C Program to shuffle a given Aay#include stdio.h #include .pdf

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// C Program to shuffle a given Aay #include #include #include // A utility function to print an Aay void printArray (int A[], int n) { int i; for (i = 0; i < n; i++) printf(\"%d \", A[i]); printf(\"\ \"); } int* shuffle(int A[], int B[]) { int n1 = 5; int n2 = 2; int i = 0, j = 0, k = 0; int *C; C = (int*)malloc(7 * sizeof(int)); // Merging starts while (i < n1 && j < n2) { if (k%2 == 0) { C[k] = A[i]; i++; k++; } else { C[k] = B[j]; k++; j++; } } /* elements in array \'A\' are still remaining where as the array \'B\' is exhausted */ while (i < n1) { C[k] = A[i]; i++; k++; } /* elements in array \'B\' are still remaining where as the array \'A\' is exhausted */ while (j < n2) { C[k] = B[j]; k++; j++; } return C; } int main() { int A[] = {1, 2, 3, 4, 5}; int B[] = {10, 20}; int n1 = 5; int n2 = 2; int nC = 7; int *C; C = (int*)malloc(7 * sizeof(int)); printf(\"Array A: \"); printArray(A, n1); printf(\"Array B: \"); printArray(B, n2); C = shuffle (A, B); printf(\"\ Shuffled: \"); printArray(C,nC); return 0; } /* output: Array A: 1 2 3 4 5 Array B: 10 20 Shuffled: 1 10 2 20 3 4 5 */ Solution // C Program to shuffle a given Aay #include #include #include // A utility function to print an Aay void printArray (int A[], int n) { int i; for (i = 0; i < n; i++) printf(\"%d \", A[i]); printf(\"\ \"); } int* shuffle(int A[], int B[]) { int n1 = 5; int n2 = 2; int i = 0, j = 0, k = 0; int *C; C = (int*)malloc(7 * sizeof(int)); // Merging starts while (i < n1 && j < n2) { if (k%2 == 0) { C[k] = A[i]; i++; k++; } else { C[k] = B[j]; k++; j++; } } /* elements in array \'A\' are still remaining where as the array \'B\' is exhausted */ while (i < n1) { C[k] = A[i]; i++; k++; } /* elements in array \'B\' are still remaining where as the array \'A\' is exhausted */ while (j < n2) { C[k] = B[j]; k++; j++; } return C; } int main() { int A[] = {1, 2, 3, 4, 5}; int B[] = {10, 20}; int n1 = 5; int n2 = 2; int nC = 7; int *C; C = (int*)malloc(7 * sizeof(int)); printf(\"Array A: \"); printArray(A, n1); printf(\"Array B: \"); printArray(B, n2); C = shuffle (A, B); printf(\"\ Shuffled: \"); printArray(C,nC); return 0; } /* output: Array A: 1 2 3 4 5 Array B: 10 20 Shuffled: 1 10 2 20 3 4 5 */.

// C Program to shuffle a given Aay
#include
#include
#include
// A utility function to print an Aay
void printArray (int A[], int n)
{
int i;
for (i = 0; i < n; i++)
printf("%d ", A[i]);
printf(" ");
}
int* shuffle(int A[], int B[])
{
int n1 = 5;
int n2 = 2;
int i = 0, j = 0, k = 0;
int *C;
C = (int*)malloc(7 * sizeof(int));
// Merging starts
while (i < n1 && j < n2)
{
if (k%2 == 0)
{
C[k] = A[i];
i++;
k++;
}
else
{
C[k] = B[j];
k++;
j++;
}

}
/* elements in array 'A' are still remaining
where as the array 'B' is exhausted */
while (i < n1)
{
C[k] = A[i];
i++;
k++;
}
/* elements in array 'B' are still remaining
where as the array 'A' is exhausted */
while (j < n2)
{
C[k] = B[j];
k++;
j++;
}
return C;
}
int main()
{
int A[] = {1, 2, 3, 4, 5};
int B[] = {10, 20};
int n1 = 5;
int n2 = 2;
int nC = 7;
int *C;
C = (int*)malloc(7 * sizeof(int));
printf("Array A: ");
printArray(A, n1);
printf("Array B: ");
printArray(B, n2);

