3 times that of ADC.
How equalunits is times that area?
Shaded of to is units
Height area is 2 3 AC 17 cm

4. 2
= 36cm
At first 5u : 2u
- Area R S - Area
3P
5u
3 : 1
p p
CUT 9cm 2 CUT
6cm
1P
2u
CUT18
u
u 18
6cm 2
3p u 18 Area of rectangle at first = 6cm x 6cm = 36cm
2p CUT 18
u 18 u 2 u = 36 cm 2 2
u 18 u 18 1p 1 u = 36 cm 2 ÷ 2 =18cm
2 p = 18 cm 2 X 3 36 cm 2
Rectangle Square
= 54cm 2 - 27 cm 2
Prepared By Mr Seelan
1 p = 54cm 2 ÷ 2 = 27cm 2 2 =9cm2
Hp: 90691139
Home use only AfterCut the Separate theRectanglethe3cm–squareandunits 1 part
shadedshaded cut, 5 = AreaisAreapartssquarethe end
Area ofareaAfter of for bothatand of squareSquare
Area of rectangle square , isfirstthe and 2 square
shaded partrectangle 36 rectangle in
is area units Area

5. X = 1 unit, rectangle A = 8 units Prepared By Mr Seelan
Hp: 90691139
Home use only
X = 1 unit, rectangle B = 6 units
3 boxes = 9cm 2 boxes = 4cm
1 box = 9cm ÷ 3 1 box = 4cm ÷ 2
8 7 6 5 = 3cm = 2cm
2 2 2 2
6 cm 6 cm 6 cm 6 cm Area of small rectangle =3cm x 2cm
2
3cm = 6 cm
4 3 2 1 2 3 9cm
2 2 2
A
6 cm 6 cm 6 cm x 2 2
6 cm 1 6 cm 2 3
4 5
x6 2
6 cm 6 cm
2 2cm
2 2 2 4cm
6 cm 6 cm 4 6 cm 5 6
2 2 2
6 cm 6 B B cm 6 cm
2 B
Area of unshaded part = 12 boxes x 6 cm
2
= 72 cm
2
Raffles SA1 2010
5/23/2012 Mr Seelan Ans : Area of unshaded part is 72 cm
Hp: 90691139 5

6. Total boxes = 15 boxes
Make all boxes $540equal size
15 boxes = into
Henry Park SA1 2009 Extend the= $540boxes to make the same size as the big boxes
1 box small ÷ 15
= $36
Ans: a) The badminton racket cost $21
Ans: b) The tennis racket cost $342
$36 1 badminton racket cost = $36 -$15
Badminton $21 $15
? = $21
1 badminton racket
racket 1 1 Tennis racket cost = $57 x 6
= $342
2 soccer balls
1 soccer ball
Soccer Ball 2 3 1 tennis racket
$435+$15+$15+$15
$15 $15 $15 $15 $15 $15 +$15 +$15 +$15+$15
Tennis 4 5
$21 6
$21 $21 $15 $21
7 8 9
$21
= $540
racket
$36 $36 $36 $36 $36
10 11 12 13 14 15
5/23/2012 $57 $57Mr Seelan Hp: 90691139
$57 $57 $57 $57 6
1 time 2 times 3 times 4 times 5 times 6 times

7. June = 3 boxes
same Amy = 7 boxes
$60
$20 same
$60
Divide this into 3 boxes Divide this into 3 boxes 3 boxes = $180
1 box = $180 ÷ 3 boxes
= $60
3 small boxes = $60
$60 1 small box = $60 ÷ 3 boxes
= $20
$60 $180
$60
Amy and Susan each pay = $60 + $20
Susan = $80
June Amy
Prepared By Mr Seelan
Hp: 90691139 Home use only Ans: $80 each
Raffles SA2
5/23/2012 2010 Mr Seelan Hp: 90691139 7