11. Example P={p 1 , p 2 , p 3 }; T={t 1 , t 2 , t 3 }; I(t 1 )={}, I(t 2 )={p 1 , p 2 }, I(t 3 )={p 3 }; O(t 1 )={p 1 }, O(t 2 )={p 3 }, O(t 3 )={p 2 } Initial marking: M 0 =[1, 1, 0]. Using the firing rule , we have M 1 =M 0 +e t C=[1, 1, 0]+[0, 1, 0]C=[0, 0, 1] where e t is the characteristic vector of t: e t (x):=1 if x=t, else =0. t 1 t 2 t 3 p 1 p 3 p 2
15. PN Modelling of Solvent Charging Illustration of places and transitions. p 1 : Reactor available p 2 : Charging Solvent 1 to the reactor p 3 . Charging Solvent 2 to the reactor p 4 : Charging Solvent 3 to the reactor p 5 : Charging Solvent 4 to the reactor p 6 : Reaction in progress to the reactor S 1 : Solvent 1 S 2 : Solvent 2 S 3 : Solvent 3 S 4 : Solvent 4 t 1 : Start charging solvent 1 t 2 : Stop charging solvent 1 & start charging solvent 2 t 3 : Stop charging solvent 2 & start charging solvent 3 t 4 : Stop charging solvent 3 & start charging solvent 4 t 5 : Stop charging solvent 4 & start reaction
16.
17. Modelling of Reactor and Blender Illustration of places and transitions p 7 : Charging solvents p 8 : Reaction in progress to the reactor p 9 : Discharging reactor & charging blender p 10 : Blending&testing&discharging R: Reactor available B: Blender available t 6 : Start charging solvents t 7 : Stop charging solvents & start reaction t 8 : Stop reaction&start charging blender t 9 : Stop charging&discharging & start blending t 10 : Stop discharging blender
18. Modelling of Quality Test Illustration of places and transitions p 12 : Ready for blending p 13 : Logical place for rejected material p 14 : Blending p 15 : Testing p 16 : Testing fail & require reblending p 17 : Testing success & discharging blender S 5 : Blending resource available O 1 : Operator available for testing O 2 : Operator available for discharging t 12 : Pumping to blender finish t 13 : Start blending t 14 : Stop blending & start testing t 15 : testing finish (fail) t 16 : testing finish (success) & start discharging blender t 17 : Start reblending t 16 : Discharging finish
26. Gantt Chart Firing sequence: t 1 t 2 t 3 t 4 t 5 t 6 t 7 t 8 leads to c=14 min Firing sequence: t 5 t 6 t 1 t 7 t 2 t 8 t 3 t 4 leads to c=11 min (optimum)