C = shuffle (A, B);
printf(" Shuffled: ");
printArray(C,nC);
return 0;
}
/*
output:
Array A: 1 2 3 4 5
Array B: 10 20
Shuffled: 1 10 2 20 3 4 5
*/
Solution
// C Program to shuffle a given Aay
#include
#include
#include
// A utility function to print an Aay
void printArray (int A[], int n)
{
int i;
for (i = 0; i < n; i++)
printf("%d ", A[i]);
printf(" ");
}
int* shuffle(int A[], int B[])
{
int n1 = 5;
int n2 = 2;
int i = 0, j = 0, k = 0;
int *C;

C = (int*)malloc(7 * sizeof(int));
// Merging starts
while (i < n1 && j < n2)
{
if (k%2 == 0)
{
C[k] = A[i];
i++;
k++;
}
else
{
C[k] = B[j];
k++;
j++;
}
}
/* elements in array 'A' are still remaining
where as the array 'B' is exhausted */
while (i < n1)
{
C[k] = A[i];
i++;
k++;
}
/* elements in array 'B' are still remaining
where as the array 'A' is exhausted */
while (j < n2)
{
C[k] = B[j];
k++;
j++;

}
return C;
}
int main()
{
int A[] = {1, 2, 3, 4, 5};
int B[] = {10, 20};
int n1 = 5;
int n2 = 2;
int nC = 7;
int *C;
C = (int*)malloc(7 * sizeof(int));
printf("Array A: ");
printArray(A, n1);
printf("Array B: ");
printArray(B, n2);
C = shuffle (A, B);
printf(" Shuffled: ");
printArray(C,nC);
return 0;
}
/*
output:
Array A: 1 2 3 4 5
Array B: 10 20
Shuffled: 1 10 2 20 3 4 5
*/

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1) List currently running jobs ANS) see currently running command: ps examples: $ps 2.Kill one of the running jobs ANS) a.kill any process by PID command: kill {PID} example: $kill 1012 3.Run the ls command with –help option ANS) ls command: ls command is used to list the contents of a directory Syntax: ls [-a] [-A] [-b] [-c] [-C] [-d] [-f] [-F] [-g] [-i] [-l] [-L] [-m] [-o] [-p][-q] [-r] [-R] [-s] [-t] [-u] [-x] [pathnames] Parameters OR Switches • -a Shows All The Files, Including Hidden File Which Begin With ADot. • -A Shows All The Files Including Hidden Files. Does Not Displays The Working Directory (.) OR The Parent Directory (..) • -b Force Printing of Non-Printable Characters To Be in Octal \\ddd Notation. • -c Use Time of Last Modification of The i-Node For Sorting (-t) OR For Printing (-l OR -n) • -C Multi-Column Output With Entries Sorted Down The Columns. Which is Generally The Default Option. • -d Lists Only The Directory Names But Not its Contents. • -f Force Each Argument To Be Interpreted As A Directory And List The Name Found in Each Slot. -f Option Turns off -l, -t, -s, And -r, And Turns on –a, The List Order is The Order in Which Entries Appear in The Directory. • -F Mark Directories With A Trailing Slash (/), DOORS With A Trailing Greater-Than Sign (>), Executable Files With A Trailing Asterisk (*), FIFOs With A Trailing Vertical Bar (|), Symbolic Links With A Trailing Equals Sign (=). • -g Same As -l Parameter, Except The Owner is Not Printed. • -i For Each File, Prints The i-Node Number in The First Column. • -l Shows The User With Huge Amounts of Information With Permissions, Owners, Size, And When Last Modified.) • -L If An Argument is A Symbolic Link, List The File OR Directory To Which The Link References Rather Than The Link Itself. • -m Stream Output Format, In This Files Are Listed Across The Page, Separated By Commas. • -n Same As –l Parameter, Except That The Owner\'s UID And Group\'s GID Numbers Are Printed, Rather Than The Associated Character Strings. -o The Same As -l, Except That The Group is Not Printed. -p Displays A Forward Slash (/) in Front of All Directories. -q Force Printing of Non-Printable Characters in File Names As The Character Question Mark (?). -r Reverses The Order of How The Files Are Displayed. -R Includes The Contents of Subdirectories. -s Give Size in Blocks, Including Indirect Blocks, For Each Entry. -t Shows The End User The Files Modification Time. -u Use Time of Last Access Instead of Last Modification For Sorting Use With The -t Option OR For Printing Use With The -l Option. -x Displays Files in Columns. -1 Prints One Entry Per Line of Output. pathnames File OR Directory To List. 4.Run the help command on echo ANS) echo command display to the Screen. “echo” is Useful For • Producing Diagnostics in Command Files • For Sending Known Data into A Pipe • For Displaying The Contents of Environment Variables syntax: echo [-n] text 5.Cat an existing file using a command that misspells one c.

