the reaction as follows:- 14N7 + 0n1 --> 4He2 + 10C6 so, the nuclide produced When Nitrogen-14 is bombarded by (andabsorbs) a proton, a new nuclide is produced, plus an alphaparticle is Carbon. Solution the reaction as follows:- 14N7 + 0n1 --> 4He2 + 10C6 so, the nuclide produced When Nitrogen-14 is bombarded by (andabsorbs) a proton, a new nuclide is produced, plus an alphaparticle is Carbon..