1) List currently running jobsANS) see currently runningcommand.pdf

1) List currently running jobsANS) see currently runningcommand.pdf

1) List currently running jobsANS) see currently runningcommand.pdf

Step1 Total pressure = partial pressure of Hydrogen + Vapour pressure of water at the given temperature. Step2 Partial pressure of Hydrogen = 767 - Vapour pressure of water at 295.3 K Step3 = 767.0- 20.2 = 746.8 torr Solution Step1 Total pressure = partial pressure of Hydrogen + Vapour pressure of water at the given temperature. Step2 Partial pressure of Hydrogen = 767 - Vapour pressure of water at 295.3 K Step3 = 767.0- 20.2 = 746.8 torr.

Step1 Total pressure = partial pressure of Hydrog.pdf

Step1 Total pressure = partial pressure of Hydrog.pdf

Step1 Total pressure = partial pressure of Hydrog.pdf

I would say very many elements exista as monoatomic molecules.All the metals,for example.Don\'t get confused by the fact that if metals have a crystaline structure,then the molecules would be composed by more than one atoms... An Element Is A Single Atom. No, an element is any material that is composed of only a single kind of atom (ie: all its atoms are identical) While A Molecule Is A Group Of Atoms That Are Bond Together To Form Another Compounds... A molecule is a group of atoms that are bonded together, but they do not form a compound. A compound is is something whose molecules contain more than one kind of atom. Some Elements Exist As A Diatomic Atom. Some elements are a collection of diatomic molecules. You can not have a diatomic atom - that\'s self-contradictory. Example Of These Are Hydrogen And The Halogens Family( Chlorine. Fluorine Etc.) In Case Of Hydrogen. Hydrogen Is A Diatomic Atom. If The Hydrogen Bonded To Other Elements This Is An Example Of Molecule... Hydrogen is made up of diatomic molecules. If hydrogen bonds with atoms of another element you get a compound. In Short Element Is A Single Atom While Molecule Composed Of 2 Or More Atoms That Are Bonded Together. You can not compare an element and a molecule. You can compare an element and a compound. An element is made of only a single kind of atom - whether as a crystal (Fe), or isolated atoms (He) or as molecules (H2), does not matter. A compound is made up of molecules (or crystals) with more than one kind of atom (NH3, H2O, NaCl) Solution I would say very many elements exista as monoatomic molecules.All the metals,for example.Don\'t get confused by the fact that if metals have a crystaline structure,then the molecules would be composed by more than one atoms... An Element Is A Single Atom. No, an element is any material that is composed of only a single kind of atom (ie: all its atoms are identical) While A Molecule Is A Group Of Atoms That Are Bond Together To Form Another Compounds... A molecule is a group of atoms that are bonded together, but they do not form a compound. A compound is is something whose molecules contain more than one kind of atom. Some Elements Exist As A Diatomic Atom. Some elements are a collection of diatomic molecules. You can not have a diatomic atom - that\'s self-contradictory. Example Of These Are Hydrogen And The Halogens Family( Chlorine. Fluorine Etc.) In Case Of Hydrogen. Hydrogen Is A Diatomic Atom. If The Hydrogen Bonded To Other Elements This Is An Example Of Molecule... Hydrogen is made up of diatomic molecules. If hydrogen bonds with atoms of another element you get a compound. In Short Element Is A Single Atom While Molecule Composed Of 2 Or More Atoms That Are Bonded Together. You can not compare an element and a molecule. You can compare an element and a compound. An element is made of only a single kind of atom - whether as a crystal (Fe), or isolated atoms (He) or as molecules (H2), does not matter. A compound is made up of .

I would say very many elements exista as monoatom.pdf

I would say very many elements exista as monoatom.pdf

I would say very many elements exista as monoatom.pdf

E is simply hexane...no polarity at all...nothing to speak of has extra electron density. A is a benzene ring, and if you play with the resonance you will see that sometimes the electrons can be in many different places which will make it polar at those times. :) nate Solution E is simply hexane...no polarity at all...nothing to speak of has extra electron density. A is a benzene ring, and if you play with the resonance you will see that sometimes the electrons can be in many different places which will make it polar at those times. :) nate.

E is simply hexane...no polarity at all...nothing.pdf

E is simply hexane...no polarity at all...nothing.pdf

E is simply hexane...no polarity at all...nothing.pdf

Ferroxyl contains the chemical compound Potassium ferricyanide which reacts with the ferrous ions to produce the color \"Prussian blue\". Iron is being oxidized at the anode and creating Ferrous (Fe+2) ions. Therefore, with the introduction of Ferroxyl, the anode will turn blue as the Ferroxyl reacts with the Ferrous ions. It is also worth noting that this is a acidic solution and the blue pigment is insoluble in water. This is useful in detecting metal oxidation that leads to rust. Same thing basically for the OH. Solution Ferroxyl contains the chemical compound Potassium ferricyanide which reacts with the ferrous ions to produce the color \"Prussian blue\". Iron is being oxidized at the anode and creating Ferrous (Fe+2) ions. Therefore, with the introduction of Ferroxyl, the anode will turn blue as the Ferroxyl reacts with the Ferrous ions. It is also worth noting that this is a acidic solution and the blue pigment is insoluble in water. This is useful in detecting metal oxidation that leads to rust. Same thing basically for the OH..

Ferroxyl contains the chemical compound Potassium.pdf

Ferroxyl contains the chemical compound Potassium.pdf

Ferroxyl contains the chemical compound Potassium.pdf

There are two different types of mechanisms. There are elimination and substitution reactions. The elimination reaction is when there is a proton transfer and loss of leaving group taking place. The substitution reaction is when there is a loss of leaving group and nucleophlic attack. From what we see in this reaction, we see that there is a nucleophilic attack with the MeI and OH. So this is a substitution reaction. Now to determine whether it is SN1 or SN2, we would have to look at the reaction. There is a tertary compound, which favors SN1 reactions better than SN2. The final answer would be SN1. I hope this makes sense. Let me know if anything is unclear. Solution There are two different types of mechanisms. There are elimination and substitution reactions. The elimination reaction is when there is a proton transfer and loss of leaving group taking place. The substitution reaction is when there is a loss of leaving group and nucleophlic attack. From what we see in this reaction, we see that there is a nucleophilic attack with the MeI and OH. So this is a substitution reaction. Now to determine whether it is SN1 or SN2, we would have to look at the reaction. There is a tertary compound, which favors SN1 reactions better than SN2. The final answer would be SN1. I hope this makes sense. Let me know if anything is unclear..

There are two different types of mechanisms. Ther.pdf

There are two different types of mechanisms. Ther.pdf

There are two different types of mechanisms. Ther.pdf

What must be true about a set of data when its standard deviation is.pdf

What must be true about a set of data when its standard deviation is.pdf

What must be true about a set of data when its standard deviation is.pdf

When one drives from sea level to trailhead in high Sierras, altitude increases. At higher altitudes, atmospheric pressure drops and so does the oxygen content of the air. We run out of enough oxygen in blood for our brain and body that leads to dizziness and heavy breathing. This is detrimental as it can even stop our brain due to lack of oxygen. These symptoms are collectively called Altitude sickness which reduces, as one spends some time in such region as our body gets acclimatized to such environment. Solution When one drives from sea level to trailhead in high Sierras, altitude increases. At higher altitudes, atmospheric pressure drops and so does the oxygen content of the air. We run out of enough oxygen in blood for our brain and body that leads to dizziness and heavy breathing. This is detrimental as it can even stop our brain due to lack of oxygen. These symptoms are collectively called Altitude sickness which reduces, as one spends some time in such region as our body gets acclimatized to such environment..

When one drives from sea level to trailhead in high Sierras, altitud.pdf

When one drives from sea level to trailhead in high Sierras, altitud.pdf

When one drives from sea level to trailhead in high Sierras, altitud.pdf

the reaction as follows- 14N7 + 0n1 -- 4He2 + 1.pdf

the reaction as follows- 14N7 + 0n1 -- 4He2 + 1.pdf

the reaction as follows- 14N7 + 0n1 -- 4He2 + 1.pdf

The important thing here is to understand the Standard Electrode Potential for each of our metals involved. Whichever of the metals has a larger negative number is the one that will be our anode, the other will be our cathode. Therefore, for this reaction, we know that Aluminum is going to be our anode. With this reasoning, we know that where the anode is, so will oxidation occur. If we think about it, where oxidation is occurring, the metal (in this case Aluminum) is giving up electrons and feeding it to the other side. Since we know the salt bridge is there to balance out the lost electrons from the oxidation side, we know that the NO3- are going to flow to the left hand side to make up for the electrons that are going from the left hand side to the right hand side. Your salt bridge sends anions to the left hand side! Hope this helps! Solution The important thing here is to understand the Standard Electrode Potential for each of our metals involved. Whichever of the metals has a larger negative number is the one that will be our anode, the other will be our cathode. Therefore, for this reaction, we know that Aluminum is going to be our anode. With this reasoning, we know that where the anode is, so will oxidation occur. If we think about it, where oxidation is occurring, the metal (in this case Aluminum) is giving up electrons and feeding it to the other side. Since we know the salt bridge is there to balance out the lost electrons from the oxidation side, we know that the NO3- are going to flow to the left hand side to make up for the electrons that are going from the left hand side to the right hand side. Your salt bridge sends anions to the left hand side! Hope this helps!.

The important thing here is to understand the Standard Electrode Pot.pdf

The important thing here is to understand the Standard Electrode Pot.pdf

The important thing here is to understand the Standard Electrode Pot.pdf

The pathway would be overactive.The GTPase activity of the alpha s.pdf

The pathway would be overactive.The GTPase activity of the alpha s.pdf

The pathway would be overactive.The GTPase activity of the alpha s.pdf

The metal ion is Pb2+.The white precipitate PbCl2 is insoluble in .pdf

The metal ion is Pb2+.The white precipitate PbCl2 is insoluble in .pdf

The metal ion is Pb2+.The white precipitate PbCl2 is insoluble in .pdf

The electron carriers that feed into the ETC are NADH and FADH2.NA.pdf

The electron carriers that feed into the ETC are NADH and FADH2.NA.pdf

The electron carriers that feed into the ETC are NADH and FADH2.NA.pdf

The developmental potential, or potency of a cell, describes the range of different cell types it can become. Therefore it involves. The determination means a cell restricts itself choosing a particular fate. Differentiation follows determination and the cell becomes a specific cell type ultimately. Solution The developmental potential, or potency of a cell, describes the range of different cell types it can become. Therefore it involves. The determination means a cell restricts itself choosing a particular fate. Differentiation follows determination and the cell becomes a specific cell type ultimately..

The developmental potential, or potency of a cell, describes the ran.pdf

The developmental potential, or potency of a cell, describes the ran.pdf

The developmental potential, or potency of a cell, describes the ran.pdf

//Tested on linux,ubuntu #include #include #include #include #include /*Main function start*/ int main(int argc, char *argv[]) { /*variable for buffer*/ struct stat statbuf; /*pointer variable declaration*/ DIR *dp; struct dirent *dirp; /*if we are not providing file path then it will take current directory as name*/ if(argc==1) { dp = opendir(\"./\"); } else { dp = opendir(argv[1]); } while ( (dirp=readdir(dp)) != NULL) { /*lstat - get symbolic link status * Please readabout lstat more*/ lstat(dirp->d_name, &statbuf); /*checking it is directory or not*/ if(S_ISDIR(statbuf.st_mode)) { /*it is printing directory name with /*/ printf(\"%s/ \ \", dirp->d_name); } else { /*If it is file then we are printing only name of file*/ printf(\"%s\ \", dirp->d_name); } } /*cosing directory pointer*/ closedir(dp); exit(0); } /*main function end*/ /**********output**********/ gopal@gopal:~/Desktop/chegg$ gcc directory.c gopal@gopal:~/Desktop/chegg$ ./a.out dLinkedList.c random.c jasmin/ LinkedStack.cpp VideoGame.java LinkedStack.cpp Client.class web.xml ../ TemplateMain.cpp Energy.py PrecondViolatedExcept.h CSA.cpp BoxofProduce.cpp ./ Unanswere/ Tree.c target/ readFile.c inventory.txt goodQuestion interest.c VideoGameManager.java Thanks a lot Solution //Tested on linux,ubuntu #include #include #include #include #include /*Main function start*/ int main(int argc, char *argv[]) { /*variable for buffer*/ struct stat statbuf; /*pointer variable declaration*/ DIR *dp; struct dirent *dirp; /*if we are not providing file path then it will take current directory as name*/ if(argc==1) { dp = opendir(\"./\"); } else { dp = opendir(argv[1]); } while ( (dirp=readdir(dp)) != NULL) { /*lstat - get symbolic link status * Please readabout lstat more*/ lstat(dirp->d_name, &statbuf); /*checking it is directory or not*/ if(S_ISDIR(statbuf.st_mode)) { /*it is printing directory name with /*/ printf(\"%s/ \ \", dirp->d_name); } else { /*If it is file then we are printing only name of file*/ printf(\"%s\ \", dirp->d_name); } } /*cosing directory pointer*/ closedir(dp); exit(0); } /*main function end*/ /**********output**********/ gopal@gopal:~/Desktop/chegg$ gcc directory.c gopal@gopal:~/Desktop/chegg$ ./a.out dLinkedList.c random.c jasmin/ LinkedStack.cpp VideoGame.java LinkedStack.cpp Client.class web.xml ../ TemplateMain.cpp Energy.py PrecondViolatedExcept.h CSA.cpp BoxofProduce.cpp ./ Unanswere/ Tree.c target/ readFile.c inventory.txt goodQuestion interest.c VideoGameManager.java Thanks a lot.

Tested on linux,ubuntu#include stdlib.h #include systypes..pdf

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UChicago CMSC 23320 - The Best Commit Messages of 2024

UChicago CMSC 23320 - The Best Commit Messages of 2024

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When Quality Assurance Meets Innovation in Higher Education - Report launch w...

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8 Tips for Effective Working Capital Management

8 Tips for Effective Working Capital Management

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Transparency, Recognition and the role of eSealing - Ildiko Mazar and Koen No...

Transparency, Recognition and the role of eSealing - Ildiko Mazar and Koen No...

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Stl Algorithms in C++ jjjjjjjjjjjjjjjjjj

Stl Algorithms in C++ jjjjjjjjjjjjjjjjjj

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Trauma-Informed Leadership - Five Practical Principles

Trauma-Informed Leadership - Five Practical Principles

The Story of Village Palampur Class 9 Free Study Material PDF

The Story of Village Palampur Class 9 Free Study Material PDF

The Story of Village Palampur Class 9 Free Study Material PDF

Analyzing and resolving a communication crisis in Dhaka textiles LTD.pptx

Analyzing and resolving a communication crisis in Dhaka textiles LTD.pptx

Analyzing and resolving a communication crisis in Dhaka textiles LTD.pptx

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ĐỀ THAM KHẢO KÌ THI TUYỂN SINH VÀO LỚP 10 MÔN TIẾNG ANH FORM 50 CÂU TRẮC NGHI...

ĐỀ THAM KHẢO KÌ THI TUYỂN SINH VÀO LỚP 10 MÔN TIẾNG ANH FORM 50 CÂU TRẮC NGHI...

Mattingly "AI & Prompt Design: Named Entity Recognition"

Mattingly "AI & Prompt Design: Named Entity Recognition"

Mattingly "AI & Prompt Design: Named Entity Recognition"

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The Liver & Gallbladder (Anatomy & Physiology).pptx

The Liver & Gallbladder (Anatomy & Physiology).pptx

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DEMONSTRATION LESSON IN ENGLISH 4 MATATAG CURRICULUM

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SURVEY I created for uni project research

SURVEY I created for uni project research

SURVEY I created for uni project research

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Mattingly "AI and Prompt Design: LLMs with NER"

Mattingly "AI and Prompt Design: LLMs with NER"

C Program to shuffle a given Aay#include stdio.h #include .pdf

1. // C Program to shuffle a given Aay #include #include #include // A utility function to print an Aay void printArray (int A[], int n) { int i; for (i = 0; i < n; i++) printf("%d ", A[i]); printf(" "); } int* shuffle(int A[], int B[]) { int n1 = 5; int n2 = 2; int i = 0, j = 0, k = 0; int *C; C = (int*)malloc(7 * sizeof(int)); // Merging starts while (i < n1 && j < n2) { if (k%2 == 0) { C[k] = A[i]; i++; k++; } else { C[k] = B[j]; k++; j++; }

2. } /* elements in array 'A' are still remaining where as the array 'B' is exhausted */ while (i < n1) { C[k] = A[i]; i++; k++; } /* elements in array 'B' are still remaining where as the array 'A' is exhausted */ while (j < n2) { C[k] = B[j]; k++; j++; } return C; } int main() { int A[] = {1, 2, 3, 4, 5}; int B[] = {10, 20}; int n1 = 5; int n2 = 2; int nC = 7; int *C; C = (int*)malloc(7 * sizeof(int)); printf("Array A: "); printArray(A, n1); printf("Array B: "); printArray(B, n2);

3. C = shuffle (A, B); printf(" Shuffled: "); printArray(C,nC); return 0; } /* output: Array A: 1 2 3 4 5 Array B: 10 20 Shuffled: 1 10 2 20 3 4 5 */ Solution // C Program to shuffle a given Aay #include #include #include // A utility function to print an Aay void printArray (int A[], int n) { int i; for (i = 0; i < n; i++) printf("%d ", A[i]); printf(" "); } int* shuffle(int A[], int B[]) { int n1 = 5; int n2 = 2; int i = 0, j = 0, k = 0; int *C;

4. C = (int*)malloc(7 * sizeof(int)); // Merging starts while (i < n1 && j < n2) { if (k%2 == 0) { C[k] = A[i]; i++; k++; } else { C[k] = B[j]; k++; j++; } } /* elements in array 'A' are still remaining where as the array 'B' is exhausted */ while (i < n1) { C[k] = A[i]; i++; k++; } /* elements in array 'B' are still remaining where as the array 'A' is exhausted */ while (j < n2) { C[k] = B[j]; k++; j++;

5. } return C; } int main() { int A[] = {1, 2, 3, 4, 5}; int B[] = {10, 20}; int n1 = 5; int n2 = 2; int nC = 7; int *C; C = (int*)malloc(7 * sizeof(int)); printf("Array A: "); printArray(A, n1); printf("Array B: "); printArray(B, n2); C = shuffle (A, B); printf(" Shuffled: "); printArray(C,nC); return 0; } /* output: Array A: 1 2 3 4 5 Array B: 10 20 Shuffled: 1 10 2 20 3 4 5 */